Homework 10 Reading Exercises

MATH 4050 Homework 10 Due Friday, April 29 Reading • Stillwell, 21.8, 22.9, 24.7*, 24.8*, 24.9 (* these are much too hard, but have some choice tidbits - do the best you can) • Finish Logicomix. • You may find D. Royster's chapters on hyperbolic geometry helpful Exercises Hyperbolic Geometrry 1. A Saccheri quadrilateral is a quadrilateral ABCD where angles C and D are right angles, and sides AD and BC have the same length. Using absolute geometry, prove that angles A and B are equal. 2. Prove the àngle-angle-angle' theorem for hyperbolic geometry: Two triangles whose cor- responding angles are equal are congruent. Hint: line them up at one corner, and if they are not the same triangle the space between them is a quadrilateral with a problem. 3. For each part, draw a Poincarédisk and then draw the indicated diagram. (a) Four hyperbolic lines that don't cross each other (b) A point P , a hyperbolic line `, and three more hyperbolic lines through P that don't cross `. (c) A triangle with angles 90◦ − 5◦ − 5◦. (d) A Saccheri quadrilateral with acute angles of 45◦. (e) A pentagon with five right angles. 4. Find the defect of each hyperbolic polygon in question 3c, d, and e. Hilbert's Problems Choose one of Hilbert's 23 problems and give a short explanation of it (or part of it), and to what extent it has been solved. Some of the more approachable ones are 1, 2, 3, 7, 8, 10, 13, 16, 17 and 18. Russell's Paradox Here is a slight variaton on Russell's paradox. Let S be any set (which contains sets). Let R be the set of x 2 S with x2 = x. That is, R is all sets in S which do not contain themselves. Modern set theory axioms allow R to exist. (a) Show that R is not in S. (b) Explain why there can be no set containing all sets. (Cantor is very excited about this, on pg. 169 of Logicomix)..

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Downloaded from Bookstore.Ams.Org 30-60-90 Triangle, 190, 233 36-72
Index 30-60-90 triangle, 190, 233 intersects interior of a side, 144 36-72-72 triangle, 226 to the base of an isosceles triangle, 145 360 theorem, 96, 97 to the hypotenuse, 144 45-45-90 triangle, 190, 233 to the longest side, 144 60-60-60 triangle, 189 Amtrak model, 29 and (logical conjunction), 385 AA congruence theorem for asymptotic angle, 83 triangles, 353 acute, 88 AA similarity theorem, 216 included between two sides, 104 AAA congruence theorem in hyperbolic inscribed in a semicircle, 257 geometry, 338 inscribed in an arc, 257 AAA construction theorem, 191 obtuse, 88 AAASA congruence, 197, 354 of a polygon, 156 AAS congruence theorem, 119 of a triangle, 103 AASAS congruence, 179 of an asymptotic triangle, 351 ABCD property of rigid motions, 441 on a side of a line, 149 absolute value, 434 opposite a side, 104 acute angle, 88 proper, 84 acute triangle, 105 right, 88 adapted coordinate function, 72 straight, 84 adjacency lemma, 98 zero, 84 adjacent angles, 90, 91 angle addition theorem, 90 adjacent edges of a polygon, 156 angle bisector, 100, 147 adjacent interior angle, 113 angle bisector concurrence theorem, 268 admissible decomposition, 201 angle bisector proportion theorem, 219 algebraic number, 317 angle bisector theorem, 147 all-or-nothing theorem, 333 converse, 149 alternate interior angles, 150 angle construction theorem, 88 alternate interior angles postulate, 323 angle criterion for convexity, 160 alternate interior angles theorem, 150 angle measure, 54, 85 converse, 185, 323 between two lines, 357 altitude concurrence theorem,
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Geometry: Neutral MATH 3120, Spring 2016 Many Theorems of Geometry Are True Regardless of Which Parallel Postulate Is Used
Geometry: Neutral MATH 3120, Spring 2016 Many theorems of geometry are true regardless of which parallel postulate is used. A neutral geom- etry is one in which no parallel postulate exists, and the theorems of a netural geometry are true for Euclidean and (most) non-Euclidean geomteries. Spherical geometry is a special case of Non-Euclidean geometries where the great circles on the sphere are lines. This leads to spherical trigonometry where triangles have angle measure sums greater than 180◦. While this is a non-Euclidean geometry, spherical geometry develops along a separate path where the axioms and theorems of neutral geometry do not typically apply. The axioms and theorems of netural geometry apply to Euclidean and hyperbolic geometries. The theorems below can be proven using the SMSG axioms 1 through 15. In the SMSG axiom list, Axiom 16 is the Euclidean parallel postulate. A neutral geometry assumes only the ﬁrst 15 axioms of the SMSG set. Notes on notation: The SMSG axioms refer to the length or measure of line segments and the measure of angles. Thus, we will use the notation AB to describe a line segment and AB to denote its length −−! −! or measure. We refer to the angle formed by AB and AC as \BAC (with vertex A) and denote its measure as m\BAC. 1 Lines and Angles Deﬁnitions: Congruence • Segments and Angles. Two segments (or angles) are congruent if and only if their measures are equal. • Polygons. Two polygons are congruent if and only if there exists a one-to-one correspondence between their vertices such that all their corresponding sides (line sgements) and all their corre- sponding angles are congruent.
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Saccheri and Lambert Quadrilateral in Hyperbolic Geometry
MA 408, Computer Lab Three Saccheri and Lambert Quadrilaterals in Hyperbolic Geometry Name: Score: Instructions: For this lab you will be using the applet, NonEuclid, developed by Castel- lanos, Austin, Darnell, & Estrada. You can either download it from Vista (Go to Labs, click on NonEuclid), or from the following web address: http://www.cs.unm.edu/∼joel/NonEuclid/NonEuclid.html. (Click on Download NonEuclid.Jar). Work through this lab independently or in pairs. You will have the opportunity to finish anything you don't get done in lab at home. Please, write the solutions of homework problems on a separate sheets of paper and staple them to the lab. 1 Introduction In the previous lab you observed that it is impossible to construct a rectangle in the Poincaré disk model of hyperbolic geometry. In this lab you will study two types of quadrilaterals that exist in the hyperbolic geometry and have many properties of a rectangle. A Saccheri quadrilateral has two right angles adjacent to one of the sides, called the base. Two sides that are perpendicular to the base are of equal length. A Lambert quadrilateral is a quadrilateral with three right angles. In the Euclidean geometry a Saccheri or a Lambert quadrilateral has to be a rectangle, but the hyperbolic world is different ... 2 Saccheri Quadrilaterals Definition: A Saccheri quadrilateral is a quadrilateral ABCD such that \ABC and \DAB are right angles and AD ∼= BC. The segment AB is called the base of the Saccheri quadrilateral and the segment CD is called the summit. The two right angles are called the base angles of the Saccheri quadrilateral, and the angles \CDA and \BCD are called the summit angles of the Saccheri quadrilateral.
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Tightening Curves on Surfaces Monotonically with Applications
Tightening Curves on Surfaces Monotonically with Applications † Hsien-Chih Chang∗ Arnaud de Mesmay March 3, 2020 Abstract We prove the first polynomial bound on the number of monotonic homotopy moves required to tighten a collection of closed curves on any compact orientable surface, where the number of crossings in the curve is not allowed to increase at any time during the process. The best known upper bound before was exponential, which can be obtained by combining the algorithm of de Graaf and Schrijver [J. Comb. Theory Ser. B, 1997] together with an exponential upper bound on the number of possible surface maps. To obtain the new upper bound we apply tools from hyperbolic geometry, as well as operations in graph drawing algorithms—the cluster and pipe expansions—to the study of curves on surfaces. As corollaries, we present two efficient algorithms for curves and graphs on surfaces. First, we provide a polynomial-time algorithm to convert any given multicurve on a surface into minimal position. Such an algorithm only existed for single closed curves, and it is known that previous techniques do not generalize to the multicurve case. Second, we provide a polynomial-time algorithm to reduce any k-terminal plane graph (and more generally, surface graph) using degree-1 reductions, series-parallel reductions, and ∆Y -transformations for arbitrary integer k. Previous algorithms only existed in the planar setting when k 4, and all of them rely on extensive case-by-case analysis based on different values of k. Our algorithm≤ makes use of the connection between electrical transformations and homotopy moves, and thus solves the problem in a unified fashion.
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Saccheri Quadrilaterals Definition: Let Be Any Line Segment, and Erect Two
Saccheri Quadrilaterals Definition: Let be any line segment, and erect two perpendiculars at the endpoints A and B. Mark off points C and D on these perpendiculars so that C and D lie on the same side of the line , and BC = AD. Join C and D. The resulting quadrilateral is a Saccheri Quadrilateral. Side is called the base, and the legs, and side the summit. The angles at C and D are called the summit angles. Lemma: A Saccheri Quadrilateral is convex. ~ By construction, D and C are on the same side of the line , and by PSP, will be as well. If intersected at a point F, one of the triangles ªADF or ªBFC would have two angles of at least measure 90, a contradiction (one of the linear pair of angles at F must be obtuse or right). Finally, if and met at a point E then ªABE would be a triangle with two right angles. Thus and must lie entirely on one side of each other. So, GABCD is convex. Theorem: The summit angles of a Saccheri Quadrilateral are congruent. ~ The SASAS version of using SAS to prove the base angles of an isosceles triangle are congruent. GDABC GCBAD, by SASAS, so pD pC. Corollaries: • The diagonals of a Saccheri Quadrilateral are congruent. (Proof: ªABC ªBAD by SAS; CPCF gives AC = BD.) • The line joining the midpoints of the base and summit of a quadrilateral is the perpendicular bisector of both the base and summit. (Proof: Let N and M be the midpoints of summit and base, respectively.
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Arxiv:1808.05573V2 [Math.GT] 13 May 2020 A.K.A
THE MAXIMAL INJECTIVITY RADIUS OF HYPERBOLIC SURFACES WITH GEODESIC BOUNDARY JASON DEBLOIS AND KIM ROMANELLI Abstract. We give sharp upper bounds on the injectivity radii of complete hyperbolic surfaces of finite area with some geodesic boundary components. The given bounds are over all such surfaces with any fixed topology; in particular, boundary lengths are not fixed. This extends the first author's earlier result to the with-boundary setting. In the second part of the paper we comment on another direction for extending this result, via the systole of loops function. The main results of this paper relate to maximal injectivity radius among hyperbolic surfaces with geodesic boundary. For a point p in the interior of a hyperbolic surface F , by the injectivity radius of F at p we mean the supremum injrad p(F ) of all r > 0 such that there is a locally isometric embedding of an open metric neighborhood { a disk { of radius r into F that takes 1 the disk's center to p. If F is complete and without boundary then injrad p(F ) = 2 sysp(F ) at p, where sysp(F ) is the systole of loops at p, the minimal length of a non-constant geodesic arc in F with both endpoints at p. But if F has boundary then injrad p(F ) is bounded above by the distance from p to the boundary, so it approaches 0 as p approaches @F (and we extend it continuously to @F as 0). On the other hand, sysp(F ) does not approach 0 as p @F .
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A Brief Survey of Elliptic Geometry
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Chapter 4 Euclidean Geometry
Chapter 4 Euclidean Geometry Based on previous 15 axioms, The parallel postulate for Euclidean geometry is added in this chapter. 4.1 Euclidean Parallelism, Existence of Rectangles De¯nition 4.1 Two distinct lines ` and m are said to be parallel ( and we write `km) i® they lie in the same plane and do not meet. Terminologies: 1. Transversal: a line intersecting two other lines. 2. Alternate interior angles 3. Corresponding angles 4. Interior angles on the same side of transversal 56 Yi Wang Chapter 4. Euclidean Geometry 57 Theorem 4.2 (Parallelism in absolute geometry) If two lines in the same plane are cut by a transversal to that a pair of alternate interior angles are congruent, the lines are parallel. Remark: Although this theorem involves parallel lines, it does not use the parallel postulate and is valid in absolute geometry. Proof: Assume to the contrary that the two lines meet, then use Exterior Angle Inequality to draw a contradiction. 2 The converse of above theorem is the Euclidean Parallel Postulate. Euclid's Fifth Postulate of Parallels If two lines in the same plane are cut by a transversal so that the sum of the measures of a pair of interior angles on the same side of the transversal is less than 180, the lines will meet on that side of the transversal. In e®ect, this says If m\1 + m\2 6= 180; then ` is not parallel to m Yi Wang Chapter 4. Euclidean Geometry 58 It's contrapositive is If `km; then m\1 + m\2 = 180( or m\2 = m\3): Three possible notions of parallelism Consider in a single ¯xed plane a line ` and a point P not on it.
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Examples of Euclidean Geometry in Real Life
Examples Of Euclidean Geometry In Real Life Quartziferous Geof never jump-offs so imperialistically or enshrines any midribs anomalously. Cancellated Errol forswears ritually. Bullish Maddie overawes decorously while Heath always spindle his expiator strangulating rebukingly, he reattach so antithetically. Is to develop applications and technical problems are commonly taught mathematics, we will be extended indefinitely, lines intuitions in a sphere and expectations of euclidean Kant which was dominant at hand time. Euclidean geometry has the poteotial to bleach a quite significant role indeed perhaps the seoior secondary mathematics syllabus. Image credit: Camilla Ciolli Mattioli. Those sometimes can access JSTOR can pocket some sun the papers mentioned above there. Before constructing architectural forms, mathematics and geometry help came forth the structural blueprint of negligent building. So wconstructions are possible. Consider the interpretation of a mesh line segment as the shortest distance between two points. Lobachevskian geometry or Riemannian geometry. Of wet the traditional high school curricula, EG comes closest to capturing that essential aspect of mathematics as it being understood by mathematicians. This blog deals with various shapes in nor life. How from making and fixing things with him own hands? Mark made two points on your tennis ball. However, warrant a modern perspective we realize that regard is impossible and use language to give meaning to tank other words. It away be proved in those same way as well previous ones. If we we able to travel to a planet in that far away a system, though would square be surprised to see exotic things. Theycan be asked to happy about while our review of parallelism changes on a spherical surface.
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Euclid's Fifth Postulate
GENERAL ⎜ ARTICLE Euclid’s Fifth Postulate Renuka Ravindran In this article, we review the fifth postulate of Euclid and trace its long and glorious history. That after two thousand years, it led to so much discussion and new ideas speaks for itself. “It is hard to add to the fame and glory of Euclid, who managed to write an all-time bestseller, a classic book read and scrutinized for Renuka Ravindran was on the last twenty three centuries.” The book is called 'The Elements’ the faculty of the Depart- and consists of 13 books all devoted to various aspects of geom- ment of Mathematics, IISc, Bangalore. She was also etry and number theory. Of these, the most quoted is the one on Dean, Science Faculty at the fundamentals of geometry Book I, which has 23 definitions, 5 IISc. She has been a postulates and 48 propositions. Of all the wealth of ideas in The visiting Professor at Elements, the one that has claimed the greatest attention is the various universities in USA and Germany. Fifth Postulate. For two thousand years, the Fifth postulate, also known as the ‘parallel postulate’, was suspected by mathemati- cians to be a theorem, which could be proved by using the first four postulates. Starting from the commentary of Proclus, who taught at the Neoplatonic Academy in Athens in the fifth century some 700 years after Euclid to al Gauhary (9th century), to Omar Khayyam (11th century) to Saccheri (18th century), the fifth postulate was sought to be proved. Euclid himself had just stated the fifth postulate without trying to prove it.
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Homework 27 Answers #1 Hint: Use the Defect Theorem 4.8.2. #2 Hint: Note That the Altitude Splits the Saccheri Quadrilateral
Homework 27 Answers #1 Hint: Use the defect theorem 4.8.2. #2 Hint: Note that the altitude splits the Saccheri quadrilateral into two Lambert quadrilaterals. Use the properties of Lambert quadrilaterals to complete the proof. #3 Hint: Same hint as #2. #4 Hint: Show that none of the properties hold for a Saccheri quadrilateral, which is a parallelogram. 1. Suppose that every triangle has the same defect c. Let ABC be a triangle, and suppose that point E is in the interior of BC. We know that δ(ABC) = δ(ABE) + δ(ECA). But the defect of each of these triangles is c, so c = c + c, which implies that c = 0. Because it is not possible to have a triangle with a defect of 0 in a hyperbolic geometry, then triangles in a hyperbolic geometry can't all have the same defect. 2. Let MN be the altitude of the Saccheri quadrilateral ABCD. Since the D N C altitude is perpendicular to both AB and CD, then ∠DAM, ∠AMN, and ∠MND are all right angles. Then it follows that AMND is a Lambert quadrilateral. But this implies that MN < AD. Through a similar proof, A B MN < BC. M 3. Let MN be the altitude of the Saccheri quadrilateral ABCD. Let ∠DAM, ∠AMN, and ∠MND are all right angles. Note that AMND and BMNC are Lambert quadrilaterals, so by #2 above, AM < DN and BM < CN. Also, since M is in the interior of AB and N is in the interior of CD, A * M * B and C * N * D.
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Geometry Through History Saccheri Quadrilaterals and Consequences Lecture Notes/Solutions from Class Friday, February 12
MATH 392 { Geometry Through History Saccheri Quadrilaterals and Consequences Lecture Notes/Solutions From Class Friday, February 12 Background Recall that on Wednesday we were considering the proof of Theorem 1 The following are equivalent: (1) Euclid's Postulates I-V ( and all the additional facts such as Pasch's Axiom and the Axiom of Continuity that Euclid did not state explicitly, but that are needed for complete proofs of the Propositions in Book I of the Elements.) (2) Euclid's Postulates I - IV (and all the facts as in (1)), plus: The set of points equidistant from a given line is another line. We proved (1) ) (2) and saw the intuition behind (2) ) (1), but we had some work left to establish the implication. We had completed: Lemma 1 Let CDKH be a quadrilateral with CH ? CD, DK ? CD and CH = DK. Then \CHK = \DKH. Figures as in this Lemma are called \Saccheri quadrilaterals" because Girolamo Saccheri, S.J. considered their properties extensively in his work on geometry. Lemma 2 (Saccheri-Legendre Theorem) Assume Euclid's Postulates I - IV (and all the facts as in (1) of the theorem) hold. Then the angle sum in every triangle is ≤ 180◦. To complete the proof of (2) ) (1), recall that we needed to show that non-parallel lines \diverge" on one side of their intersection point { the distance between points on one line and the other line grows without bound. This will follow from our next statement: Lemma 3 Assume Euclid's Postulates I - IV (and all the facts as in (1) of the theorem) hold.
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