A Card Game for Bell's Theorem and Its Loopholes Guy Vandegrift¹, Joshua Stomel²
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WikiJournal of Science, 2018, 1(1):6 doi: 10.15347/wjs/2018.005 Research Article A card game for Bell's theorem and its loopholes Guy Vandegrift¹, Joshua Stomel² Abstract In 1964 John Stewart Bell made an observation about the behavior of particles separated by macroscopic distances that had puzzled physicists for at least 29 years, when Einstein, Podolsky and Rosen put forth the famous EPR paradox. Bell made certain assumptions leading to an inequality that entangled particles are routinely observed to violate in what are now called Bell test experiments. As an alternative to showing students a "proof" of Bell's inequality, we introduce a card game that is impossible to win. The solitaire version is so simple it can be used to introduce binomial statistics without mentioning physics or Bell's theorem. Things get interesting in the partners' version of the game because Alice and Bob can win, but only if they cheat. We have identified three cheats, and each corresponds to a Bell's theorem "loophole". This gives the instructor an excuse to discuss detector error, cau- sality, and why there is a maximum speed at which information can travel. The conundrum any theory that might replace quantum mechanics.[6] It is also possible to view a loophole as a physical mecha- Although this can be called a theorem, it might be bet- nism by which the outcome of a Bell's theorem experi- ter viewed as something "spooky" that has been rou- ment might seem less "spooky". In this paper, we asso- tinely observed, and is consistent with quantum me- ciate loopholes with ways to cheat at the partners' ver- chanics. But this puzzling behaviour violates what sion of the card game. It should be noted that the might be called common notions about what is and is three loophole mechanisms introduced in this paper not possible.[1][2] Students typically encounter a math- raise questions that are even spookier than quantum ematical theorem as an incomprehensible statement mechanics: Are the photons "communicating" with each that cannot be digested until it is first proven and then other? Do they "know" the future? Do they "persuade" applied in practice. It is not uncommon for novices to the measuring devices to fail when the "cards are unfa- refer to some version of Bell's inequality as Bell's theo- vorable"?[7] rem because the inequality can be mathematically "proven".[3] The problem is that what is proven turns out Since entanglement is so successfully modeled by to be untrue. quantum mechanics, one can argue that there is no need for a mechanism that "explains" it. Nevertheless, David Mermin described an imaginary device not unlike there are reasons for investigating loopholes. At the that shown in Fig. 1, and refers to the fact that such a most fundamental level, history shows that a successful device actually exists as a conundrum, then pointed out physical theory can be later shown to be an approxima- that many physicists deny that it is a conundrum.[4] tion to a deeper theory, and the need for this new the- ory is typically associated with a failure of the old para- A simple Bell's theorem experiment digm. It is plausible that a breakdown of quantum me- It is customary to name the particles[5] in a Bell's theo- chanics might be discovered using a Bell's theorem ex- rem experiment "Alice" and "Bob", an anthropomor- periment designed to investigate a loophole. But the phism that serves to emphasize the fact that a pair of vast majority of us (including most working physicists) humans cannot win the card game ... unless they need other reasons to care about loopholes: Many find cheat. To some experts, a "loophole" is a constraint on it interesting that we seem to live in a universe gov- erned by fundamental laws, and Bell's theorem yields insights into the bizarre nature of those laws. Also, 1 Wright State University Lake Campus, Celina, Ohio, 45822 those who teach can use these card games to motivate 2 Wright State University Lake Campus, Celina, Ohio, 45822 *Author correspondence: [email protected] ORCID: [0000-0000-0000-0001] Supplementary material: commons.wikimedia.org/location Licensed under: CC-BY Received 02-02-2018; accepted 31-05-2018 1 of 10 | WikiJournal of Science WikiJournal of Science, 2018, 1(1):6 doi: 10.15347/wjs/2018.005 Research Article introductory discussions about statistical inference, po- while the odd cards (3,5,7,9) represent a photon being larization, and modern physics. blocked. Although Bell's inequality is easy to prove[9], we avoid it here because the card game reverses roles regarding probability: Instead of the investigators attempting to ascertain the photons' so-called hidden variables, the players are acting as particles attempting to win the game by guessing the measurement angles. Another Figure 1 | The outside casing of each device remains station- complication is that the original form of Bell's inequal- ary while the circle with parallel lines rotates with the center ity does not adequately model the partners' version of arrow pointing in one of three directions (♥, ♣, ♠.) If Jacks the game because humans have the freedom to exhibit are used to represent these directions, Alice will see J♥ as her question card. She will respond with an "odd"-numbered a behavior not observed by entangled particles (under answer card (3♥) to indicate that she is blocked by the filter. ideal experimental conditions). This behavior involves a If Bob passes through a filter with the "spade" orientation, 100% correlation (or anti-correlation) whenever the po- he sees J♠ as the question card, and answers with the "even" larization measurement angles are either parallel or numbered 2♠. This wins one point for the team because perpendicular to each other.[10] In the partners' version they gave different answers to different questions. of the card game, this behavior must be enforced by de- ducting a penalty from the partners' score whenever Figure 1 shows a hypothetical and idealized experi- they are caught using a forbidden strategy (which we ment involving two entangled photons simultaneously shall later call the β-strategy). The minimum required emitted by a single (parent) atom. After the photons penalty is calculated in Supplementary file:The car have been separated by some distance, each is ex- and the goats. Fortunately students need not master posed to a measurement that determines whether the this calculation because the actual penalty should often photon would pass or be blocked by the polarizing fil- be whatever it takes to encourage a strategy that mim- ter.[8] To ensure that the results seem "spooky" it ics this aspect of entanglement (which we shall call the should be possible to rotate the filter while the pho- α-strategy.) tons are en route so that the filter's angle of orienta- A theoretical understanding of how one can model en- tion is not "known" to either photon until it encounters tanglement using the Schrödinger equation can be the filter. If the filters are rotated between only three found in Supplementary file:Tube entanglement. polarization angles, we may use card suits (hearts ♥, clubs ♣, spades ♠) to represent these angles. These The solitaire card game three polarization angles are associated with "ques- Figure 2 shows the three possible outcomes associated tion" cards, because the measurement essentially asks with one hand of the solitaire version of the game. The the photon a question: solitaire version requires nine cards. The figure uses a set with three "jacks" (♥ ♣ ♠) for the questions, and (2,3) "Will you pass through a filter oriented at for the six (even/odd) answer cards. To play one round this angle?" of the game, the player first shuffles the three question For simplicity we restrict our discussion to symmetric cards and places them face down so their identity is not angles (0°, 120°, 240°.) The filter's axis of polarization known. Next, for each of the three suits, the player se- is shown in the figure as parallel lines, with the center lects an even or odd answer card. The figure shows the line pointing to the heart, club, or spade. Any face card player choosing the heart and club to be even, while the can be used to "ask" the question, and the four face spade is odd: 2♥ 2♣ 3♠. This is the only viable strategy, cards (jack, queen, king, ace) are equivalent. If the de- since the alternative is to always lose by selecting three tectors are flawless, each measurement is binary: The answers that are all even or all odd. In the partner's ver- photon either passes or is blocked by the filter (subse- sion we shall introduce a second, β-strategy, which is quent measurements on a photon would yield nothing not possible in the solitaire game. interesting.) The measurement's outcome is repre- After three answer cards are selected and turned face sented by an even or odd numbered "answer" card (of up, two of the three question cards are randomly se- the same suit). The numerical value of an answer card lected and also turned face up. Figure 2 depicts all three is not important: all even numbers (2,4,6,8) are equiva- equally probable outcomes, or ways to select two out of lent and represent a photon passing through the filter, 2 of 10 | WikiJournal of Science WikiJournal of Science, 2018, 1(1):6 doi: 10.15347/wjs/2018.005 Research Article three cards (3 choose 2.)[11] The round is scored by add- with a probability of 3/4. Table 1 shows that this scoring ing or subtracting points, as shown in Table 1: First the system causes humans to average a loss of at least 1/3 suit of each of the two upturned question cards is of a point per round, while entangled particles maintain matched to the corresponding answer card.