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AP NOTES 12-1 : ELECTROCHEMICAL CELLS

Review:

OXIDATION-REDUCTION REACTIONS – the changes that occur when are transferred between reactants (also known as a reaction)

OIL RIG

Oxidation Is Loss of electrons ...... Reduction Is Gain of electrons

Oxidation and reduction ALWAYS occur simultaneously

Oxidation – the loss of electrons by a substance (the oxidation number rises, becoming more positive)

Reduction – the gain of electrons by a substance (the oxidation number lowers, becoming more negative)

Oxidizing Agent – the substance in a redox reaction which causes another substance to be oxidized (it itself is reduced)

Reducing Agent – the substance in a redox reaction which causes another substance to be reduced (it itself is oxidized)

Example: Balance the following redox reaction:

Al + Sn4+ → Al3+ + Sn

ELECTROCHEMICAL CELLS

There are two main types of electrochemical cells:

Galvanic (Voltaic) Cells – these cells are spontaneous and react with no outside input

*These cells convert into (ie. batteries)

Electrolytic Cells – these cells are non-spontaneous and require energy input in order for the reaction to occur

*This is the type of cell used to electroplate onto the of other metals

In an , oxidation and reduction occur simultaneously.

A typical galvanic (voltaic) cell:

– the where oxidation occurs (AN OX)

*This is the negative electrode

– the electrode where reduction occurs (RED CAT)

*This is the positive electrode

Electron flow always occurs through the from the anode to the cathode ( CAT)

bridge – a device used to maintain electrical neutrality in the cell by supplying to replace the charges; generally consists of a neutral salt

*anions move to the anode side, cations move to the cathode side

voltmeter – measures the cell potential (emf), usually in

Example: In the previous diagram, what reactions occur at the anode and the cathode?

In a standard electrochemical cell, substances are always in their standard states, and are 1.0 M.

To show the contents of an electrochemical cell, we use Standard Cell :

Reaction:

M + N+ → N + M+

Standard :

M | M+ || N+ | N (anode) (cathode)

*If the “electrode” is an or a , then an “inert electrode” must be used ( or are common)

EXAMPLE: Draw the diagram of an electrochemical cell based on the following cell notation. Use nitrate as the . Be sure to clearly label the and solutions involved, as well as the direction of flow. In addition, show a balanced for the reaction.

Ni | Ni2+ || Ag+ | Ag

AP CHEMISTRY NOTES 12-2 ELECTROCHEMISTRY – CALCULATING CELL POTENTIAL

CELL POTENTIAL

Electromotive (“emf” or “E” or “ε”) – the force which moves electrons from the anode to the cathode

In order to determine whether a process is spontaneous, the cell potential must be calculated. The cell potential refers to a measure of (emf) for a cell. This value can be determined by combining the potentials of both the oxidation and reduction half-reactions.

To read a chart:

*The half-reactions are written as reductions.

*The elements with more positive reduction potentials are more easily reduced.

*The elements with more negative reduction potentials are more easily oxidized.

EXAMPLE: Will a reaction occur if a piece of is dipped into a of (II) nitrate?

EXAMPLE: What will happen if a bracelet is dropped into a solution of copper(II) nitrate?

EXAMPLE: Which of the following is the stronger ?

bromine

Which of the following is the stronger ?

chromium

o Calculation of Cell Potential (E cell)

To calculate cell potential:

1. Write oxidation and reduction half-reactions (use the reduction potential chart to determine which substance is oxidized and which is reduced if you are not given this information).

2. Use the reduction potential chart to find for each half-reaction.

3. Change the sign of the for the oxidation reaction (and re-write as oxidation if necessary)

4. Add the two voltages together (but do not multiply the voltages by the integers used to balance the half-reactions!)

o o o E cell = E ox + E red

5. Determine the spontaneity of the cell:

o *Positive E cell – spontaneous (galvanic or voltaic cell)

o *Negative E cell – non-spontaneous ()

EXAMPLE: Calculate the cell voltage for the following reaction. In addition, determine the type of cell that would form as well as a balanced reaction for the process.

Cr3+ + Cu → Cr + Cu2+

EXAMPLE: Calculate the voltage for the following reaction. In addition, determine the type of cell this would form as well as a balanced reaction for the process.

Fe + Cu2+ → Cu + Fe2+

Recall that an electrolytic cell uses electrical energy to produce a (ie. , , etc.)

The only difference between electrolytic and galvanic cells is that in electrolytic cells:

*the anode is positive (often an inert electrode is used)

*the cathode is negative (often an inert electrode is used)

*a (or some source of emf) must be used to “push” the reaction

AP CHEMISTRY NOTES 12-3

APPLICATIONS IN ELECTROCHEMISTRY

Faraday’s Law – the amount of a substance being oxidized or reduced at each electrode during electrolysis is directly proportional to the amount of that passes through the cell

Calculations involving electrolytic cells are best done by simply using dimensional and a few key conversions factors:

1 (V) = 1 /

1 Amp (A) = 1 Coulomb/Second

1 (F) = 96,500 / of electrons

EXAMPLE: What of is plated when a current of 15 amps is passed for 60. minutes through a solution containing cobalt(II) ions?

EXAMPLE: How long will it take to plate out one kilogram of aluminum from aluiminum ions using a current of 100 amps?

SPONTANEITY OF CELLS

Thermodynamically Favored (Spontaneous):

∆H < 0 ∆S > 0 K > 1 ∆G < 0 Ecell > 0

The relationship between free energy and the spontaneity of an electrochemical cell can be shown using the following equations: ∆Go = - n F Eo ∆Go = - RT ln K

Where G = free energy n = # mol of electrons transferred F = Faraday’s Constant (96,500 C/mol e-) Eo = cell potential R = 8.3145 J/K.mol T = (K) K = o EXAMPLE: Calculate the Ecell and ∆G at 25 C for the following reaction. In addition, determine the equilibrium constant for the reaction.

Cu2+ + Fe → Cu + Fe2+

Determination of Cell Potential at Other Than Standard Conditions

To calculate the potential of a cell in which some or all components are not in standard states, the is used:

EXAMPLE: Calculate the voltage of the following reaction (at 25oC) with the following conditions:

2+ 3+ o 2Al + 3Mn → 2Al + 3Mn E cell = 0.48 volts

[Mn2+] = 0.50 M [Al3+] = 1.5 M