Winter 2013 Chem 254: Introductory Thermodynamics
Chapter 2: Internal Energy (U), Work (w), Heat (q), Enthalpy (H) ...... 13 Heat Capacities ...... 16 Calculating ΔU, ΔH, w, q in Ideal Gas ...... 18 Isothermal Compression ...... 21 Reversible Process (limiting process) ...... 22 Isothermal Expansion ...... 22
Chapter 2: Internal Energy (U), Work (w), Heat (q), Enthalpy (H)
Internal Energy (excludes motion and rotation of vessel)
Look at isolated part of universe
UUUsystem Environment Total = isolated
First law of thermodynamics: - Total U for isolated system is constant - Energy can be exchanged between various components - Energy forms can be interconverted Eg. Chemical En Heat Work
UUUtotal system environement 0
Chapter 2: Internal Energy, Work, Heat and Enthalpy 13
Winter 2013 Chem 254: Introductory Thermodynamics
Work In classical mechanics, move object a distance d with force F in direction of displacement is work N m = J
F mg dh w mgh (kg m s-2 m = N m = J)
h w mgd cos cos d h w mgd mgh d
General formula
w F dL Line integral
PV work (constant external pressure)
F m applies constant force P A F w mgh Fh ()() Ah P V V A ext 12
w Pext() V final V initial Joules, or L Bar (1 L Bar = 100 J)
Chapter 2: Internal Energy, Work, Heat and Enthalpy 14
Winter 2013 Chem 254: Introductory Thermodynamics
More general formula for PV work, P does not need to be constant V w f P dV V ext i Sign Convention : Work done on the system raises internal energy of system ( w 0) Work done by the system lowers the internal energy ( w 0)
Other forms of work: - electrical work wQ Q is charge in coulombs difference in potential (in Volts or J/C) Run a current over Q I t I is current (in Amps or C/s) w I t
Important: Work is associated with a process, with change. Work is transitory. You cannot say that a system contains that amount of energy or heat
Heat: associated with a process going from State 1 State 2
Usystem q w q is heat; w is the work
Heat is exchanged between system and environment
q 0: system loses energy q 0 : system gains energy qq system environment
note: TTsystem environment for heat to flow
Isolated system
Chapter 2: Internal Energy, Work, Heat and Enthalpy 15
Winter 2013 Chem 254: Introductory Thermodynamics
TTouter inner (regulate) So there is no flow of heat
UUsystem environment 0
Uinner 0
Beaker + Lab +… = environment (isolated) U 0; U 0 I II UU 0 I II Chemical Energy Butane + O CO H 2 2 2
Note : UII 0even if temperature increases! Why? Chemical energy of butane is converted to heat.
Heat Capacities
The amount of energy (heat) required to raise the temperature of 1 gram of substance by 1 oC. Heat capacity of water is 4.18 J/g K = 1 calorie
1) Heat capacity is dependent on heat Eg. 10 oC 11 oC and 80 oC 81 oC, require slightly different energies
2) At least 2 types of heat capacity
a) Keep volume constant CV
b) Keep pressure constant CP
3) Heat capacity is proportional to amount of substance
Molar heat capacities : CPm, ,CVm,
n moles : CV nC V, m , CP nC P, m
4) General formula Chapter 2: Internal Energy, Work, Heat and Enthalpy 16
Winter 2013 Chem 254: Introductory Thermodynamics
T q f C dT VVT i
If CV is constant over temperature range: T f Tf qV C V dT C V T C V T f T i T Ti i
qVV C() T
And qPP C() T
Which is larger CP or CV ? Relation for and for ideal gas?
VV ; TT 2121
U qP w q P P ext () V21 V PV nRT
U qP nR() T21 T qPP C T ; U qVV C T
CPV T C T nR T
CPV C nR or CCRP,, m V m
Therefore CP is larger than CV . At constant P , the system also does PV work when raising T . (analysis for ideal gas)
No work because V is constant
U qV w qV
UCT V
Bomb calorimetry
qsystem q surrounding C Calorimeter T V V V measure U reaction
Chapter 2: Internal Energy, Work, Heat and Enthalpy 17
Winter 2013 Chem 254: Introductory Thermodynamics
system surroundings qqPV system Calorimeter qP C V T measure system qHP reaction
True definition of Enthalpy
H U () PV PV PV2 2 PV 1 1 ; for PV1 1 PV 2 2 ; H U PV
At constant Pressure
H U PV2 2 PV 1 1 HUPV
H qPP w P V q P()() V P V
H qPP C T
Completely general :UH, are function of state specify TVP,,
UUTPVUTPV (,,)(,,)2 2 2 1 1 1 HHTPVHTPV (,,)(,,) 2 2 2 1 1 1
Change in UH, are the same for both paths Change in qw, are different for different paths
Calculating ΔU, ΔH, w, q in Ideal Gas
1) Calculating UH, is easy if T is known T UUT()] Uf CdTCT Tf CT T T V V Ti V f i i
UCT V for any process
HHT( ) .....
Chapter 2: Internal Energy, Work, Heat and Enthalpy 18
Winter 2013 Chem 254: Introductory Thermodynamics
HCT P for any process (if CP is constant)
We know CPV C nR
Special cases: Isothermal Process T is constant T 0 ; UH 0
2) Work: w P dV PV work only ext
- Constant V Vif V w 0 ; q qV U
Vf - Constant Pext w P dV P() V V ; q q H extV ext f i P i
Isothermal reversible process: (Reversible process: delicate, see later) 1 P nRT nRT is constant ext V
Vf dV V w nRT nRTln V f V Vi i V
Vf nRTln Vfi ln V nRT ln Vi
Vf w nRT ln Vi
3) Heat
Adiabatic process : q 0 by definition U q w; Uw
Adiabatic Reversible Process nRT q 0 , Uw, P ext V
Vf nRT U w dV V i V nRT nC dT dV Vm, V dT nR nC dV Vm, TV
Chapter 2: Internal Energy, Work, Heat and Enthalpy 19
Winter 2013 Chem 254: Introductory Thermodynamics
ffdT dV nC nR Vm, iiTV
TVff nCvm, ln nR ln TVii
Cvm, TVff ln ln RTVii For adiabatic reversible process: C TV C T P V C P vm, lnff ln OR Pm, lnf ln i OR lnf Pm, ln i RTVii RTPif VCPi V, m f
1)
R C TVVf R f f Vm, ln ln ln TCVVi V, m i i R
TVCVm, ff TVii
2)
C T nRT P Vm, lnff ln i R Ti P f nRT i T P ln f i TPif T P lnf ln i TPif C T P Vm, 1 lnf ln i RTPif CRVm, Tf Pi ln ln RTP if C T P Pm, lnf ln i RTPif
Chapter 2: Internal Energy, Work, Heat and Enthalpy 20
Winter 2013 Chem 254: Introductory Thermodynamics
Adiabatic Isobaric Process Constant external pressure AND q 0
Isothermal Compression
Constant external pressure w Pf V f V i 0 qw 0 (because U 0 because isothermal)
What is work in 2-step process?
w2 P int V int Vi P f V f V int
ww21 ; qq21
Chapter 2: Internal Energy, Work, Heat and Enthalpy 21
Winter 2013 Chem 254: Introductory Thermodynamics
Conclusion: w and q depend on details of process, not only on initial and final state.
Repeat for 3 step, 4….
w5 w 4 w 3 w 2 w 1 ; q5 q 4 q 3 q 2 q 1 The more steps, the less w and less heat
Reversible Process (limiting process)
PPext gas at each step nRT P ext V Isothermal Reversible Process
VVffdV w P dV nRT VVext iiV V nRTln |Vf nRT ln f work, q is minimal Vi Vi
Isothermal Expansion
Chapter 2: Internal Energy, Work, Heat and Enthalpy 22
Winter 2013 Chem 254: Introductory Thermodynamics
w1 Pf V f V i 0 ;
qw11 0
ww ; qq 21 21
w3 w 2 w 1 ; q3 q 2 q 1
More processes more work ( w ), more heat ( q )
w5 w 4 w 3 w 2 w 1 ; q5 q 4 q 3 q 2 q 1
Limiting Expansion Work compressionexp ansion wwlimit limit
VVffdV V w P dV nRT nRT ln f limit VVext ii VVi
Chapter 2: Internal Energy, Work, Heat and Enthalpy 23
Winter 2013 Chem 254: Introductory Thermodynamics
Grains of sand : I can run process either way The thermodynamic work is the same both ways for reversible process
Irreversible Process (Big chunks of mass)
Follows arrows in reverse: add mass, piston rises? ; removes mass, piston lowers?
This is absurd, hence: Why do irreversible processes run in one way and not another? What is special about irreversible?
Chapter 2: Internal Energy, Work, Heat and Enthalpy 24