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Sculpting with and Foliation

Hang Li, Zhipei Yan

May, 2016

1 Theory

Definition 1.1. For E(total space), B(base), F (fiber) and surjection

π : E → B (1) if there is an open neighborhood U of π(x) (x ∈ E) such that π−1(U) and U × F are homeomorphic, (E, B, F, π) is a fiber bundle. And E has the form of product space B × F .

Figure 1: Base and Fiber

Here are two kinds of fiber bundle on a .

Figure 2: Trivial Fibers Figure 3: Nontrivial Fibers

1 Definition 1.2. {Ui} is an of an n-dimensional manifold U. For each chart Ui, define n φi : Ui → R (2)

If Ui ∩ Uj 6= ∅, define −1 ϕij = φj ◦ φi (3)

And if ϕij has the form of 1 2 ϕij = (ϕij(x), ϕij(x, y)) (4) 1 n−p n−p ϕij : R → R (5) 2 n p ϕij : R → R (6) then for any stripe si : x = ci in Ui there must be a stripe in Uj sj : x = cj such that si and sj are the same curve in Ui ∩ Uj and can be connected. The maximal connection is a leaf. This structure is called a p-dimensional foliation F of an n-dimensional manifold U.

Property 1.1. All the fiber bundles compose a group GF = ({Fi}, ◦). If we regard the fiber bundle(1-manifold) as a parameterization on a (2-manifold), we can prove it easily. As an example, we use the parameterization on a torus.

{u, v} → {(R + r cos v) cos u, (R + r cos v) sin u, r sin v} (7)

Then we can get the trivial fibers in Fig. 2.

{u, v} = {t, const} (8)

To generalize the creating method of fiber bundle, it’s necessary to define the transformation functions. Definition 1.3. A transformation function F : [0, 1]2 → [0, 1]2 for fiber bundle must be: • F is C1([0, 1]2) • F is bijection • F (u, 0) = F (u, 1), F (0, v) = F (1, v) Fu(u, 0) = Fu(u, 1), Fu(0, v) = Fu(1, v) Fv(u, 0) = Fv(u, 1), Fv(0, v) = Fv(1, v) An example is F (u, v) = {u, {v + u/2}}. The {·} inside means the fractional part. Generally, transformation functions always use {·} to make sure that F have the properties listed above. In the following parts, we will omit it. With transformation functions, we can easily get any fiber in any fiber bundle:

F : {u, v} = {t, const} → {u0, v0} = F (u, v) → {(R + r cos v0) cos u0, (R + r cos v0) sin u0, r sin v0} (9)

And

Property 1.2. For GF , we have following properties:

• ∀Fi,Fj, Fi ◦ Fj is defined as 0 0 0 0 0 0 0 Fj ◦ Fi : {u , v } = Fj(Fi(u, v)) → {(R + r cos v ) cos u , (R + r cos v ) sin u , r sin v } (10)

• Identity element is I : I(u, v) = {u, v} (11)

• ∀Fi, −1 0 0 −1 0 0 0 0 0 Fi : {u , v } = Fi (u, v) → {(R + r cos v ) cos u , (R + r cos v ) sin u , r sin v } (12)

2 2 Result

As an example, assume u F (u, v) = {u, v + } (13) 1 2 F2(u, v) = {u, v + sin 2πu} (14) 1 F (u, v) = {u + sin 2πv, v} (15) 3 2 F = F3 ◦ F2 ◦ F1 (16)

1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 4: A fiber of I Figure 5: A fiber of I

1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 6: Five fibers of I Figure 7: Five fibers of I

3 1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 8: A fiber of F1 Figure 9: A fiber of F1

1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 10: Five fibers of F1 Figure 11: Five fibers of F1

4 1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 12: A fiber of F2 Figure 13: A fiber of F2

1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 14: Five fibers of F2 Figure 15: Five fibers of F2

5 1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 16: A fiber of F3 Figure 17: A fiber of F3

1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 18: Five fibers of F3 Figure 19: Five fibers of F3

6 1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 20: A fiber of F2 ◦ F1 Figure 21: A fiber of F2 ◦ F1

1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 22: Five fibers of F2 ◦ F1 Figure 23: Five fibers of F2 ◦ F1

7 1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 24: A fiber of F3 ◦ F2 ◦ F1 Figure 25: A fiber of F3 ◦ F2 ◦ F1

1.0

0.8

0.6

1.0 0.4 0.5 0.0 2 -0.5 -1.0 0.2 0 -2

0 -2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 2

Figure 26: Five fibers of F3 ◦ F2 ◦ F1 Figure 27: Five fibers of F3 ◦ F2 ◦ F1

8 Figure 28: Base and Fiber

9