Creo: Hole Tutorial By: Matthew Jourden Brighton High School
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Mutations That Separate the Functions of the Proofreading Subunit of the Escherichia Coli Replicase
G3: Genes|Genomes|Genetics Early Online, published on April 15, 2015 as doi:10.1534/g3.115.017285 Mutations that separate the functions of the proofreading subunit of the Escherichia coli replicase Zakiya Whatley*,1 and Kenneth N Kreuzer*§ *University Program in Genetics & Genomics, Duke University, Durham, NC 27705 §Department of Biochemistry, Duke University Medical Center, Durham, NC 27710 1 © The Author(s) 2013. Published by the Genetics Society of America. Running title: E. coli dnaQ separation of function mutants Keywords: DNA polymerase, epsilon subunit, linker‐scanning mutagenesis, mutation rate, SOS response Corresponding author: Kenneth N Kreuzer, Department of Biochemistry, Box 3711, Nanaline Duke Building, Research Drive, Duke University Medical Center, Durham, NC 27710 Phone: 919 684 6466 FAX: 919 684 6525 Email: [email protected] 1 Present address: Department of Biology, 300 N Washington Street, McCreary Hall, Campus Box 392, Gettysburg College, Gettysburg, PA 17325 Phone: 717 337 6160 Fax: 7171 337 6157 Email: [email protected] 2 ABSTRACT The dnaQ gene of Escherichia coli encodes the ε subunit of DNA polymerase III, which provides the 3’ 5’ exonuclease proofreading activity of the replicative polymerase. Prior studies have shown that loss of ε leads to high mutation frequency, partially constitutive SOS, and poor growth. In addition, a previous study from our lab identified dnaQ knockout mutants in a screen for mutants specifically defective in the SOS response following quinolone (nalidixic acid) treatment. To explain these results, we propose a model whereby in addition to proofreading, ε plays a distinct role in replisome disassembly and/or processing of stalled replication forks. -
Lesson 3: Rectangles Inscribed in Circles
NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 3 M5 GEOMETRY Lesson 3: Rectangles Inscribed in Circles Student Outcomes . Inscribe a rectangle in a circle. Understand the symmetries of inscribed rectangles across a diameter. Lesson Notes Have students use a compass and straightedge to locate the center of the circle provided. If necessary, remind students of their work in Module 1 on constructing a perpendicular to a segment and of their work in Lesson 1 in this module on Thales’ theorem. Standards addressed with this lesson are G-C.A.2 and G-C.A.3. Students should be made aware that figures are not drawn to scale. Classwork Scaffolding: Opening Exercise (9 minutes) Display steps to construct a perpendicular line at a point. Students follow the steps provided and use a compass and straightedge to find the center of a circle. This exercise reminds students about constructions previously . Draw a segment through the studied that are needed in this lesson and later in this module. point, and, using a compass, mark a point equidistant on Opening Exercise each side of the point. Using only a compass and straightedge, find the location of the center of the circle below. Label the endpoints of the Follow the steps provided. segment 퐴 and 퐵. Draw chord 푨푩̅̅̅̅. Draw circle 퐴 with center 퐴 . Construct a chord perpendicular to 푨푩̅̅̅̅ at and radius ̅퐴퐵̅̅̅. endpoint 푩. Draw circle 퐵 with center 퐵 . Mark the point of intersection of the perpendicular chord and the circle as point and radius ̅퐵퐴̅̅̅. 푪. Label the points of intersection . -
Squaring the Circle a Case Study in the History of Mathematics the Problem
Squaring the Circle A Case Study in the History of Mathematics The Problem Using only a compass and straightedge, construct for any given circle, a square with the same area as the circle. The general problem of constructing a square with the same area as a given figure is known as the Quadrature of that figure. So, we seek a quadrature of the circle. The Answer It has been known since 1822 that the quadrature of a circle with straightedge and compass is impossible. Notes: First of all we are not saying that a square of equal area does not exist. If the circle has area A, then a square with side √A clearly has the same area. Secondly, we are not saying that a quadrature of a circle is impossible, since it is possible, but not under the restriction of using only a straightedge and compass. Precursors It has been written, in many places, that the quadrature problem appears in one of the earliest extant mathematical sources, the Rhind Papyrus (~ 1650 B.C.). This is not really an accurate statement. If one means by the “quadrature of the circle” simply a quadrature by any means, then one is just asking for the determination of the area of a circle. This problem does appear in the Rhind Papyrus, but I consider it as just a precursor to the construction problem we are examining. The Rhind Papyrus The papyrus was found in Thebes (Luxor) in the ruins of a small building near the Ramesseum.1 It was purchased in 1858 in Egypt by the Scottish Egyptologist A. -
Geometry Course Outline
GEOMETRY COURSE OUTLINE Content Area Formative Assessment # of Lessons Days G0 INTRO AND CONSTRUCTION 12 G-CO Congruence 12, 13 G1 BASIC DEFINITIONS AND RIGID MOTION Representing and 20 G-CO Congruence 1, 2, 3, 4, 5, 6, 7, 8 Combining Transformations Analyzing Congruency Proofs G2 GEOMETRIC RELATIONSHIPS AND PROPERTIES Evaluating Statements 15 G-CO Congruence 9, 10, 11 About Length and Area G-C Circles 3 Inscribing and Circumscribing Right Triangles G3 SIMILARITY Geometry Problems: 20 G-SRT Similarity, Right Triangles, and Trigonometry 1, 2, 3, Circles and Triangles 4, 5 Proofs of the Pythagorean Theorem M1 GEOMETRIC MODELING 1 Solving Geometry 7 G-MG Modeling with Geometry 1, 2, 3 Problems: Floodlights G4 COORDINATE GEOMETRY Finding Equations of 15 G-GPE Expressing Geometric Properties with Equations 4, 5, Parallel and 6, 7 Perpendicular Lines G5 CIRCLES AND CONICS Equations of Circles 1 15 G-C Circles 1, 2, 5 Equations of Circles 2 G-GPE Expressing Geometric Properties with Equations 1, 2 Sectors of Circles G6 GEOMETRIC MEASUREMENTS AND DIMENSIONS Evaluating Statements 15 G-GMD 1, 3, 4 About Enlargements (2D & 3D) 2D Representations of 3D Objects G7 TRIONOMETRIC RATIOS Calculating Volumes of 15 G-SRT Similarity, Right Triangles, and Trigonometry 6, 7, 8 Compound Objects M2 GEOMETRIC MODELING 2 Modeling: Rolling Cups 10 G-MG Modeling with Geometry 1, 2, 3 TOTAL: 144 HIGH SCHOOL OVERVIEW Algebra 1 Geometry Algebra 2 A0 Introduction G0 Introduction and A0 Introduction Construction A1 Modeling With Functions G1 Basic Definitions and Rigid -
Dimension Guide
UNDERCOUNTER REFRIGERATOR Solid door KURR114KSB, KURL114KSB, KURR114KPA, KURL114KPA Glass door KURR314KSS, KURL314KSS, KURR314KBS, KURL314KBS, KURR214KSB Detailed Planning Dimensions Guide Product Dimensions 237/8” Depth (60.72 cm) (no handle) * Add 5/8” (1.6 cm) to the height dimension when leveling legs are fully extended. ** For custom panel models, this will vary. † Add 1/4” (6.4 mm) to the height dimension 343/8” (87.32 cm)*† for height with hinge covers. 305/8” (77.75 cm)** 39/16” (9 cm)* Variant Depth (no handle) Panel ready models 2313/16” (60.7 cm) (with 3/4” panel) Stainless and 235/8” (60.2 cm) black stainless Because Whirlpool Corporation policy includes a continuous commitment to improve our products, we reserve the right to change materials and specifications without notice. Dimensions are for planning purposes only. For complete details, see Installation Instructions packed with product. Specifications subject to change without notice. W11530525 1 Panel ready models Stainless and black Dimension Description (with 3/4” panel) stainless models A Width of door 233/4” (60.3 cm) 233/4” (60.3 cm) B Width of the grille 2313/16” (60.5 cm) 2313/16” (60.5 cm) C Height to top of handle ** 311/8” (78.85 cm) Width from side of refrigerator to 1 D handle – door open 90° ** 2 /3” (5.95 cm) E Depth without door 2111/16” (55.1 cm) 2111/16” (55.1 cm) F Depth with door 2313/16” (60.7 cm) 235/8” (60.2 cm) 7 G Depth with handle ** 26 /16” (67.15 cm) H Depth with door open 90° 4715/16” (121.8 cm) 4715/16” (121.8 cm) **For custom panel models, this will vary. -
DNA POLYMERASE III HOLOENZYME: Structure and Function of a Chromosomal Replicating Machine
Annu. Rev. Biochem. 1995.64:171-200 Copyright Ii) 1995 byAnnual Reviews Inc. All rights reserved DNA POLYMERASE III HOLOENZYME: Structure and Function of a Chromosomal Replicating Machine Zvi Kelman and Mike O'Donnell} Microbiology Department and Hearst Research Foundation. Cornell University Medical College. 1300York Avenue. New York. NY }0021 KEY WORDS: DNA replication. multis ubuni t complexes. protein-DNA interaction. DNA-de penden t ATPase . DNA sliding clamps CONTENTS INTRODUCTION........................................................ 172 THE HOLO EN ZYM E PARTICL E. .......................................... 173 THE CORE POLYMERASE ............................................... 175 THE � DNA SLIDING CLAM P............... ... ......... .................. 176 THE yC OMPLEX MATCHMAKER......................................... 179 Role of ATP . .... .............. ...... ......... ..... ............ ... 179 Interaction of y Complex with SSB Protein .................. ............... 181 Meclwnism of the yComplex Clamp Loader ................................ 181 Access provided by Rockefeller University on 08/07/15. For personal use only. THE 't SUBUNIT . .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. 182 Annu. Rev. Biochem. 1995.64:171-200. Downloaded from www.annualreviews.org AS YMMETRIC STRUC TURE OF HOLO EN ZYM E . 182 DNA PO LYM ER AS E III HOLO ENZ YME AS A REPLIC ATING MACHINE ....... 186 Exclwnge of � from yComplex to Core .................................... 186 Cycling of Holoenzyme on the LaggingStrand -
Spectral Dimensions and Dimension Spectra of Quantum Spacetimes
PHYSICAL REVIEW D 102, 086003 (2020) Spectral dimensions and dimension spectra of quantum spacetimes † Michał Eckstein 1,2,* and Tomasz Trześniewski 3,2, 1Institute of Theoretical Physics and Astrophysics, National Quantum Information Centre, Faculty of Mathematics, Physics and Informatics, University of Gdańsk, ulica Wita Stwosza 57, 80-308 Gdańsk, Poland 2Copernicus Center for Interdisciplinary Studies, ulica Szczepańska 1/5, 31-011 Kraków, Poland 3Institute of Theoretical Physics, Jagiellonian University, ulica S. Łojasiewicza 11, 30-348 Kraków, Poland (Received 11 June 2020; accepted 3 September 2020; published 5 October 2020) Different approaches to quantum gravity generally predict that the dimension of spacetime at the fundamental level is not 4. The principal tool to measure how the dimension changes between the IR and UV scales of the theory is the spectral dimension. On the other hand, the noncommutative-geometric perspective suggests that quantum spacetimes ought to be characterized by a discrete complex set—the dimension spectrum. We show that these two notions complement each other and the dimension spectrum is very useful in unraveling the UV behavior of the spectral dimension. We perform an extended analysis highlighting the trouble spots and illustrate the general results with two concrete examples: the quantum sphere and the κ-Minkowski spacetime, for a few different Laplacians. In particular, we find that the spectral dimensions of the former exhibit log-periodic oscillations, the amplitude of which decays rapidly as the deformation parameter tends to the classical value. In contrast, no such oscillations occur for either of the three considered Laplacians on the κ-Minkowski spacetime. DOI: 10.1103/PhysRevD.102.086003 I. -
Find the Radius Or Diameter of the Circle with the Given Dimensions. 2
8-1 Circumference Find the radius or diameter of the circle with the given dimensions. 2. d = 24 ft SOLUTION: The radius is 12 feet. ANSWER: 12 ft Find the circumference of the circle. Use 3.14 or for π. Round to the nearest tenth if necessary. 4. SOLUTION: The circumference of the circle is about 25.1 feet. ANSWER: 3.14 × 8 = 25.1 ft eSolutions Manual - Powered by Cognero Page 1 8-1 Circumference 6. SOLUTION: The circumference of the circle is about 22 miles. ANSWER: 8. The Belknap shield volcano is located in the Cascade Range in Oregon. The volcano is circular and has a diameter of 5 miles. What is the circumference of this volcano to the nearest tenth? SOLUTION: The circumference of the volcano is about 15.7 miles. ANSWER: 15.7 mi eSolutions Manual - Powered by Cognero Page 2 8-1 Circumference Copy and Solve Show your work on a separate piece of paper. Find the diameter given the circumference of the object. Use 3.14 for π. 10. a satellite dish with a circumference of 957.7 meters SOLUTION: The diameter of the satellite dish is 305 meters. ANSWER: 305 m 12. a nickel with a circumference of about 65.94 millimeters SOLUTION: The diameter of the nickel is 21 millimeters. ANSWER: 21 mm eSolutions Manual - Powered by Cognero Page 3 8-1 Circumference Find the distance around the figure. Use 3.14 for π. 14. SOLUTION: The distance around the figure is 5 + 5 or 10 feet plus of the circumference of a circle with a radius of 5 feet. -
Hyperbolic Geometry
Flavors of Geometry MSRI Publications Volume 31,1997 Hyperbolic Geometry JAMES W. CANNON, WILLIAM J. FLOYD, RICHARD KENYON, AND WALTER R. PARRY Contents 1. Introduction 59 2. The Origins of Hyperbolic Geometry 60 3. Why Call it Hyperbolic Geometry? 63 4. Understanding the One-Dimensional Case 65 5. Generalizing to Higher Dimensions 67 6. Rudiments of Riemannian Geometry 68 7. Five Models of Hyperbolic Space 69 8. Stereographic Projection 72 9. Geodesics 77 10. Isometries and Distances in the Hyperboloid Model 80 11. The Space at Infinity 84 12. The Geometric Classification of Isometries 84 13. Curious Facts about Hyperbolic Space 86 14. The Sixth Model 95 15. Why Study Hyperbolic Geometry? 98 16. When Does a Manifold Have a Hyperbolic Structure? 103 17. How to Get Analytic Coordinates at Infinity? 106 References 108 Index 110 1. Introduction Hyperbolic geometry was created in the first half of the nineteenth century in the midst of attempts to understand Euclid’s axiomatic basis for geometry. It is one type of non-Euclidean geometry, that is, a geometry that discards one of Euclid’s axioms. Einstein and Minkowski found in non-Euclidean geometry a This work was supported in part by The Geometry Center, University of Minnesota, an STC funded by NSF, DOE, and Minnesota Technology, Inc., by the Mathematical Sciences Research Institute, and by NSF research grants. 59 60 J. W. CANNON, W. J. FLOYD, R. KENYON, AND W. R. PARRY geometric basis for the understanding of physical time and space. In the early part of the twentieth century every serious student of mathematics and physics studied non-Euclidean geometry. -
Zero-Dimensional Symmetry
Snapshots of modern mathematics № 3/2015 from Oberwolfach Zero-dimensional symmetry George Willis This snapshot is about zero-dimensional symmetry. Thanks to recent discoveries we now understand such symmetry better than previously imagined possible. While still far from complete, a picture of zero-dimen- sional symmetry is beginning to emerge. 1 An introduction to symmetry: spinning globes and infinite wallpapers Let’s begin with an example. Think of a sphere, for example a globe’s surface. Every point on it is specified by two parameters, longitude and latitude. This makes the sphere a two-dimensional surface. You can rotate the globe along an axis through the center; the object you obtain after the rotation still looks like the original globe (although now maybe New York is where the Mount Everest used to be), meaning that the sphere has rotational symmetry. Each rotation is prescribed by the latitude and longitude where the axis cuts the southern hemisphere, and by an angle through which it rotates the sphere. 1 These three parameters specify all rotations of the sphere, which thus has three-dimensional rotational symmetry. In general, a symmetry may be viewed as being a transformation (such as a rotation) that leaves an object looking unchanged. When one transformation is followed by a second, the result is a third transformation that is called the product of the other two. The collection of symmetries and their product 1 Note that we include the rotation through the angle 0, that is, the case where the globe actually does not rotate at all. 1 operation forms an algebraic structure called a group 2 . -
101.1 CP Lines and Segments That Intersect a Circle.Notebook April 17, 2017 Chapter 10 Circles Part 1 - Lines and Segments That Intersect a Circle
101.1 CP Lines and Segments that Intersect a Circle.notebook April 17, 2017 Chapter 10 Circles Part 1 - Lines and Segments that Intersect a Circle In this lesson we will: Name and describe the lines and segments that intersect a circle. A chord is a segment whose endpoints are on the circle. > BA is a chord in circle O. A diameter is a chord that intersects the center of the circle. > BA is a diameter in circle P. A radius is a segment whose endpoints are the center of the circle and a point on the circle. > PA is a radius in circle P. A radius of a circle is half the length of the circle's diameter. 1 101.1 CP Lines and Segments that Intersect a Circle.notebook April 17, 2017 A tangent is a line or segment that intersects a circle at one point. The point of tangency is the point where the line or segment intersects the circle > line t is a tangent line to circle O and P is the point of tangency A common tangent is a line that is tangent to two circles. A secant is a line that intersects a circle at two points. The segment part of a secant contained inside the circle is a chord. > line AB is a secant in circle O > segment AB is a chord in circle O 2 101.1 CP Lines and Segments that Intersect a Circle.notebook April 17, 2017 Examples: Naming Lines and Segments that Intersect Circles Name each line or segment that intersects 8L. -
Restoration of Mir-193A Expression Is Tumor-Suppressive in MYC
Bharambe et al. Acta Neuropathologica Communications (2020) 8:70 https://doi.org/10.1186/s40478-020-00942-5 RESEARCH Open Access Restoration of miR-193a expression is tumor-suppressive in MYC amplified Group 3 medulloblastoma Harish Shrikrishna Bharambe1,2, Annada Joshi1, Kedar Yogi1,2, Sadaf Kazi1 and Neelam Vishwanath Shirsat1,2* Abstract Medulloblastoma, a highly malignant pediatric brain tumor, consists of four molecular subgroups, namely WNT, SHH, Group 3, and Group 4. The expression of miR-193a, a WNT subgroup-specific microRNA, was found to be induced by MYC, an oncogenic target of the canonical WNT signaling. MiR-193a is not expressed in Group 3 medulloblastomas, despite MYC expression, as a result of promoter hypermethylation. Restoration of miR-193a expression in the MYC amplified Group 3 medulloblastoma cells resulted in inhibition of growth, tumorigenicity, and an increase in radiation sensitivity. MAX,STMN1, and DCAF7 were identified as novel targets of miR-193a. MiR- 193a mediated downregulation of MAX could suppress MYC activity since it is an obligate hetero-dimerization partner of MYC. MYC induced expression of miR-193a, therefore, seems to act as a feedback inhibitor of MYC signaling. The expression of miR-193a resulted in widespread repression of gene expression that included not only several cell cycle regulators, WNT, NOTCH signaling genes, and those encoding DNA replication machinery, but also several chromatin modifiers like SWI/SNF family genes and histone-encoding genes. MiR-193a expression brought about a reduction in the global levels of H3K4me3, H3K27ac, the histone marks of active chromatin, and an increase in the levels of H3K27me3, a repressive chromatin mark.