612 CLASS LECTURE: HYPERBOLIC GEOMETRY 1. Conformal Metrics As a Vector Space, C Has a Canonical Norm, the Same As the Standard
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612 CLASS LECTURE: HYPERBOLIC GEOMETRY JOSHUA P. BOWMAN 1. Conformal metrics As a vector space, C has a canonical norm, the same as the standard R2 norm. Denote this jdzj|one should think of dz as the identity map on C: ζ 7! ζ. This also means C has a standard norm as the tangent space to itself at any of its points. We will consistently use Roman letters (e.g., z) to represent a point in C when we're thinking of it as a topological ◦ space, and Greek letters (e.g., ζ) to represent a point in C thought of as a vector. Let U ⊂ C be a plane domain (non-empty, connected, but not necessarily simply connected). Definition 1.1. A conformal metric on U is a metric of the form ρ jdzj, where ρ is a smooth, positive function on U. We will also use ρ to denote the metric itself, not just the function. Almost always, \conformal" is used with respect to something else; here, we mean that angles in a conformal metric are the same as those in the background Euclidean metric. In other words, the unit ball of the norm in the tangent space at z is invariant under (Euclidean) rotations. Example 1.2. On U = C n f0g, ρ = jdzj=jzj is a conformal metric. U is preserved by multiplication by a non-zero complex number a; call such a map ma. The derivative of ma is again multiplication by a. Let z 2 U and let ζ 2 Tz(U) = C. The image of z by ma is az, and the image of ζ by the derivative is aζ 2 Taz(U). Hence jaζj jajjζj jζj ρ(az)jaζj = = = = ρ(z)jζj; jazj jajjzj jzj that is, the metric is preserved by ma. Definition 1.3. If ρU is a conformal metric on U and ρV is a conformal metric on V , then a conformal diffeomorphism f : U ! V is called an isometry if it sends tangent vectors to tangent vectors of the same length, i.e., 0 ρV (f(z))jf (z)ζj = ρU (z)jζj for all z 2 U, ζ 2 C. Definition 1.4. Let D be the open unit disk in C. The Poincar´emetric (or hyperbolic metric) on D is the conformal metric 2 jdzj ρ = : D 1 − jzj2 Theorem 1.5. Up to a global scaling factor, ρD is the unique conformal metric on D that is invariant under the action of Aut(D). Date: 13 March 2008. 1 Proof. Recall that Schwarz's Lemma implies that all automorphisms of D have the form z − a f (z) = eiθ ; θ 2 ; a 2 : θ;a 1 − az R D Suppose ρ is any conformal metric on D invariant under Aut(D). If z 2 D is any point and 0 ζ 2 Tz(D) is any tangent vector, then f0;z : w 7! (w − z)=(1 − zw) sends z to 0, and f0;z sends ζ ζ 7! f 0 (z)ζ = 2 T : 0;z 1 − jzj2 0D By the invariance of ρ, we must therefore have jζj ρ(z)jζj = ρ(0)jf 0 (z)ζj = ρ(0) : 0;z 1 − jzj2 Which shows that ρ is a multiple of ρD. Conversely, ρD has just been shown to be invariant iθ under f0;a for all a, and it is clearly invariant under multiplication by e , hence it is invariant under all of Aut(D). Corollary 1.6. The isometry group of ρD is precisely Aut(D). Proof. Immediate, as previously observed, from Schwarz's Lemma. We can determine a lot about the geometry of the metric space (D; ρD) just from the our 1 knowledge of ρD and Aut(D). Given any smooth (C ) curve γ :[a; b] ! D, its Poincar´e length is Z b 0 `D(γ) = ρD(γ(t)) jγ (t)j dt: a Using the definition of a geodesic as a \locally length-minimizing" curve, we can then com- pute the geodesics in D. Let z 2 D − f0g; we want to find a geodesic path from 0 to z. Because ρD is invariant under rotations, we can assume z lies in (0; 1). Let γ :[a; b] ! D be any path from 0 to z. The composition of γ with the rotational projection (r; θ) 7! (r; 0) is again a smooth path jγj whose radial component is the same as that of γ, but whose rotational component is zero; hence `D(jγj) ≤ `D(γ). Thus the geodesic from 0 to z is the segment [0; z]. The complete geodesics through 0 are therefore the diameters of D. To find the geodesic path between z1 and z2, we recall that we can send z1 to 0 by an isometry, find the geodesic from 0 to the image of z2, and reverse the isometry. Because all of the elements of Aut(D) are M¨obiustransformations, which are conformal and send circles to circles, we conclude that the geodesic from z1 to z2 is the arc of the circle passing through 1 z1 and z2 and orthogonal to @D = S . (If these properties of M¨obiustransformations are unfamiliar to you, then work through Exercise 30 in Chapter 14 of [4].) Definition 1.7. Let H be the open upper half-plane in C. The Poincar´emetric (or hyperbolic metric) on H is the conformal metric jdzj ρ = ; y = Im z: H y 2 1 As subsets of CP = C [ f1g, we know that D and H are conformally equivalent, via the M¨obiustransformations 1 + z ' : z 7! i ! ; 1 − z D H w − i : w 7! ! : w + i H D We want to show that, in fact, these maps are isometries. We'll do this by \pulling back" ρH via ' and showing that the result coincides with ρD. (We won't formally define \pull-back", but it basically means cooking up a metric so that a diffeomorphism becomes an isometry. The definition should be clear after an example.) Given z 2 D, ζ 2 C, we have 2 0 1 2i j1 − zj 2 jζj ρ ('(z))j' (z)ζj = ζ = = ρ (z)jζj: H Im '(z) (1 − z)2 1 − jzj2 j1 − zj2 D Definition 1.8. We call any smooth Riemannian manifold that is isometric to (D; ρD) a model of the hyperbolic plane. Definition 1.9. If U is any simply connected domain in C, not equal to all of C, then its Poincar´emetric ρU is the conformal metric obtained by pulling back the Poincar´emetric on D via the Riemann map. (Note: this is well-defined because the Riemann map is defined up to an element of Aut(D).) Often, pictures are easier to draw in H than in D, because the geodesics are simply the circles and lines in C orthogonal to the real axis (again, this follows from properties of M¨obiustransformations). Also, the isometry group in this model simply becomes PSL2(R) ⊂ PSL2(C), because these are the M¨obiustransformations that preserve the real axis. This model distinguishes a single point 1 on the boundary, as we occasionally wish to do. Other models are also useful. For example, if we wanted to distinguish two points on the boundary, we could use the band model. Let B be the infinite strip B := fz 2 C j jIm zj < πg ; and define its Poincar´emetric by jdzj ρ = ; y = Im z: B cos y Then all translations in the x-direction are isometries: moreover, they preserve the two boundary points ±∞ and the geodesic between them. The remaining geodesics in this model are much more difficult to describe, however, except to say that they meet the boundary orthogonally (or have one end limiting to ±∞). Exercise 1. (1) Show that the map z 7! ez is an isometry from B with the conformal metric jdzj to C n (−∞; 0] with the conformal metric jdzj=jzj. [Note: the same calculation shows that the covering map z 7! ez is a local isometry from (C; jdzj) to (C n f0g; jdzj=jzj).] (2) Show that (B; ρB) is isometric to (D; ρD). (3) Find the Poincar´emetric on C n [0; 1). (4) Using the idea of \local isometry" from (1), find the Poincar´emetric on D n f0g. 3 2. Curvature The most geometric way to describe the qualitative difference between conformal metrics is via their curvature. Roughly speaking, we want to compare how the area of a circle grows in terms of its radius, and compare this to the Euclidean growth rate πr2. More precisely, we define the following. Definition 2.1. Let ρ jdzj be a conformal metric on U ⊂ C. Then the Gaussian curvature, or simply curvature, of ρ jdzj at z 2 U is ∆ log ρ(z) K (z) = − ; ρ ρ2(z) where ∆ is the standard Laplacian @2=@x2 + @2=@y2. Here's an attempt at a geometric explanation, somewhat hand-wavey for now: ∆/ρ2 = divρ2 gradρ is the Laplace{Beltrami operator for (U; ρ), hence is defined intrinsically. Note that the volume form on each tangent space to points in U is given by ρ2 dx ^ dy. ρx • gradρ log ρ = ρ measures the change in ρ with respect to itself ; the ρ-length of ρy 2p 2 2 this vector is ρ ρx + ρy , which takes into account both the current volume form and how fast it's changing. ρx • divρ2 ρ measures how the volume form changes when moving along flow lines ρy of the gradient of log ρ, i.e., in the direction that the metric is increasing most quickly.