Symmetric Norm Inequalities and Positive Semi-Definite Block-Matrices Antoine Mhanna
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Symmetric Norm Inequalities And Positive Semi-Definite Block-Matrices Antoine Mhanna To cite this version: Antoine Mhanna. Symmetric Norm Inequalities And Positive Semi-Definite Block-Matrices. 2015. hal-01182244v5 HAL Id: hal-01182244 https://hal.inria.fr/hal-01182244v5 Preprint submitted on 14 Sep 2015 HAL is a multi-disciplinary open access L’archive ouverte pluridisciplinaire HAL, est archive for the deposit and dissemination of sci- destinée au dépôt et à la diffusion de documents entific research documents, whether they are pub- scientifiques de niveau recherche, publiés ou non, lished or not. The documents may come from émanant des établissements d’enseignement et de teaching and research institutions in France or recherche français ou étrangers, des laboratoires abroad, or from public or private research centers. publics ou privés. Symmetric Norm Inequalities And Positive Semi-Definite Block-Matrices Antoine Mhanna1 1 Dept of Mathematics, Lebanese University, Hadath, Beirut, Lebanon. [email protected] Abstract For positive semi-definite block-matrix M, we say that M is P.S.D. and we write A X M = M+ , with A M+, B M+ . The focus is on studying the conse- X B ∈ n+m ∈ n ∈ m ∗ quences of a decomposition lemma due to C. Bourrin and the main result is extending the class of P.S.D. matrices M written by blocks of same size that satisfies the inequality: M A + B for all symmetric norms. k k ≤ k k Keywords : Matrix Analysis, Hermitian matrices, symmetric norms. 1 Introduction Let A be an n n matrix and F an m m matrix, (m>n) written by blocks such that A × × is a diagonal block and all entries other than those of A are zeros, then the two matrices have the same singular values and for all unitarily invariant norms A = F = A 0 , k k k k k ⊕ k we say then that the symmetric norm on Mm induces a symmetric norm on Mn, so for square matrices we may assume that our norms are defined on all spaces Mn, n 1. ≥ The spectral norm is denoted by . , the Frobenius norm by . , and the Ky Fan k ks k k(2) k norms by . Let M+ denote the set of positive and semi-definite part of the space − k kk n of n n complex matrices and M be any positive semi-definite block-matrices; that is, × A X M = M+ , with A M+, B M+ . X B ∈ n+m ∈ n ∈ m ∗ 1 2 Decomposition of block-matrices M+ Lemma 2.1. For every matrix M in n+m written in blocks, we have the decomposition: A X A 0 0 0 = U U + V V X B 0 0 ∗ 0 B ∗ ∗ for some unitaries U, V Mn m. ∈ + Proof. Factorize the positive matrix as a square of positive matrices: A X C Y C Y = . X B Y D Y D ∗ ∗ ∗ we verify that the right hand side can be written as T ∗T + S∗S so : C Y C Y C 0 C Y 0 Y 0 0 . = . + . Y D Y D Y 0 0 0 0 D Y D ∗ ∗ ∗ ∗ T ∗ T S∗ S CC + YY 0 | A{z 0 } | {z } 0| {z 0} | {z }0 0 Since T T = ∗ = , SS = = and ∗ 0 0 0 0 ∗ 0 Y Y + DD 0 B ∗ AA∗ is unitarily congruent to A∗A for any square matrix A, the lemma follows. Remark 1. As a consequence of this lemma we have: M A + B k k ≤ k k k k for all symmetric norms. Equations involving unitary matrices are called unitary orbits representations. A + A∗ A A∗ Recall that if A Mn, R(A)= and I(A)= − . ∈ 2 2i M+ Corollary 2.1. For every matrix in 2n written in blocks of the same size, we have the decomposition: A+B A X 2 R(X) 0 0 0 = U − U ∗ + V V ∗ X B 0 0 0 A+B + R(X) ∗ 2 for some unitaries U, V M n. ∈ 2 1 I I Proof. Let J = − where I is the identity of Mn, J is a unitary matrix, and √ I I 2 we have: A+B A B X∗ X R(X) − + − A X 2 − 2 2 J J ∗ = X∗ B A B X X∗ A+B −2 −2 2 + R(X) − N | {z } 2 Now we factorize N as a square of positive matrices: A X L M L M = J . J X B ∗ M F M F ∗ ∗ ∗ and let: L M L + M M + F δ = J = 1 ∗ ∗ M F √2 M L F M ∗ ∗ − − L M L + M M L ψ = J = 1 − M F √2 F + M F M ∗ ∗ − ∗ A direct computation shows that: (L+M ∗)(L+M)+(M+F )(F +M ∗) (L+M ∗)(M L)+(M+F )(F M ∗) 1 − − δ.ψ = 2 (M ∗ L)(L+M)+(F M)(F +M ∗) (M ∗ L)(M L)+(F M)(F M ∗) − − − − − − =Γ∗Γ+Φ∗Φ (1) 1 L + M M L 1 0 0 where: Γ = − , and Φ = to finish notice √2 0 0 √2 F + M ∗ F M ∗ − that for any square matrix A, A∗A is unitarily congruent to AA∗ and, ΓΓ∗, ΦΦ∗ have the required form. The previous corollary implies that A+B R(X) and A+B R(X). 2 ≥ 2 ≥− M+ Corollary 2.2. For every matrix in 2n written in blocks of the same size, we have the decomposition: A X A+B + I(X) 0 0 0 = U 2 U + V V X B 0 0 ∗ 0 A+B I(X) ∗ ∗ 2 − for some unitaries U, V Mn m. ∈ + A X A iX Proof. The proof is similar to Corollary 2.1, we have: J J = 1 X B 1∗ iX B ∗ − ∗ I 0 where J = , and 1 0 iI − A+B + I(X) A X 2 ∗ K = JJ1 J1∗J ∗ = X B A B ∗ + I(X) ∗ 2 − here (*) means an unspecified entry, the proof is similar to that in Corollary 2.1 but for reader’s convenience we give the main headlines: first factorize K as a square of positive A X matrices; that is, M = = J J L2JJ next decompose L2 as in Lemma 2.1 to X B 1∗ ∗ 1 ∗ obtain M = J1∗J ∗(T ∗T + S∗S)JJ1 = J1∗J ∗(T ∗T )JJ1 + J1∗J ∗(S∗S)JJ1 3 A+B + I(X) 0 0 0 where T T = 2 and SS = finally the congruence ∗ 0 0 ∗ 0 A+B I(X) 2 − property completes the proof. The existence of unitaries U and V in the decomposition process need not to be unique as one can take the special case; that is, M any diagonal matrix with diagonal k k entries equals a nonnegative number k, explicitly M = kI = U I U + V I V 2 ∗ 2 ∗ for any U and V unitaries. Remark 2. Notice that from the Courant-Fischer theorem if A, B M+, then the ∈ n eigenvalues of each matrix are the same as the singular values and A B = A k ≤ ⇒ k k ≤ B k, for all k = 1, ,n, also A<B = A k < B k, for all k = 1, , n. k k · · · ⇒ k k k k · · · M+ Corollary 2.3. For every matrix in 2n written in blocks of the same size, we have: A X 1 A + B + X X∗ 0 0 0 U | − | U ∗ + V V ∗ X B ≤ 2 0 0 0 A + B + X X ∗ | − ∗| for some unitaries U, V Mn m. ∈ + Proof. This a consequence of the fact that I(X) I(X) . ≤ | | 3 Symmetric Norms and Inequalities In [1] they found that if X is hermitian then M A + B (2) k k ≤ k k for all symmetric norms. It has been given counter-examples showing that this does not necessarily holds if X is a normal but not Hermitian matrix, the main idea of this section is to give examples and counter-examples in a general way and to extend the previous inequality to a larger class of P.S.D. matrices written by blocks satisfying (2). Theorem 3.1. If A and B are positive definite matrices of same size. Then A X 1 > 0 A XB− X∗ X B ⇐⇒ ≥ ∗ 4 A X I XB 1 A XB 1X 0 I 0 Proof. Write = − − − ∗ where I is X B 0 I 0 B XB 1 I ∗ − the identity matrix, and that complete the proof since for any matrix A, A 0 X∗AX 0, X. ≥ ⇐⇒ ≥ ∀ A B Theorem 3.2. Let M = be any square matrix written by blocks of same size, C D if AC = CA then det(M) = det(AD CB) − Proof. Suppose first that A is invertible, let us write M as Z 0 I E M = (3) V I 0 F upon calculation we find that: Z = A, V = C, E = A 1B, F = D CA 1B taking the − − − determinant on each side of (3) we get: 1 det(M) = det(A(D CA− B)) = det(AD CB) − − the result follows by a continuity argument since the Determinant function is a continuous function. A X Given the matrix M = a matrix in M+ written by blocks of same size, X 0 2n ∗ we know that it M is not P.S.D., to see this notice that all the 2 2 extracted principle × submatrices of M are P.S.D if and only if X = 0 and A is positive semi-definite. Even if a proof of this exists and would take two lines, it is quite nice to see a different constructive proof, a direct consequence of Lemma 2.1.