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2012
On the Quantization Problem in Curved Space
Benjamin Bernard Wright State University
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This Thesis is brought to you for free and open access by the Theses and Dissertations at CORE Scholar. It has been accepted for inclusion in Browse all Theses and Dissertations by an authorized administrator of CORE Scholar. For more information, please contact [email protected]. ON THE QUANTIZATION PROBLEM IN CURVED SPACE
A thesis submitted in partial fulfillment of the requirements for the degree of Master of Science
by
BENJAMIN JOSEPH BERNARD B.S., University of Cincinnati, 1999
2012 Wright State University WRIGHT STATE UNIVERSITY
GRADUATE SCHOOL
July 3, 2012 I HEREBY RECOMMEND THAT THE THESIS PREPARED UNDER MY SUPERVISION BY Benjamin Joseph Bernard ENTITLED On the Quantization Problem in Curved Space BE ACCEPTED IN PARTIAL FULFILLMENT OF THE REQUIREMENTS FOR THE DEGREE OF Master of Science.
Lok C. Lew Yan Voon, Ph.D., Thesis Director
Doug Petkie, Ph.D. Chair, Department of Physics Committee on Final Examination
Lok C. Lew Yan Voon, Ph.D.
Morten Willatzen, Ph.D.
Gary Farlow, Ph.D.
Andrew Hsu, Ph.D. Dean, Graduate School ABSTRACT
Bernard, Benjamin Joseph. M.S., Department of Physics, Wright State Univer- sity, 2012. On the Quantization Problem in Curved Space
The nonrelativistic quantum mechanics of particles constrained to curved surfaces is studied. There is open debate as to which of several approaches is the correct one. After a review of existing literature and the required mathematics, three approaches are studied and applied to a sphere, spheroid, and triaxial ellipsoid. The first approach uses differential geometry to reduce the problem from a three- dimensional problem to a two-dimensional problem. The second approach uses three dimensions and holds one of the separated wavefunctions and its associated coordi- nate constant. A third approach constrains the particle in a three-dimensional space between two parallel surfaces and takes the limit as the distance between the surfaces goes to zero. Analytic methods, finite element methods, and perturbation theory are applied to the approaches to determine which are in agreement. It is found that the differential geometric approach has the most agreement. Constrained quantum mechanics has application in materials science, where topo- logical surface states are studied. It also has application as a simplified model of Carbon-60, graphene, and silicene structures. It also has application as in semiclas- sical quantum gravity, where spacetime is a pseudo-Riemannian manifold, to which the particles are constrained.
iii TABLE OF CONTENTS
CHAPTER
I. Introduction ...... 1
II. Mathematical Review ...... 5
2.1 Differential Geometry of Two-Dimensional Riemannian Mani- folds Embedded in R3 ...... 5 2.1.1 Introduction ...... 5 2.1.2 The Gauss-Bonnet theorem ...... 9 2.2 Differential Forms ...... 10 2.2.1 Introduction to differential forms ...... 10 2.2.2 The exterior derivative and its relation to divergence, gradient, and curl ...... 11 2.2.3 The Hodge dual operator ...... 12 2.2.4 The Laplace operator ...... 14 2.3 The Finite Element Method ...... 14 2.3.1 Weak formulation ...... 15 2.3.2 Numerical analysis ...... 16
III. Review of Constrained Quantum Mechanics ...... 21
3.1 Review of Existing Literature ...... 21 3.1.1 Jensen and Koppe (Ref. [1]) and da Costa (Ref. [2]) 21 3.1.2 Encinosa and Etimadi (Ref. [3]) ...... 35 3.1.3 Ley-Koo and Castillo-Animas (Ref. [4]) ...... 45
IV. Some Common Pitfalls ...... 61
4.1 Formulation of the Laplace-Beltrami Operator for the Surface from the Laplace Operator of the Embedded Coordinate System 63 4.2 The Effect of Curvature on Potential Energy ...... 64
iv 4.3 A Note on Spherical Coordinates ...... 65 4.4 On Separation Constants ...... 66
V. Analysis of a Sphere ...... 69
5.1 Analytical Solution ...... 69 5.2 Shell Method ...... 73 5.2.1 Summary of the method ...... 73 5.2.2 Calibration using the sphere ...... 74 5.2.3 Varying the distance between the spheres ...... 76 5.2.4 Calibration using a finite cylinder ...... 77 5.3 Summary ...... 79
VI. Analysis of the Prolate and Oblate Spheroids ...... 81
6.1 Formulation of Schr¨odingerEquation ...... 81 6.1.1 Fundamental forms and Laplace operator ...... 81 6.1.2 Mean and Gaussian curvatures ...... 83 6.1.3 Formulation and separation of the Schr¨odingerequation 84 6.2 Equivalence of the Two-Dimensional Equation with Ref. [5] . 87 6.2.1 Statement of the problem ...... 87 6.2.2 Choice of substitution ...... 88 6.2.3 Proof of equivalence ...... 89 6.3 Derivation of Equation (24) in Ref. [5] ...... 95 6.4 Numerical Validation of Ref. [5] ...... 102 6.5 Numerical Validation of Ref. [4] ...... 103 6.5.1 Extraction of data values in the reference material . 103 6.5.2 Using the two-dimensional equation ...... 108 6.6 Application of the Shell Method to the Spheroid ...... 111 6.6.1 Spherical limit ...... 111 6.6.2 Comparison with Ref. [5] ...... 113 6.7 Time-Independent Perturbation Theory Approach ...... 117 6.7.1 Perturbation using the spheroidal coordinate Schr¨odinger equation ...... 117 6.7.2 Energy shift due to curvature as a perturbation from a sphere ...... 118 6.8 Conclusions ...... 121
VII. Analysis of the Triaxial Ellipsoid ...... 123
7.1 Ellipsoidal Coordinate Formulation ...... 124 7.1.1 Fundamental forms and tangential Laplace-Beltrami operator ...... 124 7.1.2 Calculation of mean and Gaussian curvature . . . . 127
v 7.1.3 Formulation of the Schr¨odinger equation ...... 130 7.2 Longitude-Colatitude Coordinate Formulation ...... 130 7.3 Shell Method ...... 135 7.4 Time-Independent Perturbation Approach ...... 135 7.4.1 Application of the perturbation ...... 138 7.5 Conclusions ...... 138
VIII. Conclusions ...... 139
APPENDICES ...... 141 A. Transformation Properties of Differential Geometric Constructs . . . . . 143 A.1 Definitions of the System ...... 143 A.2 Metric Tensor ...... 145 A.3 Normal Vector ...... 146 A.4 Second Derivatives ...... 149 A.5 Second Fundamental Form ...... 150 A.6 Gaussian Curvature ...... 152 A.7 Mean Curvature ...... 152 B. Use of FEMLAB ...... 155 B.1 Startup ...... 155 B.2 Geometry ...... 155 B.3 Options ...... 158 B.3.1 Summary ...... 158 B.3.2 Constants and expressions ...... 159 B.4 Physics Menu ...... 161 B.4.1 Subdomain coefficients ...... 161 B.4.2 Boundary conditions ...... 164 B.4.3 Periodic boundary conditions ...... 164 B.5 Mesh Generation and Refinement ...... 167 B.6 Solver Parameters ...... 169 B.7 Solve the Problem ...... 169 B.8 Postprocessing ...... 169 C. Tables of Extracted Data ...... 175 D. Tables of Metric Tensors and Laplace-Beltrami Operators for Selected Coordinate Systems ...... 179 D.1 Metric Tensors ...... 179 D.2 Laplacian and Laplace-Beltrami Operators ...... 184
BIBLIOGRAPHY ...... 189
vi LIST OF FIGURES
Figure
3.1 Flowchart for a Schr¨odingerparticle constrained to a surface . . . . 23
3.2 Cross-section of Prolate Spheroid ...... 47
5.1 Overlay of shell method energy levels for cylinders with Differential Geometric analytical values ...... 79
6.1 η component M 2 − K for a prolate spheroid with f = 2.2, ξ = 1.1 . 84
6.2 M 2 − K for a prolate spheroid with f = 2.2, ξ = 1.1 ...... 85
2 6.3 Numerical solution of |σ00| for χ = 0.5 for the spheroid using ODE 103
2 6.4 Numerical solution of |σ10| for χ = 2.5 for the spheroid using ODE 104
2 6.5 Numerical solution of |σ00| for χ = 4 for the spheroid using ODE . 104
6.6 Energy eigenvalues for spheroids using finite element of ODE overlaid with Ref. [5] ...... 105
6.7 |σ|2 for ξ = 1.1, f = 10, m = 0, 1, 2, and 3 ...... 106
6.8 Energy levels for a prolate spheroid with ξ = 1.1 overlaid with Ref. [4]107
6.9 Energy levels for a prolate spheroid with ξ = 1.25 overlaid with Ref. [4] ...... 107
6.10 Energy levels for a prolate spheroid with ξ = 2 overlaid with Ref. [4] 108
6.11 Plot of E vs. χ in meV showing the spherical limit ...... 112
vii 6.12 Overlay of shell method energy levels for spheroids with Figure 4a from Ref. [5] ...... 113
6.13 (Color in electronic copy) |ψ|2 for the first three eigenfunctions for an oblate spheroid with χ = 0.5 ...... 115
6.14 (Color in electronic copy) |ψ|2 for the ground state for a prolate spheroid with χ =4...... 116
6.15 Overlay of various method ground state energy levels for spheroids with Figure 4a from Ref. [5] ...... 120
7.1 Plot of parameterization of the triaxial ellipsoid ...... 124
2 7.2 (Color in electronic copy) M − K for an ellipsoid with x0 = 1, y0 = 1.5, z0 =2...... 129
7.3 Perturbed ε for the triaxial ellipsoid for various values of χ1 and χ2 137
B.1 Model Navigator ...... 156
B.2 Model Navigator with physics added ...... 156
B.3 Geometry Editor ...... 157
B.4 Rectangle Editor ...... 157
B.5 Geometry Zoomed to extents ...... 158
B.6 Constants Menu Item ...... 160
B.7 Constants after editing ...... 160
B.8 Scalar Expressions ...... 161
B.9 Scalar Expressions after editing ...... 162
B.10 Subdomain Settings Menu Item ...... 163
B.11 Subdomain Settings diffusion coefficient tensor entry ...... 163
B.12 Subdomain Settings after editing ...... 164
B.13 Boundary Settings Menu Item ...... 165
viii B.14 Boundary conditions for periodic edges ...... 165
B.15 Boundary conditions for edge of cylinder ...... 166
B.16 Periodic Boundary Conditions menu item ...... 166
B.17 Periodic Boundary Conditions Source Tab ...... 166
B.18 Periodic Boundary Conditions Destination Tab ...... 167
B.19 Periodic Boundary Conditions Source Vertices Tab ...... 167
B.20 Periodic Boundary Conditions Destination Vertices Tab ...... 168
B.21 Periodic Boundary Conditions Destination Tab for u x ...... 168
B.22 Initialized Mesh ...... 168
B.23 Refined Mesh ...... 169
B.24 Solver Parameters menu item ...... 170
B.25 Solver Parameters Screen ...... 170
B.26 Solve Problem menu item ...... 171
B.27 Solve Problem Progress screen ...... 171
B.28 Postprocessing Mode ...... 172
B.29 Plot Parameters Menu ...... 172
B.30 Plot Parameters Screen ...... 173
B.31 Plot Parameters General Tab ...... 174
ix LIST OF TABLES
Table
5.1 Analytical Energy levels for concentric spheres ...... 75
5.2 FEMLAB Energy levels for concentric spheres ...... 76
5.3 Convergence of FEMLAB runs on concentric spheres by refinements 76
5.4 The Sphere ...... 77
5.5 Fit values for energy in the surface limit for a cylinder using the shell method ...... 78
6.1 Fit values for energy in the surface limit for spheroids ...... 111
6.2 Energy comparison with Ref. [5] ...... 114
6.3 Spheroid Energy Eigenstates for l = 1, m =0...... 114
6.4 Spheroid Energy Eigenstates for l = m =1...... 117
7.1 Ellipsoid energy levels using the shell method ...... 135
7.2 Perturbative ε for ellipsoids near spherical limit ...... 136
B.1 Constants for the Cylinder ...... 160
B.2 Expressions for the Cylinder ...... 161
B.3 Subdomain Coefficients for the Cylinder ...... 162
B.4 Boundary Conditions for the Cylinder ...... 164
B.5 Periodic Boundary Conditions for the Cylinder ...... 165
x C.1 Extracted Energies and Numerically Calculated Energies From Ref. [4]175 C.1 Extracted Energies and Numerically Calculated Energies From Ref. [4]176 C.1 Extracted Energies and Numerically Calculated Energies From Ref. [4]177
xi PREFACE
This document is the product of two years of research into quantum mechanics and differential geometry. Many other related topics were investigated, such as the Dirac equation, geometric quantization, symplectic geometry, Fourier methods, infi- nite dimensional differential geometry, and fractional dimensional space. The cylinder and M¨obiusstrips were also solved during the course of the research. During these studies it was found that there is still disagreement between the various methods used. This was the genesis of the thesis you now read. It was decided to compare and contrast the various formulations and find which one was the correct one. Ben Bernard June 18th, 2012
xii ACKNOWLEDGEMENTS
Thanks to Dr. Giovanni Cantele, for kindly providing his source code, and to Dr. Morten Willatzen, for allowing me to use and modify his source code for the triaxial ellipsoid. Also thanks to Robert Zabloudil for reviewing the final draft for grammatical and typographical errors.
xiii For my wife and child, for their patience and understanding during two long years of study.
xiv LIST OF ABBREVIATIONS
DG differential geometric
FEM finite element method
FFT fast Fourier transform nm nanometers
QM quantum mechanics
ODE ordinary differential equation
PDE partial differential equation
xv
CHAPTER I
Introduction
This thesis studies the quantum mechanics of particles constrained to curved sur- faces using differential geometric methods. This has application in materials science, where molecules can form two-dimensional topological objects, such as fullerenes, graphene, and silicene.
It is a somewhat different problem than the three-dimensional quantum dot prob- lem, as the dimensionality is lowered, thereby changing the three-dimensional Laplace operator to a two-dimensional Laplace-Beltrami operator, and the curvature of the surface produces a potential energy term.
The quantum mechanics of particles constrained to a surface was first researched in 1971 by Jensen and Koppe [1]. In 1981 da Costa et al [2] explored such a system in more detail. Other papers include Ley-Koo and Castillo-Animas [4], who studied the prolate spheroid by holding the ξ coordinate in the spheroidal wave equation constant, Encinosa and Etemadi [3], who studied Monge patches with cylindrical symmetry, and Kleinert [6], who studied Dirac quantization on a sphere.
There exist multiple methods for deriving and solving the Schr¨odingerequation for a particle constrained to surfaces. One approach (Refs. [1; 2; 3]) uses differential geometry to reduce the dimensionality of the three-dimensional partial differential equation (PDE) to a two-dimensional one. Another method (Ref. [4]) is to solve
1 the three-dimensional PDE and hold the surface normal coordinate constant. A third method (Refs. [7; 6]) involves incorporating the constraints into the classical Hamiltonian and quantizing its Dirac bracket. There are other methods as well (Refs. [8; 9; 10]) which are beyond the scope of this thesis.
Finally, one may treat one or more terms in the equation as a perturbation; however this only holds as long as those terms are small compared with standard solutions. This is a standard method taught in most quantum mechanics courses, and is generally easy to implement if one knows the unperturbed state well. However, this method breaks down as the shape deviates from the unperturbed state. For example, a highly eccentric spheroid will have significant error if a sphere is used for its unperturbed state. A nearly spherical triaxial ellipsoid, on the other hand, will likely have fairly accurate results.
This plethora of techniques presents a problem: while each technique produces results consistent with itself, the techniques produces results that do not agree with other techniques. This was noted by Ref. [11], which compared the method of da Costa (Ref. [2]) with the method of Dirac (Ref. [7]) in the hope of resolving this issue. It was found there that the da Costa equation agrees with Dirac’s formalism when two ordering parameters are used in conjunction with a conserved constraint in the latter approach, and physical ordering is adopted for those parameters. The divergent surface-normal term does not appear under the Dirac formalism because it disappears under the Dirac bracket. This consolidates the Dirac and da Costa methods, as they are equivalent.
The aim of this thesis is to analyze each of the methods and determine which is the best method to use for a given problem. It is likely to depend on the surface in question; for example some simple surfaces such as the sphere and cylinder have easily derived analytical solutions. Other surfaces may have a metric tensor that is sufficiently simple to allow the curvature term to be neglected. Still other surfaces are
2 separated into ordinary differential equation (ODE)s that can be more readily solved by numerical methods. Then there is the class of surfaces that is not easily solved by any method. In this thesis, the general procedure is outlined, and then finite element analysis is used to study the sphere, spheroid, and triaxial ellipsoid. The sphere has no cur- vature term using the differential geometric approach. The spheroid has a separable curvature term, and the curvature term for the triaxial ellipsoid is not separable. The triaxial ellipsoid has never been studied. It is hoped that studying these surfaces will shed light on which is the proper method.
3
CHAPTER II
Mathematical Review
2.1 Differential Geometry of Two-Dimensional Riemannian
Manifolds Embedded in R3
2.1.1 Introduction
Throughout this text, unless stated otherwise, like indices will be summed over. Partial derivatives will be denoted variously by the following notations as makes the most sense for the context: ∂f i = ∂ f i = f i . (2.1) ∂qj j ,j
To begin the study of constrained quantum mechanics, several differential geomet- ric tools will be needed. We begin with a parametrization (also known as a coordinate chart) r(qi) from Cartesian coordinates to generalized coordinates qi that are tangent to the surface at all points on the surface:
x(q) r = y(q) . (2.2) z(q)
The first and second partial derivatives of the components of the parametriza-
5 tion make up the Jacobian and Hessian matrices, respectively. The elements of the Jacobian matrix are given by ∂ri J i = , (2.3) j ∂qj
and each element of the parametrization has its own Hessian matrix, which collectively can form a rank-three tensor: ∂2ri Hi = . (2.4) jk ∂qj∂qk
From the parametrization we can construct the metric tensor, or first fundamental form. This describes how the distances between points change under coordinate transformations. For a surface, it is given by [12]
∂r ∂r g = · . (2.5) ij ∂qi ∂qj
If gij = 0, i 6= j, then the coordinate system is orthogonal and the components of
2 the metric are often referred to as scale factors hi, with (hi) = gii. [13]
Also from the parametrization, we can derive the unit normal vector. This vector field has unit norm and is orthogonal to the surface at all points passing through the surface. It is given by [14] ∂r ∂r ∂q1 × ∂q2 n = . (2.6) ∂r × ∂r ∂q1 ∂q2
Once we have the normal vector, we can now compute the second fundamental form, given by [8] ∂2r h = n · . (2.7) ij ∂qi∂qj
The second fundamental form is closely related to the shape operator (also known as
6 the Weingarten map). It is given by the matrix [2]
1 g12h21 − g22h11 h11g21 − h21g11 α = (2.8) g h22g12 − h12g22 h21g12 − h22g11
We will now take a slight detour to show, using linear algebra, that the shape operator provides a linear map between the first and second fundamental forms, and that its determinant and trace are related to the mean and Gaussian curvatures. Begin with the Weingarten equations in matrix form.
1 g12h21 − g22h11 h11g21 − h21g11 α = g h22g12 − h12g22 h21g12 − h22g11 1 −g22h11 + g12h21 −h21g11 + h11g21 = g −g22h12 + g12h22 −h22g11 + h21g12 −g g 22 12 h11 h21 h11 h21 g −g 1 12 11 = g −g22 g12 h12 h22 h21 h22 g12 −g11 1 h11 h21 −g22 g12 = (2.9) g h12 h22 g12 −g11
The first and second fundamental forms are symmetric matrices, so
1 h11 h12 g22 −g12 α = − (2.10) g h21 h22 −g21 g11
7 and we have the simple relation
α = −hg−1, (2.11)
which is more elegantly written as
h = −αg. (2.12)
Once these components can be found, we can calculate the Gaussian curvature using the formula h K = = − det α, (2.13) g
where h = det h and g = det g. The Gaussian curvature is an intrinsic curvature and an invariant of the surface.
The next quantity is the mean curvature, which is an extrinsic curvature that can be calculated in several ways. Among them is (Ref. [2])
1 M = (g h + g h − 2g h ) = − Tr α. (2.14) 2g 11 22 22 11 12 12
Because it is an extrinsic property, it is not invariant but instead depends on its embedding.
Finally, following the postulate of Podolsky in 1928 [15], we will need to replace the Laplace operator in the Schr¨odingerequation with the Laplace-Beltrami operator. The Laplace-Beltrami operator is [2]
√ √ 1 ∂ g ∂χ 1 ∂ g ∂χ D 1 2 t t χt q , q = √ 1 1 + √ 2 2 + g ∂q g11 ∂q g ∂q g22 ∂q √ √ 1 ∂ g ∂χt 1 ∂ g ∂χt √ 2 1 + √ 1 2 . (2.15) g ∂q g21 ∂q g ∂q g12 ∂q
8 2 2 The operator D will often be notated as ∇ or ∇LB using an abuse of notation. Note that when the coordinate system is orthogonal, the metric is diagonal, and the curvature term becomes
2 2 (g11h22 + g22h11) − 4g11g22h11h22 M − K = 2 2 , 4(g11) (g22) 2 2 2 2 (g11) (h22) + 2g11g22h11h22 + (g22) (h11) − 4g11g22h11h22 = 2 2 , 4(g11) (g22) 2 (g11h22 − g22h11) = 2 2 , 4(g11) (g22) 1 g h − g h 2 = 11 22 22 11 , 4 g11g22 1 h h 2 = 11 − 22 , (2.16) 4 g22 g11
which simplifies calculations considerably.
2.1.2 The Gauss-Bonnet theorem
We close this section on classical differential geometry with an important result. But first we will need two more definitions.
The Euler characteristic of a surface is a topological invariant related to the genus of the surface (the number of holes in the surface). For a surface with genus g, it is
χ = 2 − 2g. (2.17)
A surface with no holes has genus zero, hence χ = 2.
The geodesic curvature is a measure of curvature relative to the curvature of the shortest paths on a curved surface in such a way that the geodesic curvature along such paths is zero. Full details of geodesic curvature are not needed for this project and are therefore beyond the scope of this thesis.
The Gauss-Bonnet theorem, which states that the geometry of a surface M with
9 Gaussian curvature K, geodesic curvature kg and Euler characteristic χ(M) is related to its topology by Z Z Kda + kgds = 2πχ(M). (2.18) M ∂M
For a closed surface without boundary, such as an ellipsoid, there are no boundaries to integrate and the central term can be omitted. Thus we are left with the integral curvature Z Kda = 4π, (2.19) M which is a topological invariant.
2.2 Differential Forms
2.2.1 Introduction to differential forms
Differential forms are the integrands of integrals including the suffix dx, where x is the variable of integration. The line, surface, or volume being integrated over is called a chain. A p-dimensional integral involves a p-form with a p-chain. The forms and chains must have the same dimensionality. For example, a function f is a zero-form, dx is a one-form, dA = dx∧dy is a two-form, and dV = d3x = dx∧dy ∧dz is a three-form.
The ∧ in the two-form is a generalization of the cross product called the wedge, or exterior, product. The wedge product is associative and distributive. It also has the property that a ∧ a = 0. The wedge product of an n-form with an m-form is an (n + m)-form. The wedge product of a p-form a and a q-form b obeys the relation [16; 17] a ∧ b = (−1)pqb ∧ a. (2.20)
A zero-form f is just a function. Integrals of zero-forms are ordinary integrals.
10 A one-form F may be written as
F = Fxdx + Fydy + Fzdz. (2.21)
This is often shown in vector calculus texts (such as Ref. [14]) as F · dr. Therefore integrals of one-forms are line integtrals.
A two-form is the wedge product of two one-forms. The wedge product of two one-forms in three dimensions is the cross product of them. A two-form exists in two-dimensions. Thus a two-form can be written
F = Fxdx ∧ dy + Fydy ∧ dz + Fzdz ∧ dx. (2.22)
A three-form is the wedge product of a one-form and a two-form, or the triple wedge product of three one-forms. The space of three-forms in three-dimensional space is one-dimensional because there is only one combination of dx, dy, and dz, dx ∧ dy ∧ dz. Integrals of three-forms are volume integrals.
2.2.2 The exterior derivative and its relation to divergence, gradient, and curl
n n o The exterior derivative of f with respect to a p-form in R with basis e1, e2, ...e n (p) is a (p + 1)-form given by the relation[18]
n (p) n X X ∂f df = dxi. (2.23) ∂xi i=1 k=1
We now look at the exterior derivatives of various types of forms in R3. We begin with a zero-form f. Its exterior derivative is the one-form
∂f ∂f ∂f df = dx + dy + dz = ∇f. (2.24) ∂x ∂y ∂z
11 For a one-form F = Fxdx + Fydy + Fzdz we have the two-form
∂F ∂F ∂F ∂F ∂F ∂F dF = z − y dy∧dz+ x − z dz∧dx+ y − x dx∧dy = ∇×F. ∂y ∂z ∂z ∂x ∂x ∂y (2.25)
For a two-form we have the three-form
∂F ∂F ∂F dF = x + y + z dxdydz = ∇ · F. (2.26) ∂x ∂y ∂z
The exterior derivative of a three-form fdx ∧ dy ∧ dz is always zero by Poincar´e’s Lemma [19],
∂f ∂f d(fdx ∧ dy ∧ dz) = dx ∧ dx ∧ dy ∧ dz + dy ∧ dx ∧ dy ∧ dz ∂x ∂y ∂f + dz ∧ dx ∧ dy ∧ dz, ∂z = 0. (2.27)
This is often written as d2 = 0.
Thus we see that the gradient, curl, and divergence correspond to the exterior derivatives of zero-, one-, and two-forms respectively.
2.2.3 The Hodge dual operator
We are now in a position to discuss the Hodge star operator, ∗. Its motivation is to find the dual of an n-form in q-dimensional space. The Hodge operator gives the
dual of a form. Given a p-form in Rn, the Hodge operator ∗ returns an (n − p)-form
p ! n Y 1 Y ∗ df ik = dxik . (2.28) (n − p)! i1i2...ipip+1in k=1 k=p+1
12 This rather terse definition is due to the requirement that Stokes’s theorem,
Z Z f = df (2.29) ∂Ω Ω is satisfield, where Ω is a chain and ∂Ω is its boundary. For one-forms in three- dimensional space,
∗dx = dy ∧ dz, ∗dy = dz ∧ dx, and ∗dz = dx ∧ dy. (2.30)
The Hodge dual of a two-form in three-dimensional space is a one-form, given by
∗(dy ∧ dz) = dx, ∗(dz ∧ dx) = dy, and ∗(dx ∧ dy) = dz. (2.31)
Finally, the Hodge dual of a three-form is a zero-form in three-dimensional space.
13 2.2.4 The Laplace operator
Applying the exerior derivative and Hodge dual of a zero form twice in an orthog- onal basis is the Laplacian. Explicitly,
∂f ∂f ∂f ∗d ∗ df = ∗d ∗ dq1 + dq2 + dq3 , ∂q1 ∂q2 ∂q3 ˆe1 ∂f ˆe2 ∂f ˆe3 ∂f = ∗d ∗ √ 1 + √ 2 + √ 3 , g11 ∂q g22 ∂q g33 ∂q ˆe2 ∧ ˆe3 ∂f ˆe3 ∧ ˆe1 ∂f ˆe1 ∧ ˆe2 ∂f = ∗d √ 1 + √ 2 + √ 3 , g11 ∂q g22 ∂q g33 ∂q √ √ √ g22g33 ∂f 2 3 g11g33 ∂f 3 1 g11g22 ∂f 1 2 = ∗d √ 1 dq ∧ dq + √ 2 dq ∧ dq + √ 3 dq ∧ dq , g11 ∂q g22 ∂q g33 ∂q √ √ ∂ g22g33 ∂f ∂ g11g33 ∂f = ∗ 1 √ 1 + 2 √ 2 ∂q g11 ∂q ∂q g22 ∂q √ ∂ g11g22 ∂f 1 2 3 + 3 √ 3 dq ∧ dq ∧ dq , ∂q g33 ∂q 1 ∂ √ ∂f ∂ √ ∂f ∂ √ ∂f = √ gg11 + gg22 + gg33 , g ∂q1 ∂q1 ∂q2 ∂q2 ∂q3 ∂q3 ∗d ∗ df = ∇2f. (2.32)
Therefore the Laplacian maps a zero-form to a zero-form.
In summary, the exterior derivative and the Hodge dual provide the tools neces- sary to derive the gradient, curl, divergence, and Laplacian in any three-dimensional orthogonal coordinate system.
2.3 The Finite Element Method
The purpose of this section is to summarize the theory behind the finite element method. This consists of two parts: putting the equation into a weak form using the Galerkin method, and then performing numerical analysis of this weak form. This section draws heavily from [20] and the reader is encouraged to read that treatise on the subject.
14 2.3.1 Weak formulation
We begin with a given linear second order differential equation, which can be put into the form f [y00, y0, y, x] = 0, (2.33) where f is a functional of differential operators operating on y(x). We first slice the continuum into a discrete lattice with n + 1 nodes connecting n segments. We then approximate y(x) as a linear combination of shape functions φi(x) over these segments [20]: n+1 X y(x) ≡ aiφi(x). (2.34) i=1
This is not an identity but an approximation. Therefore there is a residual error intrinsic to the formulation. This residual is defined as [20]:
R(y, x) ≡ f [y00, y0, y, x] . (2.35)
We seek to minimize this residual function by assuming that the weighted integral over its domain is zero [20]:
Z L W (x)R(y, x)dx = 0. (2.36) 0 where W (x) is a weighting function. In the Galerkin method, the weighting functions are taken to be the shape functions. This produces [20]
Z L φ(x)R(y, x)dx = 0. (2.37) 0
Equation (2.37) is not sufficient because the first order derivatives are not con- tinuous at the nodes, which means that the second order derivatives do not exist at
15 those points. Integration by parts provides the required form [20]
Z L Z Z L dφ Z φ(x)R(y00, y0, y, x)dx = φ(x) R(y00, y0, y, x)dx − R(y00, y0, y, x)dx dx. 0 0 dx (2.38)
In the case of a linear differential equation,
f[y00, y0, y, x] = Ay00 + By0 + Cy + D, (2.39)
this integral is
Z Z L dφ Z φ(x) R(y00, y0, y, x)dx − R(y00, y0, y, x)dx dx = 0 dx dy L Z L dφ dy φ(x) A + By + C − A + By + C dx, (2.40) dx 0 0 dx dx
leaving the weak form as the integral equation
dy L Z L dφ dy φ(x) A + By + C − A + By + C dx = 0. (2.41) dx 0 0 dx dx
This form has the advantage of not requiring the second derivative be a continuous function and is therefore better suited to our purpose.
2.3.2 Numerical analysis
The next step is to implement numerical analysis over the weak form given in equation (2.41). We begin by focusing on a single segment with nodes xi and xi+1, with values y(xi) at the node xi and y(xi+1) at the node xi+1. We set up our shape functions such that φi+1(xi) = 0 and φi(xi) = 1 [20]. We then have shape functions that only affect the neighboring nodes. We can then write this section of the overall
16 system as [20]
ai dφi dφi+1 dφ dφ y(x) = ai + ai+1 = i i+1 , (2.42) dx dx dx dx ai+1
where the ai terms are coefficients from the linear combination in equation (2.34). This form is then plugged into the weak form given by equation (2.41) and written in matrix form, ultimately producing a linear algebra equation allowing for the solution of the ai terms. These terms are then back-substituted into equation (2.34) and the numeric value of y(x) is determined.
Reference [20] uses a heat diffusion problem as an example. Given the boundary value problem d2T −K dx2 = Q, x = 0, (2.43) dT −K dx = q, T = TL, x = L, we arrive at the weak form [20]
Z L Z L L dφ dT dT K dx − φQdx − Kφ = 0. (2.44) 0 dx dx 0 dx 0
Using equation (2.34) gives [20] n+1 Z L Z L L X dφi dφj dT K dx a − φ Qdx + φ −K = 0, i = 1, 2, . . . n + 1. dx dx j i i dx j=1 0 0 0 (2.45)
We then choose the shape functions [20]
xi+1 − x φi(x) = , (2.46) xi+1 − xi
x − xi φi+1(x) = , (2.47) xi+1 − xi
17 such that each node only depends on its neighboring nodes.
Using these, we arrive at the system [20]
! Z L/2 dφ T dφ Z L q K dx a − Q φdx − = 0, (2.48) 0 dx dx 0 0
ai where φ = (note that it is a row vector) and a = . Evaluating φ at φi φi+1 ai+1 our values of x results in [20]
φ = 2x 2x (2.49) 1 − L L
dφ = − 2 2 . (2.50) dx L L
Using this in equation (2.48) and integrating gives for the first element [20]
2K 1 −1 a1 QL 1 q 0 − − = . (2.51) L 4 −1 1 a2 1 0 0
This process is then repeated for each element, giving similar results, and the system is then assembled with the form
1 −1 0 a1 q 1 0 2K QL −1 2 1 a = 0 + 2 = 0 . (2.52) L 2 4 0 −1 1 a3 0 1 0
Assembly is done such that the matrix is nearly block diagonal, except that each block is superimposed along the upper left and lower right element and added to-
QL gether. The vector with the 4 term is similarly superimposed and added, although
18 q it is not diagonal; rather it is stacked. All elements of the 0 vector beyond the 0 first element are zero because if no flux is specified, we assume that it is zero [20]. Once assembled, this system is solved using linear algebraic methods for the vector a. This solution is then fed back into equation 2.34 to find the numerical approxima- tion of the original boundary value problem.
19
CHAPTER III
Review of Constrained Quantum Mechanics
3.1 Review of Existing Literature
There are several methods for analyzing particles constrained to curved surfaces. We will review them in this chapter.
3.1.1 Jensen and Koppe (Ref. [1]) and da Costa (Ref. [2])
Ref. [1], published in 1971, derives the fundamentals of the theory and may be considered the first paper on the subject. Ref. [2], published ten years later, clarifies and more firmly derives the results of Ref. [1]. A summary of these papers is now given. Both references give essentially the same derivation and so the two sources will be combined. The method Ref. [1] suggests is studying a particle confined between two parallel surfaces and reducing the distance between them until the surface-tangential portion is the only term that remains. The program is as follows: set up a system of parallel surfaces distance d apart with infinite potential outside the surfaces and no potential between them. Then solve the eigenvalue problem for several different values of d. Fit the slope of each eigenvalue to the form E = A/d2 − . The value of is the energy eigenvalue of the particle as the distance between the surfaces goes to zero. Ref. [1] uses a ring as an example.
21 The method of Ref. [2] reduces the three-dimensional system to a two-dimensional PDE; unfortunately even when separable these can be quite unwieldy. First, an ap- propriate coordinate system is selected. Such a coordinate system will have two or- thogonal coordinates tangential to the surface and one orthogonal to the surface. The metric tensor is derived, and from it the Weingarten equations, second fundamental form, mean and Gaussian curvatures, and the Laplace-Beltrami operator are derived for the coordinate system. These are used to form a surface tangential Schr¨odinger equation, which might be separable. Ref. [2] uses a bookbinder surface as an exam- ple. Ref. [5] uses this method to solve the problem of a particle constrained to the surface of a spheroid.
The process for calculation of a particle constrained to a curved surface as de- scribed in Ref. [2] is illustrated in Figure 3.1. The ultimate goal is to convert the three-dimensional problem into a two-dimensional problem by using coordinates tan- gential and normal to the surface.
3.1.1.1 Geometric construction
Begin with a parameterized two-dimensional surface r. Create a coordinate system using tangential coordinates (q1, q2) and a coordinate q3 that is normal to the surface everywhere. This gives us the mapping
x(q1, q2) 1 2 r(q , q ) = y(q1, q2) , (3.1) z(q1, q2)
which produces the metric tensor
gij = r,i · r,j. (3.2)
22 Figure 3.1: Flowchart for a Schr¨odingerparticle constrained to a surface
The normal vector is therefore
r × r Nˆ = ,1 ,2 (3.3) |r,1 × r,2|
The surrounding space can likewise be parameterized as
R(q1, q2, q3) = r(q1, q2) + q3Nˆ (q1, q2) (3.4)
We now introduce a potential barrier to constrain the particle to the surface,
0, |q3| < d 3 2 Vλ(q ) = , (3.5) 3 d V0, q > 2
where d is the width of the well and V0 is the energy value.
23 Taking the determinant of the shape operator gives
h det α = − det h det (g−1) = − = −K, (3.6) g
and its trace gives
1 Tr α = − (g h + g h − 2g h ) = −2M. (3.7) g 11 22 22 11 12 21
Continuing with the derivation of the Laplace-Beltrami operator, we find the gradients of the embedding. The derivatives of the normal vector are given by
Nˆ ,i = αijr,j, (3.8)
which leads to the second fundamental form,
hij = r,ij · Nˆ . (3.9)
The derivative of the parameterization of the surrounding space is
n 3 o 3 R,i = r,i + q Nˆ = r,i + q αij, (3.10) ,i
while the derivative of the surface coordinates are
3 r,j = (δij + q αij)r,j. (3.11)
The derivative of the parameterization of the surrounding space with respect to q3 is the normal vector:
R,3 = Nˆ . (3.12)
24 3.1.1.2 Formulation of the three-dimensional metric and Laplacian
The next goal is to define a metric in the three-dimensional space. The derivation goes as follows:
Gij = R,i · R,j
3 3 = (δik + q αik)r,k · (δjm + q αjm)r,m
3 3 = (δik + q αik)(δjm + q αjm)(r,k · r,m)
3 3 3 3 = (δikδjm + δikq αjm + q αikδjm + q αikq αjm)(r,k · r,m)
3 3 2 = δikδjm(r,k · r,m) + q (δikαjm + αikδjm)(r,k · r,m) + (q ) αikαjm(r,k · r,m)
3 3 2 = (r,i · r,j) + q (αjm(r,i · r,m) + αik(r,k · r,j)) + (q ) αikαjm(r,k · r,m)
3 3 2 = gij + q (αjmgim + αikgkj) + (q ) αikgkmαjm
3 3 2 = gij + q (αikgkj + αjmgmi) + (q ) αikgkmαjm
T 3 T 3 2 = gij + [αg + (αg) ]ijq + (αgα )ij(q ) (3.13)
Switching to full matrix notation,
G = g + [αg + (αg)T ]q3 + (αgαT )(q3)2,
= g + [−hg−1g + (−hg−1g)T ]q3 + [−hg−1g(−hg−1)T ](q3)2,
= g + [−h + (−h)T ]q3 + [−h(−hg−1)T ](q3)2,
= g − 2hq3 + h(g−1)T hT (q3)2,
= g − 2hq3 + hg−1h(q3)2 (3.14)
Gg−1 = gg−1 − 2hg−1q3 + hg−1hg−1(q3)2,
= I + 2αq3 + α2(q3)2,
= (I + αq3)2. (3.15)
25 This leaves the equation G = (I + αq3)2g (3.16)
The volume element plays a role in the separation of the Schr¨odingerequation. The determinant is given by
det G = det (I + αq3)2 det g, (3.17) which expands to
3 3 3 3 2 det (I + αq ) = (1 + α11q )(1 + α22q ) − α12α21(q ) (3.18)
Further expansion gives
3 3 3 3 2 3 2 I + αq = 1 + I + α22q + I + α11q + I + α11I + α22(q ) − I + α12I + α21(q ) ,
3 3 2 = 1 + (I + α11 + I + α22)q + (I + α11I + α22 − I + α12I + α21)(q ) ,
= 1 + Tr αq3 + det α(q3)2. (3.19)
Thus we have a function f that satisfies
p 3 3 3 2 f = I + αq = 1 + 2Mq + K(q ) . (3.20)
Orthonormality of the normal coordinate with the tangent subspace means that the full metric has the form
G11 G12 0 G = G G 0 . (3.21) 12 22 0 0 1
26 3.1.1.3 Schr¨odingerequation
We now introduce the Schr¨odinger equation
2 ∂ψ − ~ ∇2ψ + V ψ = i . (3.22) 2m λ ~ ∂t
Using Ref. [15], which is nearly as old as quantum mechanics itself, we use the three-dimensional Laplace-Beltrami operator. It is
√ 2 1 ij ∇ ψ = √ [ GG ψ,j],i (3.23) G where the metric tensor of the surrounding space is given by
G22 −G12 0 ij 1 G = −G G 0 , (3.24) g 12 11 0 0 1 and its determinant is
2 G = G11G22 − (G12) . (3.25)
So the Schr¨odingerequation expands to
2 √ ~ 1 ij − √ [ GG ψ,j],i + Vλψ = i~ψ,t, 2m G 2 1 2 2 − ~ G Gijψ − ~ Gij ψ − ~ Gijψ + V ψ = i ψ , 2m 2G ,i ,j 2m ,i ,j 2m ,ji λ ~ ,t 2 2 2 − ~ GG Gijψ − ~ Gij ψ − ~ Gijψ 2m ,i ,j 2m ,i ,j 2m ,ji 2 1 2 2 − ~ G G33ψ − ~ G33 ψ − ~ G33ψ + V ψ = i ψ . (3.26) 2m 2G ,3 ,3 2m ,3 ,3 2m ,33 λ ~ ,t
27 Noting that G33 = 1 we then have
2 1 2 2 − ~ G Gijψ − ~ Gij ψ − ~ Gijψ 2m 2G ,i ,j 2m ,i ,j 2m ,ji 2 G 2 − ~ ,3 ψ − ~ ψ + V ψ = i ψ . (3.27) 2m 2G ,3 2m ,33 λ ~ ,t
Next utilize the identity √ G [ln G] = ,3 (3.28) ,3 2G and separate the q3 variables to get
2 X 2 1 2 2 − ~ G Gijψ − ~ Gij ψ − ~ Gijψ 2m 2G ,i ,j 2m ,i ,j 2m ,ji i,j=1 2 1 √ 2 − ~ [ln G] ψ − ~ ψ + V ψ = i ψ , 2m 2G ,3 ,3 2m ,33 λ ~ ,t 2 2 X 1 − ~ G Gijψ + Gij ψ + Gijψ 2m 2G ,i ,j ,i ,j ,ji i,j=1 2 n √ o − ~ ψ + [ln G] ψ + V ψ = i ψ 2m ,33 ,3 ,3 λ ~ ,t 2 2 X 1 − ~ G Gijψ + Gij ψ + Gijψ 2m 2G ,i ,j ,i ,j ,ji i,j=1 2 n √ o − ~ ψ + [ln G] ψ + V ψ = i ψ (3.29) 2m ,33 ,3 ,3 λ ~ ,t
The tangential terms can be combined to form a new operator
1 D(q1, q2, q3)[ψ] = G Gijψ + Gij ψ + Gijψ , (3.30) 2G ,i ,j ,i ,j ,ji shortening the Schr¨odingerequation to
2 2 √ − ~ D(q1, q2, q3)[ψ] − ~ ψ + [ln G] ψ + V ψ = i ψ . (3.31) 2m 2m ,33 ,3 ,3 λ ~ ,t
28 3.1.1.4 Separation of variables
We now look to separate this equation into an equation tangential to the surface and an equation normal to the surface. To separate the equation, define a function
1 2 3 1 2 3 χ(q , q , q ) = χt(q , q )χn(q ) (3.32) and relate it to ψ by
χ(q1, q2, q3) = pf(q1, q2, q3)ψ(q1, q2, q3), (3.33) such that we can define the surface probability density as
Z 2 2 3 P = |χt| |χn| dq . (3.34)
We require a function f(q1, q2, q3) that has the volume element
√ dV = Gdq1dq2dq3. (3.35)
√ Defining dS = Gdq1dq2, we have
√ dV = f(q1, q2, q3) Gdq1dq2dq3. (3.36)
We can write the function derived above as
f = 1 + Tr (α)q3 + det (α)(q3)2 2 . (3.37)
29 √χ Next plug ψ = f into the Schr¨odinger equation and expand it:
2 χ 2 ∂2 χ ∂ h √ i ∂ χ − ~ D √ − ~ √ + ln G √ 2m f 2m ∂(q3)2 f ∂q3 ∂q3 f χ ∂ χ +V √ = i √ , (3.38) λ f ~∂t f
2 χ 2 ∂2 χ ∂ h √ i ∂ χ −pf ~ D √ − ~ pf √ + pf ln G √ 2m f 2m ∂(q3)2 f ∂q3 ∂q3 f ∂χ +V χ = i λ ~ ∂t (3.39),
2 χ 2 ∂ ∂ χ G ∂ χ −pf ~ D √ − ~ pf √ + pf ,3 √ 2m f 2m ∂q3 ∂q3 f 2G ∂q3 f ∂χ +V χ = i . (3.40) λ ~ ∂t
The central term evaluates to
∂ χ 1 χf χ χf √ = χ pf − √,3 = √,3 − ,3 , (3.41) ∂q3 f f ,3 2 f f 2f 32 which converts the Schr¨odingerequation to
2 χ 2 ∂ χ 1 ∂ χf G χ χf −pf ~ D √ − ~ pf √,3 − ,3 + pf ,3 √,3 − ,3 2m f 2m ∂q3 f 2 ∂q3 f 32 2G f 2f 32 ∂χ +V χ = i , λ ~ ∂t (3.42)
30 2 χ 2 χ χ f χ f χf 3 −pf ~ D √ − ~ pf √,33 − ,3 ,3 − ,3 ,3 − ,33 + χpf (f )2 2m f 2m f 2f 32 2f 32 2f 32 4f 3 ,3 G χ χf ∂χ +pf ,3 √,3 − ,3 + V χ = i . 2G f 2f 32 λ ~ ∂t (3.43)
Noting that G,3 = 2ff,3g,
2 χ 2 χ f χ f χf −pf ~ D(√ ) − ~ χ − ,3 ,3 − ,3 ,3 − ,33 2m f 2m ,33 2f 2f 2f 3 2ff g χf ∂χ + χ(f )2 + ,3 χ − ,3 + V χ = i . (3.44) 4f 2 ,3 2f 2g ,3 2f λ ~ ∂t
2 χ 2 3 1 −pf ~ D √ − ~ χ + χ(f )2 − (f )2χ 2m f 2m ,33 4f 2 ,3 2f 2 ,3 f f f ∂χ − ,33 χ − ,3 χ + ,3 χ + V χ = i (3.45) 2f f ,3 f ,3 λ ~ ∂t
2 χ 2 −pf ~ D √ − ~ {χ 2m f 2m ,33 3 2 f ∂χ + (f )2 − (f )2 − 2f ,33 χ + V χ = i (3.46) 4f 2 ,3 4f 2 ,3 4f 2 λ ~ ∂t
2 χ 2 pf − ~ D √ − ~ {χ 2m f 2m ,33 1 ∂χ + (f )2 − 2ff χ + V χ = i (3.47) 4f 2 ,3 ,33 λ ~ ∂t
31 2 χ 2 ∂2χ pf − ~ D √ − ~ 2m f 2m ∂(q3)2 " # ) 1 ∂f 2 ∂2f ∂χ + − 2f χ + V χ = i (3.48) 4f 2 ∂q3 ∂(q3)2 λ ~ ∂t
Since we are only interested in the surface, we can take the limit d → 0 and
3 q → 0, except for the Vλ term where it is important, and take V0 → ∞. Then f → 1 and
3 f,3 = lim Tr (α) + 2 det (α)q = Tr α, (3.49) q3→0
f,33 = 2 det α, (3.50)
2 2 ∂2χ 1 ∂χ − ~ D(χ) − ~ + (Tr α)2 − 4 det α χ + V χ = i (3.51) 2m 2m ∂(q3)2 4 λ ~ ∂t " # 2 2 ∂2χ 1 2 ∂χ − ~ D(χ) − ~ + Tr α − det α χ + V χ = i (3.52) 2m 2m ∂(q3)2 2 λ ~ ∂t
2 2 ∂2χ 2 ∂χ − ~ D(χ) − ~ − ~ (M 2 − K)χ + V χ = i (3.53) 2m 2m ∂(q3)2 2m λ ~ ∂t
Next we look at the D operator.
1 D(q1, q2, q3)[ψ] G Gijψ + Gij ψ + Gijψ , (3.54) 2G ,i ,j ,i ,j ,ji where
T 3 T 3 2 Gij = gij + [αg + (αg) ]ijq + (αgα )ij(q ) . (3.55)
3 ij ij 2 In the limit q → 0, Gij = gij, G = g , and G = f g = g, so we have
√ 1 2 3 1 ij ij ij 1 ij D(q , q , q )[ψ] = g,ig ψ,j + G ψ,j + g ψ,ji = √ [ Gg ψ,j],i. (3.56) 2G ,i G
Thus 2 X 1 ∂ √ ∂ψ D(q1, q2, q3)[ψ] = √ Ggij = ∇2 ψ. (3.57) ∂qi ∂qj LB i,j=1 G
32 1 2 3 1 2 3 Let χ(q , q , q , t) = χt(q , q , t)χn(q , t). Then
1 2 1 ∂ √ ∂χ 2 1 ∂χ ~ √ ij t ~ 2 t − i Gg j − (M − K) − i~ χt 2m G ∂q ∂q 2m χt ∂t 2 2 1 ~ ∂ χn 1 ∂χn = 3 2 − Vλ + i~ . (3.58) χn 2m ∂(q ) χn ∂t
Thus the equations separate to
2 √ 2 ~ 1 ∂ ij ∂χt ~ 2 ∂χn − √ Gg − (M − K)χt = i~ , (3.59) 2m G ∂qi ∂qj 2m ∂t and 2 ∂2χ ∂χ − ~ n + V χ = i n . (3.60) 2m ∂(q3)2 λ n ~ ∂t
The first equation is an infinite square well. The second will have energy eigen- values . The energy eigenvalues of the full PDE are given by
2n2π2 E = ~ + . (3.61) 2md2
Because it produces infinite energy eigenvalues as the range of q3 goes to zero, we can ignore the first term for the case of a constrained particle, leaving . Using the Weingarten equations the potential in the second equation can be written as
! 2 1 2 2 − ~ Tr (α ) − det (α ) = − ~ M 2 − K , (3.62) 2m 2 ij ij 2m where M is the mean curvature and K is the Gaussian curvature.
Thus the Laplace-Beltrami operator D (which is also denoted by the usual ∇2 or
2 ∇LB), mean curvature M, and Gaussian curvature K combine to form the curved- space Schr¨odingerequation:
2 − ~ D + M 2 − K χ q1, q2 = Eχ q1, q2 . (3.63) 2m t t
33 This is the equation that is used for solving particles constrained to curved surfaces as a two-dimensional problem. Note that if this derivation is not done correctly (for example, by taking a three-dimensional equation and simply holding one coordinate fixed with zero derivative at that value), the curvature terms will not show up in the Schr¨odingerequation.
3.1.1.5 Particle constrained to a circle
As a preliminary example, we study a particle constrained to a circle of radius a. Although this is a space curve and not a surface, and thus has a slightly different curvature term (Ref. [2]), it highlights a nontrivial effect of using the differential geometric formalism.
For a particle constrained to a circle of radius a, the parameterization is
a cos θ r = (3.64) a sin θ
Its derivatives are is given by
∂r − sin θ = a . (3.65) ∂θ cos θ
Thus the metric is − sin θ − sin θ 2 2 g = a · = a . (3.66) cos θ cos θ
The Laplace-Beltrami operator is
1 ∂2ψ ∇2ψ = , (3.67) a2 ∂θ2
34 and the curvature is 1 k = . (3.68) a
For a space curve, the Schr¨odingerequation is [2]
2 ∂2ψ 2 k2 − ~ − ~ ψ = Eψ, (3.69) 2ma2 ∂θ2 2m 4
so the Schr¨odingerequation becomes
2 ∂2ψ 2 − ~ − ~ ψ = Eψ. (3.70) 2ma2 ∂θ2 8ma2
This can be written as
∂2ψ 1 2ma2E = − + ψ, (3.71) ∂θ2 4 ~2 which is the Helmholtz equation with k2 equal to the quantity in parenthesis on the right hand side.
This has energy levels 2 1 E = ~ n2 − (3.72) 2ma2 4 where n ∈ N.
2 ~ Note that this energy has a shift of ∆E = − 8ma2 from the traditional solution in numerous quantum mechanics textbooks. [21; 22; 23; 24] However, since it is a constant shift, it does not affect the differences between energy levels and therefore has a negligible physical effect because it merely moves the zero-point energy.
3.1.2 Encinosa and Etimadi (Ref. [3])
Ref. [3] uses differential forms to derive the same Schr¨odingerequation as Refs. [2]. Rather than using classical differential geometry, one first forms the line element ds
35 and from it uses the exterior derivative and Hodge star operator to derive a Laplacian and the curvature energy shift. This produces equations identical to the method of Ref. [2] above.
3.1.2.1 Derivation of the Laplacian operator via differential forms
The derivation of the distortion potential begins with a parameterization of the two-dimensional surface in question and its embedding into a three-dimensional space.
The coordinate system is defined as two surface-parallel coordinates q1 and q2, and an orthogonal coordinate q3. The parameterization is
r(q1, q2, q3) = x(q1, q2) + q3ˆe3. (3.73)
The next step is to take the exterior derivative. It is
dr = dx + d(q3ˆe3) = dx + dq3ˆe3, (3.74)
where dq3 is the infinitesimal displacement normal to the surface. The exterior deriva- tive can be projected onto a coordinate basis by
dx = x,1dq1 + x,2dq2 = σ1ˆe1 + σ2ˆe2, (3.75)
where the ˆei’s are unit basis vectors and the σi’s are one-forms on . From this it can be deduced that
σ1 σ2 x,1dq1 + x,2dq2 = x,1 + x,2 , (3.76) |x,1| |x,2| so that σ1 = |x,1| dq1 and σ2 = |x,2| dq2.
36 For a zero-form χ, the exterior derivative is [3; 17]
∂χ ∂χ ∂χ dχ = dx1 + dx2 + dx3 ∂x1 ∂x2 ∂x3 ∂χ ∂χ ∂χ = |x,1| dq1 + |x,2| dq2 + dq3 ∂x1 ∂x2 ∂x3 ∂χ ∂χ ∂χ = σ1 + σ2 + dq3 ∂x1 ∂x2 ∂x3
= a1σ1 + a2σ2 + a3dq3, (3.77)
where the ai functions are zero forms. Its Hodge dual gives
∗dχ = ∗ (a1σ1 + a2σ2 + a3dq3) = a1σ2 ∧ dq3 + a2dq3 ∧ σ1 + a3σ1 ∧ σ2. (3.78)
Applying the exterior derivative of this gives
d ∗ dχ = d(a1σ2 ∧ dq3) + d(a2dq3 ∧ σ1) + d(a3σ1 ∧ σ2). (3.79)
Noting d2x = 0, a ∧ a = 0, and d(a ∧ b) = da ∧ b + (−1)pa ∧ db, where a is a p-form,
d ∗ dχ = d(a1σ2) ∧ dq3 + d(a2dq3) ∧ σ1 + d(a3σ1) ∧ σ2 + a1σ2 ∧ d(dq3)
+a2dq3 ∧ dσ1 + a3σ1 ∧ dσ2,
= da1σ2 ∧ dq3 + da2dq3 ∧ σ1 + da3σ1 ∧ σ2 + a1d2 ∧ dq3 + a3dσ1 ∧ σ2
+a2dq3 ∧ dσ1 + a3σ1 ∧ dσ2. (3.80)
∂σi Noting that di = 0 because = 0 for all (i, j), ∂xj
d ∗ dχ = χ,11σ1 ∧ σ2 ∧ dq3 + χ,22σ2 ∧ dq3 ∧ σ1 + χ,33dq3 ∧ σ1 ∧ σ2,
= χ,11σ1 ∧ σ2 ∧ dq3 + χ,22σ2 ∧ dq3 ∧ σ1 + χ,33dq3 ∧ σ1 ∧ σ2,
2 = (∇ χ)σ1 ∧ σ2 ∧ dq3. (3.81)
37 Taking the Hodge operator once more gives
∗d ∗ dχ = ∇2χ. (3.82)
Thus we have derived the Laplacian operator for this coordinate system via dif- ferential forms.
3.1.2.2 Cylindrical coordinates
Now that this has been derived, the parameterization is modified slightly such that in cylindrical coordinates it is described by the Monge form
r = ρ cos φˆi + ρ sin φˆj + S(ρ)kˆ. (3.83)
The arc length is given by 1 q = 1 + S2 . (3.84) Z ,ρ
This has cylindrical symmetry. The unit basis vectors are then given by
r,ρ ˆe1 = = (cos φ, sin φ, S,ρ) Z, (3.85) |r,ρ|
r,ρ 1 ˆe2 = = (−ρ sin φ, ρ cos φ, 0) = (− sin φ, cos φ, 0) , (3.86) |r,φ| ρ
ˆe3 = (−S,ρ cos φ, −S,ρ sin φ, 1) Z. (3.87)
38 The exterior derivative of the parameterization is
dr = σ1ˆe1 + σ2ˆe2 + σ3eˆ3
= r,ρdρ + r,φdφ + z,ρr,zdz,
= (cos φ, sin φ, S,ρ) dρ + (− sin φ, cos φ, 0) ρdφ + (−S,ρ cos φ, −S,ρ sin φ, 1) dz,
= (cos φ, sin φ, S,ρ) Zσ1 + (− sin φ, cos φ, 0) σ2 + (−S,ρ cos φ, −S,ρ sin φ, 1) Zσ3.
(3.88)
dρ This implies that σ1 = Z , σ2 = ρdφ, and σ3 = dq3.
Taking the Hodge dual of the exterior derivative gives
dρ 1 ∗ = ρdφ ∧ dq , ∗ρdφ = dq ∧ dρ, and ∗ dq = ρdρ ∧ dφ. (3.89) Z 3 Z 3 3
The next step is to derive the Laplacian operator.
∂χ ∂χ ∂χ dχ = dρ + dφ + dq3, ∂ρ ∂φ ∂q3 ∂χ dρ 1 ∂χ ∂χ = Z + ρdφ + dq3. (3.90) ∂ρ Z ρ ∂φ ∂q3
Taking the Hodge dual of this gives
∂χ 1 ∂χ dρ ∂χ dρ ∗dχ = Z ρdφ ∧ dq3 + dq3 ∧ + ∧ ρdφ, ∂ρ ρ ∂φ Z ∂q3 Z ∂χ 1 ∂χ ρ ∂χ = d ρZ dφ ∧ dq3 + d ρ dq3 ∧ dρ + d dρ ∧ dφ , ∂ρ Z ∂φ Z ∂q3 ∂ ∂χ ∂ 1 ∂χ = ρZ dρ ∧ dφ ∧ dq + ρ dφ ∧ dq ∧ dρ ∂ρ ∂ρ 3 ∂φ Z ∂φ 3 ∂ ρ ∂χ + dq3 ∧ dρ ∧ dφ, ∂q3 Z ∂q3 Z ∂ ∂χ ∂ 1 ∂χ ∂ ρ ∂χ dρ = ρZ + ρ + ∧ ρdφ ∧ dq3 . ρ ∂ρ ∂ρ ∂φ Z ∂φ ∂q3 Z ∂q3 Z (3.91)
39 The second Hodge dual gives
Z ∂ ∂χ Z ∂ 1 ∂χ Z ∂ ρ ∂χ ∗d ∗ dχ = ρZ + + , ρ ∂ρ ∂ρ ρ ∂φ Zρ ∂φ ρ ∂q3 Z ∂q3 Z 1 = Z2χ + (Z + ρZ ) χ + χ + χ (3.92) ,ρρ ρ ,ρ ,ρ ρ2 ,φφ ,33
Z2 1 ∇2χ = Z2χ + + ZZ χ + χ + χ . (3.93) ,ρρ ρ ,ρ ,ρ ρ2 ,φφ ,33
Now that the Laplacian is derived, we use it to derive equation 13 in Ref. [3].
Z 1 ∇2χ = Z2χ + Z + Z χ + χ + χ = ∇2χ + χ , (3.94) ,ρρ ρ ,ρ ,ρ ρ2 ,φφ ,33 t ,33 where Z 1 ∇2χ = Z2χ + Z + Z χ + χ . (3.95) t ,ρρ ρ ,ρ ,ρ ρ2 ,φφ
2 2 Noting that, setting λ = G11 and µ = G22,
√ 2 1 h ij i ∇ χ = √ GG χ,j , G ,i 1 = G Gijχ + Gijχ + Gijχ , 2G ,i ,j ,i ,j ,ji 1 = GG Gijχ + Gijχ + Gijχ + G χ + χ , ,i ,j ,i ,j ,ji 2G ,3 ,3 ,33 1 G = G Gijχ + Gijχ + Gijχ + ,3 χ + χ . (3.96) 2G ,i ,j ,i ,j ,ji 2G ,3 ,33
Using the identity h √ i G ln G = ,3 , (3.97) ,3 2G
40 we have
2 √ 2 X 1 ij ij ij h i ∇ χ = GG,iG χ,j + G,i χ,j + G χ,ji + ln G χ,3 + χ,33, 2 ,3 i,j=1 1 ∂ µ 1 = χ + χ + χ + [ln (λµ)] χ + χ , λ2 ,ρρ ∂ρ λ ,ρ µ2 ,φφ ,3 ,3 ,33 2 = ∇t χ + [ln (λµ)],3 χ,3 + χ,33, 1 ∂ µ 1 = χ + χ + χ (3.98) λ2 ,ρρ ∂ρ λ ,ρ µ2 ,φφ
The differential form derivation shows
Z 1 ∇2χ = Z2χ + Z + Z χ + χ ,ρρ ρ ,ρ ,ρ ρ2 ,φφ 1 ∂ µ 1 = χ + χ + χ . (3.99) λ2 ,ρρ ∂ρ λ ,ρ µ2 ,φφ
1 So λ = Z and µ = ρ.
On the surface, q3 = 0 and the second fundamental form is
h11 = (0, 0,S,ρρ) · (−S,ρ cos φ, −S,ρ sin φ, 1) Z,
= ZS,ρρ, (3.100) and
h22 = (−ρ cos φ, −ρ sin φ, 0) · (−S,ρ cos φ, −S,ρ sin φ, 1) Z
= ρS,ρZ. (3.101)
The metric tensor on the surface is diagonal with components λ2, µ2 and is given
41 by
2 2 2 2 2 2 g11 = λ = |r,ρ| = cos φ + sin φ + S,ρ = 1 + S,ρ 1 = , (3.102) Z2
2 2 2 2 2 2 g22 = µ = |r,φ| = ρ sin φ + ρ cos φ
= ρ2, (3.103) and
g33 = 1. (3.104)
The discriminant is √ ρ g = . (3.105) Z
The Laplacian derived using this method is
2 Z h ρ 2 i Z ρ 1 Z h ρ i ∇ χ = Z χ,ρ + 2 χ,φ + χ,3 , ρ Z ,ρ ρ Z ρ ,φ ρ Z ,3 Z 1 = [ρZχ ] + χ + χ , ρ ,ρ ,ρ ρ2 ,φφ ,33 Z 1 = Z2χ + Z + Z χ + χ + χ . (3.106) ,ρρ ρ ,ρ ,ρ ρ2 ,φφ ,33
As before, compare with the more general derivation
1 ∂ µ 1 ∇2χ = χ + χ + χ + χ (3.107) λ2 ,ρρ ∂ρ λ ,ρ µ2 ,φφ ,33 to get λ = 1/Z and µ = ρ.
From the first and second fundamental forms we can calculate the shape operator
42 and get the principal curvatures from that.
S,ρρZ 3 1 g22h11 0 2 0 S,ρρZ 0 α = − = − λ = − . (3.108) g ρS,ρZ S,ρZ 0 h22g11 0 µ2 0 ρ
Thus the principal curvatures are
S Z k = − ,ρ (3.109) 1 ρ and S k = − ,ρρ = −S Z3. (3.110) 2 λ3 ,ρρ
The Gaussian and mean curvatures are
S S Z4 K = k k = ,ρ ,ρρ , (3.111) 1 2 ρ
and Z S M = − ,ρ + Z2S . (3.112) 2 ρ ,ρρ
In the surrounding space, the metric tensor has additional components proportional to the distance from the surface and the principal curvatures. Hence
1 + q k λ = 3 2 , (3.113) Z and
µ = ρ (1 + q3k1) . (3.114)
3.1.2.3 Schr¨odingerequation
We finally derive the Schr¨odingerequation. From here, this is simply an appli- cation of Ref. [2]. Equations 17 through 26 in Ref. [3] is a derivation identical to
43 equations 6 through 15 in Ref. [2].
Equation 27 is straightforward,
" # 2 2 Z2 S ρS Z2 2 S S Z4 V = − ~ (H2 − K) = − ~ ,ρ + ,ρρ − ,ρ ,ρρ , D 2m 2m 4 ρ ρ ρ 2 Z2 4ρS S Z4 = − ~ S + ρS Z22 − ,ρ ,ρρ , 2m 4ρ2 ,ρ ,ρρ 4ρ2 2 Z2 = − ~ S2 + 2ρS S Z2 + ρ2S2 Z4 − 4ρS S Z2 , 2m 4ρ2 ,ρ ,ρ ,ρρ ,ρρ ,ρ ,ρρ 2 Z2 = − ~ S2 − 2ρS S Z2 + ρ2S2 Z4 , 2m 4ρ2 ,ρ ,ρ ,ρρ ,ρρ 2 Z2 = − ~ S − ρS Z22 . (3.115) 2m 4ρ2 ,ρ ,ρρ
The kinetic energy operator for a particle with only radial dependence is
2 2 Z2 − ~ ∇2ψ = − ~ Z2χ + + ZZ χ . (3.116) 2m 2m ,ρρ ρ ,ρ ,ρ
But
h 2 −12i 2 −32 3 Z,ρ = 1 + S,ρ = −S,ρS,ρρ 1 + S,ρ = −Z S,ρS,ρρ. (3.117) ,ρ
So
2 2 Z2 − ~ ∇2ψ = − ~ Z2χ + χ − Z4S S χ , 2m 2m ,ρρ ρ ,ρ ,ρ ,ρρ ,ρ 2 1 = − ~ Z2 χ + χ − Z4S S χ . (3.118) 2m ,ρρ ρ ,ρ ,ρ ,ρρ ,ρ
The Schr¨odingerequation for the surface in question is now ready for analysis.
44 3.1.3 Ley-Koo and Castillo-Animas (Ref. [4])
Ref. [4] takes a more straightforward approach. Rather than try to apply differen- tial geometry, it begins by defining the spheroidal coordinate system, and identifying the constants of the motion. Among them are two constants similar to a sphere’s an- gular momentum which are quantized using canonical quantization to form a quantum operator Λ.ˆ
While this approach works well for a particle confined to a sphere, this shows certain pitfalls (detailed below in chapter IV). The Laplace-Beltrami operator of the surface does not produce the same equation as the Laplace operator of the surround- ing space, although the two surfaces have similar qualities. The sphere hides these differences because the normal coordinate has a metric component equal to one, and the constant curvature of the surface nullifies the curvature energy shift. However, under certain conditions where the normal coordinate’s metric tensor element does have a value equal to one, this approach can be used as an unperturbed state for an additional curvature energy shift treated as a perturbation, described below.
The Hamiltonian operator is found to produce the prolate spheroidal wave equa- tion while the Λˆ operator produces a similar equation. The Hamiltonian is separated and the ξ component of the wavefunction is set to a constant value. The energy eigenvalues are then computed down to a parameter λ. The remaining eigenfunctions and energy levels are described by Ref. [25].
However, Ref. [4] then continues to derive the energy levels using the Λˆ operator. The method involves constructing a matrix of the operator in a basis of associated Legendre polynomials [26; 23] and diagonalizing it. The result is a representation of the wavefunction as a linear combination of spherical harmonics. A computer is used to numerically solve the eigenvalues for the various coefficients of the series and finding the intersections of the curves created by the parameters at various values with the straight lines identified with the energy levels from the Hamiltonian.
45 This method does not consider an energy shift due to curvature, and it handles the operator-ordering problem by using half of the anticommutator bracket. It has the advantage of relative simplicity compared to the differential geometric approach. However, it is questionable as to whether this equation is correct, as it is different from Refs. [2; 15; 5; 3].
3.1.3.1 Derivation of operators
The relevant operators of this quantum mechanical system in curved coordinates are
rˆi = ri, (3.119) X ∂rj 1 ∂ pˆ = −i , (3.120) j ~ ∂q h ∂q m m m m X ∂rj 1 ∂ ∂rj 1 ∂ pˆ2 = − 2 , (3.121) j ~ ∂q h ∂q ∂q h ∂q m,u m m m u u u
2 2 2 pˆ = −~ ∇ , (3.122) and
y z,m ∂ − z y,m ∂ hm ∂qm hm ∂qm ∂rj εijk ∂ ˆ X X z,m ∂ x,m ∂ lk =r ˆipˆjεijk = −i~ ri = −i~ x − z , (3.123) ∂q h ∂q hm ∂qm hm ∂qm i,j,m m m m m x y,m ∂ − y x,m ∂ hm ∂qm hm ∂qm
ˆ2 2 X ∂rj εijk ∂ ∂rv εuvk ∂ l = −~ ri ru . (3.124) ∂qm hm ∂qm ∂qw hw ∂qw ijkmuvw
3.1.3.2 Coordinate system
There are two angular momenta that combine to be a constant of motion for the prolate spheroid. [4] First define 2f as the distance between the two foci (which lie along the z-axis), and define r1 and r2 as the distance between a point and each respec-
46 Figure 3.2: Cross-section of Prolate Spheroid
tive focus. Figure 3.2 shows a diagram of this system. Then the prolate spheroidal coordinates are defined as [4] r + r ξ = 1 2 , (3.125) 2f r − r η = 1 2 , (3.126) 2f and φ, where ξ ∈ [1, ∞), η ∈ [−1, 1], and φ ∈ [1, 2π).
3.1.3.3 Invariants of the system
We next look for invariants in the system. For the free particle they are the energy, the z-component of the angular momentum, and a third not so immediately found. First define
l1 = r1 × p = (r + f) × p (3.127)
47 and
l2 = r2 × p = (r − f) × p. (3.128)
For a sphere, l1 = l2 and l · l is a constant of the motion. Therefore we look at l1 · l2. Taking its time derivative, we have
∂ ∂ {l · l } = {[(r + f) × p] · [(r − f) × p]} . (3.129) ∂t 1 2 ∂t
We can evaluate this using the identities
∂ ∂l ∂l {l · l } = 1 · l + l · 2 (3.130) ∂t 1 2 ∂t 2 1 ∂t
∂p and, because ∂t = 0, ∂ ∂f {f × p} = × p. (3.131) ∂t ∂t
Combining these we have
∂ ∂f ∂f {l · l } = × p · [(r + f) × p] − [(r − f) × p] · × p ∂t 1 2 ∂t ∂t ∂f = × p · (r × p − f × p − r × p − f × p) ∂t ∂f = × p · (−2f × p) ∂t ∂f = −2 × p · (f × p) ∂t = 0. (3.132)
Now that the time variation of this operator is known, we construct a quantum operator for it. Since we do not know which order is the correct order of operation,
48 we take the average of l1 · l2 and l2 · l1:
1 2Λˆ = [l · l + l · l ] ~ p 2 1 2 2 1 1 = {[(r + f) × p] · [(r − f) × p] + [(r − f) × p] · [(r + f) × p]} 2 1 = {(r × p + f × p) · (r × p − f × p) + (r × p − f × p) · (r × p + f × p)} 2 1 = {(r × p) · (r × p) + (f × p) · (r × p) − (r × p) · (f × p) − (f × p) · (f × p) 2 + (r × p) · (r × p) − (f × p) · (r × p) + (r × p) · (f × p) − (f × p) · (f × p)}
= 1/2 2kr × pk2 − 2kf × pk2
= l2 − kf × pk2. (3.133)
This can be further expanded noting that fx = fy = 0:
2 2 2 2 2 l − kf × pk = l − (−fzpy) − (fzpx)
2 = l − [fzpyfzpy + fzpxfzpx] . (3.134)
Before continuing, we note that f, being the distance between the foci, is just a constant. Therefore they can be pulled to the left:
2 2 2 2 2 2 2 l − kf × pk = l − fz py − fz px
2 2 2 2 = l − fz px + py
2 2 2 2 2 2 2 = l − fz px + py + pz + fz pz
2 2 2 2 2 2 2 2 2 = l − fx + fy + fz px + py + pz + fz pz
2 2 2 2 2 2 2 = l − f p + fx + fy + fz pz
ˆ2 2 2 2 = l − f pˆ − pˆz . (3.135)
49 3.1.3.4 Geometric constructions
The next step is to calculate the geometric constructions. These are the parame- √ terization vector, the unit vectors, the scale factors hi = gii, gradient and Laplacian, and finally the momentum operator and its square.
Letting r = (x (ξ, η, φ) , y (ξ, η, φ) , z (ξ, η, φ)), the geometry indicates that
x pξ2 − 1p1 − η2 cos φ y = f pξ2 − 1p1 − η2 sin φ , (3.136) z ξη
and
1 ˆeξ = (ˆexx,ξ + ˆeyy,ξ + ˆezz,ξ) , hξ 1 ˆeη = (ˆexx,η + ˆeyy,η + ˆezz,η) , hη 1 ˆeφ = (ˆexx,φ + ˆeyy,φ + ˆezz,φ) , (3.137) hφ
ˆ ˆ ˆ where ˆex,ˆey,ˆez are the Cartesian unit vectors i, j, and k, respectively.
The scale factors are
s ∂x2 ∂y 2 ∂z 2 fpξ2 − η2 hξ = + + = , ∂ξ ∂ξ ∂ξ pξ2 − 1 s ∂x2 ∂y 2 ∂z 2 fpξ2 − η2 hη = + + = , ∂η ∂η ∂η p1 − η2 s ∂x2 ∂y 2 ∂z 2 h = + + = fp(ξ2 − 1) (1 − η2). (3.138) φ ∂φ ∂φ ∂φ
50 These produce the gradient operator
X ˆei ∂ ˆeξ ∂ ˆeη ∂ ˆeφ ∂ ∇ = = + + h ∂q h ∂ξ h ∂η h ∂φ i i i ξ η φ ∂ ∂ ∂ 1 ∂ ∂ ∂ ∂ 1 ∂ = ˆex x + ˆey y + ˆez z + ˆex x + ˆey y + ˆez z ∂ξ ∂ξ ∂ξ hξ ∂ξ ∂η ∂η ∂η hη ∂η ∂ ∂ ∂ 1 ∂ + ˆex x + ˆey y + ˆez z ∂φ ∂φ ∂φ hφ ∂φ x,ξ ∂ + x,η ∂ + x,φ ∂ hξ ∂ξ hη ∂η hφ ∂φ = y,ξ ∂ + y,η ∂ + y,φ ∂ . (3.139) hξ ∂ξ hη ∂η hφ ∂φ z,ξ ∂ + z,η ∂ + z,φ ∂ hξ ∂ξ hη ∂η hφ ∂φ
However, (x, y, z) = (x(ξ, η, φ), y(ξ, η, φ), z(ξ, η φ)). The next step is therefore to calculate the Jacobian matrix and the coefficients of each of the above derivatives. The Jacobian matrix is √ √ 2 2 ξ √1−η cos φ −η √ξ −1 cos φ −pξ2 − 1p1 − η2 sin φ x,ξ x,η x,φ 2 2 √ξ −1 √1−η 1−η2 ξ2−1 J = y y y = f ξ √ sin φ −η √ sin φ pξ2 − 1p1 − η2 cos φ . ,ξ ,η ,φ 2 2 ξ −1 1−η z,ξ z,η z,φ η ξ 0 (3.140) Using equation (3.137), we can project the basis vectors onto the Cartesian basis as
√ √ 2 1−η2 ξ √1−η cos φ ξ √ cos φ ξ2−1 ξ2−η2 p 2 √ √ ξ − 1 1−η2 1−η2 ˆeξ = ξ √ sin φ = ξ √ sin φ , (3.141) p 2 2 2 ξ2 − η2 ξ −1 (√ξ −η ξ2−1 η √ η ξ2−η2
√ 2 −η √ ξ −1 cos φ √ξ2−η2 ξ2−1 ˆeη = −η √ sin φ , (3.142) 2 2 √ξ −η 1−η2 √ ξ ξ2−η2
51 −pξ2 − 1p1 − η2 sin φ − sin φ 1 p p ˆeφ = ξ2 − 1 1 − η2 cos φ = cos φ . (3.143) p(ξ2 − 1) (1 − η2) 0 0
The gradient operator is calculated to be
pξ2 − 1 ∂ p1 − η2 ∂ 1 ∂ ∇ = eξ + eη + eφ . (3.144) pξ2 − η2 ∂ξ pξ2 − η2 ∂η fp(ξ2 − 1) (1 − η2) ∂φ
When projected into Cartesian space it becomes
√ √ 2 2 ξ √ 1−η cos φ −η √ ξ −1 cos φ ξ2−η2 ξ2−η2 √ p 2 √ p 2 2 ξ − 1 ∂ 2 1 − η ∂ ∇ = ξ √ 1−η sin φ + −η √ ξ −1 sin φ 2 2 p 2 2 p √ξ −η ξ2 − η2 ∂ξ √ξ −η ξ2 − η2 ∂η ξ2−1 1−η2 √ η √ ξ ξ2−η2 ξ2−η2 − sin φ 1 ∂ + cos φ . (3.145) fp(ξ2 − 1) (1 − η2) ∂φ 0
When it is simplified and multiplied by −i~, it gives the momentum operator,
pˆ = −i ∇ √ √ √ √ ~ 2 2 2 2 ξ 1−η ξ −1 cos φ ∂ − η ξ −1 1−η cos φ ∂ − √ sin φ ∂ ξ2−η2 ∂ξ ξ2−η2 ∂η 2 2 ∂φ √ √ √ √ f (ξ −1)(1−η ) 2 2 2 2 = −i ξ 1−η ξ −1 sin φ ∂ − η ξ −1 1−η sin φ ∂ + √ cos φ ∂ . (3.146) ~ ξ2−η2 ∂ξ ξ2−η2 ∂η 2 2 ∂φ f (ξ −1)(1−η ) ξ2−1 ∂ 1−η2 ∂ η ξ2−η2 ∂ξ + ξ2−η2 ξ ∂η
This will be used in calculating the angular momentum and in the Λ operator. Its
52 square is
2 2 2 pˆ = −~ ∇ 2 1 ∂ ∂ ∂ ∂ = −~ ξ2 − 1 + 1 − η2 f 2 ξ2 − η2 ∂ξ ∂ξ ∂η ∂η ξ2 − η2 ∂2 + . (3.147) (ξ2 − 1) (1 − η2) ∂φ2
Another part of this that will be needed is the z-component of the momentum squared. It is
ξ2 − 1 ∂ ξ2 − 1 ∂ (ξ2 − 1) (1 − η2) ∂ ξ ∂ pˆ2 = − 2 η2 + η z ~ ξ2 − η2 ∂ξ ξ2 − η2 ∂ξ ξ2 − η2 ∂ξ ξ2 − η2 ∂η (1 − η2)(ξ2 − 1) ∂ η ∂ 1 − η2 ∂ 1 − η2 ∂ + ξ + ξ2 . ξ2 − η2 ∂η ξ2 − η2 ∂ξ ξ2 − η2 ∂η ξ2 − η2 ∂η (3.148)
This is used to construct the Hamiltonian operator.
3.1.3.5 Laplacian and Hamiltonian operator
Next we construct the Hamiltonian operator in prolate spheroidal coordinates. The Hamiltonian derives from the Laplacian. The Laplacian is given in Ref. [13] as
1 ∂ ∂ ∂ ∂ ξ2 − η2 ∂2 ∇2 = (ξ2 − 1) + (1 − η2) + , f 2(ξ2 − η2) ∂ξ ∂ξ ∂η ∂η (ξ2 − 1)(1 − η2) ∂φ2 (3.149) which is identical to the one given in Ref. [4].
The Laplacian is given by
1 ∂ h h ∂ ∂ h h ∂ ∂ h h ∂ ∇2 = η φ + ξ φ + ξ η . (3.150) hξhηhφ ∂ξ hξ ∂ξ ∂η hη ∂η ∂φ hφ ∂φ
53 Its derivation follows:
pξ2 − 1p1 − η2 ∇2 = × fpξ2 − η2fpξ2 − η2fpξ2 − 1p1 − η2 √ 2 2 f√ξ −η fp(ξ2 − 1) (1 − η2) ∂ 1−η2 ∂ √ 2 2 ∂ξ f√ξ −η ∂ξ ξ2−1 √ 2 2 f√ξ −η fp(ξ2 − 1) (1 − η2) ∂ ξ2−1 ∂ + √ 2 2 ∂η f√ξ −η ∂η 1−η2 √ √ 2 2 2 2 f√ξ −η f√ξ −η ∂ ξ2−1 1−η2 ∂ + ∂φ fp(ξ2 − 1) (1 − η2) ∂φ
(3.151)
pξ2 − 1p1 − η2 ∇2 = × fpξ2 − η2fpξ2 − η2fpξ2 − 1p1 − η2 " p p ! ∂ p f ξ2 − η2f (ξ2 − 1) (1 − η2) ∂ ξ2 − 1 ∂ξ p1 − η2fpξ2 − η2 ∂ξ ! ∂ p1 − η2fpξ2 − η2fp(ξ2 − 1) (1 − η2) ∂ + ∂η pξ2 − 1fpξ2 − η2 ∂η !# ∂ fpξ2 − η2fpξ2 − η2 ∂ + ∂φ p1 − η2pξ2 − 1fp(ξ2 − 1) (1 − η2) ∂φ 1 ∂ ∂ ∂ ∂ = f(ξ2 − 1) + f(1 − η2) f 3(ξ2 − η2) ∂ξ ∂ξ ∂η ∂η ∂ f(ξ2 − η2) ∂ + , (3.152) ∂φ (ξ2 − 1)(1 − η2) ∂φ which finally results in
1 ∂ ∂ ∂ ∂ ∂ ξ2 − η2 ∂ ∇2 = (ξ2 − 1) + (1 − η2) + . f 2(ξ2 − η2) ∂ξ ∂ξ ∂η ∂η ∂φ (ξ2 − 1)(1 − η2) ∂φ (3.153)
54 Multiplying by the Schr¨odingerfactor to get the Schr¨odingeroperator we have the Hamiltonian operator for a free particle:
2 Hˆ = ~ ∇2 p 2µ 2 1 ∂ ∂ ∂ ∂ ξ2 − η2 ∂2 = ~ (ξ2 − 1) + (1 − η2) + . 2µf 2 ξ2 − η2 ∂ξ ∂ξ ∂η ∂η (ξ2 − 1)(1 − η2) ∂φ2 (3.154)
3.1.3.6 Angular momentum operators
Now that the Hamiltonian is derived, the angular momentum operator is derived. A large amount of algebra shows shows that the angular momentum operator in the
ˆ ∂ z direction is simply Lz = −i~ ∂φ , while for x and y it is
" p 2 p 2 # ˆ ξ − 1 1 − η ∂ ∂ ξη cos φ ∂ Lx = −i~ f sin φ ξ − η − . ξ2 − η2 ∂η ∂ξ p(ξ2 − 1) (1 − η2) ∂φ (3.155) " p 2p 2 # ˆ 1 − η ξ − 1 ∂ ∂ ξη sin φ ∂ Ly = −i~ f cos φ η − ξ − . ξ2 − η2 ∂ξ ∂η p(ξ2 − 1) (1 − η2) ∂φ (3.156)
55 2 2 2 2 Combining these terms using L = Lx + Ly + Lzproduces the lengthy equation
( " pξ2 − 1p1 − η2 ∂ pξ2 − 1p1 − η2 ∂ ∂ L2 = − 2 f sin φ ξ f sin φ ξ − η ~ ξ2 − η2 ∂η ξ2 − η2 ∂η ∂ξ # ξη cos φ ∂ − p(ξ2 − 1) (1 − η2) ∂φ " #! ∂ pξ2 − 1p1 − η2 ∂ ∂ ξη cos φ ∂ −η f sin φ ξ − η − ∂ξ ξ2 − η2 ∂η ∂ξ p(ξ2 − 1) (1 − η2) ∂φ " ξη cos φ ∂ pξ2 − 1p1 − η2 ∂ ∂ − f sin φ ξ − η p(ξ2 − 1) (1 − η2) ∂φ ξ2 − η2 ∂η ∂ξ # ξη cos φ ∂ − p(ξ2 − 1) (1 − η2) ∂φ " " p1 − η2pξ2 − 1 ∂ p1 − η2pξ2 − 1 ∂ ∂ + f cos φ η f cos φ η − ξ ξ2 − η2 ∂ξ ξ2 − η2 ∂ξ ∂η # ξη sin φ ∂ − p(ξ2 − 1) (1 − η2) ∂φ " #! ∂ p1 − η2pξ2 − 1 ∂ ∂ ξη sin φ ∂ −ξ f cos φ η − ξ − ∂η ξ2 − η2 ∂ξ ∂η p(ξ2 − 1) (1 − η2) ∂φ " ξη sin φ ∂ p1 − η2pξ2 − 1 ∂ ∂ − f cos φ η − ξ p(ξ2 − 1) (1 − η2) ∂φ ξ2 − η2 ∂ξ ∂η ## ) ξη sin φ ∂ ∂2 − + . (3.157) p(ξ2 − 1) (1 − η2) ∂φ ∂φ2
This equation is so long as to be nearly useless unless one uses a computer algebra system such as Mathematica. However, it can be used in conjunction with the mo- mentum operator to derive a symmetry operator to the Hamiltonian. This operator, ˆ called Λp, is given by ˆ ˆ2 2 2 2 Λp = l − f (ˆp − pˆz). (3.158)
56 Plugging in equations (3.147) and (3.148), and simplifying gives
η2 ∂ ∂ ξ2 ∂ ∂ ξ2 + η2 − 1 ∂2 Λˆ = (ξ2 − 1) + (1 − η2) + . p ξ2 − η2 ∂ξ ∂ξ ξ2 − η2 ∂η ∂η (ξ2 − 1)(1 − η2) ∂φ2 (3.159)
This operator is a symmetry operator of the Hamiltonian.
3.1.3.7 Separation of variables
We begin by assuming that the wavefunction has the form
ψ(ξ, η, φ) = Ξ(ξ)H(η)Φ(φ), (3.160)
and then carrying out the process of separation of variables of the Schr¨odingerequa- tion, which results in
2 1 1 ∂ ∂Ξ 1 ∂ ∂H ~ (ξ2 − 1) + (1 − η2) 2µf 2 ξ2 − η2 Ξ ∂ξ ∂ξ H ∂η ∂η ξ2 − η2 1 ∂2Φ + = E, (3.161) (ξ2 − 1)(1 − η2) Φ ∂φ2
Letting 1 ∂2Φ = m2 (3.162) Φ ∂φ2 and 2k2 E = ~ , (3.163) 2µ
then we have
1 ∂ ∂Ξ 1 ∂ ∂H m2(ξ2 − η2) (ξ2 − 1) + (1 − η2) = f 2k2(ξ2−η2)− . (3.164) Ξ ∂ξ ∂ξ H ∂η ∂η (ξ2 − 1)(1 − η2)
57 Factoring the far right term gives
1 ∂ ∂Ξ 1 ∂ ∂H 1 1 (ξ2 − 1) + (1 − η2) = f 2k2(ξ2 − η2) − m2 + . Ξ ∂ξ ∂ξ H ∂η ∂η ξ2 − 1 1 − η2 (3.165) ˆ Adding λ − λ for the eigenvalue of the Λp and rearranging gives
1 ∂ ∂Ξ m2 (ξ2 − 1) − f 2k2ξ2 + − λ Ξ ∂ξ ∂ξ ξ2 − 1 1 ∂ ∂H m2 + (1 − η2) + f 2k2η2 + + λ = 0. (3.166) H ∂η ∂η 1 − η2
The separated equations are therefore
∂ ∂ m2 (ξ2 − 1) − f 2k2ξ2 + − λ Ξ = 0, (3.167) ∂ξ ∂ξ ξ2 − 1 and ∂ ∂ m2 (1 − η2) + f 2k2η2 + + λ H = 0. (3.168) ∂η ∂η 1 − η2
3.1.3.8 Solution of the separated system
Now that the equation is separated, we then seek to solve the resulting separated ODEs. The prolate spheroid is a surface of constant ξ; therefore we take as our boundary condition
Ξ(ξ) = Ξ(ξ0) = constant, (3.169)
and dΞ = 0. (3.170) dξ
The solution to the Ξ equation is therefore
2 2 2 2 m f k ξ0 + 2 − λ Ξ(ξ0) = 0, (3.171) ξ0 − 1
58 which reduces to 2 2 2 2 ~ k ~ 1 m Eλm = = 2 2 λ − 2 . (3.172) 2µ 2µ f ξ0 ξ0 − 1
This leaves the other equation:
∂ ∂ m2 (1 − η2) + f 2k2η2 + + λ H = 0. (3.173) ∂η ∂η 1 − η2
This is the spheroidal wave equation, and is well-documented (Ref. [25]). In that
reference, H(η) = Smn(c, η), where c = fk. The solutions are called prolate angular functions, come in two varieties, and have the form
∞ (1) X mn m Smn(fk, η) = dr (fk)Pm+r(η), (3.174) r=0,1
∞ (2) X mn m Smn (fk, η) = dr (fk)Qm+r(η), (3.175) s=−∞
m m where Pm+r(η) and Qm+r(η) are Legendre functions of the first and second kinds.
mn Derivation of the dr (fk) coefficients is lengthy and beyond the scope of this paper. There are several normalization schemes to choose from. The energy eigenvalues are determined from equation (3.172) by the intersections of 2 2 2 2 m λ = ξ0 k f + 2 (3.176) ξ0 − 1 and 2 2 2 2 2 2 m y(k f ) = ξ0 k f + 2 . (3.177) ξ0 − 1
Ref. [4] performs this calculation using a computer and produces plots of the curves produced by the equations above.
59
CHAPTER IV
Some Common Pitfalls
The non-relativistic quantum mechanics of particles constrained to curves and surfaces is a problem which occasionally finds its place in textbooks (e.g., Ref. [27]) and lecture notes. The simplest example is that of a particle moving on the surface of a sphere, and this problem is often mapped onto the rigid rotator problem. It is also of fundamental importance in the formal theory of quantum mechanics since it has been understood that the standard canonical quantization prescription in Cartesian coordinates breaks down in curved space[7]. The problem was probably first solved by Jensen and Koppe in 1971 [1], and clarified in more detail in the early nineteen eighties by da Costa [2].
Despite this, there are two mistakes that authors occasionally make when working in the field. For example, see Ref. [4], which assumes that the Schr¨odingerproblem can be constrained by simply holding one coordinate constant in the three-dimensional Schr¨odingerequation.
Both mistakes are possibly related to the simplicity and prevalence of the problem for a particle constrained to the surface of a sphere. The purpose of this chapter is to clarify the procedure to prevent these mistakes from being made in the future.
The first mistake, made in Ref. [4], is to assume that the Laplacian for the surface is simply the Laplacian of the three-dimensional problem with the term containing
61 the derivative with respect to the constrained coordinate removed, and setting it to a constant value throughout the remainder of the operator. It will be shown that this not the case, because removing one term from the metric tensor will change the determinant of the metric tensor, and therefore the Laplace-Beltrami operator as well. So while the metric tensor of the surface is a subspace of the metric tensor of the space it is imbedded in, the Laplace-Beltrami operator for the surface is sufficiently different from the Laplacian of its surrounding space to require the Laplace-Beltrami operator to be derived.
One special case is for a particle constrained to a sphere, for which the Laplace- Beltrami operator is the same as for full three-dimensional spherical coordinates with- out the radial term. This is because the metric is diagonal, and the constrained coordinate has a scale factor equal to one. Therefore the determinant remains the same.
The second mistake is to neglect the potential energy due to the curvature of the surface. It is shown in the literature [1; 2] that, when constraining a particle to an embedded surface, there is an effective potential energy well on that surface, dependent on its parameterization, that is generated by its curvature. Again, the particle constrained to the surface of a sphere is a special case, because the mean curvature squared minus the Gaussian curvature is zero, resulting in it safely being neglected from the equation. For most surfaces, this term is nonzero, so it cannot be neglected. Both mistakes will be worked out in more detail below.
62 4.1 Formulation of the Laplace-Beltrami Operator for the
Surface from the Laplace Operator of the Embedded Co-
ordinate System
Let M be a metric space in E3 and then let
3 x(Q): E → M : Q 7→ x. (4.1)
be a coordinate chart from Cartesian coordinates to M. The metric tensor of M is then ∂x ∂x G = · . (4.2) ij ∂Qi ∂Qj
If we now hold Q3 constant, we have a coordinate system q := (Q 1 , Q 2 ):(q 1 , q 2 ) and a parametrized surface N ⊂ E2 with N ∈ M and parametrization x(q): E3 → M : x(q) = (x(q), y(q), z(q)). The metric tensor of N is then
∂x ∂x g = · . (4.3) ij ∂q i ∂q j
From this we see that
Gij = gij : i, j = 1, 2. (4.4)
While the metric tensor of N is a subspace of the metric tensor of M, the com- ponent will generally produce a different metric discriminant. That is,
G := det[Gij] 6= det[gij] =: g. (4.5)
unless G33 = 1.
63 For orthogonal coordinate systems, in which Gij = 0 : i 6= j, we have
G = G33g. (4.6)
The Laplacian operator for M is defined as
3 X 1 ∂ √ ∂f ∇2f(Q) := √ GGij , (4.7) ∂Qi ∂Qj i,j=1 G while the Laplace-Beltrami operator for N is
2 X 1 ∂ √ ∂f ∇2 f(q) := √ ggij , (4.8) LB g ∂qi ∂qj i,j=1
2 2 Finally, ∇LBf(q) in terms of ∇ f(Q) is
2 1 ∂ √ ∂f X ∂G33 ∂f ∇2 f(q) = ∇2f(Q) − √ GG33 − Gij LB ∂Q3 ∂Q3 ∂Qi ∂Qi G i,j=1 2 1 X ∂ √ ∂f ∂ √ ∂f −√ GGi3 + GG3i . (4.9) ∂Qi ∂Q3 ∂Qi ∂Q3 G i=1
For orthogonal coordinate systems this becomes
2 X ∂G33 ∂f 1 ∂ √ ∂f ∇2 f(q) = ∇2f(Q) − Gij − √ GG33 . (4.10) LB ∂Qi ∂Qi ∂Q3 ∂Q3 i,j=1 G
Therefore it is not trivial to formulate the Laplace-Beltrami operator of the surface from the Laplacian of the coordinate system in which the surface is embedded.
4.2 The Effect of Curvature on Potential Energy
It is occasionally assumed that the Laplacian is the only component that needs to be modified for the Schr¨odingerequation. But it has been shown that there is an
64 effective potential induced by the curvature of the surface. This potential energy is
2 V = − ~ M 2 − K , (4.11) S 2µ where µ is the mass of the particle, M is the mean curvature, and K is the Gaussian curvature.
For a plane curve (such as a circular or elliptic ring), the effective potential is instead given by [18] 2 V = − ~ κ2, (4.12) D 8µ
where κ is the curvature, defined for a parametrization in Cartesian coordinates (x, y) as [14] |x0y00 − y0x00| κ = . (4.13) (x02 + y02)3/2
4.3 A Note on Spherical Coordinates
Spherical coordinates form a special case, and are noteworthy because they are central to discussion of angular momentum in nearly all quantum mechanics courses. It appears that the mistakes mentioned above happen because the sphere masks them.
For the sphere, the constrained coordinate is typically the radial coordinate r.
The full metric tensor for spherical coordinates is
1 0 0 2 Gij = 0 r 0 . (4.14) 0 0 r2 sin2 θ
65 When constraining the radial coordinate, this becomes
r2 0 gij = . (4.15) 0 r2 sin2 θ
Thus for the sphere, we have G = g and the constrained component is one and the constrained component is one. Therefore, for the sphere,
1 ∂ √ ∂f ∇2 f(θ, φ) = ∇2f(a, θ, φ) − √ G , (4.16) LB G ∂r ∂r which is simply the Laplace operator with the radial term removed. This produces the illusion that one can simply remove the constrained term from the Laplace operator to obtain a suitable Laplace-Beltrami operator for the surface.
The situation is compounded by the fact that, for a sphere of radius a,
1 1 V = M 2 − K = − = 0. (4.17) S a2 a2
Because of this triviality, the curvature term typically does appear in discussions of angular momentum in quantum mechanics textbooks. This means that the concept of potential energy from curvature is not as well known, and therefore often neglected.
4.4 On Separation Constants
One advantage of the two-dimensional Laplace-Beltrami approach, instead of ap- plying a function of constraint to the full three-dimensional Schr¨odingerequation, is that the two-dimensional approach produces two separated equations instead of three. This in turn produces one less constant of separation.
For closed surfaces like spheres, there will still be two quantum numbers in the final solution. One of the quantum numbers will appear as the constant of separation,
66 and the other will be hidden inside the energy term. For example, the spherical coordinate Schr¨odingerequation is traditionally solved with the orbital quantum number appearing in the radial equation [23]. In the two- dimensional case, the radial equation does not exist. The orbital quantum number instead appears when the constraint is applied that the wavefunction must be finite: the Legendre equation only has finite solutions for eigenvalues λ that satisfy
2mE λ = = l(l + 1). (4.18) ~2
Two common mistakes made when constraining particles to curved surfaces are examined and clarified. A comment is made regarding the simplicity of the problem of the particle constrained to the surface of a sphere. A table of metric tensors and Laplace-Beltrami operators for various coordinate systems and their constrained counterparts is listed.
67
CHAPTER V
Analysis of a Sphere
In this chapter, the sphere problem is derived rigorously and fully using the differ- ential geometric technique. The sphere is the simplest closed surface to solve for due to its symmetry and constant curvature. It is a standard problem covered in many quantum mechanics textbooks. It will be the first of three surfaces studied.
5.1 Analytical Solution
The parameterization of a sphere with radius a in spherical coordinates is
x a sin θ cos φ y = a sin θ sin φ . (5.1) z a cos θ
The Jacobian is a cos θ cos φ −a sin θ sin φ J = a cos θ sin φ a sin θ cos φ (5.2) −a sin θ 0
69 The associated metric tensor is
a2 0 gij = . (5.3) 0 a2 sin2 θ
The Laplace-Beltrami operator is
1 1 ∇2ψ = ∂ [sin θ∂ ψ] + ∂2ψ. (5.4) a2 sin θ θ θ a2 φ
The normal vector is a2 sin2 θ cos φ N = a2 sin2 θ sin φ . (5.5) a2 sin θ cos θ
Its norm is kNk = a2 sin θ. (5.6)
Therefore the unit normal vector is
sin θ cos φ n = sin θ sin φ . (5.7) cos θ
The Hessian matrix is
−a sin θ cos φ −a cos θ sin φ −a sin θ cos φ H = −a sin θ sin φ a cos θ cos φ −a sin θ sin φ . (5.8) −a cos θ 0 0
70 Therefore the second fundamental form is
−a 0 hij = . (5.9) 0 −a sin2 θ
This puts the Gaussian curvature at
h a2 sin2 θ 1 K = = = . (5.10) g a4 sin2 θ a2
The mean curvature is
1 a3 1 M = (g h + g h − 2g h ) = − = . (5.11) 2g 11 22 22 11 12 12 a4 a
Therefore M 2 − K = 0. (5.12)
Putting these elements together gives the Schr¨odingerequation
1 ∂2ψ cos θ ∂ψ 1 ∂2ψ 2µE + + = − ψ. (5.13) a2 ∂θ2 a2 sin θ ∂θ a2 sin2 θ ∂φ2 ~2
Multiply both sides by a2 sin2 θ to get
∂2ψ ∂ψ ∂ψ 2µE sin2 θ + sin θ cos θ + = −a2 sin2 θ ψ. (5.14) ∂θ2 ∂θ ∂φ2 ~2
This is slightly different from the traditional angular momentum derivation in that the energy is present rather than being separated out as part of the radial equation. Separating the variables gives
1 d2Θ 1 dΘ 2µE 1 d2Φ sin2 θ + sin θ cos θ + a2 sin2 θ = − = m2. (5.15) Θ dθ2 Θ dθ ~2 Φ dφ2
71 where m is a separation constant. These become
d2Θ dΘ 2µE sin2 θ + sin θ cos θ + a2 sin2 θ Θ = m2Θ, (5.16) dθ2 dθ ~2 and d2Φ = −m2Φ. (5.17) dφ2
Equation (5.17) has the solution
Φ(φ) = Aeimφ + Be−imφ. (5.18)
Equation (5.16) is
d2Θ dΘ 2µa2E sin2 θ + sin θ cos θ + sin2 θΘ = m2Θ. (5.19) dθ2 dθ ~2
This is Legendre’s differential equation,
d2Θ dΘ sin2 θ + sin θ cos θ + λ sin2 θΘ = m2Θ, (5.20) dθ2 dθ with 2µa2E λ = . (5.21) ~2
To ensure that solutions are nonsingular for integer m we must have the identity
λ = l(l + 1) : l ∈ N. (5.22)
The solution is then the associated Legendre polynomials, which we expected:
m Θ(θ) = APl (cos θ) . (5.23)
72 The associated Legendre functions of the second kind have singularities present, and so are not part of the solution. Combining this with Φ gives
m imφ −imφ ψlm (θ, φ) = Pl (cos θ) Alme + Blme . (5.24)
The boundary conditions and the normalization constraint |ψ|2 = 1 result in the solution being the spherical harmonics:
m imφ ψlm (θ, φ) = AlmPl (cos θ) e = Ylm (θ, φ) . (5.25)
This is the standard solution covered in most quantum mechanics textbooks.
5.2 Shell Method
The sphere was used to calibrate calculations using the shell squeezing method. This method removes the singularities by working with a three-dimensional volume problem in Cartesian coordinates. Thus it is hoped that the method will yield the correct energy levels and remove any ambiguity as to which method is correct.
5.2.1 Summary of the method
Throughout this section, energy given by an E or are given in electron volts and
2 ~ energy values given by an ε are given in units where 2m = 1. They are related by the equation 2mE ε = . (5.26) ~2
Furthermore, note that
2 ~ = 3.810099 eV · A˚. (5.27) 2m
73 The solution to the energy levels for a particle constrained to a sphere of radius a is l(l + 1) ε = . (5.28) a2
Ref. [1] shows that the energy of a particle constrained to a surface can be calculated from a particle constrained between two parallel surfaces separated by uniform distance d using the formula
π2 2 = lim E − ~ , (5.29) d→0 2Md2
and throwing out the singular term as being unphysical.
5.2.2 Calibration using the sphere
The first step was to calibrate a single set of concentric spheres to the analytical solution. The Schr¨odingerequation for a particle constrained to a spherical shell of inner radius a and outer radius b with no internal potential energy is a combination of a spherical well with a hard sphere inside it. The general solution is
∞ ∞ l X X X ψ(r, θ, φ) = [Anlmjn (knlr) + Bnlmyn(knl(r)] Ylm(θ, φ), (5.30) n=1 l=0 m=−l
where nπ k = . (5.31) nl b − a
The zeros of the spherical Bessel functions and spherical Neumann functions occur at integer multiples of π, hence the energy contribution from the radial component is identical to an infinite square well. Because the volume of interest does not include the origin and does not extend to infinity, we must keep both the spherical Bessel functions and spherical Neumann functions in the general solution. The solution is based on the moment of inertia of the classical shell of nonzero, finite thickness.
74 Table 5.1: Analytical Energy levels for concentric spheres n = 1, (a − b) l = 0, m = 0 1,1,0 1,1,−1 1,1,1 1,2,0 1,2,2 20 0.094010 0.095135 0.095135 0.095135 0.097383 0.097383 10 0.376042 0.377180 0.377180 0.377180 0.379457 0.379457
The moment of inertia for a spherical shell with inner radius a and outer radius b is [28] 2 b5 − a5 I = M . (5.32) 5 b3 − a3
Two values that are needed are shown in Table 5.1.
Combining the equation 2k2 E = ~ , (5.33) nl 2I
with the equation
2 kl = l(l + 1), (5.34)
produces the formula 2 (b3 − a3) E = 5 ~ l(l + 1) . (5.35) l M (b5 − a5)
FEMLAB was used to calculate the solution for a particle constrained to move between two concentric spherical shells, one with radius 110 Aand˚ one with radius 90 A.˚ These were then moved closer together by 5 Aeach.˚ The energy levels calculated by FEMLAB agree with the analytical solution to within (−0.7 ± 0.6)%. These are given in Table 5.2.
Further convergence to the analytical value of 0.376042 eV is shown in Table 5.3 for spheres 10 Aapart˚ by the number of mesh refinements. Beyond two refinements, the calculation time neared one hour for one pair of shells. At three refinements for the 110 Aand˚ 95 Apair,˚ there were over three hundred thousand degrees of freedom in the finite element system. The eigenfunction closely resembled the spherical harmonics, with only the lowest order Bessel functions contributing to the radial portions.
75 Table 5.2: FEMLAB Energy levels for concentric spheres n = 1, Refinements a − b l = 0, m = 0 1,1,0 1,1,−1 1,1,1 1,2,0 1,2,2 0 20 0.0954 0.0964 0.0964 0.0964 0.0984 0.0985 1 20 0.0949 0.0957 0.0958 0.0958 0.0974 0.0974 2 20 0.0944 0.0952 0.0952 0.0952 0.0967 0.0968 0 10 0.3812 0.3823 0.3824 0.3824 0.3846 0.3847 1 10 0.3801 0.3809 0.3810 0.3810 0.3826 0.3826 2 10 0.3784 0.3791 0.3792 0.3792 0.3806 0.3807 3 10 0.3772 0.3779 0.3779 0.3780 0.3794 0.3794
Table 5.3: Convergence of FEMLAB runs on concentric spheres by refinements Refine- Degrees of Calculation Calculated Absolute Relative ments freedom Time (s) energy Error Error 0 13995 13.516 0.381196 −0.005154 −1.37% 1 36948 99.844 0.380061 −0.004019 −1.07% 2 103927 662.922 0.378353 −0.002311 −0.61% 3 301380 3036.328 0.377162 −0.00112 −0.30%
5.2.3 Varying the distance between the spheres
Five sets of two concentric spherical shells were constructed in FEMLAB with a mean radius of 100 Ain˚ each set. These shells were treated as infinite barriers which the particle could not escape, i.e., given two concentric shells of radii a and b, ψ(a) = ψ(b) = 0. Each set of concentric spheres used different values of a and b while keeping their average constant. Energy levels were noted for each set of spheres.
Once the energy levels were tabulated, they were placed in Excel and plotted, and a linear trendline was added to the plot using d−2 as the linear component. This produced a fit of the form B ε = + A. (5.36) tot d2
In all runs, B ≈ π2, indicating a good fit, and A is the energy (in units of ε) of the constrained particle, because it is the only term that is not divergent as d → 0.
Table 5.4 shows the total energy levels by d for the analytical solution and for the numerical runs, respectively, with the coefficients of the fits for each below them
76 Table 5.4: The Sphere Total Energy d Calculated Analytical ε00 20 0.024914 0.024674 ε00 40 0.006180 0.006169 ε00 60 0.002743 0.002742 ε00 80 0.001542 0.001542 ε00 100 0.000987 0.000987 ε10 20 0.025122 0.024874 ε10 40 0.006383 0.006369 ε10 60 0.002950 0.002942 ε10 80 0.001755 0.001742 ε10 100 0.001207 0.001187 ε11 20 0.025128 0.024874 ε11 40 0.006384 0.006369 ε11 60 0.002950 0.002942 ε11 80 0.001755 0.001742 ε11 100 0.001207 0.001187 A00 -0.000 0.000000 A10 0.0002 0.00020 A11 0.0002 0.00020 B00 π2 1.01 1 B10 π2 1.01 1 B11 π2 1.01 1
(listed as Aij and Bij/π). The convergence of the ground state is shown in this table.
It can be seen that the value for A00 = 0 Therefore, the shell method works well for the sphere to about three digits of accuracy.
5.2.4 Calibration using a finite cylinder
Let us now consider the finite cylinder as another test case of the shell squeezing technique. Reference [80] lists the energy of a particle with mass m constrained to a hollow cylinder with thickness 2, radius R, and length L as
" # 2 nπ 2 kπ 2 4l1 − 1 E = ~ + + (1 + δ) , (5.37) HC 2m 2 L 4R2
77 Table 5.5: Fit values for energy in the surface limit for a cylinder using the shell method l ∆EDG ∆EHC ∆EHC − ∆EDG δ 0 −0.25 −0.000 0.250 −0.999 1 0.75 0.660 −0.090 −0.119 1 0.75 0.659 −0.091 −0.122 2 3.75 3.824 0.074 0.020 2 3.75 3.821 0.071 0.019 3 8.75 8.563 −0.187 −0.021
where l ∈ N is a quantum number and δ is the error of the numerical solution of the 3-D equation and the differential geometric dimensional reduction method. The authors of Ref. [80] found that for their runs, for the n = 1 state, δ = 3.9 × 10n, where n = −9 for = 10−4, −7 for = 10−3, −5 for = 10−2, and −3 for = 10−1. Thus it was found in that reference that the differential geometric approach had good agreement with the numerical calculation.
FEMLAB was used to calculate both δ and to use the shell squeezing method to approximate the energy using the form
A E = + C. (5.38) (2)2
At the limit → 0, only the C term remains finite and thus the divergent term is thrown out as being unphysical. Thus this corresponds to the energy of the particle
constrained to the surface. The results (in units where ~/2m = 1) are listed in Table 5.5. Numerical simulation did not reproduce the negative energy shift predicted by the differential geometric method. However, the shift was simulated for the excited states. The reason for this is unknown. The calculations produced an maximum error of 0.18 from the differential geometric method and are shown in Figure 5.1.
78 Figure 5.1: Overlay of shell method energy levels for cylinders with Differential Geo- metric analytical values
5.3 Summary
The sphere was shown to have an analytical solution and zero curvature term. The shell method was introduced and shown to agree with the sphere, but to disagree with the finite cylinder for the ground state and agree with it for the excited states. The reason for the zero ground state for the cylinder is unknown. However, this technique will be used again later when the spheroid and ellipsoid are studied.
79
CHAPTER VI
Analysis of the Prolate and Oblate Spheroids
In this chapter, the symmetry of the sphere is relaxed and prolate and oblate spheroids are studied. It should be noted that the technique used in some refer- ences such as Ref. [4] produces different results because the problem is solved as a three-dimensional problem with one component of the separated wavefunction held constant. Thus the energy shift due to curvature is neglected. This results in a ground state with zero energy, whereas the curvature prohibits this when using the two-dimensional equation. The goal of this chapter is to derive the two-dimensional equation and find its solutions. These are compared with Cantele’s work (Ref. [5]), which is shown to be equivalent.
6.1 Formulation of Schr¨odingerEquation
6.1.1 Fundamental forms and Laplace operator
The parameterization of the prolate spheroid is
fpξ2 − 1p1 − η2 cos φ r = fpξ2 − 1p1 − η2 sin φ . (6.1) fξη
81 The Jacobian matrix is √ 2 −ηf √ξ −1 cos φ −fpξ2 − 1p1 − η2 sin φ √1−η2 ∂(x, y, z) 2 = −ηf √ξ −1 sin φ fpξ2 − 1p1 − η2 cos φ . (6.2) 2 ∂(η, φ) 1−η fξ 0
From this the metric tensor can be calculated. It is
2 2 f 2 ξ −η 0 1−η2 gij = . (6.3) 0 f 2(ξ2 − 1)(1 − η2)
Its determinant is g = f 4(ξ2 − η2)(ξ2 − 1). (6.4)
This is sufficient information to derive the tangential portion of the Laplace- Beltrami operator. It is
" 2 # 2 1 ∂ 1 − η ∂χt 1 ∂ χt D[χt(u, v)] = + f 2pξ2 − η2 ∂η pξ2 − η2 ∂η f 2(ξ2 − 1)(1 − η2) ∂φ2 1 − η2 ∂2χ η(η2 − 2ξ2 + 1) ∂χ = t + t f 2(ξ2 − η2) ∂η2 f 2(ξ2 − η2)2 ∂η 1 ∂2χ + t . (6.5) f 2(ξ2 − 1)(1 − η2) ∂φ2
The next object to calculate is the second fundamental form. This requires the Hessian matrix and the unit normal vector. The unit normal vector is √ 2 √1−η ξ cos φ √ξ2−1 1 2 n = − √1−η ξ sin φ , (6.6) 2 2 2 2 f (ξ − η ) ξ −1 η
82 and the Hessian matrix is √ 2 2 p 2 1 η ξ −1 p 2 p 2 −f ξ − 1 cos φ √ − 3 ηf √ sin φ −f ξ − 1 1 − η cos φ 2 2 2 1−η (1−η ) 2 √1−η 2 2 H = p 2 √ 1 η √ξ −1 p 2 p 2 . −f ξ − 1 sin φ − 3 ηf cos φ −f ξ − 1 1 − η sin φ 1−η2 (1−η2) 2 1−η2 0 0 0 (6.7)
With these values calculated, the second fundamental form can be calculated. It is ξ(1−3η2) f(ξ2−η2)(1−η2) 0 hij = . (6.8) (1−η2)ξ 0 f(ξ2−η2)
Its determinant is ξ2(1 − 3η2) h = . (6.9) f 2(ξ2 − η2)2
With the fundamental forms calculated, the curvatures can be derived.
6.1.2 Mean and Gaussian curvatures
The mean curvature is
ξ 1 (1 − η2)2 M = + , (6.10) 2f 3(ξ2 − η2) ξ2 − 1 ξ2 − η2
and the Gaussian curvature is
ξ2(1 − 3η2) K = . (6.11) f 6(ξ2 − η2)3(ξ2 − 1)
These combine to form the effective potential
2 ξ2 (η2 − 1)4 + 1 η2(2η2 − 1) + 1 V = − ~ + . (6.12) S 2µ 4f 6(ξ2 − 1)(ξ2 − η2)2 ξ2 − 1 ξ2 − η2
Figure 6.1 plots M 2 − K as a function of η for the case f = 2.2, ξ = 1.1. Thus the
83 Figure 6.1: η component M 2 − K for a prolate spheroid with f = 2.2, ξ = 1.1
potential is attractive at the poles. Figure 6.2 shows a three-view plot of this value.
We are now ready to formulate the Schr¨odingerequation.
6.1.3 Formulation and separation of the Schr¨odingerequation
The full Schr¨odingerequation for a particle constrained to the surface of a prolate spheroid is
" # 1 ∂ 1 − η2 ∂χ 1 ∂2χ t + t f 2pξ2 − η2 ∂η pξ2 − η2 ∂η f 2(ξ2 − 1)(1 − η2) ∂φ2 ξ2 (η2 − 1)4 + 1 η2(2η2 − 1) + 1 + + χ 4f 6(ξ2 − 1)(ξ2 − η2)2 ξ2 − 1 ξ2 − η2 t 2 = −k χt, (6.13) where k2 = 2mE . ~2
This equation, although formidable, is separable. Let χt(η, φ) = H(η)Φ(φ). Then
84 Figure 6.2: (Color in electronic version) M 2 − K for a prolate spheroid with f = 2.2, ξ = 1.1
85 equation (6.13) becomes
1 (ξ2 − 1)(1 − η2)2 d2H 1 (1 − η2)2 η(1 − η2) dH + (ξ2 − 1) − 2 + H ξ2 − η2 dη2 H (ξ2 − η2)2 ξ2 − η2 dη ξ2(1 − η2) (η2 − 1)4 + 1 η2(2η2 − 1) + 1 2µE + + f 2(1 − η2)(ξ2 − 1) 4f 4(ξ2 − η2)2 ξ2 − 1 ξ2 − η2 ~2 1 ∂2Φ = − = m2 (6.14) Φ ∂φ2
This separates into the equations
1 − η2 d2H 1 1 − η2 dH + − 2η f 2(ξ2 − η2) dη2 f 2(ξ2 − η2) ξ2 − η2 dη ξ2 1 − η2(1 − 2η2) + 1 + (1 − η2)4 + 4f 6(ξ2 − 1)(ξ2 − η2)2 ξ2 − η2 m2 2µE + H = − H, (6.15) f 2(ξ2 − 1)(1 − η2) ~2 and d2Φ = −m2Φ. (6.16) dφ2
Since equation 6.16 is nearly trivial, we will solve it first. It is
imφ −imφ Φ(φ) = Ae + Be : m ∈ Z, (6.17) where A and B are constants.
This leaves the H(η) equation. This will be shown to be identical with equation (24) from Ref. [5], which was solved numerically using the shooting method and the software package NAG.
86 6.2 Equivalence of the Two-Dimensional Equation with Ref.
[5]
We now turn to duplicate the results of Ref. [5] using the full two-dimensional equation, equation (6.13). To do so, we must first prove that it is equivalent to the equation used in that reference.
6.2.1 Statement of the problem
Given the map
x fpξ2 − 1p1 − η2 cos φ a sin θ cos φ y = fpξ2 − 1p1 − η2 sin φ = a sin θ sin φ , (6.18) z fξη c cos θ
where a = f sinh α and c = f cosh α for α ≥ 0, [13] show that the (ξ, η, φ) equation
1 − η2 ∂2σ (ξ2 − η2) + (ξ2 − 1) ∂σ 1 ∂2σ − η + f 2(ξ2 − η2) ∂η2 f 2(ξ2 − η2)2 ∂η f 2(ξ2 − 1)(1 − η2) ∂φ2 ξ2 (η2 − 1)4 + 1 η2(2η2 − 1) + 1 + + σ 4f 6(ξ2 − 1)(ξ2 − η2)2 ξ2 − 1 ξ2 − η2 = −εSσ, (6.19)
is equivalent to
2 r 2 2 1 ∂ σ 1 ∂ g22 ∂σ 1 ∂ σ T 2m S S − 2 − √ − 2 − − D σ = 2 E − En σ, g11 ∂θ g11g22 ∂θ g11 ∂θ g22 ∂φ 4 ~ (6.20) where
2 2 2 2 g11 = a cos θ + c sin θ, (6.21)
2 2 g22 = a sin θ, (6.22)
87 c χ = , (6.23) a f e = , (6.24) c 2m(ES − ES) εS = n , (6.25) ~2 and m(1 + χ2 tan2 θ) mS(θ) = (6.26) χ2(1 + tan2 θ)
under the transform a2 cos2 θ + c2 sin2 θ1/4 σ = t(θ). (6.27) a2 sin2 θ
6.2.2 Choice of substitution
Inspection of equation (6.18) shows some similarities between the prolate spheroidal coordinates and the spherical coordinates. Specifically, the coordinate charts reduce to p p ξ2 − 1 1 − η2 = sinh α sin θ (6.28) and ξη = cosh α cos θ, (6.29) which cannot be analytically solved. However, there are similarities in domains: ξ > 1, α > 1, η ∈ [−1, 1], and θ ∈ [0, 2π]. We also note that cos θ ∈ [−1, 1]. By applying intuition to the coordinate domains, we find that ξ roughly corresponds to α and η to θ. Therefore we propose the relationships
p ξ2 − 1 = sinh α, (6.30)
ξ = cosh α, (6.31)
p 1 − η2 = sin θ, (6.32)
88 η = cos θ. (6.33)
Trying this map gives cosh2 α − sinh2 α = 1 (6.34)
sin2 θ + cos2 θ = 1. (6.35)
These are just the Pythagorean Theorem for hyperbolic functions and Euler’s identity, respectively. Therefore this system is consistent and might work.
6.2.3 Proof of equivalence
Begin with equation (6.20) and let M = T , K = D, and εS = 2m (ES −ES). Then 2 ~2 n
1 1 ∂2σ a2 cos θ ∂σ 1 ∂2σ − − − a2 cos2 θ 1 + χ2 tan2 θ ∂θ2 sin θ a2 cos2 θ + c2 sin2 θ2 ∂θ a2 sin2 θ ∂φ2 − M 2 − K σ = εSσ (6.36)
c Using the change of variables η = cos θ, ξ = cosh α = f , then
1 − η2 = sin2 θ, (6.37)
a2 c2 ξ2 − 1 = sinh2 α = = − 1, (6.38) f 2 f 2 1 − η2 = tan2 θ, (6.39) η2 a2 c2 a2 c2 ξ2 − η2 = + sin2 θ = − cos2 θ = + ξ2 − 1 = − η2, (6.40) f 2 f 2 f 2 f 2
a2 = f 2(ξ2 − 1) (6.41) and f 2 + a2 = c2. (6.42)
89 Finally, f 2 + 1 = χ2. (6.43) a2
The derivatives are ∂ ∂η ∂ p ∂ = = − 1 − η2 , (6.44) ∂θ ∂θ ∂η ∂η ∂ 1 ∂ = − , (6.45) ∂η sin θ ∂θ ∂2 ∂η ∂ ∂η ∂ ∂η ∂2 ∂η ∂2η ∂ = = ( )2 + , (6.46) ∂θ2 ∂θ ∂η ∂θ ∂η ∂θ ∂η2 ∂θ ∂θ2 ∂η
∂2 ∂2 ∂ = (1 − η2) + η . (6.47) ∂θ2 ∂η2 ∂η and ∂2 1 ∂2 2 ∂ = + (6.48) ∂η2 sin2 θ ∂θ2 sin3 θ tan θ ∂θ
Plugging in all of these substitutions into equation (6.36) gives
1 1 ∂2 ∂ − (1 − η2) + η f 2(ξ2 − 1)η2 h f 2 1−η2 i ∂η2 ∂η 1 + f 2(ξ2−1) + 1 η2 f 2(ξ2 − 1)η p ∂ − − 1 − η2 p1 − η2 {f 2(ξ2 − 1)η2 + [f 2 + f 2(ξ2 − 1)] (1 − η2)}2 ∂η 1 ∂2σ − − (M 2 − K)σ = εSσ (6.49) f 2(ξ2 − 1)(1 − η2) ∂φ2
Cleaning this up gives
1 − η2 ∂2σ η ξ2 − 1 ∂σ 1 ∂2σ − + − 1 − f 2(ξ2 − η2) ∂η2 f 2(ξ2 − η2) ξ2 − η2 ∂η f 2(ξ2 − 1)(1 − η2) ∂φ2 −(M 2 − K)σ = εSσ. (6.50)
Thus the first and third terms are proved. All that remains is to show that the
90 curvatures are equal and that
η ξ2 − 1 η [(ξ2 − η2) + (ξ2 − 1)] − 1 = − (6.51) f 2(ξ2 − η2) ξ2 − η2 f 2(ξ2 − η2)2
This means that we need to prove
ξ2 − 1 (ξ2 − η2) + (ξ2 − 1) − 1 = (6.52) ξ2 − η2 ξ2 − η2
Observe that
ξ2 − 1 + ξ2 − η2 (ξ2 − η2) + (ξ2 − 1) − 1 = (6.53) ξ2 − η2 ξ2 − η2
Therefore equation (6.19) and equation (6.20) are equivalent up to the Laplace- Beltrami operator. Unfortunately, Ref. [5] does not give the formulas for the cur- vatures. However, they can be derived, so the two equations can be proved. The Jacobian of the spherical coordinate representation of equation (6.18) is
a cos θ cos φ a sin θ sin φ ∂(x, y, z) = a cos θ sin φ −a sin θ cos φ , (6.54) ∂(θ, φ) −c sin θ 0
with Hessian matrix
−a sin θ cos φ a cos θ sin φ a sin θ cos φ H = −a sin θ sin φ −a cos θ cos φ a sin θ sin φ . (6.55) −c cos θ 0 0
91 The normal vector is
(−a sin θ cos φ)(−c sin θ) − (a cos θ sin φ)(0) N = (0)(a cos θ cos φ) − (a sin θ sin φ)(−c sin θ) , (6.56) (a sin θ sin φ)(a cos θ sin φ) − (a cos θ cos φ)(−a sin θ cos φ) which simplifies to ac sin2 θ cos φ N = ac sin2 θ sin φ . (6.57) a2 sin θ cos θ
Its norm is p N = a c2 sin4 θ + a2 sin2 θ cos2 θ. (6.58)
The metric tensor is given by equations (6.21) and (6.22). The second fundamental form is −ac sin θ hθθ = √ , (6.59) c2 sin4 θ + a2 sin2 θ cos2 θ acsin3θ hφφ = √ , (6.60) c2 sin4 θ + a2 sin2 θ cos2 θ
hθφ = 0, (6.61)
and its determinant is −a2c2 sin4 θ h = . (6.62) c2 sin4 θ + a2 sin2 θ cos2 θ
The metric discriminant is its square root,
g = a2 sin2 θ(a2 cos2 θ + c2 sin2 θ). (6.63)
Therefore the Gaussian curvature is
χ2 K = − , (6.64) a2 sin4 θ(cot2 θ + χ2)2
92 and the Mean curvature is
χ(χ2 − 1) 1 M = 3 . (6.65) 2a sin θ (cot2 θ + χ2) 2
Now that the mean and Gaussian curvatures have been calculated, Theorem (A.76) and Theorem (A.79) from section A can be used to transform equations (6.64) and (6.65). The Jacobian matrix for transforming from prolate spheroidal coordinates to spherical coordinates is − sin θ 0 J = . (6.66) 0 1
Therefore the metric tensor transforms as
g0 = g sin2 θ. (6.67)
The corresponding Hessian matrix is
− cos θ 0 0 H [u] = . (6.68) 0 0
Using these formulas in Theorem (A.76) and defining up as the p-th component of the parameterization in spherical coordinates and xp as the same component of the parameterization in spheroidal coordinates gives
0 h 0 p k e f i 0 a b g h h = (∂ 11u ) nk(∂px ) + J 1J 1hef (∂ 22u )nb(∂ax ) + J 2J 2hgh
0 c d i j 0 p q r s − (∂ 12u )nd(∂cx ) + J 1J 2hij [(∂ 12u )nq(∂px ) + J 1J 2hrs]
k 2 = − cos θnk(∂1x ) + sin θh11 [h22] . (6.69)
93 A closer look at the normal vector dotted with the η derivative shows
( p 2 p 2 k 1 fη ξ − 1 1 − η nk(∂1x ) = − − cos φ ξ cos φ f 2(ξ2 − η2) p1 − η2 pξ2 − 1 ) fηpξ2 − 1 p1 − η2 − sin φ ξ sin φ + fξη p1 − η2 pξ2 − 1 1 = − −fηξcos2φ − fηξsin2φ + fξη f 2(ξ2 − η2) 1 = − {−fηξ + fξη} f 2(ξ2 − η2) = 0. (6.70)
Filling this value in gives
0 2 h = h11h22 sin θ. (6.71)
Plugging into the definition of Gaussian curvature shows
h0 h h sin2 θ h K0 = = 11 22 = = K. (6.72) g0 g sin2 θ g
Therefore the Gaussian curvature is equivalent.
Next we check the mean curvature term. Plugging our coordinates into Theorem (A.79) gives
1 M 0 = sin2 θg n (∂0 um)(∂ xk) + h 2 sin2 θg 11 k 22 m 22 0 p k 2 +g22 nk(∂ 11u )(∂px ) + sin θh11 . (6.73)
Recalling that
0 m ∂ φφu = 0, (6.74) sin θ 0 p ∂ θθu = , (6.75) 0
94 and
k k nk∂1x = nη∂1x = 0 (6.76)
means that
1 1 M 0 = g h sin2 θ + g h sin2 θ = [g h + g h ] = M. (6.77) 2 sin2 θg 11 22 22 11 2g 11 22 22 11
Therefore the mean curvature is also invariant under this coordinate transform. It follows that equation (6.19) is equivalent to equation (6.20).
This ends the proof.
6.3 Derivation of Equation (24) in Ref. [5]
The next step is to derive equation (24) in Ref. [5] from the base metric. The Laplacian is given by
1 √ ∇2σ = √ ∂ gij g∂ σ g i j 1 √ 1 √ = √ ∂ g11 g∂ σ + √ ∂ g22 g∂ σ g 1 1 g 2 2 r r 1 g22 1 g11 = √ ∂1 ∂1σ + √ ∂2 ∂2σ g11g22 g11 g11g22 g22 1 1 1 g22 1 g11 = ∂1 [∂1σ] + ∂2 [∂2σ] + ∂1 ∂1σ + ∂2 ∂2σ, g11 g22 2g11g22 g11 2g11 g22 (6.78)
So the Schr¨odingerequation becomes
g11 g11 g22 1 g11 2 ∂1 [∂1σ] + ∂2 [∂2σ] + ∂1 ∂1σ + ∂2 ∂2σ + g11(M − K)σ = −g11εσ, g22 2g22 g11 2 g22 (6.79)
Now substitute ∂ ∂ = , (6.80) 1 ∂θ
95 ∂ ∂ = , (6.81) 2 ∂φ
and g 1/4 σ = 11 t(θ)eimφ. (6.82) g22
Then 3/4 1/4 1 g22 g11 g11 imφ ∂1σ = ∂1 t + ∂1te , (6.83) 4 g11 g22 g22
3/4 1/4 1 g22 g11 g11 imφ ∂1 [∂1σ] = ∂1 ∂1 t + ∂1te , (6.84) 4 g11 g22 g22 and
( 1/4 " 3/4 3/4 # g11 1 g22 g11 1 g22 g11 ∂1[∂1σ] = ∂1∂1t + ∂1 + ∂1 ∂1t g22 4 g11 g22 4 g11 g22 " 1/4 3/4 # ) 1 3 g11 g22 g11 g22 g11 imφ + ∂1 ∂1 + ∂1∂1 t e . 4 4 g22 g11 g22 g11 g22 (6.85)
Since g11 and g22 do not depend on φ,
1/4 g11 imφ ∂2σ = im te , (6.86) g22
and 1/4 2 g11 imφ ∂2[∂2σ] = −m te , (6.87) g22
96 and we get
( " 3/4 1/4 3/4 # 1 g11 g11 g22 g11 g22 g11 ∂1 ∂1 + ∂1∂1 t(θ) 4 g22 g22 g11 g22 g11 g22 " 3/4 # 1/4 1/4 ) 1 g22 g11 g11 g11 imφ + ∂1 ∂1t(θ) + ∂1 ∂1t + ∂1∂1t e 4 g11 g22 g22 g22 g g 1/4 −m2 11 11 t(θ)eimφ g22 g22 ( 3/4 1/4 ) g11 g22 1 g22 g11 g11 imφ + ∂1 ∂1 t(θ) + ∂1t e 2g22 g11 4 g11 g22 g22 1/4 1/4 1 g11 g11 imφ 2 g11 imφ +im ∂2 t(θ)e + g11(M − K) t(θ)e 2 g22 g22 g22 1/4 g11 imφ = −g11ε t(θ)e . (6.88) g22
Cleaning up gives
1 g22 g11 1 g11 g22 ∂1∂1t + ∂1 + ∂1 ∂1t(θ) 2 g11 g22 2 g22 g11 5 g22 g11 1 g22 g11 2 g11 2 + ∂1 ∂1 + ∂1∂1 − m + g11(M − K) t(θ) 16 g11 g22 4 g11 g22 g22
= −εg11t(θ). (6.89)
Focusing on the first derivative term,
g11 g22∂1g11 − g11∂1g22 ∂1 = 2 , (6.90) g22 (g22) and g22 g11∂1g22 − g22∂1g11 ∂1 = 2 . (6.91) g11 (g11)
97 So
g22 g11 g11 g22 ∂1 + ∂1 g11 g22 g22 g11 g11g22g22∂1g11 g11g22g22∂1g11 g11g11g22∂1g22 g11g11g22∂1g22 = 2 2 − 2 2 + 2 2 − 2 2 (g11) (g22) (g11) (g22) (g11) (g22) (g11) (g22) = 0. (6.92)
Therefore
5 g22 g11 ∂1∂1t + ∂1 ∂1 + 16 g11 g22 1 g22 g11 2 2 g11 ∂1∂1 + g11(M − K) − m t(θ) = −εg11t(θ). (6.93) 4 g11 g22 g22
Now, we have to calculate several values that will be used the next few steps:
1 cos2 θ = , (6.94) 1 + tan2 θ
tan2 θ sin2 θ = , (6.95) 1 + tan2 θ −a sin θ cos φ ∂θφx −a sin θ cos φ H = −a sin θ sin φ ∂ φy −a sin θ sin φ , (6.96) θ −c cos θ ∂θφz 0
√χ tan θ cos φ 1+χ2 tan2 θ n = √χ tan θ sin φ , (6.97) 2 2 1+χ tan θ √ 1 1+χ2 tan2 θ
c2(1 + χ2 tan2 θ) g = a2 cos2 θ + c2 sin2 θ = , (6.98) 11 χ2(1 + tan2 θ)
c2 tan2 θ g = a2 sin2 θ = , (6.99) 22 χ2(1 + tan2 θ)
98 c cos θ(tan2 θ + 1) −cp(1 + tan2 θ) h11 = − = , (6.100) p1 + χ2 tan2 θ p1 + χ2 tan2 θ
−c sin θ tan θ −c tan2 θ h22 = = √ , (6.101) p1 + χ2 tan2 θ p1 + χ2 tan2 θ 1 + tan2 θ
c2 tan2 θ h = , (6.102) 1 + χ2 tan2 θ c4 tan2 θ(1 + χ2 tan2 θ) g = , (6.103) χ4 (1 + tan2 θ)2
c2 tan2 θ χ4(1 + tan2 θ)2 χ4(1 + tan2 θ)2 K = = , (6.104) 1 + χ2 tan2 θ c4 tan2 θ(1 + χ2 tan2 θ) c2(1 + χ2 tan2 θ)2
1 M = (g h + g h ) 2g 11 22 22 11 " 1 χ4(1 + tan2 θ)2 c2(1 + χ2 tan2 θ) −c tan2 θ = √ 2 c4 tan2 θ(1 + χ2 tan2 θ) χ2(1 + tan2 θ) p1 + χ2 tan2 θ 1 + tan2 θ √ # c2 tan2 θ (−c 1 + tan2 θ) + χ2(1 + tan2 θ) p1 + χ2 tan2 θ √ χ2 1 + tan2 θ 1 + χ2 tan2 θ + 1 + tan2 θ = − , (6.105) 2cp1 + χ2 tan2 θ 1 + χ2 tan2 θ and
( √ )2 −χ2 1 + tan2 θ 1 + χ2 tan2 θ + 1 + tan2 θ χ4(1 + tan2 θ) M 2 − K = − 2cp1 + χ2 tan2 θ 1 + χ2 tan2 θ c2(1 + χ2 tan2 θ)2 χ4(1 + tan2 θ) = (1 + χ2 tan2 θ)2 + 2(1 + χ2 tan2 θ)(1 + tan2 θ) 4c2(1 + χ2 tan2 θ)3 4χ4(1 + tan2 θ) +(1 + tan2 θ)2 − 4c2(1 + χ2 tan2 θ)2 χ4(1 + tan2 θ)(1 + χ2 tan2 θ)2 2χ4(1 + tan2 θ)2(1 + χ2 tan2 θ) = + 4c2(1 + χ2 tan2 θ)3 4c2(1 + χ2 tan2 θ)3 χ4(1 + tan2 θ)3 4χ4(1 + tan2 θ + − 4c2(1 + χ2 tan2 θ)3. (6.106) 4c2(1 + χ2 tan2 θ)3 1 + χ2 tan2 θ)
99 So
g11 2 1 = χ + 2 , (6.107) g22 tan θ
2 g22 tan θ = 2 2 , (6.108) g11 1 + χ tan θ
2 2 2 g11 1 + χ tan θ 1 + tan θ ∂1 = ∂1 2 = −2 3 , (6.109) g22 tan θ tan θ
2 2 g22 tan θ 2 tan θ (1 + tan θ) ∂1 = ∂1 2 2 = 2 2 2 , (6.110) g11 1 + χ tan θ (1 + χ tan θ) and
2 2 2 2 g11 −2(1 + tan θ 4(1 + tan θ) + 2(1 + tan θ) ∂1∂1 = ∂1 3 = 4 . (6.111) g22 tan θ tan θ
Plugging all of these into the Schr¨odingerequation
5 g22 g11 1 g22 g11 ∂1∂1t + ∂1 ∂1 + ∂1∂1 16 g11 g22 4 g11 g22 2 2 g11 +g11(M − K) − m t = −εg11t, g22 (6.112)
gives
5 2 tan θ(1 + tan2 θ) 2(1 + tan2 θ) ∂ ∂ t + − 1 1 16 1 + χ2 tan2 θ)2 tan3 θ 1 tan2 θ 4(1 + tan2 θ) + 2(1 + tan2 θ)2 + 4 1 + χ2 tan2 θ tan4 θ 1 + χ2 tan2 θ χ4(1 + tan2 θ)(1 + χ2 tan2 θ)2 +fracc2χ2 1 + tan2 θ 4c2(1 + χ2 tan2 θ)3 2χ4(1 + tan2 θ)2(1 + χ2 tan2 θ) χ4(1 + tan2 θ)3 + + 4c2(1 + χ2 tan2 θ)3 4c2(1 + χ2 tan2 θ)3 4χ4(1 + tan2 θ)(1 + χ2 tan2 θ) 1 + χ2 tan2 θ − − m2 t(θ) 4c2(1 + χ2 tan2 θ)3 tan2 θ εc2 1 + χ2 tan2 θ = − t(θ), (6.113) χ2 1 + tan2 θ
100 which simplifies to
∂1∂1t 4 + 4χ2 tan2 θ + 4 tan2 θ + 4χ2 tan4 θ + 2 + 2χ2 tan2 θ + 4 tan2 θ + 4χ2 tan4 θ + 4(1 + χ2 tan2 θ)2 tan2 θ 2 tan4 θ + 2χ2 tan6 θ − 5 − 10 tan2 θ − 5 tan4 θ + χ2 tan2 θ + 2χ4 tan4 θ + χ6 tan6 θ + 4(1 + χ2 tan2 θ)2 tan2 θ χ2 tan2 θ + 2χ2 tan4 θ + 2χ2 tan2 θ + 2χ2 tan4 θ + 2χ4 tan4 θ − 2χ4 tan6 θ + χ2 tan6 θ + 4(1 + χ2 tan2 θ)2 tan2 θ −4χ2 tan2 θ − 4χ4 tan4 θ 1 + χ2 tan2 θ εc2 1 + χ2 tan2 θ + − m2 t(θ) = − t(θ), 4(1 + χ2 tan2 θ)2 tan2 θ tan2 θ χ2 1 + tan2 θ (6.114)
and further to
∂1∂1t −1 + 2 + 4 tan2 θ + 4 tan2 θ − 10 tan2 θ + 6χ2 tan2 θ + 4(1 + χ2 tan2 θ)2 tan2 θ 2χ2 tan2 θ + 2χ2 tan2 θ − 4χ2 tan2 θ + 4(1 + χ2 tan2 θ)2 tan2 θ 4χ2 tan4 θ + 4χ2 tan4 θ + 4χ2 tan4 θ + 2χ4 tan4 θ + 4(1 + χ2 tan2 θ)2 tan2 θ −4χ4 tan4 θ + 2χ4 tan4 θ + 2 tan4 θ − 5 tan4 θ + 4(1 + χ2 tan2 θ)2 tan2 θ 2 − 2χ2 + 1 + χ4 1 + χ2 tan2 θ + χ2 tan6 θ − m2 t(θ) 4(1 + χ2 tan2 θ)2 tan2 θ tan2 θ εc2 1 + χ2 tan2 θ = − t(θ). χ2 1 + tan2 θ (6.115)
101 Still more simplification gives
1 + (6χ2 − 2) tan2 θ (8χ2 − 3) tan4 θ ∂ ∂ t + + 1 1 4(1 + χ2 tan2 θ)2 tan2 θ 4(1 + χ2 tan2 θ)2 tan2 θ χ2(3 − 2χ2 + χ4) tan6 θ 1 + χ2 tan2 θ + −m2 t(θ) 4(1 + χ2 tan2 θ)2 tan2 θ tan2 θ εc2 1 + χ2 tan2 θ = − t(θ). χ2 1 + tan2 θ (6.116)
Finally, this becomes
∂2t 1 + (6χ2 − 2) tan2 θ + (8χ2 − 3) tan4 θ + χ2(3 + χ4 − 2χ2) tan6 θ − − ∂θ2 4(1 + χ2 tan2 θ)2 tan2 θ 1 εc2 1 + χ2 tan2 θ −m2 χ2 + t = t, tan2 θ χ2 1 + tan2 θ (6.117)
which is Canteles equation (24).
This ends the proof.
6.4 Numerical Validation of Ref. [5]
The next step is to compare the results of a numerical solution of equation 24 in Ref. [5] to the results plotted in Figure 4a of that reference. To do so, the equation must be entered into a boundary value problem solver with the correct conditions.
For each value of χ, corresponding values of ξ and f were calculated using the formulas χ ξ = , (6.118) pχ2 − 1 and 3V 1/3 f = , (6.119) 4πξ(ξ2 − 1)
102 2 Figure 6.3: Numerical solution of |σ00| for χ = 0.5 for the spheroid using ODE where V is the volume of the ellipsoid (set equal to 216 nm3 or 512 nm3 ). One of the authors of Ref. [5] kindly provided his source code. However, the software package he used, NAG, was not available. Therefore FEMLAB was used to attempt to model the boundary conditions and geometry as accurately as possible. The results are shown in Figures 6.3, 6.4, 6.14, and 6.6. These results are validated to six decimal places for the m = ±1 state, but vary from Ref. [5] by up to ten percent for the m = 0 states, partially because there are second order poles at η = ±1. However, they are close.
6.5 Numerical Validation of Ref. [4]
6.5.1 Extraction of data values in the reference material
Energy levels were extracted from the plots in Ref. [4] by taking screen shots of the plots, then finding the pixel index of each bar in the plots, and matching them to the pixels of the tick marks on the axes. These plots had a nominal pixel resolution of 0.11628ε per pixel. The results in Ref. [4] were validated in two ways. The first was using the spheroidal wave equation, which was the equation used in that reference. The second
103 2 Figure 6.4: Numerical solution of |σ10| for χ = 2.5 for the spheroid using ODE
2 Figure 6.5: Numerical solution of |σ00| for χ = 4 for the spheroid using ODE
104 Figure 6.6: Energy eigenvalues for spheroids using finite element of ODE overlaid with Ref. [5]
method used the 2-D equation in prolate spheroidal coordinates. It was found that the spheroidal wave equation produced eigenvalues whose mean error was within 0.1% of Ref. [4] , and whose standard deviation of error was 7% from that reference. Using the correct unperturbed Hamiltonian (equation (6.15)) produced results that deviated significantly from those in Ref. [4].
A first run was made to validate the energy levels in the reference paper, using the equation in the paper. This equation is
2 1 ∂ ∂ψ ∂ ∂ψ 1 ∂2ψ − ~ ξ2 − 1 + 1 − η2 + 2µf 2 ξ2 − η2 ∂ξ ∂ξ ∂η ∂η (ξ2 − 1)(1 − η2) ∂φ2 = εψ.
(6.120) which, after separation and calculation of λ from the ξ equation, becomes the latitu-
105 Figure 6.7: |σ|2 for ξ = 1.1, f = 10, m = 0, 1, 2, and 3
dinal equation
d dη 1 1 1 − η2 − m2 + η = −f 2(ξ2 − η2)εη. (6.121) dη dη ξ2 − 1 1 − η2
Figure 6.7 shows the ground state wavefunctions of equation (6.120) for ξ = 1.1, f = 10, m = 0, 1, 2, and 3. The straight line corresponds to m = 0, and as m increases, the wavefunction more closely resembles a Gaussian distribution. Figures 6.8 through 6.10 show the calculated energy levels overlaid with Ref. [4]. This is sufficient to validate the energy levels in Ref. [4]. It does not validate that the technique is accurate; only that the solutions to the equation used in that source are.
106 Figure 6.8: Energy levels for a prolate spheroid with ξ = 1.1 overlaid with Ref. [4]
Figure 6.9: Energy levels for a prolate spheroid with ξ = 1.25 overlaid with Ref. [4]
107 Figure 6.10: Energy levels for a prolate spheroid with ξ = 2 overlaid with Ref. [4]
6.5.2 Using the two-dimensional equation
We now attempt to compare the energy levels for a prolate spheroid using the unperturbed two-dimensional Hamiltonian operator to that in Ref. [4]. The equation modeled is " # 1 ∂ 1 − η2 ∂S + λS − m2S = 0 (6.122) p 2 2 ∂η p 2 2 ∂η ξ0 − η ξ0 − η where 2µf 2 λ = E. (6.123) ~2
108 The one-dimensional FEMLAB system is
∂u ∂ ∂u ∂u da + −c − αu − γ + β + au = f on Ω ∂t ∂x ∂x ∂x hu = r on ∂Ω (Dirichlet) ∂u n · (−c ∂x − αu − γ) + qu = g − hµ on ∂Ω (Generalized Neumann). (6.124)
For the equation we are studying, the FEMLAB parameters are
p 2 2 da = ξ − η , (6.125)
α = β = γ = f = 0, (6.126)
1 − η2 c = − , (6.127) pξ2 − η2 p a = −m2 ξ2 − η2. (6.128)
The energies displayed must be scaled due to the values of ~, c, and the particle mass µ. These constants are given in eV·A.˚ For these calculations, f = 1 and ξ was varied. The line segment was set to go from -1 to 1, so that a simple correspon- dence between x and η could be made. Therefore the calculations must be scaled to correspond with the actual arc length in A.˚
The arc length is half of the circumference of an ellipse and can therefore be given by the Gauss-Kummer series expansion
∞ 2 n 1 X 2 (a − b) L = π(a + b) (0.5 | n) , (6.129) 2 (a + b)2 n=0
where a and b are the semimajor axes, given by
a = fξ, (6.130)
109 and p b = f ξ2 − 1, (6.131) and the binomial coefficient is calculated as