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Ch. 1 notes, part2 1 of 10

A Brief History of Modern and the development of the Schrödinger Equation

"Modern" physics means physics discovered after 1900; i.e. twentieth-century physics.

1900: (German) tried to explain blackbody ("BB") radiation (that's radiation from warm objects, like glowing coals) using Maxwell's equations and statistical and found that he could not. He could only reproduce the experimentally-known BB spectrum by assuming that the energy in an electromagnetic wave of frequency f is quantized according to , where n = 1, 2, 3, … and h = Planck's constant = 6.6×10−34 (SI units) Planck regarding this as a math trick; he was baffled by its physical significance.

1905: , motivated in part by Planck's work, invents the concept of a photon (though the name "photon" came later!) to explain the photoelectric effect. A photon is a quantum (packet) of electromagnetic radiation, with energy

.

h Note the definition of  ≡ =1.05x10-34 J s = 6.6x10-16 eV s (Called "hbar") 2π

1911: Ernest Rutherford (New Zealand/Britain) shows that an consists of a small, heavy, positively-charged nucleus, surrounded by small light .€ But there is a problem with the classical theory of this nuclear atom: An in orbit about a nucleus is accelerating and, according to Maxwell's equations, an accelerating charge must radiate (give off EM radiation). As the electron radiates, giving energy, it should spiral into the nucleus.

1913: (Danish), a theorist working in Rutherford's lab, invents the . This is essentially a classical model, treating the electron as a particle with a definite position and , but the model has two non-classical, ad hoc assumptions: 1) The angular momentum of the electron is quantized: . 2) The electron orbits, determined by (1), are stable ("stationary"), do not radiate, unless there is a transition between two orbits, and then the atom emits or absorbs a single photon of energy Classically, an electron in an atom should radiate and spiral The predictions of Bohr model match the experimental spectrum of inward as it loses energy. hydrogen perfectly.

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Ch. 1 notes, part2 2 of 10

It is important to remember that the Bohr model is simple, useful, and wrong. For instance, it predicts that the ground state of the H-atom has angular momentum , when in fact, the ground state of the H atom (s-state) has L = 0. The Bohr model is a semi-classical model, meaning it combines aspects of classical and . Semi-classical models are frequently used by because they are heuristically useful (easy to understand and often give correct results). But they must always be used with extreme care, because the microscopic world is really purely quantum. We insert into the microscopic world not because it is correct, but because it is convenient.

1922: (French) proposes wave-particle duality. Theory and experiment indicate that waves sometimes act like particles (photons). Perhaps, argues de Broglie, particles can sometimes act like waves. For photons: .

According to (and Maxwell's equations) light of energy E carries momentum .

Hence, . De Broglie argues that the same equations apply to particles and introduces the idea of matter waves.

de Broglie relations:

De Broglie's hypothesis provides a nice explanation for Bohr's quantization condition : assuming that an integer number of fit in one orbital circumference (the condition for a standing wave), we have

Soon, there was indisputable experimental verification of the photon concept and n = 5 of the de Broglie relations. In 1923, the American Arthur Holly Compton observes the Compton Effect, the change in of gamma-rays upon collision with electrons. This effect can only be explained by assuming that gamma-rays are photons with energy and momentum

. Then, in 1927, Americans Davisson and Germer diffract a beam of electrons from a nickel crystal, experimentally verifying that for electrons. Late in 1925, Erwin Schrödinger, then Professor of Physics at Zurich University, gives a colloquium describing de Broglie's theory. In the audience is Peter Debye, who called this theory "childish" because "to deal properly with waves, one has to have a wave equation". Over Christmas break, Schrödinger begins developing his equation for matter waves.

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Ch. 1 notes, part2 3 of 10

1927: Erwin Schrödinger (Austrian) constructs a wave equation for de Broglie's matter waves. He assumes that a free particle ( = V = 0) is some kind of wave described by

{ Recall Euler's relation: , so .} Initially, Schrödinger works with a complex wavefunction purely for mathematical convenience. He expects that, in the end, he will take the real part of Ψ to get the physically "real" matter wave. )

The energy of this free particle is all kinetic so . According the de Broglie relations, this can be rewritten:

Schrödinger searches for a wave equation that will reproduce this energy relation. He notes that

and

so ... the (trial) equation

This looks promising. To describe a particle with both KE and potential energy V = V(x), Schrödinger added in the term V⋅Ψ , producing finally

The Schrödinger Equation is really an energy equation in disguise. When you look at the S.E., you should try to see E = KE + PE. For a particle with frequency f (energy E = h f ) and wavelength λ (momentum p = h/λ ) in a potential V, this equation appears to correctly predict that

which (according to de Broglie) is

This "derivation" is merely a plausibility argument. Schrödinger immediately used the equation to solve for the energies in a and found that he got the right answer for the energy levels. This gave him confidence that the equation was correct.

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Ch. 1 notes, part2 4 of 10

The physicist famously asserted that the Schrödinger Equation accounts for "much of physics and all of chemistry". It is probably the most important equation of the 20th Century. Its effect on technological progress has been much, much greater than the more famous equation E = mc2. Schrödinger was quite puzzled by the of the . What is the physical meaning of Ψ(x,t)? He wanted to think of it as some kind of physical matter wave, like an electromagnetic wave E(x,t). But this interpretation could not explain a host of experimental results, such as that fact that a particle with a large extended wave function is always found at one small spot when a position measurement is made.

It was German theorist , who late in 1927 proposed that the wave function is a kind of information wave. It provides information about the probability of the results of measurement, but does not provide any physical picture of "what is really going on." Bohr, Heisenberg, and others argued that questions like "what is really going on" are meaningless. Humans live at the macroscopic level, excellently described by classical mechanics, and our brains evolved to correctly describe macroscopic (classical) phenomena. When we ask "what is going on", we are really asking for an explanation in terms that our brains can process, namely, a classical explanation. The microscopic world is fundamentally different from the classical world of large objects that we inhabit, and our brains' internal models simply don't apply at the level of . There may be no hope of understanding "what is really going on" in atoms because our brains are not built for that job. All we can know are the results of measurements made with macroscopic instruments.

This view, that the wave function provides probabilistic information, but not a physical picture of reality, is part of the "Copenhagen interpretation" of Quantum Mechanics (so-called because it was largely developed at Bohr's research institute in Copenhagen.) Einstein, de Broglie, Schrödinger himself, and others were very dissatisfied with this view, and they never accepted the Copenhagen interpretation.

Nobel Prizes for QM

Many of the pioneers of QM eventually received Nobel Prizes in Physics

1918 Max Planck, concept of energy quanta 1921 Albert Einstein, photon concept and explanation of photoelectric effect 1922 Niels Bohr, Bohr Model 1926 and Gustav Hertz, Franck-Hertz experiment showing quantization of atomic levels 1927 , Charles Wilson, Compton effect, Wilson cloud chamber 1929 Louis de Broglie, wave-particle duality 1932 , and Matrix formulation of QM 1933 Erin Schrödinger and Paul Dirac, Formulation of QM 1937 Clinton Davisson and George Thomson, experimental discovery of electron 1945 , exclusion principle 1954 Max Born, interpretation of the wave function …

• Ernest Rutherford received the 1908 in chemistry for experimental investigations of , but never received the prize for discovery of the nuclear atom. • Albert Einstein never received the prize for either Special or General Relativity.

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Ch. 1 notes, part2 5 of 10

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Ch. 1 notes, part2 6 of 10

Max Planck, German, 1858-1947

Albert Einstein, German-Swiss-American, 1879-1955

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Ch. 1 notes, part2 7 of 10

Ernest Rutherford, New Zealand-British, 1871-1937

Niels Bohr, Danish, 1885-1962

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Ch. 1 notes, part2 8 of 10

Louis de Broglie, French, 1892-1987

Erwin Rudolf Josef Alexander Schrödinger, Austrian, 1887-1961

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Ch. 1 notes, part2 9 of 10

Comment on numbers and scales: QM involves solving partial differential equations (or matrix equations, or operator equations) which can at times be mathematically formidable, but in many cases, understanding the simple relations described in the sections above, and knowing the basic units and numerical constants, is enough to give you a sense for a lot of physics.

Simple relations to remember: All waves: λυ = v (wavelength * frequency = speed of wave. For light, v=c = 3x108 m/s) Light: E=hν (energy of photon is Planck's constant times frequency) =  ω (same, just convert frequency, ν, to angular frequency, ω, by υ = 2πω ) deBroglie relations ("matter waves") € p = h /λ = k 2π (p is momentum,€ lambda=wavelength of the matter wave, k = is the "wave€ number") λ Einstein: E=mc2 (only for objects at rest, otherwise use E 2 = p2c 2 + m2c 4 ) € It's amazing how much back of the envelope physics you can do with freshman physics, plus these!

Common numbers and constants: € € You can always look up constants (and you should locate your favorite collection!) but having a few common constants at your fingertips is really pretty handy. -34 Still, (e.g.)  =1.05x10 J s is a number which I often forget (it's so small!) The combination of this constant times the ,  c= 2000 eV Angstroms (roughly) is somehow a simpler number for me to remember. And this combination occurs often! • An Angstrom is 10-10 m, or 0.1 nm, a very convenient distance in atoms, since that happens to be € the typical size of atomic orbits. • An eV is not a standard SI energy unit, but this€ one I always seem to remember from E&M: 1eV = 1.6x10-19 J is a typical atomic energy scale. It's the energy gained when an charge "e" (like a , or electron) moves through a potential difference of 1 Volt) You use eV a lot in practical atomic problems.

q q Remember from E&M that electrical potential energy of two charges a distance r apart is 1 2 , 4πε0r e2 which tells us (using q=e) that has units of energy*distance, the exact SAME units as  c (!) 4πε0 Sure enough, the following combination of constants (which is thus UNITLESS,€ a pure number) e2 appears over and over in physical problems: = 1/137. € 4 c € πε0 This is called the "fine structure constant of nature". Another combination which you often see is 2 mec =511 keV (where m is the electron mass, and c the speed of light. By E=mc^2, this must have units of energy) € If you solve a problem and the answer does NOT have such a combination of constants, you might "multiply and divide" by some power of c (or  ) to GET this combination, so you can then just € "remember" the answer. I can't tell you how much calculator grief this has saved me over the years.

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Ch. 1 notes, part2 10 of 10

Slightly silly Example: How many photons does an ordinary lightbulb emit each second?

This is a highly complex (and ill-defined!) problem, but we can make a simple, crude estimate by making some simplifying assumptions. 1) Assume light from a bulb is visible, in the middle of the spectrum (yellow). You would then have to go look up the wavelength of visible light, it's about 6000 Angstroms. 2) Assume that all the energy is going into visible light (ok assumption for a fluorescent bulb). You would then have to go look up the power of a bulb, though you can probably guess that's about 100W for a bright one. Each individual photon has energy E=hν, and so the total power (100 J/s) must be producing a total of 100 J/s / (hν Joules/photon) That's it, that's how many photons/sec should come out. Now, ν=c/λ (which is handy, because λ=6000 Angstroms was what I looked up) And 1eV = 1.6x10-19 J converts us to a more "photonic" energy scale So the answer is 100 J/s / (1. 6x10-19 J/eV) * λ / hc, and then multiplying top and bottom by 2 π, I get -19 (200π / 1. 6x10 ) * (λ /  c), and now I put in λ=6000 Angstroms, and  c= 2000 eV Angstroms, to get about 1022 photons each second. No wonder we never notice or care that they're discrete, that's a huge number!

€ € Slightly less silly Example: What energy should electrons have if you want to do an experiment to demonstrate their "wave nature"?

I am thinking that "showing wave nature" means generating some sort of interference, and for THAT, you need to have a wavelength comparable to a "slit size". The smallest slit I can imagine is ONE atom wide (imagine bouncing electrons off a crystal, they can bounce off of one atom, or its neighbor, and those two "sources" will interfere). Thus, without doing any hairball calculations, I would roughly want λ(electron) = atomic size = 1 Angstrom. (or so) DeBroglie then tells me I want the electron to have momentum p = h /λ . And the energy associated with that momentum will be the good old freshman 2 2 h formula, E = p /2m. So E = 2 . That's it, I could plug in numbers! 2mλ € But I can also multiply top and bottom by c^2, and divide top and bottom by (2 pi)^2, to get 4π 2 (c)2 E = 2 2 (this is the SAME formula but now has combinations of constants I remember!) 2mc λ € This I can do in my head. π^2 is about 10, so I have (without a calculator!) E = 4*π^2 *(2000 eV Angstrom)^2 / 2 (511 keV)(1 Angstrom)^2 That’s about 40*4*10^6 eV^2 / (1000 * 1000 eV) = 160 eV. € Anything LOWER than that will have a smaller momentum, or LONGER wavelength, and will diffract even better. So that's an upper bound. You don't need a high voltage supply for this! (This is the basic physics of the Davisson and Germer experiment that first showed that deBroglie was not off his rocker!)

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