How to Introduce the Magnetic Dipole Moment
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The Magnetic Moment of a Bar Magnet and the Horizontal Component of the Earth’S Magnetic Field
260 16-1 EXPERIMENT 16 THE MAGNETIC MOMENT OF A BAR MAGNET AND THE HORIZONTAL COMPONENT OF THE EARTH’S MAGNETIC FIELD I. THEORY The purpose of this experiment is to measure the magnetic moment μ of a bar magnet and the horizontal component BE of the earth's magnetic field. Since there are two unknown quantities, μ and BE, we need two independent equations containing the two unknowns. We will carry out two separate procedures: The first procedure will yield the ratio of the two unknowns; the second will yield the product. We will then solve the two equations simultaneously. The pole strength of a bar magnet may be determined by measuring the force F exerted on one pole of the magnet by an external magnetic field B0. The pole strength is then defined by p = F/B0 Note the similarity between this equation and q = F/E for electric charges. In Experiment 3 we learned that the magnitude of the magnetic field, B, due to a single magnetic pole varies as the inverse square of the distance from the pole. k′ p B = r 2 in which k' is defined to be 10-7 N/A2. Consider a bar magnet with poles a distance 2x apart. Consider also a point P, located a distance r from the center of the magnet, along a straight line which passes from the center of the magnet through the North pole. Assume that r is much larger than x. The resultant magnetic field Bm at P due to the magnet is the vector sum of a field BN directed away from the North pole, and a field BS directed toward the South pole. -
Neutron Electric Dipole Moment from Beyond the Standard Model on the Lattice
Introduction Quark EDM Dirac Equation Operator Mixing Lattice Results Conclusions Neutron Electric Dipole Moment from Beyond the Standard Model on the lattice Tanmoy Bhattacharya Los Alamos National Laboratory 2019 Lattice Workshop for US-Japan Intensity Frontier Incubation Mar 27, 2019 Tanmoy Bhattacharya nEDM from BSM on the lattice Introduction Standard Model CP Violation Quark EDM Experimental situation Dirac Equation Effective Field Theory Operator Mixing BSM Operators Lattice Results Impact on BSM physics Conclusions Form Factors Introduction Standard Model CP Violation Two sources of CP violation in the Standard Model. Complex phase in CKM quark mixing matrix. Too small to explain baryon asymmetry Gives a tiny (∼ 10−32 e-cm) contribution to nEDM CP-violating mass term and effective ΘGG˜ interaction related to QCD instantons Effects suppressed at high energies −10 nEDM limits constrain Θ . 10 Contributions from beyond the standard model Needed to explain baryogenesis May have large contribution to EDM Tanmoy Bhattacharya nEDM from BSM on the lattice Introduction Standard Model CP Violation Quark EDM Experimental situation Dirac Equation Effective Field Theory Operator Mixing BSM Operators Lattice Results Impact on BSM physics Conclusions Form Factors Introduction 4 Experimental situation 44 Experimental landscape ExperimentalExperimental landscape landscape nEDM upper limits (90% C.L.) 4 nEDMnEDM upper upper limits limits (90% (90% C.L.) C.L.) 10−19 19 19 Beam System Current SM 1010− −20 −20−20 BeamBraggBeam scattering SystemSystem -
Section 14: Dielectric Properties of Insulators
Physics 927 E.Y.Tsymbal Section 14: Dielectric properties of insulators The central quantity in the physics of dielectrics is the polarization of the material P. The polarization P is defined as the dipole moment p per unit volume. The dipole moment of a system of charges is given by = p qiri (1) i where ri is the position vector of charge qi. The value of the sum is independent of the choice of the origin of system, provided that the system in neutral. The simplest case of an electric dipole is a system consisting of a positive and negative charge, so that the dipole moment is equal to qa, where a is a vector connecting the two charges (from negative to positive). The electric field produces by the dipole moment at distances much larger than a is given by (in CGS units) 3(p⋅r)r − r 2p E(r) = (2) r5 According to electrostatics the electric field E is related to a scalar potential as follows E = −∇ϕ , (3) which gives the potential p ⋅r ϕ(r) = (4) r3 When solving electrostatics problem in many cases it is more convenient to work with the potential rather than the field. A dielectric acquires a polarization due to an applied electric field. This polarization is the consequence of redistribution of charges inside the dielectric. From the macroscopic point of view the dielectric can be considered as a material with no net charges in the interior of the material and induced negative and positive charges on the left and right surfaces of the dielectric. -
Gauss' Theorem (See History for Rea- Son)
Gauss’ Law Contents 1 Gauss’s law 1 1.1 Qualitative description ......................................... 1 1.2 Equation involving E field ....................................... 1 1.2.1 Integral form ......................................... 1 1.2.2 Differential form ....................................... 2 1.2.3 Equivalence of integral and differential forms ........................ 2 1.3 Equation involving D field ....................................... 2 1.3.1 Free, bound, and total charge ................................. 2 1.3.2 Integral form ......................................... 2 1.3.3 Differential form ....................................... 2 1.4 Equivalence of total and free charge statements ............................ 2 1.5 Equation for linear materials ...................................... 2 1.6 Relation to Coulomb’s law ....................................... 3 1.6.1 Deriving Gauss’s law from Coulomb’s law .......................... 3 1.6.2 Deriving Coulomb’s law from Gauss’s law .......................... 3 1.7 See also ................................................ 3 1.8 Notes ................................................. 3 1.9 References ............................................... 3 1.10 External links ............................................. 3 2 Electric flux 4 2.1 See also ................................................ 4 2.2 References ............................................... 4 2.3 External links ............................................. 4 3 Ampère’s circuital law 5 3.1 Ampère’s original -
Temporal Analysis of Radiating Current Densities
Temporal analysis of radiating current densities Wei Guoa aP. O. Box 470011, Charlotte, North Carolina 28247, USA ARTICLE HISTORY Compiled August 10, 2021 ABSTRACT From electromagnetic wave equations, it is first found that, mathematically, any current density that emits an electromagnetic wave into the far-field region has to be differentiable in time infinitely, and that while the odd-order time derivatives of the current density are built in the emitted electric field, the even-order deriva- tives are built in the emitted magnetic field. With the help of Faraday’s law and Amp`ere’s law, light propagation is then explained as a process involving alternate creation of electric and magnetic fields. From this explanation, the preceding math- ematical result is demonstrated to be physically sound. It is also explained why the conventional retarded solutions to the wave equations fail to describe the emitted fields. KEYWORDS Light emission; electromagnetic wave equations; current density In electrodynamics [1–3], a time-dependent current density ~j(~r, t) and a time- dependent charge density ρ(~r, t), all evaluated at position ~r and time t, are known to be the sources of an emitted electric field E~ and an emitted magnetic field B~ : 1 ∂2 4π ∂ ∇2E~ − E~ = ~j + 4π∇ρ, (1) c2 ∂t2 c2 ∂t and 1 ∂2 4π ∇2B~ − B~ = − ∇× ~j, (2) c2 ∂t2 c2 where c is the speed of these emitted fields in vacuum. See Refs. [3,4] for derivation of these equations. (In some theories [5], on the other hand, ρ and ~j are argued to arXiv:2108.04069v1 [physics.class-ph] 6 Aug 2021 be responsible for instantaneous action-at-a-distance fields, not for fields propagating with speed c.) Note that when the fields are observed in the far-field region, the contribution to E~ from ρ can be practically ignored [6], meaning that, in that region, Eq. -
Electric Current and Power
Chapter 10: Electric Current and Power Chapter Learning Objectives: After completing this chapter the student will be able to: Calculate a line integral Calculate the total current flowing through a surface given the current density. Calculate the resistance, current, electric field, and current density in a material knowing the material composition, geometry, and applied voltage. Calculate the power density and total power when given the current density and electric field. You can watch the video associated with this chapter at the following link: Historical Perspective: André-Marie Ampère (1775-1836) was a French physicist and mathematician who did ground-breaking work in electromagnetism. He was equally skilled as an experimentalist and as a theorist. He invented both the solenoid and the telegraph. The SI unit for current, the Ampere (or Amp) is named after him, as well as Ampere’s Law, which is one of the four equations that form the foundation of electromagnetic field theory. Photo credit: https://commons.wikimedia.org/wiki/File:Ampere_Andre_1825.jpg, [Public domain], via Wikimedia Commons. 1 10.1 Mathematical Prelude: Line Integrals As we saw in section 5.1, a surface integral requires that we take the dot product of a vector field with a vector that is perpendicular to a specified surface at every point along the surface, and then to integrate the resulting dot product over the surface. Surface integrals must always be a double integral, since they must involve an integral over a two-dimensional surface. We also have a special symbol for a surface integral over a closed surface, such as a sphere or a cube: (Copies of Equations 5.1 and 5.2) While a surface integral requires a double integral to be taken of a dot product over a surface, a line integral requires a single integral to be taken of a dot product over a linear path. -
PHYS 352 Electromagnetic Waves
Part 1: Fundamentals These are notes for the first part of PHYS 352 Electromagnetic Waves. This course follows on from PHYS 350. At the end of that course, you will have seen the full set of Maxwell's equations, which in vacuum are ρ @B~ r~ · E~ = r~ × E~ = − 0 @t @E~ r~ · B~ = 0 r~ × B~ = µ J~ + µ (1.1) 0 0 0 @t with @ρ r~ · J~ = − : (1.2) @t In this course, we will investigate the implications and applications of these results. We will cover • electromagnetic waves • energy and momentum of electromagnetic fields • electromagnetism and relativity • electromagnetic waves in materials and plasmas • waveguides and transmission lines • electromagnetic radiation from accelerated charges • numerical methods for solving problems in electromagnetism By the end of the course, you will be able to calculate the properties of electromagnetic waves in a range of materials, calculate the radiation from arrangements of accelerating charges, and have a greater appreciation of the theory of electromagnetism and its relation to special relativity. The spirit of the course is well-summed up by the \intermission" in Griffith’s book. After working from statics to dynamics in the first seven chapters of the book, developing the full set of Maxwell's equations, Griffiths comments (I paraphrase) that the full power of electromagnetism now lies at your fingertips, and the fun is only just beginning. It is a disappointing ending to PHYS 350, but an exciting place to start PHYS 352! { 2 { Why study electromagnetism? One reason is that it is a fundamental part of physics (one of the four forces), but it is also ubiquitous in everyday life, technology, and in natural phenomena in geophysics, astrophysics or biophysics. -
Magnetic and Electric Dipole Moments of the H 3 1 State In
PHYSICAL REVIEW A 84, 034502 (2011) 3 Magnetic and electric dipole moments of the H 1 state in ThO A. C. Vutha,1,* B. Spaun,2 Y. V. Gurevich,2 N. R. Hutzler,2 E. Kirilov,1 J. M. Doyle,2 G. Gabrielse,2 and D. DeMille1 1Department of Physics, Yale University, New Haven, Connecticut 06520, USA 2Department of Physics, Harvard University, Cambridge, Massachusetts 02138, USA (Received 13 July 2011; published 29 September 2011) 3 The metastable H 1 state in the thorium monoxide (ThO) molecule is highly sensitive to the presence of a CP-violating permanent electric dipole moment of the electron (eEDM) [E. R. Meyer and J. L. Bohn, Phys. Rev. A 78, 010502 (2008)]. The magnetic dipole moment μH and the molecule-fixed electric dipole moment DH of this −3 state are measured in preparation for a search for the eEDM. The small magnetic moment μH = 8.5(5) × 10 μB 3 displays the predicted cancellation of spin and orbital contributions in a 1 paramagnetic molecular state, providing a significant advantage for the suppression of magnetic field noise and related systematic effects in the eEDM search. In addition, the induced electric dipole moment is shown to be fully saturated in very modest electric fields (<10 V/cm). This feature is favorable for the suppression of many other potential systematic errors in the ThO eEDM search experiment. DOI: 10.1103/PhysRevA.84.034502 PACS number(s): 31.30.jp, 11.30.Er, 33.15.Kr Measurable CP violation is predicted in many proposed was subsequently probed a few millimeters downstream by extensions to the standard model, and could provide a clue exciting laser-induced fluorescence (LIF). -
Ee334lect37summaryelectroma
EE334 Electromagnetic Theory I Todd Kaiser Maxwell’s Equations: Maxwell’s equations were developed on experimental evidence and have been found to govern all classical electromagnetic phenomena. They can be written in differential or integral form. r r r Gauss'sLaw ∇ ⋅ D = ρ D ⋅ dS = ρ dv = Q ∫∫ enclosed SV r r r Nomagneticmonopoles ∇ ⋅ B = 0 ∫ B ⋅ dS = 0 S r r ∂B r r ∂ r r Faraday'sLaw ∇× E = − E ⋅ dl = − B ⋅ dS ∫∫S ∂t C ∂t r r r ∂D r r r r ∂ r r Modified Ampere'sLaw ∇× H = J + H ⋅ dl = J ⋅ dS + D ⋅ dS ∫ ∫∫SS ∂t C ∂t where: E = Electric Field Intensity (V/m) D = Electric Flux Density (C/m2) H = Magnetic Field Intensity (A/m) B = Magnetic Flux Density (T) J = Electric Current Density (A/m2) ρ = Electric Charge Density (C/m3) The Continuity Equation for current is consistent with Maxwell’s Equations and the conservation of charge. It can be used to derive Kirchhoff’s Current Law: r ∂ρ ∂ρ r ∇ ⋅ J + = 0 if = 0 ∇ ⋅ J = 0 implies KCL ∂t ∂t Constitutive Relationships: The field intensities and flux densities are related by using the constitutive equations. In general, the permittivity (ε) and the permeability (µ) are tensors (different values in different directions) and are functions of the material. In simple materials they are scalars. r r r r D = ε E ⇒ D = ε rε 0 E r r r r B = µ H ⇒ B = µ r µ0 H where: εr = Relative permittivity ε0 = Vacuum permittivity µr = Relative permeability µ0 = Vacuum permeability Boundary Conditions: At abrupt interfaces between different materials the following conditions hold: r r r r nˆ × (E1 − E2 )= 0 nˆ ⋅(D1 − D2 )= ρ S r r r r r nˆ × ()H1 − H 2 = J S nˆ ⋅ ()B1 − B2 = 0 where: n is the normal vector from region-2 to region-1 Js is the surface current density (A/m) 2 ρs is the surface charge density (C/m ) 1 Electrostatic Fields: When there are no time dependent fields, electric and magnetic fields can exist as independent fields. -
Phys102 Lecture 3 - 1 Phys102 Lecture 3 Electric Dipoles
Phys102 Lecture 3 - 1 Phys102 Lecture 3 Electric Dipoles Key Points • Electric dipole • Applications in life sciences References SFU Ed: 21-5,6,7,8,9,10,11,12,+. 6th Ed: 16-5,6,7,8,9,11,+. 21-11 Electric Dipoles An electric dipole consists of two charges Q, equal in magnitude and opposite in sign, separated by a distance . The dipole moment, p = Q , points from the negative to the positive charge. An electric dipole in a uniform electric field will experience no net force, but it will, in general, experience a torque: The electric field created by a dipole is the sum of the fields created by the two charges; far from the dipole, the field shows a 1/r3 dependence: Phys101 Lecture 3 - 5 Electric dipole moment of a CO molecule In a carbon monoxide molecule, the electron density near the carbon atom is greater than that near the oxygen, which result in a dipole moment. p Phys101 Lecture 3 - 6 i-clicker question 3-1 Does a carbon dioxide molecule carry an electric dipole moment? A) No, because the molecule is electrically neutral. B) Yes, because of the uneven distribution of electron density. C) No, because the molecule is symmetrical and the net dipole moment is zero. D) Can’t tell from the structure of the molecule. Phys101 Lecture 3 - 7 i-clicker question 3-2 Does a water molecule carry an electric dipole moment? A) No, because the molecule is electrically neutral. B) No, because the molecule is symmetrical and the net dipole moment is zero. -
Lab 6: the Earth's Magnetic Field
Lab 6: The Earth's Magnetic Field N Direction of the 1 Introduction S magnetic dipole moment m The earth just like other planetary bodies has a mag- netic ¯eld. The purpose of this experiment is to mea- Figure 1: Magnetic ¯eld lines of a bar magnet sure the horizontal component of the earth's magnetic Magnetic Axis ¯eld BH using a very simple apparatus. The measure- ment involves combining the results of two separate o Axis of Rotation 23.5 experiments to obtain BH . The ¯rst experiment will o involve studies of how a freely suspended bar magnet 11.5 interacts with the earth's magnetic ¯eld. The second experiment will involve an investigation of the com- bined e®ect of the magnetic ¯eld of a bar magnet and Plane of the S the earth's magnetic ¯eld on a compass needle. Earths orbit A magnetic dipole is the fundamental entity in mag- netostatics just like a point charge is the simplest con- N ¯guration in electrostatics. A bar magnet is an exam- ple of a magnetic dipole. The magnetic ¯eld lines of the magnet are closed loops that are directed from Geographic south north to south outside the magnet, and from south pole to north inside the magnet, as illustrated in ¯gure 1. The magnetic dipole moment (by convention) is a vector drawn pointing from the south pole toward Figure 2: Earth's magnetic ¯eld the north pole. At any point in space, the direction of the magnetic ¯eld is along the tangent to the ¯eld THE BACKGROUND CONCEPTS AND EX- line at that point. -
Quantum Mechanics Electric Dipole Moment
Quantum Mechanics_electric dipole moment In physics, the electric dipole moment is a measure of the separation of positive and negative electrical charges in a system of electric charges, that is, a measure of the charge system's overall polarity. The SI units are Coulomb-meter (C m). This article is limited to static phenomena, and does not describe time-dependent or dynamic polarization. Elementary definition Animation showing the Electric field of an electric dipole. The dipole consists of two point electric charges of opposite polarity located close together. A transformation from a point-shaped dipole to a finite-size electric dipole is shown. A molecule of water is polar because of the unequal sharing of its electrons in a "bent" structure. A separation of charge is present with negative charge in the middle (red shade), and positive charge at the ends (blue shade). In the simple case of two point charges, one with charge +q and the other one with charge −q, the electric dipole moment p is: where d is the displacement vector pointing from the negative charge to the positive charge. Thus, the electric dipole moment vector p points from the negative charge to the positive charge. An idealization of this two-charge system is the electrical point dipole consisting of two (infinite) charges only infinitesimally separated, but with a finite p. Torque Electric dipole p and its torque τin a uniform E field. An object with an electric dipole moment is subject to a torque τ when placed in an external electric field. The torque tends to align the dipole with the field, and makes alignment an orientation of lower potential energy than misalignment.