Employability Skills - Study Material
V.H.N.SENTHIKUMARA NADAR COLLEGE (AUTONOMOUS) (Reaccredited with 'A' Grade by NAAC) VIRUDHUNAGAR – 626001
PREFACE One of the primary aims of higher education is to transform the youth into employable lot with the skills needed for jobs. In the present scenario, it is unanimously accepted that employment opportunity is plenty but the employable youth are scarce. This is explicitly revealed when the students fail to score in the competitive examinations conducted by various Recruitment Boards.
Generally every competitive examination touches some basic elements like Reasoning, General Knowledge, Arithmetic, Mental Ability and General Awareness. Keeping this in mind, this study material has been prepared. It aims at giving a basic idea on the elements of competitive examinations. Answers and explanations are given at the and of each unit for easy reference of the students. The students can begin their preparation for competitive examinations with this study material. A journey of thousand miles begins with a single step.
We express our deep sense of appreciation to Dr.R.Vairamuthuvel, Dr.R.Selvam, Dr.V.Manohar, Mr.R.Ayyamperumal, and Mr.G.Rameshkumar for preparing this study material, with all sincerity and total commitment.
Dr.P.Sundara Pandian Principal V.H.N.S.N. College (Autonomous) Virudhunagar.
CONTENTS
Unit No. Title Page No.
I Quantitative Aptitude – I 1 - 20
II Quantitative Aptitude – II 21 - 92
III Verbal Reasoning - I 93 - 123
IV Verbal Reasoning - II 124 - 157
V General Knowledge 158 - 168
Unit - I QUANTITATIVE APTITUDE – I
Average
Percentage
Profit and Loss
Ratio and Proportion
Time and Work
Time and Distance
Employability Skills Unit – I
UNIT – I QUANTITATIVE APTITUDE – I 1.1 Profit and Loss Cost price is that price at which a particular article is bought. Selling price is that price at which a particular article is sold. Profit = SP – CP Loss = CP – SP Profit % = Profit x 100 Loss % = Loss x 100 Cost price Cost price 1. A gold bracelet is sold for Rs.14,500 at a loss of 20%. What is the cost price of the gold bracelet? a) 18525 b) 18000 c) 18125 d) 10500 2. A gold bracelet is sold for Rs.27,000 at a loss of 10%. What is the cost price of the gold bracelet? a) 24000 b) 30000 c) 28125 d) 20500 3. Meena bought a watch with 25% discount on the selling price. If the watch cost her Rs.1,545, What is the original selling price of the watch? a) 260 b) 2060 c) 2600 d) 1500 4. Veena bought a watch with 15% discount on the selling price. If the watch cost her Rs.34000, What is the original selling price of the watch? a) 40000 b) 46000 c) 36000 d) 45000 5. Selling price of 12 fruits is equal to the cost price of 16 fruits. What is the profit percentage? a) 30 b) 33.33 c) 25 d) 20 6. Selling price of 10 fruits is equal to the cost price of 14 fruits. What is the profit percentage? a) 42 b) 33.33 c) 44 d) 40 7. Selling price of 15 fruits is equal to the cost price of 18 fruits. What is the profit percentage? a) 32 b) 33.33 c) 20 d) 35
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8. A shopkeeper sells two radios, each for Rs.2 000. If he gains 12% on one and suffers a loss of 12% on the other, what is his overall gain or loss? a) No gain No loss b) 1.44% Gain c) 1.44% Loss d) 1% Gain 9. A shopkeeper sells two radios, each for Rs.5,000. If he gains 10% on one and suffers a loss of 10% on the other, what is his overall gain or loss? a) No gain No loss b) 1.44% Gain c) 1% Loss d) 1% Gain 10. A shopkeeper sells two radios, each for Rs.10,000. If he gains 20% on one and suffers a loss of 20% on the other, what is his overall gain or loss? a) No gain No loss b) 2% Gain c) 4% Gain d) 4% Loss 11. A wholesaler sells a chair for 15% profit. If he sells the same for Rs.6 less, his profit will be 10%. Find the cost price of the chair. a) 120 b) 150 c) 600 d) 160 12. A wholesaler sells a chair for 14% profit. If he sells the same for Rs.8 less, his profit will be 9%. Find the cost price of the chair. a) 140 b) 150 c) 130 d) 160 13. A retailer sells a box and suffers 15% loss. If he had sold it for Rs.36 more, he would have earned a profit of 10%. What was the cost price? a) 145 b) 148 c) 138 d) 144 14. A retailer sells a box and suffers 12% loss. If he had sold it for Rs.34 more, he would have earned a profit of 13%. What was the cost price? a) 136 b) 138 c) 135 d) 134
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15. A retailer sells a box and suffers 10% loss. If he had sold it for Rs.30 more, he would have earned a profit of 15%. What was the cost price? a) 130 b) 120 c) 150 d) 140 16. A retailer sells goods for Rs.900 and gains 12.5 %. If he wants a profit of 15%, for what price should he sell the goods? a) 450 b) 480 c) 920 d) 980 17. A retailer sells goods for Rs.9900 and gains 10%. If he wants a profit of 20%, for what price should he sell the goods? a) 10800 b) 14800 c) 9000 d) 9800 18. If by selling for Rs.72, there is a loss of 10%. For how much should the article be sold to have a profit of 15%? a) 46 b) 92 c) 192 d) 167 19. If by selling for Rs.4000, there is a loss of 20%. For how much should the article be sold to have a profit of 20%? a) 4000 b) 7000 c) 5000 d) 6000 AVERAGES Average = 푆푢푚 표푓 푎푙푙 푖푡푒푚푠 No.of items Sum of all items = Average x No. of items 20. The average age of a class of 30 students is 18. When the teacher’s age is included the average age becomes 19. What is the age of the teacher? a) 50 b) 49 c) 48 d) 46 21. The average age of a class of 20 students is 21. When the teachers’ age is included the average age becomes 22. What is the age of the teacher? a) 42 b) 43 c) 48 d) 46
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22. The average age of a class of 10 students is 22. When the teachers’ age is included the average age becomes 24. What is the age of the teacher? a) 42 b) 43 c) 44 d) 45 23. The average marks obtained by 9 students were calculated to be 65. Later on, it was found that the mark of one student was wrongly read as 76 instead of 67. Find the correct average. a) 66 b) 64 c) 74 d) 56 24. The average marks obtained by 9 students were calculated to be 65. Later on, it was found that the mark of one student was wrongly read as 86 instead of 77. Find the correct average. a) 66 b) 64 c) 74 d) 56 25. The average marks obtained by 10 students were calculated to be 60. Later on, it was found that the mark of one student was wrongly read as 86 instead of 76. Find the correct average. a) 69 b) 59 c) 79 d) 89 26. The average of 9 consecutive odd numbers is 11. What is the difference between the 1st and last number? a) 20 b) 48 c) 32 d) 16 27. The average of 10 consecutive odd numbers is 11. What is the difference between the 1st and last number? a) 20 b) 18 c) 32 d) 16 28. The average of 15 consecutive odd numbers is 11. What is the difference between the 1st and last number? a) 20 b) 28 c) 32 d) 16 29. The average of 5 consecutive even numbers is 12. What is the difference between the 1st and last number? a) 4 b) 8 c) 2 d) 10
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30. The average of 7 consecutive even numbers is 12. What is the difference between the 1st and last number? a) 4 b) 8 c) 12 d) 10 31. The average of 9 consecutive even numbers is 12. What is the difference between the 1st and last number? a) 4 b) 8 c) 12 d) 16 Percentages ‘Per cent’ means ‘for every one hundred’. It is denoted by the symbol %. For converting a given percentage into a fraction, divide it by 100. For converting a given fraction into a percentage, multiply it by 100. 32. 25% of 75% of 256 = ? a) 45 b) 48 c) 38 d) 16 33. 25% of 75% of 288 = ? a) 45 b) 48 c) 38 d) 54 34. 75% of 25% of 352 = ? a) 66 b) 46 c) 36 d) 56 35. 20% of 30% of a number is 12. Find the number. a) 200 b) 100 c) 220 d) 24 36. 20% of 30% of a number is 36. Find the number. a) 600 b) 700 c) 620 d) 720 37. 20% of 30% of a number is 1872. Find the number. a) 31600 b) 31700 c) 31200 d) 30200 38. A number when decreased by 20% gives 120. Find the number. a) 240 b) 150 c) 160 d) 24
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39. A number when decreased by 16% gives 168. Find the number. a) 200 b) 150 c) 160 d) 180 40. A number when decreased by 22% gives 234. Find the number. a) 300 b) 150 c) 160 d) 180 41. A number when increased by 25% gives 2500. Find the number. a) 2000 b) 1500 c) 625 d) 3125 42. A number when increased by 15% gives 2300. Find the number. a) 2000 b) 1500 c) 2625 d) 3125 43. A number when increased by 24% gives 4960. Find the number. a) 4000 b) 4500 c) 6250 d) 3125 44. A man spends 20% of his income on food and 70% on clothing. If he still has a balance of Rs. 200, what is his total income? a) 200 b) 2000 c) 1200 d) 4000 45. A man spends 10% of his income on food and 70% on clothing. If he still has a balance of Rs. 400, what is his total income? a) 2200 b) 2000 c) 1200 d) 4000 46. A man spends 15% of his income on food and 45% on clothing. If he still has a balance of Rs. 1600, what is his total income? a) 4200 b) 4100 c) 3200 d) 4000 47. A student has to secure 40% of the marks in an examination to qualify. He gets 120 marks and fails by 80 marks. Find the maximum marks. a) 450 b) 500 c) 550 d) 180
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48. A student has to secure 30% of the marks in an examination to qualify. He gets 120 marks and fails by 30 marks. Find the maximum marks. a) 450 b) 500 c) 550 d) 180 49. A student has to secure 50% of the marks in an examination to qualify. He gets 140 marks and fails by 10 marks. Find the maximum marks. a) 450 b) 500 c) 550 d) 300 50. If A’s salary is 25% more than B’s, by how much percent is B’s salary less than A’s? a) 25 b) 20 c) 15 d) 10 51. If A’s salary is 20% more than B’s, by how much percent is B’s salary less than A’s? a) 25 b) 20 c) 15 d) 16.67 52. If A’s salary is 50% less than B’s, how much percent is B’s salary more than A’s? a) 33 b) 50 c) 100 d) 10 53. If A’s salary is 20% less than B’s, how much percent is B’s salary more than A’s? a) 35 b) 25 c) 75 d) 85 54. A seller gives two successive discounts of 10% and 20%. Find the single equivalent discount rate. a) 30 b) 25 c) 10 d) 28 55. A seller gives two successive discounts of 15% and 25%. Find the single equivalent discount rate. a) 36.25 b) 25.25 c) 10.25 d) 28.25 Time and Distance 56. A boy goes to school at a speed of 3 km/hr and returns to the village at a speed of 2 km/hr. If he takes 5 hrs in all, what is the distance between the village and the school? a) 3 b) 8 c) 6 d) 9
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57. A train travels from A to B at the rate of 20 km p.h. and from B to A at the rate of 30 km / hr. What is the average rate for the whole journey? a) 30 b) 25 c) 24 d) 28 58. How many seconds will a train 100 meters long running at the rate of 36 km an hour take to pass a certain telegraph post? a) 30 b) 25 c) 10 d) 28 59. How long does a train 110 meters long running at the rate of 36 km/hr take to cross a bridge 132 meters in length? a) 30 b) 25 c) 10 d) 24.2 60. Two trains 121 metres and 99 metres in length respectively are running in opposite directions, one at the rate of 40 km and the other at the rate of 32 km an hour. In what time will they be completely clear of each other from the moment they meet? a) 21 b) 9 c) 11 d) 28 61. Two trains 121 metres and 99 metres in length respectively are running in same directions, one at the rate of 40 km and the other at the rate of 32 km an hour. In what time will they be completely clear of each other from the moment they meet? a) 99 b) 80 c) 72 d) 16 Ratio and Proportion 62. Find x in the proportion 2: x = 3: 9. a) 6 b) 2 c) 10 d) 9 63. In a college, the ratio of the number of boys to girls is 8 : 5. If there are 160 girls, find the total number of students in the college. a) 300 b) 250 c) 180 d) 416
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64. A dog takes 3 leaps for every 5 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, what is the ratio of the speed of the dog to that of the hare? a) 9:5 b) 2:5 c) 5:9 d) 2:8 65. A and B joined a partnership business by investing Rs.30000 and Rs.50000 respectively. If they earn a profit of Rs. 4000, find A’s share in the profit. a) 300 b) 2500 c) 1500 d) 2800 66. In a partnership, A kept his capital of Rs.50000 for one year and B contributed Rs.40000 for a period of 8 months. Find their profit sharing ratio. a) 3:4 b) 15:8 c) 4:5 d) 1:2 67. A profit of Rs. 30000 is to be distributed among A, B, C in the proportion 3: 5: 7. What will be the difference between B’s and C’s shares?. a) 3000 b) 2500 c) 1000 d) 4000 68. Two numbers are respectively 20% and 50% more than a third number. Find the ratio of the first two numbers. a) 3:5 b) 5:4 c) 4:5 d) 2:3 69. A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share? a) 3000 b) 2800 c) 1700 d) 2000 70. In a mixture of 60 litres, the ratio of milk and water 2:1. If this ratio is to be 1:2, how much quantity of water is to be further added? a) 60 b) 25 c) 80 d) 28 Time and Work 71. A can do a piece of work in 20 days. B can do the same work in 30 days. In how many days, both working together will finish the job? a) 12 b) 25 c) 15 d) 18
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72. A can do a piece of work in 18 days. B can do the same work in 36 days. In how many days, both working together will finish the job? a) 11.50 b) 12 c) 15.50 d) 18.50 73. A can do a piece of work in 15 days. B can do the same work in 30 days. In how many days, both working together will finish the job? a) 10 b) 12 c) 15 d) 18 74. A and B working together can do a piece of work in 12 days whereas B alone can do it in 18 days. How many days will A alone take to do the work? a) 30 b) 36 c) 17 d) 20 75. A and B working together can do a piece of work in 8 days whereas B alone can do it in 12 days. How many days will A alone take to do the work? a) 30 b) 36 c) 24 d) 20 76. A and B working together can do a piece of work in 16 days whereas B alone can do it in 24 days. How many days will A alone take to do the work? a) 30 b) 38 c) 48 d) 20 77. A tap can fill a tank in 15 minutes while another tap can empty it in 20 minutes. If both the taps are opened simultaneously, when will the tank be full? a) 30 b) 60 c) 45 d) 20 78. A tap can fill a tank in 10 minutes while another tap can empty it in 20 minutes. If both the taps are opened simultaneously, when will the tank be full? a) 30 b) 20 c) 25 d) 15 79. A tap can fill a tank in 20 minutes while another tap can empty it in 30 minutes. If both the taps are opened simultaneously, when will the tank be full? a) 30 b) 40 c) 50 d) 60
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80. 12 men can do a piece of work in 15 days. How many men are required to complete the work in 10 days? a) 18 b) 36 c) 26 d) 20 81. 15 men can do a piece of work in 14 days. How many men are required to complete the work in 6 days? a) 30 b) 35 c) 25 d) 20 82. 26 men can do a piece of work in 18 days. How many men are required to complete the work in 12 days? a) 39 b) 35 c) 25 d) 29 Try Yourself 83. Mohan bought a watch with 12% discount on the selling price. If the watch cost her Rs.1760, what is the original selling price of the watch? a) 2600 b) 2060 c) 2000 d) 1500 84. Selling price of 15 fruits is equal to the cost price of 20 fruits. What is the profit percentage? a) 30 b) 33.33 c) 25 d) 20 85. A shopkeeper sells two radios, each for Rs.5 000. If he gains 14% on one and suffers a loss of 14% on the other, what is his over all gain or loss? a) No gain No loss b) 1.96% Gain c) 1.96% Loss d) 1% Gain 86. A retailer sells goods for Rs.8800 and gains 10%. If he wants a profit of 15%, for what price should he sell the goods? a) 10800 b) 14800 c) 9200 d) 9800 87. The average age of a class of 20 students is 18. When the teacher’ age is included the average age becomes 19. What is the age of the teacher? a) 37 b) 39 c) 48 d) 46
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88. The average of 10 consecutive even numbers is 12. What is the difference between the 1st and last number? a) 14 b) 18 c) 2 d) 10 89. A seller gives two successive discounts of 15% and 20%. Find the single equivalent discount rate. a) 32 b) 25 c) 22 d) 28 90. A boy goes to school at a speed of 4 km/hr and returns to the village at a speed of 3 km/hr. If he takes 7 hrs in all, what is the distance between the village and the school? a) 14 b) 18 c) 6 d) 12 91. How many seconds will a train 120 meters long running at the rate of 54 km an hour take to pass a certain telegraph post? a) 3 b) 5 c) 8 d) 12 92. How long does a train 110 meters long running at the rate of 54 km/hr take to cross a bridge 130 meters in length? a) 16 b) 25 c) 10 d) 24 93. A dog takes 4 leaps for every 6 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, what is the ratio of the speed of the dog to that of the hare? a) 9:5 b) 1:2 c) 3:1 d) 2:1 94. In a mixture 90 litres, the ratio of milk and water 2:1. If this ratio is to be 1:2, how much quantity of water is to be further added? a) 60 b) 25 c) 90 d) 28 95. A can do a piece of work in 20 days. B can do the same work in 30 days. In how many days, both working together will finish the job? a) 12 b) 25 c) 15 d) 18 96. A and B working together can do a piece of work in 16 days whereas B alone can do it in 24 days. How many days will A alone take to do the work?
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a) 30 b) 38 c) 48 d) 20 97. A tap can fill a tank in 10 minutes while another tap can empty it in 20 minutes. If both the taps are opened simultaneously, when will the tank be full? a) 30 b) 20 c) 25 d) 15 98. 15 men can do a piece of work in 14 days. How many men are required to complete the work in 6 days? a) 30 b) 35 c) 25 d) 20 99. At an examination, full marks were 500. A got 10% less than B, B 25% more than C and C 20% less than D. If A got 360, what percentage of full marks was obtained by D? a) 80 b) 55 c) 25 d) 20 100. The population of village increases at the rate of 5% every 10 years. What was the population 20 years ago of the village if the present one be 8820? a) 9000 b) 8000 c) 10000 d) 7700 @ @ @ @ @
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Solutions and Answers 1. Cost = Rs.100 Loss = Rs. 20 SP = Rs. 80 Cost = (100/80) x 14500 = Rs. 18,125 Answer: c) 18125 2. Answer: b) 30000 3. Selling price = Rs. 100 Discount = Rs. 25 Cost = Rs. 75 (100 / 75) x 1545 = Rs. 2,060 Answer: b) 2060 4. Answer: a) 40000
5. C−S x 100 = 16−12 x 100 = 33.33 % S 12 Answer: b) 33.33 % 6. Answer: d) 40 7. Answer: c) 20
2 8. 푃푒푟푐푒푛푡푎푔푒 표푓 푙표푠푠 = (Gain % or Loss %) 100 2 푃푒푟푐푒푛푡푎푔푒 표푓 푙표푠푠 = (12) = 1.44% loss (ALWAYS LOSS) 100 Answer: c) 1.44% loss 9. Answer: c) 1% Loss 10. Answer: d) 4% Loss 11. Difference in profit = 15 – 10 = 5% (when both are profits) 5% = 6 푇ℎ푒푟푒푓표푟푒 푐표푠푡 = 6 x 100 = Rs. 120 5 Answer: a) 120 12. Answer: d) 160 13. Difference in profit = 15 + 10 = 25% (when one is profit & another is loss) 25% = 36
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푇ℎ푒푟푒푓표푟푒 푐표푠푡 = 36 x 100 = Rs. 144 25 Answer: d) 144 14. Answer: a) 136 15. Answer: b) 120 16. 900 푥 100 + 15 = 900 푥 115 = 920 100 + 12.5 112.5 Answer: c) 920 17. Answer: a) 10800 18. 72 푥 100 + 15 = 72 푥 115 = 92 100− 10 90 Answer: b) 92 19. Answer: d) 6000 20. Old average + (New N x Change in average) =18 + (31 x 1) = 49 Answer: b) 49 21. Answer: a) 42 22. Answer: c) 44 23. Total marks wrongly increased by (76 – 67) i.e 9 marks Average was wrongly increased by (9 / 9) i.e 1 mark Correct average = 65 – 1 = 64 Answer: b) 64 24. Answer: b) 64 25. Answer: b) 59 26. (9-1) x 2 = 16 (Difference between 2 consecutive odd No.s is 2) Answer: d) 16 27. Answer: b) 18 28. Answer: b) 28 29. (5-1) x 2 = 8 (Difference between 2 consecutive even No.s is 2)
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Answer: b) 8 30. Answer: c) 12 31. Answer: d) 16 32. 256 x (1/4) x (3/4) = 16 x 3 = 48 Answer : b) 48 33. Answer : d) 54 34. Answer : a) 66 35. Number = 12 x (100/20) x (100/30) = 200 Answer : a) 200 36. Answer : a) 600 37. Answer : c) 31200 38. Number = 100 decreased by 20% Result = 80% of the number. 80% = 120 Number = (120 / 80) x 100 = 150 Answer : b) 150 39. Answer : a) 200 40. Answer : a) 300 41. Number = 100 Increased by 25% Result = 125% of the number. 125% = 2500 Number = (2500 / 125) x 100 = 2000 Answer : a) 2000 42. Answer : a) 2000 43. Answer : a) 4000 44. Balance = 100 -20 -70 =10% 10% = 200 Total income = (200 / 10) x 100 = Rs. 2000 Answer : b) 2000 45. Answer : b) 2000 46. Answer : d) 4000 47. Qualifying marks = 120 + 80 = 200 40% = 200
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Maximum marks = (200 / 40) x 100 = 500 Answer : b) 500 48. Answer : b) 500 49. Answer : d) 300 50. B =100 A = 100 + 25 = 125 Required percentage = (25 / 125) x 100 = 20% Answer : b) 20 51. Answer : d) 16.67 52. B =100 A = 100 - 50 = 50 Required percentage = (50 / 50) x 100 = 100% Answer : c) 100 53. Answer : b) 25 54. Single discount % = 1st discount + 2nd discount – (1st dis x 2nd dis / 100) = 10 + 20 – (10 x 20 / 100) = 28% Answer : d) 28 55. Answer : a) 36.25
56. 푅푒푞푑. 퐷𝑖푠푡푎푛푐푒 = 푇표푡푎푙 푡𝑖푚푒 푡푎푘푒푛 푥 Product of the two speeds Addition of the two speeds 5 푥 3 x 2 = 6 푘푚 3 + 2 Answer: c) 6 km 57. 2 x y Average speed = km/hr x + y 2 20 30 Average speed = = 24 km/hr 20 + 30 58. In passing the post the train must travel its own length. 5 Now, 36 km/hr = 36 = 10m/sec 18
100 Therefore reqd. time = = 10 seconds 10
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59. In crossing the bridge, the train must travel its own length plus the length of the bridge. 5 Now, 36 km/hr = 36 = 10m/sec 18
242 Therefore reqd. time = = 24.2 seconds 10 60. As the two trains are moving in opposite directions their relative speed = 40 + 32 = 72 km/hr. 5 = 72× = 20m/sec 18 Total length Therefore reqd. time = Relative speed 121 + 99 = = 11 sec 20 61. Relative Speed = 40 - 32 = 8hr 5 20 = 8× = 18 9 Total length = 121 + 99 = 220m. Total length There, Reqd. time = Relative speed 220 = 9 = 99 sec. 20 62. 2 / x = 3 / 9 3x = 18 ; x = 6 63. (160 / 5) x 13 = 416 64. Dog : Hare = (3*3) leaps of hare : 5 leaps of hare = 9 : 5. 65. A:B = 30000:50000 = 3:5 A’s share = 4000 x (3 / 8) = Rs.1500 66. A = 50000 x 12 = 6 00 000 B = 40000 x 8 = 3 20 000 Ratio = 6 00 000 : 3 20 000 = 15 : 8
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67. (30000 / 15) x 2 = Rs. 4000 68. Let the third No = x First No = (120 /100) x = (6/5)x Second No = (150 /100) x = (3/2)x Ratio = (6/5) : (3/2) = 12:15 = 4:5 69. C gets 1 share more than D. This 1 share = 1000 B’s share = 2 share = Rs.2000 70. Quantity of milk = (60×2/3) litres =40 litres. Quantity of water in it = (60−40) litres =20 litres. New ratio =1:2 Let quantity of water to be added further be x litres. Then, milk: water = (40 / 20+x) Now, (40 / 20+x) = 1 / 2 ⇒ 20+x=80 ⇒ x= 60 71. AB 20 30 Days = = 12 days A+B 20 + 30 72. Answer: b) 12 days 73. Answer: a) 10 days 74. (individual combined) 18 12 Days = = 36 days (individual - combined) 18 - 12 75. Answer: c) 24 76. Answer: c) 48 77. time to empty time to fill 20 × 15 Time= = = 60 minutes time to empty - time to fill 20 - 15 78. Answer: b) 20 79. Answer: d) 60
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80. Days decrease. So more men required. Inverse. 12 x (15 / 10) = 18 81. Answer: b) 35 82. Answer: a) 39 83. Answer: c) 2000 84. Answer: b) 33.33% 85. Answer: c) 1.96% Loss 86. Answer: c) 9200 87. Answer: b) 39 88. Answer: b) 18 89. Answer: a) 32 90. Answer: d) 12 91. Answer: c) 8 92. Answer: a) 16 93. Answer: d) 2:1 94. Answer: c) 90 95. Answer: a) 12 96. Answer: c) 48 97. Answer: b) 20 98. Answer: b) 35 99. Answer: a) 80 100. Answer: b) 8000
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Unit - II QUANTITATIVE APTITUDE – II
Train Speed
Boat and Stream
Simple Interest
Compound Interest
Calendar
Partnerships
Employability Skills Unit – II
UNIT – II QUANTITATIVE APTITUDE – II 1.1 Train Speed Train Speed Problems on trains are most frequently asked questions in any competitive exam. Problems on trains and ‘Time and Distance’ are almost same. The only difference is we have to consider the length of the train while solving problems on trains. Points to remember 1. Time taken by a train of length l metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres. 2. Time taken by a train of length l metres to pass a stationery object of length b metres is the time taken by the train to cover (l + b) metres. 3. Suppose two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s. 4. Suppose two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s. 5. If two trains of length a metres and b metres are moving in opposite directions at u m/s and v m/s, then:
The time taken by the trains to cross each (a + b) sec. other = (u + v) 6. If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then:
The time taken by the faster train to cross the (a + b) sec. slower train = (u - v)
21 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
7. If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then: (A's speed) : (B's speed) = (b : a) Unit Conversion
Some Shortcut Methods Rule 1: If two trains of p meters and q meters are moving in same direction at the speed of x m/s and y m/s (x > y) respectively then time taken by the faster train to overtake slower train is given by
Example 1 Two trains of length 130 meter and 70 meter are running in the same direction with the speed of 50 km/h and 70 km/h. How much time will faster train take to overtake the slower train from the moment they meet? Sol: Let’s say p = 130 meter = 0. 13 km q = 70 meter = 0.07 km x = 70 km/h and y = 50 km/h, So from the equation given above,
0.01 hours = 36 second So it will take 36 seconds to overtake.
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Rule 2: If two trains of p meters and q meters are moving in opposite direction at the speed of x m/s and y m/s respectively then time taken by trains to cross each other is given by
Example 2 Two trains of length 130 meter and 70 meter are running in the opposite direction with the speed of 50 km/h and 70 km/h. How much time will trains take to cross each other from the moment they meet? Sol: Let’s say p = 130 meter = 0. 13 km q = 70 meter = 0.07 km x = 70 km/h and y = 50 km/h, So from the equation given above,
0.0017 hours = 6 seconds So it will take 6 seconds to cross each other.
Solved Problems 101. A train is running at a speed of 40 km/hr and it crosses a post in 18 seconds. What is the length of the train? A. 190 metres B. 160 metres C. 200 metres D. 120 metres
23 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
102. A train, 130 meters long travels at a speed of 45 km/hr crosses a bridge in 30 seconds. The length of the bridge is A. 270 m B. 245 m C. 235 m D. 220 m 103. A train has a length of 150 meters. It is passing a man who is moving at 2 km/hr in the same direction of the train, in 3 seconds. Find out the speed of the train. A. 182 km/hr B. 180 km/hr C. 152 km/hr D. 169 km/hr 104. A train having a length of 240 m passes a post in 24 seconds. How long will it take to pass a platform having a length of 650 m? A. 120 sec B. 99 s C. 89 s D. 80 s 105. A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 140 m long? A. 38 sec B. 35 s C. 44 sec D. 40 s 106. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively. If they cross each other in 23 seconds, what is the ratio of their speeds? A. Insufficient data B. 3 : 1 C. 1 : 3 D. 3 : 2 107. A jogger is running at 9 kmph alongside a railway track in 240 meters ahead of the engine of a 120 meters long train. The train is running at 45 kmph in the same direction. How much time does it take for the train to pass the jogger? A. 46 B. 36 C. 18 D. 22
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 24 Employability Skills Unit – II
108. Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. If the faster train passes the slower train in 36 seconds, what is the length of each train? A. 88 B. 70 C. 62 D. 50 109. Two trains having length of 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions (on parallel tracks). The time which they take to cross each other, is A. 10.8 s B. 12 s C. 9.8 s D. 8 s 110. Two trains are moving in opposite directions with speed of 60 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. The slower train crosses the faster train in --- seconds A. 56 B. 48 C. 47 D. 26 111. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? A. 120 metres B. 180 metres C. 324 metres D. 150 metres 112. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is: A. 45 km/hr B. 50 km/hr C. 54 km/hr D. 55 km/hr 113. The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is: A. 200 m B. 225 m C. 245 m D. 250 m
25 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
114. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is: A. 1 : 3 B. 3 : 2 C. 3 : 4 D. None of these 115. A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform? A. 120 m B. 240 m C. 300 m D. None of these 116. A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long? A. A. 65 sec B. B. 89 sec C. C. 100 sec D. D. 150 sec 117. Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A. 50 m B. 72 m C. 80 m D. 82 m 118. A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long? A. 40 sec B. 42 sec C. 45 sec D. 48 sec 119. Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A. 36 B. 45 C. 48 D. 49
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 26 Employability Skills Unit – II
120. A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger? A. 3.6 sec B. 18 sec C. 36 sec D. 72 sec Boats and Streams Boats and Streams problems are frequently asked problems in competitive exams. Stream: Moving water of the river is called stream. Still Water: If the water is not moving then it is called still water. Upstream: If a boat or a swimmer moves in the opposite direction of the stream then it is called upstream. Downstream: If a boat or a swimmer moves in the same direction of the stream then it is called downstream. Points to remember 1. When speed of boat or a swimmer is given, then it normally means speed in still water. 2. Downstream/ Upstream: In water, the direction along the stream is called downstream. And, the direction against the stream is called upstream. 3. If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then: Speed downstream = (u + v) km/hr. Speed upstream = (u - v) km/hr. 4. If the speed downstream is a km/hr and the speed upstream is b km/hr, then: Speed in still water = ½(a + b) km/hr ab Rate of stream = ½ (a - b) km/hr or 2
27 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
Some Shortcut Methods Rule 1: A man can row certain distance downstream in t1 hours and returns the same distance upstream in t2 hours. If the speed of stream is y km/h, then the speed of man in still water is given by
Example
A man goes certain distance against the current of the stream in 2 hour and returns with the stream in 20 minutes. If the speed of stream is 4 km/h then how long will it take for the man to go 4 km in still water? Sol:
Let’s say t1 = 20 minutes = 0.33 hours and t2 = 1 hours Y = 4, then man’s speed in still water
So man’s speed is 7.94 km/h in still water. Now, time taken by the man to row 4 km in still water
Rule 2: A man can row in still water at x km/h. In a stream flowing at y km/h, if it takes him t hours to row to a place and come back, then the distance between two places is given by
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Example A man can row 4 km/h in still water. When the water is running at 2 km/h, it takes him 2 hours to go to a place and come back. What is the distance between that place and man’s initial position? Sol: Let’s say x = 4 km/h = man’s speed in still water. y = 2 km/h = water’s speed. t = 2, so
Rule 3: A man can row in still water at x km/h. In a stream flowing at y km/h, if it takes t hours more in upstream than to go downstream for the same distance, then the distance is given by
Example A man can row 4 km/h in still water. The water is running at 2 km/h. He travels to a certain distance and comes back. It takes him 2 hours more while travelling against the stream than travelling with the stream. What is the distance? Sol: Let’s say x = 4 km/h = man’s speed in still water. y = 2 km/h = water’s speed. t = 2, so
Rule 4: A man can row in still water at x km/h. In a stream flowing at y km/h, if he rows the same distance up and down the stream, then his average speed is given by
29 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
Example Speed of boat in still water is 9 km/h and speed of stream is 2 km/h. The boat rows to a place which is 47 km away and comes back in the same path. Find the average speed of boat during whole journey. Sol: Let’s say x = 9 km/h = speed in still water Y = 2 km/h = speed of stream
Solved Problems 121. A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream. A. 2 hours B. 3 hours C. 4 hours D. 5 hours 122. A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is: A. 8.5 km/hr B. 9 km/hr C. 10 km/hr D. 12.5 km/hr 123. A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively? A. 2 : 1 B. 3 : 2 C. 8 : 3 D. Cannot be determined
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124. A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is: A. 4 B. 5 C. 6 D. 10 125. In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is: A. 3 km/hr B. 5 km/hr C. 8 km/hr D. 9 km/hr 126. A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water? A. 4 km/hr B. 6 km/hr C. 8 km/hr D. Data inadequate 127. The speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is: A. 1.2 km B. 1.8 km C. 2.4 km D. 3.6 km 128. A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is: A. 2 mph B. 2.5 mph C. 3 mph D. 4 mph 129. A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place? A. 2.4 km B. 2.5 km C. 3 km D. 3.6 km
31 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
130. A boat covers a certain distance downstream in 1 hour, while it comes back in 1 ½ hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water? A. 12 kmph B. 13 kmph C. 14 kmph D. 15 kmph 131. A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water? A. 40 minutes B. 1 hour C. 1 hr 15 min D. 1 hr 30 min 132. A man can row three-quarters of a kilometre against the stream in 11 ¼ minutes and down the stream in 7 ½ minutes. The speed (in km/hr) of the man in still water is: A. 2 B. 3 C. 4 D. 5 133. Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is: A. 16 hours B. 18 hours C. 20 hours D. 24 hours
134. A man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat (in still water) and the stream is: A. 2 : 1 B. 3 : 1 C. 3 : 2 D. 4 : 3
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135. A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is: A. 1 km/hr B. 1.5 km/hr C. 2 km/hr D. 2.5 km/hr 136. A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is: A. 8.5 km/hr B. 10 km/hr. C. 12.5 km/hr D. 9 km/hr 137. A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is: A. 10 B. 6 C. 5 D. 4 138. In one hour, a boat goes 14 km/hr along the stream and 8 km/hr against the stream. The speed of the boat in still water (in km/hr) is: A. 12 km/hr B. 11 km/hr C. 10 km/hr D. 8 km/hr 139. A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is: A. 1 km/hr. B. 2 km/hr. C. 1.5 km/hr. D. 2.5 km/hr. 140. A boatman goes 2 km against the current of the stream in 2 hour and goes 1 km along the current in 20 minutes. How long will it take to go 5 km in stationary water? A. 2 hr 30 min B. 2 hr C. 4 hr D. 1 hr 15 min
33 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
Simple Interest and Compound Interest Simple Interest Concept When a person borrows some money from another person then the borrower has to pay some extra money for the use of that money to the lender. This extra money is called Interest. In other words, the amount charged by lender for giving his money for a specific amount of time is called Interest. The amount of money borrowed is known as Principal. Total of Interest and Principal is known as Total Amount. Amount = Principal + Interest. The borrower has to pay interest according to some percent of principal for the fixed period of time. This percentage is known as Interest Rate. This fixed period may be a year, six months, three months or a month and correspondingly the rate of interest is charged annually, half yearly, quarterly or monthly. For example, the rate of interest is 10% per annum means the interest payable on Rs 100 for one year is Rs 10. Some Basic Formulas If A = Amount P = Principal I = Interest N = No. of years R = Interest Rate Per Year, then Amount = Principal + Interest A = P + I Principal Rate N SimpleIntersest 100
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PNR A 100
Compound Interest Concept In compound interest, the interest for each period is added to the principle before interest is calculated for the next period. With this method the principle grows as the interest is added to it. This method is mostly used in investments such as savings account and bonds. To understand compound interest clearly, let’s take an example. 1000 is borrowed for three years at 10% compound interest. What is the total amount after three years? You can understand the process of compound interest by image shown below.
Year Principal Interest Amount (10%) 1st 1000 100 1100 2nd 1100 110 1210 3rd 1210 121 1331 Difference between Simple Interest and compound interest After three years,
35 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
In simple interest, the total amount would be 1300 And in compound interest, the total amount would be 1331. Some Basic Formulas If A = Amount P = Principle C.I. = Compound Interest T = Time in years R = Interest Rate Per Year
Shortcut Formulas Rule 1: If rate of interest is R1% for first year, R2% for second year and R3% for third year, then
Rule 2: If principal = P, Rate = R% and Time = T years then 1. If the interest is compounded annually:
2. If the interest is compounded half yearly (two times in year):
3. If the interest is compounded quarterly (four times in year):
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Rule 3: If difference between Simple Interest and Compound Interest is given. If the difference between Simple Interest and Compound Interest on a certain sum of money for 2 years at R% rate is given then
If the difference between Simple Interest and Compound Interest on a certain sum of money for 3 years at R% is given then
Rule 3: If sum A becomes B in T1 years at compound interest, then after T2 years
Solved Problems Simple Interest 141. How much time will it take for an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest? A. 2 years B. 3 years C. 1 year D. 4 years
37 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
142. Arun took a loan of Rs. 1400 with simple interest for as many years as the rate of interest. If he paid Rs.686 as interest at the end of the loan period, what was the rate of interest? A. 8% B. 6% C. 4% D. 7% 143. A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is : A. Rs. 700 B. Rs. 690 C. Rs. 650 D. Rs. 698 144. A sum fetched a total simple interest of Rs. 929.20 at the rate of 8 p.c.p.a. in 5 years. What is the sum? A. Rs. 2323 B. Rs. 1223 C. Rs. 2563 D. Rs. 2353 145. A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is: A. Rs. 650 B. Rs. 690 C. Rs. 698 D. Rs. 700 146. Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B? A. Rs. 6400 B. Rs. 6500 C. Rs. 7200 D. Rs. 7500 147. A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9% p.a. in 5 years. What is the sum? A. Rs. 4462.50 B. Rs. 8032.50 C. Rs. 8900 D. Rs. 8925
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148. How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest? A. 3.5 years B. 4 years C. 4.5 years D. 5 years 149. Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest? A. 3.6 B. 6 C. 18 D. Cannot be determined 150. A person borrows Rs.5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 61⁄4% p.a for 2 years. Find his gain in the transaction per year.
A. Rs. 167.50 B. Rs. 150 C. Rs.225 D. Rs. 112.50 Compound Interest 151. A bank offers 5% compound interest calculated on half- yearly basis. A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is: A. Rs. 120 B. Rs. 121 C. Rs. 122 D. Rs. 123 152. The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is: A. 625 B. 630 C. 640 D. 650
39 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
153. There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate? A. Rs. 2160 B. Rs. 3120 C. Rs. 3972 D. Rs. 6240 154. What is the difference between the compound interests on Rs. 5000 for 1½ years at 4% per annum compounded yearly and half-yearly? A. Rs. 2.04 B. Rs. 3.06 C. Rs. 4.80 D. Rs. 8.30 155. The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is: A. 2 B. 2.5 C. 3 D. 4 156. What will be the compound interest on a sum of Rs. 25,000 after 3 years at the rate of 12% p.a.? A. Rs. 9000.30 B. Rs. 9720 C. Rs. 10123.20 D. Rs. 10483.20 157. At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years? A. 6% B. 6.5% C. 7% D. 7.5% 158. The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is: A. 3 B. 4 C. 5 D. 6 159. Albert invested an amount of Rs. 8000 in a fixed deposit scheme for 2 years at compound interest rate 5% p.a. How much amount will Albert get on maturity of the fixed deposit? A. Rs. 8600 B. Rs. 8620 C. Rs. 8820 D. None of these
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160. The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is: A. 6.06% B. 6.07% C. 6.08% D. 6.09% 161. Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is: A. Rs. 1550 B. Rs. 1650 C. Rs. 1750 D. Rs. 2000 162. If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same at the same rate and for the same time? A. Rs. 51.25 B. Rs. 52 C. Rs. 54.25 D. Rs. 60 163. The difference between simple interest and compound on Rs. 1200 for one year at 10% per annum reckoned half-yearly is: A. Rs. 2.50 B. Rs. 3 C. Rs. 3.75 D. Rs. 4 164. The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum? A. 8 B. 10 C. 12 D. Cannot be determined 165. The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is: A. Rs. 400 B. Rs. 500 C. Rs. 600 D. Rs. 800
41 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
Calendar 1. Odd Days: We are supposed to find the day of the week on a given date. For this, we use the concept of 'odd days'. In a given period, the number of days more than the complete weeks are called odd days. 2. Leap Year: (i) Every year divisible by 4 is a leap year, if it is not a century. (ii) Every 4th century is a leap year and no other century is a leap year. Note: A leap year has 366 days. Examples: i. Each of the years 1948, 2004, 1676 etc. is a leap year. ii. Each of the years 400, 800, 1200, 1600, 2000 etc. is a leap year. iii. None of the years 2001, 2002, 2003, 2005, 1800, 2100 is a leap year. 3. Ordinary Year: The year which is not a leap year is called an ordinary year. An ordinary year has 365 days. 4. Counting of Odd Days: 1. 1 ordinary year = 365 days = (52 weeks + 1 day.) 1 ordinary year has 1 odd day. 2. 1 leap year = 366 days = (52 weeks + 2 days) 1 leap year has 2 odd days. 3. 100 years = 76 ordinary years + 24 leap years = (76 x 1 + 24 x 2) odd days = 124 odd days. = (17 weeks + days) 5 odd days. Number of odd days in 100 years = 5.
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Number of odd days in 200 years = (5 x 2) = 3 odd days. Number of odd days in 300 years = (5 x 3) = 1 odd day. Number of odd days in 400 years = (5 x 4 + 1) = 0 odd day. Similarly, each one of 800 years, 1200 years, 1600 years, 2000 years etc. has 0 odd days. Mapping of the number of odd day to the day of the week Number of 0 1 2 3 4 5 6 Odd Days Day of the Sun Mon Tues Wednes Thurs Frid Satur week day day day day day ay day Last day of a century cannot be Tuesday or Thursday or Saturday. For the calendars of two different years to be the same, the following conditions must be satisfied. 1. Both years must be of the same type. i.e., both years must be ordinary years or both years must be leap years. 2. 1st January of both the years must be the same day of the week.
Solved Problems 166. It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010? A. Sunday B. Saturday C. Friday D. Wednesday 167. What was the day of the week on 28th May, 2006? A. Thursday B. Friday C. Saturday D. Sunday 168. What was the day of the week on 17th June, 1998? A. Monday B. Tuesday C. Wednesday D. Thursday
43 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
169. What will be the day of the week 15th August, 2010? A. Sunday B. Monday C. Tuesday D. Friday 170. Today is Monday. After 61 days, it will be: A. Wednesday B. Saturday C. Tuesday D. Thursday 171. If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004? A. Sunday B. Saturday C. Tuesday D. Wednesday 172. On what dates of April, 2001 did Wednesday fall? A. 1st, 8th, 15th, 22nd, 29th B. 2nd, 9th, 16th, 23rd, 30th C. 3rd, 10th, 17th, 24th D. 4th, 11th, 18th, 25th 173. How many days are there in x weeks x days? A. 7x2 B. 8x C. 14x D. 7 174. The last day of a century cannot be A. Monday B. Wednesday C. Tuesday D. Friday 175. On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004? A. Tuesday B. Monday C. Sunday D. Wednesday 176. The calendar for the year 2007 will be the same for the year A. 2017 B. 2018 C. 2014 D. 2016
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 44 Employability Skills Unit – II
177. Which of the following is not a leap year? A. 1200 B. 800 C. 700 D. 2000 178. 01-Jan-2007 was Monday. What day of the week lies on 01-Jan-2008? A. Wednesday B. Sunday C. Friday D. Tuesday 179. 8th Dec 2007 was Saturday, what day of the week was it on 8th Dec, 2006? A. Sunday B. Tuesday C. Friday D. Tuesday 180. On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004? A. Sunday B. Friday C. Saturday D. Monday Partnerships 1. Two or more people can get together to do business by pooling resources. The deal is known as partnership. All the people who have invested money in the partnership are called partners. 2. If investments of all the partners are for the same time period, the gain or loss is distributed among the partners = the ratio of their investments. Assume P and Q invest Rs. aandRs. b respectively for a year in a partnership, then at the end of the year: (P's share of profit): (Q's share of profit) = a : b. 3. If investments are for different time periods, then equivalent capitals are calculated for a unit of time Assume A invests Rs. a for x months and B invests Rs. b for y months then, (A's share of profit) : (B's share of profit)= ax : by
45 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
4. A partner who manages the business is known as a working partner 5. A partner who simply invests the money is a sleeping partner. When more than one person agrees to invest their money to run a business or firm, then this kind of agreement is called partnership. The persons involved in the partnership are called partners. There are two types of partners. 1. Sleeping Partner: Sleeping partner is the person who provides only investment but does not take part in running the business. 2. Working Partner: Working partner is the person who not only invests the money but also takes part in running the business. For this work he is paid some salary or some percent of profit in addition. There are two types of partnership. 1. Simple Partnership: In simple partnership, capitals of partners are invested for the same period of time. 2. Compound Partnership: In compound partnership, capitals of partners are invested for the different period of time. Basic Formulas If two partners A and B are investing their money to run a business then (Simple Partnership)
Capital of A : Capital of B = Profit of A : Profit of B If two partners A and B are investing their money for different period of time to run a business then (Compound Partnership)
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 46 Employability Skills Unit – II
Capital of A × Time period of A : Capital of B × Time period of B = Profit of A : Profit of B Example 1 Jack and Jill start a business by investing $ 2,000 for 8 months and $ 3,000 for 6 months respectively. If their total profit is $ 510 and then what is profit of Jill? Sol: Capital of Jack = 2000 and Time period = 8 months Capital of Jill = 3000 and Time period = 6 months
So, Profit of Jack : Profit of Jill = 8 : 9 So we have 8 + 9 = 17 parts of total profit. Out of this 17 parts, Jack will get 8 parts and Jill will get 9 parts. Now, total profit is 510 So, One Part = 510/17 = 30. Jill’s profit = 30 × 9 = 270 and Jack’s profit = 30 × 8 = 240. If n partners are investing for different period of time then
C1T1 : C2T2 : C3T3 : … : CnTn = P1 : P2 : P3 : … : Pn Where C is the capital invested, T is time period of capital invested and P is profit earned. Example 2 Raju, Kamal and Vinod start a business by investing Rs 5,000 for 12 months, Rs 8,000 for 9 months and Rs
47 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
10,000 for 6 months. If at the end of the year their total profit is Rs 2000 then find the profit of each partner. Sol: Raju’s investment is 5000 for 12 months. Kamal’s investment is 8000 for 9 months. Vinod’s investment is 10000 for 6 months.
So their ratio of investments is 5000 × 12 : 8000 × 9 : 10000 × 6 60 : 72 : 60 5 : 6 : 5 So their profit, Raju : Kamal : Vinod = 5 : 6 : 5 So there are 5 + 6 + 5 = 16 parts of profit. Out of these 16 parts, Raju will get 5 parts, Kamal will get 6 parts and Vinod will get 5 parts. So, Total profit = 2000 One part = 2000/16 = 125 Raju’s profit = 5 × 125 = 625 Kamal’s profit = 6 × 125 = 750 Vinod’s profit = 5 × 125 = 625 Shortcut Methods
Rule 1: If two partners are investing their money C1 and C2 for equal period of time and their total profit is P then their shares of profit are
If these partners are investing their money for different period of time which is T1and T2, then their profits are
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 48 Employability Skills Unit – II
Rule 2: If n partners are investing their money C1, C2, …,Cn for equal period of time and their total profit is P then their shares of profit are
If these partners are investing their money for different period of time which is T1, T2,… ,Tn then their profits are
Solved Problems 181. X and Y invest Rs.21000 and Rs.17500 respectively in a business. At the end of the year, they make a profit of Rs.26400. What is the share of X in the profit? A. Rs.14400 B. Rs.26400 C. Rs.12000 D. Rs.12500 182. X starts a business with Rs.45000. Y joins in the business after 3 months with Rs.30000. What will be the ratio in which they should share the profit at the end of the year? A. 1:2 B. 2:1 C. 1:3 D. 3:1 183. Suresh started a business with Rs.20,000. Kiran joined him after 4 months with Rs.30,000. After 2 months, Suresh withdrew Rs.5,000 of his capital and 2 more months later, Kiran brought in Rs.20,000 more. What should be the ratio in which they should share their profits at the end of the year? A. 21:32 B. 32:21 C. 12:17 D. 17:12
49 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
184. Kamal started a business with Rs.25000 and after 4 months, Kiran joined him with Rs.60000. Kamal received Rs.58000 including 10% of profit as commission for managing the business. What amount did Kiran receive? A. 75000 B. 70000 C. 72000 D. 78000 185. A and B started a partnership business investing Rs. 20,000 and Rs. 15,000 respectively. C joined them with Rs. 20,000 After six months. Calculate B's share in total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business? A. 7500 B. 8500 C. 9000 D. 8000 186. A and B invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and A's share is Rs. 855, the total profit is: A. Rs. 1425 B. Rs. 1500 C. Rs. 1537.50 D. Rs. 1576 187. A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit. A. Rs. 1900 B. Rs. 2660 C. Rs. 2800 D. Rs. 2840 188. A, B and C enter into a partnership in the ratio 7/2:4/3:6/5. After 4 months, A increases his share 50%. If the total profit at the end of one year be Rs. 21,600, then B's share in the profit is: A. Rs. 2100 B. Rs. 2400 C. Rs. 3600 D. Rs. 4000
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 50 Employability Skills Unit – II
189. A, B and C subscribe Rs. 50,000 for a business. A subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 35,000, A receives: A. Rs. 8400 B. Rs. 11,900 C. Rs. 13,600 D. Rs. 14,700 190. Three partners shared the profit in a business in the ratio 5 : 7 : 8. They had partnered for 14 months, 8 months and 7 months respectively. What was the ratio of their investments? A. 5 : 7 : 8 B. 20 : 49 : 64 C. 38 : 28 : 21 D. None of these 191. A starts a business with a capital of Rs. 85,000. B joins in the business with Rs.42500 after some time. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1? A. 5 months B. 6 months C. 7 months D. 8 months 192. A starts a business with Rs.40,000. After 2 months, B joined him with Rs.60,000. C joined them after some more time with Rs.1,20,000. At the end of the year, out of a total profit of Rs.3,75,000, C gets Rs.1,50,000 as his share. How many months after B joined the business, did C join? A. 4 months B. 5 months C. 6 months D. 7 months 193. A and B invest in a business in the ratio 3: 2. Assume that 5% of the total profit goes to charity. If A's share is Rs. 855, what is the total profit? A. 1400 B. 1500 C. 1600 D. 1200
51 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
194. A, B and C invest in a partnership in the ratio: 7/2, 4/3, 6/5. After 4 months, A increases his share 50%. If the total profit at the end of one year be Rs. 21,600, then what is B's share in the profit? A. Rs. 2000 B. Rs. 3000 C. Rs. 4000 D. Rs. 5000 195. A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. What is the share of B in the profit. A. 2660 B. 1000 C. 2300 D. 4000 196. A starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B's contribution in the capital? A. Rs. 7500 B. Rs. 8000 C. Rs. 8500 D. Rs. 9000 197. A and B entered into partnership with capitals in the ratio 4 : 5. After 3 months, A withdrew ¼ of his capital and B withdrew 1/5 of his capital. The gain at the end of 10 months was Rs. 760. A's share in this profit is: A. Rs. 330 B. Rs. 360 C. Rs. 380 D. Rs. 430 198. A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C? A. 3 : 5 : 2 B. 3 : 5 : 5 C. 6 : 10 : 5 D. Data inadequate
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 52 Employability Skills Unit – II
199. A, B, C rent a pasture. A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs. 175, how much must C pay as his share of rent? A. Rs. 45 B. Rs. 50 C. Rs. 55 D. Rs. 60 200. A and B started a business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, C joined them with Rs. 20,000. What will be B's share in total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business? A. Rs. 7500 B. Rs. 9000 C. Rs. 9500 D. Rs. 10,000
53 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
Solutions and Answers Train Speed 101. Answer: Option C Explanation: Speed of the train, v = 40 km/hr = 40000/3600 m/s = 400/36 m/s Time taken to cross, t = 18 s Distance Covered, d = vt = (400/36)× 18 = 200 m Distance covered is equal to the length of the train = 200 m
102. Answer: Option B Explanation: Assume the length of the bridge = x meter Total distance covered = 130+x meter total time taken = 30s speed = Total distance covered /total time taken = (130+x)/30 m/s => 45 × (10/36) = (130+x)/30 => 45 × 10 × 30 /36 = 130+x => 45 × 10 × 10 / 12 = 130+x => 15 × 10 × 10 / 4 = 130+x => 15 × 25 = 130+x = 375 => x = 375-130 =245
103. Answer: Option A Explanation: Length of the train, l = 150m Speed of the man ,Vm= 2 km/hr
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 54 Employability Skills Unit – II
Relative speed, Vr = total distance/time = (150/3) m/s = (150/3) × (18/5) = 180 km/hr Relative Speed = Speed of train, Vt - Speed of man (As both are moving in the same direction) => 180 = Vt - 2 =>Vt = 180 + 2 = 182 km/hr
104. Answer: Option C Explanation: v = 240/24 (where v is the speed of the train) = 10 m/s t = (240+650)/10 = 89 seconds
105. Answer: Option D Explanation: Speed = 45 km/hr = 45×(10/36) m/s = 150/12 = 50/4 = 25/2 m/s Total distance = length of the train + length of the platform = 360 + 140 = 500 meter Time taken to cross the platform = 500/(25/2) = 500×2/25 = 40 seconds
106. Answer: Option D Explanation: Let the speed of the trains be x and y respectively length of train1 = 27x length of train2 = 17y Relative speed= x+ y Time taken to cross each other = 23 s => (27x + 17 y)/(x+y) = 23
55 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
=> (27x + 17 y)/ = 23(x+y) => 4x = 6y => x/y = 6/4 = 3/2
107. Answer: Option B Explanation: Distance to be covered = 240+ 120 = 360 m Relative speed = 36 km/hr = 36×10/36 = 10 m/s Time = distance/speed = 360/10 = 36 seconds 108. Answer: Option D Explanation: Assume the length of each train = x Total distance covered for overtaking the slower train = x+x = 2x Relative speed = 46-36 = 10km/hr = (10×10)/36 = 100/36 m/s Time = 36 seconds 2x/ (100/36) = 36 => (2x × 36 )/100 = 36 => x = 50 meter
109. Answer: Option A Explanation: Distance = 140+160 = 300 m Relative speed = 60+40 = 100 km/hr = (100×10)/36 m/s Time = distance/speed = 300 / (100×10)/36 = 300×36 / 1000 = 3×36/10 = 10.8 s
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 56 Employability Skills Unit – II
110. Answer: Option B Explanation: Relative speed = 60+90 = 150 km/hr (Since both trains are moving in opposite directions) Total distance = 1.1+.9 = 2km Time = 2/150 hr = 1//75 hr = 3600/75 seconds = 1200/25 = 240/5 = 48 seconds
111. Answer: Option D Explanation: 5 50 Speed = 60× m/sec = m/sec 18 3 50 Length of the train = (Speed x Time) = ×9 m = 150 m. 3
112. Answer: Option B Explanation: 125 Speed of the train relative to man = m/sec 10 25 = 2 25 18 = × km/hr 25 = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 x = 50 km/hr.
57 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
113. Answer: Option C Explanation: 5 25 Speed = 45× m/sec = m/sec 18 2 Time = 30 sec. Let the length of bridge be x metres. 130+x 25 Then, 30 2 =2(130 + x) = 750 x = 245 m. 114. Answer: Option B Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27x metres, and length of the second train = 17y metres. 27x+17y 23 x+y 27x + 17y = 23x + 23y 4x = 6y x3 y2 115. Answer: Option B Explanation: 5 Speed = 54× m/sec 18 Length of the train = (15 x 20)m = 300 m.
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 58 Employability Skills Unit – II
Let the length of the platform be x metres. x+300 Then, 15 36 x + 300 = 540 x = 240 m.
116. Answer: Option B Explanation: 240 Speed m / sec = 10 m/sec. 24 240+650 Required time = sec = 89 sec. 10
117. Answer: Option A Explanation: Let the length of each train be x metres. Then, distance covered = 2x metres. Relative speed = (46 - 36) km/hr 5 =10× m/sec 18 2 5 =m/sec 9 2x 25 36 9
=2x = 100 =x = 50.
59 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
118. Answer: Option A Explanation: Formula for converting from km/hr to m/s: X km/hr = 5 X× m/s 18 5 25 Therefore, Speed = 45× m/s m/sec . 18 2 Total distance to be covered = (360 + 140) m = 500 m. Distance Formula for finding Time = Speed 500x2 Required time = sec = 40 sec. 25 119. Answer: Option C Explanation: Relative speed = (60+ 90) km/hr 5 =150× m/sec 18 125 =m/sec . 3 Distance covered = (1.10 + 0.9) km = 2 km = 2000 m. 3 Required time = 2000× sec = 48 sec. 125 120. Answer: Option C Explanation: Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 60 Employability Skills Unit – II
5 = 36× 18 = 10 m/sec. Distance to be covered = (240 + 120) m = 360 m. 360 Time taken = sec = 36 sec. 10 Boats and Streams 121. Answer: Option C Explanation: Speed downstream = (13 + 4) km/hr = 17 km/hr. 68 Time taken to travel 68 km downstream = hrs = 4 hrs. 17 122. Answer: Option C Explanation: Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr. Man's rate against the current = (12.5 - 2.5) km/hr = 10 km/hr.
123. Answer: Option C Explanation: Let the man's rate upstream be x kmph and that downstream be y kmph. Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs. 4 x×8 = y×4 5 44 x=4y 5
61 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
11 yx 5 y + x yx Required ratio = : 22 16xx 1 6 1 xx : 5 2 5 2 83 : 55 8:3
124. Answer: Option B Explanation: Let the speed of the stream be x km/hr. Then, Speed downstream = (15 + x) km/hr, Speed upstream = (15 - x) km/hr. 30 30 1 4 (15xx ) (15 ) 2 900 9 225 x2 2
9x2 225
x2 25 x 5 km/hr
125. Answer: Option C Explanation: Speed in still water = ½ (11 + 5) kmph = 8 kmph.
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 62 Employability Skills Unit – II
126. Answer: Option B Explanation: 16 Rate downstream kmph = 8 kmph. 2 16 Rate upstream kmph = 4 kmph. 4 1 Speed in still water (8 4) kmph = 6 kmph. 2
127. Answer: Option D Explanation: Speed downstream = (15 + 3) kmph = 18 kmph. 12 Distance travelled 18x km = 3.6 km. 60
128. Answer: Option A Explanation: Let the speed of the stream x mph. Then, Speed downstream = (10 + x) mph, Speed upstream = (10 - x) mph. 36 36 90 10xx 10 60 72xx 60 90 100 2
xx2 48 100 10 xx 50 -2 0 x 2mph
63 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
129. Answer: Option A Explanation: Speed downstream = (5 + 1) kmph = 6 kmph. Speed upstream = (5 - 1) kmph = 4 kmph. Let the required distance be x km. xx Then, 1 64 2xx 3 12 5x 12 x 2.4 km.
130. Answer: Option D Explanation: Let the speed of the boat in still water be x kmph. Then, Speed downstream = (x + 3) kmph, Speed upstream = (x - 3) kmph. 3 xx 3 1 3 2 2xx 6 3 9 x 15kmph
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 64 Employability Skills Unit – II
131. Answer: Option C Explanation: 1 Rate downstream = 60 km/hr = 6 km/hr. 10 Rate upstream = 2 km/hr. 1 Speed in still water = (6 2) km/hr = 4 km/hr. 2 5 1 Required time = hrs = 1 hr 15 min. 4 4
132. Answer: Option D Explanation: We can write three-quarters of a kilometre as 750 metres, and 11 ¼ minutes as 675 seconds. 750 10 Rate upstream = m/sec = m/sec. 675 9 750 5 Rate downstream = m/sec = m/sec. 450 3 1 10 5 Rate in still water = m/sec 2 9 3 25 m/sec 18 25 18 km/hr 18 5 = 5 km/hr.
65 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
133. Answer: Option D Explanation: Speed upstream = 7.5 kmph. Speed downstream = 10.5 kmph. 105 105 Total time taken = hours = 24 hours. 7.5 10.5
134. Answer: Option B Explanation: Let man's rate upstream be x kmph. Then, his rate downstream = 2x kmph. 22x x x x (Speed in still water): (Speed of stream)= : 22 3xx = : 22 = 3 : 1
135. Answer: Option A Explanation: Suppose he move 4 km downstream in x hours. Then, 4 Speed downstream = km/hr. x 3 Speed upstream = km/hr. x 48 48 1 =14 or x = . (4/xx ) (3/ ) 2
So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 66 Employability Skills Unit – II
1 Rate of the stream = 86 km/hr = 1 km/hr. 2
136. Answer: Option B Explanation: Man's speed with the current = 15 km/hr speed of the man + speed of the current = 15 km/hr speed of the current is 2.5 km/hr Hence, speed of the man = 15 - 2.5 = 12.5 km/hr man's speed against the current = speed of the man - speed of the current = 12.5 - 2.5 = 10 km/hr
137. Answer: Option C Explanation: Speed of the motor boat = 15 km/hr Let speed of the stream = v Speed downstream = (15+v) km/hr Speed upstream = (15-v) km/hr Time taken downstream = 30/(15+v) Time taken upstream = 30/(15−v) Total time = 30/(15+v)+30/(15−v) It is given that total time is 4 hours 30 minutes = 412 hour = 92 hour i.e., 30/(15+v)+30(15−v)=92 ⇒1(15+v)+1(15−v)=92×30=320 ⇒15−v+15+v(15+v)(15−v)=320 ⇒30152−v2=320 ⇒30225−v2=320
67 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
⇒10225−v2=120 ⇒225−v2=200 ⇒v2=225−200=25 ⇒v=5 km/hr
138. Answer: Option B Explanation: Solution 1: Using Formula Let the speed downstream be a km/hr and the speed upstream be b km/hr, then Speed in still water =12(a+b) km/hr Rate of stream =12(a−b) km/hr Speed in still water = 12(14+8) kmph = 11 kmph. Solution 2: Using Principles Let speed of the boat in still water = a and speed of the stream = b Then a + b = 14 a - b = 8 Adding these two equations, we get 2a = 22 => a = 11 ie, speed of boat in still water = 11 km/hr
139. Answer: Option A Explanation: Assume that he moves 4 km downstream in x hours Then, speed downstream = distance/ time=4x km/hr Given that he can row 4 km with the stream in the same time as 3 km against the stream
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 68 Employability Skills Unit – II i.e., speed upstream = 34of speed downstream=> speed upstream = 3x km/hr He rows to a place 48 km distant and come back in 14 hours =>48(4x)+48(3x)=14= =>12x+16x=14 =>6x+8x=7 =>14x=7 =>x=12 Hence, speed downstream = 4x=4(12) = 8 km/hr speed upstream = 3x=3(12) = 6 km/hr Now we can use the below formula to find the rate of the stream Let the speed downstream be a km/hr and the speed upstream be b km/hr, then Speed in still water =12(a+b) km/hr Rate of stream =12(a−b) km/hr Hence, rate of the stream = 12(8−6) =1 km/hr
140. Answer: Option A Explanation: Speed upstream = 22=1 km/hr Speed downstream = 1(2060)=3 km/hr Speed in still water = 12(3+1)=2 km/hr Time taken to travel 5 km in still water = 52=212 hours = 2 hour 30 minutes
69 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
Simple Interest and Compound Interest 141. Answer: Option A Explanation: P = Rs.900 SI = Rs.81 T = ? R = 4.5% T= 100×SIPR=100×81900×4.5=2 years
142. Answer: Option D Explanation: Let rate = R% Then, Time, T = R years P = Rs.1400 SI = Rs.686 SI=PRT100⇒686=1400× R × R100⇒686=14 R2⇒49=R2⇒R=7 i.e.,Rate of Interest was 7%
143. Answer: Option D Explanation: Simple Interest (SI) for 1 year = 854-815 = 39 Simple Interest (SI) for 3 years = 39 × 3 = 117 Principal = 815 - 117 = Rs.698
144. Answer: Option A Explanation: SI = Rs.929.20 P = ? T = 5 years
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 70 Employability Skills Unit – II
R = 8% P = 100×SIRT=100×929.208×5 = Rs.2323
145. Answer: Option C Explanation: S.I. for 1 year = Rs. (854 - 815) = Rs. 39. S.I. for 3 years = Rs.(39 x 3) = Rs. 117. Principal = Rs. (815 - 117) = Rs. 698.
146. Answer: Option A Explanation: Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 -x). x14 2 (13900 x ) 11 x 2 Then, 3508 100 100 28x - 22x = 350800 - (13900 x 22) 6x = 45000 x = 7500. So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
147. Answer: Option D Explanation: Principal
71 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
100x4016.25 = Rs. 9x5 401625 Rs. 45 = Rs. 8925.
148. Answer: Option B Explanation: 100 81 principla Time = years = 4 years. 450 4.5
149. Answer: Option B Explanation: Let rate = R% and time = R years. 1200 R R Then, 432 100 12R2 = 432 R2 = 36 R = 6.
150. Answer: Option D Explanation: Solution 1 The person borrows Rs. 5000 for 2 years at 4% p.a. simple interest Simple interest that he needs to pay = PRT=(5000×4×2)/100=400 He also lends it at 61⁄4% p.a for 2 years
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 72 Employability Skills Unit – II
Simple interest that he gets = PRT=(5000×25/4×2)/100=625 His overall gain in 2 years = Rs.625 - Rs.400 = Rs.225 His overall gain in 1 year = 2252 = Rs.112.5 Solution 2 The person borrows Rs. 5000 for 2 years at 4% p.a. simple interest He also lends it at 61⁄4% p.a for 2 years 6¼ %−4%=2¼ % So his gain in the transaction for 1 year = The simple interest he gets for Rs.5000 for 1 year at 2 1⁄4% per annum =PRT=5000×94×1100=112.5
151. Answer: Option B Explanation:
2 55 Amount = Rs. 1600 1+ 1600 1 2 100 2 100 41 41 41 = Rs. 1600 1600 40 40 40 41 41 = Rs. 1600 1 40 40 1600 41 81 = Rs. 40 40 = Rs. 3321. C.I. = Rs. (3321 - 3200) = Rs. 121
73 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
152. Answer: Option A Explanation: Let the sum be Rs. x. Then,
2 4 676 51 C. I . x 1 x x x x . 100 625 625 xx4 2 2 SI... 100 25 51xx 2 1 625 25 x = 625.
153. Answer: Option C Explanation: Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years. 100 60 R 10%p.a 100 6 Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
3 10 C. I Rs 12000 1 1 100 331 = Rs.12000 1000 = 3972.
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 74 Employability Skills Unit – II
154. Answer: Option A Explanation:
1 4 4 2 5000 1+ 1 100 100 C.I. when interest compounded yearly = 26 51 = Rs. 5000 25 50 = Rs. 5304.
3 2 C.I. when interest is compounded half-yearly = Rs. 5000 1+ 100
51 51 51 = Rs. 5000 50 50 50 = Rs. 5306.04 Difference = Rs. (5306.04 - 5304) = Rs. 2.04
155. Answer: Option A Explanation: Amount = Rs. (30000 + 4347) = Rs. 34347. Let the time be n years.
n 7 Then, 30000 1 34347 100
n 2 107 34347 11449 107 100 30000 10000 100 n = 2 years.
75 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
156. Answer: Option C Explanation:
3 12 Amount= Rs. 25000 1 100 28 28 28 = Rs.25000 25 25 25 = Rs. 35123.20 C.I. = Rs. (35123.20 - 25000) = Rs. 10123.20
157. Answer: Option A Explanation: Let the rate be R% p.a.
2 R Then, 1200 x 1 = 1348.32 100
2 R 134832 11236 1 100 120000 10000
22 R 106 1 100 100 R 106 1 100 100 R 6%
V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. 76 Employability Skills Unit – II
158. Answer: Option B Explanation:
nn 20 6 PP1 2 2. 100 5 6666 Now, 2. 5555 So, n = 4 years.
159. Answer: Option C Explanation:
2 5 Amount = Rs. 8000 1+ 100 21 21 = Rs.8000 20 20 = Rs. 8820.
160. Answer: Option D Explanation: Amount of Rs. 100 for 1 yearwhen compounded half-yearly
2 3 Rs. 100 1+Rs .106.09 100 Effective rate = (106.09 - 100)% = 6.09%
161. Answer: Option C Explanation:
2 10 C.I. = Rs. 4000 × 1+ 4000 100
77 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
11 11 = Rs.4000 4000 10 10 = Rs. 840. 420 100 Sum = Rs. Rs. 1750. 3 8
162. Answer: Option A Explanation: Sum = Rs. (50 x 100)/(2 x 5) = Rs. 500. Amount = Rs. 500 x [1 + (5/100)]2 = Rs. 500 x (21/20) x (21/20) = Rs. 551.25 C.I. = Rs. (551.25 - 500) = Rs. 51.25
163. Answer: Option B Explanation: S.I. = Rs (1200 x 10 x 1)/ 100 = Rs. 120. C.I. = Rs. {1200 x [1 +(5/100)]2 – 1200} = Rs. 123. Difference = Rs. (123 - 120) = Rs. 3.
164. Answer: Option A Explanation: R 2 15000 x R x 2 15000 x 1 + - 15000 - = 96 100 100
R 2 2R 15000 1 + - 1 - = 96 100 100
15000 (100 + R)2 - 10000 - (200 x R) = 96
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10000 96 x 2 R2 = = 64 3
R = 8. Rate = 8%.
165. Answer: Option B Explanation: Let the sum be Rs. P.
10 2 Then, P 1 + - P = 525 100
11 2
P - 1 = 525 10
525 x 100 P = = 2500. 21
Sum = Rs . 2500. 2500 x 5 x 4 So, S.I. = Rs. = Rs. 500 100
Calendar 166. Answer: Option C Explanation: On 31st December, 2005 it was Saturday. Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. On 31st December 2009, it was Thursday. Thus, on 1st Jan, 2010 it is Friday.
79 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
167. Answer: Option D Explanation: 28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006) Odd days in 1600 years = 0 Odd days in 400 years = 0 5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days 148 days = (21 weeks + 1 day) 1 odd day. Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day. Given day is Sunday.
168. Answer: Option C Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998) Odd days in 1600 years = 0 Odd days in 300 years = (5 x 3)=1 97 years has 24 leap years + 73 ordinary years. Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days. Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days 168 days = 24 weeks = 0 odd day. Total number of odd days = (0 + 1 + 2 + 0) = 3. Given day is Wednesday.
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169. Answer: Option A Explanation: 15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010) Odd days in 1600 years = 0 Odd days in 400 years = 0 9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days. Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days 227 days = (32 weeks + 3 days) 3 odd days. Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days. Given day is Sunday.
170. Answer: Option B Explanation: Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday. After 61 days, it will be Saturday.
171. Answer: Option A Explanation: The year 2004 is a leap year. So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only. The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004. Given that, 6th March, 2005 is Monday. 6th March, 2004 is Sunday (1 day before to 6th March, 2005).
81 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
172. Answer: Option D Explanation: We shall find the day on 1st April, 2001. 1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001) Odd days in 1600 years = 0 Odd days in 400 years = 0 Jan. Feb. Mar. Apr. (31 + 28 + 31 + 1) = 91 days 0 odd days. Total number of odd days = (0 + 0 + 0) = 0 On 1st April, 2001 it was Sunday. In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
173. Answer: Option B Explanation: x weeks x days = (7x + x) days = 8x days.
174. Answer: Option C Explanation: 100 years contain 5 odd days. Last day of 1st century is Friday. 200 years contain (5 x 2) 3 odd days. Last day of 2nd century is Wednesday. 300 years contain (5 x 3) = 15 1 odd day. Last day of 3rd century is Monday. 400 years contain 0 odd day. Last day of 4th century is Sunday. This cycle is repeated.
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Last day of a century cannot be Tuesday or Thursday or Saturday.
175. Answer: Option C Explanation: The year 2004 is a leap year. It has 2 odd days. The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005. Hence, this day is Sunday.
176. Answer: Option B Explanation: For a year to have the same calendar with 2007, the total odd days from 2007 should be 0.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd Days : 1 2 1 1 1 2 1 1 1 2 1 Take the year 2014 given in the choice. Total odd days in the period 2007-2013 = 5 normal years + 2 leap year = 5 x 1 + 2 x 2 = 9 odd days = 2 odd day (As we can reduce multiples of 7 from odd days which will not change anything) Take the year 2016 given in the choice. Number of odd days in the period 2007-2015 = 7 normal years + 2 leap year = 7 x 1 + 2 x 2 = 11 odd days = 4 odd days (Even if the odd days were 0, calendar of 2007 will not be same as the calendar of 2016 because 2007 is not a leap year whereas 2016 is a leap year. In fact, you can straight away
83 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II ignore this choice due to this fact without even bothering to check the odd days) Take the year 2017 given in the choice. Number of odd days in the period 2007-2016 = 7 normal years + 3 leap year = 7 x 1 + 3 x 2 = 13 odd days = 6 odd days Take the year 2018 given in the choice. Number of odd days in the period 2007-2017 = 8 normal years + 3 leap year = 8 x 1 + 3 x 2 = 14 odd days = 0 odd day (As we can reduce multiples of 7 from odd days which will not change anything) Also, both 2007 and 2018 are not leap years. Since total odd days in the period 2007-2017 = 0 and both 2007 and 2018 are of same type, 2018 will have the same calendar as that of 2007
177. Answer: Option C Explanation: Remember the leap year rule (Given in the formulas) 1. Every year divisible by 4 is a leap year, if it is not a century. 2. Every 4th century is a leap year, but no other century is a leap year. 800, 1200 and 2000 comes in the category of 4th century (such as 400, 800, 1200, 1600, 2000 etc). Hence 800, 1200 and 2000 are leap years. 700 is not a 4th century, but it is a century. Hence it is not a leap year
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178. Answer: Option D Explanation: Given that January 1, 2007 was Monday. Odd days in 2007 = 1 (we have taken the complete year 2007 because we need to find out the odd days from 01-Jan-2007 to 31-Dec-2007, that is the whole year 2007) Hence January 1, 2008 = (Monday + 1 Odd day) = Tuesday
179. Answer: Option C Explanation: Given that 8th Dec 2007 was Saturday Number of days from 8th Dec, 2006 to 7th Dec 2007 = 365 days 365 days = 1 odd day Hence 8th Dec 2006 was = (Saturday - 1 odd day) = Friday
180. Answer: Option A Explanation: Given that 8th Feb, 2005 was Tuesday Number of days from 8th Feb, 2004 to 7th Feb, 2005 = 366 (Since Feb 2004 has 29 days as it is a leap year) 366 days = 2 odd days Hence 8th Feb, 2004 = (Tuesday - 2 odd days) = Sunday
Partnerships 181. Answer: Option A Explanation: Ratio of the investment = 21000 : 17500 = 210 : 175 = 42 : 35 = 6 : 5 Share of X in the profit = 26400 × (6/11) = 2400 × 6 = 14400
85 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
182. Answer: Option B Explanation: Ratio in which they should share the profit = Ratio of the investments multiplied by the time period = 45000 × 12: 30000 × 9 = 45 ×12: 30 ×9 = 3 ×12: 2 × 9 = 2:1
183. Answer: Option A Explanation: Here capital is not the same. Suresh invests 20000 for initial 6 months and 15000 for the next 6 months. Hence his term of ratio = (20000×6 + 15000×6) Kiran invest Rs.30000 for 4 months and Rs.50000 for next 4 months. Hence his term of ration = (30000×4 : 50000×4) Suresh :Kiran = ( 20000×6 + 15000×6) : (30000×4 : 50000×4) = (20×6 + 15×6) : (30×4 + 50×4) = (20×3 + 15×3) : (30×2 : 50×2) = 105:160 = 21:32 184. Answer: Option C Explanation: Ratio of the profits = 25000×12 : 60000×8 = 25×12 : 60×8 = 5×3 : 12:2 = 5 : 4×2
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= 5:8 Let the total profit = x. Then Kamal received 10x/100 = x/10 as commission for managing the business Remaining profit = x - x/10 = 9x/10 which is shared in the ration 5:8 Kamal's share = x/10 + (9x/10) × (5/13) = 58000 => x + 9x(5/13) = 580000 =>x(1 + 45/13) = 580000 =>x ( 58/13) = 580000 =>x ( 1/13) = 10000 => x = 130000 Kiran's share = 130000 - 58000 = 72000
185. Answer: Option A Explanation: A : B : C = 20000×24 : 15000×24 : 20000×18 = 20×4 : 15×4 : 20×3 = 4×4 : 3×4 : 4×3 = 4:3:3 B's Share = 25000 × 3/10 = 7500
186. Answer: Option B Explanation: Let the total profit be Rs. 100. After paying to charity, A's share = Rs.95 x (3/5) = Rs. 57. If A's share is Rs. 57, total profit = Rs. 100. If A's share Rs. 855, total profit =(100/57) x 855 = 1500.
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187. Answer: Option B Explanation: For managing, A received = 5% of Rs. 7400 = Rs. 370. Balance = Rs. (7400 - 370) = Rs. 7030. Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3) = 39000 : 42000 : 30000 = 13 : 14 : 10 B's share = Rs.7030 x (14/37) = Rs. 2660.
188. Answer: Option D Explanation: Ratio of initial investments = (7/2) : (4/3) : (6/5) = 105 : 40 : 36. Let the initial investments be 105x, 40x and 36x. A : B : C = [105x × 4 +(150/100) × 105x × 8] : (40x × 12) : (36x × 12) = 1680x : 480x : 432x = 35 : 10 : 9. Hence, B's share = Rs. 21600 x (10/54) = Rs. 4000.
189. Answer: Option D Explanation: Let C = x. Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000. So, x + x + 5000 + x + 9000 = 50000 3x = 36000 x = 12000 A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12. A's share = Rs.35000 × (21/50) = Rs. 14,700.
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190. Answer: Option B Explanation: Let their investments be Rs. x for 14 months, Rs. y for 8 months and Rs. z for 7 months respectively. Then, 14x : 8y : 7z = 5 : 7 : 8.
14x 5 49 Now, = 98x = 40y y = x 8y 7 20 14x 5 112 16 And, = 112x = 35z z = x = x. 7z 8 35 5 49 16 x : y : z = x : x : x = 20 : 49 : 64. 20 5
191. Answer: Option D Explanation: Let B joins for x months. Then A:B = 85000×12 : x× 42500 = 3 : 1 => 850×12 : 425x= 3 : 1 => 850×12/ 425x = 3/1 = 3 => 850×4 /425x = 1 => 2×4/x = 1 => x = 8
192. Answer: Option A Explanation: Assume that C was there in the business for x months A:B:C = 40000×12 : 60000×10 : 120000×x = 40×12 : 60×10 : 120x = 40 : 5×10 : 10x =8 : 10 : 2x = 4 : 5 : x C's share = 375000×x/(9+x) = 150000
89 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – II
=> 375x/(9+x) = 150 => 15x = 6(9+x) => 5x = 18 + 2x => 3x = 18 => x = 18/3 = 6 It means C was there in the business for 6 months. Given that B joined the business after 2 months. Hence C joined after 4 months after B joined
193. Answer: Option B Explanation: Assume that the total profit is x. Since 5% goes for charity, 95% of x will be divided between A and B in the ratio 3: 2 => A's profit = (95x/100) × (3/5) = 855 => 95x/100 = 855×5/3 = 285×5 = 1425 => x = 1425 × 100/95 = 285 × 100/19 = 1500 Hence the total profit = 1500
194. Answer: Option C Explanation: Ratio of the initial investment = 7/2 : 4/3 : 6/5 = 105 : 40 : 36 From this ratio, we can assume that actual initial investments of A, B and C are 105x, 40x and 36x respectively A increases his share 50% after 4 months. Hence the ratio of their investments = (105x × 4) + (105x × 150/100 × 8) : 40x × 12 : 36x : 12 = 105 + (105 × 3/2 × 2) : 40×3 : 36 × 3 = 105 × 4 : 40 ×3 : 36 × 3
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= 35 × 4 : 40 : 36 = 35 : 10 : 9 B's share = total profit × (10/54) = 21,600 × 10/54 = 4000
195. Answer: Option A Explanation: A is a working member and for that, he receive 5% of the profit = 5% of 7400 = 5×7400/100 = 370 Remaining amount = 7400-370 = 7030 Ratio of their investments = 6500×6 : 8400×5 : 10000×3 = 65×6 : 84×5 : 100×3 = 13×6 : 84 : 20×3 = 13×2 : 28 : 20 = 13 : 14 : 10 Share of B in the profit = 7030 × (14/37) = 190×14 = 2660
196. Answer: Option D Explanation: Let B's capital be Rs. x. 3500 x 12 2 Then, = 7x 3
14x = 126000 x = 9000. 197. Answer: Option A Explanation: 1 1 A : B = 4x x 3 + 4x - x 4x x 7 : 5x x 3 + 5x - x 5x x 7 4 5
= (12x + 21x) : (15x + 28x) = 33x :43x = 33 : 43. 33 A's share = Rs. 760 x = Rs. 330. 76
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198. Answer: Option C Explanation: Let the initial investments of A and B be 3x and 5x. A : B : C = (3x x 12) : (5x x 12) : (5x x 6) = 36 : 60 : 30 = 6 : 10 : 5.
199. Answer: Option A Explanation: A : B : C = (10 x 7) : (12 x 5) : (15 x 3) = 70 : 60 : 45 = 14 : 12 : 9. C's rent = Rs.175 x (9/35) = Rs. 45.
200. Answer: Option A Explanation: A : B : C = (20,000 x 24) : (15,000 x 24) : (20,000 x 18) = 4 : 3 : 3. B's share = Rs. 25000 x (3/10) = Rs. 7,500.
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Unit - III VERBAL REASONING - I
Analogy
Classification
Series
Coding and Decoding
Blood Relations
Direction Sense Test
Employability Skills Unit – III
UNIT – III Verbal reasoning – analogy, classification, series, coding & decoding, blood relations, direction sense test I. ANALOGY ‘ANALOGY’ questions demand you to determine the relationship or correspondence between the two words or numbers in pair an then to recognize a similar relationship between the numbers of a different pair of words. Analogy tests are, therefore, meant to test a candidate’s overall knowledge, power of reasoning and ability to think accurately. Given below are some common relationships which will help the candidate detect most analogies in a better way.
A. WORD ANALOGY.
201. Car : Garage : : Aeroplane : ? (a) Port (b) Depot (c) Hanger (d) Harbour
202. Race : Fatigue : : Fast : ? (a) Food (b) Appetite (c) Hunger (d) Weakness
203. Ship : Sea : : Camel : ? (a) Forest (b) Land (c) Mountain (d) Desert
204. Calendar : Dates : : Dictionary : ? (a) Vocabulary (b) language (c) Words (d) Book
205. Motorcycle: Battery : : Life : ? (a) Earth (b) Sun (c) Moon (d) Star
206. Neck is related to Tie in the same way as waist is related to ….? (a) Watch (b) Belt (c) Ribbon (d) Shirt
93 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – III
207. Chapati is to cook as Meat is to …? (a) Boil (b) Fry (c) Bake (d) Roast
208. Cat : Mouse : : ? : ? (a) Horse : Stable (b) Trap : Cheese (c) Bird : Worm (d) Lion : Cage
209. Water is related to Ice in the same way as Lava is related to (a) Rock (b) Ash (c) Flake (d) Peeble
210. Crown is related to Royal in the same way as Crucifix is related to (a) Military (b) Religion (c) Terrorism (d) Throne
B. ALPHABET ANALOGY 211. DDA : ADD : : RRB : ? (a) RBR (b) BRB (c) BRR (d) RBB
212. ACFJ is related to ZXUQ in the same way as EGJN is related to ….? (a) DBYU (b) VTQM (c) VTRP (d) VUSQ
C. NUMBER ANALOGY 213. 9 : 80 : : 7 : ? (a) 48 (b) 50 (c) 78 (d) 82
214. 372 : 124 :: ? : ? (a) 81 : 243 (b) 900 : 450 (c) 624 : 208 (d) 513 :161
215. Which number is like the given set of numbers? (11, 7, 13) (a) 9 (b) 17 (c) 12 (d) 25
216. Which set of numbers is like the given set – ( 64, 32, 8) ? (a) (125, 25, 5) (b) (81, 27, 3) (c) (56, 28, 7) (d) (112, 56, 16)
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I. CLASSIFICATION ‘Classification’ means to select the items of a given group on the basis of certain common quality they posses and then spot the stranger aside.
1. WORD CLASSIFICATION In this type test, we are given a group of certain items in the form of words or numbers/pair of numbers, out of which all except one are of similar nature to one another in some manner. The candidate is required to choose this one time which does not fit into this group.
217. (a) Ear (b) Lung (c) Eye (d) Heart
218. (a) Rose (b) Lotus (c) Marigold (d) Lily
219. (a) Carrot (b) Potato (c) Tomato (d) Ginger
220. (a) Shoulder (b) Foot (c) Elbow (d) Arm
2- ALPHABET CLASSIFICATION A B C D E F G H I J K L M N O P Q R S T U V W X Y Z In this type of question, usually five groups of letters are given. Four of them are similar to each other in same manner and one is different. Choose the group of letters which is different from others.
221. (a) FH (b) IK (c) PN (d) SU
222. (a) ABD (b) HIK (c) VWN (d) QRT
223. (a) CFIL (b) PSVX (c) JMPS (d) ORUX
95 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – III
224. (a) CZHK (b) MLAG (c) XUBU (d) SENO
3 - NUMBERICAL CLASSIFICATION In this type of questions, certain numbers are given out of which all expect one is alike in some manner while one is different and this number is the answer. Choose the one which is different from the other.
225. (a) 11 (b) 13 (c) 15 (d) 17
226. (a) 8 (b) 64 (c) 125 (d) 28
227. (a) 119 (b) 136 (c) 147 (d) 153
228. (a) 385 (b) 572 (c) 671 (d) 427
229. (a) 263 (b) 111 (c) 6242 (d) 383
4. NUMBERICAL PAIR CLASSIFICATION In this type of questions, certain pairs of numbers are given out of which all expect one are similar in some manner while one is different. The numbers in these similar pairs may have the same property or may be related to each according to the same rule. The candidate is required to choose the odd pair. Choose the numeral pair which is different from others.
230. (a) 42 – 4 (b) 36 – 6 (c) 32 – 2 (d) 15 – 5
231. (a) 13 – 21 (b) 19 – 27 (c) 15 – 23 (d) 16 – 24
232. (a) 70 – 80 (b) 54 – 62 (c) 28 – 32 (d) 21 – 24
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233. (a) 7 – 18 (b) 9 – 26 (c) 11 – 36 (d) 13 – 42
234. (a) 24 – 21 (b) 46 – 32 (c) 62 – 23 (d) 84 – 24
II. CODDING - DECODDING A CODE is a system of given a signal and DECODING is a method to decipher the CODE. The Coding and Decoding Test is, therefore, to judge a candidate’s ability to decipher the code language. While solving the problems on coding – decoding, the English alphabets and their number value helps the candidate’s performance.
A B C D E F G H I J K L M 1 2 3 4 5 6 7 8 9 10 11 12 13 N O P Q R S T U V W X Y Z 14 15 16 17 18 19 20 21 22 23 24 25 26
235. If GIVE is coded as 5137 and BAT is coded as 924, how is GATE coded? (a) 427 (b) 2547 (c) 5247 (d) 5724
236. If B = 2, H = 8 and CAB = 6, then what is the number value of RACE? (a) 31 (b) 30 (c) 28 (d) 27
237. In a certain code, 15789 is written as XTZAL and 2346 is written as NPSU. How is 23549 written in that code? (a) NPTUL (b) PNTSL (c) NPTSL (b) (d) NBTSL (e) Road
238. In a certain code, ROAD is written as URDG. How is SWAN written in that code? (a) VXDQ (b) VZDQ (c) UXDQ (d) VZXO
97 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – III
239. If in a certain language REMOTE coded as ROTEME, which word would be coded as PNIICC? (a) NPIICC (b) PICCIN (c) PINCIC (d) PICNIC
EXERCISE 240. If in a certain language MYSTIFY is coded as NZTUJGZ, how is NEMESIS coded in that language? (a) MDLHRDR (b) OFNFTJT (c) ODNHTDR (d) PGOKUGU
241. In a certain code language TAP is written as SZO, then in the same code language, FREEZE is written as (a) EQDFYG ( b) ESDFYF (c) GQFDYE (d) EQDDYD
242. In a certain code SIKKIM is written as THLJJL. How is TRAINING written in that code? (a) SQBHOHOH (b) UQBHOHOF (c) UQBJOHHO (d) UQBJOHOH
243. In a certain code MENTION is written as LNEITNO. How is PATTERN written in that code? (a) APTTREM (b) PTAETNR (c) OTAETNR (d) OTAETRN
244. In a certain code, FORGE is written as FPTJ1. How is CULPRIT written in that code? (a) CSJNPGR (b) CVMQSTU (c) CVNSVNZ (d) CXOSULW
245. In a certain language CARROM is coded as BZQQNL, which word will be coded as HOUSE? (a) IPVTF (b) GNTRD (c) INVRF (d) GPTID
246. In a certain language, NEOMAN is coded as OGRQFT, which word will be coded as ZKCLUP? (a) YJBKTO (b) XIZJSN (c) YIZHPJ (d) YIAQKJ
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247. If in a certain language, POPULAR is coded as QPQVMBS, which word would be coded as GBNPVT? (a) FAMOSU (b) FAMOUS (c) FASOUM (d) FOSAUM
248. If in a certain language, CALCUTTA is coded as GEPGYXXE which word would be coded as FSQFCE? (a) BOMBYA (b) BOMBAY (c) BOMYAB (d) BOBAYM
249. If in a certain language, MACHINE is coded as LBBIHOD, which would be coded as SLTMFNB? (a) RKSLEMA (b) TKULGMC (c) RMSNEOA (d) TMUNGOC
250. If in a certain language A is coded as 1, B is coded as 2, and so on, how is BIDDIC coded in that code? (a) 294493 (b) 284563 (c) 375582 (d) 394492
251. If PAINT is coded as 74128 and EXCEL is coded as 93596, then how would you decode ACCEPT? (a) 455978 (b) 547978 (c) 554978 (d) 735961
252. If D = 4, and cover = 63, then BASIS = ? (a) 49 (b) 50 (c) 54 (d) 55
253. If PALAM could be given the code number 43, what code number can be given to SANTACRUZ? (a) 75 (b) 85 (c) 120 (d) 123
254. If Z = 52 and ACT = 48, then BAT will be equal to (a) 39 (b) 41 (c) 44 (d) 46
255. If the cook is called butler, butler is called manager, manager is called teacher, teacher is called clerk and clerk is called principal, who will teach in the class? (a) Cook (b) Butler (c) Manager (d) Clerk
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256. If diamond is called gold, gold is called silver, silver is called ruby and ruby is called emerald, which is cheapest jewel? (a) Diamond (b) Sliver (c) Gold (d) Ruby
257. If eye is called hand, hand is called mouth, mouth is called ear, ear is called nose and nose is called tongue, with which of the following would a person hear? (a) Eye (b) Mouth (c) Nose (d)Ear
258. If rat is called dog, dog is called mongoose, mongoose is called lion, lion is called snake and snake is called an elephant, which is reared as pet? (a) Rat (b) Dog (c) Mongoose (d) Lion
259. If finger is called toe, toe is called foot, foot is called thumb, thumb is called ankle, ankle is called palm and palm is called knee, which one finger has different name? (a) Thumb (b) Ankle (c) Knee (d) Palm
IV. BLOOD RELATIONS KNOWLEDGE OF THE BLOOD RELATIONS i. Mother’s or Father’s Son is called Brother ii. Mother’s or Father’s Daughters is called Sister iii. Mother’s or Father’s Father is called Grand Father iv. Mother’s or Father’s Mother is called Grand Mother v. Mother’s or Father’s brother is called Uncle vi. Mother’s or Father’s sister is called Aunt vii. Son’s Wife is called Daughter-in-law viii. Daughter’s is husband is called Son-in-law ix. Brother’s wife is called sister-in-law x. Sister’s husband or Husband’s wife’s or brother is called Brother-in-law xi. Brother’s son is called nephew xii. Brother’s daughter is called Niece
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260. Sarita introduced a boy as the son of the daughter of the father of her uncle. The boy is Sarita’s ….. (a) Brother (b) Son (c) Uncle (d) Son-in-law
261. Pointing to an old man, Sohan said, “His son is my son’s uncle”. How is old man related to Sohan? (a) Brother (b) Father (c) Uncle (d) Grand Father
262. A and B are brothers. C and D are sisters. A’s son is D’s brother. How is B related to C? (a) Brother (b) Father (c) Uncle (d) Grand Father
263. A + B means ‘A is the brother of’ B; A – B means ‘A is the mother of’ B and A x B means ‘A is the sister of’ B. which of the following means A is the maternal uncle of B? (a) A + C + B (b) A – b + C (c) A + C – B (d) A + C x B
EXERCISE 264. Sohan introduces Mohan as the son of the only brother of his father’s wife. How is Mohan related to Sohan? (a) Cousin (b) Son (c) Uncle (d) Son-in-law
265. Pointing out to a photograph, a man tells his friend, “She is the daughter of the only son of my father’s wife”. How is the girl related to the man in the photograph? (a) Mother (b) Daughter (c) Sister (d) Cousin
266. Pointing to a man, a woman said. “His mother is the only daughter of my mother”. How is the woman related to the man? (a) Mother (b) Daughter (c) Sister (d) Grand Mother
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267. Pointing to a man in a photograph, a woman said, “His brother’s father is the only son of my grandfather”. How is the woman related to the man in the photograph? (a) Mother (b) Aunt (c) Sister (d) Daughter 268. Pointing to a man in the photograph, Ashmita said, “His mother’s only daughter is my mother”. How is Ashmita related to that man? (a) Nephew (b) Wife (c) Sister (d) Niecce
269. In Kunal says, “john’s mother is the only daughter of my mother”. How is Kunal related to John? (a) Brother (b) Father (c) Can’t be found (d) None of these
270 Pointing to a photograph, Anil said, “She is the daughter of my grandfather’s only son”. How is Anil related to the girl in the photograph? (a) Brother (b) Father (c) Can’t be found (d) Cousin
271. Ram has a brother Shyam. Ram is the son of Ramesh. Suresh is Ramesh’s father. How Shyam is related to Suresh? (a) Son (b) Grandson (c) Brother (d) Grandfather
272. i. M is the brother of B ii. B is the brother of N:; and iii. M is the brother of D;
Which of the following statements is definitely true? (a) N is the brother of B (b) N is the brother of D (c) M is the brother of B (d) All of these
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V. DIRECTION SENSE TEST This test is meant to test the candidate’s ability to trace and follows the direction. Correctly given in the questions asked. The questions asked consist of a sort of puzzle in directions. A successive follow up of directions given in the questions s formulated and the candidate is required to find the final direction or the distance between the two points. There are four major directions and four sub-major directions N
W E
S Four major directions (clock-wise) are North (N); East(E); South (S) and West (W). The word NEWS means the information collected from all directions. Four sub-major directions are (clock wise) North – East (NE); South – East (SE); South – West (SW) and North – West (NW).
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273. A man starts walking from his home south a distance of 50 metres. He took a half towards right. In which directions he walking now? N
W E
S 50 m
a) East b) West c) South West d) North West 274. If south –east becomes North, Norrth becomes southwest and so on, then what will west become?
NW N NE
W E
SW SE S a) South East b) South West c) North East d) North West
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275. A man is facing North-west. He turns 90° in the clock wise direction and then 135° in the anticlockwise direction. Which direction is he facing now? N
NW NE
W E
SW SE S a) East b) West c) South d) North 276. A man walks 30 meters towards South. Then, turning to his right he walks 30 meters. Then, turning to his left he walks 20 meters. Again he turns to his left and walks 30 meters. How far is he from his initial position? (a)30 meters (b) 20 meters (c) 80 meters (d) None of these
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EXERCISE 277. A man is facing West. He turns 45° in the clockwise direction and then another 180° in the same direction and then 270° in the anticlockwise direction. Which direction is he facing now? (a) South (b) North-west (c) West (d) South-west
278. Mahesh walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position? (a) 20 m (b) 30 m (c) 50 m (d) 60 m
279. Suresh walks 20 metres north. Then he turns right and walks 30 m. then he turns right and walk 35 m. Then he turns left and walks 15 m. Then he gains turns left and walks 15 m. In which directions and how many metres away is he from his original position? (a)15 m; West (b) 30 m; East (c) 30 m; West (d) 45 m; East
280. A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 kms. After this he turns to North and walks 9 kms. Now, how far is he from his starting point? (a) 3 kms. (b) 4 kms (c) 5 kms (d) 7 kms
281. If A is to the South of B and C is to the east of B, in what direction is A with respect to C? a) North-East (b) North- West (c) South-East (d) South-West
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282. In the given figure, P is 300 km eastward of O and Q is 400 kms North of O, R is exactly in the middle of Q and P. The distance between Q and R is: North
Q
East O R P (a) 250 kms (b) 250 √2 kms. (c) 300 kms (d) 350 kms 283. Ravi wants to go to the school. He starts from his home which is in the East and comes to the crossing. The road to the left ends in a theatre, straight ahead is the hospital. In which direction is the school? (a) East (b) West (c) North (d) South
284. Ankit, Bansi, Rohan and Sohan are friends. They play cards. Ankit and Bansi become partners. Sohan faces North. If Ankit faces towards West, then who faces towards South? (a) Bansi (b) Rohan (c) Sohan (d) Data is inadequate 285. P, Q, R and S are playing carom game. P, R and S, Q are partners. S is to the right of R who is facing West. Then Q is facing what direction? (a) East (b) West (c) North (d) South
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286. After walking 6kms, I turned right and covered a distance of 2 kms, then turned left and covered a distance of 10 kms. In the end, I was moving towards the North. From which direction did I start my journey? (a) East (b) West (c) North (d) South
VII. SERIES COMPLETION TEST A series is a set of numbers or alphabetical letters, generally called the terms of the series that are following a certain rule or pattern throughout. The candidate has to find this rule and complete the given series by choosing the suitable term or find a wrong term in the series. TYPE I - COMPLETION OF GIVEN NUMBERR SERIES 287. 7, 28, 49, 70, 91, 112 (a) 135 (b) 134 (c) 133 (d) 130
288. 7, 12, 19, 28, 39, __. (a) 49 (b) 57 (c) 50 (d) 52
289. 3, 7, 15, 27, 43, 63, ___. (a) 86 (b) 87 (c) 89 (d) 90
290. 17, 19, 22, 27, 34, 45, (a) 58 (b) 57 (c) 56 (d) 59
291. 1, 2, 6, 15, 31, ____ (a) 47 (b) 52 (c) 55 (d) 56
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Type II- MISSING TERM 292. 11, 23, 48, 99, ____, 409. (a) 200 (b) 202 (c) 201 (d) 205
293. 0, 6, 24, 60, …., 210. (a) 117 (b) 119 (c) 120 (d) 126 Type III- MIXING OF TWO OR MORE SERIES 294. 0, 4, 6, 3, 7, 9, 6, …, 12. (a) 8 (b) 10 (c) 11 (d) 14
295. 1, 1, 3, 9, 6, 36, 10, 100, ….., 225. (a) 15 (b) 16 (c) 20 (d) 25
TYPE 2. FINDING A WRONG NUMBER IN A SERIES 296. Find a wrong number in the series 7, 28, 63, 124, 215, 342, 511. (a) 7 (b) 28 (c) 124 (d) 215
297. Find a wrong number in the series: 9, 19, 37, 75, 149, 297. (a)75 (b) 37 (c) 19 (d) 297
298. 6, 42, 67, (……), 92, 96 (a)77 (b) 82 (c) 70 (d) 83
299. 3, 10, 21, (….), 51 (a)34 (b) 32 (c) 33 (d) 37
300. 128, (….), 82, 62, 44, 28 (a)99 (b) 104 (c) 109 (d) 106
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ANSWER AND EXPLANATIONS
201. Car is temporarily parked in the Garage and Aeroplane is parked in a Hanger. So the answer is (c).
202. Race causes fatigue and fast causes hunger. Hence, (c) is the answer.
203. Ship is the means of transport in sea whereas camel is the means of transport in desert, so the answer is (d).
204. Calendar is a list of dates and dictionary is a collection of words. Hence, the correct choices is (c).
205. Battery is a source of energy for the motorcycle in the same way as the sun is a source of energy for life. The answer is (b).
206. Tie is worn in the neck and belt is worn on the waist. Hence, the correct choice is (b).
207. To cook is the process of making chapattis and to roast is the process for Meat to eat it. The answer is (d).
208. Cat feeds on the mouse and birds feeds on the worms. Thus, the answer is (c).
209. water solidifies to become ice and lava into rock (mainly) (a)
210. Crown indicates Royal state & Crucifix indicates religion attachment (b)
211. The letters are being reversed, so the answer is BRR i.e.(c).
212. A, C, F, J are 1st, 3rd, 6th and 10th letters from the start of alphabets whereas Z, X, U, Q are the 1st, 3rd, 6th and 10th letters from the end. In the same way EGJN are related to VTQM. The answer is (b).
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213. The logic is χ : (χ² - 1 ). So the missing number is 7² - 1 i.e. 48. The correct choice is (a).
214. In the given pair, first number is three times the second. So 624 is three times 208. Hence, the answer is (c).
215. All the numbers in a set are prime numbers. So 17 is a prime number. So the correct choice is (b).
216. In the given set, first numbers is divided by 2 to get the second and second is divided by 4 to get the third number. Hence, the choice is (c).
217. All except Heart are the parts of the human body in a pair whereas Heart is a single one. The answer is (d).
218. Here, all except Lotus are flowers that grow on land whereas Lotus is a water-flower. Hence, (b) is the answer.
219. Here, all except Tomato grow underground. Hence, the answer is (c) .
220. All except Foot are the parts of the hand. Hence, the answer is (b).
221. Here all other groups expect PN, consist of two alternate letters in order, while (c) is in the reverse order. Hence, the answer is (c).
222. Expect VWZ, all other groups consist of three letters in which first two are consecutive letters and the third one is one step forward of the second letter. In VWZ, there are two steps forward between second and third letters. Thus, the answer is (c).
223. In all other groups, expect PSVX, each letter move three steps forward to obtain the next letter. So, the answer is (b).
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224. Here XUBU is the only group in which a letter is repeated. Thus, the answer is (c).
225. 15 is not a prime number, while rests are prime number. Hence, the answer is (c).
226. All except 28 are prefect cubes on some number. So the answer is (d).
227. Only 119 has different factors 7 and 17 and no factor is repeated. So the answer is (a)
228. The middle digit is sum of the other two. This property is not satisfied in (d).
229. Except (e), all other satisfy the property: “Middle number is the product of the other two”. Hence, the answer is (d).
230. In all other pairs except (a), the second number divides the first completely. So (a) is the answer.
231. Difference of two numbers is 8 in each pair, but except (d), others contain odd numbers. Hence, (d) is the answer.
232. In each of the pair except (b), the ratio of two numbers in a pair is 7:8. Hence, (b) is the answer.
233. Except in (c) in all other pairs, 2nd number = 4 times the first minus 10 is the second number. So (c) is the answer.
234. Except (c), other pairs do have a common factor. So the answer is (c).
235. Clearly it can be seen that G is coded as 5; A as 2, T as 4 and E as 7. So the code for GATE into is 5247. The correct choice is (c).
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236. Clearly, in a given code. A = 1, B = 2, C = 3 etc. Now CAB = 3+1+2=6. RACE = 18+1+3+5=27. Hence, the answer is (d)
237. Looking into the method of coding, it is clear that 2 is coded as N, 3 as P, 5 as T, as S and 9 as L. So, 23549 is coded as NPTSL. The answer is (c).
238. Clearly, in ROAD, each letter is moving 3 steps forward to write URDG. So accordingly moving each letter of SWAN 3 steps forward we can write it as VZDQ. So the answer is (b).
239. The groups of second and third letters; fourth and fifth letters in the word interchange places in that code. Hence, the word PICNIC would be coded as PNIICC. (d)
240. (b) Each letter of the word MYSTIFY is moved one step forward to obtain the corresponding letter of the code.
241. (d) Each letter in the given word is moved one step backward to obtain the corresponding letter of the code.
242. (b) The letters in the given word are moved alternately one step forward and one step backward to obtain the letters of the code.
243. (c) Clearly, to obtain the code, the first letter of the word one step backward and the remaining letters are moved in reverse order taking two at a time.
244. (c) First letter remains the same and other letters move one, two, three and four steps forward to obtain the corresponding letter of the code.
245. (a) Each letter of the word is one step ahead of the corresponding letter of the code.
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246. (c) Clearly, the letters in the word are 1, 2, 3, 4, 5 and 6placces before the corresponding alphabets in the given code.
247. (b) Each letter of the word is one step behind the corresponding letter of the code.
248. (a) Each letter of the word is four steps behind the corresponding letter of the code.
249. (b) In the code, we have alternately on letter one step behind and the other onbe step ahead of the corresponding letter in the word.
250. (a)
251. (a)
252. (b) Clearly A = 1, B = 2, C = 3 etc. COVER = 3+15+22+5+18 = 63 BASIS = 2+1+19+9+19 = 50.
253. (d) In the given code A =1, B=2, C = 3……., Z=26 So PALAM = 16 +1+12+1+13= 43. SANTACRUZ = 19 +1+14+20+1+3+18+21+26 = 123
254. (d) In the given code, A = 2, B = 4, C = 6, ……, Z = 52 So ACT = 2+6+40 = 48 BAT = 4+2+40 = 46
255. (a) A letter teaches in a class and as given ‘teacher’ is called ‘clerk’. So a ‘clerk’ will teach in the class.
256. (d) Cheapest jewel is “silver’ and since silver is called ruby, ‘ruby’ is the cheapest.
257. (c) A person hears with his ‘ears’ but ‘ear’ is called ‘nose’. So a person will hear with the ‘nose’.
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258. (c) Clearly ‘dog’ is reared as pet. But ‘dog’ is called ‘mongoose’. So ‘mongoose’ is reared as pet.
259. (b) Clearly, the thumb is a finger having a different name. But ‘thumb’ is called ‘ankle’. So ‘ankle’ is the finger that has a different name.
260. Sol: Usually we start from the end and keep on simplifying: Daughter of uncle’s father means uncle’s sister. Uncle’s sister means mother and son of the mother means her brother. So the boy is Sarita’s brother. The answer is (a).
261. Sohan’s son’s uncle means Sohan’s brother. So, the old man’s son is sohan’s brother,i.e.the old man is the uncle of sohan. The answer is (c).
262. Studying the statements carefully, was find that B is the brother of A and A’s son is the brother of D, so D is the daughter of A. Since C and D are sisters, so C is also the daughter of A. Thus B is the uncle of C. the answer is (c).
263. Note that C has a relation between A and B. Option (1) A + C + B implies that A is the brother of C who is the brother of B means that A is the brother of B. so (1) does not give what is asked. Option (2) also does not say what is required. Option (3) A + C – B means A is the brother of C who is the mother of B means that A is the maternal uncle of B. Hence, the answer is (c).
264. (a) Father’s wife means mother; mother’s brother means uncle and uncle’s son means cousin. So Mohan is Sohan’s cousin.
265. (b) Father’s wife means mother; mother’s only son means himself and thus the girl is daughter to the man.
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266. (a) Only daughter of my mother means herself. So, the woman is the mother of the man.
267. (c) Only son of woman’s grandfather means woman’s father; Man’s brother’s father means man’s father. So the woman is the sister of the man.
268. (d) Ashmita’s mother’s is the man’s mother. So Ashmita mother is man’s sister i.e. Ashmita is the niece of the man.
269. (e) Only daughter of Kunal’s mother means Kunal’s sister. So, John’s mother is Kunal’s sister. i.e. John’s maternal uncle.
270. (a) My grandfather’s only son means my father. So, the girl is the daughter of Anil’s father i.e. Anil is the brother of the girl.
271. (b) Sham is the brother Ram and Ram is the son of Ramesh means that Sham is the son of Ramesh. Now Suresh is the father of Ramesh, therefore Sham is the grandfather of Suresh.
272. (d) All of these. M is brother of N and B is the brother of N means M is the brother of B.
273. The man starts from A towards south and reach B after covering a distance of 50 m. he then takes half right trun and now his position is towards south-west. Ans: (c) South-west
274. South-east becoming North means these directions are turning anti-clockwise through an angle of 135°. Thus, West when moved anti-clockwise through 135° will become South-east. Ans: South-East.
275. Turning 90° from NW clockwise means, he facing NE from NE moving 135° anticlockwise means he is now facing West. Ans: (b) West
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276. (d) the movement of the man is as shown in figure A 30m 30m B C 20m D 30m E The man’s distance from the initial position AE = (AB + BE) = (AB + CD) = (30 + 20) = 50 metres 277. (d) Strictly according to the instructions about the movements of the man, draw the diagram. First turn takes him NW; second turn takes him SE and third turn takes him SW. So finally he is facing SW. N
NW NE
W E
SW SE S
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278. (d) Mahesh starts from A and moves North reaches B. the turns left i.e. West reaches C; now turns left to reach D and finally turns right and reaches E. According to the diagram, now EA = ED+DA=ED+CB=20 + 40 = 60 kms. C 40 B
20 20 E D A 279. (d) Suresh starts from A. His afterward movements are show in the diagram made according to the instructions. His final position is F. Now F lies to the east of A. He is at a distance AF which is (30+15) i.e.45 m. B 30 C
20 A F
D 15 E
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280. (c) The man starts from A and moves to B → C →D → E (his final position).Man’s distance from A = AE. Now
AE² = AL² + LE² = (1 + 2) ² + (9 – 5) ² = 9 + 16 = 25 E
A 1 B L
5 9 C 2 D
281. (d) A diagram is made according to the directions given in the question. Clearly A will be South-west of C. B C East
A South 282. (a) PQ = √OP² +OQ² = √(300)² +(400)² = √100²(3² + 4²) = √100² x 5² =(100 x 5) i.e.500 km. R being in the midway of PQ so QR = 250 kms.
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283. (a) Starting from his house which is eastward, and moves westwards comes at O, the crossing. To his left is theatre (South) and straight i.e. towards, West, there is a hospital. So obviously his school is toward North.
North School W E School House Theatre
South 284. (b) Sohan faces North. Ankit faces West. So his partner Nansi will face towards A i.e. towards East. Now, Rohan who will face Sohan, will face towards South. Rohan
Bansc Ankit
Sohan
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285. (a) According to the data R faces west. S is to the right of R so S facing South. Hence Q who is a partner of S will face North. S P R
Q
286. (c) Remember this logic: “You start from a point in any direction; you now turn right after covering certain distance. You now turn left after covering some distance. You will find that you are now moving in the same direction in which you started. North 10
B 6 C
2 A Now, since finally the man is moving North, this means the man started his journey Northwards.
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287. Clearly the difference between the two consecutive terms is 211. So the next term is 112 + 21 i.e. 133. Hence the answer is (c).
288. Here the given series follows the rule: +5, +7, +9, +11, +13,… The term next to 39 is 39 + 13 i.e 52. Hence, the answer is (d).
289. Clearly, the pattern is +4, +8, +12, +16, +20, +24, …..so the term next to 63 is 63 + 24 i.e. 87. Hence, the answer is (b).
290. Clearly the rule is +2, +3, +5, +7, +11, +13,….. They are prime numbers. The prime number next to 45 is 45 + 13 i.e. 58. Hence, the answer is (a).
291. Here the logic is +1, +4, +9, +16, +25, … i.e 1², 2², 3², 4², 5²,…. So the term next to 31 is 31 + 25 i.e. 56. Hence, the answer is (d).
292. Here the logic is x2+1, +2, +3, +4, +5 …. So the series is 11, 11 x 2 +1, 23 x 2 +2, 48 X 2 +3, 99 X 2 +4I.E. 202. Hence, the answer is (b).
293. the pattern of the sequence is 1³ – 1, 2³ – 2, 3³ – 3, 4³ – 4, 5³ – 5, 6³ – 6,… Thus the missing term is 120. Hence, the answer is (c).
294. The given sequence is a mixture of three series I. 0, 3, 6 II. 4, 7, …. III. 6, 9, 12 The rule in each of these series is+3. So the missing number is7+3i.e.10.Hence, the answer is (b).
295. The given series a mixture of two series: 1, 3, 6, 10, ….. II. 1, 9, 36, 100, 125 The logic of I is +2, +3, +4, +5, and the logic of II is the squares of the corresponding numbers of I. So the missing number is 10 + 5 i.e. 15 (a).
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296. Clearly, the correct sequence is: 2³ – 1, 3³ – 1, 4³ – 1, 5³ – 1, 6³ – 1, 7³ – 1, 8³ – 1 28 is wrong and should be replaced by 3³ – 1 i.e. 26. Hence, the answer is (b).
297. Clearly, the correct sequence is: a. 9, 2x9+1=19, 2x19–1=37, 2x37+=75; 2 x 75–1=149; 2x149+1 = 299. i.e. the logic is x 2±1. b. 297 are wrong and should be replaced by 299. Hence, the answer is (d).
298. (d) The Series is : 6, (+62)42, (+52)67, (+42)83, (+32)92, (+22)96.
299. (a) The series is : 3, (+7)10, (+11) 21, (+13) 34, (+17) 51 (Prime numbers)
300. (b) The series is : 128, (-24) 104, (-22) 82, (-20) 62, (-18) 44, (-16) 28
123 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Unit - IV VERBAL REASONING - II
Number Test
Ranking and Time Sequence Test
Alphabet Test
Logical Venn Diagram
Employability Skills Unit – IV
UNIT – IV VERBAL REASONING
Ranking In this, generally the ranks of a person both from the top and from the bottom will be mentioned and the total number of persons is to be found.
E.g. 2. Radha ranks twentyfirst from the top and twentieth from the bottom in a certain examination. How many students are there in her class? (1) 40 (2) 41 (3) 42 (4) 45
Clearly the whole class consists of (i) 20 students who have a rank higher than Radha (ii) Radha (iii) 19 students who have rank lower than Radha i.e. (20 + 1 + 19) = 40. So, the answer is (1)
301.Kanmani ranked sixteenth from the top and twenty ninth from the bottom among those who passed an examination. Six student did not participate in the competition and five failed in it. How many student were there in the class? A. 35 B. 45 C. 50 D. 55 302.Murugan is sixth from the left end and Prasanna is tenth from the right end in a row of boys. If there are eight boys between Murugan and Prasanna, how many boys are there in the row? A. 22 B. 24 C. 26 D. 28
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303. In a row of girls, Nithya and Suganya occupy the ninth place from the right end and tenth place from the left end, respectively. If they interchange their places, then Nithya and Suganya occupy seventeenth place from the right and eighteenth place from the left respectively. How many girls are there in the row? A. 22 B. 24 C. 26 D. 28 304.In a queue of children, Arun is fifth from the left and Suresh is sixth from the right. When they interchange their places among themselves, Arun becomes thirteenth from the left. Then, what will be Suresh’s position from the right? A. 8th B. 14th C. 15th D. 16th 305.In a queue, Arun is 10th from the front while Mukesh is 25th from behind and Maha is just in the middle of the two. If there be 50 persons in the queue, What position does Maha occupy from the front? A. 17th B. 18th C. 19th D. 20th 306.In a row of boys, if A who is tenth from the left and B who is ninth from the right interchange their positions. A becomes fifteenth from the left. How many boys are there in the row? A. 21 B. 23 C. 27 D. 28 307.In a row of girls, Ramya is fifth from the left and Priya is sixth from the right. When they exchange their positions, then Ramya becomes thirteenth from the left. What will be Priya’s position from the right? A. 7th B. 9th C.12th D. 14th 308. If Ajay finds that he is twelth from the right in a line of boys and fourth from the left, how many boys should be added to the line such that there are 28 boys in the line? A. 13 B. 14 C. 16 D. 20
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309. In a row of boys, A is fifteenth from the left and B is fourth from the right. There are three boys between A and B, C is just left of A. What is the C’s position from the right? A. 5th B. 9th C. 12th D. 13th 310. Rajan ranks eighteenth in a class of 49 students. What is his rank from the last? A. 18 B. 19 C. 31 D. 32 311. N ranks fifth in a class. S is eighth from the last. If T is sixth after N and just in the middle of N and S, then how many students are there in the class? A. 21 B. 23 C. 24 D. 25 312.Some boys are sitting in a row. P is sitting fourteenth from the left and Q is seventh from the right. If there are four boys between P and Q, how many boys are there in the row? A. 19 B. 21 C. 23 D. 25 313. In a class of 35 students, Kamal is placed seventh from the bottom whereas Sunil is placed ninth from the top. Manoj is placed exactly in between the two. What is Kamal’s position from Manoj? A. 7 B. 9 C. 10 D. 12 314. In a queue, Viji is fourteenth from the front and Jack is seventeenth from the end, while Mary is in between Viji and Jack. If Viji be ahead of Jack and there be 48 persons in the queue, how many persons are there between Viji and Mary? A. 5 B. 6 C. 7 D. 8 315. Meena iss 10th and Reena is 6th from left. If Meena and Reena also exchange their positions between themselves, then after the exchange, Meena’s position from the left will be A. 5 B. 6 C. 7 D. 8
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316. Students line up in a queue in which Ashok stands fifteenth from the left and Sakthi is seventh from the right. If they interchange their places, Sakthi would be fifteenth from the right. How many students are there in the queue? A. 21 B. 22 C. 28 D. 29 317. Sugan ranks sixteenth from the top and forty ninth from the bottom in a class. How many students are there in the class? A. 54 B. 64 C. 65 D. 66 318. Ram ranked ninth from the top and thirty–eighth from the bottom in a class. How many students are there in the class? A. 44 B. 45 C. 46 D. 47 319. Mahi ranked ninth from the top and thirty eighth from the bottom in a class. How many students are there in the class? A. 42 B. 44 C. 46 D. 48 320. In a row of girls facing North, Reena is 10th to the left of Pallavi, who is 21st from the right end. If Malini, who is 17th from the left end, is fourth to the right of Reena, how many girls are there in the row? A. 37 B. 41 C. 43 D. 49
Time Sequence The Ability to reason based on the order of time is tested in this section.
321. Ashish leaves his house at 20 minutes to seven in the morning, reaches Kunal`s house in 25 minutes, they finish their breakfast in another 15 minute and leave for
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their office which takes another 35 minutes, At what time do they leave Kunal`s houses to reach their office ? A. 7.40 a.m. B. 7.20 a.m. C. 7.45 a.m. D. 8.15 a.m. 322. Ajay left home for the bus stop 15 minutes earlier than usual. It takes 10 minutes to reach the stop. He reached the stop at 8.40 a.m. What time does he usually leave home for the bus stop ? A. 8.30 a.m. B. 8.45 p.m. C. 8.55 a.m. D. None of these 323. Reaching the place of meeting on Tuesday 15 minutes before 08.30 hours, Anuj found himself half an hour earlier than the man who was 40 minutes late. What was the scheduled time of the meeting ? A. 8.00 hrs B. 8.05 hrs C. 8.15 hrs D. 8.45 hrs 324. The priest told the devotee, "The temple bell is rung at regular intervals of 45 minutes. The last bell was rung five minutes ago. The next bell is due to be rung at 7.45 a.m." At what time did the priest give this information to the devotee ? A. 7.40 a.m. B. 7.05 a.m. C. 7.00 a.m. D. 6.55 a.m. 325. The train for Lucknow leaves every two and a half hours from New Delhi Railway Station. An announcement was made at the station that the train for Lucknow had left 40 minutes ago and the next train will leave at 18.00 hrs. At what time was the announcement made ? A. 15.30 hrs B. 17.10 hrs C. 16.00 hrs D. None of these 326. An application was received by inward clerk in the afternoon of the week day. Next day he forwarded it to the table of the senior clerk, who was on leave that day.
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The senior clerk next day evening put up the application to the desk officer. Desk officer studied the application and disposed off the matter on the same day i.e. Friday. Which day was the application received by the inward clerk ? A. Monday B. Tuesday C. Wednesday D. Earlier week`s Saturday 327. There are twenty people working in an office. The first group of five works between 8.00 A.M. and 2.00 P.M. The second group of ten works between 10.00 A.M. and 4.00 P.M. And the third group of five works between 12 noon and 6.00 P.M. There are three computers in the office which all the employees frequently use. During which of the following hours the computers are likely to be used most ? A. 10.00 A.M. -- 12 noon B. 12 noon -- 2.00 P.M. C. 1.00 P.M. -- 3.00 P.M. D. 2.00 P.M. -- 4.00 P.M. 328. A monkey climbs 30 feet before at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m, at what time will he first touch a flag at 120 feet from the ground ? A. 4 p.m. B. 5 p.m. C. 6 p.m. D. None of these
(I). Kamal is available at home from 12 noon to 4 p.m. on Tuesday, Thursday and Sunday. (II). His younger brother Navin is available at home on Monday, Thursday, Friday and Sunday between 10 a.m. to 2 p.m. (III). The eldest brother Rajiv is available between 9 a.m. to 12 noon on Monday, Wednesday and Thursday and 2 p.m. to 4 p.m. on Friday, Saturday and Sunday.
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329. At a time, on which day of a week all the three brothers are available at home ? A. None B. Sunday C. Thursday D. Canont be determined 330. For how many days only one brother is available at a particular time in a week ? A. One B. Two C. Three D. Four
331. On which day(s) of a week, the youngest and the eldest brothers are available at home at the same time ? A. Only Monday B. Only Thursday C. Only Friday D. Both Monday and Thursday 332. Kailash remembers that his brother Deepak`s birthday falls after 20th May but before 28th May, while Geeta remembers that Deepak`s birthday falls before 22nd May but after 12th May. On what date Deepak`s birthday falls ? A. 20th May B. 21st May C. 22nd May D. Cannot be determined 333.Sangeeta remembers that her father`s birthday was certainly after eighth but before thirteenth of December. Her sister Natasha remembers that their father`s birthday was definitely after ninth but before fourteenth of December. On which date of December was their father`s birthday ? A. 10th B. 11th C. 12th D. Data inadequate
334. If the day before yesterday was Saturday, what day will fall on the day after tomorrow ?
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A. Friday B. Thursday C. Wednesday D. Tuesday 335. Mohini went to the movies nine day ago, She goes to the movies only on Thursday.What day of the week is today? A. Thursday B. Saturday C. Sunday D. Tuesday 336. If the day of a month is Monday, which of the following will be the third day from 21st of the month ? A. Monday B. Tuesday C. Wednesday D. Thursday 337. 1.12.91 is the first Sunday. Which is the fourth Tuesday of December 91 ? A. 17.12.91 B. 24.12.91 C. 26.12.91 D. 31.12.91 338. If Thursday was the day after the day before yesterday five days ago, what is the least number of days ago when Sunday was three days before the day after tomorrow ? A. Two B. Three C. Four D. Five 339. If the 25th of August in a year in Thursday, the number of Mondays in that month is A. 3 B. 4 C. 5 D. 6 340. If 3rd December, 1990 is Sunday, what day is 3rd January, 1991 ? A. Tuesday B. Wednesday C. Thursday D. Friday
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Number Test In this catagory of questions, generally a long series of numbers is given. The candidate is required to find out how many times a number satisfying the condition specified in the question will occur. E.g. 1. How many 9’s are there in the following number sequence which are immediately preceded by 5 but not immediately followed by 3 ?
3 9 5 9 4 5 9 3 7 9 8 5 9 9 8 7 9 5 1 9 6 5 9 4 3 9 5 9 3 8
(1) One (2) Two (3) Three (4) Four The numbers satisfying the given conditions can be shown as follows. 3 9 5 9 4 5 9 3 7 9 8 5 9 9 8 7 9 5 1 9 6 5 9 4 3 9 5 9 3 8. So, the answer is (3)
341. Which is the third number to the left of the number which is exactly in the middle of the following sequence of numbers ? 1 2 3 4 5 6 7 8 9 2 4 6 8 9 7 5 3 1 9 8 7 6 5 4 3 2 1 A. 3 B. 4 C. 5 D. 6 342. How many 3's are there in the following sequence which are neither preceded by 6 nor immediately followed by 9? 9 3 6 6 3 9 5 9 3 7 8 9 1 6 3 9 6 3 9 A. One B. Two C. Three D. Four
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343. Count each 7 which is not immediately preceded by 5 but is immediately followed by either 2 or 3. How many such 7's are there ? 5 7 2 6 5 7 3 8 3 7 3 2 5 7 2 7 3 4 8 2 6 7 8 A. 2 B. 3 C. 4 D. 5 344. How many 6's are there in the following series of numbers which are preceded by 7 but not immediately followed by 9 ? 6 7 9 5 6 9 7 6 8 7 6 7 8 6 9 4 6 7 7 6 9 5 7 6 3 A. One B. Two C. Three D. Four 345. How many 7's are there in the following series which are not immediately followed by 3 but immediately preceded by 8 ? 8 9 8 7 6 2 2 6 3 2 6 9 7 3 2 8 7 2 7 7 8 7 3 7 7 9 4 A. 10 B. 3 C. 2 D. 0
346. Count each 1 in the following sequence of numbers that is immediately followed by 2, if 2 is not immediately followed by 3. How many such 1's are there ? 1 2 1 3 4 5 1 2 3 5 2 1 2 6 1 4 5 1 1 2 4 1 2 3 2 1 7 5 2 1 2 5 A. 2 B. 4 C. 5 D. 7 347. How many 7's are there in the following series which are preceded by 6 which is not preceded by 8 ? 8 7 6 7 8 6 7 5 6 7 9 7 6 1 6 7 7 6 8 8 6 9 7 6 8 7 A. Nil B. One C. Two D. Three
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348. In the following list of numerals, how many 2's are followed by 1's but not preceded by 4 ? 4 2 1 2 1 4 2 1 1 2 4 4 4 1 2 2 1 2 1 4 4 2 1 4 2 1 2 1 2 4 1 4 2 1 2 4 1 4 6 A. Two B. Three C. Four D. Five 349. How many 7's are there in the following sequence which are precedede by 9 and followed by 6 ? 7 8 9 7 6 5 3 4 2 8 9 7 2 4 5 9 2 9 7 6 4 7 A. 2 B. 3 C. 4 D. 5 350. How many 5s are there in the following number sequence, which are immediately preceded by 7 and immediately followed by 6? 7 5 5 9 4 5 7 6 4 5 9 8 7 5 6 7 6 4 3 2 5 6 7 8 A. One B. two C. three D. four 351. How many 6's are there in the following number series , each of which is immediately preceded by 1 or 5 and immediately followed by 3 or 9? 2 6 3 7 5 6 4 2 9 6 1 3 4 1 6 3 9 1 5 6 9 2 3 1 6 5 4 3 2 1 9 6 7 1 6 3 A. none B. one C.two D.three
352. How many 7's immediately preceded by 6 but not immediately followed by 4 are there in the following series? 7 4 2 7 6 4 3 6 7 5 3 5 7 8 4 3 7 6 7 2 4 0 6 7 4 3 A.One B. Two C. Four D. Six 353. In the series given below , count the number of 9's , each of which is not immediately preceded by 5 but is immediately followed by either 2 or 3. How many such 9's are there ?
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1 9 3 2 1 7 4 2 6 9 7 4 6 1 3 2 8 7 4 1 3 8 3 2 5 6 7 4 3 9 5 8 2 0 1 8 7 4 6 3 A. one B. three C. five D. six 354. How many 4's are there preceded by 7 but not followed by 3? 5 9 3 2 1 7 4 2 6 9 7 4 6 1 3 2 8 7 4 1 3 8 3 2 5 6 7 4 3 9 5 8 2 0 1 8 7 4 6 3 A.three B. four C. five D. six. 355. If the positions of the first and the sixth digits of the number 2796543018 are interchanged, similarly the positions of the second and the seventh digits are interchanged and so on, which of the following will be the third to the left of seventh digit from the left end? A. 0 B.1 C. 7 D. 8 356. What will be the difference between the sum of the odd digits and the sum of the even digits in the number 857423? A. 0 B.1 C. 2 D. None 357. If each of the odd digits in the number 54638 is decreased by 1 and each of the even digits is increased by 1, then which of the following will be the sum of the digits of the new number? A. 25 B. 26 C. 28 D. 29 358. How many times will you write even numerals if you write all the numbers from 291 to 300? A. 11 B. 13 C. 15 D. 17 359. A number is greater than 3 but less than 8. Also, it is greater than 6 but less than 10. The number is? A.5 B. 6 C. 7 D. 8
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360) How many 5s are there in the following number sequence which are immediately preceded by 7 and immediately followed by 6? 7 5 5 9 4 5 7 6 4 5 9 8 7 5 6 7 6 4 3 2 5 6 7 8 A. 1 B. 2 C. 3 D. 4
Alphabet Test In this type of questions, certain words are given. The candidate is required to arrange them in the order in which they shall be arranged in a dictionary and then state the word which is placed in the desired place. For such questions, the candidate requires basic knowledge of the ‘Dictionary Usage’. In a dictionary, the words are put in alphabetical order with respect to the second alphabet of the words and so on.
361. Arrange the given words Alphabetical Order and choose the one that comes first. A. Wasp B. Waste C. War D. Wrinkle 362. Arrange the given words Alphabetical Order and choose the one that comes first. A. Science B. Scrutiny C. Scripture D. Script 363. Arrange the given words Alphabetical Order and choose the one that comes first. A. Intense B. Intellect C.Intend D. Integument 364. Arrange the given words Alphabetical Order and choose the one that comes first. A. Nature B. Native C.Narrate D. Nascent
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365. Arrange the given words Alphabetical Order and choose the one that comes first. A. Didactic B.Dictum C.Dictionary D. Diastole 366. In the following question, arrange the given words in the sequence in which they occur in the dictionary and then choose the correct sequence. Salvage, Salad, Salary, Saroopa, Sand A. 1,2,4,5,3 B. 2,1,5,4,3 C. 2,1,4,5,3 D. 2,3,1,5,4 367. How many letters are there in the word 'CREATIVE' which have as many letters between them in the word as in the alphabet ? A. 1 B. 2 C. 3 D. 4 368. In the word 'PARADISE', how many pairs of letters are there which have as many letters between them in the word as in the alphabet ? A. None B. One C. Two D. Three 369. How many pairs of letters in the word 'DABBLE' have as many letters between them in the word as in the alphabet ? A. Nil B. One C. Two D. Three 370. How many pairs of letters are there in the word 'HORIZON' which have as many letters between them in the word as in the English alphabet ? A. One B. Two C. Three D. More than three 371. How many pairs of letters are there in the word 'DONATE' which have as many letters between them as there are in the alphabet ? A. Nil B. One C. Two D. Three
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372. How many pairs of letters in the word 'CHAIRS' have as many letters between them in the word as in the alphabet ? A. None B. One C.Two D. Three
The following three question is based on the following alphabet series. A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
373. In the Engish alphabet, which letter will be to the immediate left of M ? A. N B. L C. O D. K 374. Which letter is sixteenth to the right of the letter which is fourth to the left of I ? A. S B. T C. U D. V 375. If the above alphabets were written in the reverse order, which will be the fifth letter to the left of the ninth letter from the right ? A. P B. N C. D D. W 376. The letter of the word NUMKIPP are in disorder. If they are arranged in proper order, the name of a vegetable is formed.What is the last letter of the .word so formed ? A. K B. M C. N D. P 377. If by arranging the letters of the word NABMODINT, the name of a game is formed, what are the first and the last letters of the word so formed ? A. B, T B. B, N C. N, D D. A, T 378. If it is possible to make a meaningful word with the second, the fifth, the tenth and the twelfth letters of the
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word 'METROPOLITAN', which of the following will be the third letter of that word ? If no such word can be made give X as the answer and if more than one such word can be made, give M as the answer. A. N B. Q C. T D.. M 379. Two letters in the word 'PRESENCE' have as many letters between them in the word as in the alphabet and in the same order. Which one of the two letters comes earlier in the alphabet ? (Hint : Do not count the pair EC, because as mentioned in the question, the letters should be in the same order. Which one of the two letters comes earlier in the alphabet.) A. C B. E C. R D. P 380. H D Y S M W N B Q P O C R T B L Z V E G U F Which three letters have the same distance as they have in the alphabetical order although they have changed places ? A. HMP B. NQZ C. QOE D. YLF
VENN DIAGRAM Venn diagrams are today’s mostly used method for solving syllogisms. With some practice they can be drawn fairly quickly making them a valuable tool in solving syllogisms in timed aptitude tests. Venn diagrams show all possible and hypothetically logical relations between a collection of finite and infinite statements. By means of an overlap between some certain assumptions conclusions can be made using the (in)finite statements. Two examples of the use of Venn diagrams will follow to clarify the above.
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Next follows an example. Syllogism: 1. A car is no boat. 2. Some boats are water bicycles A. No boat is a water bicycle B. Some water bicycles are no cars C. No boat is a car D. Some cars ware no water bicycles
The correct answer of this syllogism is B: some water bicycles are no cars. A useful tool for solving syllogisms is a Venn Diagram. The Venn diagram for this example syllogism is shown above. Venn diagrams enable simple relations between the different statements to results in a valid conclusion of the syllogism. Example a. All hamburgers are meals b. Some cows are hamburgers Possible answers: 1. All meals are cows 2. At least some meals are cows 3. No cows are meals 4. Some cows are no meal It is possible to assign a subject, predicate and middle term for all the statements. However, this would take lot of unnecessary time. Choosing between four statements when solving syllogisms can be handled best by making a Venn diagram straight away. In that way the possible answers from the statements can be checked on their validity piece by piece, resulting in the correct statement.
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First Statement First statement 2a will be examined. The method behind drawing this part of the Venn diagram is exactly the same as the one explained in example 1, resulting in figure 3. In this way the first part of the Venn diagram displays that all hamburgers are meals, since the part with only hamburgers is shaded to result in the overlap area between the two terms; hamburgers and meals. 2nd Statement Next statement 2b is examined. This statement needs a different approach since the statement claims the following: some cows are hamburgers. This means that it is not possible to just shade a whole area as was done before. In order to do that the statement should contain words like “all” or “none”. In this case the statement contains the word “some” and in that case a cross is used to represent that part of the statement in the Venn Diagram. Therefore a cross is put in the overlap between cows and hamburgers, representing the statement that some cows are hamburgers. Linking Statements Linking the two statements and the circles together results in the Venn Diagram of figure 5. With the help of this Venn diagram the 4 statements can be checked for their validity.
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Checking Statements: 1. All meals are cows. However it can be seen that the term meals has an overlap with both hamburgers as well as cows, meaning that both are possible en thus resulting in an invalid statement. 2. Some meals are cows. This is correct, since the Venn diagram clearly shows a link between hamburgers and meals (a) and Cows and hamburgers (b). This automatically generates a link between meals and cows (be aware of the fact that there is no link between cows and meals). The Venn diagram clearly shows that this area is not shaded and thus a possible correct answer. 3. No cows are meals. It can easily be concluded that this statement is incorrect, since an overlap is present between these two terms. 4. Some cows are no meals. Be aware of the rank of the terms. It was already suggested that some cows are hamburgers, but nothing is stated between the relation of cows and meals. In statement 2 the rank was different so conclusions could be made, which in this situation is not the case. In this example the correct answer is statement 2. Most syllogisms can be solved by using the above manner. The trick by solving syllogisms is often correct reading and interpreting of the statements and conclusions for obtaining a valid reasoning. Directions to Solve Each of these questions given below contains three elements. These elements may or may not have some inter linkage. Each group of elements may fit into one of these
142 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar Employability Skills Unit – IV diagrams at (A), (B), (C), (D) and/or (E). You have to indicate the group of elements which correctly fits into the diagrams. 381. Which of the following diagrams indicates the best relation between Travelers, Train and Bus ?
A. B.
C. D. 382. Which of the following diagrams indicates the best relation between Profit, Dividend and Bonus ?
A. B.
C. D. 383. Which of the following diagrams indicates the best relation between Women, Mothers and Engineers ?
A. B.
C. D. 384. Which of the following diagrams indicates the best relation between Factory, Product and Machinery ?
A. B.
C. D. 385. Which of the following diagrams indicates the best relation between Author, Lawyer and Singer ?
A. B.
C. D.
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386. Which of the following diagrams indicates the best relation between Hospital, Nurse and Patient ?
A. B.
C. D. 387. Which of the following diagrams indicates the best relation between Mercury, Zinc and Metal ?
A. B.
C. D. 388. Which of the following diagrams indicates the best relation between Teacher, Writer and Musician ?
A. B.
C. D. 389. Which of the following diagrams indicates the best relation between Boys, Girls and Students ?
A. B.
C. D. 390. Which of the following diagrams indicates the best relation between Tall man, Black haired people and Indians ?
A. B.
C. D.
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Directions to Solve In each of the following questions two statements are given and these statements are followed by two conclusions numbered (1) and (2). You have to take the given two statements to be true even if they seem to be at variance from commonly known facts. Read the conclusions and then decide which of the given conclusions logically follows from the two given statements, disregarding commonly known facts. Give answer: • (A) If only (1) conclusion follows • (B) If only (2) conclusion follows • (C) If either (1) or (2) follows • (D) If neither (1) nor (2) follows and
391. Statements: Some actors are singers. All the singers are dancers. Conclusions: 1. Some actors are dancers. 2. No singer is actor. A. Only (1) conclusion follows B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows
392. Statements: All the harmoniums are instruments. All the instruments are flutes. Conclusions: 1. All the flutes are instruments. 2. All the harmoniums are flutes. A. Only (1) conclusion follows
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B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows
393. Statements: Some mangoes are yellow. Some tixo are mangoes. Conclusions: 1. Some mangoes are green. 2. Tixo is a yellow. A. Only (1) conclusion follows B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows
394. Statements: Some ants are parrots. All the parrots are apples. Conclusions: 1. All the apples are parrots. 2. Some ants are apples. A. Only (1) conclusion follows B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows
395. Statements: Some papers are pens. All the pencils are pens. Conclusions: 1. Some pens are pencils. 2. Some pens are papers.
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A. Only (1) conclusion follows B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows E. Both (1) and (2) follow 396. Statements: All the actors are girls. All the girls are beautiful. Conclusions: 1. All the actors are beautiful. 2. Some girls are actors. A. Only (1) conclusion follows B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows E. Both (1) and (2) follow 397. Statements: All the windows are doors. No door is a wall. Conclusions: 1. Some windows are walls. 2. No wall is a door. A. Only (1) conclusion follows B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows E. Both (1) and (2) follow 398. Statements: All cups are books. All books are shirts. Conclusions: 1. Some cups are not shirts. 2. Some shirts are cups.
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A. Only (1) conclusion follows B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows E. Both (1) and (2) follow 399. Statements: Some cows are crows. Some crows are elephants. Conclusions: 1. Some cows are elephants. 2. All crows are elephants. A. Only (1) conclusion follows B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows E. Both (1) and (2) follow 400. Statements: All the pencils are pens. All the pens are inks. Conclusions: 1. All the pencils are inks. 2. Some inks are pencils. A. Only (1) conclusion follows B. Only (2) conclusion follows C. Either (1) or (2) follows D. Neither (1) nor (2) follows E. Both (1) and (2) follow @ @ @ @ @
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Solutions and Answers 301. Number of boys who passed = (15 + 1 + 28) = 44 Total number of boys in the class = 44 + 6 +5 = 55. Answer: D) 55 302. Clearly, number of boys in the row = ( 6 + 10 + 8) = 24. Answer: C) 24 303. Since Nithya and Suganya exchange places, so Rita’s new position is the same as Monika’s earlier position. This position is 17th from the right and 10th from the left. Therefore Number of girls in the row = (16 + 1 + 9) = 26. Answer: C) 26 304. Since Arun and Suresh interchange places, so Arun’s new position (13th from left) is the same as Suresh’s earlier position (6th from right).So, number of children in the queue = (12 + 1 + 5) = 18.Now. Suresh’s new position is the same as Arun’s earlier position fifth from left.Therefore Suresh’s position from the right = (18 – 4) = 14th. Answer: B) 14th. 305. Number of persons between Arun and Mukesh= 50 – (10 + 25) = 15.Since Maha lies in middle of these 15 persons, so Maha’s position is 8th from Arun i.e. 18th from the front. Answer: B) 18th 306. Clearly, A’s new position is 15th from the left. But this is the same as B’s earlier position which is 9th from the right.In a row of girls, Ramya is fifth from the left and Priya is sixth from the right. When they exchange their positions, then Ramya becomes thirteenth from the left. Answer: B) 23rd 307. Ramya’s new position is 13th from left. But it is the same as Priya’s earlier position which is 6th from the right.Thus, the row consists of ( 12 + 1 + 5 ) = 18 girls.Now, Priya’s new position is Ramya’s earlier position which is 5th from the left.Number of girls to the right of Priya = (18 – 5) = 13.So, Priya’s new position is 14th from the right. Answer: D) 14th
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308. Clearly number of boys in the line = (11 + 1 + 3) = 15. Therefore number of boys to be added = 28 – 15 = 13. Answer: A) 13 309. Number of boys in the row = ( 15 + 4 + 3 ) = 22. C is just left of A. So, C is 14th from the left end. Number of boys to the right end of the row. So, C is 9th from the right end of the row. Answer: B)9th 310. Number of students behind Rajan in rank = ( 49 – 18 ) = 31.So, Rajan is 32nd from the last. Answer: D) 32nd 311. 16 + 7 = 24 Answer: C) 24 312. Number of boys in the row = number of boys uptil P + number of boys between P and Q + number of boys including Q and those behind Q = 14 + 4 + 7 = 25. Answer: D) 25 313. Number of students between Kamal and Sunil = 35 – ( 7 + 9) = 19. Clearly, there are 9 students between Kamal and Manoj, as well as Manoj and Sunil. So Kamal is 10th from Manoj. Answer: C) 10th 314. Number of persons between Viji and Jack = 48 – (14 + 17) = 17. Now, Mary lies in middle of these 17 persons i.e., at the eighth position. So, number of persons between Viji and Mary = 8. Answer: D) 8 315. Meena’s new position is Reena’s earlier position which is 6th from the left. Answer: B) 6th 316. Sakthi’s new position is 15th from the right as well as the left end of the row. Therefore number of students in the queue = ( 14 + 1 + 14 ) = 29. Answer: D) 29 317. Clearly, number of students in the class = (15 + 1 + 48) = 64. Answer: B) 64
150 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar Employability Skills Unit – IV
318. Clearly, number of students in the class = ( 8 + 1 + 37 ) = 46. Answer: B) 46 319. Answer: C) 46 320. Pallavi is 21st from right and Reena is 10th to the left of Pallavi. So, Reena is 31st from right. Malini is 4th to the right of Reena. So, Malini is 27th from the right. Also, Malini is 17th from the left. Therefore number of girls in the row = ( 26 + 1 + 16 ) = 43. Answer: C) 43 321. Answer: B) 7.20 a.m 322. Answer: D) None of these 323. Answer: B) 8.05 hrs 324. Answer: A) 7.05 a.m. 325. Answer: D) None of these 326. Answer: C) Wednesday 327. Answer: B) 12 noon -- 2.00 P.M. 328. Answer: C) 6 p.m. 329. Answer: A) None 330. Answer: D) Four 331. Answer: D) Both Monday and Thursday We prepare a table as under :
Mon Tue Wed Thu Fri Sat Sun
9 a.m. to 10 R R R a.m.
10 a.m. to 12 N, N, R R N N noon R
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12 noon to 2 K, K, N K N p.m. N N
2 p.m. to 4 K, K K R R p.m. R
Clearly, all the three brothers are not available at the same time on any day of the week.
332. Answer: B) 21st May 333. Answer: D) Data inadequate 334. Answer: C) Wednesday 335. Answer: D) Tuesday 336. Answer: C) Wednesday 337. Answer: B) 24.12.91 338. Answer: A) Two 339. Answer: C) 5 340. Answer: B) Wednesday Number test
341. Answer: B) 4 342. Answer: B) Two 343. Answer: A) 2 344. Answer: C) Three 345. Answer: C) 2 346. Answer: B) 4 347. Answer: D) Three 348. Answer: C) Four 349. Answer: A) 2 350. Answer: A) One
152 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar Employability Skills Unit – IV
351. Answer: D) Three 352. Answer: B) Two 353. Answer: A) One 354. Answer: B) Four 355. Answer: B) 1 356. Answer: B) 1 357. Answer: D) 27 358. Answer: B) 13 359. Answer: C) 7 360. Answer: A) 1 Alphabet Test 361. Answer: C) War 362. Answer: A) Science 363. Answer: D) Integument 364. Answer: C) Narrate 365. Answer: D) Diastole 366. Answer: D) 2, 3, 1, 5, 4 367. Answer: C) 3 368. Answer: Option D - Three 369. Answer: Option E - More than three 370. Answer: Option D - More than three 371. Answer: Option C - Two 372. Answer: Option C - Two 373. Answer: Option B. L 374. Answer: Option C. U 375. Answer: Option B – N 376. Answer: Option C – N
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377. Answer: Option B - B, N 378. Answer: Option D – M 379. Answer: Option D – P 380. Answer: Option D – YLF 381. Answer: Option D Explanation: Bus and Train are different from each other but some travelers travel by bus and some travel by train. 382. Answer: Option B Explanation: Bonus and Dividend are different from each other. But both these are parts of profit. 383. Answer: Option A Explanation: All mothers are women and some mothers and some women may be engineers. 384. Answer: Option D Explanation: Product and Machinery are different from each other but both are found in Factory. 385. Answer: Option B Explanation: All the three are different professions. 386. Answer: Option C Explanation: Hospital consists of nurse and patient but nurse and patient are of two different nature. 387. Answer: Option B Explanation: Mercury and Zinc both are different from one another but belong to metal.
154 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar Employability Skills Unit – IV
388. Answer: Option A Explanation: A teacher may or may not be a writer and musician. Similarly a musician may or may not be a teacher and writer and so a writer may or may not be a teacher and musician. 389. Answer: Option D Explanation:
390. Answer: Option A Explanation:
391. Answer: Option A Explanation:
392. Answer: 393. Answer: Option D Explanation:
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394. Answer: Option B Explanation:
395. Answer: Option D Explanation:
396. Answer: Option E Explanation:
397. Answer: Option B Explanation:
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398. Answer: Option B Explanation:
399. Answer: Option D Explanation:
400. Answer: Option D Explanation:
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Unit - V GENERAL KNOWLEDGE
Abbreviations & Acronyms
Famous Personalities
Important Days
(National & International)
Capital Cities and Currencies
Authors and Inventors
Employability Skills Unit – V
UNIT – V GENERAL KNOWLEDGE Abbreviations & Acronyms 401. What does the abbreviation AIDS stand for? i) Albumin Inadequacy Disease Syndrome ii) Anti-Immunity Disease Syndrome iii) Acquired Immune Deficiency Syndrome iv) Acidity Imbalance Disease Syndrome 402. What does AIMA mean? i) All India Management Association ii) Asian Internal Maintenance Act iii) American Incidental Medical Assistance iv) All India Medical Association 403. What is the full form of ASLV? i) Asian Satellite Launching Vehicle Vigilance ii) American Service of Labour iii) Atlantic Satellite Launching Voyage iv) Augmented Satellite Launch Vehicle 404. What is the full form of BHEL? i) Bharat Heavy Electronics Limited ii) Bharat Heavy Electricals Limited iii) British Hardware Engineering Limited iv) Bihar Heavy Electronics Limited 405. What is the expansion of CBI? i) Central Board of Investigation ii) Criminal Board of Investigation iii) Central Bureau of Investigation iv) Central Bureau of Intelligence 406. What does the abbreviation CSIR stand for? i) Council of Scientific and Industrial Research ii) Central Scholarship for Industrial Research iii) Current Study of Industrial Regulations iv) Council for Selection of Institutional Researchers 407. What is DNA? i) Diabolic Nitric Acid iii) Detoxified Nitric Acid ii) Deoxyribo Nucleic iv) Diabetic Nucleic Acid Acid
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408. What is ECG’s full form? i) Electro Cardio Graph iii) Electro Cardiogram ii) Electronic Cardio iv) Energy Cardio Graph Gram 409. What does FIFA stand for? i) Federation of International Farmers Association ii) Federation of International Football Association iii) Federation of Indian Fishermen Association iv) Financial Investment and Foreign Accounts 410. Write the full form of HUDCO. i) Housing and Urban Development Corporation ii) Housing and Urban Development Company iii) Hindustan Urban Development Corporation iv) Home for Under Developed Countries 411. What is the expansion of the term ICMR? i) International Council for Modern Research ii) International Centre for Malaria Research iii) Indian Council of Medical Research iv) Indian Centre for Military Rehabilitation 412. What is the full form of IMF? i) Indian Manufacturer’s Federation ii) International Monetary Fund iii) International Muslim Federation iv) Indian Management Fund 413. What does the abbreviation ISI mean? i) Indian Space Institute ii) International Security Institute iii) Institute for Social Improvement iv) Indian Standard Institution 414. What is the full form of ISRO? i) International Standard Research Organisation ii) Indian Space Research Organisation iii) Indian Science and Research Organisation iv) Industrial Security and Relief Office 415. Write the expansion of ISBN. i) Indian Standard Bureau of Newspapers ii) Indian Security and Border Networks iii) Indian Standard Book Number iv) International Standard Book Number
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416. What is the expansion of LASER? i) Light Amplification by Stimulated Emission of Radiation ii) Light Aggravated by Simultaneous Emission of Rays iii) Light Analysis and Spark Expansion Rays iv) Low Angled Signal Electronic Rays 417. What do you mean by the term LPG? i) Low Pressure Gas iii) Limited Petroleum Gas ii) Liquefied Petroleum iv) Lithium Preservation Gas Gas 418. What is the expansion of NASA? i) Non Alignment States Association ii) National Agriculture and Science Administration iii) National Anti-Corruption and Security Act iv) National Aeronautics and Space Administration 419. Write the full form of SAIL. i) South African Industries Limited ii) Steel Authority of India Limited iii) South Asian Industrial League iv) Society for All Industrial Labourers 420. What is the expansion of WHO? i) World Hypnotists Organisation ii) World Hygiene Organisation iii) World Health Organisation iv) Welfare Home for Orthopaedics Famous Personalities 421. Who is known as the ‘Father of Indian Missile Technology’? i) Aryabhatta iii) Dr.Mayilsamy ii) Dr.Abdul Kalam Annadurai iv) Dr.Radhakrishnan 422. Which Marxist Revolutionay is known as the ‘Father of Russia’? i) Mikhail Gorbachev iii) Lenin ii) Vladimir Pudin iv) Leo Tolstoy 423. Who is the founder of Bhoodan Movement? i) Rajagopalachari iii) Gandhiji ii) Gopalakrishna iv) Vinoba Bhave Gokhale
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424. Who was the founder of Nazism? i) Bismarck iii) Hermann Goering ii) Adolf Hitler iv) Franz Stang 425. Who is the father of Modern Economics? i) Karl Marx iii) Benjamin Graham ii) Adam Smith iv) Milton Friedman 426. Who founded Scout Movement? i) Robert Baden Powel iii) Ernest Thompson Seton ii) Frederick Russell iv) William Alexander Burnham Smith 427. Who is called ‘the Father of White Revolution in India’? i) Deepa Narayan iii) H.M.Dalaya ii) Lal Bahadur Sastri iv) Dr. Varghese Kurian 428. Who founded the Kalakshetra of Adayar in Tamilnadu? i) Rukmani Devi iii) Padma Subramaniam Arundale iv) Balasaraswathi ii) M.S.Subbulakshmi 429. Who founded the International Red Cross Society? i) Gustave Moynier iii) Louis Appia ii) Henry Dunant iv) Theodore Maunoir 430. Who is considered the founder of psycho analysis? i) Alfred Adler iii) Carl Gustav Jung ii) Sigmund Freud iv) Jacques Lacan 431. Who is considered the father of cybernetics? i) Jay Forrester iii) Norbert Wiener ii) Andre Marie Ampere iv) Gordon Pask 432. Who was the founder of the Indian National Congress? i) Subash Chandra iii) Subramania Bharathiar Bose iv) A.O.Hume ii) Mahatma Gandhi 433. Who declared that his ultimate aim was to wipe ‘every tear from every eye’? i) Rajendra Prasad iii) Jawaharlal Nehru ii) Sardar Patel iv) Mahatma Gandhi 434. Who among the following is a social activist campaigning against child labour? i) Baba Amte iii) Mira Nair ii) Shabana Azmi iv) Swami Agnivesh
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435. Who is the father of Geometry? i) Aristotle iii) Pythagoras ii) Euclid iv) Kepler 436. Who was known as ‘Iron Man of India’? i) Govind Ballabh Pant iii) Subash Chandra Bose ii) Jawaharlal Nehru iv) Sardar Patel 437. The Indian to beat the computers in mathematical wizardry is i) Ramanujam iii) Raja Ramanna ii) Rina Panigrahi iv) Sakunthala Devi 438. Professor Amarty a Sen is famous in which of the fields? i) Bio-chemistry iii) Economics ii) Electronics iv) Geology 439. The name of Pierre Cardin is associated with which of the following fields? i) Painting iii) Pop Music ii) Films iv) Fashion Designing 440. Name the Chinese Buddhist pilgrim who visited India during the reign of King Harsha? i) Taizong iii) Wu Cheng ii) Huen Tsang iv) Fahian Important Days (National) 441. National Youth Day is celebrated on i) January 12 iii) December 5 ii) February 14 iv) March 8 442. When is Flag Day celebrated? i) April 14 iii) September 15 ii) November 15 iv) December 7 443. Farmers Day falls on i) October 18 iii) February 24 ii) December 23 iv) May 5 444. Tourism Day is celebrated on i) January 25 iii) June 25 ii) March 25 iv) July 15 445. National Vaccination Day is observed on i) August 21 iii) March 16 ii) November 15 iv) October 4 446. When do we observe National Science Day? i) February 8 iii) February 24 ii) February 13 iv) February 28
162 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – V
447. Martyr’s Day is observed on i) January 30 iii) May 20 ii) April 1 iv) December 1 448. National Postal Day is celebrated on i) October 14 iii) October 10 ii) August 12 iv) August 8 449. When is Kargil Victory Day celebrated in India every year? i) March 4 iii) May 7 ii) April 19 iv) July 26 450. Minorities Rights Day is observed on i) June 30 iii) December 18 ii) July 15 iv) October 17 Important Days (International) 451. World Laughter Day falls on i) July 12 iii) January 10 ii) November 2 iv) March 7 452. World Leprosy Eradication Day is observed on i) January 30 iii) March 30 ii) February 28 iv) April 30 453. International Women’s Day is celebrated on i) March 8 iii) March 17 ii) March 11 iv) April 3 454. On which date World Consumer Rights Day is observed? i) May 21 iii) August 14 ii) March 15 iv) September 10 455. World Forestry Day is celebrated on i) February 11 iii) March 21 ii) April 17 iv) January 12 456. World Day for Water is observed on i) March 22 iii) August 15 ii) December 4 iv) May 1 457. When is Anti-tobacco Day observed? i) May 5 iii) May 27 ii) May 21 iv) May 31 458. When is World Population Day observed? i) July 9 iii) July 11 ii) July 10 iv) July 12
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459. Which of the following is observed as World Ozone Day? i) April 11 iii) September 16 ii) May 11 iv) November 16 460. ______is observed as Human Rights Day. i) October 30 iii) May 12 ii) December 10 iv) March 22 Capital Cities and Currencies 461. Of which country is Beirut capital? i) Palestine iii) Lebanon ii) Cyprus iv) Syria 462. Which is the capital of Bhutan? i) Thimphu iii) Daga ii) Jakar iv) Paro 463. Which was the capital of the Chola Dynasty? i) Madurai iii) Mamallapuram ii) Thanjavur iv) Kaveripoompattinam 464. Which is the capital of Afghanistan? i) Kandahar iii) Kunduz ii) Kabul iv) Jalalabad 465. Of which country is Nairobi capital? i) Uganda iii) Burundi ii) Tanzania iv) Kenya 466. Which is the capital of Canada? i) Victoria iii) Ottawa ii) Edmonton iv) Winnipeg 467. Which South East Asian capital city is known as the ‘Pearl of the Orient’? i) Hong Kong iii) Singapore ii) Banghok iv) Kualalumpur 468. What was the capital of England before London? i) Lancashire iii) Winchester ii) Kent iv) Gloucester 469. Tokyo is the capital of which country? i) Taiwan iii) Thailand ii) Japan iv) South Korea 470. Which is the capital of Czech Republic? i) Auckland iii) Prague ii) The Hague iv) San Jose
164 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar. Employability Skills Unit – V
471. What is China’s currency? i) Escudos iii) Yen ii) Yuan iv) Dollar 472. What is the currency of Bangladesh? i) Kyat iii) Taka ii) Peso iv) Rand 473. What is the currency of France? i) Dong iii) Pound ii) Euro iv) Dinar 474. Which country’s currency is called Naira? i) Chile iii) Nigeria ii) Venezuela iv) Spain 475. Which country shares its name with its currency? i) Poland iii) Jordan ii) Norway iv) Zaire 476. What is the currency of North Korea and South Korea? i) Won iii) Baht ii) Rupee iv) Kroner 477. ‘Lek’ is the name of the currency of an European country. Which is that country? i) Italy iii) Albania ii) Spain iv) Finland 478. What is the currency of Indonesia? i) Rupiah iii) Lira ii) Escudos iv) Guilder 479. Which is the currency of Saudi Arabia? i) Peseta iii) Riyal ii) Dinar iv) Mark 480. What is the currency of Srilanka? i) Dollar iii) Ringgit ii) Shilling iv) Rupee Authors and Inventors 481. Who wrote The Nation’s Voice? i) C.Rajagopalachari iii) Jawaharlal Nehru ii) Mahatma Gandhi iv) Jeyaprakash Narayan 482. Who is the author of Alice in Wonderland? i) Lewis Carrol iii) R.L.Stevenson ii) J.K.Rowling iv) Mark Twain
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483. Das Capital is one of the great works in world literature. Who is the author? i) Vladimir Lenin iii) Karl Marx ii) Leo Tolstoy iv) Joseph Stalin 484. For which book of poems was Rabindranath Tagore awarded the Nobel Prize? i) The Aeolian Harp iii) The Magic Lute ii) Gitanjali iv) Kavithanjali 485. Aundhati Roy won Booker Prize in 1997. For which work she won it? i) Aymanam iii) The Banyan Tree ii) The God of Small iv) We are One Things 486. Mahatma Gandhi wrote an autobiography noted for its honesty and lack of evasion. What is its title? i) Discovery of India iii) My Story ii) Our Civilization iv) My Experiments with Truth 487. Name the author of Anna Karenina. i) Charles Dickens iii) Karl Marx ii) Leo Tolstoy iv) W.B.Yeats 488. Who compiled the first dictionary in English? i) Ben Jonson iii) Dr.Samuel Johnson ii) John Milton iv) John Lyle 489. One of the greatest Tamil epics is Silappathikaram. Who wrote it? i) Kambar iii) Ilango Adigal ii) Seethalai Sathanar iv) Saint Vyasa 490. Sunny Days is a well-known autobiography of a world famous cricket player. Who is he? i) Kapil Dev iii) Sachin Tendulkar ii) Vivian Richard iv) Sunil Gavaskar 491. A submarine plays an important role in the modern naval warfare. Who invented it? i) Cornelis Drebbel iii) Karl benz ii) Robert W. Bunsen iv) Henry Greathead 492. Name the scientist who invented the electric battery. i) Albert Blake Dick iii) Etienne Lenoir ii) Michael Faraday iv) Alexandro Volta
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493. Who invented the radio? i) Thonmas Alva Edison iii) Emile Berliner ii) Marconi iv) Rudolf Diesel 494. Who is the inventor of bicycle? i) Lee de Forest iii) Hercules ii) Siemens iv) Kirkpatrick Macmillan 495. Name the American who invented fountain pen. i) Lewis Edson iii) John Fitch Watermann iv) Hudson Maxim ii) Blaise Pascal 496. Who built the first telephone that transmitted electrically the human voice? i) Anaximander iii) Robsert Liston ii) Alexander Graham iv) Thomas Newcomen Bell 497. Who invented safety pins? i) John Boyd Dunlop iii) Eugen Steinach ii) Walter Hunt iv) Aldous Huxley 498. Who is the inventor of Stethoscope? i) Elisha Thomson iii) Rene Laennec ii) James Watt iv) Braille 499. Name the surgeon who did the first human heart transplantation successfully. i) Christian Neethling iii) Edward Butler Barnard iv) Richard Hoe ii) Zenobe Gramme 500. Who discovered the wonder drug pencillin? i) George Stevenson iii) Alexander Fleming ii) Benjamin Franklin iv) Thomas Savery
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Answers
401. iii 426. i 451. iii 476. i 402. i 427. iv 452. i 477. iii 403. iv 428. i 453. i 478. i 404. ii 429. ii 454. ii 479. iii 405. iii 430. ii 455. iii 480. iv 406. i 431. iii 456. i 481. i 407. ii 432. iv 457. iv 482. i 408. iii 433. iii 458. iii 483. iii 409. ii 434. i 459. iv 484. ii 410. i 435. ii 460. ii 485. ii 411. iii 436. iv 461. iii 486. iv 412. ii 437. iv 462. i 487. ii 413. iv 438. iii 463. ii 488. iii 414. ii 439. iv 464. ii 489. iii 415. iv 440. ii 465. iv 490. iv 416. i 441. i 466. iii 491. i 417. ii 442. iv 467. iii 492. iv 418. iv 443. ii 468. iii 493. ii 419. ii 444. i 469. ii 494. iv 420. iii 445. iii 470. iii 495. i 421. ii 446. iv 471. ii 496. ii 422. iii 447. i 472. iii 497. ii 423. iv 448. iii 473. ii 498. iii 424. ii 449. iv 474. iii 499. i 425. ii 450. iii 475. iv 500 iii
@ @ @ @ @
168 V.H.N.Senthikumara Nadar College (Autonomous), Virudhunagar.