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Date: 13.05.2020 E-CONTENT SUBJECT – PHYSICS CLASS - B.Sc. ( Hons.) Part I Dr. Debarati Ghosh Department of Physics, T. P. S. College, Patna.

CENTRAL

� �

� � Fig. 1

Suppose that a acting on a particle of mass in is such that [see Fig. 1]: (a) it is always directed from � toward or away from a fixed point O ,

(b) its magnitude depends only on the distance r from O .

Then we call the force a central force or central force field with O as the center of force. Thus F is a central force if and only if

(1)

1 r where r = is a unit vector in the direction of r . 1 r The central force is one of attraction toward O or repulsion from O according as f (r)<0 or f (r)>0 respectively.

SOME IMPORTANT PROPERTIES OF CENTRAL FORCE FIELDS

If a particle moves in a central force field, then the following properties are valid. Property 1: The path or orbit of the particle must be a plane curve, i.e. the particle moves in a plane.

Property 2: The of the particle is conserved, i.e. is constant.

Property 3: The particle moves in such a way that the vector or radius vector drawn from O to the particle sweeps out equal areas in equal times. In other words, the time rate of change in area (i.e. the areal ) is constant. This is sometimes called the law of areas.

Property 4: A central force is conservative in nature.

Prove that if a particle moves in a central force field, then its path must be a plane curve i.e. the particle moves in a plane.

Let F=f (r)r1 be the central force field. Then

(1)

Since r1 is a unit vector in the direction of the position vector r . Since

d v F=m , this can be written dt

2 (2) or (3)

Integrating, we find (4) where h is a constant vector. Multiplying both sides of equation (4) by r • ,

(5) using the fact that

Thus r is perpendicular to the constant vector h , and so the motion takes place in a plane. We shall assume that this plane is taken to be the xy plane whose origin is at the center of force.

Prove that for a particle moving in a central force field the angular momentum is conserved.

Let F=f (r)r1 be the central force field. Then

(1)

Since r1 is a unit vector in the direction of the position vector r . Since

d v F=m , this can be written dt

(2)

3 or (3)

Integrating, we find (4) where h is a constant vector. Multiplying both sides of equation (4) by m , we have

m(r×v)=mh =constant (5)

Since the left side of expression (5) is the angular momentum, it follows that the angular momentum is conserved, i.e. is always constant in magnitude and direction.

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