Mazes for Superintelligent Ginzburg Projection
Izidor Hafner Mazes for Superintelligent Ginzburg projection Cell[ TextData[ {"I. Hafner, Mazes for Superintelligent}], "Header"] 2 Introduction Let as take an example. We are given a uniform polyhedron. 10 4 small rhombidodecahedron 910, 4, ÅÅÅÅÅÅÅÅÅ , ÅÅÅÅÅ = 9 3 In Mathematica the polyhedron is given by a list of faces and with a list of koordinates of vertices [Roman E. Maeder, The Mathematica Programmer II, Academic Press1996]. The list of faces consists of a list of lists, where a face is represented by a list of vertices, which is given by a matrix. Let us show the first five faces: 81, 2, 6, 15, 26, 36, 31, 19, 10, 3< 81, 3, 9, 4< 81, 4, 11, 22, 29, 32, 30, 19, 13, 5< 81, 5, 8, 2< 82, 8, 17, 26, 38, 39, 37, 28, 16, 7< The nest two figures represent faces and vertices. The polyhedron is projected onto supescribed sphere and the sphere is projected by a cartographic projection. Cell[ TextData[ {"I. Hafner, Mazes for Superintelligent}], "Header"] 3 1 4 11 21 17 7 2 8 6 5 20 19 30 16 15 3 14 10 12 18 26 34 39 37 29 23 9 24 13 28 27 41 36 38 22 25 31 33 40 42 35 32 5 8 17 24 13 3 1 2 6 15 26 36 31 19 10 9 4 7 14 27 38 47 43 30 20 12 25 49 42 18 11 16 39 54 32 21 23 2837 50 57 53 44 29 22 3433 35 4048 56 60 59 52 41 45 51 58 55 46 The problem is to find the path from the black dot to gray dot, where thick lines represent walls of a maze.
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