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Series: Convergence and Divergence Comparison Tests
Series: Convergence and Divergence Here is a compilation of what we have done so far (up to the end of October) in terms of convergence and divergence. • Series that we know about: P∞ n Geometric Series: A geometric series is a series of the form n=0 ar . The series converges if |r| < 1 and 1 a1 diverges otherwise . If |r| < 1, the sum of the entire series is 1−r where a is the first term of the series and r is the common ratio. P∞ 1 2 p-Series Test: The series n=1 np converges if p1 and diverges otherwise . P∞ • Nth Term Test for Divergence: If limn→∞ an 6= 0, then the series n=1 an diverges. Note: If limn→∞ an = 0 we know nothing. It is possible that the series converges but it is possible that the series diverges. Comparison Tests: P∞ • Direct Comparison Test: If a series n=1 an has all positive terms, and all of its terms are eventually bigger than those in a series that is known to be divergent, then it is also divergent. The reverse is also true–if all the terms are eventually smaller than those of some convergent series, then the series is convergent. P P P That is, if an, bn and cn are all series with positive terms and an ≤ bn ≤ cn for all n sufficiently large, then P P if cn converges, then bn does as well P P if an diverges, then bn does as well. (This is a good test to use with rational functions. -
Calculus II Chapter 9 Review Name______
Calculus II Chapter 9 Review Name___________ ________________________ SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question. A recursion formula and the initial term(s) of a sequence are given. Write out the first five terms of the sequence. an 1) a = 1, a = 1) 1 n+1 n + 2 Find a formula for the nth term of the sequence. 1 1 1 1 2) 1, - , , - , 2) 4 9 16 25 Find the limit of the sequence if it converges; otherwise indicate divergence. 9 + 8n 3) a = 3) n 9 + 5n 3 4) (-1)n 1 - 4) n Determine if the sequence is bounded. Δn 5) 5) 4n Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges. 3 3 3 3 6) 3 - + - + ... + (-1)n-1 + ... 6) 8 64 512 8n-1 7 7 7 7 7) + + + ... + + ... 7) 1·3 2·4 3·5 n(n + 2) Find the sum of the series. Q n 9 8) _ (-1) 8) 4n n=0 Use partial fractions to find the sum of the series. 3 9) 9) _ (4n - 1)(4n + 3) 1 Determine if the series converges or diverges; if the series converges, find its sum. 3n+1 10) _ 10) 7n-1 1 cos nΔ 11) _ 11) 7n Find the values of x for which the geometric series converges. n n 12) _ -3 x 12) Find the sum of the geometric series for those x for which the series converges. -
MAT 5930. Analysis for Teachers
MAT 5930. Analysis for Teachers. Wm C Bauldry [email protected] Fall ’13 Wm C Bauldry ([email protected]) MAT 5930. Analysis for Teachers. Fall ’13 1 / 147 Nordkapp, Norway. Today Wm C Bauldry ([email protected]) MAT 5930. Analysis for Teachers. Fall ’13 2 / 147 Introduction and Calculus Considered 1 Course Introduction (Class page, Course Info, Syllabus) 2 Calculus Considered 1 A Standard Freshman Calculus Course B Topics List: MAT 1110; MAT 1120 B Refer to texts by Thomas (traditional), Stewart (very popular, but. ), and Hughes-Hallett, et al, or Ostebee & Zorn (“reform”). B Historical: L’Hopital’sˆ Analyse des Infiniment Petits pour l’Intelligence des Lignes Courbes, Cauchy’s Cours d’Analyse, and Granville, Smith, & Longley’s Elements of the Differential and Integral Calculus 2 An AP Calculus Course(AB,BC) 1 Functions, Graphs, and Limits Representations, one-to-one, onto, inverses, analysis of graphs, limits of functions, asymptotic behavior, continuity, uniform continuity 2 Derivatives Concept, definitions, interpretations, at a point, as a function, second derivative, applications, computation, numerical approx. 3 Integrals Concept, definitions, interpretations, properties, Fundamental Theorem, applications, techniques, applications, numerical approx. Wm C Bauldry ([email protected]) MAT 5930. Analysis for Teachers. Fall ’13 3 / 147 Calculus Considered 2 (Calculus Considered) 3 Calculus Problems x1 Precalculus material: function, induction, summation, slope, trigonometry x2 Limits and Continuity: Squeeze Theorem, discontinuity, removable discontinuity, different interpretations of limit expressions x3 Derivatives: trigonometric derivatives, power rule, indirect methods, Newton’s method, Mean Value Theorem,“Racetrack Principle” x4 Integration: Fundamental Theorem, Riemann sums, parts, multiple integrals x5 Infinite Series: geometric, integrals and series, partial fractions, convergence tests (ratio, root, comparison, integral), Taylor & Maclaurin Wm C Bauldry ([email protected]) MAT 5930. -
MATH 162: Calculus II Differentiation
MATH 162: Calculus II Framework for Mon., Jan. 29 Review of Differentiation and Integration Differentiation Definition of derivative f 0(x): f(x + h) − f(x) f(y) − f(x) lim or lim . h→0 h y→x y − x Differentiation rules: 1. Sum/Difference rule: If f, g are differentiable at x0, then 0 0 0 (f ± g) (x0) = f (x0) ± g (x0). 2. Product rule: If f, g are differentiable at x0, then 0 0 0 (fg) (x0) = f (x0)g(x0) + f(x0)g (x0). 3. Quotient rule: If f, g are differentiable at x0, and g(x0) 6= 0, then 0 0 0 f f (x0)g(x0) − f(x0)g (x0) (x0) = 2 . g [g(x0)] 4. Chain rule: If g is differentiable at x0, and f is differentiable at g(x0), then 0 0 0 (f ◦ g) (x0) = f (g(x0))g (x0). This rule may also be expressed as dy dy du = . dx x=x0 du u=u(x0) dx x=x0 Implicit differentiation is a consequence of the chain rule. For instance, if y is really dependent upon x (i.e., y = y(x)), and if u = y3, then d du du dy d (y3) = = = (y3)y0(x) = 3y2y0. dx dx dy dx dy Practice: Find d x d √ d , (x2 y), and [y cos(xy)]. dx y dx dx MATH 162—Framework for Mon., Jan. 29 Review of Differentiation and Integration Integration The definite integral • the area problem • Riemann sums • definition Fundamental Theorem of Calculus: R x I: Suppose f is continuous on [a, b]. -
CALCULUS HANDOUT 6 - RIEMANN-DARBOUX INTEGRAL - Definitions
CALCULUS HANDOUT 6 - RIEMANN-DARBOUX INTEGRAL - definitions THE RIEMANN DARBOUX INTEGRAL A partition P of the interval [a; b] is a finite set of points fx0; x1; ::; xng satisfying a = x0 < x1 < :: < xn = b. Consider a function f defined and bounded on [a; b]. n X Upper Darboux sum of f related to P : Uf (P ) = Mi(xi − xi−1) where Mi = sup f(x). i=1 xi−1≤x≤xi n X Lower Darboux sum of f related to P : Lf (P ) = mi(xi − xi−1) where mi = inf f(x). xi−1≤x≤xi i=1 Consider M = supff(x) j a ≤ x ≤ bg and m = infff(x) j a ≤ x ≤ bg. For any partition P of [a; b] we have: m(b − a) ≤ Lf (P ) ≤ Uf (P ) ≤ M(b − a). Lf = fLf (P ) j P is a partition of [a; b]g and Uf = fUf (P ) j P is a partition of [a; b]g are bounded sets. So Lf = sup Lf and Uf = inf Uf exist. Moreover, Lf ≤ Uf . A function defined and bounded on [a; b] is Riemann-Darboux integrable on [a; b] if Lf = Uf . Z b This common value is denoted by f(x) dx = Lf = Uf . a Properties of the Riemann-Darboux integral: If f and g are Riemann-Darboux integrable on [a; b] then all the integrals below exist and Z b Z b Z b (1) (α f(x) + β g(x)) dx = α f(x) dx + β g(x) dx for any α; β 2 R: a a a Z b Z c Z b (2) f(x) dx = f(x) dx + f(x) dx for any a ≤ c ≤ b. -
Calculus 141 Section 9.6 Lecture Notes
Calculus 141, section 9.6 Ratio Test and Root Tests notes by Tim Pilachowski ∞ c r m ● The geometric series ∑ c r n = if and only if r <1. n = m 1 − r ∞ 1 ● The p-series converges whenever p > 1 and diverges whenever 0 < p ≤ 1. ∑ p n =1 n ∞ ∞ ● The Integral Test states a series a converges if and only if f ()x dx converges. ∑ n ∫1 n =1 ∞ ● In the Direct Comparison Test, ∑ an converges if its terms are less than those of a known convergent n =1 series, and diverges if its terms are greater than those of a known convergent series. ∞ an ● The Limit Comparison Test states: If lim exists and is a positive number, then positive series ∑ an n → ∞ bn n =1 ∞ and ∑ bn either both converge or both diverge. n =1 A downside to the Comparison Tests is that they require a suitable series to use for the comparison. In contrast, the Ratio Test and the Root Test require only the series itself. ∞ ∞ an+1 Ratio Test (Theorem 9.15) Given a positive series an for which lim = r : a. If 0 ≤ r < 1, then an ∑ n→∞ ∑ n =1 an n =1 ∞ an+1 converges. b. If r > 1, then an diverges. c. If r = 1 or lim does not exist, no conclusion. ∑ n→∞ n =1 an The proof of part a. relies upon the definition of limits and the “creation” of a geometric series which converges to which we compare our original series. Briefly, by the nature of inequalities there exists a value s for which an+1 0 ≤ r < s < 1. -
MATH 166 TEST 3 REVIEW SHEET General Comments and Advice
MATH 166 TEST 3 REVIEW SHEET General Comments and Advice: The student should regard this review sheet only as a sample of potential test problems, and not an end-all-be-all guide to its content. Anything and everything which we have discussed in class is fair game for the test. The test will cover roughly Sections 10.1, 10.2, 10.3, 10.4, and 10.5. Don't limit your studying to this sheet; if you feel you don't fully understand a particular topic, then try to do more problems out of your textbook! Summary of Relative Growth Rates. For two sequences (an) and (bn) such that (an) ! 1 and (bn) ! 1, let the symbols (an) << (bn) denote that (bn) grows faster than (an). Then the following is a summary of our most commonly encountered growth rates: (ln n) << ((ln n)r) << (nq) << (n) << (np) << (bn) << (n!) << (nn), where r > 1, 0 < q < 1, p > 1, and b > 1. General Strategy for Determining Convergence of a Series. There is no hard and fast rule for determining whether a series converges or diverges, and in general the student should build up their own intuition on the subject through practice. However, the following mental checklist can be a helpful guideline. 1 X (1) Divergence Test. Given a series an, the first thing one should always n=1 ask is, do the terms (an) ! 0? If not, we are done and the series diverges by the DT. If the terms do shrink to zero, however, we have to put more thought into the problem. -
Chapter 10 Multivariable Integral
Chapter 10 Multivariable integral 10.1 Riemann integral over rectangles Note: ??? lectures As in chapter chapter 5, we define the Riemann integral using the Darboux upper and lower inte- grals. The ideas in this section are very similar to integration in one dimension. The complication is mostly notational. The differences between one and several dimensions will grow more pronounced in the sections following. 10.1.1 Rectangles and partitions Definition 10.1.1. Let (a ,a ,...,a ) and (b ,b ,...,b ) be such that a b for all k. A set of 1 2 n 1 2 n k ≤ k the form [a ,b ] [a ,b ] [a ,b ] is called a closed rectangle. In this setting it is sometimes 1 1 × 2 2 ×···× n n useful to allow a =b , in which case we think of [a ,b ] = a as usual. If a <b for all k, then k k k k { k} k k a set of the form(a 1,b 1) (a 2,b 2) (a n,b n) is called an open rectangle. × ×···× n For an open or closed rectangle R:= [a 1,b 1] [a 2,b 2] [a n,b n] R or R:= (a 1,b 1) n × ×···× ⊂ × (a2,b 2) (a n,b n) R , we define the n-dimensional volume by ×···× ⊂ V(R):= (b a )(b a ) (b a ). 1 − 1 2 − 2 ··· n − n A partition P of the closed rectangle R=[a ,b ] [a ,b ] [a ,b ] is afinite set of par- 1 1 × 2 2 ×···× n n titions P1,P2,...,Pn of the intervals [a1,b 1],[a 2,b 2],...,[a n,b n]. -
The Direct Comparison Test (Day #1)
9.4--The Direct Comparison Test (day #1) When applying the Direct Comparison Test, you will usually compare a tricky series against a geometric series or a p-series whose convergence/divergence is already known. Use the Direct Comparison Test to determine the convergence or divergence of the series: ∞ 1) 1 3 n + 7 n=1 9.4--The Direct Comparison Test (day #1) Use the Direct Comparison Test to determine the convergence or divergence of the series: ∞ 2) 1 n - 2 n=3 Use the Direct Comparison Test to determine the convergence or divergence of the series: ∞ 3) 5n n 2 - 1 n=1 9.4--The Direct Comparison Test (day #1) Use the Direct Comparison Test to determine the convergence or divergence of the series: ∞ 4) 1 n 4 + 3 n=1 9.4--The Limit Comparison Test (day #2) The Limit Comparison Test is useful when the Direct Comparison Test fails, or when the series can't be easily compared with a geometric series or a p-series. 9.4--The Limit Comparison Test (day #2) Use the Limit Comparison Test to determine the convergence or divergence of the series: 5) ∞ 3n2 - 2 n3 + 5 n=1 Use the Limit Comparison Test to determine the convergence or divergence of the series: 6) ∞ 4n5 + 9 10n7 n=1 9.4--The Limit Comparison Test (day #2) Use the Limit Comparison Test to determine the convergence or divergence of the series: 7) ∞ 1 n 4 - 1 n=1 Use the Limit Comparison Test to determine the convergence or divergence of the series: 8) ∞ 5 3 2 n - 6 n=1 9.4--Comparisons of Series (day #3) (This is actually a review of 9.1-9.4) page 630--Converging or diverging? Tell which test you used. -
Direct and Limit Comparison Tests
Joe Foster Direct and Limit Comparison Tests We have seen that a given improper integral converges if its integrand is less than the integrand of another integral known to converge. Similarly, a given improper integral diverges if its integrand is greater than the integrand of another integral known to diverge. We now apply the same idea to infinite series instead. Direct Comparison Test for Series: If0 a b for all n N, for some N, then, ≤ n ≤ n ≥ ∞ ∞ 1. If bn converges, then so does an. nX=1 nX=1 ∞ ∞ 2. If an diverges, then so does bn. nX=1 nX=1 a The Limit Comparison Test: Suppose a > 0 and b > 0 for all n. If lim n = L, where L is finite and L> 0, then n n →∞ n bn the two series an and bn either both converge or both diverge. X X ∞ 1 Example 1: Determine whether the series converges or diverges. 2n + n nX=1 1 1 We have for all n 1. So, 2n + n ≤ 2n ≥ ∞ ∞ 1 1 . 2n + n ≤ 2n nX=1 nX=1 1 Since the series on the right is a geometric series with r = , it converges. So we determine that our series of interest also 2 converges. ∞ 1 Example 2: Determine whether the series converges or diverges. n2 + n +1 nX=1 1 1 We have for all n 1. So, n2 + n +1 ≤ n2 ≥ ∞ ∞ 1 1 . n2 + n +1 ≤ n2 nX=1 nX=1 Since the series on the right is a p series with p = 2 > 1, it converges. -
Comparison Tests for Integrals
Joe Foster Direct and Limit Comparison Tests Tests for Convergence: When we cannot evaluate an improper integral directly, we try to determine whether it con- verges of diverges. If the integral diverges, we are done. If it converges we can use numerical methods to approximate its value. The principal tests for convergence or divergence are the Direct Comparison Test and the Limit Comparison Test. Direct Comparison Test for Integrals: If0 ≤ f(x) ≤ g(x) on the interval (a, ∞], where a ∈ R, then, ∞ ∞ 1. If g(x) dx converges, then so does f(x) dx. ˆa ˆa ∞ ∞ 2. If f(x) dx diverges, then so does g(x) dx. ˆa ˆa Why does this make sense? 1. If the area under the curve of g(x) is finite and f(x) is bounded above by g(x) (and below by 0), then the area under the curve of f(x) must be less than or equal to the area under the curve of g(x). A positive number less that a finite number is also finite. 2. If the area under the curve of f(x) is infinite and g(x) is bounded below by f(x), then the area under the curve of g(x) must be “less than or equal to” the area under the curve of g(x). Since there is no finite number “greater than” infinity, the area under g(x) must also be infinite. Example 1: Determine if the following integral is convergent or divergent. ∞ cos2(x) 2 dx. ˆ2 x cos2(x) cos2(x) We want to find a function g(x) such that for some a ∈ R, f(x)= ≤ g(x) or f(x)= ≥ g(x) for all x ≥ a. -
Math Flow Chart
Updated November 12, 2014 MATH FLOW CHART Grade 6 Grade 7 Grade 8 Grade 9 Grade 10 Grade 11 Grade 12 Calculus Advanced Advanced Advanced Math AB or BC Algebra II Algebra I Geometry Analysis MAP GLA-Grade 8 MAP EOC-Algebra I MAP - ACT AP Statistics College Calculus Algebra/ Algebra I Geometry Algebra II AP Statistics MAP GLA-Grade 8 MAP EOC-Algebra I Trigonometry MAP - ACT Math 6 Pre-Algebra Statistics Extension Extension MAP GLA-Grade 6 MAP GLA-Grade 7 or or Algebra II Math 6 Pre-Algebra Geometry MAP EOC-Algebra I College Algebra/ MAP GLA-Grade 6 MAP GLA-Grade 7 MAP - ACT Foundations Trigonometry of Algebra Algebra I Algebra II Geometry MAP GLA-Grade 8 Concepts Statistics Concepts MAP EOC-Algebra I MAP - ACT Geometry Algebra II MAP EOC-Algebra I MAP - ACT Discovery Geometry Algebra Algebra I Algebra II Concepts Concepts MAP - ACT MAP EOC-Algebra I Additional Full Year Courses: General Math, Applied Technical Mathematics, and AP Computer Science. Calculus III is available for students who complete Calculus BC before grade 12. MAP GLA – Missouri Assessment Program Grade Level Assessment; MAP EOC – Missouri Assessment Program End-of-Course Exam Mathematics Objectives Calculus Mathematical Practices 1. Make sense of problems and persevere in solving them. 2. Reason abstractly and quantitatively. 3. Construct viable arguments and critique the reasoning of others. 4. Model with mathematics. 5. Use appropriate tools strategically. 6. Attend to precision. 7. Look for and make use of structure. 8. Look for and express regularity in repeated reasoning. Linear and Nonlinear Functions • Write equations of linear and nonlinear functions in various formats.