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Today in Physics 217: magnetic multipoles

‰ Multipole expansion of the magnetic vector potential z ‰ Magnetic θ B ‰ Magnetic from a w magnetic m ‰ Torque on a magnetic y dipole in uniform B θ ‰ Force and energy and x magnetic dipoles

13 November 2002 Physics 217, Fall 2002 1 Multipole expansion of the magnetic vector potential Consider an arbitrary loop that carries a current I. Its vector potential at point r is r Id r =−rr′ Ar()= . θ c ∫ r

Just as we did for V, we can expand 1 r I r’ in a power and use the series as an approximation scheme: d ∞ n 11 r′ = ∑ Pn ()cosθ r rrn=0  (see lecture notes for 21 October 2002 for derivation).

13 November 2002 Physics 217, Fall 2002 2 Multipole expansion of the magnetic vector potential (continued) Put this series into the expression for A: I  11 Ar()=+ drd′cosθ Monopole, dipole, cr ∫∫r2 1322 1 +−rd′ cos θ , r3 ∫ 22 1533 3 +−rd′ cosθθ cos octupole r4 ∫ 22 +…

Of special note in this expression:

13 November 2002 Physics 217, Fall 2002 3 Multipole expansion of the magnetic vector potential (continued) ‰ The monopole term is zero, since ∫ d = 0. This isn’t surprising, since “no magnetic monopoles” is built into the Biot-Savart law, from which we obtained A. ‰ For points far away from the loop compared to its size, we obtain a good approximation for A by using just the first (or first two) nonvanishing terms. (For points closer by, one would need more terms for the same accuracy.) ‰ This is, of course, the same useful behaviour we saw in the multipole expansion of V.

13 November 2002 Physics 217, Fall 2002 4 Magnetic dipoles

II Ardipole ()==⋅rd′′cosθ () rrˆ d cr22∫∫ cr Note that ddd()rrˆˆˆ⋅=⋅+⋅′′ r r r( ′′ r rr )() ′ r ′ () ( ) () dddrrˆˆˆ⋅=⋅+⋅′′ r r r ′′ r rr ′ r ′ ∫∫∫() but ∫ d ()rrˆ ⋅=′′ r 0 , so () ∫∫rrrˆˆ⋅=−⋅dd′′ rrr ′ ′. Also, rrrˆˆˆˆ××=∫∫′dd ′ rrr ′()() ⋅− ′ ∫ rrr ⋅ ′′ d =−⋅2. ∫ rrr ′′ d ()

13 November 2002 Physics 217, Fall 2002 5 Magnetic dipoles (continued) 1 Thus ()rrˆˆˆ⋅=⋅=−××′′dd r rr ′ () r r ′ d ∫∫2 ∫ 1 I so Arrdipole =−ˆ ×′ ×d 2 cr2 ∫ rmˆˆ×× mr ≡− = , rr22 I where mr≡×′ d . 2c ∫

pr⋅ ˆ (Compare to Vddipole ==,.)prρτ′′ r2 ∫

13 November 2002 Physics 217, Fall 2002 6 Magnetic dipoles (continued)

To see what this means in terms of geometry of a πα− current loop and its dipole d α , consider the triangle r’ formed by r′ and d : 11 1 r′′×=drdrd sinαπα = ′ sin () − 22 2 = area of triangle. 1 m So ra′′×=dd , and 2 II maa== d ′ for plane loops. a cc∫ I

13 November 2002 Physics 217, Fall 2002 7 from a magnetic dipole

For a dipole with mz = m ˆ , we have, in spherical coordinates, mr× ˆ msinθ Adipole == φˆ , rr22 rˆ ∂∂θˆ so BA=×— =sinθ ArAφφ − dipole dipole rrrsinθθ∂∂ mmrˆ ∂∂sinθθˆ 1 =−sin2 θ r3 sinθ ∂∂θ rrr mmrˆ sinθθˆ =+2sinθθ cos rr33sinθ 2cosmmθθ sinˆ 1 =+=⋅−rˆˆˆθ 3.()mrr m rrr333

13 November 2002 Physics 217, Fall 2002 8 Magnetic field from a magnetic dipole (continued)

‰ That is to say, B from magnetic dipoles looks exactly like E from electric dipoles. ‰ We can thus work out forces, torques, energies, and even a lot about magnetostatics in magnetically-polarizable matter in strict analogy with electrostatics. The real- dipole paradigms:

+q a s Planar loop -q I p = qs m = Ia/c (Ia in MKS)

13 November 2002 Physics 217, Fall 2002 9 Torque on a magnetic dipole in uniform B

z z

θ B m B IwB w m F = c θ View down x θ y y θ IwB F = x c

Iw NF== sinθθθ B sin = mB sin c ⇒=×NmB()cf. NpE =× .

13 November 2002 Physics 217, Fall 2002 10 Force and energy and magnetic dipoles

Thus the following should be no surprise: FmB=⋅—() =⋅()mB— if no currents exist at dipole's position. (cf. Fp=⋅()— E) WW=−mB ⋅(cf. =− pE ⋅ )

Magnetic dipoles thus tend to align in magnetic fields in the same way that electric dipoles align in electric fields.

13 November 2002 Physics 217, Fall 2002 11