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10-1 CHAPTER 10 DEFORMATION 10.1 Stress-Strain Diagrams And
EN380 Naval Materials Science and Engineering Course Notes, U.S. Naval Academy CHAPTER 10 DEFORMATION 10.1 Stress-Strain Diagrams and Material Behavior 10.2 Material Characteristics 10.3 Elastic-Plastic Response of Metals 10.4 True stress and strain measures 10.5 Yielding of a Ductile Metal under a General Stress State - Mises Yield Condition. 10.6 Maximum shear stress condition 10.7 Creep Consider the bar in figure 1 subjected to a simple tension loading F. Figure 1: Bar in Tension Engineering Stress () is the quotient of load (F) and area (A). The units of stress are normally pounds per square inch (psi). = F A where: is the stress (psi) F is the force that is loading the object (lb) A is the cross sectional area of the object (in2) When stress is applied to a material, the material will deform. Elongation is defined as the difference between loaded and unloaded length ∆푙 = L - Lo where: ∆푙 is the elongation (ft) L is the loaded length of the cable (ft) Lo is the unloaded (original) length of the cable (ft) 10-1 EN380 Naval Materials Science and Engineering Course Notes, U.S. Naval Academy Strain is the concept used to compare the elongation of a material to its original, undeformed length. Strain () is the quotient of elongation (e) and original length (L0). Engineering Strain has no units but is often given the units of in/in or ft/ft. ∆푙 휀 = 퐿 where: is the strain in the cable (ft/ft) ∆푙 is the elongation (ft) Lo is the unloaded (original) length of the cable (ft) Example Find the strain in a 75 foot cable experiencing an elongation of one inch. -
Bending Stress
Bending Stress Sign convention The positive shear force and bending moments are as shown in the figure. Figure 40: Sign convention followed. Centroid of an area Scanned by CamScanner If the area can be divided into n parts then the distance Y¯ of the centroid from a point can be calculated using n ¯ Âi=1 Aiy¯i Y = n Âi=1 Ai where Ai = area of the ith part, y¯i = distance of the centroid of the ith part from that point. Second moment of area, or moment of inertia of area, or area moment of inertia, or second area moment For a rectangular section, moments of inertia of the cross-sectional area about axes x and y are 1 I = bh3 x 12 Figure 41: A rectangular section. 1 I = hb3 y 12 Scanned by CamScanner Parallel axis theorem This theorem is useful for calculating the moment of inertia about an axis parallel to either x or y. For example, we can use this theorem to calculate . Ix0 = + 2 Ix0 Ix Ad Bending stress Bending stress at any point in the cross-section is My s = − I where y is the perpendicular distance to the point from the centroidal axis and it is assumed +ve above the axis and -ve below the axis. This will result in +ve sign for bending tensile (T) stress and -ve sign for bending compressive (C) stress. Largest normal stress Largest normal stress M c M s = | |max · = | |max m I S where S = section modulus for the beam. For a rectangular section, the moment of inertia of the cross- 1 3 1 2 sectional area I = 12 bh , c = h/2, and S = I/c = 6 bh . -
Guide to Rheological Nomenclature: Measurements in Ceramic Particulate Systems
NfST Nisr National institute of Standards and Technology Technology Administration, U.S. Department of Commerce NIST Special Publication 946 Guide to Rheological Nomenclature: Measurements in Ceramic Particulate Systems Vincent A. Hackley and Chiara F. Ferraris rhe National Institute of Standards and Technology was established in 1988 by Congress to "assist industry in the development of technology . needed to improve product quality, to modernize manufacturing processes, to ensure product reliability . and to facilitate rapid commercialization ... of products based on new scientific discoveries." NIST, originally founded as the National Bureau of Standards in 1901, works to strengthen U.S. industry's competitiveness; advance science and engineering; and improve public health, safety, and the environment. One of the agency's basic functions is to develop, maintain, and retain custody of the national standards of measurement, and provide the means and methods for comparing standards used in science, engineering, manufacturing, commerce, industry, and education with the standards adopted or recognized by the Federal Government. As an agency of the U.S. Commerce Department's Technology Administration, NIST conducts basic and applied research in the physical sciences and engineering, and develops measurement techniques, test methods, standards, and related services. The Institute does generic and precompetitive work on new and advanced technologies. NIST's research facilities are located at Gaithersburg, MD 20899, and at Boulder, CO 80303. -
Navier-Stokes-Equation
Math 613 * Fall 2018 * Victor Matveev Derivation of the Navier-Stokes Equation 1. Relationship between force (stress), stress tensor, and strain: Consider any sub-volume inside the fluid, with variable unit normal n to the surface of this sub-volume. Definition: Force per area at each point along the surface of this sub-volume is called the stress vector T. When fluid is not in motion, T is pointing parallel to the outward normal n, and its magnitude equals pressure p: T = p n. However, if there is shear flow, the two are not parallel to each other, so we need a marix (a tensor), called the stress-tensor , to express the force direction relative to the normal direction, defined as follows: T Tn or Tnkjjk As we will see below, σ is a symmetric matrix, so we can also write Tn or Tnkkjj The difference in directions of T and n is due to the non-diagonal “deviatoric” part of the stress tensor, jk, which makes the force deviate from the normal: jkp jk jk where p is the usual (scalar) pressure From general considerations, it is clear that the only source of such “skew” / ”deviatoric” force in fluid is the shear component of the flow, described by the shear (non-diagonal) part of the “strain rate” tensor e kj: 2 1 jk2ee jk mm jk where euujk j k k j (strain rate tensro) 3 2 Note: the funny construct 2/3 guarantees that the part of proportional to has a zero trace. The two terms above represent the most general (and the only possible) mathematical expression that depends on first-order velocity derivatives and is invariant under coordinate transformations like rotations. -
Using Lenterra Shear Stress Sensors to Measure Viscosity
Application Note: Using Lenterra Shear Stress Sensors to Measure Viscosity Guidelines for using Lenterra’s shear stress sensors for in-line, real-time measurement of viscosity in pipes, thin channels, and high-shear mixers. Shear Stress and Viscosity Shear stress is a force that acts on an object that is directed parallel to its surface. Lenterra’s RealShear™ sensors directly measure the wall shear stress caused by flowing or mixing fluids. As an example, when fluids pass between a rotor and a stator in a high-shear mixer, shear stress is experienced by the fluid and the surfaces that it is in contact with. A RealShear™ sensor can be mounted on the stator to measure this shear stress, as a means to monitor mixing processes or facilitate scale-up. Shear stress and viscosity are interrelated through the shear rate (velocity gradient) of a fluid: ∂u τ = µ = γµ & . ∂y Here τ is the shear stress, γ˙ is the shear rate, µ is the dynamic viscosity, u is the velocity component of the fluid tangential to the wall, and y is the distance from the wall. When the viscosity of a fluid is not a function of shear rate or shear stress, that fluid is described as “Newtonian.” In non-Newtonian fluids the viscosity of a fluid depends on the shear rate or stress (or in some cases the duration of stress). Certain non-Newtonian fluids behave as Newtonian fluids at high shear rates and can be described by the equation above. For others, the viscosity can be expressed with certain models. -
Equation of Motion for Viscous Fluids
1 2.25 Equation of Motion for Viscous Fluids Ain A. Sonin Department of Mechanical Engineering Massachusetts Institute of Technology Cambridge, Massachusetts 02139 2001 (8th edition) Contents 1. Surface Stress …………………………………………………………. 2 2. The Stress Tensor ……………………………………………………… 3 3. Symmetry of the Stress Tensor …………………………………………8 4. Equation of Motion in terms of the Stress Tensor ………………………11 5. Stress Tensor for Newtonian Fluids …………………………………… 13 The shear stresses and ordinary viscosity …………………………. 14 The normal stresses ……………………………………………….. 15 General form of the stress tensor; the second viscosity …………… 20 6. The Navier-Stokes Equation …………………………………………… 25 7. Boundary Conditions ………………………………………………….. 26 Appendix A: Viscous Flow Equations in Cylindrical Coordinates ………… 28 ã Ain A. Sonin 2001 2 1 Surface Stress So far we have been dealing with quantities like density and velocity, which at a given instant have specific values at every point in the fluid or other continuously distributed material. The density (rv ,t) is a scalar field in the sense that it has a scalar value at every point, while the velocity v (rv ,t) is a vector field, since it has a direction as well as a magnitude at every point. Fig. 1: A surface element at a point in a continuum. The surface stress is a more complicated type of quantity. The reason for this is that one cannot talk of the stress at a point without first defining the particular surface through v that point on which the stress acts. A small fluid surface element centered at the point r is defined by its area A (the prefix indicates an infinitesimal quantity) and by its outward v v unit normal vector n . -
Review of Fluid Mechanics Terminology
CBE 6333, R. Levicky 1 Review of Fluid Mechanics Terminology The Continuum Hypothesis: We will regard macroscopic behavior of fluids as if the fluids are perfectly continuous in structure. In reality, the matter of a fluid is divided into fluid molecules, and at sufficiently small (molecular and atomic) length scales fluids cannot be viewed as continuous. However, since we will only consider situations dealing with fluid properties and structure over distances much greater than the average spacing between fluid molecules, we will regard a fluid as a continuous medium whose properties (density, pressure etc.) vary from point to point in a continuous way. For the problems that we will be interested in, the microscopic details of fluid structure will not be needed and the continuum approximation will be appropriate. However, there are situations when molecular level details are important; for instance when the dimensions of a channel that the fluid is flowing through become comparable to the mean free paths of the fluid molecules or to the molecule size. In such instances, the continuum hypothesis does not apply. Fluid : a substance that will deform continuously in response to a shear stress no matter how small the stress may be. Shear Stress : Force per unit area that is exerted parallel to the surface on which it acts. 2 Shear stress units: Force/Area, ex. N/m . Usual symbols: σij , τij (i ≠j). Example 1: shear stress between a block and a surface: Example 2: A simplified picture of the shear stress between two laminas (layers) in a flowing liquid. The top layer moves relative to the bottom one by a velocity ∆V, and collision interactions between the molecules of the two layers give rise to shear stress. -
Bending Moment & Shear Force
Strength of Materials Prof. M. S. Sivakumar Problem 1: Computation of Reactions Problem 2: Computation of Reactions Problem 3: Computation of Reactions Problem 4: Computation of forces and moments Problem 5: Bending Moment and Shear force Problem 6: Bending Moment Diagram Problem 7: Bending Moment and Shear force Problem 8: Bending Moment and Shear force Problem 9: Bending Moment and Shear force Problem 10: Bending Moment and Shear force Problem 11: Beams of Composite Cross Section Indian Institute of Technology Madras Strength of Materials Prof. M. S. Sivakumar Problem 1: Computation of Reactions Find the reactions at the supports for a simple beam as shown in the diagram. Weight of the beam is negligible. Figure: Concepts involved • Static Equilibrium equations Procedure Step 1: Draw the free body diagram for the beam. Step 2: Apply equilibrium equations In X direction ∑ FX = 0 ⇒ RAX = 0 In Y Direction ∑ FY = 0 Indian Institute of Technology Madras Strength of Materials Prof. M. S. Sivakumar ⇒ RAY+RBY – 100 –160 = 0 ⇒ RAY+RBY = 260 Moment about Z axis (Taking moment about axis pasing through A) ∑ MZ = 0 We get, ∑ MA = 0 ⇒ 0 + 250 N.m + 100*0.3 N.m + 120*0.4 N.m - RBY *0.5 N.m = 0 ⇒ RBY = 656 N (Upward) Substituting in Eq 5.1 we get ∑ MB = 0 ⇒ RAY * 0.5 + 250 - 100 * 0.2 – 120 * 0.1 = 0 ⇒ RAY = -436 (downwards) TOP Indian Institute of Technology Madras Strength of Materials Prof. M. S. Sivakumar Problem 2: Computation of Reactions Find the reactions for the partially loaded beam with a uniformly varying load shown in Figure. -
Shear Force and Bending Moment in Beams and Frames CHAPTER2
Shear Force and Bending Moment in Beams and Frames CHAPTER2 2.0 INTRODUCTION To bridge a gap in land on earth is most pressing problem for structural engineers. Slabs, beams or any combination of these are extensively used in bridging gaps. Construction of bridges, covering of door and window openings and covering of roof of enclosures are examples where beams and slabs are used. The space below a beam is available for other use. Structural actions of beams and slabs are slightly different. A beam collects fl oor load and transfers it longitudinally to the supports, which are usually provided either at both ends (beam action) or at one end only (cantilever action). Cantilevers are used in construction of balconies in homes and footpaths in bridges. A slab transfers fl oor load in both directions whereas a beam transfers fl oor load in only longitudinal direction. Therefore, a beam is a one-dimensional structural element and it can be represented by a line as shown in Fig. 2.1(b) in which arrow shows the direction of load transfer. Mechanical engineers extensively use cantilevers. The boom of a crane, the cutting blade of a bulldozer and wings of a fan are few examples of cantilevers. The span of beam or cantilever, which is defi ned as distance between adjacent supports, governs the complexity of its design. Shear force and bending moment diagrams quantify structural action of beams and cantilevers and are required for their rational design. Beams and cantilevers shown in Fig. 2.1 are known as fl exural elements. -
Glossary of Notations
108 GLOSSARY OF NOTATIONS A = Earthquake peak ground acceleration. IρM = Soil influence coefficient for moment. = A0 Cross-sectional area of the stream. K1, K2, = aB Barge bow damage depth. K3, and K4 = Scour coefficients that account for the nose AF = Annual failure rate. shape of the pier, the angle between the direction b = River channel width. of the flow and the direction of the pier, the BR = Vehicular braking force. streambed conditions, and the bed material size. = BRa Aberrancy base rate. Kp = Rankine coefficient. = = bx Bias of ¯x x/xn. KR = Pile flexibility factor, which gives the relative c = Wind analysis constant. stiffness of the pile and soil. C′=Response spectrum modeling parameter. L = Foundation depth. = CE Vehicular centrifugal force. Le = Effective depth of foundation (distance from = CF Cost of failure. ground level to point of fixity). = CH Hydrodynamic coefficient that accounts for the effect LL = Vehicular live load. of surrounding water on vessel collision forces. LOA = Overall length of vessel. = CI Initial cost for building bridge structure. LS = Live load surcharge. = Cp Wind pressure coefficient. max(x) = Maximum of all possible x values. = CR Creep. M = Moment capacity. = cap CT Expected total cost of building bridge structure. M = Moment capacity of column. = col CT Vehicular collision force. M = Design moment. = design CV Vessel collision force. n = Manning roughness coefficient. = D Diameter of pile or column. N = Number of vessels (or flotillas) of type i. = i DC Dead load of structural components and nonstructural PA = Probability of aberrancy. attachments. P = Nominal design force for ship collisions. DD = Downdrag. B P = Base wind pressure. -
On the Generation of Vorticity at a Free-Surface
Center for TurbulenceResearch Annual Research Briefs On the generation of vorticity at a freesurface By T Lundgren AND P Koumoutsakos Motivations and ob jectives In free surface ows there are many situations where vorticityenters a owin the form of a shear layer This o ccurs at regions of high surface curvature and sup ercially resembles separation of a b oundary layer at a solid b oundary corner but in the free surface ow there is very little b oundary layer vorticity upstream of the corner and the vorticity whichenters the owisentirely created at the corner Ro o d has asso ciated the ux of vorticityinto the ow with the deceleration ofalayer of uid near the surface These eects are quite clearly seen in spilling breaker ows studied by Duncan Philomin Lin Ro ckwell and Dabiri Gharib In this pap er we prop ose a description of free surface viscous ows in a vortex dynamics formulation In the vortex dynamics approach to uid dynamics the emphasis is on the vorticityvector which is treated as the primary variable the velo city is expressed as a functional of the vorticity through the BiotSavart integral In free surface viscous ows the surface app ears as a source or sink of vorticityand a suitable pro cedure is required to handle this as a vorticity b oundary condition As a conceptually attractivebypro duct of this study we nd that vorticityis conserved if one considers the vortex sheet at the free surface to contain surface vorticity Vorticity which uxes out of the uid and app ears to b e lost is really gained by the vortex sheet -
Stress, Cauchy's Equation and the Navier-Stokes Equations
Chapter 3 Stress, Cauchy’s equation and the Navier-Stokes equations 3.1 The concept of traction/stress • Consider the volume of fluid shown in the left half of Fig. 3.1. The volume of fluid is subjected to distributed external forces (e.g. shear stresses, pressures etc.). Let ∆F be the resultant force acting on a small surface element ∆S with outer unit normal n, then the traction vector t is defined as: ∆F t = lim (3.1) ∆S→0 ∆S ∆F n ∆F ∆ S ∆ S n Figure 3.1: Sketch illustrating traction and stress. • The right half of Fig. 3.1 illustrates the concept of an (internal) stress t which represents the traction exerted by one half of the fluid volume onto the other half across a ficticious cut (along a plane with outer unit normal n) through the volume. 3.2 The stress tensor • The stress vector t depends on the spatial position in the body and on the orientation of the plane (characterised by its outer unit normal n) along which the volume of fluid is cut: ti = τij nj , (3.2) where τij = τji is the symmetric stress tensor. • On an infinitesimal block of fluid whose faces are parallel to the axes, the component τij of the stress tensor represents the traction component in the positive i-direction on the face xj = const. whose outer normal points in the positive j-direction (see Fig. 3.2). 6 MATH35001 Viscous Fluid Flow: Stress, Cauchy’s equation and the Navier-Stokes equations 7 x3 x3 τ33 τ22 τ τ11 12 τ21 τ τ 13 23 τ τ 32τ 31 τ 31 32 τ τ τ 23 13 τ21 τ τ τ 11 12 22 33 x1 x2 x1 x2 Figure 3.2: Sketch illustrating the components of the stress tensor.