- Magnetism
- Magnets
Zero external field
Finite external field
• Types of magnetic systems • Pauli paramagnetism in metals • Landau diamagnetism in metals • Larmor diamagnetism in insulators • Ferromagnetism of electron gas • Spin Hamiltonian
Paramagnets Diamagnets Ferromagnets
• Mean field approach • Curie transition
Antiferromagnets Ferrimagnets
- …
- …
- …
- Pauli paramagnetism
- Pauli paramagnetism
- ε↑ = p2 / 2m−e=B/ 2mc
- ε = p2 / 2m+e=B/ 2mc
Let us first look at magnetic properties of a free electron gas.
↓G
d3 p
Electron are spin-1/2 particles
#of majority spins:
- N↑,↓ =V
- 3 f (ε↑,↓
)
∫
In external magnetic field B – Zeeman splitting
#of minority spins:
(2π=)
- ε↑ = p2 / 2m−e=B/ 2mc
- ε↓ = p2 / 2m+e=B/ 2mc
Magnetization (magnetic moment per unit volume):
- minority spins
Fermi level
e=
- M =
- (N↑ − N↓ )
: aligned along the field and proportional
2Vmc
to B in low fields
- magnetic succeptibility
χ
M = χB
- majority spins
- paramagnetism
χ > 0
- Pauli succeptibility
- Landau quantization
G
- ε↑ = p2 / 2m−e=B/ 2mc
- ε↓ = p2 / 2m+e=B/ 2mc
A free electron in magnetic field:
ˆ
B & z
G
2
2
µ+e=B/2mc
G
⎛⎜⎝
⎞⎟⎠
=
ieA
Ay = Bx; A = A = 0
- V
- g e=B
Schrödinger equation:
- x
- z
- −
- ∇+
- ψ = εψ
- N↑ − N↓ =
- g(ε)dε ≈
V
∫
- 2m
- =c
2 µ−e=B/2mc
2 mc
n,kz
B=1T corresponds to e=B / mc =1K ×kB provided m is free electrons’s mass
Solutions: labeled by two indices
G
ψ
nk (r) = exp(iky y +ikz z)ϕn (x − =cky / eB)
For any fields,
e=B/ mc ꢀ µ
ϕn
- wave functions of a harmonic oscillator
Magnetic succeptibility:
Energies: εnk = =2kz2 / 2m+(e=B/ mc)(n+1/ 2)
2
- strongly degenerate!!
e=
- ⎛
- ⎞
χP
=
g
⎜⎝
⎟⎠
2mc
We “quantized” momenta transverse to the field
(Landau levels)
1
- Landau diamagnetism
- Electrons in metals
A free electron in magnetic field: moves along spiral trajectories and create magnetic field themselves.
We know that there are diamagnetic metals. How can we explain their existence?
This magnetic field is directed antiparallel to the external one
Different spectra of electrons in metals and free electrons.
m*
Example: renormalized electron mass
Diamagnetism
This only affects orbital motion, not Zeeman splitting
dk
Energy:
E = 2
εnk f ε
- (
- )
∑
- s
- nk
∫
2π
= −V −1
n
χP* = χP; χL* = χL (m/ m*)2
- M
- ∂E /
∂
B
Magnetization:
2
13
e=
1
⎛⎝
⎞
- Result for the succeptibility:
- We can explain paramagnetic and diamagnetic metals!
χL = −
g = − χP
- ⎜
- ⎟
⎠
2mc
3
But there is no way we can explain ferromagnetic and antiferromagnetic metals in non-interacting electron model.
Total succeptibility:
χ
=
χP
+
χL
=
2χP /3
>
0
: paramagnetic!
Try insulators?
- Larmor diamagnetism
- Larmor diamagnetism
- e2
- e2ZN
Consider an ionic insulator with filled shells. Electrons are localized at the ions.
∆Eg =
- B2
- r2
=
B2 r2
G
2
∑
i
Electron Hamiltonian:
- 12mc2
- 12mc2
2
g
- G
- G G G
- G
⎛⎜⎝
⎞⎟⎠
=
- ieA
- e
- =
- G
i g
ˆ
H
- = −
- ∇+
- +
BS; A
=
B
×
r
2m
=
- c
- mc
1 ∂2E e2Z
Succeptibility:
cA r2
- ionic charge
Z
r small: consider terms with the field as a perturbation.
- χ = −
- = −
V ∂B2
6mc2
g
cA- #of atoms per unit volume
Correction to the energy in the ground state:
ˆ
∆Eg = g.s H g.s
Diamagnetism!
Total spin and total momentum of electrons in a filled shell are zero;
r2
If the ionic shells are not filled – can get paramagnetic contribution due to other terms.
- only the term with
- contributes.
e2
8mc2 e2
12mc2
∆Eg =
B2 x2 + y2
=
- B2
- r2
- (
- )
Can explain paramagnetic and diamagnetic insulators, but not ferromagnetic and antiferromagnetic ones!
- ∑
- ∑
- i
- i
- i
- i
- i
- g
- g
Ferromagnetism for localized electrons
Exchange interaction
Try to visualize for localized electrons (atoms; artificial atoms – quantum dots; defects etc)
Two electrons: antisymmetric wave function! Take an electron level
ε
The simplest model:
Wave function of two electrons:
δ
Discrete electron states; spacing (each level is doubly degenerate)
δ
1
S = 0,1
for
- ψ (r ,r ) =
- ϕ (r )ϕ (r ) ±ϕ (r )ϕ (r )
- [
- ]
- 1
- 2
- 1
- 1
- 2
- 2
- 2
- 1
- 1
- 2
2
To put an electron into the system costs electrostatic energy U and exchange
energy -J
Energy splitting due to interaction: spin-dependent!
Same spin: U +δ − J
ε →ε +C ± J / 2
Energy to pay:
Opposite spin: U
C = d r d r U(r − r ) ϕ1(r ) 2 ϕ2 (r ) 2
- 1
- 2
- 1
- 2
- 1
- 2
∫
J <δ Non-magnetic state
J >δ Ferromagnetic state
J = 2 d r d r U(r − r )ϕ1(r )ϕ1*(r )ϕ2*(r )ϕ2 (r )
- 1
- 2
- 1
- 2
- 1
- 2
- 1
- 2
∫
G G
ˆ
Spin Hamiltonian
H = const − JS1S2
2
- Itinerant ferromagnetism
- Itinerant ferromagnetism
If we can not get ferromagnetism with free electrons, try interacting electrons.
Working the interaction terms out for free electrons (see Advanced
Quantum Mechanics, lecture 4)
35
3N
=
2kF2 2m
- Hartree-Fock approximation:
- Kinetic energy:
Ekin
=
NEF
=
5
Eint = g V g
int
3
kF
G G e2
- G
- G
- G
- G
- G
- G
Potential energy:
NB: N =VkF3 /(3π 2 )
Eint = − Ne2
2
12
≈
drdr '
ψi (r) 2 ψ j (r ') −ψi (r)ψ j (r ')ψi (r ')ψ j (r)
- *
- *
- ⎡
- ⎤
- G
- G
4
π
∑
∫
- ⎢
- ⎥
- ⎦
- ⎣
r −r '
ij
Try now a spin-polarized ground state: kF↑ ≠ kF↓
Kinetic energy loss can be compensated by the potential energy gain!
Fock (exchange)
Hartree (direct)
interaction interaction. Only exists if spin projections are the same
in the states i and j
- 5
- 1
- For
- - spin-polarized ground state (ferromagnetism!!)
kF aB <
2π 21/3 +1
aB = =2 / me2
Never occurs in real life.
- Bohr radius
- Antiferromagnetic ordering
- Antiferromagnetic ordering
2
A different situation: a pair of magnetic atoms in an insulating matrix Consider d-electrons, 5 electrons per atom
2nd order corrections to the ground state: virtual states
Miν
∆E = −
∑
E − Ei
νν
- Virtual
- Ground
U – ionization energy; t – overlap between the atoms
t
ꢀ
U
∆E = −25t2 /U ꢀ t,U
Unperturbed ground state: either parallel or antiparallel spins.
Ferromagnetic state: no second-order correction (forbidden by Pauli principle)
Antiferromagnetic state preferential!
- Spin Hamiltonian
- Mean field approach
Let us single out one particular spin at i.
Does not work for many atoms – but still represents a good model to treat
G
i
G
ˆ
magnetism
ˆ
ˆ
H = −JS S +(all other spins)
G G
i
∑
j
ˆ ˆ
ˆ
H = − J S S
i and j – lattice sites
j
∑
- ij
- j
ij
- G
- G
ˆ
GG
Approximation: this spin sees the average field (Weiss field)
ˆ
ˆ
h = −J
S
Common approximation: only nearest neighbours interact; the same exchange integrals for all bonds
∑
H = hSi
j j
G G
i
Now we need to calculate the average field self-consistently.
ˆ ˆ
ˆ
Heisenberg model:
H = −J S S
∑
j
Each site has
N
nearest neighbours. For each neighbour,
ij
P ∝ exp(−h/ 2kBT)
↓
chance to be “up” (parallel to the field)
P↑ ∝ exp(+h/ 2kBT)
J > 0 (J < 0)
favors ferromagnetism (antiferromagnetism) chance to be “down” (antiparallel to the field)
Exact solution: only known for 1D chain (Bethe 1931) – no magnetism!
- JN
- JN
- h
Can also be treated for high spins (classical) Let us see what we can do with approximate solutions.
Equation for the field:
- h = −
- P − P
=
tanh
- (
- )
- ↑
- ↓
- 2
- 2
2kBT
3
- Mean field approach
- Curie transition
Magnetization close to transition temperature
JN
- JN
- h
T =
h =
tanh
c
tanh x ≈ x − x3 /3
4kB
2
2kBT
Solution:
h = 12kB2T (T −T)