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3 ℝ Theorem 2. For a connected, simple G of infinite center, Hc(G; ) ≠ 0 if and only if §ℝ ℝ 3 ℝ G is isomorphic to SL(2, ), the universal cover of SL(2, ). In that case, dim Hc(G; ) = 1.

Before proceeding to the proofs of the theorems, we comment on the question of explicit 3-cocycles in the setting of Theorem 1. Thus, fix G as in Theorem 1, and assume that the equiv- alent conditions hold. Let J be a complex structure on the g of G, and regard it as a complex Lie algebra. Let ∙ k ⊂ g be a compact of g,

∙ Bg be the of g, and ∙ K the connected subgroup of G with Lie algebra k. Then g = k ⊕ Jk is a Cartan decomposition, and k is simple; see Theorem 3.2 below for a reference. The subgroup K is maximal compact in G, and G∕K is a of non- ∙ ∗ k compact type with TK (G∕K) ≅ g∕k ≅ Jk. Let (Λ (g∕k) ) denote the complex of k-invariant, alternating, multilinear forms on g∕k, and Ω∙(G∕K)G be the complex of G-invariant differential forms on G∕K. Left-translation of an element of the former gives rise of an element of the latter, and this assignment is an isomorphism. 3 ℝ ∙ ∗ k It is a consequence of van Est’s theorem that there is an isomorphism Hc(G; )≅(Λ (Jk) ) ; use Corollary 2.6 with p = Jk. The formula

(1.1) !(X,Y,Z) ∶= Bg(X, J[Y , Z]), X,Y,Z ∈ Jk, defines a non-zero element ! ∈ (Λ3(Jk)∗)k. Let ̃! ∈ Ω3(G∕K)G be corresponding 3-form. This one integrated over “3-simplices” produces a non-trivial, G-invariant continuous 3-cocycle 4 I! ∶ G → ℝ. k More precisely: Fix a base point o ∈ G∕K. For any k-tuple (g0, … ,gk) ∈ G , consider the ⋅ geodesic k-simplex Δ(g0, … ,gk) ⊂G∕K, defined inductively as follows: let Δ(g0)∶={g0 o}, ⋅ and for k > 0, set Δ(g0, … ,gk) to be the union of the geodesics connecting gk o to each point in Δ(g0, … ,gk−1). It is not hard to verify that the expression

(1.2) I (g , … ,g ) ∶= ̃! ! 0 4 Ê Δ(g0,…,g4) is a well-defined G-invariant continuous 3-cocycle. Finally, its non-triviality follows from the fact, by Dupont [4], that integration over simplices realizes van Est’s isomorphism at the level of cochains.

Remark 1.1. Concerning Theorem 2, the group G ∶= SL(2§, ℝ) has trivial maximal compact 3 ℝ subgroup M. Thus, van Est’s theorem (Theorem 2.1 below) yields an isomorphism Hc(G; ) ≅ H3(Ω∙(G)G). An obvious G-invariant 3-form of G is its volume form. Arguing as with (1.2), we conclude that the volume of 3-simplices is a non-trivial G-invariant continuous 3-cocycle of G.

We point out that the expression obtained by removing the J in (1.1) is known to define a generating class of H3(k; ℝ) and of the de Rham cohomology group H3(K; ℝ); see the refer- ence [7]. However, we have found no account in the literature of the formula (1.1) nor of the statements of our two theorems. This was in fact the main motivation for writing this note. ON THE THIRD-DEGREE CONTINUOUS COHOMOLOGY OF SIMPLE LIE GROUPS 3

The rest of this paper contains proofs of Theorems 1 and 2. They do not rely on the classifi- cation of simple Lie groups. Acknowledgments: The author expresses his gratitude to his PhD advisor Marc Burger for suggesting the question of the characterization that led to Theorem 1, and for many helpful discussions. He further thanks Tobias Hartnick and Maria Beatrice Pozzetti for their valuable comments and suggestions.

2. NOTATION AND BACKGROUND 2.1. Notation. Whenever there is no explicit mention of coefficients when using any notion of cohomology, it should be understood for the rest of this paper that they are trivial ℝ-coefficients. ∙ The functor Hc refers to the continuous cohomology of topological groups. On the other hand, when applied to manifolds (including Lie groups), H∙ denotes their cohomology as spaces. If g is a Lie algebra and m ⊂ g is any subalgebra, then (Λ∙(g∕m)∗)m will denote the complex of m-invariant, alternating, multilinear forms on g∕m; for the definition of the m-action on g∕m and of the coboundary operator, we refer the reader to Chapter 1 of [1]. The cohomology of this complex, denoted by H∙(g, m) is known as the Lie algebra cohomology of g relative to m. If m is trivial, we will write H∙(g) instead of H∙(g, m). If G is a connected Lie group and M

2.2. Background on continuous cohomology of Lie groups. A powerful tool for computing the continuous cohomology of a connected Lie group G is van Est’s theorem; see the original references by van Est [5] and Hochschild–Mostow [9]. We quote it from [1, Corollary IX.5.6]. Theorem 2.1 (van Est, Hochschild–Mostow). Let G be a connected Lie group with Lie algebra g, and M be a maximal compact (connected) subgroup of G with Lie algebra m ⊂ g. Then ∙ ∙ ∙ (2.1) Hc(G)≅HG(G∕M)≅H (g, m).

For the rest of this section, let G be a non-compact, connected, semisimple1 Lie group with Lie algebra g, and let M

∙ the compact dual gu ∶= k ⊕ ip of g, ∙ the compact dual Gu of G, i.e. the 1-connected, compact, semisimple Lie group with Lie algebra gu, and ∙ the connected subgroup Mu of Gu with Lie algebra m. ∙ the connected subgroup Ku of Gu with Lie algebra k.

1For background in semisimple Lie groups and Lie algebras, we refer the reader to [8]. ON THE THIRD-DEGREE CONTINUOUS COHOMOLOGY OF SIMPLE LIE GROUPS 4

Remark 2.2. Any subgroup K¨ < G with Lie algebra k is automatically connected and closed in G, and contains the center of G. Furthermore, K¨ is compact if and only if the center of G is finite. If that is the case, K¨ is a maximal compact subgroup of G, and G∕K¨ is a symmetric space of non-compact type. This is the content of Theorem VI.1.1 in [8].

Remark 2.3. The connected subgroup Ku

A second computational tool is the next theorem of Chevalley–Eilenberg [2], whose main ideas they attribute to Cartan.

∙ ∙ Theorem 2.4 (Cartan, Chevalley–Eilenberg). If Mu

∙ ∙ It is not hard to observe that there is an isomorphism H (g, m)≅H (gu, m). Combining it with (2.1), we obtain:

∙ ∙ Corollary 2.5. If Mu

The case of finite center. We impose now the additional assumption that G has a finite center. Then, by Remark 2.2, the subgroup K

(2.2) M = K, m = k and Mu = Ku. Moreover, by the same remark, G∕K is a symmetric space of non-compact type. It is a theorem by Cartan that invariant differential forms on a symmetric space are automatically closed. Hence:

Corollary 2.6. Under the assumption of finite center of G, there exist isomorphisms ∙ ∙ G ∙ ∗ k ∙ ∗ k ∙ Hc(G)≅Ω (G∕K) ≅ (Λ p ) ≅ (Λ (ip) ) ≅H (Gu∕Ku).

3. PROOF OF THEOREM 1 The equivalence (3) ⇔ (4) is a classical fact that holds for any connected Lie group, and goes back to Newlander–Nirenberg. Thus, we will only prove the equivalence (1) ⇔ (2) ⇔ (3). A first reduction is provided by the following lemma.

Lemma 3.1. If G is a compact, connected, (hence with finite center), then none of the statements (1)-(4) in Theorem 1 hold.

Proof. If G satisfied (4), then by connectedness and compactness, G would be isomorphic to a quotient ℂn∕Λ, where Λ < ℂn is a lattice. In particular, G would be Abelian, contradicting the assumption of simplicity. On the other hand, properties (1) and (2) fail because by Theorem 2.1, the continuous cohomology of a compact Lie group vanishes in any positive degree. 

Hence, from now on in this section, let G be a non-compact, connected, simple Lie group with finite center, and let g be its Lie algebra. We argue now in the order (3) ⇒ (2) ⇒ (1) ⇒ (3), where (2) ⇒ (1) is evident. ON THE THIRD-DEGREE CONTINUOUS COHOMOLOGY OF SIMPLE LIE GROUPS 5

3.1. Proof of (3) ⇒ (2). Assume that g admits a complex structure J. Then: Theorem 3.2. Any compact real form k of g is simple, maximal compactly embedded in g, and (3.1) g = k ⊕ Jk is a Cartan decomposition of g. About the proof. The fact that k is maximal compactly embedded and that the decomposition above is a Cartan decomposition is Corollary III.7.5 of [8]. The simplicity of k is part of the proof of Theorem VIII.5.4 in [8].  Fix a compact real form k of g. By Corollary 2.6 (with p = Jk), there exists isomorphisms 3 3 ∗ k 3 ∗ k 2 ∗ k Hc(G)≅(Λ (Jk) ) ≅ (Λ k ) . Let (V k ) denote the space of k-invariant, symmetric bilinear forms on k. We make use of the following fact: Proposition 3.3. The assignment Φ∶(V2k∗)k → (Λ3k∗)k, defined by 2 ∗ k ΦB(X,Y,Z) = B(X, [Y , Z]), for B ∈ (V k ) and X,Y,Z ∈ k, is a linear isomorphism. About the proof. This is Proposition I in Section 5.7 of [7]. The statement holds if k is any compact, . 

We conclude the proof of the implication by pointing out that the space (V2k∗)k has dimension one because of the simplicity of k; a generator of it is the Killing form of k. A proof of this fact can be found, for example, in the discussion at the beginning of VIII.§5 of [8].

3.2. Proof of (1) ⇒ (3). Assume now that g does not admit a complex structure. We adopt the same notation of (2.2) and Corollary 2.6, and fix: ∙ a maximal compact subgroup K

∙ the compact dual gu ∶= k ⊕ ip of g, ∙ the compact dual Gu of G, and ∙ the connected subgroup Ku of Gu with Lie algebra k.

The starting point for the proof of this implication is the following theorem.

Theorem 3.4. (i) The compact dual gu is simple. (ii) The symmetric space of compact type Gu∕Ku is irreducible. In particular, the action of Ad(Ku) on the vector space ip is irreducible. About the proof. Part (i) is a combination of Theorem VIII.5.3 and Theorem V.2.4 of [8]. Part (ii) is a consequence of Theorem VIII.5.3 of [8]; see also the Definition at the beginning of VIII.§5 of [8].  Remark 3.5. Note that (i) does not hold for Lie algebras that do admit a complex structure. For example, the compact dual of sl(2, ℂ) is the Lie algebra su(2) ⊕ su(2) ≅ so(4, ℝ). ON THE THIRD-DEGREE CONTINUOUS COHOMOLOGY OF SIMPLE LIE GROUPS 6

3 3 3 By Corollary 2.6, we have Hc(G)≅H (Gu∕Ku). Thus it suffices to show that H (Gu∕Ku) vanishes. We distinguish two cases: Case 1: k is Abelian. The following proposition establishes the claim. 2 Proposition 3.6. The symmetric space Gu∕Ku is diffeomorphic to the 2-dimensional sphere S .

Proof. The group Ku is Abelian; because it is a non-trivial torus, it contains an element j of order four. The image of j under the Ad (j)ð is a complex structure on Gu ip the real vector space ip. Thus, we regard ip now as a ℂ-vector space. By the commutativity of ℂ Ku, the Ad(Ku)-action on ip is -linear. By (ii) of Theorem 3.4 and Schur’s lemma, we obtain that dimℂ ip = 1. In consequence,

dim(Gu∕Ku) = dimℝ ip = 2 dimℂ ip = 2.

Since Gu is 1-connected and Ku is connected, the space Gu∕Ku is 1-connected, and we conclude by the classification of surfaces. 

Case 2: k is non-Abelian. The claim follows from the next proposition with U = Gu and L = Ku. Proposition 3.7. Let U be a 1-connected, compact, simple Lie group, and L < U be a con- nected, closed, non-Abelian subgroup. Then H3(U∕L) = 0. We point out that U∕L needs not be a symmetric space. We give a proof of this proposition in the next subsection.

3.3. Proof of Proposition 3.7. We will need three facts about the topology of Lie groups. Theorem 3.8 (Weyl). The universal covering group of a compact semisimple Lie group is com- pact. In particular, any Lie group with a compact, is compact. About the proof. A proof of this theorem is found in [8] as Theorem II.6.9. 

Theorem 3.9 (Bott). For any connected Lie group H, the second homotopy group 2(H) van- ℤ ishes. If, moreover, H is simple, then 3(H) ≅ . About the proof. It is a consequence of the fact, due to Bott, that the loop space of a compact, 1- connected Lie group has the homotopy type of a CW-complex with no odd-dimensional cells and finitely many cells of each even dimension. A proof of this fact is completely Morse-theoretical; see Theorem 21.6 in [10]. Based on it, one can conclude as indicated in [3]. 

Before quoting the third fact, we give the definition of the Dynkin index of a homomorphism between two compact, connected, simple Lie groups, as found in [11]:

Definition. Let G1 and be compact, connected, simple Lie groups with Lie algebras g1 and ∗ g2, respectively, and let i ∈ hi be a root of maximal length of gi with respect to a Cartan 2 ∗ gi subalgebra hi (i = 1, 2). Moreover, let Bi ∈ (V gi ) be a negative-definite, gi-invariant bilinear 2 form on gi normalized in such a way that the square of the length of the root i with respect to

2 ⇒ 2 ∗ gi As mentioned in the proof of the implication (3) (2) of Theorem 1, dim(V gi ) = 1, so the forms Bi are uniquely determined up to a positive constant. ON THE THIRD-DEGREE CONTINUOUS COHOMOLOGY OF SIMPLE LIE GROUPS 7

∗ → the associated inner product on hi equals two. If ' ∶ G1 G2 is a homomorphism, then there ⋅ exists a non-negative real number j' such that B2 = j' B1, called the Dynkin index of '.

Theorem 3.10. Let ' ∶ G1 → G2 be a homomorphism between two compact, connected, simple Lie groups G1 and G2. Then:

(i) The Dynkin index j' is a non-negative integer. It is equal to zero if and only if ' is the homomorphism that maps every element to the identity.

(ii) If 3(Gi) = ⟨i⟩ for i = 1, 2 (see Theorem 3.9), then '# 1 = ±j' 2.

About the proof. Part (i) is Proposition 11, §3 of [11], and (ii) is Theorem 2, §17 of the same reference. 

ℤ Proof of Proposition 3.7. We will prove that the integral homology group H3(U∕L; ) is finite and therefore by the universal coefficient theorem H3(U∕L) = 0. Because U is 1-connected and L is connected, we have that U∕L is 1-connected. Therefore, the Hurewicz homomorphism → ℤ ℎ ∶ 3(U∕L) H3(U∕L; ) in degree three is surjective. The claim follows after proving finiteness of 3(U∕L). Consider now the long exact sequence in homotopy   ⋯ # # ⋯ → 3(L) ,,,,,,,→ 3(U) ,,,,,,,,,→ 3(U∕L) → 2(L) →   ↪ ↠ of the fibration L U U∕L. By Theorem 3.9 and exactness, the homomorphism # is ℤ surjective and 3(U∕L) ≅ 3(U)∕im # ≅ ∕im #. Therefore, 3(U∕L) is finite if and only if the image of # is non-trivial. Let l be the Lie algebra of L, hence compact and non-Abelian. In particular, l splits as the direct sum of its center and a non-trivial semisimple ideal. Thus, let l1 be a simple ideal of l, and let L1 be the 1-connected, simple Lie group with Lie algebra l1, which is compact by Theorem 3.8. Now let  ∶ L1 → L be the unique Lie group homomorphism whose derivative ↪ ℤ is the inclusion l1 l. Again by Theorem 3.9, we know that 3(K1) ≅ . We obtain the following diagram in homotopy:  # ℤ 3(L) / 3(U) ≅ O ♠6 ♠ ♠  ♠ # ♠ ◦ ♠ # #=∶ # ℤ ≅ 3(L1) ◦ ◦ Set ∶=  . Obviously, the image of # = # # is contained in the image of #. Hence, it suffices to show that the former one is non-trivial in order to prove that so is the latter. To conclude, note that is an immersion, since its derivative is injective. In particular, it is not the homomorphism that maps every element of L1 to the identity of U. Thus, the Dynkin index j of is not zero by Theorem 3.10 (i). Furthermore, by Theorem 3.10 (ii), the generator  gets mapped by to ±j  , so im ≅ j ℤ ≠ {0}.  L1 # U # ON THE THIRD-DEGREE CONTINUOUS COHOMOLOGY OF SIMPLE LIE GROUPS 8

4. PROOF OF THEOREM 2 Let G be a connected, simple Lie group with infinite center Z and Lie algebra g. We set ↠ G0 ∶= G∕Z, which is a connected, center-free Lie group with Lie algebra g, and let p ∶ G G0 be the canonical projection. In addition, let ∙ k be a maximal compactly embedded subalgebra of g, which splits as the direct sum k = z(k) ⊕ m of its center z(k) and a semisimple or trivial ideal m; ∙ g = k ⊕ p be a Cartan decomposition of g,

∙ gu = k ⊕ ip be the compact dual of g, ∙ K0

Case 1: k is Abelian. We are exactly in the situation of Proposition 3.6. Thus, it follows that 2 the symmetric space of non-compact type G0,u∕K0,u is diffeomorphic to S . Then, via duality, 2 ℝ §ℝ G0∕K0 is diffeomorphic to the hyperbolic plane H , G0 ≅ PSL(2, ), and G ≅ SL(2, ), being the only infinite cover of G0. 3 Before showing that the dimension of Hc(G) equals one, we prove the following lemma, which will also be useful in the case of k non-Abelian.

Lemma 4.1. If dim z(k) = 1, then the connected subgroup M

Proof. By the semisimplicity of m and Theorem 3.8, the Lie subgroup M

Note that in our case z(k) = k ≅ so(2, ℝ), which is one-dimensional, and m is trivial. Hence, the connected subgroup M of G with Lie algebra m is therefore trivial, and by the previous lemma, maximal compact in G. Moreover, it is well known that the compact dual of g is gu = 3 su(2). Thus, G has as compact dual the Lie group Gu = SU(2) ≅ S . From Corollary 2.5 with Mu trivial, we have an isomorphism 3 3 3 3 Hc(G)≅H (Gu)=H (S ), and the last one is clearly one-dimensional.

Case 2: k is non-Abelian. This assumption means that both z(k) and m are non-trivial. By the non-triviality of z(k) and the simplicity of G0, it follows from Theorems VIII.6.1 and VIII.6.2 of [8] that G0∕K0 is an irreducible Hermitian symmetric space of non-compact type, and that 1 the center Z(K0) of K0 is isomorphic to S . In particular, dim z(k) = 1. The connected subgroup M

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