Discriminant Testing TEACHER NOTES MATH NSPIRED
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A Computational Approach to Solve a System of Transcendental Equations with Multi-Functions and Multi-Variables
mathematics Article A Computational Approach to Solve a System of Transcendental Equations with Multi-Functions and Multi-Variables Chukwuma Ogbonnaya 1,2,* , Chamil Abeykoon 3 , Adel Nasser 1 and Ali Turan 4 1 Department of Mechanical, Aerospace and Civil Engineering, The University of Manchester, Manchester M13 9PL, UK; [email protected] 2 Faculty of Engineering and Technology, Alex Ekwueme Federal University, Ndufu Alike Ikwo, Abakaliki PMB 1010, Nigeria 3 Aerospace Research Institute and Northwest Composites Centre, School of Materials, The University of Manchester, Manchester M13 9PL, UK; [email protected] 4 Independent Researcher, Manchester M22 4ES, Lancashire, UK; [email protected] * Correspondence: [email protected]; Tel.: +44-(0)74-3850-3799 Abstract: A system of transcendental equations (SoTE) is a set of simultaneous equations containing at least a transcendental function. Solutions involving transcendental equations are often problematic, particularly in the form of a system of equations. This challenge has limited the number of equations, with inter-related multi-functions and multi-variables, often included in the mathematical modelling of physical systems during problem formulation. Here, we presented detailed steps for using a code- based modelling approach for solving SoTEs that may be encountered in science and engineering problems. A SoTE comprising six functions, including Sine-Gordon wave functions, was used to illustrate the steps. Parametric studies were performed to visualize how a change in the variables Citation: Ogbonnaya, C.; Abeykoon, affected the superposition of the waves as the independent variable varies from x1 = 1:0.0005:100 to C.; Nasser, A.; Turan, A. -
Math 1232-04F (Survey of Calculus) Dr. J.S. Zheng Chapter R. Functions
Math 1232-04F (Survey of Calculus) Dr. J.S. Zheng Chapter R. Functions, Graphs, and Models R.4 Slope and Linear Functions R.5* Nonlinear Functions and Models R.6 Exponential and Logarithmic Functions R.7* Mathematical Modeling and Curve Fitting • Linear Functions (11) Graph the following equations. Determine if they are functions. (a) y = 2 (b) x = 2 (c) y = 3x (d) y = −2x + 4 (12) Definition. The variable y is directly proportional to x (or varies directly with x) if there is some positive constant m such that y = mx. We call m the constant of proportionality, or variation constant. (13) The weight M of a person's muscles is directly proportional to the person's body weight W . It is known that a person weighing 200 lb has 80 lb of muscle. (a) Find an equation of variation expressing M as a function of W . (b) What is the muscle weight of a person weighing 120 lb? (14) Definition. A linear function is any function that can be written in the form y = mx + b or f(x) = mx + b, called the slope-intercept equation of a line. The constant m is called the slope. The point (0; b) is called the y-intercept. (15) Find the slope and y-intercept of the graph of 3x + 5y − 2 = 0. (16) Find an equation of the line that has slope 4 and passes through the point (−1; 1). (17) Definition. The equation y − y1 = m(x − x1) is called the point-slope equation of a line. The point is (x1; y1), and the slope is m. -
Solving Cubic Polynomials
Solving Cubic Polynomials 1.1 The general solution to the quadratic equation There are four steps to finding the zeroes of a quadratic polynomial. 1. First divide by the leading term, making the polynomial monic. a 2. Then, given x2 + a x + a , substitute x = y − 1 to obtain an equation without the linear term. 1 0 2 (This is the \depressed" equation.) 3. Solve then for y as a square root. (Remember to use both signs of the square root.) a 4. Once this is done, recover x using the fact that x = y − 1 . 2 For example, let's solve 2x2 + 7x − 15 = 0: First, we divide both sides by 2 to create an equation with leading term equal to one: 7 15 x2 + x − = 0: 2 2 a 7 Then replace x by x = y − 1 = y − to obtain: 2 4 169 y2 = 16 Solve for y: 13 13 y = or − 4 4 Then, solving back for x, we have 3 x = or − 5: 2 This method is equivalent to \completing the square" and is the steps taken in developing the much- memorized quadratic formula. For example, if the original equation is our \high school quadratic" ax2 + bx + c = 0 then the first step creates the equation b c x2 + x + = 0: a a b We then write x = y − and obtain, after simplifying, 2a b2 − 4ac y2 − = 0 4a2 so that p b2 − 4ac y = ± 2a and so p b b2 − 4ac x = − ± : 2a 2a 1 The solutions to this quadratic depend heavily on the value of b2 − 4ac. -
Elements of Chapter 9: Nonlinear Systems Examples
Elements of Chapter 9: Nonlinear Systems To solve x0 = Ax, we use the ansatz that x(t) = eλtv. We found that λ is an eigenvalue of A, and v an associated eigenvector. We can also summarize the geometric behavior of the solutions by looking at a plot- However, there is an easier way to classify the stability of the origin (as an equilibrium), To find the eigenvalues, we compute the characteristic equation: p Tr(A) ± ∆ λ2 − Tr(A)λ + det(A) = 0 λ = 2 which depends on the discriminant ∆: • ∆ > 0: Real λ1; λ2. • ∆ < 0: Complex λ = a + ib • ∆ = 0: One eigenvalue. The type of solution depends on ∆, and in particular, where ∆ = 0: ∆ = 0 ) 0 = (Tr(A))2 − 4det(A) This is a parabola in the (Tr(A); det(A)) coordinate system, inside the parabola is where ∆ < 0 (complex roots), and outside the parabola is where ∆ > 0. We can then locate the position of our particular trace and determinant using the Poincar´eDiagram and it will tell us what the stability will be. Examples Given the system where x0 = Ax for each matrix A below, classify the origin using the Poincar´eDiagram: 1 −4 1. 4 −7 SOLUTION: Compute the trace, determinant and discriminant: Tr(A) = −6 Det(A) = −7 + 16 = 9 ∆ = 36 − 4 · 9 = 0 Therefore, we have a \degenerate sink" at the origin. 1 2 2. −5 −1 SOLUTION: Compute the trace, determinant and discriminant: Tr(A) = 0 Det(A) = −1 + 10 = 9 ∆ = 02 − 4 · 9 = −36 The origin is a center. 1 3. Given the system x0 = Ax where the matrix A depends on α, describe how the equilibrium solution changes depending on α (use the Poincar´e Diagram): 2 −5 (a) α −2 SOLUTION: The trace is 0, so that puts us on the \det(A)" axis. -
Write the Function in Standard Form
Write The Function In Standard Form Bealle often suppurates featly when active Davidson lopper fleetly and ray her paedogenesis. Tressed Jesse still outmaneuvers: clinometric and georgic Augie diphthongises quite dirtily but mistitling her indumentum sustainedly. If undefended or gobioid Allen usually pulsate his Orientalism miming jauntily or blow-up stolidly and headfirst, how Alhambresque is Gustavo? Now the vertex always sits exactly smack dab between the roots, when you do have roots. For the two sides to be equal, the corresponding coefficients must be equal. So, changing the value of p vertically stretches or shrinks the parabola. To save problems you must sign in. This short tutorial helps you learn how to find vertex, focus, and directrix of a parabola equation with an example using the formulas. The draft was successfully published. To determine the domain and range of any function on a graph, the general idea is to assume that they are both real numbers, then look for places where no values exist. For our purposes, this is close enough. English has also become the most widely used second language. Simplify the radical, but notice that the number under the radical symbol is negative! On this lesson, you fill learn how to graph a quadratic function, find the axis of symmetry, vertex, and the x intercepts and y intercepts of a parabolawi. Be sure to write the terms with the exponent on the variable in descending order. Wendler Polynomial Webquest Introduction: By the end of this webquest, you will have a deeper understanding of polynomials. Anyone can ask a math question, and most questions get answers! Follow along with the highlighted text while you listen! And if I have an upward opening parabola, the vertex is going to be the minimum point. -
Lesson 1: Multiplying and Factoring Polynomial Expressions
NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 1 M4 ALGEBRA I Lesson 1: Multiplying and Factoring Polynomial Expressions Classwork Opening Exercise Write expressions for the areas of the two rectangles in the figures given below. 8 2 2 Now write an expression for the area of this rectangle: 8 2 Example 1 The total area of this rectangle is represented by 3a + 3a. Find expressions for the dimensions of the total rectangle. 2 3 + 3 square units 2 푎 푎 Lesson 1: Multiplying and Factoring Polynomial Expressions Date: 2/2/14 S.1 This work is licensed under a © 2014 Common Core, Inc. Some rights reserved. commoncore.org Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 1 M4 ALGEBRA I Exercises 1–3 Factor each by factoring out the Greatest Common Factor: 1. 10 + 5 푎푏 푎 2. 3 9 + 3 2 푔 ℎ − 푔 ℎ 12ℎ 3. 6 + 9 + 18 2 3 4 5 푦 푦 푦 Discussion: Language of Polynomials A prime number is a positive integer greater than 1 whose only positive integer factors are 1 and itself. A composite number is a positive integer greater than 1 that is not a prime number. A composite number can be written as the product of positive integers with at least one factor that is not 1 or itself. For example, the prime number 7 has only 1 and 7 as its factors. The composite number 6 has factors of 1, 2, 3, and 6; it could be written as the product 2 3. -
Polynomials and Quadratics
Higher hsn .uk.net Mathematics UNIT 2 OUTCOME 1 Polynomials and Quadratics Contents Polynomials and Quadratics 64 1 Quadratics 64 2 The Discriminant 66 3 Completing the Square 67 4 Sketching Parabolas 70 5 Determining the Equation of a Parabola 72 6 Solving Quadratic Inequalities 74 7 Intersections of Lines and Parabolas 76 8 Polynomials 77 9 Synthetic Division 78 10 Finding Unknown Coefficients 82 11 Finding Intersections of Curves 84 12 Determining the Equation of a Curve 86 13 Approximating Roots 88 HSN22100 This document was produced specially for the HSN.uk.net website, and we require that any copies or derivative works attribute the work to Higher Still Notes. For more details about the copyright on these notes, please see http://creativecommons.org/licenses/by-nc-sa/2.5/scotland/ Higher Mathematics Unit 2 – Polynomials and Quadratics OUTCOME 1 Polynomials and Quadratics 1 Quadratics A quadratic has the form ax2 + bx + c where a, b, and c are any real numbers, provided a ≠ 0 . You should already be familiar with the following. The graph of a quadratic is called a parabola . There are two possible shapes: concave up (if a > 0 ) concave down (if a < 0 ) This has a minimum This has a maximum turning point turning point To find the roots (i.e. solutions) of the quadratic equation ax2 + bx + c = 0, we can use: factorisation; completing the square (see Section 3); −b ± b2 − 4 ac the quadratic formula: x = (this is not given in the exam). 2a EXAMPLES 1. Find the roots of x2 −2 x − 3 = 0 . -
Quadratic Polynomials
Quadratic Polynomials If a>0thenthegraphofax2 is obtained by starting with the graph of x2, and then stretching or shrinking vertically by a. If a<0thenthegraphofax2 is obtained by starting with the graph of x2, then flipping it over the x-axis, and then stretching or shrinking vertically by the positive number a. When a>0wesaythatthegraphof− ax2 “opens up”. When a<0wesay that the graph of ax2 “opens down”. I Cit i-a x-ax~S ~12 *************‘s-aXiS —10.? 148 2 If a, c, d and a = 0, then the graph of a(x + c) 2 + d is obtained by If a, c, d R and a = 0, then the graph of a(x + c)2 + d is obtained by 2 R 6 2 shiftingIf a, c, the d ⇥ graphR and ofaax=⇤ 2 0,horizontally then the graph by c, and of a vertically(x + c) + byd dis. obtained (Remember by shiftingshifting the the⇥ graph graph of of axax⇤ 2 horizontallyhorizontally by by cc,, and and vertically vertically by by dd.. (Remember (Remember thatthatd>d>0meansmovingup,0meansmovingup,d<d<0meansmovingdown,0meansmovingdown,c>c>0meansmoving0meansmoving thatleft,andd>c<0meansmovingup,0meansmovingd<right0meansmovingdown,.) c>0meansmoving leftleft,and,andc<c<0meansmoving0meansmovingrightright.).) 2 If a =0,thegraphofafunctionf(x)=a(x + c) 2+ d is called a parabola. If a =0,thegraphofafunctionf(x)=a(x + c)2 + d is called a parabola. 6 2 TheIf a point=0,thegraphofafunction⇤ ( c, d) 2 is called thefvertex(x)=aof(x the+ c parabola.) + d is called a parabola. The point⇤ ( c, d) R2 is called the vertex of the parabola. -
From Jay-Z to Dead Prez: Examining Representations of Black
JBSXXX10.1177/0021934714528953Journal of Black StudiesBelle 528953research-article2014 Article Journal of Black Studies 2014, Vol. 45(4) 287 –300 From Jay-Z to Dead © The Author(s) 2014 Reprints and permissions: Prez: Examining sagepub.com/journalsPermissions.nav DOI: 10.1177/0021934714528953 Representations of jbs.sagepub.com Black Masculinity in Mainstream Versus Underground Hip-Hop Music Crystal Belle1 Abstract The evolution of hip-hop music and culture has impacted the visibility of Black men and the Black male body. As hip-hop continues to become commercially viable, performances of Black masculinities can be easily found on magazine covers, television shows, and popular websites. How do these representations affect the collective consciousness of Black men, while helping to construct a particular brand of masculinity that plays into the White imagination? This theoretical article explores how representations of Black masculinity vary in underground versus mainstream hip-hop, stemming directly from White patriarchal ideals of manhood. Conceptual and theoretical analyses of songs from the likes of Jay-Z and Dead Prez and Imani Perry’s Prophets of the Hood help provide an understanding of the parallels between hip-hop performances/identities and Black masculinities. Keywords Black masculinity, hip-hop, patriarchy, manhood 1Columbia University, New York, NY, USA Corresponding Author: Crystal Belle, PhD Candidate, English Education, Teachers College, Columbia University, 525 West 120th Street, New York, NY 10027, USA. Email: [email protected] Downloaded from jbs.sagepub.com at Mina Rees Library/CUNY Graduate Center on January 7, 2015 288 Journal of Black Studies 45(4) Introduction to and Musings on Black Masculinity in Hip-Hop What began as a lyrical movement in the South Bronx is now an international phenomenon. -
The Determinant and the Discriminant
CHAPTER 2 The determinant and the discriminant In this chapter we discuss two indefinite quadratic forms: the determi- nant quadratic form det(a, b, c, d)=ad bc, − and the discriminant disc(a, b, c)=b2 4ac. − We will be interested in the integral representations of a given integer n by either of these, that is the set of solutions of the equations 4 ad bc = n, (a, b, c, d) Z − 2 and 2 3 b ac = n, (a, b, c) Z . − 2 For q either of these forms, we denote by Rq(n) the set of all such represen- tations. Consider the three basic questions of the previous chapter: (1) When is Rq(n) non-empty ? (2) If non-empty, how large Rq(n)is? (3) How is the set Rq(n) distributed as n varies ? In a suitable sense, a good portion of the answers to these question will be similar to the four and three square quadratic forms; but there will be major di↵erences coming from the fact that – det and disc are indefinite quadratic forms (have signature (2, 2) and (2, 1) over the reals), – det and disc admit isotropic vectors: there exist x Q4 (resp. Q3) such that det(x)=0(resp.disc(x) = 0). 2 1. Existence and number of representations by the determinant As the name suggest, determining Rdet(n) is equivalent to determining the integral 2 2 matrices of determinant n: ⇥ (n) ab Rdet(n) M (Z)= g = M2(Z), det(g)=n . ' 2 { cd 2 } ✓ ◆ n 0 Observe that the diagonal matrix a = has determinant n, and any 01 ✓ ◆ other matrix in the orbit SL2(Z).a is integral and has the same determinant. -
Finding Aid to the Historymakers ® Video Oral History with James Poyser
Finding Aid to The HistoryMakers ® Video Oral History with James Poyser Overview of the Collection Repository: The HistoryMakers®1900 S. Michigan Avenue Chicago, Illinois 60616 [email protected] www.thehistorymakers.com Creator: Poyser, James, 1967- Title: The HistoryMakers® Video Oral History Interview with James Poyser, Dates: May 6, 2014 Bulk Dates: 2014 Physical 7 uncompressed MOV digital video files (3:06:29). Description: Abstract: Songwriter, producer, and musician James Poyser (1967 - ) was co-founder of the Axis Music Group and founding member of the musical collective Soulquarians. He was a Grammy award- winning songwriter, musician and multi-platinum producer. Poyser was also a regular member of The Roots, and joined them as the houseband for NBC's The Tonight Show Starring Jimmy Fallon. Poyser was interviewed by The HistoryMakers® on May 6, 2014, in New York, New York. This collection is comprised of the original video footage of the interview. Identification: A2014_143 Language: The interview and records are in English. Biographical Note by The HistoryMakers® Songwriter, producer and musician James Jason Poyser was born in Sheffield, England in 1967 to Jamaican parents Reverend Felix and Lilith Poyser. Poyser’s family moved to West Philadelphia, Pennsylvania when he was nine years old and he discovered his musical talents in the church. Poyser attended Philadelphia Public Schools and graduated from Temple University with his B.S. degree in finance. Upon graduation, Poyser apprenticed with the songwriting/producing duo Kenny Gamble and Leon Huff. Poyser then established the Axis Music Group with his partners, Vikter Duplaix and Chauncey Childs. He became a founding member of the musical collective Soulquarians and went on to write and produce songs for various legendary and award-winning artists including Erykah Badu, Mariah Carey, John Legend, Lauryn Hill, Common, Anthony Hamilton, D'Angelo, The Roots, and Keyshia Cole. -
Nature of the Discriminant
Name: ___________________________ Date: ___________ Class Period: _____ Nature of the Discriminant Quadratic − b b 2 − 4ac x = b2 − 4ac Discriminant Formula 2a The discriminant predicts the “nature of the roots of a quadratic equation given that a, b, and c are rational numbers. It tells you the number of real roots/x-intercepts associated with a quadratic function. Value of the Example showing nature of roots of Graph indicating x-intercepts Discriminant b2 – 4ac ax2 + bx + c = 0 for y = ax2 + bx + c POSITIVE Not a perfect x2 – 2x – 7 = 0 2 b – 4ac > 0 square − (−2) (−2)2 − 4(1)(−7) x = 2(1) 2 32 2 4 2 x = = = 1 2 2 2 2 Discriminant: 32 There are two real roots. These roots are irrational. There are two x-intercepts. Perfect square x2 + 6x + 5 = 0 − 6 62 − 4(1)(5) x = 2(1) − 6 16 − 6 4 x = = = −1,−5 2 2 Discriminant: 16 There are two real roots. These roots are rational. There are two x-intercepts. ZERO b2 – 4ac = 0 x2 – 2x + 1 = 0 − (−2) (−2)2 − 4(1)(1) x = 2(1) 2 0 2 x = = = 1 2 2 Discriminant: 0 There is one real root (with a multiplicity of 2). This root is rational. There is one x-intercept. NEGATIVE b2 – 4ac < 0 x2 – 3x + 10 = 0 − (−3) (−3)2 − 4(1)(10) x = 2(1) 3 − 31 3 31 x = = i 2 2 2 Discriminant: -31 There are two complex/imaginary roots. There are no x-intercepts. Quadratic Formula and Discriminant Practice 1.