Rules for

Derivatives (Dx): β€’ In this tutorial we will use Dx for the ( ). Dx indicates that we are taking the derivative with respect to x. ( ) is another symbol𝒅𝒅 for representing a derivative. 𝒅𝒅𝒅𝒅 β€’ The derivative represents the β€² of the some x, and slope represents a of change at that point. 𝑓𝑓 π‘₯π‘₯ β€’ The derivative (Dx) of a () is zero. . Ie: y = 3 since y is the same for any x, the slope is zero (horizontal )

Power Rule: The fundamental tool for finding the Dx of f(x)

β€’ multiply the exponent the coefficient of x and then reduce the exponent by 1

2 2 Ex: [ ] ( ) = 3 = 3 1 2 2 [ ] ( ) = [ πŸ‘πŸ‘ + ] β€² ( ) = 3 = 3 𝑦𝑦𝑦𝑦𝑦𝑦𝑦𝑦𝑦𝑦𝑦𝑦 𝑫𝑫𝑫𝑫 𝒙𝒙 β†’ 𝑓𝑓 π‘₯π‘₯ π‘₯π‘₯ 𝑑𝑑𝑑𝑑 π‘₯π‘₯ 𝑛𝑛 β€² π‘›π‘›βˆ’ πŸ‘πŸ‘ β€² 𝐷𝐷𝐷𝐷 π‘₯π‘₯ �⎯⎯⎯� 𝑓𝑓 π‘₯π‘₯ 𝑛𝑛π‘₯π‘₯ * [dx represents𝑫𝑫 the𝑫𝑫 𝒙𝒙derivativeπŸ“πŸ“ β†’ of𝑓𝑓 whatπ‘₯π‘₯ is insideπ‘₯π‘₯ 𝑑𝑑𝑑𝑑 (x), π‘₯π‘₯ is usually 1 for simple functions, the dx must always be considered and is always there, even if it is only 1]

Sum Rule: The Dx of a is equal to the sum of the Dx’s

[ ( ) + ( )] ( ) + ( ) β€² β€² Ex: [3 2 + 2 + 3] (3 2) + (2 ) + (3𝐷𝐷)𝐷𝐷=𝑓𝑓6π‘₯π‘₯ + 2𝑔𝑔+π‘₯π‘₯0 ⟹ 𝑓𝑓 π‘₯π‘₯ 𝑔𝑔 π‘₯π‘₯ β€² β€² β€² Constant Coefficient𝐷𝐷𝐷𝐷 π‘₯π‘₯ Rule:π‘₯π‘₯ Theβ†’ Dx𝑓𝑓 ofπ‘₯π‘₯ a 𝑓𝑓 π‘₯π‘₯ with 𝐹𝐹a constantπ‘₯π‘₯ coefficient is equal to the constant times the Dx. The constant can be initially removed from the derivation.

[3 2] = 3( [ 2])

Ex: [(4) 2] = ln(4) [ 2] = ln(4) 2 = 2 ln(4) =𝐷𝐷ln𝐷𝐷(4π‘₯π‘₯)2 = ln(𝐷𝐷16𝐷𝐷 )π‘₯π‘₯

Chain Rule:𝐷𝐷𝐷𝐷 There isπ‘₯π‘₯ nothing new𝐷𝐷𝐷𝐷 hereπ‘₯π‘₯ other thanβˆ— theπ‘₯π‘₯ dx is now somethingπ‘₯π‘₯ otherπ‘₯π‘₯ than 1. π‘₯π‘₯ The dx represents the Dx of the inside function g(x). It is called a because you have to consider the dx as not being 1 and take the Dx of the inside also.

[ ( ) ( ) = ( ) ( ) β€² β€² β€² Ex: Dx (sin(3x)) = cos(3x) dx* = 3 cos(3x) 𝐷𝐷 𝐷𝐷 * 𝑓𝑓[dx�𝑔𝑔 isπ‘₯π‘₯ g’(οΏ½ 3x⟹) 𝑓𝑓= οΏ½3𝑔𝑔] π‘₯π‘₯ �𝑑𝑑𝑑𝑑 𝑓𝑓 �𝑔𝑔 π‘₯π‘₯ �𝑔𝑔 π‘₯π‘₯

* [the dx here is g’(x)]

Ex: Dx [(3x2+2)2] = 2(3x2+2) dx* = 2( 3x2+2 ) (6x) = (6x2 + 4)(6x) = 36x3 + 24x

*[dx is Dx (3x2 + 2) = 6x] notice we used the Rule along with the Chain Rule

James S__ Jun 2010 r6 Rules for Derivatives

U-sub: This is when you let some letter equal the whole inside quantity. It can be very useful in a Chain Rule situation. Ex: Dx [(sin(x))3] β–ΊIf we let U = sin(x) then = cos(x) Now we have: Dx [U3] = 3U2du 3[sin(x)]2[cos(x)] β–Ίsubstitute⟹ back in for U and du

Product⟹ Rule: The Dx of a product is equal to the sum of the products Dx of each times the other factor. [ ( ) ( )] [ ( ) ( ) + ( ) ( ) ]

β€² β€² 𝐷𝐷𝐷𝐷 𝑓𝑓 π‘₯π‘₯ β€’ 𝑔𝑔 π‘₯π‘₯ ⟹ 𝑓𝑓 π‘₯π‘₯ 𝑑𝑑𝑑𝑑 β€’ 𝑔𝑔 π‘₯π‘₯ 𝑓𝑓 π‘₯π‘₯ β€’ 𝑔𝑔 π‘₯π‘₯ 𝑑𝑑𝑑𝑑 Ex: 3 2 = 6 ( ) + (3 2) π‘₯π‘₯ π‘₯π‘₯ π‘₯π‘₯ π‘₯π‘₯: 𝑒𝑒Dx (numerator)π‘₯π‘₯ 𝑒𝑒 timesπ‘₯π‘₯ 𝑒𝑒 the denominator minus Dx (denominator) times the numerator, divided by the denominator squared. This is a variation of the .

( ) ( ) ( ) ( ) ( )

( ) β€² [ ( )]2 β€² 𝑓𝑓 π‘₯π‘₯ 𝑓𝑓 π‘₯π‘₯ 𝑔𝑔 π‘₯π‘₯ βˆ’ 𝑓𝑓 π‘₯π‘₯ 𝑔𝑔 π‘₯π‘₯ 𝐷𝐷𝐷𝐷 οΏ½ οΏ½ ⟹ 𝑔𝑔 π‘₯π‘₯ 𝑔𝑔 π‘₯π‘₯ sin ( ) cos ( )(3 ) sin (3 )(3) 3 ( ) 3sin (3 ) ( ) sin (3 ) = = = Ex: 3 (3 )2 9 2 3 2 π‘₯π‘₯ π‘₯π‘₯ π‘₯π‘₯ βˆ’ π‘₯π‘₯ π‘₯π‘₯π‘₯π‘₯π‘₯π‘₯π‘₯π‘₯ π‘₯π‘₯ βˆ’ π‘₯π‘₯ π‘₯π‘₯π‘₯π‘₯π‘₯π‘₯π‘₯π‘₯ π‘₯π‘₯ βˆ’ π‘₯π‘₯

𝐷𝐷𝐷𝐷 οΏ½ π‘₯π‘₯ οΏ½ π‘₯π‘₯ π‘₯π‘₯ π‘₯π‘₯ Special Rules: 1 1 1 β€’ [ln( )] = = [ ( ) ] = ( ) ( ) 𝐷𝐷𝐷𝐷 𝑙𝑙𝑙𝑙𝑙𝑙𝑏𝑏 π‘₯π‘₯ 𝑏𝑏 𝑑𝑑𝑑𝑑 𝐷𝐷𝐷𝐷 π‘₯π‘₯ π‘₯π‘₯ 𝑙𝑙𝑙𝑙 𝑒𝑒 𝑑𝑑𝑑𝑑 1 π‘₯π‘₯ cos ( ) [ln(sin( ))] = cos( ) = = cot( ) π‘₯π‘₯𝑙𝑙𝑙𝑙 𝑏𝑏 Ex: sin ( ) ( ) sin ( ) π‘₯π‘₯

𝐷𝐷𝐷𝐷 π‘₯π‘₯ π‘₯π‘₯1 𝑙𝑙𝑙𝑙 𝑒𝑒 π‘₯π‘₯ 3 π‘₯π‘₯ π‘₯π‘₯ [log(3 2)] = (6 ) = Ex: (3 2)( 10) ( )( 10)

𝐷𝐷𝐷𝐷 π‘₯π‘₯ π‘₯π‘₯ 𝑙𝑙𝑙𝑙 π‘₯π‘₯ π‘₯π‘₯ 𝑙𝑙𝑙𝑙 β€’ [ ] = ln( ) [ ] = (ln( )) π‘₯π‘₯ π‘₯π‘₯ π‘₯π‘₯ π‘₯π‘₯ Ex:𝐷𝐷𝐷𝐷 Dx𝑒𝑒 [3e4x]𝑒𝑒 = 3𝑑𝑑[𝑑𝑑(e4x )[ln(e)]𝑒𝑒 (4)] = 12(e4x) 𝐷𝐷𝐷𝐷 𝑁𝑁 𝑁𝑁 𝑁𝑁 𝑑𝑑𝑑𝑑

2 2 Ex: [13 +5 ] = (13 +5 )[ln(13)](2 + 5) π‘₯π‘₯ π‘₯π‘₯ π‘₯π‘₯ π‘₯π‘₯ 𝐷𝐷𝐷𝐷 π‘₯π‘₯

James S__ Jun 2010 r6