Subroutines & Stack
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The Instruction Set Architecture
Quiz 0 Lecture 2: The Instruction Set Architecture COS / ELE 375 Computer Architecture and Organization Princeton University Fall 2015 Prof. David August 1 2 Quiz 0 CD 3 Miles of Music 3 4 Pits and Lands Interpretation 0 1 1 1 0 1 0 1 As Music: 011101012 = 117/256 position of speaker As Number: Transition represents a bit state (1/on/red/female/heads) 01110101 = 1 + 4 + 16 + 32 + 64 = 117 = 75 No change represents other state (0/off/white/male/tails) 2 10 16 (Get comfortable with base 2, 8, 10, and 16.) As Text: th 011101012 = 117 character in the ASCII codes = “u” 5 6 Interpretation – ASCII Princeton Computer Science Building West Wall 7 8 Interpretation Binary Code and Data (Hello World!) • Programs consist of Code and Data • Code and Data are Encoded in Bits IA-64 Binary (objdump) As Music: 011101012 = 117/256 position of speaker As Number: 011101012 = 1 + 4 + 16 + 32 + 64 = 11710 = 7516 As Text: th 011101012 = 117 character in the ASCII codes = “u” CAN ALSO BE INTERPRETED AS MACHINE INSTRUCTION! 9 Interfaces in Computer Systems Instructions Sequential Circuit!! Software: Produce Bits Instructing Machine to Manipulate State or Produce I/O Computers process information State Applications • Input/Output (I/O) Operating System • State (memory) • Computation (processor) Compiler Firmware Instruction Set Architecture Input Output Instruction Set Processor I/O System Datapath & Control Computation Digital Design Circuit Design • Instructions instruct processor to manipulate state Layout • Instructions instruct processor to produce I/O in the same way Hardware: Read and Obey Instruction Bits 12 State State – Main Memory Typical modern machine has this architectural state: Main Memory (AKA: RAM – Random Access Memory) 1. -
Writing Fast Fortran Routines for Python
Writing fast Fortran routines for Python Table of contents Table of contents ............................................................................................................................ 1 Overview ......................................................................................................................................... 2 Installation ...................................................................................................................................... 2 Basic Fortran programming ............................................................................................................ 3 A Fortran case study ....................................................................................................................... 8 Maximizing computational efficiency in Fortran code ................................................................. 12 Multiple functions in each Fortran file ......................................................................................... 14 Compiling and debugging ............................................................................................................ 15 Preparing code for f2py ................................................................................................................ 16 Running f2py ................................................................................................................................. 17 Help with f2py .............................................................................................................................. -
Simple Computer Example Register Structure
Simple Computer Example Register Structure Read pp. 27-85 Simple Computer • To illustrate how a computer operates, let us look at the design of a very simple computer • Specifications 1. Memory words are 16 bits in length 2. 2 12 = 4 K words of memory 3. Memory can be accessed in one clock cycle 4. Single Accumulator for ALU (AC) 5. Registers are fully connected Simple Computer Continued 4K x 16 Memory MAR 12 MDR 16 X PC 12 ALU IR 16 AC Simple Computer Specifications (continued) 6. Control signals • INCPC – causes PC to increment on clock edge - [PC] +1 PC •ACin - causes output of ALU to be stored in AC • GMDR2X – get memory data register to X - [MDR] X • Read (Write) – Read (Write) contents of memory location whose address is in MAR To implement instructions, control unit must break down the instruction into a series of register transfers (just like a complier must break down C program into a series of machine level instructions) Simple Computer (continued) • Typical microinstruction for reading memory State Register Transfer Control Line(s) Next State 1 [[MAR]] MDR Read 2 • Timing State 1 State 2 During State 1, Read set by control unit CLK - Data is read from memory - MDR changes at the Read beginning of State 2 - Read is completed in one clock cycle MDR Simple Computer (continued) • Study: how to write the microinstructions to implement 3 instructions • ADD address • ADD (address) • JMP address ADD address: add using direct addressing 0000 address [AC] + [address] AC ADD (address): add using indirect addressing 0001 address [AC] + [[address]] AC JMP address 0010 address address PC Instruction Format for Simple Computer IR OP 4 AD 12 AD = address - Two phases to implement instructions: 1. -
Cognitive Programming Language (CPL) Programmer's Guide
Cognitive Programming Language (CPL) Programmer's Guide 105-008-02 Revision C2 – 3/17/2006 *105-008-02* Copyright © 2006, Cognitive. Cognitive™, Cxi™, and Ci™ are trademarks of Cognitive. Microsoft® and Windows™ are trademarks of Microsoft Corporation. Other product and corporate names used in this document may be trademarks or registered trademarks of other companies, and are used only for explanation and to their owner’s benefit, without intent to infringe. All information in this document is subject to change without notice, and does not represent a commitment on the part of Cognitive. No part of this document may be reproduced for any reason or in any form, including electronic storage and retrieval, without the express permission of Cognitive. All program listings in this document are copyrighted and are the property of Cognitive and are provided without warranty. To contact Cognitive: Cognitive Solutions, Inc. 4403 Table Mountain Drive Suite A Golden, CO 80403 E-Mail: [email protected] Telephone: +1.800.525.2785 Fax: +1.303.273.1414 Table of Contents Introduction.............................................................................................. 1 Label Format Organization .................................................................. 2 Command Syntax................................................................................ 2 Important Programming Rules............................................................. 3 Related Publications........................................................................... -
PIC Family Microcontroller Lesson 02
Chapter 13 PIC Family Microcontroller Lesson 02 Architecture of PIC 16F877 Internal hardware for the operations in a PIC family MCU direct Internal ID, control, sequencing and reset circuits address 7 14-bit Instruction register 8 MUX program File bus Select 8 Register 14 8 8 W Register (Accumulator) ADDR Status Register MUX Flash Z, C and DC 9 Memory Data Internal EEPROM RAM 13 Peripherals 256 Byte Program Registers counter Ports data 368 Byte 13 bus 2011 Microcontrollers-... 2nd Ed. Raj KamalA to E 3 8-level stack (13-bit) Pearson Education 8 ALU Features • Supports 8-bit operations • Internal data bus is of 8-bits 2011 Microcontrollers-... 2nd Ed. Raj Kamal 4 Pearson Education ALU Features • ALU operations between the Working (W) register (accumulator) and register (or internal RAM) from a register-file • ALU operations can also be between the W and 8-bits operand from instruction register (IR) • The operations also use three flags Z, C and DC/borrow. [Zero flag, Carry flag and digit (nibble) carry flag] 2011 Microcontrollers-... 2nd Ed. Raj Kamal 5 Pearson Education ALU features • The destination of result from ALU operations can be either W or register (f) in file • The flags save at status register (STATUS) • PIC CPU is a one-address machine (one operand specified in the instruction for ALU) 2011 Microcontrollers-... 2nd Ed. Raj Kamal 6 Pearson Education ALU features • Two operands are used in an arithmetic or logic operations • One is source operand from one a register file/RAM (or operand from instruction) and another is W-register • Advantage—ALU directly operates on a register or memory similar to 8086 CPU 2011 Microcontrollers-.. -
A Simple Processor
CS 240251 SpringFall 2019 2020 FoundationsPrinciples of Programming of Computer Languages Systems λ Ben Wood A Simple Processor 1. A simple Instruction Set Architecture 2. A simple microarchitecture (implementation): Data Path and Control Logic https://cs.wellesley.edu/~cs240/s20/ A Simple Processor 1 Program, Application Programming Language Compiler/Interpreter Software Operating System Instruction Set Architecture Microarchitecture Digital Logic Devices (transistors, etc.) Hardware Solid-State Physics A Simple Processor 2 Instruction Set Architecture (HW/SW Interface) processor memory Instructions • Names, Encodings Instruction Encoded • Effects Logic Instructions • Arguments, Results Registers Data Local storage • Names, Size • How many Large storage • Addresses, Locations Computer A Simple Processor 3 Computer Microarchitecture (Implementation of ISA) Instruction Fetch and Registers ALU Memory Decode A Simple Processor 4 (HW = Hardware or Hogwarts?) HW ISA An example made-up instruction set architecture Word size = 16 bits • Register size = 16 bits. • ALU computes on 16-bit values. Memory is byte-addressable, accesses full words (byte pairs). 16 registers: R0 - R15 • R0 always holds hardcoded 0 Address Contents • R1 always holds hardcoded 1 0 First instruction, low-order byte • R2 – R15: general purpose 1 First instruction, Instructions are 1 word in size. high-order byte 2 Second instruction, Separate instruction memory. low-order byte Program Counter (PC) register ... ... • holds address of next instruction to execute. A Simple Processor 5 R: Register File M: Data Memory Reg Contents Reg Contents Address Contents R0 0x0000 R8 0x0 – 0x1 R1 0x0001 R9 0x2 – 0x3 R2 R10 0x4 – 0x5 R3 R11 0x6 – 0x7 R4 R12 0x8 – 0x9 R5 R13 0xA – 0xB R6 R14 0xC – 0xD R7 R15 … Program Counter IM: Instruction Memory PC Address Contents 0x0 – 0x1 ß Processor 1. -
A Compiler for a Simple Language. V0.16
Project step 1 – a compiler for a simple language. v0.16 Change log: v0.16, changes from 0.15 Make all push types in compiler actions explicit. Simplified and better documentation of call and callr instruction compiler actions. Let the print statement print characters and numbers. Added a printv statement to print variables. Changed compiler actions for retr to push a variable value, not a literal value. Changes are shown in orange. v0.15, changes from 0.14 Change compiler actions for ret, retr, jmp. Change the description and compiler actions for poke. Change the description for swp. Change the compiler actions for call and callr. Changes shown in green. v0.14, changes from 0.13 Add peek, poke and swp instructions. Change popm compiler actions. Change callr compiler actions. Other small changes to wording. Changes are shown in blue. v0.13, changes from 0.12 Add a count field to subr, call and callr to simplify code generation. Changes are shown in red. v0.12 Changes from 0.11. Added a callr statement that takes a return type. Fix the generated code for this and for call to allow arguments to be pushed by the call. Add a retr that returns a value and update the reg. v0.11: changes from 0.10. Put typing into push operators. Put opcodes for compare operators. fix actions for call. Make declarations reserve a stack location. Remove redundant store instruction (popv does the same thing.) v0.10: changes from 0.0. Comparison operators (cmpe, cmplt, cmpgt) added. jump conditional (jmpc) added. bytecode values added. -
Scope in Fortran 90
Scope in Fortran 90 The scope of objects (variables, named constants, subprograms) within a program is the portion of the program in which the object is visible (can be use and, if it is a variable, modified). It is important to understand the scope of objects not only so that we know where to define an object we wish to use, but also what portion of a program unit is effected when, for example, a variable is changed, and, what errors might occur when using identifiers declared in other program sections. Objects declared in a program unit (a main program section, module, or external subprogram) are visible throughout that program unit, including any internal subprograms it hosts. Such objects are said to be global. Objects are not visible between program units. This is illustrated in Figure 1. Figure 1: The figure shows three program units. Main program unit Main is a host to the internal function F1. The module program unit Mod is a host to internal function F2. The external subroutine Sub hosts internal function F3. Objects declared inside a program unit are global; they are visible anywhere in the program unit including in any internal subprograms that it hosts. Objects in one program unit are not visible in another program unit, for example variable X and function F3 are not visible to the module program unit Mod. Objects in the module Mod can be imported to the main program section via the USE statement, see later in this section. Data declared in an internal subprogram is only visible to that subprogram; i.e. -
Programming Basics - FORTRAN 77
CWCS Workshop May 2005 Programming Basics - FORTRAN 77 http://www.physics.nau.edu/~bowman/PHY520/F77tutor/tutorial_77.html Program Organization A FORTRAN program is just a sequence of lines of plain text. This is called the source code. The text has to follow certain rules (syntax) to be a valid FORTRAN program. We start by looking at a simple example: program circle real r, area, pi c This program reads a real number r and prints c the area of a circle with radius r. write (*,*) 'Give radius r:' read (*,*) r pi = atan(1.0e0)*4.0e0 area = pi*r*r write (*,*) 'Area = ', area end A FORTRAN program generally consists of a main program and possibly several subprograms (i.e., functions or subroutines). The structure of a main program is: program name declarations statements end Note: Words that are in italics should not be taken as literal text, but rather as a description of what belongs in their place. FORTRAN is not case-sensitive, so "X" and "x" are the same variable. Blank spaces are ignored in Fortran 77. If you remove all blanks in a Fortran 77 program, the program is still acceptable to a compiler but almost unreadable to humans. Column position rules Fortran 77 is not a free-format language, but has a very strict set of rules for how the source code should be formatted. The most important rules are the column position rules: Col. 1: Blank, or a "c" or "*" for comments Col. 1-5: Blank or statement label Col. 6: Blank or a "+" for continuation of previous line Col. -
MIPS: Design and Implementation
FACULTEIT INGENIEURSWETENSCHAPPEN MIPS: Design and Implementation Computerarchitectuur 1MA Industriele¨ Wetenschappen Elektronica-ICT 2014-10-20 Laurent Segers Contents Introduction......................................3 1 From design to VHDL4 1.1 The factorial algorithm.............................4 1.2 Building modules................................5 1.2.1 A closer look..............................6 1.2.2 VHDL..................................7 1.3 Design in VHDL................................8 1.3.1 Program Counter............................8 1.3.2 Instruction Memory........................... 14 1.3.3 Program Counter Adder........................ 15 1.4 Bringing it all together - towards the MIPS processor............ 15 2 Design validation 19 2.1 Instruction Memory............................... 19 2.2 Program Counter................................ 22 2.3 Program Counter Adder............................ 23 2.4 The MIPS processor.............................. 23 3 Porting to FPGA 25 3.1 User Constraints File.............................. 25 4 Additional features 27 4.1 UART module.................................. 27 4.1.1 Connecting the UART-module to the MIPS processor........ 28 4.2 Reprogramming the MIPS processor..................... 29 A Xilinx ISE software 30 A.1 Creating a new project............................. 30 A.2 Adding a new VHDL-module......................... 30 A.3 Creating an User Constraints File....................... 30 A.4 Testbenches................................... 31 A.4.1 Creating testbenches.......................... 31 A.4.2 Running testbenches.......................... 31 2 Introduction Nowadays, most programmers write their applications in what we call \the Higher Level Programming languages", such as Java, C#, Delphi, etc. These applications are then compiled into machine code. In order to run this machine code the underlying hardware needs be able to \understand" the proposed code. The aim of this practical course is to give an inside on the principles of a working system. -
Fortran 90 Programmer's Reference
Fortran 90 Programmer’s Reference First Edition Product Number: B3909DB Fortran 90 Compiler for HP-UX Document Number: B3908-90002 October 1998 Edition: First Document Number: B3908-90002 Remarks: Released October 1998. Initial release. Notice Copyright Hewlett-Packard Company 1998. All Rights Reserved. Reproduction, adaptation, or translation without prior written permission is prohibited, except as allowed under the copyright laws. The information contained in this document is subject to change without notice. Hewlett-Packard makes no warranty of any kind with regard to this material, including, but not limited to, the implied warranties of merchantability and fitness for a particular purpose. Hewlett-Packard shall not be liable for errors contained herein or for incidental or consequential damages in connection with the furnishing, performance or use of this material. Contents Preface . xix New in HP Fortran 90 V2.0. .xx Scope. xxi Notational conventions . xxii Command syntax . xxiii Associated documents . xxiv 1 Introduction to HP Fortran 90 . 1 HP Fortran 90 features . .2 Source format . .2 Data types . .2 Pointers . .3 Arrays . .3 Control constructs . .3 Operators . .4 Procedures. .4 Modules . .5 I/O features . .5 Intrinsics . .6 2 Language elements . 7 Character set . .8 Lexical tokens . .9 Names. .9 Program structure . .10 Statement labels . .10 Statements . .11 Source format of program file . .13 Free source form . .13 Source lines . .14 Statement labels . .14 Spaces . .14 Comments . .15 Statement continuation . .15 Fixed source form . .16 Spaces . .16 Source lines . .16 Table of Contents i INCLUDE line . 19 3 Data types and data objects . 21 Intrinsic data types . 22 Type declaration for intrinsic types . -
Control Flow Graphs • Can Be Done at High Level Or Low Level – E.G., Constant Folding
Optimizations • Code transformations to improve program – Mainly: improve execution time – Also: reduce program size Control Flow Graphs • Can be done at high level or low level – E.g., constant folding • Optimizations must be safe – Execution of transformed code must yield same results as the original code for all possible executions 1 2 Optimization Safety Optimization Safety • Safety of code transformations usually requires certain • Safety of code transformations usually requires certain information that may not be explicit in the code information which may not explicit in the code • Example: dead code elimination • Example: dead code elimination (1) x = y + 1; (1) x = y + 1; (2) y = 2 * z; (2) y = 2 * z; (3) x=y+z;x = y + z; (3) x=y+z;x = y + z; (4) z = 1; (4) z = 1; (5) z = x; (5) z = x; • What statements are dead and can be removed? • Need to know whether values assigned to x at (1) is never used later (i.e., x is dead at statement (1)) – Obvious for this simple example (with no control flow) – Not obvious for complex flow of control 3 4 1 Dead Variable Example Dead Variable Example • Add control flow to example: • Add control flow to example: x = y + 1; x = y + 1; y = 2 * z; y = 2 * z; if (d) x = y+z; if (d) x = y+z; z = 1; z = 1; z = x; z = x; • Statement x = y+1 is not dead code! • Is ‘x = y+1’ dead code? Is ‘z = 1’ dead code? •On some executions, value is used later 5 6 Dead Variable Example Dead Variable Example • Add more control flow: • Add more control flow: while (c) { while (c) { x = y + 1; x = y + 1; y = 2 * z; y = 2