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Advances in Pure , 2011, 1, 105-117 doi:10.4236/apm.2011.14023 Published Online July 2011 (http://www.SciRP.org/journal/apm)

Left Eigenvector of a

Sylvain Lavalle´e Departement de mathematiques, Universite du Quebec a Montreal, Montreal, Canada E-mail: [email protected] Received January 7, 2011; revised June 7, 2011; accepted June 15, 2011

Abstract

We determine the left eigenvector of a M associated to the eigenvalue 1 in the commu- tative and the noncommutative cases. In the commutative case, we see that the eigenvector associated to the eigenvalue 0 is (,,NN1  n ), where Ni is the ith principal of NMI=  n , where In is the 11 of dimension n . In the noncommutative case, this eigenvector is (,P1 ,Pn ), where Pi is the sum in aij  of the corresponding labels of nonempty paths starting from i and not passing through i in the complete directed graph associated to M .

Keywords: Generic Stochastic Noncommutative Matrix, Commutative Matrix, Left Eigenvector Associated To The Eigenvalue 1, Skew Field, Automata

1. Introduction stochastic free field and that the vector 11 (,,PP1  n ) is fixed by our matrix; moreover, the sum 1 It is well known that 1 is one of the eigenvalue of a of the Pi is equal to 1, hence they form a kind of stochastic matrix (i.e. the sum of the elements of each noncommutative limiting . row is equal to 1) and its associated right eigenvector is These results have been proved in [1] but the proof the vector (1,1, ,1)T . But, what is the left eigenvector proposed in this paper are completely different. associated to 1? Indeed for the major part the proof in these two In the commutative case, this eigenvector is the vector instances, we use elementary operations on the rows and

(,,)M1  M n , where M i is the i th principal minor the columns of the matrix. of the matrix. This formula is known in ; it amounts to finding the stationary distribution 2. Commutative Case of the finite whose transition matrix is the stochastic irreducible matrix. The commutative case is well known in probability In the noncommutative case, we must involve inverses theory. Indeed, we calculate the limit probability of a of elements of the skew field and as these may be finite Markov chain by replacing the stochastic matrix undefined, we take a generic noncommutative stochastic M by M I, where I is the identity matrix of the matrix: this is the matrix ()aij of noncommuting vari- appropriate dimension. For this, we use the Markov ables aij subject only to the stochastic identities; i.e. the chain tree Theorem, where this calculus is expressed in sum of each row equals one. terms of spanning trees. The Markov chain tree theorem We work in the free field generated by these variables gives a formula for the stationary distribution of a finite (in the sense of Paul Cohn), which we call the stochastic Markov chain. Equivalently, this formula gives a row free field. Considering the complete digraph on the set vector fixed by a matrix fixing (1,1, ,1)T . This

{1, ,n }, let M i be the set of paths from i to i . Let theorem is attributed to Kirchoff by Persi Diaconis, who

Pi be the paths starting from i and not passing gives a probabilistic proof of it (see [2] p. 443 and 444). through i again. We identify Pi with the noncom- See also [3,4]. mutative power series which is equal to the sum of all the The proof uses only the definition of the determinant words in Pi and we still denote this series by Pi . Next which involves the principal minors. 1 we show that the elements Pi can be evaluated in the Proposition 1 Let M be a stochastic matrix and

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NMI==() nijijb 1,n; i.e. for all in=1,  , , Proof. By definition of N , we have det N  = 0 . n We show that  j=1bij =0. Then (,,NN1  n ), where Ni is the i  th (,NN ,, N )=0N principal minor of N , is the left eigenvector associated 12 n to the eigenvalue 0. We verify this Equation with the first column of N .

Nb111 Nbnn1

bb22 23 b2n bb11 12 b1,n 1

bb32 33 b3n bb21 22 b2,n 1 = bb11  n1  

bbnn23 b nn bbnn1,1 1,2 b nn 1, 1 n bb1121,1jn b j=2 bb b 22 23 2n n

bb32 33 b3n bb2222,1jn b = b11  j=2 bn1  bb b  nn23 nn n bbnj1, n1,2bnn 1, 1 j=2

bb22 23 b 2n bb12 12 b 1,n 1

bb32 33 b 3n bb22 22 b 2,n 1 = bb11  n 1   

bbnn23 b nn bbnn1,2 1,2 b nn  1, 1  =0

bb1,nn 1 12 b 1, 1 bb1121,1nn b

bb2,nn 1 22 b 2, 1 bb2222,1nn b  bbnn11  

bbnn1, 1 n  1,2 bnn 1, 1 bbnn1, n 1,2 b nn  1, 1    =0

bb22 23 b2n bb1121,1nn b

bb32 33 b3n bb2222,1nn b = bb11  n1  

bbnn23 b nn bbnn1, n 1,2 b nn 1, 1

bb22 23 b2n bb12 13 b1n

bb32 33 b3n n2 bb22 23 b2n =(1b11   ) bn1  

bbnn23 b nn bbnn1,2 1,3 b nn 1,

bb22 23 b2n bb12 13 b1n

bb32 33 b3n n1 bb22 23 b2n =(1)bb11   n1  

bbnn23 b nn bbnn1,2 1,3 b nn 1, =detN =0

Remark 2 If M is reducible, then this proposition is irreducible and stochastic, then its adjoint will be of the asserting that the zero vector ia an eigenvector. If M is form (1, ,1)uT , where uT is a null vector. Te pro-

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 position follows from the cofactor formula for the adjoint. that its characteristic series  wL wA is ratio- nal. We shall identify a language and its characteristic 3. Noncommutative Case series. This is exposed in [5] or [6].

In [1], the authors have prove in two manners that are 3.2. Free Field actually similar, Theorem 9. In the first, results from variable-length prefix codes are required; and the second Let  be a field. If the multiplicative group of  is deals with general variable-length codes, not necessarily commutative, then  is a commutative field. Else,  is called skew field. The ring of rational formal series in prefix. Moreover, in Appendix 2 of [1], we see how the rat theory of quasideterminants may be used to obtain these noncommutative variables  A  is not a skew results on noncommutative matrices. field. However, skew fields containing A do exist. The major part of the new proof of this Theorem One of them is the free field (in the sense of Cohn), involves only the elementary operations on the rows and denoted  . The free field is the noncommutative on the columns of the stochastic matrix. Therefore, we analogue of the field of fractions of the ring of commu- need the following results. tative polynomials. There are several constructions of the free field: Amitsur [7], Bergman [8], Malcolmson [9], 3.1. Languages and Series Cohn [10] and [11]. A of order n is full if it can’t expressed Let A be a finite alphabet and A* be the free monoid as a product of matrices nn 1 by nn1 . generated by A . A language is a subset of a free Theorem 3 ([11], Thm 4.5.8.) Each full matrix M monoid A* . A language is rational if it is obtained from with coefficients in X  is invertible in the free field. finite languages by the operations (called rational) union, A square matrix of order n is called hollow if it product (concatenation) and star. The product of two contains a pq block of zeros such that pqn 1. languages LL12 is ww12 w 1 L 1, w 2 L 2 , and the star 001   of L is LwwwLn* =,   0= Ln . Ra- Example 4 The matrix 001 is hollow since 1 ni n0   tional languages may be obtained by using only unam- 111 biguous rational operations; these are: disjoint union, there is a 22 block of 0 and 4>3. unambiguous product (meaning that if wLL 12, then Proposition 5 ([11], Prop. 4.5.4) A is w has a unique factorization ww= 12w, wii L) and not full. * the star L restricted to languages which are free Proposition 6 Take   1n , M  nn and * submonoids of A .   n1 , where  is a skew field. We suppose that A formal series is an element of the  -algebra of M   noncommutative series A  , where A is a set of M is invertible. Then is invertible if and   0 noncommuting variables. A rational series is an element   1 of the smallest subalgebra of A  , which contains only if M  0 . the  -algebra of noncommutative polynomials A , Proof. 1 and which is closed under the operation () Suppose that cM= 0, then the inverse  M   * n 1 of is SS ==1 S S   n=0   0 which is defined if S has zero constant term. We MMcMMc11111  1 denote by A rat the  -algebra of rational series.   cM11  c 1 Let L be a rational language. Since L may be   obtained by unambiguous rational expressions, it follows Indeed, this matrix is the right inverse of M since

M  MM111111 c  MMc 11 1  0 cM  c MM()(111111 M c M  cM MM  11  c)  c1 =  1111 11  ()MMcM Mc  11  11  1  1 1cM  cM  c   c 10    = MMcMMc111111  =       01 ==cc

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This matrix is also the left inverse of M since

MMcMMc111111   M  11 1 cM  c  0 ()()MMcMMMc1  111   11 MMcM  1  111 = 11  1 11 ()cMMc () cM  1Mc11 Mc  11  M  1   Mc  11   M  1    10 = =c = 11 11   cc cM 01    =c 

M  In other words, the sum of each line of S is equal to () Suppose that  is invertible. Let 1; hence S is a stochastic matrix. We call S a gene-  0 ric noncommutative stochastic matrix. The algebra over M  be its inverse. Then we have  generated by its coefficients is a free a ssociative    algebra, since it is isomorph to the algebra aiij ,  j. Indeed, we ca n eliminate the a with the stochastic 0 ii relations (1). We denote this alge bra by a /(1) .   ij M   Hence, ther e is a corresponding free field called = 00 stochastic free field denoted S .  1 3.4. Paths 0    Hence M == 0 and  =1. It follows Consider the set of nonempty paths in the complete directed graph with a set of vertices 1, ,n starting 0  from i and not passing through i ; we denote by P that i the sum in a of all the corresponding words. It is 1 ij   = M  classically a rational series, and thus defines an element  == M 1  1 of the free field  .

1 ab M 0 Example 8 M =   . The graph is cd From this proposition, we deduce th e follo wing result. Corollary 7 Let , M and  be matrices with M  coefficients in A where M is full. If  is  0

M  not full (in particul ar, if  is equivalent by then  0 ** elementary operations on the lines and on the columns to PbdPc12=1 , =1 a 1 a hollow matrix) then M =0 in the free field. We shall also consider rational expressions over any skew field D , and say that such an expression is 3.3. Generic Stochastic Matrices evaluable in D if it can be evaluated without inversion of 0. I f the elements of D appea ring in the rationa l Let M = a be a generic noncommutative matrix; ij 1,ij n expression are actua lly in a subring R of D , we say that the expression is over R . i.e. the aij are noncommutative var iables. We denote rat  the corresponding free field. We associate to M There is a cano ni cal embedding of A  into  , which can be seen as follows: let S be any rational the matrix S : it’s exactly the same matrix of which the * 1 coefficients satisfy the stochastic identities series, we replace in it the operation T by 1T ; then one obtains a rational expression in  , which is n evaluable in  and represents the image of S under ina=1,  , , ij =1 (1) rat j=1 the embedding A   . Thus, each rational

Copyright © 2011 SciRes. APM S. LAVALL E´E 109 language and each rational series is naturally an element n PLi=,=1,, n, of the free field. See [12]. iij j=1 By Theorem 1 of [1], the Pi can be evaluated in the stochastic free field. where We can now state the main result of this paper.  1, if i= j  Theorem 9 Let M = aij be a generic nn 1,ij n Lij =  La =,a La ifi j ik kj ij ik kj stochastic noncommutative matrix. Let Pi be defined as kk=1 =1,k j above. Then

Let Si  be the system composed of the n Equa- 11  11 P11,, PPPnnM = ,, (2) tions Pi , LLLiiiii1,1,1,, , ,,  Lin. Multip lying to the 1 11 left by Pi each equation of Si , we obtain the system In other words, PP1 ,, n is the left eig envector n associated to the eigenvalue 1 o f M .  11 1= PPLiii  ij, =1, ,n Example 10 (Continued.) Let be S be the m atrix  jji1, T :  M with ab =1 and cd =1. We show that i n PL1= Pa1 PLa1  iij iij iikkj 11  11  kki1, P12,=,PPPM 12 1 Let QPLij = i ij , then we have From this system, we deduce the two following equa- n tions:  1 11 1 1= PQiii  j, =1, ,n Pa12 P 1=d P1 (3)  jji1, T : i  n P111=aPdP1 (4) QPa= 1  Qa 12 2  ij i ij  ik kj  kki1, From the Equation (3), we have This system transforms into the following system 11  1 Pa12 P1= d P 1 n  1 1= PQiniij , =1,  , 11 jji1, PdPa211=1    Ui :  n 1 ** 0=Paiijijjj Q a1  Qaikkj  dP21= aP (5)  kki1, ,  kj dcaabd*1=1***  We show that n d**d1=  da * aa **  1  ad * 11 Pakk11 P k =1 ** ** daad=  Define Hence, Equation (3) is satisfied. From the Equation (4), n RPa= 1 P1 (6) we have  kk11 k =1 111 PaPdP121 =2 We show that R =0. So Equation (6) is converted

11 into the following Equation Pa121=1  d n 11 ** RP11111= a Pakk 0 (7)  aP12= dP k =2 Since we again obtain Equation (5), it follows that Consider the system of the n2 1 Equations: Equa-

Equation (4) is also satisfied. tion (7) and the n systems UU1 ,, n . We have the Proof of Theorem 9. matrical representation

Let M = a be the matrix of the automaton 11 ij 1,ij n RP,,,,,,,,,,112131221232 Q Q Qnn P Q Q Q ,  and P be the language of the labels of the paths i PQ1,,, Q E =λ starting from i and not passing through i . We have nn1,1 nn 

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aamm12 a mmmmmn,1,1 a a aa1 a a a 11 12 1,mm 1 1, 1 1n aa21 22 1 a2,mm 1 a2, 1 a2n    A =   m  aa a1 a a  m1,1 m  1,2 mm 1, 1 mm 1, 1 mn 1,   aam1,1 m  1,2 a mm 1, 1 a mm  1, 1 1 a mn 1,        aann,1 ,2 a nmnmnn, 1 a, 1 a1 where mn=1, , and  =(0, ,0,1,  ,1). E is a  ntimes square matrix of order n2 1. We have RE=, 1

T E   =(1,0, ,0) and F = . The order of this   0 n2 times  matrix is n2  2 . Moreover, with the stochastic identities, we have where the Bi are defined by

aamm12 a m ,m1 a m ,m1 a mn n    aa11km2 a1,11 a,1m a 1n kk=1, 1 n  aa21   2kma2, 1 a2, m 1 a2n kk=1, 2    n Bm = am1,1 am1,2   aam1,km1,m 1 a m 1,n kk=1, 2, km1 n  aam1,1 m1,2 amm 1, 1   amk 1, amn 1,  kkm=1, 1    n aa a aann,1 ,2 nm,1 nm,1   nk kkn=1, 

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To show that R =0, we show that the matrix F is Step 2. We want a nn block of 0 in the right upper hollow. For this, we apply elementary operations on the corner of F1 . For this, we consider the j - th row of rows and on the colum ns of F until F contains a F1 (correspo nding to the j - th row of B1 ). By s t block of 0 such that stn2 3. construction of B1 , the first index of the elements of the j - th row of this block is j . Now, we consid er the

row which passes in the block B2 such that this first index of its elements is j . Such a row exists by

construction of B2 . We repeat this operation wi th the row which have the first index equals to j in the blocks

BB3 ,, n . We add each one of these rows to the j - th

row of F1 . It follows that the n last elements of the j first rows of this new matrix are all equal to 1. From each row of the j first rows, we subtract the last row of F . 1 We obtain the following matrix Step 1. We eliminate the first rowe and the last column of F . We obtain the square matrix F1 of order n2 1 (stn2 2 ).

where n   aa11k2 a1,11ma1,ma 1n kk=1, 1 n aa21   2kmaaa2, 1 2,m 1 2 n Cm = kk=1, 2   n aa aa a nn,1 ,2 nmnm,, 1 , 1  nk kkn=1, 

mn=2,, . We reduce F2 in removing the last line LLiknknmk (1)= L L(1)n, to obtain the matrix and the nth column if we start from the end. We 2 have the following matrix F3 of order n , ( s tn 1).

where, for all mn=2, , , DB=,=,=dbdmmbm bm m ij1,ijn m ij ij ij nj Step 3. Consider the rows Li of F3 , where in> and in 0mod . We want that the (1)n  last ele- We remove the (1)n  rows Li where in> and ments of these rows to be equals to 0. Let ik= nm , ni and the (1n  ) last columns of F4 to obtain the 2 where 01mn, then we apply the F5 of order ( st n n2 ).

Copyright © 2011 SciRes. APM 112 S. LAVALL E´E

( st  n2 n2 ).

where Dm is the matrix obtained from Dm in remo- ving the last row. where B1 is the block obtained from B1 by removing 1 the first column. We find a nn(1 )2 1 block of 0 Step 4. Denote by Cm the first column of the matrix located in the right upper corner and Cm and by dm the column of F5 , which is the ex- 1 1 tension of C . We want C to be transformed into a 2 22 m m nn11 =nn 2 nn 1=dimF vector of 0, mn=2,, . For this, we apply the 8 It follows that F is a hollow. From Corollary 7, operation dccj 23 cn , where ci is the it h column of F . 1n 11 11 3 RE==k =1Pakk1 P1 =0. Hence P1 ,, Pn Finally we want that the first n elements of the firs t is the left eigenvector associated to 1. column of F5 to be all 0; for this, we apply the aa11 12a 13  transformation cc12 cn . We obtain the matrix F6 2 2 Example 11. Let M = aaa be a generic of order nn1 (stnn2 )  21 22 23  a31aa 32 33  noncommutative matrix in w hich the variables satisfy the

stochastic ide ntities aaaii123  i=1 , i = 1,2,3 . We associate the a utomato n

where Cm is the ma trix obt ained from Cm by removing the first column.

Step 5. We want each Cm will be transformed into a q matrix of 0. To each colum n q of Cm , denoted Cm

q T correspon ding to the column dqm=C ,*,,* of  F . By construction of C (hence of C ), there exists 6 m m Let P be the language recognized by the automaton T 1 a column b of F such that b =,*,,C q  *. q 6 qm 

Hence, for all q , we calculate dbqq . We obtain the 2 2 matrix F7 of order nn1 (stn n2 ).

Let L be the language of words which start from i ij to j . We have PL=, L L where Step 6. Permuting the fir st and the nth column of 1111213 2 L11 =1 F7 , we obtain the matrix F8 of or der n n1

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LaLaLa12= 12 12 22 13 32 Permuting the index of the equations of U1 , we obtain the two following systems LaLaLa13 = 13 12 23 13 33 1 We have the system 1= PQQ22123  PLL1   1 12 13 UPaQaQ2 :0= 2 21 12 11 1  23a 31  SL:=aLaLa  1 1 121212221332 0=Pa Qa Q a 1   22321132333 LaLaLa13= 13 12 23 13 33  1 1 1= PQQ33132 Multiplying to left each equation of S1 by P1 , we  1 obtain the system UPaQaQ3:0= 3 31 31 111 32a 21 1= PPLPL11  1  1 1112113 0=Pa33231123222 Qa Q a 1  111  1 TPLP1:= 1 12 1 aPLaPLa12 1 12 22 1 13 32 111  111 To show that PPP123,,M = PPP 123 ,,, it  111  1 111 1 PL1 13= Pa 1 13 PLa 1 12 23 PLa 1 13 33  suffices to prove that Pa111 Pa 2213311 Pa= P. 1 Define Define QPLij = 1 ij , then RPaPaPaP= 1111 1= PQQ1  1112213311 11213 then  1 111 TQ1:= 12 PaQaQa 1 12 12 22 13 32 RP1112213311= a Pa Pa 0  1 QPaQaQa1311312231333=  Under the matrical system, we have

We obtain 11 RP,1,,,,,,,, QQP QQP QQ E =λ 1  1 12 13 2 21 23 3 31 32  1= PQQ11213  1 where UPaQa1 :0= 1 12 12 22 1 Q13a 32  λ = 0,0,0,0,0,0,0,1,1,1 0=Pa1  Qa Q a 1  11312231333 and 1000000000 1 aa a 0000100 11 12 13 0aa 1 0000100 22 23 0aa32 33  10000100 aa00a 00010 E = 21 21 23 000aa11 1 13 00010 000aa 100010 31 33 aa310000 31a 32 001  aa 0000011 1 12 001  00000aa21 22  1001

We have RE=  1 , where T tities equal to  = 1,0,0,0,0,0,0,0,0,0 and E with stochastic iden-  1000000000 aa a a 0000100  12 13 12 13   0aa a 0000100  21 23 23   0aaa32 31 32 0000100  aa00 a00010  21 21 23   00 0aa12 13 a13 0 0010  00 0aaa 0 0010  31 31 32   aa31 0000 31 a32 001   00000aa a 001  12 13 12     00000aaa21 21 23 001

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E  Let F = , we show that F is hollow.  0

 10000000001   aa12 13 a 12 a13 00001000  0aa a 00001000  21 23 23   0aaa 00001000  32 31 32   aa00 a000100  21 21 23  F =  00 0aa12 13 a13 0 00100    00 0aaa31 31 32 0 00100  aa0000 a0010  31 31 32   00000aa a 0010  12 13 12   00000aaa21 21 23 0010    00000001110

aa12 13 a 12 a13 0000100    0aa21 23 a 23 0000100  0aaa 0000100  32 31 32   aa00a 00010  21 21 23 

 00 0aa12 13 a13 0 0010 F1 =    00 0a31 aa31 32 0 0010    aa31 0 0 0 0 31 a32 001  00 0 0 0aa a 001  12 13 12   00 0 0 0aaa 001  21 21 23   0000000111

LLLL158102491036710,, LLLL  LLLL ,

aa12 13 a 12 a13 aa12 13 a 13 aa12 13 a 12 000    aaaa21 21 23 23 a21 a23 a21  aa21 23 000  aaaaaaaaa 000  31 32 31 32 31 31 32 31 32   a00aa00010  21 21 23   00 0aa12 13 a 13 0 0010 F2 =    00 0aaa31 31 32 0 0010    aa31 0000 31 a32 001  00000aa a 001  12 13 12   00000aaa 001  21 21 23   0000000111

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aa12 13 a 12 a13 aa12 13 a 13 aa12 13 a 12 00    aaaa21 21 23 23 a21 a23 a21  aa21 23 00  aaaaaaaaa 00  31 32 31 32 31 31 32 31 32   aaa00 0010  21 21 23  F31=0 0 0aa213 a13 0 0 10    00 0aaa31 31 32 0 010    aa31 000031 a32 01  00 0 0 0aa a 01  12 13 12     00 0 0 0a21 aa21 23 01

LL46,,, LL 56 LL 79 LL 89,

aa12 13 a 12 a13 aa12 13 a13 aa12 13 a12 00     aaaa21 21 23 23 a21 a23 a21  aa21 23 00   aaaaa  aaa a00   31 32 31 32 31 31 32 31 32   aaaaaa00 0 000  21 21 31 23 31 32  F4=0 0 0aaaaaa121331133132    0 0 00    00 0aaa31 31 32 0 010    aaa31 00 0 0 31 21 a32aa 21 23 00   00 0 0 0aaaaaa    00  12 13 21 12 21 23     00 0 0 0 aaa21 21 23 01

aa12 13 a 12 a13 aa12 13 a13 aa12 13 a12     aaaa21 21 23 23 a21 a23 a21  aa21 23   aaaaa  aaa a   31 32 31 32 31 31 32 31 32  F =00 aaaaaa00  52 1 2131233132   00 0aaaaaa    0 0   12 13 31 13 31 32   aa31 00 0 0 31a 21a 32a 21a 23     00 0 0 0aaaa12 13  21 12aa 21 23 

CCC123,, CCC 423  CCC 623 ,

 000aa12 13 a13 a12   000aa a a aa   21 23 23 23 21 23   000aaa32 31 32 aa31 32 a32    F621=00aa2131233132aaaa0 0   00 0aaaaaa   0 0   12 13 31 13 31 32  aa31 00 0 0 31a 21a 32a 21a 23     00 0 0 0 aaaaaa12 13 21 12  21  23 

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CC53,, CC 72

 00aa12 13 000    00aa21 23 a 23 000  00aaa 000  32 31 32  F =00aaaaaa0 0  721 2131233132 

 00 0aaaaaa12 13  31 13  31  32 0 0    aa31 00 0 0 31a 21a 32a 21a 23     00 0 0 0 aaaaaa12 13  21 12  21  23 

CC13

 aa13 12 00000     aaa23 21 23 00000  aa a 00000   31 32 32  F =0 0 aaaaaa  0 0  8 212131233132 

 000aaaaaa12 13 31 13  31  32 0 0     00aa31 0 0 31a 21a 32a 21a 23     0000 0aaaaaa12 13  21 12  21  23 

We have a 35 block of zero with 8>7. It follows column. Again, we show that F  is hollow, and hence, that F is hollow. By Corollary 7, by Corollary 7, we have R = 0 . This proves Equation 1111 R ==Pa111Pa221Pa3311 P 0. (8). This proof allo ws us to prove the next result. Example 13. (Continued.)

Theorem 12. Let Pi be defined as above, then in  11  11 * we have PP1211= PP 1 ad by Equation (5)

11*1  *  1 n ==1=PPbdP bdPP=1 1 11 1 11 Pi =1 (8) i=1 Proof. Define 4. Conclusions

n 1 R =1 Pi One of the contribution of this article is the using of i=1 elementary operations on the lines and the columns. This we will show that method provides a new way to obtain some results in

n skew field theory with a minimum of knowledge of this 1 R  Pi =1 theory. Moreover, Theorems 9 and 12 are proved exactly i=1 the same way. We replace the first column of the matrix E by the vector 5. Acknowledgements

T 1,1,0, ,0,1,0,  ,0,  ,1,0,  ,0 I am obliged to thank to Christophe Reutenauer for his and the first element of λ by 1. Denoted E and λ comments, corrections and suggestions.

E   these two matrices. Consider the matrix F  =   . 6. References  0 We repeat each step of the proof of Theorem 9, except [1] S. Lavall´ee, D. Perrin, C. Reutenauer and V. Retakh, for the last operation of step 4, which concerns the first “Codes and Noncommutative Stochastic Matrices,” To

Copyright © 2011 SciRes. APM S. LAVALL E´E 117

appear, 2008. [7] A. Amitsur, “Rational Identities and Applications to Al- [2] A. Broder, “Generating Random Spanning Trees. Proc gebra and Geometry,” Journal of Algebra, Vol. 3, 1966, 30th IEEE Symp,” Proceedings of the 30th IEEE Sympo- pp. 304-359. sium on Foundation of Computer Science, Boston, 1989, [8] G. M. Bergman, “Skew Field of Noncommutative Ra- pp. 442-447. tional Functions, after Amitsur,” S´eminaire Schu¨tzen- [3] V. Anantharam and P. Tsoucas, “A Proof of the Markov berger-Lentin-Nivat, Vol. 16, 1970. Chain Tree Theorem,” Statistic and Probability Letters, [9] P. Malcolmson, “A Prime Matrix Ideal Yields a Skew Vol. 8, No. 2, 1989, pp. 189-192. Field,” Journal of the London Mathematical Society, Vo l. [4] D.-J. Aldous, “The Randow Walk Construction of Uni- 18, 1978, pp. 221-233. form Spanning Trees and Uniform Labelled Trees,” [10] P. M. Cohn, “Free Rings and Their Relations,” Academic SIAM Journal on Discrete Mathematics, Vol. 3, No. 4, Press, Salt Lake City, 1971. 1990, pp. 450-465. [11] P. M. Cohn, “Skew Fields: Theory of General Division [5] J. Berstel and C. Reutenauer, “Les S´eries Rationnelles et Rings,” Encyclopedia of Mathematics and Its Applica- Leurs Langages,” Masson, Paris, 1984. tions, Cambridge University Press, Cambridge, 1995. [6] J. Berste l and C. Reutenauer, “Rational Series and Their [12] M. Fliess, “Sur le Plongement de l’alg`ebre des S´eries Languages,” 2008. Rationelles non Commutatives dans un Corps Gauche,” http://www-igm.univ-mlv.fr/~berstel/LivreSeries/LivreSe Proceedings of the National Academy of Sciences, Paris, ries08janvier2008.pdf. 1970.

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