Lecture 17 Atomic Structure & Spectra

Total Page:16

File Type:pdf, Size:1020Kb

Lecture 17 Atomic Structure & Spectra LECTURE 17 ATOMIC STRUCTURE & SPECTRA Instructor: Kazumi Tolich Lecture 17 2 ¨ Reading chapter 36-1 to 36-3 & 36-6 ¤ Atoms ¤ The Bohr model of the hydrogen atom ¤ Quantum theory of atoms ¤ The periodic table Atoms 3 ¨ 118 chemical elements have been discovered as of today. ¨ 94 chemical elements are naturally occurring on Earth. ¨ Each element is characterized by a number of protons, atomic number, Z. ¨ A neutral atom contains an equal number of protons and electrons. Atomic emission of light 4 ¨ The spacing and relative intensities of spectral lines in a spectrograph are Hydrogen emission spectrum characteristic of the element. Mercury emission spectrum Gas discharge tube Demo 1 5 ¨ Line Spectra ¤ Hydrogen, neon, mercury, and helium emission tubes are examined with transmission gratings. Thomson’s plum-pudding model of the atom 6 ¨ In 1904, J. J. Thomson, who discovered electrons, proposed the “plum-pudding model.” ¤ Atoms consist of a “cloud” of positive charge roughly 10-10 m in diameter. It was known that electrons are much smaller and less massive than atoms. ¤ Electrons are embedded like plums in a plum pudding. Rutherford’s model of the atom 7 ¨ Around 1911 Ernest Rutherford, with his students, showed that the positive charge and most of the mass of an atom is concentrated in a very small region (~1 fm), now called the nucleus. ¨ The majority of alpha particles fired at gold atoms were deflected through only a small angle, but a small number were deflected by a large angle. ¨ “It was quite the most incredible event that ever happened to me in my life. It was almost as incredible as if you had fired a 15-inch shell at a piece of tissue paper, and it came back and hit you.” Classical planetary model of H 8 ¨ The electron (−�) of the hydrogen atom moves in a circular orbit around the positive nucleus (+��) according to Coulomb’s law. ¨ The energy of the system is the sum of the kinetic energy of the electron plus the potential energy stored between the electron and the nucleus: 1 ��, � = − 8��+ � ¨ Classical EM theory says that an electron in a circular orbit is accelerating, so it would radiate an EM wave and loses its energy. ¨ This atom would quickly collapse as the electron spirals into the nucleus and radiates away the energy. Bohr’s postulate 1 9 ¨ As a solution for the collapsing atom problem, Bohr postulated that ¤ only certain “stationary states” are allowed. ¤ an atom with an electron in a stationary state does not radiate. ¤ an atom radiates only when the electron makes a transition from one stationary state to another. The electron in the hydrogen atom can move only in certain non- radiating, circular orbits called stationary states. Bohr’s postulate 2 10 ¨ The 2nd postulate relates the frequency of radiation, �, to the energies of the stationary states, E. � − � ��, 1 1 � = / 0 = − ℎ 8��+ℎ �0 �/ ¤ where Ei and Ef are the initial and final energies of the atom, and ri and rf are the radii of the initial and final orbits, respectively. Bohr’s postulate 3 11 4 4 ¨ From the Rydberg-Ritz formula, � = �� 6 − 6 , and Bohr’s 2nd postulate, 56 57 896 4 4 � = − , it is evident that r of stable orbits must be proportional :;<=> ?@ ?A to n2. ¨ Bohr postulated that the magnitude of the angular momentum of the electron in a stable orbit is given by 5> � ≡ �� � = �ℏ = , where � = 1,2,3, … 5 5 5 ,; Radii of Bohr orbits 12 ¨ The centripetal force on the electron is the Coulomb’s force. ¨ The orbital electron has the angular momentum given by Bohr’ 3rd postulate. ¨ The radii of the stationary state orbits: , 4��+ℏ �+ 0.0529 nm � = �, ≡ �, = �, 5 ���, � � �+: first Bohr radius Energy Levels in Bohr H 13 ¨ There is an energy level in H corresponding to each stationary state radius. �, ��U � = − 5 , , , , � 32� �+ ℏ �, �, � = − � = −13.6 eV 5 �, + �, Ionization 14 ¨ Removing an electron from an atom is called ionization. ¨ The minimum energy required to ionize the atom is the ionization energy. ¨ In a H atom in its ground state, electron is bound to the atom by the binding energy of 13.6 eV. ¨ The ionization energy of the ground-state hydrogen atom is 13.6 eV. Ground state Example 1 15 a) What is the wavelength of the least energetic photon emitted in the Lyman series of the hydrogen atom spectrum lines? b) What is the wavelength of the most energetic photon emitted in the Lyman series? Paschen Balmer Series Series (IR) (Visible) Lyman Series (UV) Success and failure 16 ¨ Bohr explained the stability and discrete spectra of H by introducing stationary states. ¨ However, there were problems. ¤ There was no justification for the stationary states or for the quantization of angular momentum. ¤ The Bohr’s method failed when two or more electrons were in orbit and could not predict the spectrum of helium. ¨ The quantum-mechanical model resolves these difficulties. Quantum theory of atoms 17 ¨ The stationary states of the Bohr model are replaced by the standing- wave solutions of the Schrödinger equation. ¨ Energy quantization is a consequence of the standing-wave solutions of the Schrödinger equation. ¨ For H, QM and the Bohr’s model give the same energy levels. ¨ The quantization of angular momentum postulated by Bohr is also predicted by QM. Schrödinger equation for an electron in an atom 18 ¨ The wave function for an electron in an atom is three dimensional. ¨ The requirement that wave function be continuous and normalizable introduces three quantum numbers for three dimensional wave function. ¨ Since the potential energy stored in the electron-nucleus system is spherically symmetric, it is convenient to use spherical coordinates. ℏ, − �,� + � � � = 0 2� Quantum numbers in spherical coordinates 19 - ¨ �: principal quantum number is associated with the probability of finding e at various r. ¨ �: orbital quantum number is related to the magnitude of the orbital angular momentum � = ℏ] � � + 1 . ¨ �^: magnetic quantum number is related to the component of the � along z- axis, �_ = �^ℏ. For l = 2 Quantum numbers in spherical coordinates 2 20 ¨ The possible values of these quantum numbers are ¤ n: principal quantum number can be any positive integer. ¤ l: orbital quantum number can be 0 or any positive integer up to n - 1. ¤ ml: magnetic quantum number has 2l + 1 possible values, ranging from -l to l. Energy and quantum numbers 21 ¨ General trend of energy vs. quantum numbers are: ¤ The lower the values of n, the lower the energy. ¤ For a given value of n, the lower the value of l, the lower the energy. ¨ The dependence of the energy on l is due to the interaction of the electrons in the atom with each other. Electron configuration 22 ¨ An electron has an intrinsic spin, so there is an additional quantum number, ms, which can be either +1/2 or -1/2. ¨ The stationary states of each electron in an atom is described by 4 quantum numbers: n, l, ml, and ms. ¨ Electron configuration can be specified by these 4 quantum numbers. ¨ No two electrons in an atom can be in the same quantum state. Quiz: 1 23 Example 2 24 ¨ An electron in an atom has principal quantum number n = 3. a) What are the possible values of l? b) What are the possible combinations of l and ml? c) Using the fact that there are two quantum states for each combination of l and ml because of electron spin, find the total number of electron states for n = 3. Quantum weirdness ¨ Bohr used to say “if you aren’t confused by quantum mechanics, then you don’t really understand it.” ¨ Based on the QM of a two-particle system, Einstein, Podolsky, and Rosen predicted results of a thought-experiment that were too weird for Einstein to accept QM. EPR thought experiment ¨ Suppose two photons A and B are simultaneously emitted in opposite direction by a source S. ¨ Each photon has a polarization X that may have two values, X1 and X2. ¨ It is always true that if A has X1, the B has X2, and vice versa. ¨ There are two quantum states: (AX1, BX2) and (AX2, BX1). ¨ Before any measurements is made, QM predicts that the actual state of this two-photon system is an equal-parts mixture of both states. ¨ By making a measurement on A, an experimentalist can reveal either X1 or X2 for A. ¨ Once the experimentalist reveals that A has X1, the system is no longer a mixture of states, but (AX1, BX2) alone. ¨ No matter how far apart A and B are, a measurement made on A automatically removes any choice for the state of B. ¨ This prediction was verified in 1980’s by Aspect et al. B S A Quantum weirdness: Schrödinger’s cat 27 ¨ Suppose a cat is placed in a sealed box containing a device that has a 50% chance of killing the cat. ¨ The wave function of the cat is ¨ The cat is dead AND alive until you open the box and check the status of the cat. ¨ When you make the observation, the cat is either dead OR alive. Quantum weirdness: e- double slit experiment ¨ When nobody is looking, an electron goes through both slits and produces interference patterns on the screen. ¨ If you place a detector to see which slit an electron goes through, interference patterns disappear. Quantum weirdness: non-locality ¨ Wave function collapses instantaneously when a detection is made somewhere. ¨ It is as if one throws a beer bottle into Boston Harbor. Its wave spreads all over the Atlantic. ¨ Then in Copenhagen, someone finds the beer bottle suddenly, and the ripples disappear everywhere at that moment.
Recommended publications
  • Unit 1 Old Quantum Theory
    UNIT 1 OLD QUANTUM THEORY Structure Introduction Objectives li;,:overy of Sub-atomic Particles Earlier Atom Models Light as clectromagnetic Wave Failures of Classical Physics Black Body Radiation '1 Heat Capacity Variation Photoelectric Effect Atomic Spectra Planck's Quantum Theory, Black Body ~diation. and Heat Capacity Variation Einstein's Theory of Photoelectric Effect Bohr Atom Model Calculation of Radius of Orbits Energy of an Electron in an Orbit Atomic Spectra and Bohr's Theory Critical Analysis of Bohr's Theory Refinements in the Atomic Spectra The61-y Summary Terminal Questions Answers 1.1 INTRODUCTION The ideas of classical mechanics developed by Galileo, Kepler and Newton, when applied to atomic and molecular systems were found to be inadequate. Need was felt for a theory to describe, correlate and predict the behaviour of the sub-atomic particles. The quantum theory, proposed by Max Planck and applied by Einstein and Bohr to explain different aspects of behaviour of matter, is an important milestone in the formulation of the modern concept of atom. In this unit, we will study how black body radiation, heat capacity variation, photoelectric effect and atomic spectra of hydrogen can be explained on the basis of theories proposed by Max Planck, Einstein and Bohr. They based their theories on the postulate that all interactions between matter and radiation occur in terms of definite packets of energy, known as quanta. Their ideas, when extended further, led to the evolution of wave mechanics, which shows the dual nature of matter
    [Show full text]
  • Quantum Mechanics in One Dimension
    Solved Problems on Quantum Mechanics in One Dimension Charles Asman, Adam Monahan and Malcolm McMillan Department of Physics and Astronomy University of British Columbia, Vancouver, British Columbia, Canada Fall 1999; revised 2011 by Malcolm McMillan Given here are solutions to 15 problems on Quantum Mechanics in one dimension. The solutions were used as a learning-tool for students in the introductory undergraduate course Physics 200 Relativity and Quanta given by Malcolm McMillan at UBC during the 1998 and 1999 Winter Sessions. The solutions were prepared in collaboration with Charles Asman and Adam Monaham who were graduate students in the Department of Physics at the time. The problems are from Chapter 5 Quantum Mechanics in One Dimension of the course text Modern Physics by Raymond A. Serway, Clement J. Moses and Curt A. Moyer, Saunders College Publishing, 2nd ed., (1997). Planck's Constant and the Speed of Light. When solving numerical problems in Quantum Mechanics it is useful to note that the product of Planck's constant h = 6:6261 × 10−34 J s (1) and the speed of light c = 2:9979 × 108 m s−1 (2) is hc = 1239:8 eV nm = 1239:8 keV pm = 1239:8 MeV fm (3) where eV = 1:6022 × 10−19 J (4) Also, ~c = 197:32 eV nm = 197:32 keV pm = 197:32 MeV fm (5) where ~ = h=2π. Wave Function for a Free Particle Problem 5.3, page 224 A free electron has wave function Ψ(x; t) = sin(kx − !t) (6) •Determine the electron's de Broglie wavelength, momentum, kinetic energy and speed when k = 50 nm−1.
    [Show full text]
  • Class 2: Operators, Stationary States
    Class 2: Operators, stationary states Operators In quantum mechanics much use is made of the concept of operators. The operator associated with position is the position vector r. As shown earlier the momentum operator is −iℏ ∇ . The operators operate on the wave function. The kinetic energy operator, T, is related to the momentum operator in the same way that kinetic energy and momentum are related in classical physics: p⋅ p (−iℏ ∇⋅−) ( i ℏ ∇ ) −ℏ2 ∇ 2 T = = = . (2.1) 2m 2 m 2 m The potential energy operator is V(r). In many classical systems, the Hamiltonian of the system is equal to the mechanical energy of the system. In the quantum analog of such systems, the mechanical energy operator is called the Hamiltonian operator, H, and for a single particle ℏ2 HTV= + =− ∇+2 V . (2.2) 2m The Schrödinger equation is then compactly written as ∂Ψ iℏ = H Ψ , (2.3) ∂t and has the formal solution iHt Ψ()r,t = exp − Ψ () r ,0. (2.4) ℏ Note that the order of performing operations is important. For example, consider the operators p⋅ r and r⋅ p . Applying the first to a wave function, we have (pr⋅) Ψ=−∇⋅iℏ( r Ψ=−) i ℏ( ∇⋅ rr) Ψ− i ℏ( ⋅∇Ψ=−) 3 i ℏ Ψ+( rp ⋅) Ψ (2.5) We see that the operators are not the same. Because the result depends on the order of performing the operations, the operator r and p are said to not commute. In general, the expectation value of an operator Q is Q=∫ Ψ∗ (r, tQ) Ψ ( r , td) 3 r .
    [Show full text]
  • On a Classical Limit for Electronic Degrees of Freedom That Satisfies the Pauli Exclusion Principle
    On a classical limit for electronic degrees of freedom that satisfies the Pauli exclusion principle R. D. Levine* The Fritz Haber Research Center for Molecular Dynamics, The Hebrew University, Jerusalem 91904, Israel; and Department of Chemistry and Biochemistry, University of California, Los Angeles, CA 90095 Contributed by R. D. Levine, December 10, 1999 Fermions need to satisfy the Pauli exclusion principle: no two can taken into account, this starting point is not necessarily a be in the same state. This restriction is most compactly expressed limitation. There are at least as many orbitals (or, strictly in a second quantization formalism by the requirement that the speaking, spin orbitals) as there are electrons, but there can creation and annihilation operators of the electrons satisfy anti- easily be more orbitals than electrons. There are usually more commutation relations. The usual classical limit of quantum me- states than orbitals, and in the model of quantum dots that chanics corresponds to creation and annihilation operators that motivated this work, the number of spin orbitals is twice the satisfy commutation relations, as for a harmonic oscillator. We number of sites. For the example of 19 sites, there are 38 discuss a simple classical limit for Fermions. This limit is shown to spin-orbitals vs. 2,821,056,160 doublet states. correspond to an anharmonic oscillator, with just one bound The point of the formalism is that it ensures that the Pauli excited state. The vibrational quantum number of this anharmonic exclusion principle is satisfied, namely that no more than one oscillator, which is therefore limited to the range 0 to 1, is the electron occupies any given spin-orbital.
    [Show full text]
  • Wave Mechanics (PDF)
    WAVE MECHANICS B. Zwiebach September 13, 2013 Contents 1 The Schr¨odinger equation 1 2 Stationary Solutions 4 3 Properties of energy eigenstates in one dimension 10 4 The nature of the spectrum 12 5 Variational Principle 18 6 Position and momentum 22 1 The Schr¨odinger equation In classical mechanics the motion of a particle is usually described using the time-dependent position ix(t) as the dynamical variable. In wave mechanics the dynamical variable is a wave- function. This wavefunction depends on position and on time and it is a complex number – it belongs to the complex numbers C (we denote the real numbers by R). When all three dimensions of space are relevant we write the wavefunction as Ψ(ix, t) C . (1.1) ∈ When only one spatial dimension is relevant we write it as Ψ(x, t) C. The wavefunction ∈ satisfies the Schr¨odinger equation. For one-dimensional space we write ∂Ψ 2 ∂2 i (x, t) = + V (x, t) Ψ(x, t) . (1.2) ∂t −2m ∂x2 This is the equation for a (non-relativistic) particle of mass m moving along the x axis while acted by the potential V (x, t) R. It is clear from this equation that the wavefunction must ∈ be complex: if it were real, the right-hand side of (1.2) would be real while the left-hand side would be imaginary, due to the explicit factor of i. Let us make two important remarks: 1 1. The Schr¨odinger equation is a first order differential equation in time. This means that if we prescribe the wavefunction Ψ(x, t0) for all of space at an arbitrary initial time t0, the wavefunction is determined for all times.
    [Show full text]
  • The Time Evolution of a Wave Function
    The Time Evolution of a Wave Function ² A \system" refers to an electron in a potential energy well, e.g., an electron in a one-dimensional in¯nite square well. The system is speci¯ed by a given Hamiltonian. ² Assume all systems are isolated. ² Assume all systems have a time-independent Hamiltonian operator H^ . ² TISE and TDSE are abbreviations for the time-independent SchrÄodingerequation and the time- dependent SchrÄodingerequation, respectively. P ² The symbol in all questions denotes a sum over a complete set of states. PART A ² Information for questions (I)-(VI) In the following questions, an electron is in a one-dimensional in¯nite square well of width L. (The q 2 n2¼2¹h2 stationary states are Ãn(x) = L sin(n¼x=L), and the allowed energies are En = 2mL2 , where n = 1; 2; 3:::) p (I) Suppose the wave function for an electron at time t = 0 is given by Ã(x; 0) = 2=L sin(5¼x=L). Which one of the following is the wave function at time t? q 2 (a) Ã(x; t) = sin(5¼x=L) cos(E5t=¹h) qL 2 ¡iE5t=¹h (b) Ã(x; t) = L sin(5¼x=L) e (c) Both (a) and (b) above are appropriate ways to write the wave function. (d) None of the above. q 2 (II) The wave function for an electron at time t = 0 is given by Ã(x; 0) = L sin(5¼x=L). Which one of the following is true about the probability density, jÃ(x; t)j2, after time t? 2 2 2 2 (a) jÃ(x; t)j = L sin (5¼x=L) cos (E5t=¹h).
    [Show full text]
  • What Is a Photon? Foundations of Quantum Field Theory
    What is a Photon? Foundations of Quantum Field Theory C. G. Torre June 16, 2018 2 What is a Photon? Foundations of Quantum Field Theory Version 1.0 Copyright c 2018. Charles Torre, Utah State University. PDF created June 16, 2018 Contents 1 Introduction 5 1.1 Why do we need this course? . 5 1.2 Why do we need quantum fields? . 5 1.3 Problems . 6 2 The Harmonic Oscillator 7 2.1 Classical mechanics: Lagrangian, Hamiltonian, and equations of motion . 7 2.2 Classical mechanics: coupled oscillations . 8 2.3 The postulates of quantum mechanics . 10 2.4 The quantum oscillator . 11 2.5 Energy spectrum . 12 2.6 Position, momentum, and their continuous spectra . 15 2.6.1 Position . 15 2.6.2 Momentum . 18 2.6.3 General formalism . 19 2.7 Time evolution . 20 2.8 Coherent States . 23 2.9 Problems . 24 3 Tensor Products and Identical Particles 27 3.1 Definition of the tensor product . 27 3.2 Observables and the tensor product . 31 3.3 Symmetric and antisymmetric tensors. Identical particles. 32 3.4 Symmetrization and anti-symmetrization for any number of particles . 35 3.5 Problems . 36 4 Fock Space 38 4.1 Definitions . 38 4.2 Occupation numbers. Creation and annihilation operators. 40 4.3 Observables. Field operators. 43 4.3.1 1-particle observables . 43 4.3.2 2-particle observables . 46 4.3.3 Field operators and wave functions . 47 4.4 Time evolution of the field operators . 49 4.5 General formalism . 51 3 4 CONTENTS 4.6 Relation to the Hilbert space of quantum normal modes .
    [Show full text]
  • Stationary States in a Potential Well- H.C
    FUNDAMENTALS OF PHYSICS - Vol. II - Stationary States In A Potential Well- H.C. Rosu and J.L. Moran-Lopez STATIONARY STATES IN A POTENTIAL WELL H.C. Rosu and J.L. Moran-Lopez Instituto Potosino de Investigación Científica y Tecnológica, SLP, México Keywords: Stationary states, Bohr’s atomic model, Schrödinger equation, Rutherford’s planetary model, Frank-Hertz experiment, Infinite square well potential, Quantum harmonic oscillator, Wilson-Sommerfeld theory, Hydrogen atom Contents 1. Introduction 2. Stationary Orbits in Old Quantum Mechanics 2.1. Quantized Planetary Atomic Model 2.2. Bohr’s Hypotheses and Quantized Circular Orbits 2.3. From Quantized Circles to Elliptical Orbits 2.4. Experimental Proof of the Existence of Atomic Stationary States 3. Stationary States in Wave Mechanics 4. The Infinite Square Well: The Stationary States Most Resembling the Standing Waves on a String 3.1. The Schrödinger Equation 3.2. The Dynamical Phase 3.3. The Schrödinger Wave Stationarity 3.4. Stationary Schrödinger States and Classical Orbits 3.5. Stationary States as Sturm-Liouville Eigenfunctions 5. 1D Parabolic Well: The Stationary States of the Quantum Harmonic Oscillator 5.1. The Solution of the Schrödinger Equation 5.2. The Normalization Constant 5.3. Final Formulas for the HO Stationary States 5.4. The Algebraic Approach: Creation and Annihilation Operators 5.5. HO Spectrum Obtained from Wilson-Sommerfeld Quantization Condition 6. The 3D Coulomb Well: The Stationary States of the Hydrogen Atom 6.1. The Separation of Variables in Spherical Coordinates 6.2. The Angular Separation Constants as Quantum Numbers 6.3. Polar andUNESCO Azimuthal Solutions Set Together – EOLSS 6.4.
    [Show full text]
  • Spectroscopy Minneapolis Community and Technical College V.10.17
    Spectroscopy Minneapolis Community and Technical College v.10.17 Objective: To observe, measure and compare line spectra from various elements and to determine the energies of those electronic transitions within atoms that produce lines in a line spectrum. Prelab Questions: Read through this lab handout and answer the following questions before coming to lab. There will be a quiz at the beginning of lab over this handout and its contents. 1. How does the spacing of stationary states change as n increases? 2. For the hydrogen atom, why isn’t light produced by the n = 3 → n = 1 electron transition visible to the eye? 3. How does the energy of an n = 3 → 2 electronic transition compare to the energy of a 2 → 1 transition? 4. What is the meaning of ROY G BIV? 5. What are the meanings of the terms “absorbed” and “transmitted.” 6. How is an emission spectrum different from an absorption spectrum? 7. What is a spectroscope? 8. Where does light enter the spectroscope? 9. What is the wavelength of the spectral line displayed in the figure at right? 10. Calculate the energy corresponding to hydrogen’s n = 1 stationary state. The Bohr Atom, Stationary States and Electron Energies Bohr’s theory of the atom locates electrons within an atom in discrete “stationary states” . The “n” quantum number identifies each stationary state with a positive integer between 1 and infinity (). Larger n values correspond to larger electron orbits about the nucleus. Stationary states energies are described using a potential energy ladder diagram at right. Electrons are forbidden from having energies between stationary states.
    [Show full text]
  • Harmonic Oscillator Physics
    Physics 342 Lecture 9 Harmonic Oscillator Physics Lecture 9 Physics 342 Quantum Mechanics I Friday, February 12th, 2010 For the harmonic oscillator potential in the time-independent Schr¨odinger equation: 2 1 2 d (x) 2 2 2 −~ + m ! x (x) = E (x); (9.1) 2 m dx2 we found a ground state 2 − m ! x 0(x) = A e 2 ~ (9.2) 1 with energy E0 = 2 ~ !. Using the raising and lowering operators 1 a+ = p (−i p + m ! x) 2 m ! ~ (9.3) 1 a− = p (i p + m ! x); 2 ~ m ! we found we could construct additional solutions with increasing energy using a+, and we could take a state at a particular energy E and construct solutions with lower energy using a−. The existence of a minimum energy state ensured that no solutions could have negative energy and was used to define 1: 0 n 1 n a− 0 = 0 H (a+ 0) = + n ~ ! a+ 0: (9.4) 2 The operators a+ and a− are Hermitian conjugates of one another { for any 1I am leaving the \hats" off, from here on { we understand that H represents a differ- ` ~ @ ´ ential operator given by H x; i @x for a classical Hamiltonian. 1 of 10 9.1. NORMALIZATION Lecture 9 f(x) and g(x) (vanishing at spatial infinity), the inner product: Z 1 Z 1 ∗ ∗ @g(x) f(x) a± g(x) dx = f(x) ∓~ + m ! x g(x) dx −∞ −∞ @x Z 1 ∗ @f(x) ∗ = ±~ g(x) + f(x) m ! x g(x) dx −∞ @x Z 1 ∗ = (a∓ f(x)) g(x) dx; −∞ (9.5) (integration by parts) or, in words, we can \act on g(x) with a± or act on f(x) with a∓" in the inner product.
    [Show full text]
  • CYK\2010\PH405+PH213\Tutorial 5 Quantum Mechanics 1. Find Allowed Energies of the Half Harmonic Oscillator 2. a Charged Particle
    CYK\2010\PH405+PH213\Tutorial 5 Quantum Mechanics 1. Find allowed energies of the half harmonic oscillator ( 1 m!2x2; x > 0; V (x) = 2 1; x < 0: 2. A charged particle (mass m, charge q) is moving in a simple harmonic potential (frequency !=2π). In addition, an external electric eld E0 is also present. Write down the hamiltonian of this particle. Find the energy eigenvalues, eigenfunctions. Find the average position of the particle, when it is in one of the stationary states. 3. Assume that the atoms in a CO molecule are held together by a spring. The spacing between the lines of the spectrum of CO molecule is 2170 cm−1. Estimate the spring constant. 4. If the hermite polynomials Hn(x) are dened using the generating function G(x; s) = exp −s2 + 2xs, that is X Hn(x) exp −s2 + 2xs = sn; n! n (a) Show that the Hermite polynomials obey the dierential equation 00 0 Hn(x) − 2xHn(x) + 2nHn(x) = 0 and the recurrence relation Hn+1(x) = 2xHn(x) − 2nHn−1(x): (b) Derive Rodrigues' formula n 2 d 2 H (x) = (−1)n ex e−x : n dxn 5. Let φn be the nth stationary state of a particle in harmonic oscillator potential. Given that the lowering operator is 1 a^ = p m!X^ + iP^ : 2~m! p and ξ = m!=~x, (a) show that 1 d a^ = p ξ + : 2 dξ (b) Show that p aφ^ n(ξ) = nφn−1(ξ) 6. Let B = fφn j n = 0; 1;:::g be the set of energy eigenfunctions of the harmonic oscillator.
    [Show full text]
  • Appendix 5: Time-Energy Uncertainty
    Appendix 6: Time-Energy Uncertainty (so called) The Generalized Uncertainty Principle applied to the Hamiltonian operator Hˆ and the generic operator Oˆ says that æ i ö 2 s 2s 2 ³ ç Hˆ ,Oˆ ÷ . (A6.1) H O è 2i [ ] ø If Oˆ does not depend explicitly on time, we can write the general form of the Ehrenfest Theorem as h ¶ < O >= [Hˆ ,Oˆ ] . (A6.2) i ¶t By plugging it into the previous equation, we obtain 2 2 2 2 2 æ i h ¶ ö æ hö æ ¶ ö s H sO ³ ç < O >÷ = ç ÷ ç < O >÷ . (A6.3) è 2i i ¶t ø è 2ø è ¶t ø Since standard deviation is always positive, we have æ hö ¶ s HsO ³ ç ÷ < O > . (A6.4) è 2ø ¶t Now let us set d s = < O >Dt , (A6.5) O dt where Dt is a time interval. Hence, s Dt = O .1 (A6.6) d < O > dt d 1 To see what this formula means, consider this. When Dt =1, thens = < O > , that O dt is, the rate of change of the expectation value is one standard deviation; when Dt = 2 , 420 By plugging this into the previous equation, we obtain h s H Dt ³ , (A6.7) 2 the Time-Energy Uncertainty Principle (TEUP). The name is misleading because Dt is not the standard deviation of an ensemble of time measurements (there is no operator for time because time is not an observable), but the amount of time < O > takes to change by O’s standard deviation. TEUP tells us that in an ensemble the smaller s H (the standard deviation of the Hamiltonian of the system, that is, its energy), the larger Dt must be.
    [Show full text]