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Chapters 6 and 8 Most chemical systems are governed by equilibria such that if: aA+ bB cC+ dD, then & Activity c d = aa dc )()( = γγ K ba where ax [X], xx is the aa ba )()(

In dilute , γx → ,1 if we assume γx = ,1 DC ][][ dc K = BA ][][ ba

EquilibriumEquilibrium constants constants may may be be written written for for dissociations, dissociations, associations, associations, reactions, reactions, oror distributions. distributions. Equilibrium Constant

aA+ bB cC+ dD

DC ][][ dc K = BA ][][ ba

• If K is very large, that the equilibrium lies far to the right (or towards products). If K is small, the reaction lies towards reactants. • Knowledge of reaction and the equilibrium ©Gary Christian, Analytical , 6th Ed. (Wiley) constant allows us to make some predictions about the system.

Important items to regarding K expressions Equilibrium and 1. All solute should be in mol/L (M). • : 2. All gas concentrations should be in atmospheres. 3. By convention, all K’s are calculated relative to 1 M ΔG o = -RT ln K solutions or 1 atm gas, so the resulting constants are o dimensionless. = eK Δ− G / RT 4. Concentrations of pure solids, pure liquids and solvents are omitted from the equilibrium constant expression. • If K >1 Æ ΔGo<0 Æ Spontaneous Equilibrium constant expressions are Æ o Æ thermodynamic relations. • If K<1 ΔG NOT Spontaneous

1 Using equilibria to characterize (Q) systems The equilibrium constant expression with non- equilibrium concentrations plugged in. : solubility (Ksp) Complexation: formation constants (Kn), • If Q>K, the reaction must proceed to the left cumulative formation constants (βn) (Ch.12) • If Q

Solubility Solubility - Separation by

The solubility product (Ksp) describes the concentrations of precipitation species present when are in equilibrium with undissolved . It is possible to quantitatively separate two or more species based on their solubility.

2+ 2- Ability to do so is related to the magnitudes of the Ksp for each Example: CaCO3 = Ca + CO3 . 2+ 2- 2+ 2- -9 K= [Ca ][CO3 ]/[CaCO3]= [Ca ][CO3 ] = Ksp = 6.0 x 10 Example: What is the of calcium in a saturated Is it possible to precipitate 99% of 0.010M Ce3+ by adding 2- 2+ of calcium ? oxalate (C2O4 ) without precipitate 0.010M Ca -8 This presence of carbonate results in a common ion effect. CaC2O4 Ksp = 1.3 x 10 What should happen? -29 Ce2(C2O4)3 Ksp = 3.0 x 10

Acids and Bases Solubility – Common Ion Effects • Definitions: Lewis – Electrons (acid: electron pair acceptor); BrØnsted-Lowry (acid: proton donor) A salt will be less soluble is one of its constituent • -Base Pairs: related by the gain or loss of one ions is already present in the solution. proton (ex. & ion). • Neutralization Reactions: reactions of acid and base to form salts and • Solvent Autoprotolysis or self-ionization: water is the most common, in which it acts both an acid and a base: + - Example: What is the solubility of ferric 2H2O H 3O +OH - in pH 8.0 buffered aqueous solution OH +H+ H 2O Autoprotolysis constant (equilibrium constants) + + − = − = − = 14 Kw [ 3OH ][OH [] H ][OH ] 10

2 pH Acid and Base Strength

- H O OH +H+ 2 Based on percent dissociation in solution P-function: pX = - log10[X] • Strong acids/bases dissociate essentially completely pH = -log [H+] in water (Table 6-2, p.108) pH > 7 is basic, pH<7 is acidic • Weak acids/bases only partially dissociate, results in - pOH=-log[OH ] equilibrium concentrations of both the acid and its pH + pOH = pKw = 14.00 at 25oC conjugate base Ka - + Ka - + Ex. Concentration of H+ and OH- in pure water at 25oC HA +H2O A +H3O HA A + H -7 ANS: 1.0x10 M Kb + - B + H2O BH +OH

Weak Acid/Base Equilibria Diprotic acids/Dibasic bases Polyprotic acids/Polybasic bases

• Weak Acid: acid (Ka) + − Ka [H ][HA ] HA +H O A- +H O+ − + − + = 2 3 [A ][H O ] [A ][H ] + - Ka1 = 3 = H A H + HA Ka 2 2 AH ][ Ka - + HA A + H HA][ HA][ - + 2- + − HA H + A [H ][A2 ] Ka = • , hydrolysis reaction: base hydrolysis 2 HA− ][ constant (Kb) + − Ka1, Ka2 … [BH ][OH ] Kb + - = + - -3 B + H2O BH +OH Kb H PO H + H PO Ka1 = 7.11 x 10 B][ 3 4 2 4 - + 2- -8 H2PO4 H + HPO4 Ka2 = 6.32 x 10 • Relationship between Ka and Kb for conjugate HPO 2- H+ + PO 3- Ka3 = 7.1 x 10-13 acid/base pairs: 4 4

+ + − =×= − = − = 14 KbKaKw [ 3OH ][OH [] H ][OH ] 10

Complex Formation Activity Formation of coordinate bonds between Lewis Acids/Bases

+ + K1 + If aA+ bB cC+ dD, then Ag aq )( NH 3 (aq) Ag NH 3 aq )()( K2 + Ag NH + aq )()( + NH (aq) Ag NH aq )()( 3 3 23 c d c d aa dc )()( [C] γγ dc [D])()( + + = = Ag NH ])([ Ag NH ])([ K = 3 = 23 ba γγ ba K K + aa ba )()( [A] ba [B])()( 1 [Ag + ][NH ] 2 Ag )([ ][NHNH ] 3 3 3 where ax is the activity of x Formation constants (Kf) are the equilibrium constants for complex ion formation. The overall, or cumulative, formation constants are ax = [X], γγ xx is the activity coefficient denoted βi dc dc + + γγ Ag aq + 2)( NH (aq) Kf Ag NH aq)()( aa dc )()( [C] dc [D])()( 3 23 K = = + ba γγ ba Ag NH ])([ aa ba )()( [A] ba [B])()( K = 23 β ⋅== KK f + 2 2 21 If γx ,1 ax →→ X ][ [Ag ][NH 3 ]

3 Activity Coefficient • Related to the size of the hydrated species • Calculate γ using the extended Debye-Hückel equation, μ 1 2 2 =++= 1 2 which relates activity coefficients to the ability of ions in ( 11 zczc 22 ...) ∑ zc ii solution to interact with one another. 2 2 i where c is concentration and z is charge of each ion .0 51z 2 μ log r −= μα Ex. What is the ionic strength of a 0.010 M Na2SO4? 1+ ½*{(0.020*1)+(0.010*(-2)2)}=0.030 M 305 If add 0.020 M KBr? z = charge of the ion ½*{(0.020*1) + (0.020*1) + (0.020*1) + (0.010*4)}=0.050 M α = effective diameter "hydrated" of the ion in nanometers μ = ionic strength of the solution

Ionic Strength and Ionic Atmospheres Hydrated Radius

• Ions with small ionic radii and large charge tend to more strongly bind to solvent molecules (Ion-dipole interactions).

• The result of this binding is a larger hydrated radius, causing diminished interaction The greater the ionic strength of a solution, the higher the charge in the with other ions. ionic atmosphere. Each ion-plus-atmosphere contains less net charge and there is less attraction between any particular cation and anion.

Ionic Strength, Ion Charge, and Ion Size effect pH Revisited .0 51z 2 μ • Increased ionic conc. Æ log r −= μα • Concentration is replaced with activity decreased activity coefficient 1+ 305 + γ • Increased ion charge (±) Æ pH = -log aH+ = -log [H ] H+ increased departure of activity coefficient from unity (Multiply charged ions are generally more likely to interact with other ions than Examples (P.147): singly charged.) • Calculate the pH of pure water using activity coefficients • Smaller hydrated radius Æ correctly. increased importance of activity effects • Calculate the pH of water containing 0.10 M KCl at 25oC.

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