CHAPTER 12 Surface Area and Volume Chapter Outline
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Arc Length. Surface Area
Calculus 2 Lia Vas Arc Length. Surface Area. Arc Length. Suppose that y = f(x) is a continuous function with a continuous derivative on [a; b]: The arc length L of f(x) for a ≤ x ≤ b can be obtained by integrating the length element ds from a to b: The length element ds on a sufficiently small interval can be approximated by the hypotenuse of a triangle with sides dx and dy: p Thus ds2 = dx2 + dy2 ) ds = dx2 + dy2 and so s s Z b Z b q Z b dy2 Z b dy2 L = ds = dx2 + dy2 = (1 + )dx2 = (1 + )dx: a a a dx2 a dx2 2 dy2 dy 0 2 Note that dx2 = dx = (y ) : So the formula for the arc length becomes Z b q L = 1 + (y0)2 dx: a Area of a surface of revolution. Suppose that y = f(x) is a continuous function with a continuous derivative on [a; b]: To compute the surface area Sx of the surface obtained by rotating f(x) about x-axis on [a; b]; we can integrate the surface area element dS which can be approximated as the product of the circumference 2πy of the circle with radius y and the height that is given by q the arc length element ds: Since ds is 1 + (y0)2dx; the formula that computes the surface area is Z b q 0 2 Sx = 2πy 1 + (y ) dx: a If y = f(x) is rotated about y-axis on [a; b]; then dS is the product of the circumference 2πx of the circle with radius x and the height that is given by the arc length element ds: Thus, the formula that computes the surface area is Z b q 0 2 Sy = 2πx 1 + (y ) dx: a Practice Problems. -
Cones, Pyramids and Spheres
The Improving Mathematics Education in Schools (TIMES) Project MEASUREMENT AND GEOMETRY Module 12 CONES, PYRAMIDS AND SPHERES A guide for teachers - Years 9–10 June 2011 YEARS 910 Cones, Pyramids and Spheres (Measurement and Geometry : Module 12) For teachers of Primary and Secondary Mathematics 510 Cover design, Layout design and Typesetting by Claire Ho The Improving Mathematics Education in Schools (TIMES) Project 2009‑2011 was funded by the Australian Government Department of Education, Employment and Workplace Relations. The views expressed here are those of the author and do not necessarily represent the views of the Australian Government Department of Education, Employment and Workplace Relations. © The University of Melbourne on behalf of the International Centre of Excellence for Education in Mathematics (ICE‑EM), the education division of the Australian Mathematical Sciences Institute (AMSI), 2010 (except where otherwise indicated). This work is licensed under the Creative Commons Attribution‑NonCommercial‑NoDerivs 3.0 Unported License. 2011. http://creativecommons.org/licenses/by‑nc‑nd/3.0/ The Improving Mathematics Education in Schools (TIMES) Project MEASUREMENT AND GEOMETRY Module 12 CONES, PYRAMIDS AND SPHERES A guide for teachers - Years 9–10 June 2011 Peter Brown Michael Evans David Hunt Janine McIntosh Bill Pender Jacqui Ramagge YEARS 910 {4} A guide for teachers CONES, PYRAMIDS AND SPHERES ASSUMED KNOWLEDGE • Familiarity with calculating the areas of the standard plane figures including circles. • Familiarity with calculating the volume of a prism and a cylinder. • Familiarity with calculating the surface area of a prism. • Facility with visualizing and sketching simple three‑dimensional shapes. • Facility with using Pythagoras’ theorem. • Facility with rounding numbers to a given number of decimal places or significant figures. -
Lateral and Surface Area of Right Prisms 1 Jorge Is Trying to Wrap a Present That Is in a Box Shaped As a Right Prism
CHAPTER 11 You will need Lateral and Surface • a ruler A • a calculator Area of Right Prisms c GOAL Calculate lateral area and surface area of right prisms. Learn about the Math A prism is a polyhedron (solid whose faces are polygons) whose bases are congruent and parallel. When trying to identify a right prism, ask yourself if this solid could have right prism been created by placing many congruent sheets of paper on prism that has bases aligned one above the top of each other. If so, this is a right prism. Some examples other and has lateral of right prisms are shown below. faces that are rectangles Triangular prism Rectangular prism The surface area of a right prism can be calculated using the following formula: SA 5 2B 1 hP, where B is the area of the base, h is the height of the prism, and P is the perimeter of the base. The lateral area of a figure is the area of the non-base faces lateral area only. When a prism has its bases facing up and down, the area of the non-base faces of a figure lateral area is the area of the vertical faces. (For a rectangular prism, any pair of opposite faces can be bases.) The lateral area of a right prism can be calculated by multiplying the perimeter of the base by the height of the prism. This is summarized by the formula: LA 5 hP. Copyright © 2009 by Nelson Education Ltd. Reproduction permitted for classrooms 11A Lateral and Surface Area of Right Prisms 1 Jorge is trying to wrap a present that is in a box shaped as a right prism. -
Solids, Nets, and Cross Sections
SOLIDS, NETS, AND CROSS SECTIONS Polyhedra: Exercises: 1. The figure below shows a tetrahedron with the faces ∆ABD,,∆∆ ABC ACD and ∆ BCD . A The edges are AB,,,, AC AD DB BC and DC . The vertices are A, B, C and D, D B C 2. The given figure is a pentahedron with faces K ∆KLM,∆∆∆ KMN , KNO , KLO and . LMNO . The edges are KL,,,,,, KM KN KO LM MN NO and LO . O L The vertices are K, L, M, N, and O. N M Prisms: Exercises (page-4): 1. The right regular octagonal prism has 8 lateral faces, so totally it has 10 faces. It has 24 edges, 8 of them are lateral edges. The prism has 16 vertices. 2. The figure below illustrates an oblique regular triangular prism. It has 5 faces (3 of them are lateral faces), 3 lateral edges and totally 9 edges. The prism has 6 vertices. Pyramids Exercises (page-6): 1. The pentagonal pyramid has 5 lateral faces and thus 6 faces in total. It has 5 lateral edges, 10 edges and 6 vertices. 2. The hexagonal pyramid has 6 lateral faces and 7 faces in total. It has 6 lateral edges, 12 edges and 7 vertices. Nets Exercises: 1. Regular right hexagonal pyramid 2. Rectangular prism 3. Regular right octagonal prism 4. Regular oblique hexagonal prism 5. and so on… 6. Right Cylinder 7. Right Cone Cross sections: Exercises (page-15): 1. i) In the cross section parallel to the base, the cross section is a regular hexagon of the same size as the base. -
Year 6 – Wednesday 24Th June 2020 – Maths
1 Year 6 – Wednesday 24th June 2020 – Maths Can I identify 3D shapes that have pairs of parallel or perpendicular edges? Parallel – edges that have the same distance continuously between them – parallel edges never meet. Perpendicular – when two edges or faces meet and create a 90o angle. 1 4. 7. 10. 2 5. 8. 11. 3. 6. 9. 12. C1 – Using the shapes above: 1. Name and sort the shapes into: a. Pyramids b. Prisms 2. Draw a table to identify how many faces, edges and vertices each shape has. 3. Write your own geometric definition: a. Prism b. pyramid 4. Which shape is the odd one out? Explain why. C2 – Using the shapes above; 1. Which of the shapes have pairs of parallel edges in: a. All their faces? b. More than one half of the faces? c. One face only? 2. The following shapes have pairs of perpendicular edges. Identify the faces they are in: 2 a. A cube b. A square based pyramid c. A triangular prism d. A cuboid 3. Which shape with straight edges has no perpendicular edges? 4. Which shape has perpendicular edges in the shape but not in any face? C3 – Using the above shapes: 1. How many faces have pairs of parallel edges in: a. A hexagonal pyramid? b. A decagonal (10-sided) based prism? c. A heptagonal based prism? d. Which shape has no face with parallel edges but has parallel edges in the shape? 2. How many faces have perpendicular edges in: a. A pentagonal pyramid b. A hexagonal pyramid c. -
Calculus Terminology
AP Calculus BC Calculus Terminology Absolute Convergence Asymptote Continued Sum Absolute Maximum Average Rate of Change Continuous Function Absolute Minimum Average Value of a Function Continuously Differentiable Function Absolutely Convergent Axis of Rotation Converge Acceleration Boundary Value Problem Converge Absolutely Alternating Series Bounded Function Converge Conditionally Alternating Series Remainder Bounded Sequence Convergence Tests Alternating Series Test Bounds of Integration Convergent Sequence Analytic Methods Calculus Convergent Series Annulus Cartesian Form Critical Number Antiderivative of a Function Cavalieri’s Principle Critical Point Approximation by Differentials Center of Mass Formula Critical Value Arc Length of a Curve Centroid Curly d Area below a Curve Chain Rule Curve Area between Curves Comparison Test Curve Sketching Area of an Ellipse Concave Cusp Area of a Parabolic Segment Concave Down Cylindrical Shell Method Area under a Curve Concave Up Decreasing Function Area Using Parametric Equations Conditional Convergence Definite Integral Area Using Polar Coordinates Constant Term Definite Integral Rules Degenerate Divergent Series Function Operations Del Operator e Fundamental Theorem of Calculus Deleted Neighborhood Ellipsoid GLB Derivative End Behavior Global Maximum Derivative of a Power Series Essential Discontinuity Global Minimum Derivative Rules Explicit Differentiation Golden Spiral Difference Quotient Explicit Function Graphic Methods Differentiable Exponential Decay Greatest Lower Bound Differential -
Comparing Surface Area & Volume
Name ___________________________________________________________________ Period ______ Comparing Surface Area & Volume Use surface area and volume calculations to solve the following situations. 1. Find the surface area and volume of each prism. Which two have the same surface area? Which two have the same volume? 4 in. 22 in. 10 in. C A 11 in. B 18 in. 10 in. 6 in. 10 in. 6 in. 2. Sketch and label two different rectangular prisms that have the same volume. Find the surface area of each. 3. Do the following cylinders have the same surface area, the same volume, or the same surface area and volume? r = 4 cm r = 2 cm h = 9 cm h = 24 cm 4. A cylinder has a surface area of 125.6 mm2 and a volume of 100.48 mm3. If another cylinder has a radius of 5 mm and the same volume, what would be the height? 5. A cylinder has a radius of 9 yd and a height of 3 yd. A second cylinder has a radius of 6 yd and a height of 12 yd. Which statement is true? a. The cylinders have the same surface area and the same volume. b. The cylinders have the same surface area and different volumes. c. The cylinders have different surface areas and the same volume. d. The cylinders have different surface areas and different volumes. 6. The surface area of a rectangular prism is 2,116 mm2. If you double the length, width, and height of the prism, what will be the surface area of the new prism? How much larger is this amount? 7. -
2D and 3D Shapes.Pdf
& • Anchor 2 - D Charts • Flash Cards 3 - D • Shape Books • Practice Pages rd Shapesfor 3 Grade by Carrie Lutz T hank you for purchasing!!! Check out my store: http://www.teacherspayteachers.com/Store/Carrie-Lutz-6 Follow me for notifications of freebies, sales and new arrivals! Visit my BLOG for more Free Stuff! Read My Blog Post about Teaching 3 Dimensional Figures Correctly Credits: Carrie Lutz©2016 2D Shape Bank 3D Shape Bank 3 Sided 5 Sided Prisms triangular prism cube rectangular prism triangle pentagon 4 Sided rectangle square pentagonal prism hexagonal prism octagonal prism Pyramids rhombus trapezoid 6 Sided 8 Sided rectangular square triangular pyramid pyramid pyramid Carrie LutzCarrie CarrieLutz pentagonal hexagonal © hexagon octagon © 2016 pyramid pyramid 2016 Curved Shapes CURVED SOLIDS oval circle sphere cone cylinder Carrie Lutz©2016 Carrie Lutz©2016 Name _____________________ Side Sort Date _____________________ Cut out the shapes below and glue them in the correct column. More than 4 Less than 4 Exactly 4 Carrie Lutz©2016 Name _____________________ Name the Shapes Date _____________________ 1. Name the Shape. 2. Name the Shape. 3. Name the Shape. ____________________________________ ____________________________________ ____________________________________ 4. Name the Shape. 5. Name the Shape. 6. Name the Shape. ____________________________________ ____________________________________ ____________________________________ 4. Name the Shape. 5. Name the Shape. 6. Name the Shape. ____________________________________ ____________________________________ ____________________________________ octagon circle square rhombus triangle hexagon pentagon rectangle trapezoid Carrie Lutz©2016 Faces, Edges, Vertices Name _____________________ and Date _____________________ 1. Name the Shape. 2. Name the Shape. 3. Name the Shape. ____________________________________ ____________________________________ ____________________________________ _____ faces _____ faces _____ faces _____Edges _____Edges _____Edges _____Vertices _____Vertices _____Vertices 4. -
Why Cells Are Small: Surface Area to Volume Ratios
Name__________________________________ Why Cells are Small: Surface Area to Volume Ratios Today’s lab is about the size of cells. To understand this, we first have to understand surface area to volume ratios. Let’s start with surface area. Get a box of sugar cubes. The surface area of the cube is calculated by finding the area (length x width) of one side. But we want to know the whole surface. On a cube, there are 6 sides, so we multiply that area x 6. So Surface area of a cube = length x width x 6 Volume is another simple calculation – we just multiply length x width x height. Build the following four structures from your sugar cubes, and fill out the table below. The one we’re most interested in, though is the surface area to volume ratio, which is just Surface area ÷ volume A B C D 1 UNIT 2 UNITS 3 4 UNITS OR CM UNITS Figure Total number Surface area of Volume of Surface area to Total surface of Cubes figure figure Volume Ratio of individual (=6 x length x (= length x ( = SA / V) cubes* width) width x height) (= 6 * # cubes) A 1 6 1 6 1 B 8 24 8 3 48 C 27 54 27 2 162 64 96 64 1.5 384 D *because surface area of one cube is 6 Surface Area to Volume Lab Questions 1. What happened to the surface area as the size increased? It increased. 2. What happened to the volume as the size increased? It also increased, but not as quickly. -
Three-Dimensional Figures
Notes Three-Dimensional Figures Polyhedra (the plural of Polyhedron) are three dimensional versions of polygons. They are made up of polygons. They are solid (no holes) and closed. Polyhedra fall into two major classes: Pyramids and Prisms. Note: Prisms and Pyramids are always named “based” on their bases. A Prism with a square base is called a Square Prism; a pyramid with a square base is called a Square Pyramid; a prism with a base that’s an octagon is called an Octagonal Prism; and so on. General Classes of Polyhedra 1) Prism - polyhedron with two opposite faces identical to each other. These opposite faces are called bases. The other faces are called lateral faces. Using the Power Solids, find all of the Prisms. Decide which faces are the bases, and which faces are the lateral faces. Then write the name of each of the prisms that you found: 2) Pyramid - polyhedron with a top "point" (called an apex), where all lateral faces meet. Using the Power Solids, find the two Pyramids. Decide which face is the base, and which faces are the lateral faces. Write the names of those two pyramids below. Other Three Dimensional Figures 1) Cylinder - curved shape analogous to a prism, except with circles for bases. Question: If the two circles are bases, what is the lateral “face”? 2) Cone - curved shape analogous to a pyramid, except with a circle for a base. Question: If the circle is the base, what is the lateral "face"? Note: The bases of cones and cylinders do not have to be circles (they could be ovals, for example), but we will pay attention to only those with circular bases. -
Triangulations and Simplex Tilings of Polyhedra
Triangulations and Simplex Tilings of Polyhedra by Braxton Carrigan A dissertation submitted to the Graduate Faculty of Auburn University in partial fulfillment of the requirements for the Degree of Doctor of Philosophy Auburn, Alabama August 4, 2012 Keywords: triangulation, tiling, tetrahedralization Copyright 2012 by Braxton Carrigan Approved by Andras Bezdek, Chair, Professor of Mathematics Krystyna Kuperberg, Professor of Mathematics Wlodzimierz Kuperberg, Professor of Mathematics Chris Rodger, Don Logan Endowed Chair of Mathematics Abstract This dissertation summarizes my research in the area of Discrete Geometry. The par- ticular problems of Discrete Geometry discussed in this dissertation are concerned with partitioning three dimensional polyhedra into tetrahedra. The most widely used partition of a polyhedra is triangulation, where a polyhedron is broken into a set of convex polyhedra all with four vertices, called tetrahedra, joined together in a face-to-face manner. If one does not require that the tetrahedra to meet along common faces, then we say that the partition is a tiling. Many of the algorithmic implementations in the field of Computational Geometry are dependent on the results of triangulation. For example computing the volume of a polyhedron is done by adding volumes of tetrahedra of a triangulation. In Chapter 2 we will provide a brief history of triangulation and present a number of known non-triangulable polyhedra. In this dissertation we will particularly address non-triangulable polyhedra. Our research was motivated by a recent paper of J. Rambau [20], who showed that a nonconvex twisted prisms cannot be triangulated. As in algebra when proving a number is not divisible by 2012 one may show it is not divisible by 2, we will revisit Rambau's results and show a new shorter proof that the twisted prism is non-triangulable by proving it is non-tilable. -
Paper Models of Polyhedra
Paper Models of Polyhedra Gijs Korthals Altes Polyhedra are beautiful 3-D geometrical figures that have fascinated philosophers, mathematicians and artists for millennia Copyrights © 1998-2001 Gijs.Korthals Altes All rights reserved . It's permitted to make copies for non-commercial purposes only email: [email protected] Paper Models of Polyhedra Platonic Solids Dodecahedron Cube and Tetrahedron Octahedron Icosahedron Archimedean Solids Cuboctahedron Icosidodecahedron Truncated Tetrahedron Truncated Octahedron Truncated Cube Truncated Icosahedron (soccer ball) Truncated dodecahedron Rhombicuboctahedron Truncated Cuboctahedron Rhombicosidodecahedron Truncated Icosidodecahedron Snub Cube Snub Dodecahedron Kepler-Poinsot Polyhedra Great Stellated Dodecahedron Small Stellated Dodecahedron Great Icosahedron Great Dodecahedron Other Uniform Polyhedra Tetrahemihexahedron Octahemioctahedron Cubohemioctahedron Small Rhombihexahedron Small Rhombidodecahedron S mall Dodecahemiododecahedron Small Ditrigonal Icosidodecahedron Great Dodecahedron Compounds Stella Octangula Compound of Cube and Octahedron Compound of Dodecahedron and Icosahedron Compound of Two Cubes Compound of Three Cubes Compound of Five Cubes Compound of Five Octahedra Compound of Five Tetrahedra Compound of Truncated Icosahedron and Pentakisdodecahedron Other Polyhedra Pentagonal Hexecontahedron Pentagonalconsitetrahedron Pyramid Pentagonal Pyramid Decahedron Rhombic Dodecahedron Great Rhombihexacron Pentagonal Dipyramid Pentakisdodecahedron Small Triakisoctahedron Small Triambic