Hindawi Publishing Corporation Journal of Function Spaces and Applications Volume 2013, Article ID 925742, 5 pages http://dx.doi.org/10.1155/2013/925742
Research Article Homotopy Characterization of ANR Function Spaces
Jaka Smrekar
Fakulteta za Matematiko in Fiziko, Jadranska Ulica 19, 1111 Ljubljana, Slovenia
Correspondence should be addressed to Jaka Smrekar; [email protected]
Received 5 May 2013; Accepted 25 August 2013
Academic Editor: Yongsheng S. Han
Copyright Β© 2013 Jaka Smrekar. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
π Let π be an absolute neighbourhood retract (ANR) for the class of metric spaces and let π be a topological space. Let π denote the space of continuous maps from π to π equipped with the compact open topology. We show that if π is a compactly generated π π Tychonoff space and π is not discrete, then π is an ANR for metric spaces if and only if π is hemicompact and π has the homotopy typeofaCWcomplex.
1. Introduction over the convergent sequence {0,1,1/2,1/3,...}.ThenπΉ is contractible; that is, it has the homotopy type of a one-point Let π be an absolute neighbourhood retract for metric spaces CW complex. But as πΉ is not locally path connected, it is not (henceforth abbreviated as βANRβ). This means that when- an ANR. ever π is embedded in a metric space as a closed subspace On the other hand, Cauty [4]showedthatametrizable πΜ, there exists a retraction of an open neighbourhood onto space is an ANR if and only if each open subspace has πΜ. We refer the reader to the first part of MardeΛsic[Β΄ 1]fora the homotopy type of a CW complex. It turns out that the scenic survey of the theory of ANRs. space of functions into an ANR inherits a good deal of π reasonable behaviour from the target space. Thus, under mild Let be a topological space. The question that this paper π ππ restrictions on π,ifπ is an ANR and π is a metrizable space is concerned with is when is , the space of continuous π πβπ with the homotopy type of a CW complex, π is in fact an functions , equipped with the compact open π ANR. Put another way, π is an ANR if and only if π is an topology, also an ANR. A basic result of Kuratowski (see [2, π page 284]), which is a consequence of the classical homotopy ANR and π is a metrizable space with the homotopy type of π extension theorem of Borsuk, states that π is an ANR if π is an ANR. ametrizablecompactum. Basic Definitions and Conventions. A topological space π is For a negative example, consider the discrete space of π N {0, 1} called hemicompact if is the union of countably many natural numbers and the two-point discrete ANR . {πΎ |π} {0, 1}N of its compact subsets π which dominate all compact Then is a Cantor set and hence certainly not an ANR. subsets in π. This means that for each compact πΆβπthere {0, 1}N In fact, as the path components of are not open, it does exists π with πΆβπΎπ. (The perhaps somewhat noninformative not even have the homotopy type of a CW complex; that is, word βhemicompactβ was introduced by Arens [5]inrelation it is not homotopy equivalent to any CW complex. As every to metrizability of function spaces. See the beginning of ANR has the homotopy type of a CW complex, this provides π Section 2.) anecessaryconditionforπ to be an ANR. Aspaceπ is compactly generated if the compact sub- In fact, a topological space has the homotopy type of spaces determine its topology. That is, a subset π΄ is closed an ANR if and only if it has the homotopy type of a CW in π if and only if π΄β©πΆis closed in πΆ for each compact complex(seeMilnor[3,Theorem2]).However,thereare subspace πΆ. Such spaces are also commonly called π-spaces numerousexamplesofspacesthathaveCWhomotopytype (see, e.g., Willard [6]). We do not require a hemicompact or but are not ANRs. For example, let πΉ be the topological cone a compactly generated space to be Hausdorff. 2 Journal of Function Spaces and Applications
Aspaceπ is Tychonoff if it is both completely regular and continuous function π΄βπ,whereπ΄ is a closed subspace of Hausdorff. Locally compact Hausdorff spaces and normal a metric space, extends continuously over a neighbourhood Hausdorff spaces are Tychonoff (examples of the latter are all of π΄. metric spaces and all CW complexes). Note that if π is a hemicompact space with the sequence The terms map and continuous function will be used of βdistinguishedβ compact sets {πΎπ}, the map into the synonymously. countable Cartesian product σΈ Amapπ:π βπ is a homotopy equivalence if there π:πσΈ βπ β exists a map (called a homotopy inverse) π πΎπ π σ³¨β βπ , defined by π σ³¨σ³¨β { π| πΎ } (β) for which the composites πβπand πβπare homotopic to π σΈ π=1 their respective identities. In this case, π and π are called σΈ homotopy equivalent,andwesaythatπ has the homotopy is an embedding (see also Cauty [12]). Consequently, if ππ type of π. πΎπ denotes the supmetric on π induced by a metric on π,then The following are our main results. π π is metrizable by the metric Theorem 1. π Let be a compactly generated hemicompact β π ππ 1 space and let be an ANR. Then is an ANR if and only π(π,π)=β min { ,ππ (π|πΎ ,π|πΎ )} . (ββ) π 2π π π if π has the homotopy type of an ANR, which is if and only if π=1 it has the homotopy type of a CW complex. (See Arens [5,Theorem7].)Giventhehypothesesof We call a (not necessarily Hausdorff) space locally com- Theorem 1, therefore, we need to show that for every pair pact if each point is contained in the interior of a compact (π, π΄) with π metric and π΄ closed in π,everycontinuous π set. It is well-known that compactly generated spaces are pre- function π:π΄ βπ extends continuously over a cisely quotient spaces of locally compact spaces. Compactly neighbourhood of π΄ in π. We need some preliminary results. generated hemicompact spaces seem to be important enough First, we state the classical exponential correspondence to warrant an analogous characterization. In the appendix, theorem with minimal hypotheses. Here, a space is regular we prove that they arise as nice quotient spaces of π-compact if points can be separated from closed sets by disjoint open locally compact spaces. sets. Assuming additional separation properties, Theorem 1 canbestrengthenedasfollows. Proposition 3. Let π, π,andπ be topological spaces. Let π π:π βπ be any function with set-theoretic adjoint Corollary 2. Let π be a compactly generated Tychonoff space π:πΓπβΜ π πΜ π π .If is continuous, then is (well-defined and let π be an ANR which contains an arc. Then π is an ANR π π and) continuous. For the converse, suppose that is locally if and only if π is hemicompact and π has the homotopy type compact. If π is continuous and, in addition, π is regular or Μ of a CW complex. π is regular, then π is continuous. This accounts for a bijection (ππ)π βπ(πΓπ) Theorem 1 is a considerable extension of Theorem 1.1 . of [7] where the equivalence was proved using a different Proof. The requirement that π be regular is standard. (See, technique under the more stringent requirement that π be e.g., [13, Corollary 2.100].) We prove that the continuity of π a countable CW complex. Our proof of Theorem 1 leans Μ implies that of π if π is locally compact and π is regular, as it on Moritaβs homotopy extension theorem for π0-embeddings (see Morita [8]). is apparently not so standard. π π(π§Μ ,π₯ )=:π¦ Even when π is a countable CW complex, it is highly Suppose that is continuous and 0 0 0 lies in nontrivial to determine whether or not the function space theopensetπβπ.Asπ is regular, there is an open set π π has the homotopy type of a CW complex. The interested π with π¦0 βπβπβπ.Asπ is locally compact, π₯0 is reader is referred to papers [7, 9, 10] for more on this. contained in the interior of a compact set πΆ.Writeπ=π(π§0). β1 β1 Clearly, πΎ=π (π)β©πΆ is a compact set contained in π (π). This means that π(π§0) lies in the open set πΊ(πΎ,.As π) π is continuous, there is an open neighbourhood π of π§0 so that 2. Proof of Theorem 1 Μ π(π) β πΊ(πΎ,.Consequently, π) π(π Γ πΎ) βπ.Asπ₯0 lies in For subsets π΄ of the domain space and π΅ of the target space, Μ the interior of πΎ, π is continuous at (π§0,π₯0). we let πΊ(π΄, π΅) denote the set of all maps π that map the set π΄ into the set π΅. For topological spaces π and π,thestandard π π (π Γ π) π Definition 4. For any space ,let denote the subbasis of the compact open topology on π is the collection topological space whose underlying set is πΓπand has its π P of all πΊ(πΎ, π) βπ with πΎ a compact subset of π and π topology determined by the subsets πΓπΆ(with the Cartesian an open subset of π. product topology) where πΆ ranges over the compact subsets To prove Theorem 1, we use the fact that ANRs for metric of π.Thatis,πΉβπΓπis closed in π (π Γ π) if and only if spacesarepreciselythemetrizableabsoluteneighbourhood πΉ β© (π ΓπΆ) is closed in πΓπΆfor each compact subspace πΆ of extensors for metric spaces (abbreviated as βANEβ); see, for π. The identity π (π Γ π),wherethelatterhasthe βπΓπ example, Hu [11, Theorem 3.2]. A space π is an ANE if every Cartesian product topology, is evidently continuous. Journal of Function Spaces and Applications 3
β1 In the language of Dydak [14], π (π Γ π) has the covariant π:π β R with π΄=π (0).Ifπ΄ is a π-embedded zero set, topology on πΓπinduced by the class of set-theoretic it is called π0-embedded. inclusions πΓπΆσ³¨ βπΓπwhere πΆ ranges over the compact For example, every closed subset of a metrizable space is subsets of π and the πΓπΆcarry the product topology. π0-embedded. The introduction of the topology π (π Γ π) is motivated We need π-embeddings in the context of Moritaβs homo- by the following lemma. topy extension theorem (which in fact characterizes ANR spaces; see Stramaccia [15]). Lemma 5. Let π be any topological space, let π be a regular space, and let π be a compactly generated hemicompact space. Theorem 7 (Morita [8]). If π΄ is π0-embedded in the topolog- π Μ Let π:π βπ be a function with set-theoretic adjoint π: ical space π, then the pair (π, π΄) has the homotopy extension Μ π πΓπβπ.Thenπ is continuous if and only if π:π (πΓ property with respect to all ANR spaces. That is, if is an ANR, π:πΓ{0}βπ β:π΄Γ[0,1]β π π) β π (ππ)π β if and are continuous maps is continuous. This accounts for a bijection π΄Γ{0} ππ (πΓπ) that agree pointwise on , then there exists a continuous . map π»:πΓ[0,1]βextending π both π and β.
Proof. Let {πΎπ} be the sequence of distinguished compacta π πΎ Lemma 8. Let πΈ be a FrechetΒ΄ space and let π be a compactly π π :π βππ in and let π denote the map that to each generated hemicompact (not necessarily Hausdorff) space. function πβπassigns its restriction to πΎπ.Clearlyπ π is π π Then πΈ is also a FrechetΒ΄ space. continuous. If π:π βπ is continuous, then so is the πΎ π βπ:πβππ π composite π .ByProposition 3,soisits Proof. One verifies readily that πΈ is a topological vector π|Μ :πΓπΎ βπ πΆ πΊ(πΎ, π) π adjoint πΓπΎπ π . As each compact set is space and that the subbasic open sets ,where are contained in one of the πΎπ, it follows by definition of π (πΓπ) convex neighbourhoods of 0 in πΈ,constituteaconvexlocal Μ π that π:π (πΓπ)βis π continuous. base for πΈ (see Schaefer [16], page 80). If πΈ is metrizable (by Μ π For the converse, assume that π:π (πΓπ)βis π an invariant metric), then πΈ is metrizable by the (invariant) Μ π continuous. This means that the restrictions of π to subspaces metric (ββ) above. If πΈ is complete, then so is πΈ since π πΓπΎπ are continuous, and Proposition 3 implies that the is compactly generated (see, e.g., Willard [6,Theorem πΎπ composites π π βπ: π βπ are continuous. But as π is 43.11]). compactly generated, a function π:πis βπ continuous if π| :πΎ βπ Proposition 9. Let π΄ be π-embedded in π and let π be a and only if all restrictions πΎπ π are continuous. β πΎ compactly generated hemicompact space. Then the subset π΄Γπ πββ π π This means that the obvious map π=1 ,whose is π-embedded in π (π .Γ π) components are π π βπ, maps into the image of the embedding π (β) and therefore yields a continuous function πβπ AresultduetoAloandSennott(see[` 17,Theorem1.2]) which is precisely π. shows that π΄ is π-embedded in π if and only if every continuous function from π΄ to a FrechetΒ΄ space extends Lemma 6. πΎ Let be a compact regular space. The topologies continuously over π. Proposition 9 seems to be the right way π ((π Γ πΎ) Γπ) π (π Γ π) ΓπΎ and (viewed as topologies on of generalizing the equivalence (1) β (2)ofTheorem2.4in πΓπΓπΎ )coincide. [17]. For a closed subset π΄ of π,thetopologyπ (π΄Γπ) coincides We note that this is a corollary of the much more general with the topology that the set π΄Γπinherits from π (π .Γ π) Theorem 1.15 of Dydak [14]. (Since πΎ is compact regular, it For arbitrary π΄,thetwotopologiesmaydiffer,butnotethat is locally compact according to the definition in14 [ ].) For π (π΄ Γ π) is always finer than the subspace topology. the sake of completeness, we provide an independent proof (along slightly different lines). Proof. Let πΈ be a FrechetΒ΄ space and let π:π΄Γπbe βπΈ acontinuousmapwhereπ΄Γπis understood to inherit its Proof. We show that the two topologies have the same π (π Γ π) continuous maps into an arbitrary space π. By definition, topology from . Precomposing with the continuous π:π (πΓπΓπΎ)β π identity π (π΄ Γ π) βπ΄Γπ and using Lemma 5,weobtaina is continuous if and only if the π π π : πΓπΆΓπΎ βπ πΆβπ continuous map π΄βπΈ .ByLemma 8, πΈ is also a FrechetΒ΄ restrictions πΆ (for compact ) Μ are continuous which, by Proposition 3,isifandonlyiftheir space and as π΄ is π-embedded in π,thefunctionπ extends Μ πΎ πΉ:πΜ π βπΈ πΉΜ adjoints ππΆ :πΓπΆβ π are continuous. The latter is if continuously to . Reapplying Lemma 5, Μ πΎ πΉ:π (πΓπ)β πΈ and only if the map π:π (πΓπ)βπ is continuous induces the desired extension . π:π (πΓπ)ΓπΎ βπ π and this in turn if and only if Proof of Theorem 1. Let π be metrizable and let π:π΄ βπ is continuous, by another application of Proposition 3.This be a continuous map defined on the closed subset π΄ of π. π finishes the proof. By assumption, π has the homotopy type of an ANR; hence (π, π΄) π admits a neighbourhood extension up to homotopy. That Let be a topological pair (no separation properties π assumed). Then π΄ is π-embedded in π if continuous pseu- is, there exist a continuous map π:π βπ where π is π dometrics on π΄ extend to continuous pseudometrics on π. open and contains π΄ and a homotopy β:π΄Γ[0,1]β π Also, π΄ is a zero set in π if there exists a continuous function beginning in π|π΄ and ending in π. 4 Journal of Function Spaces and Applications
π Let ββπ : π΄Γ[0, 1]βͺπΓ{0} βπ denote the continuous Proof. Let π be a compactly generated hemicompact space Μ union of the two, with adjoint ββπΜ : π ((π΄ Γ [0, 1]βͺπΓ with its sequence of distinguished compact subsets {πΎπ} and {0}) Γ π) β π.Asπ΄Γ[0,1]βͺπΓ{0}is closed in π΄Γπ, let π denote the obvious surjective map from the disjoint Μ β πΎ =: π π π΄ π the map ββπΜ is continuous with respect to the topology that union π π to .Clearly,aset in is closed if and (π΄Γ[0,1]βͺπΓ{0})Γπinherits from π (πΓ[0,1]Γπ). Under only if π΄β©πΎπ is closed in πΎπ for all π.Thus,π is a quotient map. the homeomorphism π (π Γ [0, 1] Γ π) β π (π Γ π) Γ[0,1] Tautologically, π is both π-compact and locally compact, and Μ π of Lemma 6,themapββπΜ corresponds to a continuous map hemicompactness renders weakly proper. Μ For the reverse implication, suppose first that π is a π : π (π΄ Γ π) Γ [0, 1] βͺ π (π Γ π)Γ{0}βπ. π΄ π π΄Γπ compactly generated hemicompact space with distinguished Obviously, as is a zero set in ,theproduct is {πΏ } π:π βπ πΓπ compact subsets π and is a weakly a zero set in with respect to the Cartesian product π π π΄Γπ π (πΓπ) proper quotient map. Clearly, as is weakly proper, is topology. A fortiori, is a zero set in . {π(πΏ )} π΄Γπ π hemicompact with distinguished compact subsets π .To Hence, by Proposition 9,theset is 0-embedded in π π:π βπ π (π Γ π) Μπ πΎ:π (πΓ see that is compactly generated, let be a . Theorem 7 yields an extension of to function that is continuous on all compact sets. Hence, if πΏ π) Γ [0, 1] βπ. Reapplying Lemma 6 and Lemma 5, πΎ π πβπ π is a compact subset of , is continuous on the saturation induces a continuous function π:πΓ[0,1]β π .Level πβ1(π(πΏ)) π πΏ π 1 π .Consequently, is continuous on .Since is of this homotopy is a continuous extension of over the compactly generated, πβπis continuous and since π is a π ππ neighbourhood . Therefore, is an ANR. quotient map, so also is π.Sincethisholdsforallπ, π is Corollary 10. πΆ π compactly generated. If is a compact space and is an ANR, then Finally, suppose that π is a π-compact locally compact ππΆ is an ANR. space. Then π is compactly generated. (See, e.g., [6], 43.9.) π U ππΆ Since is locally compact, it has an open cover consisting Proof. By Theorem 3 of Milnor [3], has CW homotopy of relatively compact sets. As π is the union of countably type. many compact sets, U has a countable subcover {ππ|π = 1, 2, 3, . . .} πΏ =βͺπ π π= Corollary 10 was proved independently by Yamashita .Thesequenceofcompactsets π π=1 π, [18] (with the additional requirement that πΆ be Hausdorff) 1, 2, 3, . . ., exhibits π as hemicompact. This completes the but the author of this note has not seen it elsewhere for proof. nonmetrizable compacta πΆ.Fromthepointofviewofπ- embeddings, however, Corollary 10 encodes a long-known Acknowledgments fact (see PrzymusinskiΒ΄ [19,Theorem3]):ifπ΄ is π-embedded in π and π is a compact space, then π΄Γπis π-embedded in The author is grateful to Atsushi Yamashita for posing the πΓπ. question that has led to the results presented here and to π the referee for recommending that a characterization of Proof of Corollary 2. Suppose that π is metrizable. If π compactly generated hemicompact spaces in the sense of contains an arc (which is if and only if it has a nontrivial π Proposition A.1 be included in the paper. The author was path component), it follows that [0, 1] is metrizable. Since supported in part by the Slovenian Research Agency Grants π is a Tychonoff space, points in π canbeseparatedfrom P1-0292-0101 and J1-4144-0101. compact sets in π by means of continuous functions πβ [0, 1]. The proof of Theorem 8 of Arens [5] can be adapted almost verbatim to render π hemicompact. The statement of References Corollary 2 follows immediately from Theorem 1. [1] S. MardeΛsic,Β΄ βAbsolute neighborhood retracts and shape theory,β in History of Topology,I.M.James,Ed.,chapter9,pp.241β269, North-Holland, Amsterdam, Netherlands, 1999. Appendix [2] K. Kuratowski, βSur les espaces localement connexes et peaniens en dimensions n,β Fundamenta Mathematicae,vol.24,no.1,pp. A Characterization of Compactly Generated 269β287, 1935. 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