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?WHAT IS... a Syzygy? Roger Wiegand

Linear algebra over rings is lots more fun than of the following form (the rather com- over fields. The main reason is that most modules plicated matrices defining the maps between free over a do not have bases—that is, their gen- modules need not concern us): erators usually satisfy some nontrivial relations 3 ∂3 6 ∂2 4 ∂1 or “syzygies”. Given a finitely generated R- 0 → R −→ R −→ R −→ R → M → 0 M R (where is a ) and a This time it takes three steps to resolve the mod- z ,...,z of generators, a syzygy of M is an element 1 n ule: The first module of syzygies of M is ker(ε), the (a ,...,a ) ∈ Rn for which a z + ···+ a z =0. 1 n 1 1 n n second (i.e., the module of syzygies of ker(ε)) is The set of all syzygies (relative to the given gen- ker(∂ ), and the third module of syzygies is ker(∂ ). erating set) is a submodule of Rn, called the mod- 1 2 The 0 at the left end of the then tells ule of syzygies. Thus the module of syzygies of M 3 us that ∂ maps R isomorphically onto ker(∂ ), is the kernel of the map Rn −→ M that takes the 3 2 that is, the third syzygy of M is free. standard elements of Rn to the given set of Hilbert’s famous “Syzygy Theorem”, published generators. in 1890, states that every finitely generated graded Suppose, for example, that R = C[x, y] and module M = ⊕∞ M over the M = R/m, where m is the maximal ideal consist- i=0 i C[x ,...,x ] has a free resolution of length at most ing of polynomials with no constant term. The 1 n n, that is, its nth syzygy is free. (The grading re- module of syzygies is m, which is generated by x spects the action of the variables, in the sense that and y. These elements are not independent, since ⊆ ≤ they satisfy the non-trivial relation (−y)x + xy =0. xj Mi Mi+1 for all i and all j n. The length is one So we look at the module S of syzygies of m, which less than the number of free modules in the reso- is the rank-one generated by the ele- lution.) Hilbert used this result to prove that the → ment (−y,x) ∈ R2. Thus after taking syzygies twice i dimC Mi is, for large i, a polynomial we have “resolved” M and obtained a free module. function of i. The idea here is that many proper- We say that S is the second module of syzygies of ties of modules are easy to compute for free mod- R/m. We can encode this information in the fol- ules and behave well along exact sequences. Thus, lowing exact sequence (where we have written el- if a module has a finite free resolution, one can eas- ements of R2 as columns, so that matrices act on ily read off certain kinds of numerical data. the left):   It turns out that every finitely generated mod- −y x [xy] ule M (not necessarily graded) over a polynomial 0 → R −→ R2 −→ R → R/ → 0 m ring R = k[x1,...,xn], where k is a , has a free For a slightly more complicated example, let resolution of length at most n. By introducing an- R = C[x, y, z] and resolve the module other variable and “homogenizing”, one can obtain M := R/(x3y + z4,xy2,x3 + y3,z5) . Using the soft- a free resolution of length at most n +1. Using ho- ware package MACAULAY 2, one obtains a free mological ideas available in the 1950s, one can then show that the nth syzygy S of M is stably free, p ∼ q Roger Wiegand is professor of mathematics at the that is, S ⊕ R = R for suitable p, q. Now University of Nebraska. His email address is one uses “Serre’s Conjecture”, proved indepen- [email protected]. dently by Quillen and Suslin in 1976: projective

456 NOTICES OF THE AMS VOLUME 53, NUMBER 4 modules over polynomial rings (such as the R- ematicians should know about syzygies, cf. David module S above) are free. Cox’s article in the November 2005 Notices. Let’s switch gears, from graded rings to local I will close by mentioning a few open problems. rings. Suppose R is a (commutative, Noetherian) First, as might be suggested by our first example, with maximal ideal m, and let M be a fi- for the simple module R/m over a nitely generated R-module. By choosing a minimal R of n, the Betti numbers are binomial n generating set for M, and then a minimal generat- coefficients: bi = i . The “Horrocks conjecture” as- ing set for the first syzygy, and so on, one obtains serts that these are the smallest possible Betti num- a free resolution bers for a module of projective dimension n. A re- lated problem is the “syzygy conjecture”, which b b b ···→R n →···→R 1 → R 0 → M → 0. asserts that if M has projective dimension n then b − b + b −···±b ≥ i for each i

On the other hand, the Betti numbers of the module C[[t3,t4,t5]]/(t3,t4,t5) over the ring C[[t3,t4,t5]] grow exponentially. These examples are symptoms of general be- havior promised by deep results in the represen- tation theory of local rings. First and foremost is the theorem of Auslander, Buchsbaum, and Serre, which says that a local ring R is regular (meaning, in the geometric context, that it corresponds to a smooth on a variety) if and only if every fi- nitely generated R-module has finite projective di- mension. Next, if R is any ring of the form C[[x1,...,xn]]/(f ), where f is a nonzero element in the square of the maximal ideal, then the minimal resolution of every finitely generated R-module is eventually periodic, of period at most two. To place the last example in context, see Avramov’s survey [1] of the asymptotic behavior of Betti numbers over local rings. The “WHAT IS…?” column carries short (one- or Syzygies and the structure of free resolutions are two-page) nontechnical articles aimed at graduate stu- dents. Each article focuses on a single mathematical currently the subject of intense research, though object rather than a whole theory. The Notices I have mentioned only a few highlights. For an ac- welcomes feedback and suggestions for topics. Mes- count of the use of syzygies in algebraic geometry, sages may be sent to [email protected]. cf. Eisenbud’s book [2]. To see why applied math-

APRIL 2006 NOTICES OF THE AMS 457