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Physics 212 Lecture 25

Physics 212 Lecture 25, Slide 1 Music Who is the Artist?

A) The Band B) Bob Seger C) CCR D) Eagles E) Steve Miller Band

We’ve had a few CCR requests Your Comments “Finally! Stuff I actually like and understand!” “Probably the easiest thing we will ever learn all year.” “I didn’t really understand the polarized portion, partially because the prelecture slide was 3 minutes of a non moving picture We’ll go over the key steps which surely cannot hold my attention when I’m on a computer. ” “I am confused about the . Why is the horizontal polarization unchanged while the vertical polarization is decreased from incidence to reflected ray??” “I could use a little more discussion on the polarization due to .” “I thought the prelecture was pretty straight forward (minus the slide about intensity - uuuhhh Checkpoints – coming up! a little more explanation por favor!), but then, the checkpoints were a bit trickier than I expected. Could we go over them please????” Hour Exam 3: 1 week from tomorrow (Wed. Apr. 25) • covers L19-26 inclusive (LC circuits to lenses) • Sign up for conflicts, etc. no later than Mon. Apr. 23 at 10:00 p.m. 05 Physics 212 Lecture 25, Slide 3 Let’s start with a summary:

from n1 to n2 from n1 to n2

Physics 212 Lecture 25, Slide 4 The speed of in a medium is slower than in empty space:

since 0 < 

vmedium = c / nmedium Remember:  is dielectric constant (capacitors) Physics 212 Lecture 25, Slide 5 A ray of light passes from air into water with an angle of incidence of 30 degrees. Checkpoint 1a

Which of the following quantities does not change as the light enters the water? A. B. frequency C. speed of propagation

“frequency depends on speed, which obviously changes”

“frequency doesn’t depend on the medium. Frequency only depends on the source producing the

“Speed of light is always the same.”

Physics 212 Lecture 25, Slide 6 A ray of light passes from air into water with an angle of incidence of 30 degrees. Checkpoint 1a

Which of the following quantities does not change as the light enters the water? A. wavelength B. frequency C. speed of propagation

What about the wave must be the same on either side ???

Observers in both media must agree on the frequency of vibration of the molecules

Physics 212 Lecture 25, Slide 7 Reflection

Physics 212 Lecture 25, Slide 8 : Snell’s Law

D sin 2 Dsin 1  n2 sin 2  n1 sin 1 c / n2 c / n1 Physics 212 Lecture 25, Slide 9 Think of a day at the beach… What's the fastest path to the ball knowing you can run faster than you can swim?

This one is better

Not the quickest route…

Physics 212 Lecture 25, Slide 10 A x1

l1 y1 Same Principle works for Light !! D

y2 l2

x2 B

2 2 2 2 l l x  y x  y Time from A to B : t  1  2  1 1  2 2 v1 v2 v1 v2 To find minimum time, dt x1 x2 dx2 differentiate t wrt x   1 dx 2 2 2 2 dx and set = 0 1 v1 x1  y1 v2 x2 y2 1

dx2 How is x2 related to x1? x2  D  x1  1 dx1

x x sin  sin  Setting 1  2  0 1 2  v = c/n n1 sin 1  n2 sin 2 dt/dx1 = 0 v1l1 v2l2 v1 v2

Physics 212 Lecture 25, Slide 11 The path of light is bent as it passes from medium 1 to medium 2. Checkpoint 2a

Compare the indices of refraction in the two media.

A. n1 > n2 B. n1 = n2 C. n1 < n2

“by snell’s law, n1 has to be bigger than n2 to make up for smaller sin(theta1) ”

“They are the same angles. ”

“if theta is smaller, n must be smaller”

Physics 212 Lecture 25, Slide 12 The path of light is bent as it passes from medium 1 to medium 2. Checkpoint 2a

Compare the indices of refraction in the two media.

A. n1 > n2 B. n1 = n2 C. n1 < n2

Snell’s Law:

n1sin1 = n2sin2

n decreases fl  increases

Physics 212 Lecture 25, Slide 13 Total Internal Reflection

o NOTE: n1 > n2 implies 2 > 1 BUT: 2 has max value = 90 !!

1 > c Total Internal Reflection

Physics 212 Lecture 25, Slide 14 A light ray travels in a medium with n1 and completely reflects from the surface of a medium n2. Checkpoint 2b

The critical angle depends on:

A. n1 only B. n2 only C. both n1 and n2

“n1 determines n2 which determines the critical angle”

“Critical angle depends on the incidence angle inside the medium, so only n2 is required. ”

“n1 must be greater than n2”

Physics 212 Lecture 25, Slide 15 A light ray travels in a medium with n1 and completely reflects from the surface of a medium n2. Checkpoint 2b

The critical angle depends on:

A. n1 only B. n2 only C. both n1 and n2

c clearly depends on both n2 and n1

Physics 212 Lecture 25, Slide 16 Intensity

Anything looks like a If two materials have the same n if light is just glancing off it. then its hard to tell them apart. Physics 212 Lecture 25, Slide 17 Polarization

56.3o

     1 2  90 sin 2  sin( 90  1)  cos1

n2 Snell’s Law: n2 sin 2  n2 cos1  n1 sin1 tan1  n1 Physics 212 Lecture 25, Slide 18 A ray of light passes from air into water with an angle of incidence of 30 degrees. Checkpoint 1b

Some of the light also reflects off the surface of the water. If the incident light is initially unpolarized, the reflected light will be A. unpolarized B. somewhat horizontally polarized C. somewhat vertically polarized

“reflection doesn’t polarize previously unpolarized light.”

“The vertical component of the E field gets smaller as the ray approaches Brewster's angle.”

“Only vertically polarized light reflects”

Physics 212 Lecture 25, Slide 19 A ray of light passes from air into water with an angle of incidence of 30 degrees. Checkpoint 1b

Some of the light also reflects off the surface of the water. If the incident light is initially unpolarized, the reflected light will be A. unpolarized B. somewhat horizontally polarized C. somewhat vertically polarized

o = horizontal

Physics 212 Lecture 25, Slide 20 A ball sits in the bottom of an otherwise empty tub at the front of the room.

Suppose N people sit high enough to see the ball (N = ).

Physics 212 Lecture 25, Slide 21 A ball sits in the bottom of an otherwise empty tub at the front of the room. Suppose N people sit high enough to see the ball (N = ).

Suppose I fill the tub with water but the ball doesn’t move. Will more or less people see the ball? A) More people will see the ball B) Same # will see the ball C) Less people will see the ball ??

A

w

Snell’s Law: ray bent away from going from water to air Physics 212 Lecture 25, Slide 22 A light is shining at the bottom of a swimming pool (shown in yellow in the figure). A person is standing at the edge of the pool. Checkpoint 3

Can the person standing on the edge of the pool be prevented from seeing the light by total internal reflection at the water-air surface? A. yes B. no

“light could all be relected and stay in the water so he can’t see it ”

“it depends on the position of the light. if it’s too close to the person, they won't see it.”

“Light comes out at many angles, so while some may be interneally reflected, all cant since they are at differnet angles”

“There would be a point where some light would be totally reflected but that would only be for a point, not for the whole light.” Physics 212 Lecture 25, Slide 23 A light is shining at the bottom of a swimming pool (shown in yellow in the figure). A person is standing at the edge of the pool. Checkpoint 3

Can the person standing on the edge of the pool be prevented from seeing the light by total internal reflection at the water-air surface? A. yes B. no

The light would go out in all directions, so only some of it would be internally reflected. The person would see the light that escaped after being refracted.

DRAW SOME RAYS

Physics 212 Lecture 25, Slide 24 Example: Refraction at water/air interface

• Diver’s illusion

97º

Diver sees all of horizon refracted into a 97°cone nn1  sin aa sin90   air  90 water water  48.5 nnww1.33

Physics 212 Lecture 25, Slide 25 Exercise 45o

A meter stick lies at the bottom of a n = 1.33 rectangular water tank of height 50cm. water You look into the tank at an angle of 45o relative to vertical along a line that 50 cm skims the top edge of the tank.

What is the smallest number on the ruler that you can see? 020 406080100

Conceptual Analysis: - Light is refracted at the surface of the water

Strategy: - Determine the angle of refraction in the water and extrapolate this to the bottom of the tank.

Physics 212 Lecture 25, Slide 26 Exercise 45o

A meter stick lies at the bottom of a n = 1.33 rectangular water tank of height 50cm. water You look into the tank at an angle of 45o relative to vertical along a line that 50 cm skims the top edge of the tank.

What is the smallest number on the ruler that you can see? 020 406080100

If you shine a laser into the tank at an angle of 45o, what is the

refracted angle R in the water ?

o o o A) R = 28.3 B) R = 32.1 C) R = 38.7

Snell’s Law: nairsin(45) = nwatersin(R)

sin(R) = nairsin(45)/nwater = 0.532

-1 o R = sin (0.532) = 32.1 Physics 212 Lecture 25, Slide 27 Exercise 45o

A meter stick lies at the bottom of a nwater = 1.33 rectangular water tank of height 50cm.  You look into the tank at an angle of R 45o relative to vertical along a line that 50 cm skims the top edge of the tank.

What is the smallest number on the ruler that you can see? 020 406080100 d o R = 32.1

What number on the ruler does the laser beam hit ?

A) 31.4 cmB) 37.6 cm C) 44.1 cm

tan(R) = d/50

d = tan(32.1) x 50cm = 31.4cm

Physics 212 Lecture 25, Slide 28 Follow-Up 45o

A meter stick lies at the bottom of a rectangular water tank of height 50cm. You look into the tank at an angle of 45o relative to vertical along a line that 50 cm nwater = 1.33 skims the top edge of the tank.

020 406080100

If the tank were half full of water, what number would the laser hit? (When full, it hit at 31.4 cm)

A) 25 cm B) 31.4 cm C) 32.0 cm D) 40.7 cm E) 44.2 cm

Physics 212 Lecture 25, Slide 29 45o 45o

nwater = 1.33 R 50 cm 50 cm

d = 31.4 cm d = 50 cm

040608010020 020 406080100 o R = 32.1

45o

50 cm nwater = 1.33  R d = 40.7 cm

040608010020

25 cm + (31.4/2) cm Physics 212 Lecture 25, Slide 30 More Practice

A monochromatic ray enters a slab with n1 = 1.5 at an angle b as shown

b TOP n = 1

n1 = 1.5

BOTTOM n = 1 b

(A) Total internal reflection at the top occurs for all angles b, such that sinb < 2/3

(B) Total internal reflection at the top occurs for all angles b, such that sinb > 2/3

o (C) There is no angle b (0 < b < 90 ) such that total internal reflection occurs at top.

Snell’s law: Ray exits to air with same nn1122sin  sin nsin is “conserved” angle as it entered !!

Physics 212 Lecture 25, Slide 31 Follow-Up

A ray of light moves through a medium with index of refraction n1 and is incident upon a second material (n2) at angle 1 as shown. This ray is then totally reflected at the interface with a third material (n3). Which statement must be true?

1 n1 (A) (B) (C) n3  n1 nnn132 nn32 n2

n3

1

n1 If n = n 1 3 n2 n 3 1

Want larger angle of refraction in n3 n3 < n1

Physics 212 Lecture 25, Slide 32 “Does gravity affect reflection/refraction? Would the reflection of the ray depend on say where you are in space? ex: standing on jupiter etc?”

“Gravity affects the path taken by light, but small effect: Einstein ring”

Physics 212 Lecture 25, Slide 33