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Topic680 Chemical Potentials; ; Debye-Huckel Equation The chemical potential of salt j in an aqueous at temperature T and pressure p (which is close to the standard pressure p0) is related to the of salt mj using equation (a). µ = µ0 + ν ⋅ ⋅ ⋅ ⋅ ⋅ γ 0 j (aq) j (aq) R T ln(Q m j ± / m ) (a)

ν ν(+) ν(−) Here Q = ν + ⋅ν − (b)

In equation (b), ν+ and ν- are the number of moles of cations and anions respectively produced on complete dissociation by one mole of salt; ν = ν+ + ν-

. Here γ± is the mean ionic where by definition, at all T and p,

limit(mj →0)γ± =1 (c)

If the thermodynamic properties of the solution are ideal than γ± is unity. However the thermodynamic properties of salt solutions, even quite dilute solutions, are not ideal as a consequence of strong long-range charge-charge interactions between in solution. The challenge is therefore to come up with an equation for γ± granted that the temperature, pressure and properties of the solvent and salt are known together with the composition of the solution. The first successful attempt to meet this challenge was published by Debye and Huckel in 1923 and 1924 [1,2]. In most published accounts, the CGS system of units is used. However here we use the SI system and trace the units through the treatment. The solvent is a dielectric (structureless) continuum characterised by its relative permittivity, εr . The solute (salt) comprises ions characterised by their charge and radius; e.g. ⋅ ≥ for -j, charge z j e and radius rj such that for cations z j 1 and for anions ≤ − z j 1 where zj is an integer. The analysis combines two important physical chemical relationships; Boltzmann’s Law and Poisson’s Equation. We consider an aqueous salt solution containing i-ionic substances, each substance having molality mi. The solution contains cations and anions. A KEY condition requires that the electric charge on the solution is zero. j=i ⋅ = Thus, ∑mj z j 0 (d) j=1 Published accounts of the Debye-Huckel equation almost always use the scale because the analysis concentrates on the distances between ions in solution rather than their mass. The concentration of j ions in a solution, volume V, is given by equation (e)

j=i ⋅ = Thus, ∑cj z j 0 (e) j=1 = c j n j / V (f)

Here nj is the amount of solute j (expressed using the unit, mole) and V is the volume of solution. These equations describe the solution as seen from the standpoint of a chemist interested in the properties of a given solution. However the ‘view’ from the standpoint of, for example, a cation in the solution is quite different. The neutrality condition in equation (d) requires that the electric charge on the + ⋅ − ⋅ solution surrounding the cation j with charge z j e equals z j e ; i.e. equal in magnitude but opposite in sign. This is the electric charge on the rest of the solution and constitutes the ‘ion atmosphere’ of the j ion. Every ion in the solution has its own atmosphere having a charge equal in magnitude but opposite in sign. Moreover interaction between a j ion and its atmosphere stabilises the j ion in solution. The task of the theory is to obtain an equation for this stabilisation of the salt (i.e. the lowering of its chemical potential in solution). Intuitively we might conclude that this stabilisation is a function of the ionic strength of the salt solution and the dielectric properties of the solvent.

We consider a reference j ion, radius rj, in solution together with a small volume element, dV, a distance not more than say (50 x rj) from the j ion. In terms of probabilities, if the j ion is a cation the probability of finding an anion in the reference volume is greater than finding a cation. Again with the j ion as reference, we identify a time averaged electric potential ψj at the volume element. The distribution of ions about the cation j is assumed to follow the

Boltzmann distribution law. The time average number of cations dn+ and anions dn- in the volume element is given by equation (g) where ion i is, in turn, taken as a cation and then as an anion. z ⋅e⋅ψ dn = p ⋅exp(− i j ) ⋅dV (g) i i k ⋅T

Here pi is the number of i ions in unit volume of the solution [3]. Each i ion has ⋅ electric charge zi e . Hence the electric charge on the volume dV is obtained by summing over the charge on the time average number of all ions. The charge ρ ρ density j is given by equation (h), where the subscript j on j stresses that the charge is described with respect to the charge on the j ion [4]. z ⋅e⋅ψ ρ = p ⋅ z ⋅e⋅exp(− i j ) (h) j ∑ i i k ⋅T

The subscript j on ρj and ψj identifies the impact of ion j on the composition and electric potential of the reference volume dV distance r from the j ion. At this point some simplification is welcomed. We expand the exponential in equation (h) [5]. Hence, ρ = j z ⋅e⋅ψ z ⋅e⋅ψ (i) p ⋅ z ⋅e − p ⋅ z ⋅e ⋅( i j ) + p ⋅ z ⋅e⋅(1/ 2)⋅( i j )2 −...... ∑∑i i i i k ⋅T ∑ i i k ⋅T The solution as a whole has zero electric charge. ⋅ ⋅ = Hence ∑pi zi e 0 (j) z ⋅e ⋅ψ Also for dilute solutions, ( i j ) <<1 (k) k ⋅T Hence the third and all subsequent terms in equation (i) are negligibly small. p ⋅(z ⋅e) 2 ⋅ψ Therefore ρ = − i i j ( ) j ∑ k ⋅T l

The approximation leading to equation (l) is welcome for an important reason. Equation (l) satisfies a key condition which requires a linear interdependence between ρj and ψj . ρ ψ Equation (l) relates charge density j and electric potential j. These two properties are also related by Poisson’s theorem [6]: ∇ 2ψ = −ρ ε ⋅ε j j / 0 r (m) Here ε0 is the permittivity of free space; εr is the relative permittivity of the

solvent [6]; ρj is the charge density per unit volume. In the case considered here, the electric charges (ions) are spherically distributed about the reference j ion. Then Poisson’s equation takes the following form [7]. ψ ρ  1  d  d j  j ⋅ r 2 ⋅  = − (n)  2    ε ⋅ε r  dr  dr  0 r

Combination of equations (l) and (n) yields the key equation (o).

ψ 2  1  d  d j  e ⋅ r 2 ⋅  = ⋅ p ⋅ z 2 ⋅ψ (o)  2    ε ⋅ε ⋅ ⋅ ∑ i i j r  dr  dr  0 r k T ψ  1  d  d j  Or, ⋅ r 2 ⋅  = κ2 ⋅ψ (p)  2    j r  dr  dr  e2 where[8] κ2 = p ⋅ z 2 (q) ε ⋅ε ⋅ ⋅ ∑ i i 0 r k T Property κ has the unit ‘reciprocal distance’. Equation (p) is a second order differential equation [9] having the general solution given by equation (p). ψ = ⋅ −κ⋅ + ⋅ κ ⋅ j A1 exp( r)/ r A 2 exp( r) / r (r)

However limit(r → ∞)exp(κ ⋅ r) / r is very large where ψj is zero. Hence A2 must be zero. ψ = ⋅ −κ ⋅ Therefore [10], j A1 exp( r) / r (s)

We combine equations (l) and (s) [11]. exp(−κ ⋅ r) p ⋅(z ⋅e)2 ρ = −A ⋅ ⋅ i i (t) j 1 r ∑ k ⋅T Using the definition of κ2 in equation (q) [12], exp(−κ ⋅ r) ρ = −A ⋅ ε ⋅ ε ⋅ κ 2 ⋅ (u) j 1 0 r r

At this point, a geometric condition is taken into account. Charge density ρj describes the electrical properties of the solution ‘outside ‘ the j ion. No other

ions can approach the j ion closer than a ‘distance of closest approach’ aj. The total charge on the solution ‘outside’ the j ion equals in magnitude but opposite in sign that on the j ion. Hence, ∞ 4⋅π⋅ ρ ⋅ r 2 ⋅dr = − z ⋅ e (v) ∫ j j a( j)

∞ exp(−κ ⋅ r) Or, 4⋅π⋅ [−A ⋅ε ⋅ε ⋅ κ2 ⋅ ]⋅ r 2 ⋅dr = − z ⋅e (w) ∫ 1 0 r j a( j) r

This integration yields an equation for A1. (z ⋅e)⋅exp(κ ⋅a ) A = j j (x) 1 ⋅ π⋅ε ⋅ε ⋅ + κ ⋅ 4 0 r (1 a j )

(z ⋅ e) ⋅ exp(κ ⋅ a ) exp(−κ ⋅ r) Hence ψ = j j ⋅ (y) j ⋅ π ⋅ ε ⋅ ε ⋅ + κ ⋅ 4 0 r (1 a j ) r

We recall that ψj is the electric potential at distance r from the j ion. In the event ⋅ that the solution contains just the j ion (i.e. an isolated j ion) with charge z j e , the electric potential ψ(iso), distance r from the j ion, is given by equation (z) [13]. z ⋅e ψ (iso) = j (z) j ⋅ π⋅ε ⋅ε ⋅ 4 0 r r

The electric potential ψj given by equation (y) is the sum of ψ(iso) and the electric potential produced by all other ions in solution ψ(rest). ψ = ψ + ψ Then j j (iso) j (rest) (za)

z ⋅ e exp(κ ⋅ a ) ⋅ exp(−κ ⋅ r)  Hence, ψ (rest) = j j −1 (zb) j ⋅ π ⋅ ε ⋅ ε ⋅  + κ ⋅  4 0 r r  1 a j 

Equation (zb) is valid for all values of r, including for r = aj. Then from equation ψ (zb), j (rest) at r = aj is given by equation (zc). z ⋅ e κ ψ (rest) = − j ⋅ (zc) j ⋅ π ⋅ ε ⋅ ε + κ ⋅ 4 0 r 1 a j We imagine that the j ion is isolated in solution and that the electrical interaction with all other i ions is then switched on at fixed T and p. The change in chemical potential of single j ion is given by equation (zd), z 2 ⋅e2 κ ∆µ (elec) = − j ⋅ (zd) j ⋅ π⋅ε ⋅ε + κ ⋅ 4 0 r 1 a j ∆µ For one mole of j ions, j (elec) is given by equation (ze) where an additional factor of ‘2’ is introduced into the denominator. Otherwise each ion would be counted twice; i.e. once as the j ion and once in solution around the j ion [14]. z 2 ⋅e2 ⋅ N κ ∆µ (elec;one mole) = − j A ⋅ (ze) j ⋅ π⋅ε ⋅ε + κ ⋅ 8 0 r 1 a j

The chemical potential of single ion j in an aqueous solution, µj(aq) is related to molality mj and single ion activity coefficient γj using equation (zf). µ = µ0 + ⋅ ⋅ 0 + ⋅ ⋅ γ j (aq) j (aq) R T ln(m j / m ) R T ln( j ) (zf) Comparison of equations (ze) and (zf) yields equation (zg). z 2 ⋅e2 κ ln(γ ) = − j ⋅ (zg) j ⋅ π ⋅ε ⋅ε ⋅ ⋅ + κ ⋅ 8 0 r k T 1 a j

The mean ionic activity coefficient γ ± for the salt in solution is given by equation (zh); i.e. for a simple salt where each mole of salt contains ν+ moles of cations and ν- moles of anions.

ν+ ν− 1/ ν γ ± = (γ + ⋅ γ − ) (zh)

Or, (ν + + ν − ) ⋅ln(γ ± ) = ν + ⋅ln(γ + ) + ν − ⋅ln(γ − ) (zi) We envisage closest approaches only between differently charged ions. Then for = = a given salt, a + a − a j . Hence from equation (zg),

e2  κ   ν ⋅ z 2 + ν ⋅ z 2  ln(γ ) = − ⋅  ⋅ + + − −  (zj) ± ⋅ π⋅ ε ⋅ ε ⋅ ⋅  + κ ⋅   ν + ν  8 0 r k T 1 a j   + −  But the salt is overall electrically neutral.

Or, ν + ⋅ z+ = −ν − ⋅z − (zk) ν = −ν ⋅ Whence, + − z− / z + (zl)

2 2 ν + ⋅z + + ν − ⋅z − So [15], = −z + ⋅z − (zm) ν + + ν −

Hence we arrive at an equation for the mean ionic activity coefficient, γ ± [16].

z ⋅ z ⋅ e 2  κ  ln(γ ) = + − ⋅  (zn) ± ⋅ π ⋅ ε ⋅ ε ⋅ ⋅  + κ ⋅  8 0 r k T 1 a j  At this point we return to equation (q) and recall that pi is the number of ions in unit volume of solution. If the concentration of i ions equals ci , (with NA = the Avogadro constant), = ⋅ then [17] pi N A ci (zo) e2 ⋅(N )2 Therefore [18], κ2 = A ⋅ c ⋅ z2 (zp) ε ⋅ε ⋅ ⋅ ∑ i i 0 r R T The convention is to express using the unit, mol dm-3 for which we use the symbol, c’. e2 ⋅(N )2 Hence κ2 = A ⋅ c' ⋅z 2 (zq) 3 ⋅ε ⋅ε ⋅ ⋅ ∑ i i 10 0 r R T For dilute solutions, the following approximation is valid where = ⋅ ⋅ 2 ionic strength I(1/ 2) ∑mi zi (zr) 2⋅e2 ⋅(N )2 ⋅ρ* ( ) κ2 = A 1 l ⋅I (zs) ε ⋅ε ⋅ ⋅ 0 r R T From equations (zn) and (zs) [19],

1/ 2 z ⋅ z ⋅ e 2 2 ⋅ e2 (N ) 2 ⋅ρ* ( ) (I)1/ 2 ln(γ ) = + − ⋅ A 1 l ⋅ (zt) ± ⋅ π⋅ ε ⋅ ε ⋅ ⋅  ε ⋅ ε ⋅ ⋅  + κ ⋅ 8 0 r k T  0 r R T  1 a j For very dilute solutions, the Debye Huckel Limiting Law (DHLL) is used + κ⋅ = where it is assumed that 1 a j 1.0 . Hence,

1/ 2 e3 ⋅[2 ⋅ N ⋅ρ* ( )]1/ 2  N  ln(γ ) = A 1 l ⋅ A ⋅ z ⋅ z ⋅ (I)1/ 2 (zu) ± ⋅ π ⋅ ε ⋅ ε ⋅ ⋅ ε ⋅ ε ⋅ ⋅  + − 8 0 r k T  0 r R T Equation (zu) may be written in the following form. e3 ⋅[2⋅ N ⋅ρ* ( )]1/ 2 ln(γ ) = A 1 l ⋅ z ⋅ z ⋅(I)1/ 2 (zv) ± ⋅ π ⋅ ε ⋅ε ⋅ ⋅ 3/ 2 + − 8 [ 0 r k T] For aqueous solutions at ambient pressure and 298.15 K, ρ* = -3 ε = 1 (l) 997.047 kg m and r 78. 36 .

-1 1/ 2 Hence [20] ln(γ ± ) = (1.1749) ⋅ z + ⋅ z − ⋅(I / mol kg ) (zw)

We note that with z,+ ⋅ z − = − z + ⋅ z − ln(γ ± ) < 0.

In other words ln(γ ± ) is a linear function of the square root of the ionic strength I. Most authors choose to write equation (zx) using logarithms to base 10.

-1 1/ 2 Then log(γ ± ) = z + ⋅ z − ⋅ A γ ⋅(I / mol kg ) (zx) Here[22] A γ = 0.510 . Certainly the latter constant is readily remembered as

‘one-half’. Slight disagreements between published estimates of A γ are a result

ε ρ* of different estimates of r and 1 (l ) . Harned and Owen [1d] published a useful Table for A γ as a function of temperature for aqueous solutions.

The full equation for ln(γ ± ) following on from equation (zt) takes the following form [22].

-1 1/ 2 − z + ⋅z− ⋅Sγ ⋅(I/ mol kg ) ln(γ ) = (zy) ± + β⋅ ⋅ -1 1/ 2 1 a j (I/ mol kg )

For aqueous solutions at ambient pressure and 298.15 K [5],Sγ = 1.175 and

-1 β = 3.285 nm . Adam [23] suggests that aj can be treated as a variable in fitting the measured dependence of ln(γ ± ) on ionic strength for a given salt. Footnotes [1] P. Debye and E. Huckel, Physik. Z.,1923, 24,185,334;1924,25,97. [2] For accounts of the theory see-- (a) K. S. Pitzer. Thermodynamics, McGraw-Hill, New York, 3rd. edition,1995, chapter 16. (b) S. Glasstone, An Introduction to Electrochemistry, D Van Nostrand, New York, 1942, chapter III. (c) R. A. Robinson and R. H. Stokes, Solutions, Butterworths, London , 2nd. edn. Revised 1965. (d) H. S. Harned and B. B. Owen, The Physical Chemistry of Electrolytic Solutions, Reinhold, New York, 2nd edn. Revised and Enlarged, 1950, chapter 2. (e) P. A. Rock, Chemical Thermodynamics, MacMillan, Toronto, 1969, section 13.9. (f) A. Prock and G. McConkey, Topics in Chemical Physics (based on The Harward Lectures by Peter J. W. Debye), Elsevier, Amsterdam, 1962, chapter 5. (g) J. O’M. Bockris and A.K. N. Reddy, Modern Electrochemistry: Ionics, Plenum Press, New York, 2nd. edn.,1998,chapter 3. (h) R. J. Hunter, J.Chem.Educ.,1966,43,550. (i) For comments on the role of water-water and water-ion interactions in aqueous salt solutions see H. S. Frank, Z. fur physik. Chemie,1965,228,364.

[3] In equation (g), dni describes the number of ions in volume dV; pi describes the number of ions in unit volume of solution. [In other words the units used to express pi and dni differ.]

z ⋅e⋅ψ [1]⋅[C]⋅[V] [1]⋅[A s]⋅[J A -1 s-1] i j = = = [1] k ⋅T [J K -1 ]⋅[K] [J K -1 ]⋅[K] ⋅ ⋅ψ  z1 e j   1  p ⋅exp−  ⋅dV = ⋅[1]⋅[m3 ] = [1] i    3   k ⋅T  m  = = -3 dn i [1 ] pi [ m ] z ⋅e⋅ψ [1]⋅[C]⋅[V] [A s]⋅[J A-1 s-1 ] [4] i = = = [1] k ⋅T [J K -1 ]⋅[K] [J]

ρ =  1  ⋅ ⋅ =  C  Then j [1] [C] ; i.e. charge per unit volume m3  m3  x x 2 x 3 [5] exp(x) = 1+ + + + ...... 1! 2! 3! [m−3 ]⋅[1]2 ⋅[C]2 ⋅[V] [m−3 ]⋅[A s]2 ⋅[J A-1 s-1] ρ = = = [C m-3 ] j [J K -1 ]⋅[K] [J] i.e. charge per unit volume

∇ 2ψ = 1 ⋅ =  V  [6] j [V] [m2 ] m 2 

-3 -3 ρ ε ⋅ε = [C m ] = [A s m ] =  V  j /0 r [F m-1 ]⋅[1] [A s V -1 m-1 ] m 2  [7]

ψ -1 -1 -1 -1  1  d  d j   1  1 [J A s ] J A s  ⋅ r 2 ⋅  = ⋅ ⋅[m2 ]⋅ =  2     2   2  r  dr  dr  m  [m] [m]  m 

ρ  C  1 1 A s  1   V  J A -1 s-1  = ⋅ ⋅ = ⋅ = = ε ⋅ε  3  -1  3   -1 -1   2   2  0 r m  [F m ] [1]  m  A s V m  m   m  [8] [C]2  1  κ2 = ⋅ ⋅[1]2 [F m-1 ]⋅[1]⋅[J K -1 ]⋅[K] m3 

2 2 = [A s] ⋅  1  = [A s] ⋅  1  = −2 − [m ] [A s V -1 m-1 ]⋅[J] m3  [A s J 1 A s m-1 ]⋅[J] m3  κ = [m−1 ] [9]

d  dψ  dψ d 2ψ r 2 ⋅ j  = 2⋅ r ⋅ j + r 2 ⋅ j = κ 2 ⋅ψ dr  dr  dr dr 2 j   d 2ψ dψ Then, r 2 ⋅ j + 2⋅ r ⋅ j − κ 2 ⋅ψ = 0 dr 2 dr j ψ = [10] j [V]

ψ = ⋅ −1 ⋅ = and j A1 exp([m] [m])/[m ] A1 [V m]

ρ =  C  [11] j m3  [12]

exp(−κ ⋅ r) − [1] A ⋅ε ⋅ ε ⋅ κ 2 ⋅ = [V m]⋅[F m-1 ]⋅[1]⋅[m] 2 ⋅ 1 0 r r [m]

− [1] [C] = [V m]⋅[A s V-1 m-1 ]⋅[1]⋅[m] 2 ⋅ = [m] [m3 ]

[1]⋅[C] [A s] [13] ψ (iso) = = = [V] j [1]⋅[1]⋅[F m-1 ]⋅[1]⋅[m] [A s V -1 ]

[14] 2 ⋅ 2 ⋅ −1 −1 ∆µ = [1] [C] [mol] ⋅  [m]  j (elec;one mole) -1  −1  [1]⋅[F m ]⋅[1] 1+ [m] ⋅[m]   [A s]2 ⋅[mol−1 ]⋅[m]−1 [A s]⋅[mol]-1 = = = [J mol-1 ] [A s V -1 m-1 ] [J-1 A s]

ν ⋅z 2 + ν ⋅z 2 − (ν ⋅ z ⋅ z ) + (ν ⋅ z 2 ) [15] + + − − = − − + − − ν + + ν − − (ν − ⋅ z − / z + ) + ν −

 ν − (ν ⋅z / z )  = −z=⋅ z − − − + − z⋅z + − − ν ⋅ + ν  + −  ( − z− / z+ ) −  [16] ⋅ 2 −1 γ = [1] [C] ⋅  [m]  ln( ± ) -1 -1  −1  [1]⋅[F m ]⋅[1]⋅[J K ]⋅[K] 1+[m] ⋅[m]

[A s]2 1 [A s] = ⋅ = = [1] [A s V -1 ] [J] [J-1 A s]⋅[J]

⋅ = −1 ⋅ -3 = −3 [17] N A ci [mol ] [mol m ] [m ] [18] [C]2 ⋅[mol−1 ]2 κ2 = ⋅[mol m-3 ] [F m-1 ]⋅[1]⋅[J mol-1 K -1 ]⋅[K]

2 −2 -2 [A s] ⋅[m] [A s]⋅[m] − = = = [m] 2 [A s V-1 ]⋅[J] [J-1 A s]⋅[J]

[19] ⋅ ⋅ 2 ⋅ 2 z + z − e = [1] [C] 8⋅ π ⋅ε ⋅ε ⋅ k ⋅ T [1]⋅[1]⋅[F m-1 ]⋅[J K -1 ]⋅[K] 0 r [A 2 s 2 ] = = [m] [A s J -1A s m-1 ]⋅[J]

1/ 2 1/ 2 2⋅ e2 ⋅ (N ) 2 ⋅ρ* ( )  ⋅ 2 ⋅ −1 2 ⋅ -3  A 1 l = [1] [C] [mol ] [kg m ]  ε ⋅ ε ⋅ ⋅   -1 ⋅ ⋅ -1 -1 ⋅   0 r R T  [F m ] [1] [J mol K ] [K] 1/ 2  2 2 ⋅ −1 2 ⋅ -3  = [A s ] [mol ] [kg m ] = −1 ⋅ ⋅ −2 1/ 2  -1 -1  [[mol ] [kg] [m ]]  [A s J A s m ]⋅[J mol ]  −1 = [m ] [mol kg -1 ]1/ 2

κ ⋅ = −1 ⋅ = a j [m ] [m] [1 ]

1/ 2 ⋅ ⋅ 2 ⋅ 2 2 ⋅ρ* 1/ 2 z + z − e 2 e (N A ) 1 (l) (I) ⋅   ⋅ 8⋅ π ⋅ε ⋅ε ⋅ k ⋅T ε ⋅ε ⋅ R ⋅T 1+ κ ⋅a 0 r  0 r  j [m −1 ] [mol kg -1 ]1/ 2 = [m]⋅ ⋅ = [1] [mol kg -1 ]1/ 2 [1]

As required ln(γ ± ) = [1 ] [20] J. S. Winn, Physical Chemistry, Harper Collins, New York, 1995,page 315. [21] M. L. McGlashan, Chemical Thermodynamics, Academic Press, 1979, p 304. [22] Using ρ* = (a) 1 (H 2O; l; 2981.5K) 997.0474 ; G.S.Kell, J. Chem. Eng.Data, 1975,20,97. ε = ± (b) r (H 2O; l; 2981.5K) 78.36 0. 05 H. Kienitz and K. N. Marsh, Pure Appl. Chem.,1981,53,1874. (c) CODATA 1986 fundamental constants [23] N. K. Adam, Physical Chemistry, Oxford, 1956, page 395.