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Four Special Systems When you add, subtract, multiply or divide the “real ” used in everyday life, you always get another . Three generalizations of the real numbers also behave in this way. Many physicists believe that all four of these “ ” underlie the laws of physics.

Examples of ℝ Real numbers real numbers: All the numbers on (1-D) number . −2 -1 0 1 2 One defining of reals is that their is never negative. −1.3 √2 e.g. 22 = 4 and also (−2)2 = 4

ℂ Complex numbers Example of a Reals used in conjunction with an i : 3i 3+2i unconventional “imaginary” unit called i. Complex numbers 2i One defining characteristic of i behave like 1i is that its square is negative. coordinates ie. i2 = −1 on a 2-D plane: 1 2 3 Real

: Reals used in conjunction with three 3+2i+1j+2k i unconventional units called i, j and k. j

Multiplication of quaternions Quaternions Real is noncommutative: Swapping behave like the of elements changes coordinates the answer. in 4-D : k

Multiplication follows a cyclic pattern, where k i multiplying neighboring elements results in the third: Cyclic Moving with arrows gives a positive answer: i x j = k pattern

Moving against arrows gives a negative answer: j x i = −k j

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Reals used in conjunction with seven 3+2e1+2e2+3e3+2e4+2e5+1e6+3e7 unconventional units: e1, e2, e3, e4, e5, e1 and (e1, e2 and e4 are comparable e7 e2 to the quaternions’ i, j and k). Octonions Multiplication of octonions is behave like e6 Real nonassociative — it matters coordinates e3 how they are grouped. in 8-D space: e5 e4 Their multiplication rules are encoded in the “.” Multiplying two neighboring elements e6 on a line results in the third element on that same line. Fano Imagine additional lines that close the loop for each plane of three elements (e.g., the dashed line).

Moving with arrows gives a positive answer: e4 e1 e.g. e5 x e2 = e3 and e6 x e3 = e4 e7 Moving against arrows gives a negative answer: e.g. e1 x e7 = −e3 and e6 x e5 = −e1 e3 e2 e5

To see their nonassociative property, multiply three elements e5, e2, e4 Grouping them like this ... (e5 x e2) x e4 = (e3) x e4 = e6 Different answers But grouping them like this … e5 x (e2 x e4) = e5 x (e1) = −e6

Revised July 22, 2018 Quanta Magazine