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GLOBAL LEARNING ISSUE: STEREOCHEMISTRY Stereochemistry "Problem Solving"

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GLOBAL LEARNING ISSUE: STEREOCHEMISTRY Stereochemistry Principles of Drug Action I, Winter, 2005 GLOBAL LEARNING ISSUE: STEREOCHEMISTRY Stereochemistry "Problem Solving" Jack DeRuiter This tutorial section is designed solely to introduce a method of "problem solving" involved with determining the stereochemical relationship between a pair of compounds. Additional tutorials have been provided to deal with other important aspects of stereochemistry. Also, prior to attempting to solve the problems in this review tutorial, you are advised to review your notes on stereochemistry from Principles of Drug Action I (PY450). The problems below test your understanding on key stereochemical concepts such as chirality, optical isomerism and enantiomers, diastereomers, geometric isomerism and conformational isomerism, etc. When attempting to determine the stereochemical relationship between a pair of compounds the following method is recommended using the examples of compounds A and B shown below. For this method to work, you must follow the steps in order!: OH CH3 CH3 OH NH2 NH2 CH CH A 3 B 3 STEP ONE: Are the compounds positional (regio-) isomers. Is there a difference in the bonding arrangements? Do the compounds have similar functional groups but different positions of attachment on the molecular framework? . IF NOT, GO TO STEP TWO! Example: NO! Compounds A and B above have the same empiric formula, the same groups and the same bonding positions or "attachment" of functional groups. Both consist of cyclohexane rings with a hydroxyl and methyl attached to one carbon and an amino group and methyl group attached to the adjacent carbon. So go to step two. STEP TWO: If they are not positional isomers, are these compounds geometric isomers? Do they contain a site of hindered bond rotation such as a C=C or cyclic system AND are the atoms (carbons) at this site unsymmetrically substituted? If such a system is present, assign the stereochemistry as "cis" or "trans" or "E" or "Z". IF NOT, GO TO THE THIRD STEP! Example: Compounds A and B above consist of a cyclic system (restricted bond rotation) AND two of the carbon atoms of this system are unsymmetrically substituted. Thus geometric isomerism is possible! 1 Principles of Drug Action I, Winter, 2005 Ring system: restricted rotation! OH CH3 CH3 OH NH2 NH2 CH CH A 3 B 3 Two carbon atoms bearing "unlike" substitutents (unsymmetrical) For these two compounds to be geometric isomers, one must have the "E" configuration, and the other the "Z" configuration. Configuration can be assigned by identifying the highest priority group on EACH unsymmetrically substituted carbon atom and determining the relative spatial relationship of those groups within compound. For example, in compound A the OH group is a higher priority than the CH3 on one carbon, and the NH2 group is a higher priority than the CH3 on the other carbon. Since the highest priority groups on each unsymmetrically substituted ring carbon project upward from the average plane of the cyclohexane ring, thus compound A is the "Z" or "cis-like" isomer. Similar priority assignments can be for compound B. When this is done it is observed that the highest priority groups on each unsymmetrically substituted ring carbon project in opposite directions from the average plane of the cyclohexane ring one up, one down). Thus compound B is the "E" isomer: OH Highest priority group at this carbon: Is axial, projecting "up" Z-isomer: Highest priority groups on each CH3 carbon projecting in the same orientation: NH2 Highest priority group at this carbon: Is equatorial, projecting "up" A CH3 CH3 Highest priority group at this carbon: Is equatorial and projecting "down" OH E-isomer: Highest priority groups on each carbon projecting in the opposite orientation NH2 Highest priority group at this carbon: Is equatorial, projecting "up" B CH3 Since the compounds in the example above were geometric isomers, you stop here with this example. If they were not you would proceed to step three. STEP THREE: Are these compounds optical isomers? If they are not positional isomers or geometric isomers AND contain an asymmetric ("chiral") center (sp3 hybridized carbon) they may be optical isomers (enantiomers). If such a system is present, assign the absolute configuration of each enantiomer as R or S. IF NOT, GO TO STEP FOUR! 2 Principles of Drug Action I, Winter, 2005 Example: Compounds A and B of this example were already determined to be geometric isomers, therefore THEY CANNOT BE ENANTIOMERS! See additional problems below for possible enantiomers. STEP FOUR: Are these compounds conformational isomers ("confomers" or "rotamers"). If they are not positional, geometric or optical isomers AND they differ only in the spatial orientation of atoms/functional groups as a result of rotation about sp3 hybridized carbons atoms, they may be conformers. If conformational isomerism is present, assign the conformers as "eclipsed", "gauche" or "anti". If you have arrived a this point and the compounds are not positional, geometric, optical or conformation isomers, you have probably made a mistake! Go back to step one and start over. Example: Compounds A and B of this example were already determined to be geometric isomers, therefore THEY CANNOT BE CONFORMERS! See additional problems below for possible conformers. Sample Problems: Apply the method above in attempting to determine the stereochemical relationship between the following pairs of compounds: CH3 CH3 CH Problem 1: H 3 H H H CH3 H H A B H OH H Problem 2: Cl CH3 CH3 OH Cl A B CH H H 3 H Problem 3: H Cl CH H 3 CH Cl H 3 CH3 A B H CH3 H CH3 H Problem 4: H CH3 H H CH3 A B 3 Principles of Drug Action I, Winter, 2005 POSITIONAL, CONFIGURATIONAL (GEOMETRIC & OPTICAL) AND CONFORMATIONAL ISOMERS Cl Positional Isomers: Cl H CH3 CH CH Same atoms/groups but CH2CH3 2 3 in a different relative AND HH bonding arrangement: HCH3 Different properties in all environments! Geometric Isomers: Cl H Same atoms/groups in Cl H CH3 the same relatitive bonding CH2CH3 arrangement, but restricted AND HCH2CH3 rotation with asymmetric Cs HCH3 Different properties in cis (Z) trans (E) all environments! Optical Isomers (Enantiomers): H Cl Cl H Same atoms/groups in CH2CH3 CH2CH3 the same relatitive bonding AND arrangement, but chiral sp3 HCH3 HCH3 with different configurations (R) Different properties in (S) chiral environments! Conformational Isomers: Same atoms/groups in Cl H H the same relatitive bonding CH2CH3 arrangement, same geometry AND CH2CH3 Cl and chiral configuration, but HCH3 different rotational forms. HCH3 Different rotational forms of the same compound! 4.
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