Lecture 1: the Earth's Magnetic Field

Total Page:16

File Type:pdf, Size:1020Kb

Lecture 1: the Earth's Magnetic Field Lecture 1: The Earth’s magnetic field Celine´ Guervilly School of Mathematics, Statistics and Physics, Newcastle University, UK Outline of these lectures Lecture 1 Geomagnetic field: Sources and spatio-temporal observations Lecture 2 Dynamo theory, experimental dynamos and numerical simulations Lecture 3/4 Dynamics of the Earth’s core: rotating fluids and convection Outline of today’s lecture Sources of the near-Earth magnetic field Magnetic data Spatial variations of the internal field: core field and crustal field Temporal variations of the core field on historical and geological timescales Sources of the near-Earth magnetic field Sources of the near-Earth magnetic field The Earth’s magnetic field is the result of the superposition of many fields produced by a great variety of sources. Two types of sources: Magnetised media and electric currents. Magnetised rocks located in the upper layers of the Earth where T < Tc. Tc: Curie temperature above which materials lose their permanent magnetic properties Iron: Tc = 1043K Hulot et al. (2015) Field of internal origin Largest contribution is the core/main field 30,000 nT at the equator, 60,000 nT at the poles Changes on secular timescales. The crustal field produced by magnetised rocks (located mainly in the crust). Very dependent on locations: from less than 1nT to 1000nT. The internal field is dominated by the core field at scales larger than 2000 km and by the crustal field on smaller scales. Hulot et al. (2015) Field of external origin Electric currents in the ionosphere and the magnetosphere. Magnitude can strongly vary with time. “Quiet” times: at the Earth’s surface, magnetospheric field about 20 nT and ionospheric field about 10 nT (varies with local time, peaks during day time). “Disturbed” times: external field of 1000 nT varying on timescales of less than 1s to several days. Hulot et al. (2015) Induced fields Rocks in the crust and mantle and salty waters in the oceans have a weak electric conductivity: induced currents due to time variations of the main and external fields. These induced currents have weak magnitudes, only a small fraction of the inducing field. In the oceans, tides and oceanic flows interacting with the main field produce weak fields of a few nT. Hulot et al. (2015) Sources of the near-Earth magnetic field A separation of the contributions from each type of field can only be achieved only with a large numbers of geomagnetic measurements. This allows to construct global models of the geomagnetic field. Hulot et al. (2015) Magnetic data Local topocentric coordinate system X, Y and Z are the components of the field pointing towards geographic north, geographic east, and vertically down. Inclination I: angle between the horizontal plane and the direction of the field (positive if downward). Declination D: angle between the magnetic north and the geographic north (positive if East). Ground data Network of about 150 ground observatories. Uneven spatial distribution. Good temporal coverage. Accuracy of 1 nT. Observatories providing data to WDC/INTERMAGNET between 1997 and 2012. Chambon-La-Foretˆ Ascension Island Antartica Ground data Ground data Observatory data provided through the INTERMAGNET network and the World Data Center (WDC) system. https://www.ngdc.noaa.gov/geomag/data.shtml Knowledge of the declination is required to use a compass! Satellite data Global map of the magnetic field. Data are obtained over different regions with the same instrumentation. Measuring from an altitude: reduced the effect of local magnetic heterogeneities. Not directly possible to determine whether observed magnetic field variations are due to temporal or spatial changes. Magsat, Ørsted, CHAMP (top) and one of the three Swarm satellites (bottom) Spatial variations of the internal field Spatial variations of the core field at the Earth’s surface Radial component of the field at the Earth’s surface in 2010 (Hulot et al. 2015) Magnetic field produced by a dipole The magnetic field produced by a magnetic dipole moment M is µ M · r B = 0 3 r - M 4πr3 r2 SI unit of M: A m2 -7 µ0 = 4π × 10 H/m is the vacuum magnetic permeability SI unit of the magnetic field B: Tesla (T) (cgs unit: Gauss with 1G=10-4T) The component of an axial dipole in spherical coordinates are 2µ M cos θ B = 0 r 4πr3 µ0M sin θ Bθ = 4πr3 Bφ = 0 Magnetic dipole Magnetic field lines around a bar magnet. Iron filings reveal the lines of force around a bar magnet. Spatial variations of the core field at the Earth’s surface Declination at the Earth’s surface in 2010 (Hulot et al. 2015) A pure axial dipole field would have zero declination everywhere. Spatial variations of the core field at the Earth’s surface Inclination at the Earth’s surface in 2010 (Hulot et al. 2015) North and South magnetic poles (I = ±90◦) are not antipodal: additional components to the inclined dipole. Spatial variations of the core field at the Earth’s surface Field intensity at the Earth’s surface in 2010 (Hulot et al. 2015) northern maximum (60,000 nT) < southern maximum (66,670 nT). Low-intensity region over South America and the South Atlantic: South Atlantic Anomaly (SAA) In an electrically insulating medium, j = 0 ) r × B = 0 and so there exists a scalar potential V such that B = -rV There are no magnetic monopoles so r · B = 0 and so the scalar potential is harmonic, i.e. r2V = 0 Assuming that the conductivity of the mantle and crust is negligible and the permanent magnetisation of the crust is very weak, the scalar potential description is valid from the CMB up to the base of the ionosphere. A solution to Laplace’s equation is uniquely determined if the value of the function or its normal derivative is specified on all boundaries. Potential field Ampere’s` law r × B = µoj, where B is the magnetic field, j the current density and µ0 the magnetic permeability. There are no magnetic monopoles so r · B = 0 and so the scalar potential is harmonic, i.e. r2V = 0 Assuming that the conductivity of the mantle and crust is negligible and the permanent magnetisation of the crust is very weak, the scalar potential description is valid from the CMB up to the base of the ionosphere. A solution to Laplace’s equation is uniquely determined if the value of the function or its normal derivative is specified on all boundaries. Potential field Ampere’s` law r × B = µoj, where B is the magnetic field, j the current density and µ0 the magnetic permeability. In an electrically insulating medium, j = 0 ) r × B = 0 and so there exists a scalar potential V such that B = -rV Assuming that the conductivity of the mantle and crust is negligible and the permanent magnetisation of the crust is very weak, the scalar potential description is valid from the CMB up to the base of the ionosphere. A solution to Laplace’s equation is uniquely determined if the value of the function or its normal derivative is specified on all boundaries. Potential field Ampere’s` law r × B = µoj, where B is the magnetic field, j the current density and µ0 the magnetic permeability. In an electrically insulating medium, j = 0 ) r × B = 0 and so there exists a scalar potential V such that B = -rV There are no magnetic monopoles so r · B = 0 and so the scalar potential is harmonic, i.e. r2V = 0 Potential field Ampere’s` law r × B = µoj, where B is the magnetic field, j the current density and µ0 the magnetic permeability. In an electrically insulating medium, j = 0 ) r × B = 0 and so there exists a scalar potential V such that B = -rV There are no magnetic monopoles so r · B = 0 and so the scalar potential is harmonic, i.e. r2V = 0 Assuming that the conductivity of the mantle and crust is negligible and the permanent magnetisation of the crust is very weak, the scalar potential description is valid from the CMB up to the base of the ionosphere. A solution to Laplace’s equation is uniquely determined if the value of the function or its normal derivative is specified on all boundaries. The solution of this equation are of the form l 1 ( θ φ) = l + m(θ φ) V r, , Almr Blm + Yl , 1 rl 1 = Xl=1 mX0 m where the spherical harmonics Yl of degree l and order m is defined as m m m imφ Yl (θ, φ) = Cl Pl (cos θ)e m m where Cl is a normalisation constant and Pl is the associated Legendre polynomials. Spherical harmonics constitute a basis of differentiable functions. Orthogonality: m n Yl Yk dS = 0 if k , l or n , m ZS Normalisation: = 1 (2l + 1)(l - m)! 1 2 YmYmdS = 1 for Cm = (-1)m 4π l l l (l + m)!) ZS Spherical harmonics decomposition In spherical coordinates, 1 @ @V 1 @ @V 1 @2V r2V = r2 + sin θ + = 0 r2 @r @r r2 sin θ ∂θ ∂θ r2 sin2 θ @2φ Spherical harmonics constitute a basis of differentiable functions. Orthogonality: m n Yl Yk dS = 0 if k , l or n , m ZS Normalisation: = 1 (2l + 1)(l - m)! 1 2 YmYmdS = 1 for Cm = (-1)m 4π l l l (l + m)!) ZS Spherical harmonics decomposition In spherical coordinates, 1 @ @V 1 @ @V 1 @2V r2V = r2 + sin θ + = 0 r2 @r @r r2 sin θ ∂θ ∂θ r2 sin2 θ @2φ The solution of this equation are of the form l 1 ( θ φ) = l + m(θ φ) V r, , Almr Blm + Yl , 1 rl 1 = Xl=1 mX0 m where the spherical harmonics Yl of degree l and order m is defined as m m m imφ Yl (θ, φ) = Cl Pl (cos θ)e m m where Cl is a normalisation constant and Pl is the associated Legendre polynomials.
Recommended publications
  • Section 14: Dielectric Properties of Insulators
    Physics 927 E.Y.Tsymbal Section 14: Dielectric properties of insulators The central quantity in the physics of dielectrics is the polarization of the material P. The polarization P is defined as the dipole moment p per unit volume. The dipole moment of a system of charges is given by = p qiri (1) i where ri is the position vector of charge qi. The value of the sum is independent of the choice of the origin of system, provided that the system in neutral. The simplest case of an electric dipole is a system consisting of a positive and negative charge, so that the dipole moment is equal to qa, where a is a vector connecting the two charges (from negative to positive). The electric field produces by the dipole moment at distances much larger than a is given by (in CGS units) 3(p⋅r)r − r 2p E(r) = (2) r5 According to electrostatics the electric field E is related to a scalar potential as follows E = −∇ϕ , (3) which gives the potential p ⋅r ϕ(r) = (4) r3 When solving electrostatics problem in many cases it is more convenient to work with the potential rather than the field. A dielectric acquires a polarization due to an applied electric field. This polarization is the consequence of redistribution of charges inside the dielectric. From the macroscopic point of view the dielectric can be considered as a material with no net charges in the interior of the material and induced negative and positive charges on the left and right surfaces of the dielectric.
    [Show full text]
  • Magnetic Fields
    Welcome Back to Physics 1308 Magnetic Fields Sir Joseph John Thomson 18 December 1856 – 30 August 1940 Physics 1308: General Physics II - Professor Jodi Cooley Announcements • Assignments for Tuesday, October 30th: - Reading: Chapter 29.1 - 29.3 - Watch Videos: - https://youtu.be/5Dyfr9QQOkE — Lecture 17 - The Biot-Savart Law - https://youtu.be/0hDdcXrrn94 — Lecture 17 - The Solenoid • Homework 9 Assigned - due before class on Tuesday, October 30th. Physics 1308: General Physics II - Professor Jodi Cooley Physics 1308: General Physics II - Professor Jodi Cooley Review Question 1 Consider the two rectangular areas shown with a point P located at the midpoint between the two areas. The rectangular area on the left contains a bar magnet with the south pole near point P. The rectangle on the right is initially empty. How will the magnetic field at P change, if at all, when a second bar magnet is placed on the right rectangle with its north pole near point P? A) The direction of the magnetic field will not change, but its magnitude will decrease. B) The direction of the magnetic field will not change, but its magnitude will increase. C) The magnetic field at P will be zero tesla. D) The direction of the magnetic field will change and its magnitude will increase. E) The direction of the magnetic field will change and its magnitude will decrease. Physics 1308: General Physics II - Professor Jodi Cooley Review Question 2 An electron traveling due east in a region that contains only a magnetic field experiences a vertically downward force, toward the surface of the earth.
    [Show full text]
  • Equivalence of Current–Carrying Coils and Magnets; Magnetic Dipoles; - Law of Attraction and Repulsion, Definition of the Ampere
    GEOPHYSICS (08/430/0012) THE EARTH'S MAGNETIC FIELD OUTLINE Magnetism Magnetic forces: - equivalence of current–carrying coils and magnets; magnetic dipoles; - law of attraction and repulsion, definition of the ampere. Magnetic fields: - magnetic fields from electrical currents and magnets; magnetic induction B and lines of magnetic induction. The geomagnetic field The magnetic elements: (N, E, V) vector components; declination (azimuth) and inclination (dip). The external field: diurnal variations, ionospheric currents, magnetic storms, sunspot activity. The internal field: the dipole and non–dipole fields, secular variations, the geocentric axial dipole hypothesis, geomagnetic reversals, seabed magnetic anomalies, The dynamo model Reasons against an origin in the crust or mantle and reasons suggesting an origin in the fluid outer core. Magnetohydrodynamic dynamo models: motion and eddy currents in the fluid core, mechanical analogues. Background reading: Fowler §3.1 & 7.9.2, Lowrie §5.2 & 5.4 GEOPHYSICS (08/430/0012) MAGNETIC FORCES Magnetic forces are forces associated with the motion of electric charges, either as electric currents in conductors or, in the case of magnetic materials, as the orbital and spin motions of electrons in atoms. Although the concept of a magnetic pole is sometimes useful, it is diácult to relate precisely to observation; for example, all attempts to find a magnetic monopole have failed, and the model of permanent magnets as magnetic dipoles with north and south poles is not particularly accurate. Consequently moving charges are normally regarded as fundamental in magnetism. Basic observations 1. Permanent magnets A magnet attracts iron and steel, the attraction being most marked close to its ends.
    [Show full text]
  • Class 35: Magnetic Moments and Intrinsic Spin
    Class 35: Magnetic moments and intrinsic spin A small current loop produces a dipole magnetic field. The dipole moment, m, of the current loop is a vector with direction perpendicular to the plane of the loop and magnitude equal to the product of the area of the loop, A, and the current, I, i.e. m = AI . A magnetic dipole placed in a magnetic field, B, τ experiences a torque =m × B , which tends to align an initially stationary N dipole with the field, as shown in the figure on the right, where the dipole is represented as a bar magnetic with North and South poles. The work done by the torque in turning through a small angle dθ (> 0) is θ dW==−τθ dmBsin θθ d = mB d ( cos θ ) . (35.1) S Because the work done is equal to the change in kinetic energy, by applying conservation of mechanical energy, we see that the potential energy of a dipole in a magnetic field is V =−mBcosθ =−⋅ mB , (35.2) where the zero point is taken to be when the direction of the dipole is orthogonal to the magnetic field. The minimum potential occurs when the dipole is aligned with the magnetic field. An electron of mass me moving in a circle of radius r with speed v is equivalent to current loop where the current is the electron charge divided by the period of the motion. The magnetic moment has magnitude π r2 e1 1 e m = =rve = L , (35.3) 2π r v 2 2 m e where L is the magnitude of the angular momentum.
    [Show full text]
  • Physics 2102 Lecture 2
    Physics 2102 Jonathan Dowling PPhhyyssicicss 22110022 LLeeccttuurree 22 Charles-Augustin de Coulomb EElleeccttrriicc FFiieellddss (1736-1806) January 17, 07 Version: 1/17/07 WWhhaatt aarree wwee ggooiinngg ttoo lleeaarrnn?? AA rrooaadd mmaapp • Electric charge Electric force on other electric charges Electric field, and electric potential • Moving electric charges : current • Electronic circuit components: batteries, resistors, capacitors • Electric currents Magnetic field Magnetic force on moving charges • Time-varying magnetic field Electric Field • More circuit components: inductors. • Electromagnetic waves light waves • Geometrical Optics (light rays). • Physical optics (light waves) CoulombCoulomb’’ss lawlaw +q1 F12 F21 !q2 r12 For charges in a k | q || q | VACUUM | F | 1 2 12 = 2 2 N m r k = 8.99 !109 12 C 2 Often, we write k as: 2 1 !12 C k = with #0 = 8.85"10 2 4$#0 N m EEleleccttrricic FFieieldldss • Electric field E at some point in space is defined as the force experienced by an imaginary point charge of +1 C, divided by Electric field of a point charge 1 C. • Note that E is a VECTOR. +1 C • Since E is the force per unit q charge, it is measured in units of E N/C. • We measure the electric field R using very small “test charges”, and dividing the measured force k | q | by the magnitude of the charge. | E |= R2 SSuuppeerrppoossititioionn • Question: How do we figure out the field due to several point charges? • Answer: consider one charge at a time, calculate the field (a vector!) produced by each charge, and then add all the vectors! (“superposition”) • Useful to look out for SYMMETRY to simplify calculations! Example Total electric field +q -2q • 4 charges are placed at the corners of a square as shown.
    [Show full text]
  • Frequency Dependence of the Permittivity
    Frequency dependence of the permittivity February 7, 2016 In materials, the dielectric “constant” and permeability are actually frequency dependent. This does not affect our results for single frequency modes, but when we have a superposition of frequencies it leads to dispersion. We begin with a simple model for this behavior. The variation of the permeability is often quite weak, and we may take µ = µ0. 1 Frequency dependence of the permittivity 1.1 Permittivity produced by a static field The electrostatic treatment of the dielectric constant begins with the electric dipole moment produced by 2 an electron in a static electric field E. The electron experiences a linear restoring force, F = −m!0x, 2 eE = m!0x where !0 characterizes the strength of the atom’s restoring potential. The resulting displacement of charge, eE x = 2 , produces a molecular polarization m!0 pmol = ex eE = 2 m!0 Then, if there are N molecules per unit volume with Z electrons per molecule, the dipole moment per unit volume is P = NZpmol ≡ 0χeE so that NZe2 0χe = 2 m!0 Next, using D = 0E + P E = 0E + 0χeE the relative dielectric constant is = = 1 + χe 0 NZe2 = 1 + 2 m!00 This result changes when there is time dependence to the electric field, with the dielectric constant showing frequency dependence. 1 1.2 Permittivity in the presence of an oscillating electric field Suppose the material is sufficiently diffuse that the applied electric field is about equal to the electric field at each atom, and that the response of the atomic electrons may be modeled as harmonic.
    [Show full text]
  • The Dipole Moment.Doc 1/6
    10/26/2004 The Dipole Moment.doc 1/6 The Dipole Moment Note that the dipole solutions: Qd cosθ V ()r = 2 4πε0 r and Qd 1 =+⎡ θθˆˆ⎤ E ()r2cossin3 ⎣ aar θ ⎦ 4πε0 r provide the fields produced by an electric dipole that is: 1. Centered at the origin. 2. Aligned with the z-axis. Q: Well isn’t that just grand. I suppose these equations are thus completely useless if the dipole is not centered at the origin and/or is not aligned with the z-axis !*!@! A: That is indeed correct! The expressions above are only valid for a dipole centered at the origin and aligned with the z- axis. Jim Stiles The Univ. of Kansas Dept. of EECS 10/26/2004 The Dipole Moment.doc 2/6 To determine the fields produced by a more general case (i.e., arbitrary location and alignment), we first need to define a new quantity p, called the dipole moment: pd= Q Note the dipole moment is a vector quantity, as the d is a vector quantity. Q: But what the heck is vector d ?? A: Vector d is a directed distance that extends from the location of the negative charge, to the location of the positive charge. This directed distance vector d thus describes the distance between the dipole charges (vector magnitude), as well as the orientation of the charges (vector direction). Therefore dd= aˆ , where: Q d ddistance= d between charges d and − Q ˆ ad = the orientation of the dipole Jim Stiles The Univ. of Kansas Dept. of EECS 10/26/2004 The Dipole Moment.doc 3/6 Note if the dipole is aligned with the z-axis, we find that d = daˆz .
    [Show full text]
  • Phys102 Lecture 3 - 1 Phys102 Lecture 3 Electric Dipoles
    Phys102 Lecture 3 - 1 Phys102 Lecture 3 Electric Dipoles Key Points • Electric dipole • Applications in life sciences References SFU Ed: 21-5,6,7,8,9,10,11,12,+. 6th Ed: 16-5,6,7,8,9,11,+. 21-11 Electric Dipoles An electric dipole consists of two charges Q, equal in magnitude and opposite in sign, separated by a distance . The dipole moment, p = Q , points from the negative to the positive charge. An electric dipole in a uniform electric field will experience no net force, but it will, in general, experience a torque: The electric field created by a dipole is the sum of the fields created by the two charges; far from the dipole, the field shows a 1/r3 dependence: Phys101 Lecture 3 - 5 Electric dipole moment of a CO molecule In a carbon monoxide molecule, the electron density near the carbon atom is greater than that near the oxygen, which result in a dipole moment. p Phys101 Lecture 3 - 6 i-clicker question 3-1 Does a carbon dioxide molecule carry an electric dipole moment? A) No, because the molecule is electrically neutral. B) Yes, because of the uneven distribution of electron density. C) No, because the molecule is symmetrical and the net dipole moment is zero. D) Can’t tell from the structure of the molecule. Phys101 Lecture 3 - 7 i-clicker question 3-2 Does a water molecule carry an electric dipole moment? A) No, because the molecule is electrically neutral. B) No, because the molecule is symmetrical and the net dipole moment is zero.
    [Show full text]
  • Magnetic Dipoles Magnetic Field of Current Loop I
    PHY2061 Enriched Physics 2 Lecture Notes Magnetic Dipoles Magnetic Dipoles Disclaimer: These lecture notes are not meant to replace the course textbook. The content may be incomplete. Some topics may be unclear. These notes are only meant to be a study aid and a supplement to your own notes. Please report any inaccuracies to the professor. Magnetic Field of Current Loop z B θ R y I r x For distances R r (the loop radius), the calculation of the magnetic field does not depend on the shape of the current loop. It only depends on the current and the area (as well as R and θ): ⎧ μ cosθ B = 2 μ 0 ⎪ r 4π R3 B ==⎨ where μ iA is the magnetic dipole moment of the loop μ sinθ ⎪ B = μ 0 ⎩⎪ θ 4π R3 Here i is the current in the loop, A is the loop area, R is the radial distance from the center of the loop, and θ is the polar angle from the Z-axis. The field is equivalent to that from a tiny bar magnet (a magnetic dipole). We define the magnetic dipole moment to be a vector pointing out of the plane of the current loop and with a magnitude equal to the product of the current and loop area: μ K K μ ≡ iA i The area vector, and thus the direction of the magnetic dipole moment, is given by a right-hand rule using the direction of the currents. D. Acosta Page 1 10/24/2006 PHY2061 Enriched Physics 2 Lecture Notes Magnetic Dipoles Interaction of Magnetic Dipoles in External Fields Torque By the FLB=×i ext force law, we know that a current loop (and thus a magnetic dipole) feels a torque when placed in an external magnetic field: τ =×μ Bext The direction of the torque is to line up the dipole moment with the magnetic field: F μ θ Bext i F Potential Energy Since the magnetic dipole wants to line up with the magnetic field, it must have higher potential energy when it is aligned opposite to the magnetic field direction and lower potential energy when it is aligned with the field.
    [Show full text]
  • Chapter 32 - Magnetism of Matter; Maxwell’S Equations 1
    Chapter 32 - Magnetism of Matter; Maxwell’s Equations 1. The simplest magnetic structure that can exist is a magnetic dipole. Magnetic monopoles do not exist. 2. (a) The orbital magnetic moment is given by q µorb = Lorb. 2m For macroscopic orbits, the angular momentum is L = mvr = mωr2. (It also possible to get this result from µ = NiA and considering the current to be i = q/T = qω/2π.) (b) The spin angular momentum of an electron is quantized and has the z component eh µs,z = ± 4πm where h =6.63 × 10−34 Js is Planck’s constant. 3. Magnetic materials. (a) Diamagnetism is exhibited by all common materials but is so feeble that it can be masked. A diamagnetic material placed in an external magnetic field develops a magnetic dipole moment directed opposite to the external field. When the external field is removed, the dipole moment disappears. If the external field is nonuniform, the diamagnetic material is repelled from a region of greater magnetic field toward a region of lesser field. (b) Paramagnetism is due to the interaction of magnetic dipoles in the material. A param- agnetic material placed in an external magnetic field develops a magnetic dipole moment in the direction of the external field. If the field is removed, the induced dipole moment will disappear. If the field is nonuniform, the paramagnetic material is attracted toward a region of greater magnetic field from a region of lesser field. (c) Ferromagnetism is the property responsible for what is commonly called “magnetic” materials. A ferromagnetic material placed in an external magnetic field develops a strong magnetic dipole moment in the direction of the external field.
    [Show full text]
  • On Modeling Magnetic Fields on a Sphere with Dipoles and Quadrupoles by DAVID G
    On Modeling Magnetic Fields on a Sphere with DipolesA and Quadrupoles<*Nfc/ JL GEOLOGICAL SURVEY PROFESSIONAL PAPER 1118 On Modeling Magnetic Fields on a Sphere with Dipoles and Quadrupoles By DAVID G. KNAPP GEOLOGICAL SURVEY PROFESSIONAL PAPER 1118 A study of the global geomagnetic field with special emphasis on quadrupoles UNITED STATES GOVERNMENT PRINTING OFFICE, WASHINGTON: 1980 UNITED STATES DEPARTMENT OF THE INTERIOR CECIL D. ANDRUS, Secretary GEOLOGICAL SURVEY H. William Menard, Director Library of Congress Cataloging in Publication Data Knapp, David Goodwin, 1907- On modeling magnetic fields on a sphere with dipoles and quadrupoles. (Geological Survey Professional Paper 1118) Bibliography: p. 35 1. Magnetism, Terrestrial Mathematical models. 2. Quadrupoles. I. Title. II. Series: United States Geological Survey Professional Paper 1118. QC827.K58 538'.?'ol84 79-4046 For sale by the Superintendent of Documents, U.S. Government Printing Office Washington, D.C. 20402 Stock Number 024-001-03262-7 CONTENTS Page Page /VOStrHCt ™™-™™™™"™-™™™"™«™™-«—"—————————————— j_ Relations with spherical harmonic analysis—Continued Introduction——————————-—--——-———........—..——....... i Other remarks concerning eccentric dipoles ———— 14 Characteristics of the field of a dipole —————————————— 1 Application to extant models -—————————-——- Multipoles ——————————-—--——--—-——--——-——...._. 2 14 E ccentric-dipole behavior ———————————————• The general quadrupole ——————-———._....................—.— 2 20 Results of calculations --—--—------——-——-—- 21 Some characteristics
    [Show full text]
  • Maxwell's Equations
    Wire Antennas: Maxwell’s equations Maxwell’s equations govern radiation variables: 1• E electricfield ( v ) m 1• H magneticfield ( a ) m • 2 E D = ε electricdisplaceme nt (Coulombs m ) B = µH magnetic flux density (Teslas) -12 (ε is permittivity; εo = 8.8542 × 10 farads/m for vacuum) -7 (µ is permeability; µo = 4π• 10 henries/m) (1 Tesla = 1 Weber m-2 = 104 gauss) Lec 09.6- 1 1/11/01 E1 Maxwell’s Equations: Dynamics and Statics Maxwell’s equations Statics ∂B ∇ × E = − → = 0 ∂t ∂D • 2 ∇ ×H = J + → J = a( m) ∂t -3 ∇ • D = ρ → =ρm ( C ) ∇ •B = 0 → = 0 ⎛ ∂ 1 ∂ 1 ∂ ⎞ ⎜ ∇ ∆xˆ ∂ +∂ xyˆ∂ ∂ y +zˆ∂ ∂ z ; ∆ ∇rˆ + θˆ + φˆ ⎟ ⎝ ∂r r∂ θr sinθ∂ φ⎠ -09.6c Le 2 /01 1/11 E2 Static Solutions to Maxwell’s Equations Maxwell’s equations govern variables: p • 1 r E electricfield ( v ) m pq • 1 H magneticfield ( a ) m vq volume of source E =−∇ since φ ∇ × = E 0 B = ∇ × sinceA ∇ • = B 0 1 ρ φ = q dv volts electrostais tic potentialat point p p ∫v q 4 πε q pqr µ Jq A p = is dv the vectorpotential at p ∫v q 4π q rpq -09.6c Le 3 /01 1/11 E3 Dynamic Solutions to Maxwell’s Equations B = ∇ × sinceA ∇ • = B 0 µ Jtq ( − r pq c) A p ()t = ∫ dvq ( static so l ution, delayed) 4 π v q rpq 8 − 1 c = 1 µo 3ε ≅o 10 × ms(velocityof light) − jkrpq µ Jeq Sinusoidal steady state: A p = ∫ dv q 4 π v q rpq where propagation constant k = ω µoε o= ωc= 2π λ methodSolution : J →q (r ) ( A) →(r ) ( → )B r E r where E = −∇( × H ) jωε from Faraday’s law Lec 09.6- 4 1/11/01 E4 Elementary Dipole Antenna (Hertzian Dipole) S = E × H z φˆ , H θ θˆ , E λ Q(t) Inr " near <<field" , rr>> d 2 π d
    [Show full text]