arXiv:hep-ph/0306015v1 2 Jun 2003 eu antcfield magnetic neous h aitna o h neato famgei moment magnetic a of interaction electron the by for Hamiltonian surrounded The nucleus a or nucleus a bare is study a to either quantity for important us destro an be without particular, can composites In molecular molecule. it and weak, atomic is atom about interaction the learn magnetic where the media an Since the atoms located. with within composites particles (molecular) bound additi atomic of In interactions constants. about fundamental learn particles on of information properties important electromagnetic of Investigation words: Key objects. and other free some of moment as well magnetic a as for deuteron consequences their the and to atom corrections order higher consider We Abstract hc orsod oasi rcsinfrequency precession spin a to corresponds which PACS: atoms Two-body a rpitsbitdt leirSine1Fbur 2008 February 1 Science Elsevier to submitted Preprint .I edle nttt o erlg VIM,S.Peters St. (VNIIM), Metrology for Institute Mendeleev I. D. mi address: Email hν H magn aeyG Karshenboim G. Savely 22.s 42.h 13.v 32.10.Dk 31.30.Jv, 14.20.Dh, 12.20.Ds, spin b a-lnkIsiu ¨rQatnpi,878Grhn,G Garching, 85748 f¨ur Quantenoptik, Max-Planck-Institut = = ula antcmmns unu electrodynamics, Quantum moments, magnetic Nuclear c µ I − ukv bevtr,164,S.Ptrbr,Russia Petersburg, St. 196140, Observatory, Pulkovo , B µ [email protected] · B h atro proton of factor g The B , a elkonform known well a has Svl .Karshenboim). G. (Savely a , b n ldmrG Ivanov G. Vladimir and g atro on rtni hydrogen in proton bound a of factor n uliprovides nuclei and ug180,Russia 198005, burg antcmoment magnetic µ on rtnand proton bound n n a also can one on, igteao or atom the ying neatosof interactions d da rb to probe a as ed s. ihahomoge- a with ermany mlcl)is (molecule) g factor, c , a (1) (2) where I is the related spin equal to either 1/2 or 1 for particles and nuclei under consideration in this paper. Comparison of the frequencies related to two different objects allows to exclude the magnetic field B from equations and to determine the ratio of their magnetic moments with an accuracy sometimes substantially higher than that in the determination of the applied magnetic field.
To measure the magnetic moment of a given nucleus one has to compare it with a value of some probe magnetic moment, which should be known or determined separately. For a significant number of most accurate measurements the probe value is related to the magnetic moment of a free or bound proton and a crucial experiment on its determination is related to a proton bound in hydrogen atom [1,2]. Nuclear magnetic moments are usually presented in units of nuclear magneton (µN ) [3,4], which is related to the proton magnetic moment via the relation
1 µ = g µ , (3) p 2 p N
where gp is the proton g factor and µN = eh/¯ 2mp.
The spin precession frequency was studied not only for a free proton, but also for the one bound in atoms or molecules located in gaseous or liquid media. The magnetic moment and the g factor of a bound proton differ from their free values (see e.g. [5,6]). The purpose of this paper is to re-evaluate in part available experimental data for light atoms and in particular to determine the g factor of a free proton (gp) and a proton bound in the ground state of hydrogen atom (gp(H)) from experiment [2]. We also study the consequences of re-evaluaton of gp and similar experiments for deuterium [7] and muonium [8].
The most accurate determination of the g factor of a free proton was performed studying the hyperfine structure of the hydrogen atom in the homogeneous magnetic field. The dependence of hyperfine sublevels of the ground state in the hydrogen atom on the value of the magnetic field B directed along the z axis is shown in Fig. 1 (see e.g. [6]). The energies of hyperfine components Emagn(F, Fz) of the 1s state are described by
1 − 1 Emagn(1, +1)= 2 (Ee Ep)+ 4 Ehfs , 1 2 2 1 Emagn(1, 0) = (Ee + Ep) + E − Ehfs , 2 hfs 4 (4) − −q1 − 1 Emagn(1, 1)= 2 (Ee Ep)+ 4 Ehfs , − 1 2 2 − 1 Emagn(0, 0) = 2 (Ee + Ep) + Ehfs 4 Ehfs , q
2 F =1 z F =0 z
F=1
F =-1 F=0 z
F =0 z