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2012
Neutrosophic Super Matrices and Quasi Super Matrices
Florentin Smarandache University of New Mexico, [email protected]
W.B. Vasantha Kandasamy [email protected]
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Recommended Citation W.B. Vasantha Kandasamy & F. Smarandache. Neutrosophic Super Matrices and Quasi Super Matrices. Ohio: Zip Publishing, 2012.
This Book is brought to you for free and open access by the Mathematics at UNM Digital Repository. It has been accepted for inclusion in Faculty and Staff Publications by an authorized administrator of UNM Digital Repository. For more information, please contact [email protected], [email protected], [email protected].
Neutrosophic Super Matrices and Quasi Super Matrices
W. B. Vasantha Kandasamy Florentin Smarandache
ZIP PUBLISHING Ohio 2012 This book can be ordered from:
Zip Publishing 1313 Chesapeake Ave. Columbus, Ohio 43212, USA Toll Free: (614) 485-0721 E-mail: [email protected] Website: www.zippublishing.com
Copyright 2012 by Zip Publishing and the Authors
Peer reviewers:
Prof. Valeri Kroumov, Okayama Univ. of Science, Japan. Dr.S.Osman, Menofia University, Shebin Elkom, Egypt. Dr. Sebastian Nicolaescu, 2 Terrace Ave., West Orange, NJ 07052, USA. Prof. Gabriel Tica, Bailesti College, Bailesti, Jud. Dolj, Romania.
Many books can be downloaded from the following Digital Library of Science: http://www.gallup.unm.edu/~smarandache/eBooks-otherformats.htm
ISBN-13: 978-1-59973-194-0 EAN: 9781599731940
Printed in the United States of America
2
CONTENTS
Preface 5
Chapter One INTRODUCTION 7
Chapter Two NEUTROSOPHIC SUPER MATRICES 9
Chapter Three SUPER BIMATRICES AND THEIR GENERALIZATION 87
3.1 Super Bimatrices and their Properties 87 3.2 Operations on Super Bivectors 139
3
Chapter Four QUASI SUPER MATRICES 157
FURTHER READING 195
INDEX 197
ABOUT THE AUTHORS 200
4
PREFACE
In this book authors study neutrosophic super matrices. The concept of neutrosophy or indeterminacy happens to be one the powerful tools used in applications like FCMs and NCMs where the expert seeks for a neutral solution. Thus this concept has lots of applications in fuzzy neutrosophic models like NRE, NAM etc. These concepts will also find applications in image processing where the expert seeks for a neutral solution. Here we introduce neutrosophic super matrices and show that the sum or product of two neutrosophic matrices is not in general a neutrosophic super matrix. Another interesting feature of this book is that we introduce a new class of matrices called quasi super matrices; these matrices are the larger class which contains the class of super matrices. These class of matrices lead to more partition of n × m matrices where n > 1 and m > 1, where m and n can also be equal. Thus this concept cannot be defined on usual row matrices or column matrices. These matrices will play a major role when studying a problem which needs multi fuzzy neutrosophic models.
5 This book is organized into four chapters. Chapter one is introductory in nature. Chapter two introduces the notion of neutrosophic super matrices and describes operations on them. In chapter three the major product of super row vectors and column vectors are defined and are extended to bisuper vectors. The final chapter introduces the new concept of quasi super matrices and suggests some open problems. We thank Dr. K.Kandasamy for proof reading and being extremely supportive.
W.B.VASANTHA KANDASAMY FLORENTIN SMARANDACHE
6
Chapter One
INTRODUCTION
In this chapter we just indicate the concepts which we have used and the place of reference of the same.
Throughout this book I will be denote the indeterminate 2 such that I = I. Z I, Q I, R I, C I, Zn I and C(Zn) I denotes the neutrosophic ring [3-4, 7]. For the definition and properties of super matrices please refer [2, 5]. The notion of bimatrices is introduced in [6].
Here in this book the notion of neutrosophic super matrices are introduced and operations on them are performed.
We also can use the entries of these super neutrosophic matrice from rings; (Z I) (g) = {a + bg | a, b Z I and g is the new element such that g2 = 0}. Z can be replaced by R or Q or Zn or C and we call them as dual number rings [11].
8 Neutrosophic Super Matrices and Quasi Super Matrices
(Q I) (g1) = {a + bg1 | a, b Q I where g1 is a new 2 element such that g1 = g1}. We call (Q I) (g1) as special dual like number neutrosophic rings. Here also Q can be replaced by R or Z or C or Zn.
(R I) (g2) = {a + bg | a, b R I, g2 the new element 2 such that g2 = –g2} is the special quasi dual number neutrosophic ring. We can replace R by Q or Z or Zn or C and still we get special quasi dual number neutrosophic rings.
Finally we can also use (Z I) (g1, g2, g3) = {a1 + a2g1 + a3g2 + a4g3 | ai Z I; 1 i 4; g1, g2, g3 are new elements 2 2 2 such that g1 = 0, g2 = g2 and g=3 –g3 with gigj = (0 or gi or gj), i j; 1 i, j 3} the special mixed neutrosophic dual number rings [11-13].
Finally in this book the new notion of quasi super matrices is introduced and their properties are studied. This new concept of quasi super matrices can be used in the construction of fuzzy- neutrosophic models.
Chapter Two
NEUTROSOPHIC SUPER MATRICES
In this chapter we for the first time introduce and study the notion of super neutrosophic matrices and their properties.
A super matrix A in which the element indeterminacy I is present is called a super neutrosophic matrix. To be more precise we will define these notions.
DEFINITION 2.1: Let X = {(x1 x2 … xr | xr+1 … xt | xt+1 …. xn) where xi R I ; R reals 1 i n) be a super row matrix which will be known as a super row neutrosophic matrix.
Thus all super row matrices in general are not super row neutrosophic matrix.
We illustrate this situation by an example.
Example 2.1: Let X = (3 I 1 –4 | 20 –5 | 2I 0 1 | 7 2 1 4), X is a super row neutrosophic matrix.
All super row matrices are not super row neutrosophic matrices.
10 Neutrosophic Super Matrices and Quasi Super Matrices
For take A = (3 1 0 1 1 | 25 – 27 | 0 1 2 3 4), A is only a super row matrix and is not a super row neutrosophic matrix.
Example 2.2: Let A = (I 3I 1 | –I 5I | 2I 0 3I 2 1 | 0 3); A is a super row neutrosophic matrix.
Example 2.3: Let A = (0.3I, 0, 1 | 0.7, 2 I, 0 I + 7 | –8I, 0.9I + 2); A is a super row neutrosophic matrix.
DEFINITION 2.2: Let
y1 y2 y r1 Y = where yi R I; 1 i n.
yt1 yn
Y is a super column matrix known as the super column neutrosophic matrix.
We illustrate this situation by some examples.
Example 2.4: Let
2 I 34I Y = 0 1 0.3I Neutrosophic Super Matrices 11
be a super column matrix. Y is clearly a neutrosophic super column matrix (super neutrosophic column matrix).
Example 2.5: Let
3I 2 0 1 Y = 5 , I 0.4 5 6I
be a super neutrosophic column vector / matrix.
It is pertinent to mention here that in general all super column matrices are not super neutrosophic column matrices. This is proved by an example.
Example 2.6: Let
3 0 1 31 A = , 4 0.5 2 1
12 Neutrosophic Super Matrices and Quasi Super Matrices
be a super column matrix which is clearly not a super neutrosophic column matrix.
We now proceed onto define the notion of neutrosophic super square matrix.
DEFINITION 2.3: Let
aa11 12 a1n aa21 22 a2n A = (a ) = ij aan1 nn
be a n n super square matrix where aij R I. A is called the neutrosophic super square matrix of order n n.
We illustrate this by an example.
Example 2.7: Let
2I05 72 I130 I2I 01I3 I 7 A = 250 2 0 6 1353 I 7 111 I1 I
be a 66 super square matrix. Clearly as the entries of A are from R I. A is neutrosophic super square matrix.
Neutrosophic Super Matrices 13
Example 2.8: Let
30 I01 I5I I1 015I01 23II00.323 A = 12 1I0I2I , 34 2I23I34 5I 6 0 1 3 5I 6I 13I567 89I
A is a 77 neutrosophic square super matrix.
All super square matrices need not in general be a neutrosophic square super matrices.
We illustrate this by an example.
Example 2.9: Let
12345 67890 A = 09876 54321 24807
A is just a square super matrix and is not a square neutrosophic super matrix.
Now we proceed onto define a rectangular super matrix.
14 Neutrosophic Super Matrices and Quasi Super Matrices
DEFINITION 2.4: Let
mmm11 12 13 m1n mmm21 22 23 m2n M = (mij) = mmmp11 p12 p13 mp1n mmmp1 p2 p3 mpn
be a p n (p n) rectangular super matrix where mij R I. Clearly M is a rectangular neutrosophic p n super matrix.
We illustrate this by an example.
Example 2.10: Let
30I654I3 2I1 520I23I4 5I6 A = 1I50I 23I45I I0110 I 1 I 2
A is a 49 rectangular neutrosophic super matrix.
Example 2.11: Let
3I120 I4I53I 123II4 A = 4I 5 6 0 2I 78I93 7 012I89I
be a 65 rectangular super neutrosophic matrix. Neutrosophic Super Matrices 15
All super rectangular matrices in general need not be a neutrosophic super rectangular matrices.
We illustrate this by an example.
Example 2.12: Let
12345678 90987654 A = 32101234 56789012
be a 4 8 super rectangular matrix. Clearly A is not a super neutrosophic rectangular matrix.
Thus we can say as in case of supermatrices if we take any neutrosophic matrix and partition it, we would get the super neutrosophic matrix.
We can as in case of supermatrices define a neutrosophic super matrix is one in which one or more of its elements are themselves simple neutrosophic matrices. The order of the neutrosophic super matrix is defined in the same way as that of a neutrosophic matrix.
We have to define addition and subtraction of neutrosophic super matrices.
We cannot add in general two neutrosophic matrices A and B of same natural order say m n.
We shall first illustrate this by an example.
16 Neutrosophic Super Matrices and Quasi Super Matrices
Example 2.13: Let
356781 53I206 012I34 010I12 I0100I I0120I A = 1234I0 and B = 0I60I0 0I1234 I23405 01I301 0123I0 0110I0 6I720I
be two super neutrosophic matrices of natural order 76. Clearly we cannot add A with B though as simple matrices A and B can be added.
Thus for two super matrices to have a compatible addition it is not sufficient they should be of same natural order they should necessarily be of same natural order but satisfy further conditions. This condition we shall define as matrix order of a super matrix.
DEFINITION 2.5: Let
aa 11 1n A = aam1 mn
be a neutrosophic super matrix where each aij is a simple neutrosophic matrix. 1 i m and 1 j n.
The natural order of A is t s; clearly t m and s n that is A has t rows and s columns.
The matrix order of the neutrosophic super matrix A is m n. i.e., it has m number of matrix rows and n number of Neutrosophic Super Matrices 17
matrix columns. The number rows in each simple neutrosophic matrix aip, i fixed is the same, p may vary; 1 p n. Likewise for akj; j fixed, 1 k m; the number columns is the same.
We now give examples of these.
Example 2.14: Let
3I12I102 I 02000I21 0 10I11I31 2 A = 2113I213 4 4I200I156I II01010I3I
aaa 11 12 13 = aaa21 22 23 aaa31 32 33
3I1 2I10 2I where a11 = , a12 = , a13 = , 020 00I2 10
10I 11I3 12 a21 = 211, a22 = 3I21 , a23 = 34 , 4I2 00I1 56I
a31 = [I I 0], a32 = [1 0 1 0] and a33 = [I 3 I] are the neutrosophic submatrices of A also known as are the component matrices of A.
The natural order of A is 6 9 and the matrix order of A is 3 3. 18 Neutrosophic Super Matrices and Quasi Super Matrices
Example 2.15: Let
3I012 00I1 0 aa 11 12 A = 1112 3 = aa21 22 I0456I aa31 32 1I0I 3
be super neutrosophic matrix. The natural order of A is 55 and the matrix order of A is 32.
Now having seen example of matrix order of a neutrosophic super matrix we now proceed on to define addition of two super neutrosophic matrices.
DEFINITION 2.6: Let A and B be two neutrosophic super matrices of same natural order say m n. Let A and B be a neutrosophic super matrices of matrix order t s where t m and s n.
We can say A+B the sum of the super neutrosophic matrices A and B be defined if and only if each simple matrix aij in A is of same order for each bij in B. 1 i t; 1 j s;
aa a bb b 11 12 1s 11 12 1s i.e., if A = and B = aat1 t2 ats bbt1 t2 bts
where aij and bij are simple matrices. Here order of aij = order of bij; 1 i s and 1 j t.
We illustrate this by some examples.
Neutrosophic Super Matrices 19
Example 2.16: Let
aaaa11 12 13 14 3I1 I A = where a11 = a12 = , aaaa21 22 23 24 101 2
10 111I a13 = , a14 = , a21 = [ 0 1 I ] , a22 = [3], 01 00I0 a23 = [1 I] and a24 =[5 1 I 0 ].
The natural order of A is 310.
3I0I10111I A = 10120100I0 . 01I31I51I0
The matrix order of A is 24.
Take a neutrosophic super matrix B of natural order 310 and matrix order 24 given by
01I010101I B = 10112101I0 I0121I1052
b11bbb 12 13 14 = . b21bbb 22 23 24
Since natural order of matrix aij = natural order of bij, for each i and j, 1 i 2 and 1 j 4 and as A and B have same natural order as well as matrix order. We can add A and B.
20 Neutrosophic Super Matrices and Quasi Super Matrices
3I1 I I2 0 212 2 I A + B = 20 2322012I0. I151I522I615I2
We see A+B is also a neutrosophic super matrix of natural order 310 and matrix order 24.
It is important to mention that even if A and B are two neutrosophic super matrices of same natural order and same matrix order yet the sum of A and B may not be defined.
This is established by an example.
Example 2.17: Let
I0123I0 1I0321I aaa11 12 13 A = 01I2340 = and aaa21 22 23 501I0I1 2340I1I
5I33I1I 01420I0 b11bb 12 13 B = I32121I = b21bb 22 23 1233410 0I15I1I
be two super neutrosophic matrices of natural order 57 and matrix order 23. Clearly A+B, i.e., the sum of A with B is not defined as a11 b11, a12 b12, a21 b21 and a22 b22. Hence the claim.
Thus we can restate the definition of the sum of two neutrosophic super matrices as follows. Neutrosophic Super Matrices 21
DEFINITION 2.7: Let A and B be two super neutrosophic matrices of same natural order say mn and matrix order st. The addition of A with B (B with A) is defined if and only if the natural order of each aij equal to natural order of bij for every 1 i s and 1 j t.
aa bb 11 1t 11 1t i.e., A = and B = aas1st bbs1st where aij and bij are simple matrices or the component submatrices of A and B respectively; 1 i s and 1 j t.
On similar lines the subtraction or difference between two neutrosophic super matrices can be defined.
Another important fact about the addition of neutrosophic super matrices is that sum of two neutrosophic super matrices need not in general give way to a neutrosophic super matrix it can be only a super matrix.
We illustrate this by an example.
Example 2.18: Let
105I2 160 I1 1234I 0102 I A = and B = I0123 I21 1 0 67890 0121 2 be two super neutrosophic matrices of same natural and matrix order.
Since each of the corresponding component matrices are equal their sum is defined.
22 Neutrosophic Super Matrices and Quasi Super Matrices
26 5 0 3 13 3 6 0 Now A+B = . 02 2 3 3 6 8 10 10 2
We see A+B is only a super matrix and is not a neutrosophic super matrix.
Now we can have the following type of super neutrosophic matrices.
DEFINITION 2.8: Let
V1 V V = 2 Vn
be a type A super vector where each Vi’s are column subvectors; 1 i n. If some of the Vi’s are neutrosophic column vectors then we call V to be a type A neutrosophic super vector or neutrosophic super vector of type A.
We illustrate this by some examples.
Example 2.19: Let
3 I 0 V1 1 V = = V , 1 2 V3 0 4 I Neutrosophic Super Matrices 23
V is a neutrosophic super vector of type A.
Example 2.20: Let
I 2 1 V1 0 V2 V = 1 = , V3 1 V4 I 1 I
V is a again a neutrosophic super vector of type A. All super vectors of type A need not be neutrosophic super vector of type A.
We illustrate this by an example.
Example 2.21: Let
1 2 3 4 V1 5 V = = V 6 2 V3 9 8 0 1
24 Neutrosophic Super Matrices and Quasi Super Matrices
be a super vector of type A. Clearly V is not a neutrosophic super vector of type A.
Example 2.22: Let
3 0 1 4 V1 V = = V 1 2 2 V3 9 8 7
be a super vector of type A and is not a neutrosophic supervector.
V1 Let V = V2 be a super vector of type A. V3
The transpose of V is again a super vector which is a row supervector given by
t ttt V = [3 0 1 4 | 1 2 | 9 7 8] = VVV123 .
We now define neutrosophic super vector of type B.
DEFINITION 2.9: Let T = [a11 | a12 | … | a1n] be a neutrosophic super vector where aij is a mmi matrix 1 i n. T is a neutrosophic super vector of type B. We call the transpose of this neutrosophic super vector of type B to be also a neutrosophic super vector of type B. Neutrosophic Super Matrices 25
We illustrate this by the following examples.
Example 2.23: Let 021 5I0 112 a1 I01 A = a = 013 , 2 a3 0I0 103 114 I25
A is a neutrosophic super vector of type B.
Example 2.24: Let
21356 I0123 4I567 00I01 10023 0I450 A1 A = 70311 = A . 2 3011I A3 I6100 025I0 1I011 23612 3I013
A is a neutrosophic super vector of type B. 26 Neutrosophic Super Matrices and Quasi Super Matrices
We wish to say super vector of type B are in general not neutrosophic.
We illustrate this situation by an example.
Example 2.25: Let 315 021 311 402 A1 A = 116 = A , 2 789 A3 123 456 789
A is only a supervector of type B which is not a neutrosophic super vector of type B.
We define the transpose of a neutrosophic supervector of type B.
DEFINITION 2.10: Let
A1 A = An be a neutrosophic super vector of type B.
The transpose of A denoted by
t A1 A At = 2 AAtt A t 12 n Ab Neutrosophic Super Matrices 27
here each Ai is a neutrosophic matrix which has same number of columns. A is also a neutrosophic super vector of type B.
We illustrate this by the following example.
Example 2.26: Let
30I 123 987 760 A1 894 A = = A 140 2 A 271 3 390 52I 123 be a neutrosophic supervector of type B.
t A1 t tt t A = AAAA2123 A3
3197812351 = 0286947922 I3704010I3
is again a neutrosophic super vector of type B.
28 Neutrosophic Super Matrices and Quasi Super Matrices
As in case of neutrosophic super matrices we can define the sum of two neutrosophic super vectors of type A and type B.
DEFINITION 2.11: Let
a1 A1 A = a Am n1 an
be a neutrosophic supervector of type A.
Let the natural order of A be n 1.
b1 B1 Suppose B = Bm bn
B is also a neutrosophic super vector of type A of same natural order say n 1.
The sum of A and B denoted by A+B is defined if and only if the natural order of Ai is equal to the natural order of Bi for every i, i = 1,2,…, m i.e., both the matrices A and B have same matrix order.
We illustrate this by the following example.
Neutrosophic Super Matrices 29
Example 2.27: Let
0 I 1 0 I A 1 B 1 1 A = 0 A2 and B = 1 B2 A B 2 3 1 3 3 0 I 2
be two neutrosophic super matrices of type A.
0 I I 1 0 0 I 1 I1 A + B = 0 + 1 = 1 . 2 1 3 3 0 3 I 2 2I
Clearly A+B is also a neutrosophic super vector of type A same natural order and matrix order that of A and B.
We can define also the subtraction of neutrosophic super vector of type A. Now A–B is calculated.
30 Neutrosophic Super Matrices and Quasi Super Matrices
0 I I 1 0 1 I 1 I1 A – B = 0 – 1 = 1 . 2 1 1 3 0 3 I 2 I2
We see A–B is also a neutrosophic super vector of type A of same natural order and matrix order as that of A and B.
However we wish to state that sum of difference of two neutrosophic supervector of type A need not always give way to neutrosophic super vector of type A it can also be only a supervector of type A.
We illustrate this situation by an example.
Example 2.28: Let
I I 1 1 0 0 2 1 A = 1 and B = 4 I I 0 2 2 1 3 0
be two neutrosophic super vector of type A.
Neutrosophic Super Matrices 31
I I 0 1 1 2 0 0 0 2 1 3 A + B = 1 + 4 = 5 I I 0 0 2 2 2 1 3 3 0 3 is only a super vector of type A and not a neutrosophic super vector of type A.
We just indicate by an example how the minor product of type A neutrosophic super vectors is carried out.
Example 2.29: Let
A = [3 I 0 | 1 2 1 4 | 0 I] [A1 A2 A3] and
0 1 I 0 B1 B = 1 B . 2 2 B3 0 2 0 32 Neutrosophic Super Matrices and Quasi Super Matrices
0 1 I 0 The minor product of AB = [3 I 0 | 1 2 1 4 | 0 I] 1 2 0 2 0
0 0 1 2 = [3 I 0] 1 + [1 2 1 4] + [0 I] 2 0 I 0
= {30 + I1 + 0I} + {10 + 21 + 12 + 40} + {02 + I0} = {0 + I + 0} + {0 + 2 + 2 + 0} + [0 + 0] = I + 4 + 0 = I + 4.
Now in general minor product of A and B, two neutrosophic super vectors of type A may not be defined. If A is the neutrosophic super row vector of type A with A = [A1 … At] with natural order 1 n and matrix order 1 t then if B is a neutrosophic column super vector of type B then the minor t product of A with B = [B1… Bt] is defined if and only if natural order of B is n 1 and the matrix order of B is t 1 with natural order of each Bi in B is the same as the transpose of the natural order of each Ai in A for i = 1, 2, …, t or equivalently the natural order of Ai in A is equal to the order of the transpose of the natural order of Bi in B for each i = 1, 2, …, t.
Neutrosophic Super Matrices 33
Thus we see the minor product of a neutrosophic super row vector A with the transpose of the A is well defined for all the conditions required for the compatibility of the minor product of neutrosophic super vectors of type A are satisfied.
We will illustrate this situation by some examples before we proceed onto define more types of products on these neutrosophic super vectors of different types.
Example 2.30: Let
A = [1 0 I 2 | 0 0 1 | 2 3 I 0 1] be a neutrosophic super vector of type A of natural order 1 12 and matrix order 1 3.
1 0 I 2 0 t 0 Clearly A = 1 2 3 I 0 1
is also a neutrosophic super vector of type A for which AAt, the matrix minor product is well defined. 34 Neutrosophic Super Matrices and Quasi Super Matrices
1 0 I 2 0 t 0 AA = [1 0 I 2 | 0 0 1 | 2 3 I 0 1] 1 2 3 I 0 1
2 1 0 3 0 = [ 1 0 I 2] + [0 0 1] 0 + [2 3 I 0 1] I I 1 0 2 1
= {11 + 00 + II+ 22} + {00+ 00 + 11} + {22 + 33 + II + 00 + 11}
= {1+0+I+4} + {0+0+1} + {4+9+I+0+1}
= {5+I} + {1} + {14 + I}
= 20 + 2I.
Thus we have the following theorems the proof of which is left as an exercise for the reader.
Neutrosophic Super Matrices 35
THEOREM 2.1: Let A = [A1 A2 … At] be a neutrosophic super row vector of natural order 1 n and matrix order 1 t. Then AAt the minor product of AAt exists (well defined).
THEOREM 2.2: Let A be a neutrosophic super row vector of type A. If B denotes the matrix A without partition then AAt = BBt.
Now for the same type A neutrosophic super vector A we define the major product.
DEFINITION 2.12: Let
A1 A = and B = [B1 … Bs] At
be two neutrosophic super vectors of type A.
The major product of A with B is defined by
A1 AB = [B1 … Bs] At
2111 1BABABA s BABABA = 2212 2 s . stst BABABA st
Here each Ai and Bj are matrices for 1 i t and 1 j s.
We illustrate this situation by the following example.
36 Neutrosophic Super Matrices and Quasi Super Matrices
Example 2.31: Let
3 2 I A = 2 and B = [2 6 0 | 1 I] 0 I 4
be two neutrosophic super vectors of type A.
3 2 I AB = 2 [2 6 0 | 1 I] 0 I 4
33 2260 21I II 22 = 260 1I 00 II 260 1I 44
Neutrosophic Super Matrices 37
618033I 412022I 2I 6I 0 I I = 412022I . 00000 2I 6I 0 I I 824044I
Example 2.32: Let
0 1 I 2 3 A = and 4 1 I 2 3
B = [0 1 | I 2 0 | 3 4 0 | I 0] be any two neutrosophic super vectors of type A.
We obtain the major product of the super column vector A with the super row vector B of the two neutrosophic matrices.
38 Neutrosophic Super Matrices and Quasi Super Matrices
0 1 I 2 3 AB = [0 1 | I 2 0 | 3 4 0 | I 0] 4 1 I 2 3
00 0 0 101 1I20 1340 1I0 II I I 22 2 2 33 3 3 = 01 I20 340 I0 44 4 4 11 1 1 II I I 2012I2023402I0 33 0 0
Neutrosophic Super Matrices 39
000 000 0000 01 I 2 0 3 4 0 I 0 0I I 2I03I4I0 I 0 022I4 0 6 8 02I0 0 3 3I 6 0 9 12 0 3I 0 = . 0 4 4I 8 0 12 16 0 4I 0 01 I 2 0 3 4 0 I 0 0I I 2I03I4I0 I 0 022I4 0 6 8 02I0 033I600 0000
Major product of two neutrosophic super vectors of type A is illustrated below by the following example.
Example 2.33: Let
2 3 I 1 A = 2 and B = [3 0 1 | 0 I 1] 0 0 1 1
be any two neutrosophic super vectors of type A.
40 Neutrosophic Super Matrices and Quasi Super Matrices
210 3013 3012 3011 I01 BA = 210 0I13 0I12 0I11 I01
32031I310210300111 = 02I31I 01I210 00I111
60I 300 001 = 03II 02I0 0I1
6I 3 1 = . 4I 2I 1 I
Now we proceed onto define the minor product of neutrosophic super vectors of type B.
We only illustrate this by numerical examples for the reader to understand the minor product without any confusion as it will involve lot of notations and symbols repelling non mathematicians away from using these matrices.
Example 2.34: 01 I2 21301I 10 Let A = 000100 and B = be any two 31 I0I001 10 21 neutrosophic super vectors of type B.
Neutrosophic Super Matrices 41
The minor product of AB is defined as follows:
01 I2 21301I 10 AB = 000100 31 I0I001 10 21
21 3 01I 31 01 = 00 010 10010 I2 I0 I 00121
I4 30 12II = 00 00 3 1 0I I0 2 1
43I4I = 31 . 2I 1I
We from the numerical illustration observe the following facts.
1. The minor products of neutrosophic super vectors of type B is always a simple matrix. It may be a simple neutrosophic matrix or may not be a simple neutrosophic matrix.
B1 2. If A = [A1 … At] and B = are neutrosophic Bt supervectors of type B, the minor product AB is defined if and only if 42 Neutrosophic Super Matrices and Quasi Super Matrices
(a) the number of submatrices in A and B are equal.
(b) The product AiBi is compatible, i.e., defined for each i, 1 i t.
(c) The resultant simple matrix is of order mn where m is the number of rows of Ai and n is the number of columns of Bi which is the same for each Ai and each Bi i.e., number of rows of A is the same as that of Ai and the number of columns of B is the same as that of each Bi.
We give yet another numerical illustration to make one understand the working.
Example 2.35:
00I110210 Let A = 1011I0012 and I10001201
201I3 11000 00I10 12011 B = 0123I 12001 10I10 20101 31011
be two neutrosophic super vectors of type B.
We now find the minor product of A with B.
Neutrosophic Super Matrices 43
201I3 11000 00I10 00I11021012011 AB = 1011I00120123I I1000120112001 10I10 20101 31011
201I3 00I1 10 11000 0123I 1011 I0 00I10 12001 I100 01 12011
21010I10 01220101 20131011
12I1I10123I = 321II240I2I3II 2I 1 1 I I 3I 1 2 0 0 1
402I121 82 1 2 3 512I3 1
533I32I6I2 = 114I3I24I4 I7 . 2I 7 4 3I I 3 3I 2
44 Neutrosophic Super Matrices and Quasi Super Matrices
Thus we see if A is a neutrosophic super vector of type B. the transpose of A is denoted by At then AAt is just neutrosophic simple matrix or a simple matrix.
We will illustrate this by an example.
Example 2.36: Let
512411234 01011I123 A = 103200I00 200I01010 I15010101
be a neutrosophic super vector of type B. We now find the minor product of AAt.
5012I 11001 51241123420305 01011I123412I0 AAt = 103200I00 11001 200I01010 1I010 I1501010121I01 32010 43001
512 41 0105012I 11 412 I 0 = 10311001 20 11001 20020305 I0 I15 01 Neutrosophic Super Matrices 45
1234 1I010 I123 21I01 0I00 32010 1010 43001 0101
30 1 11 10 5I 11 17 5 8 4I 1 1100 1 522I1 = 11 0 10 2 I 15 8 2 4 2I 0 0 0 2 4 2I 4I I 2I I 0 5I 11 1 I 15 2I I 26 1 1 0 0 1
30 20 I 2I 4 614 I I2014I I I2 4 2I I I 0 I 4I202 0 64I02
77 26 I 19 2I 14 4I 5I 18 I2617I 2I 2I2 6 = 19 2I 2 I 14 I 2 2I 2I 15 . 14 4I 2I 2 2 2I 6 I 2I 5I 18 6 2I 15 2I I 29
We see AAt is a symmetric simple neutrosophic matrix. It is always a square simple matrix. This simple matrix may be neutrosophic or may not be neutrosophic but it is always symmetric.
We give yet another numerical illustration. 46 Neutrosophic Super Matrices and Quasi Super Matrices
Example 2.37:
Let A be a neutrosophic supervector of type B given by
410213I10521012 2010120010I0600 A = 53I301210101I10 1I010300I001001
410213I10521012 2010120010I0600 AAt = 53I301210101I10 1I010300I001001
4251 103I 01I0 2031 1100 3213 I020 1010 010I 5010 2I00 1011 06I0 1010 2001
Neutrosophic Super Matrices 47
41 0 204251 1 = 01I0 53103I I 1I 0
213I 2031 01201100 30123213 1030 I020
1010 10521 012 010I 06I0 010I0 600 5010 1010 10101 I10 2I00 2001 0I001 001 1011
178 234I 0000 84102 01I0 = 23 10 34 5 3I 0 I I 0 4I 2 53I1I 0000
17 8 9 2I 11 752 6 92I2 146 11 6 6 10
31 2I 7 1 5 0 1 2 2I 1 I 0 I 0 36 6I 0 7031 16I1I0 1I11I2001 48 Neutrosophic Super Matrices and Quasi Super Matrices
67I 152I402I18I 15 2I 11 I 12 7I 8 I = . 40 2I 12 7I 52 2I 12 3I 18 I 8 I 12 3I 13 2I
AAt is clearly a neutrosophic square symmetric matrix of order 4.
Now we proceed on to illustrate major product of neutrosophic super vectors of type B by an example.
Example 2.38: Let
310 121 I01 10130121 012 A = and B = 21011002 60I 0I10010I 102 310 I00
be two neutrosophic super vectors of type B. To find
310 121 I01 10130121 012 AB = 21011002 60I 0I10010I 102 310 I00 Neutrosophic Super Matrices 49
10 1 30121 310 310 310 21 0 11002 121 121 121 0I 1 0010I 10 1 30121 I0121 I010 I0111002 0I 1 0010I 012 012 012 60I10 60I1 60I 30121 10221 1020 102 11002 3100I 31010010I 310 I00 I00 I00
51 310136 5 52I 2 52 2 2 4I III13I0I12I2I 212I2 1 1 2 0 22I = . 6 I 6 I 18 0 6 I 12 6 I 12I3 303 212I 51 310136 5 I 0 I3I0I2II
AB is clearly a neutrosophic super matrix. It may be a super matrix not necessarily neutrosophic.
Now we illustrate the major product of neutrosophic super vector of type B by an example.
50 Neutrosophic Super Matrices and Quasi Super Matrices
Example 2.39:
Consider the two neutrosophic super vectors.
2101 0110 1I00 10010010I I010 0I000I000 A = 001I and B = . 001000010 1I00 0000I0001 000I 1000 0001
The major product of the neutrosophic super vector A with the neutrosophic super vector B is described in the following:
2101 0110 1I00 10010010I I010 0I000I000 AB = 001I 001000010 1I00 0000I0001 000I 1000 0001 Neutrosophic Super Matrices 51
100 10 010I 2101 2101 2101 0I0 00 I000 0110 0110 0110 001000010 0I00 0I00 0I00 000 0I 0001 100 10010I I0100I0 I01000 I010I000 001I 001 001I 00001I 0010 000 0I0001 1I001001I00101I00010I 000I 0I0 000I 00 000I I000 1000001 100000 10000010 0001000 00010I 00010001
2I02II202I1 0I100I01 0 0I000I00 0 I01I00I1 I = 0010I001 I . 1I010I10 I 0000I000 I 10010010 I 0000I000 1
We see AB is also a neutrosophic super matrix.
Now we illustrate by examples the major product of a neutrosophic super vector of type B with its transpose.
52 Neutrosophic Super Matrices and Quasi Super Matrices
Example 2.40: Let
301 0I0 100 100 00I A = 001 100 010 I01 0I0
be a neutrosophic super vector of type B.
Now the transpose of A denoted by
30110010I0 t A = 0I0000010I 1000I10010
301 0I0 100 100 30110010I0 00I AAt = 0I0000010I= 001 1000I10010 100 010 I01 0I0 Neutrosophic Super Matrices 53
301301 30110 301010I0 0I00I0 0I000 0I00010I 100100 1000I 10010010 30110010I0 100 100 100 0I0000010I 00I 00I 00I 100 0I 10010 001 001 001 10030110010I0 100 100 0100I0000010I 010 010 I01100 I01 0I I01 10010 0I0 0I0 0I0
10 0 3 3 I 1 3 0 3I 1 0 0 I000001 0 I 3 0110000 I 0 30110010I0 I000II00I0 = . 1000I10010 30110010I0 0 I000001 0 I 3I10III1I0I10 0 I00000I 0 I
We see in the first place AAT is also a neutrosophic super matrix. Further AAt happens to be a symmetric neutrosophic super matrix.
Thus as in case of usual matrices we get in case of neutrosophic row super vector A of type B, AAT happens to be a symmetric neutrosophic super matrix.
54 Neutrosophic Super Matrices and Quasi Super Matrices
We illustrate this yet by an example as we are more interested in the reader to apply and use it, that is why we are avoiding the notational difficult way of expressing it as a definition.
Example 2.41: Let
01010010 00I01101 A = 000110I0 I0000110
be a neutrosophic super vector of type B.
000I 1000 0I00 1010 At = . 0110 0101 10I1 0100
Neutrosophic Super Matrices 55
Now we find
000I 1000 0I0001010010 1010 00I01101 AtA = 0110 000110I0 0101 I0000110 10I1 0100
000I 000I 01010 010 1000 1000 00I01 101 0I00 0I00 00011 0I0 1010 1010 I0000110 0110 0110 01010 010 0101 0101 00I01 101 10I110I1 00011 0I0 0100 0100 I0000 110
I00 0 0I I 0 010 1 00 1 0 00I 0 I I 0 I 010 2 101I0 = . 00I 1 21 I 1 I0I 0 12 1 1 I101II12I0 00I 0 11 0 1
We see clearly the neutrosophic super matrix is symmetric. 56 Neutrosophic Super Matrices and Quasi Super Matrices
We get yet another example.
Example 2.42:
30110 0001I 10001 0I000 Let B = 2000I 00100 01100 10010
be a neutrosophic super vector of type B.
30102001 000I0010 Bt = 10000110 11000001 0I10I000
Consider
30110 0001I 30102001 10001 000I0010 t 0I000 BB = 10000110 2000I 11000001 00100 0I10I000 01100 10010 Neutrosophic Super Matrices 57
3010 3011000030110 I 0001I1000001I 0 10001110100010 0I10 3010 000I 0I0001000I0000 1100 0I10 3010 000 I 2000I 2000I 100 0 00100 00100 1100 0I10 3010 000I 01100 01100 1000 10010 10010 1100 0I10
58 Neutrosophic Super Matrices and Quasi Super Matrices
2001 3011000 3011010 0001I01 0001I 10 1000100 1000101 I000 2001 0010 0I00001 0I00010 0001 I000 20 01 00 10 2000I 2000I 01 10 00100 00100 00 01 I0 00 2001 0010 01100 01100 0110 10010 10010 0001 I000
11 1 3 0 6 1 1 4 11I I 0 I 001 3 I 2 02I001 00 0I00I0 = . 6I2I04I002 10 000110 10 0I0120 41 102002 Neutrosophic Super Matrices 59
It is easily verified BBT is again a neutrosophic super matrix which is symmetric.
Example 2.43:
20 0I 00 0110101 Let A = and B = 10 0000000 11 01 be a neutrosophic super vectors of type B.
20 0I 00 0110101 Now AB = 10 0000000 11 01
2001 2010101 0I 00 0I 00000 00 00 = 1001 1010101 1100 1100000 01 01 60 Neutrosophic Super Matrices and Quasi Super Matrices
0220202 0000000 0000000 = . 0110101 0110101 0000000
We see AB is a super matrix. Clearly AB is not a neutrosophic super matrix.
Thus it is pertinent to mention here that the major product of two neutrosophic super vectors of type B need not in general be a neutrosophic super matrix; it can only be a super matrix.
This is seen from example.
Now we proceed onto show by a numerical example how the minor product of two super neutrosophic matrices which has a compatible multiplication is carried out.
Example 2.44:
Let A and B be any two super neutrosophic matrices, where
10I010 1001000I0 21010I 010001010 I10001 100II0I00 A = 011100B = 100001100 001010 010100010 0000I0 001010101 301101
Neutrosophic Super Matrices 61
10I010 1001000I0 21010I 010001010 I10001 100II0I00 AB = 011100 100001100 001010 010100010 0000I0 001010101 301101
1 2 I 0 [1 0 0 1 | 0 0 | 0 I 0] + 0 0 3
0I 10 10 010001010 11 100II0I00 01 00 01 62 Neutrosophic Super Matrices and Quasi Super Matrices
010 10I 001100001100 100010100010 010001010101 0I0 101
111 1001 00 0I0 222 III 000 = 1001 00 0I0 000 000 31 0 0 1 3 0 0 3 0 I 0
0I0100 0I01 0I010 10100I 10 I0 10 I00 10 10 10 110100 1101 11010 + 01100I 01 I0 01 I00 00 00 00 0100 01 010 0101 01 100I I0 I00
Neutrosophic Super Matrices 63
1000 01 100 010 010 010 0101 00 010 10I10I 10I 0010 10 101 001 001 001 1000 01 100 100100 100 0101 00 010 010 010 010 0010 10 101 0I0 0I0 0I0 1000 01 100 1010101 10100 101010 0010 10 101
1001000 I 0 I00I I0I00 20020002I0 010001010 I00I000 I 0 010001010 0000000 0 0 110I I1I10 0000000 0 0 100I I0I00 0000000 0 0 000000000 30030003I0 100I I0I00
010100 0 10 10I0I11I0I 001010 1 01 100001 1 00 010100 0 10 0I0I00 0 I0 101011 2 01 64 Neutrosophic Super Matrices and Quasi Super Matrices
1I102I I 0 I 1I 0 31I2 I21I2I1I I11I 111 1I1 = 210I I21I1 0. 1101II0 I 1 0 0I0I 000 I 0 5013I1I12I3I1
Thus the minor product is again a super neutrosophic matrix.
We give yet another illustration.
Example 2.45:
Let A and B be two neutrosophic super matrices where
1011200 0I0010I I121010 A = 00I0101 and 1I01I00 00100I0 11201I1
011I00I 0110101 I001000 B = 10I1001 0100100 1100I0I 0000011 Neutrosophic Super Matrices 65
1011200011I00I 0I0010I 0110101 I121010I001000 AB = 00I010110I1001 1I01I000100100 00100I01100I0I 11201I10000011
101 0I0 I12 0110101 = 00011I00I I I001000 1I0 001 112
1200 010I 10I1001 1010 0100100 + 0101 1100I0I 1I00 0000011 00I0 01I1
66 Neutrosophic Super Matrices and Quasi Super Matrices
Here the usual product of each submatrices are performed and we see in this minor product of neutrosophic super matrices each cell is compatible with usual product of submatrices.
11 1 01 1I00 1 00 0 II I 00 0 = 01 1I00 1 + 11 1 00 0 10 1 11 I 0 0 1
0101 011010 011 I0I0 I00100 I00 12 12 12 0I01 0I1010 0I1 + I0I0 I00100 I00 01 01 01 01 1010 1 12 12 12 I0 0100 0
Neutrosophic Super Matrices 67
10 I100 1 120001 12000010 12000 010I 11 010I 00I0 010I I 00 0001 1 101010 1010I10010101 010101 01010010 01010 1I0011 1I0000I0 1I00I 00I000 00I0000100I01 10 I100 1 01 0010 0 01I1 01I1 01I1 11 00I0 I 00 0001 1
011I00I I 001000 0000000 0 I I0I0I 0III00I 2I112101 = 0000000 I 00I000 011I00I 0 II0I0I 0000000 I 001000 011I00I 2I112101
12I1201 01001I I 21I1I01I 0100111 1II1I01 II00I0I I1I001I11I
68 Neutrosophic Super Matrices and Quasi Super Matrices
1I 3 1I 2I 2 0 1I 01II 01II2I 22II2 2I1I31I022I = I10I111. 1 1 2I 1 2I I 1 2I 0 2I 1 2I I 0 1 I 0 I 3I 3 I 2 2 I 2 I 1 2 2I
We see AB is again a neutrosophic super matrix under the minor product of neutrosophic matrices.
Now we show the minor product of a neutrosophic super matrix with its special transpose can be defined.
Let us first illustrate by a few examples the special transpose of a super neutrosophic matrix.
Example 2.46:
21312 I 0 1I01011 01I1102 Let A = 3I10101 0101010 I110I00
be a neutrosophic super matrix.
Neutrosophic Super Matrices 69
Now the special transpose of A denoted by At is given by a neutrosophic matrix.
21030I 1I1I11 30I101 t A = 111010. 20110I I10010 012100
Example 2.47:
21000303210 0152I I1012I 7890712I012 0I010I60120 Let A = 10I01211230 001001I I127 10011021023 0I10I1I0I12 10102311101 be a super neutrosophic matrix.
To find the transpose of the neutrosophic super matrix A we take the transpose of each of the submatrices in A. 70 Neutrosophic Super Matrices and Quasi Super Matrices
207010101 118I000I0 0590I1011 020100100 0I70101I2 t A = 3I1I21013 ; 01261I2I1 30I01I101 2101210I1 121232210 0I2007321
clearly At is also a neutrosophic super matrix.
At will be known as the special transpose of A.
Clearly if A is a neutrosophic row super vector of type B then the special transpose of A, At is a neutrosophic column super vector of type B.
Similarly if A is a neutrosophic column super vector of type B the At the special transpose of A is a neutrosophic row super vector of type B.
We illustrate this by a few examples.
Example 2.48:
Let A = [2 1 0 | 1 1 1 I 0 | 0 3 I 0] be a neutrosophic super row vector then
Neutrosophic Super Matrices 71
2 1 0 1 1 1 At = , At is a neutrosophic super column vector. I 0 0 3 I 0
Example 2.49:
3 6I 1 2 0 Let A = 1 a neutrosophic super column vector. 1 I 0 2 I
Then the special transpose of A; At = [3 6 I 1 2 0 | 1 1 I 0 | 2 I ]. Clearly At is a neutrosophic super row vector. 72 Neutrosophic Super Matrices and Quasi Super Matrices
Example 2.50:
310 1 I 3 12 I 121040123I Let A = I0I 234I201 0143I0 1 10 1
be a neutrosophic super row vector of type B.
Then At the special transpose of A.
t tt t That is if A = [A1 A2 A3] we see A = AAA123 and the row vectors are arranged as column vectors so that the number of columns of A is equal to the number of rows of At.
31 I 0 1201 01 I 4 10 23I At = I430 304I1 11 2 1 22 0 0 I3I1 1
is neutrosophic super column vector of type B.
Neutrosophic Super Matrices 73
Example 2.51: Let
0I120 100I0 1010I 2 345 0 010I2 10015I A = 7I 0 2 1 3 01011 11111 IIII3 20410 5123I
be a neutrosophic super column vector of type B. The special transpose of A is
01120 1 7I01I 25 I0031 0 0 11I 0 1 At = 10140 0 2 01I 4 2 . 2I05I 1 1 11I 1 3 00I025I3 113 0 I
We see At is a neutrosophic super row vector of type B.
We now illustrate the minor product of the neutrosophic super matrices A with its transpose.
74 Neutrosophic Super Matrices and Quasi Super Matrices
Example 2.52:
3011001201 0I00110010 101I00I101 41021I0012 Let A = 0103000I01 0111210201 I000101010 12010I00I0
be a neutrosophic super matrix.
To find the minor product of A with At.
301400I1 0I011102 10100100 10I23101 01010210 At = 010I010I 10I00010 2010I200 0101001I 10121100
Neutrosophic Super Matrices 75
3011001201 0I00110010 101I00I101 41021I0012 AAt = 0103000I01 0111210201 I000101010 12010I00I0
301400I1 0I011102 10100100 10I23101 01010210 = 010I010I 10I00010 2010I200 0101001I 10121100
301 10 0I0 01 101 I0 301400I1 4102110I23101 0I011102 010 3001010210 10100100 011 12 I00 01 120 10
76 Neutrosophic Super Matrices and Quasi Super Matrices
01201 10010 010I010I 0I101 10I00010 I0012 + 2010I200 00I01 0101001I 10201 10121100 01010 I00I0
301 301 301 3014 0 0I1 0I00I0 0I0 0I01 1 102 101 101 101 1010 0 100 410 410 410 3014 0 0I1 0100 I 01 0101 010102 1010 0 100 0113014 0110 0110I1 I000I01 I001 I00102 1201010 1200 120100
Neutrosophic Super Matrices 77
10 10 10 0110I2 013 01101 I00101 I00 I0210 21 21 21 10I2 3 101 3030 30 01010210 12 12 12 10I2 3 101 01 01 01 0101 0 210 10 10 10
010I 0 10I 01201 01201 01201 10I0 0 010 10010 10010 10010 2010 I 200 0I101 0I101 0I101 0101 0 01I I0012 I0012 I0012 1012 1 100 010I 010I 10I0 0010 00I012010I200I01 00I01 00 0101 0 01I 1012 1 100 010I 0 10I 1020110I0 10201 0 10201010 010102010 01010 I 01010200 I00I00101 I00I0 0 I00I001I 1012 1 100 78 Neutrosophic Super Matrices and Quasi Super Matrices
10 0 4 12 0 1 3I 3 1 0 I 2 3 1 0 1 0 I0I II02I0101 0210 402401I1 I0I2I3II0I 12 I 4 17 1 1 4I 6 2 1 2I 5 6 4 1 2 0 I 0 1 11 0 2 303I6 9 303 1I111202 12I43521 3I 0 I 4I 0 0 I I 0 1 0 1 0 2 1 0 32I1622I 5 10I 23101
603I22I1510 0201I0112I I3 0 2I 2 1I 3 I 0 21I2I52 I212I 2I1 0 I1 2 1I 2I10 0 513I22I160I 11I10 02I 02I02I0 II2I
17 0 7 2I 16 4 2I 7 3I 1 4 03I022II3I2 4I 7 2I 0 4 2I 6 2I 4I 1 4 I 2I 1 I 16 2 2I 6 2I I 27 9 I 7 4I 2 8 2I = . 42II 4I1911I52I0 5 73I4II752I1323I 3I 1 2 2I 4I 2 0 2 3 I 2I 4 4I 1 I 8 2I 5 3 I 2I 6 2I Neutrosophic Super Matrices 79
It is clear that AAt is a neutrosophic super symmetric matrix.
Thus minor product of a matrix A with its special transpose At gives a super symmetric matrix.
It is pertinent to observe A is not a symmetric neutrosophic matrix.
Hence At is also not a neutrosophic symmetric super matrix how ever the product is a symmetric super neutrosophic super matrix.
We give yet another example.
Example 2.53:
30I04000101 0100010010I 60000010001 71011000011 10010101100 00110010110 Let A = 1010I00I000 01I00I00I00 400010I0001 100I0011000 02110I00100 1000I010001
be a super matrix.
To find the minor product of A with 80 Neutrosophic Super Matrices and Quasi Super Matrices
306710104101 010100010020 I000011I0010 000111000I10 400100I0100I t A = 0100100I00I0 00100100I101 000010I00100 1100110I0010 000101000000 1I1100001001
product of A with At.
30I04000101 0100010010I 60000010001 71011000011 10010101100 00110010110 AAt = 1010I00I000 01I00I00I00 400010I0001 100I0011000 02110I00100 1000I010001 Neutrosophic Super Matrices 81
306710104101 010100010020 I000011I0010 000111000I10 400100I0100I 0100100I00I0 00100100I101 000010I00100 1100110I0010 000101000000 1I1100001001
301 010 600 710 100 306710104101 001 010100010020 101 I000011I0010 01I 400 100 021 100
82 Neutrosophic Super Matrices and Quasi Super Matrices
0400 0010 0001 1100 1010000111000I10 1001400100I0100I 0I000100100I00I0 00I000100100I101 010I I001 10I0 0I01
0101 010I 0001 0011 1100000010I00100 01101100110I0010 I000000101000000 0I001I1100001000 0001 1000 0100 0000
Neutrosophic Super Matrices 83
301306 30171010 3014101 010010 01010001 0100020 600100 6000011I 6000010 710 710 710 100306 10071010100 4101 001010 00110001001 0020 101100 1010011I101 0010 01I 01I01I 400 400 400 306 71010 4101 100 100 100 010 10001 0020 021 021 021 100 0011I 0010 100 100 100
000 11100 0I10 0400 0400 0400 400 100I0 100I 0010 0010 0010 010 0100I 00I0 0001 0001 0001 001 00100 I101 1100 1100 1100 00011100 0I10 10101010 1010 400 100I0 100I 10011001 1001 010 0100I 00I0 0I000I00 0I00 00100100 I101 00I0 00I0 00I0 010I 000 010I11100 010I 0I10 I001400 I001100I0 I001100I 10I0010 10I00100I 10I000I0 0I01001 0I0100100 0I01I101
84 Neutrosophic Super Matrices and Quasi Super Matrices
000 010I0 0100 0101 0101 0101 110 0110I 0010 010I 010I 010I 000 10100 0000 0001 0001 0001 1I1 10000 1000 0011 0011 0011 000010I0 0100 11001100 1100 110 0110I 0010 01100110 0110 000 10100 0000 I000I000 I000 1I110000 1000 0I00 0I00 0I00 0001000 0001010I0 00010100 1000110 10000110I 10000010 0100000 010010100 01000000 00001I1 000010000 00001000
10 0 18 21 3 1 4 I 12 3 1 3 0 1 0 1 000 1 0 0 2 0 18036426060 2460 6 2114250707 1 287 2 7 306 7101 0 41 0 1 100 0011 I 00 1 0 = + 406 7112 I 41 1 1 I10 10II1I002I0 1202428404 0 164 0 4 306 7101 0 41 0 1 12020112I0050 306 7101 0 41 0 1
Neutrosophic Super Matrices 85
160040 04I04 0 04I 0 100 1 0 0 I 0 0 I 0 0010 0 1 00 I 1 0 1 4002 1 1 I0 1 I 1 I 0101 2 1 0I 0 I 1I0 0011 1 2 00 I 1I 1 1 + 4I 0 0 I 0 0 I 0 I 0 0 I 0I00 I 0 0I 0 0 I 0 40I1 0 I I01I I 0 2I 001I I 1I00 I 1I I 1 0I011I1 0I 0 I 2I0 4I 0 1 I 0 1 I 0 2I 1 0 2I
2 1I11110I1010 1I 2II I 110 I I 010 1 I 1100001000 1 I 1201001000 1 1 0021I I0110 1 1 01120I0010 = 0000I0I00I00 II00II0I00I0 1 I 1100001000 0 0 0010I00100 1 1 00110I0010 0 0 0000000000
86 Neutrosophic Super Matrices and Quasi Super Matrices
28 1 I 19 26 4 2 4 4I 2I 17 3 2 3 4I 1I 22II 1I 2 1 0 2I1 I 0 3I 0 19 I 38 43 6 1 6 0 25 I 7 0 7 26 1 I 43 54 8 2 7 I 1 30 7 I 3 7 I 4268521I2I42I2I1 21122512II1I31 44I0 6 7I1I 1 22II 4I1I 131I 2I 2I 1 0 1 2I 2I I 1 3I 0 0 2 3I 0 17 I 25 I 30 4 I 4 I 0 18 I 4 I 042I 3077I2I1I1I04I3II2 23I0 32I31323I0 I62I0 34I0 7 7I 1 1 1I 0 42I2 0 12I
We see the minor product of a neutrosophic super matrix A with its transpose At is a symmetric neutrosophic super matrix.
The entries in these super matrices can be replaced from the dual number neutrosophic rings, special dual like number neutrosophic rings, special quasi dual number neutrosophic rings and special mixed dual number neutrosophic rings.
Chapter Three
SUPER BIMATRICES AND THEIR GENERALIZATION
In this chapter we introduce the notion of super bimatrices or equivalently will be known as bisuper matrices. The study of bimatrices has been carried out in [6]. Here we define super bimatrices and generalize them.
This chapter has two sections. Section one defines super bimatrices and enumerates a few of their properties. In section two the generalization of super bimatrices (bisupermatrices) to super n-matrices (n-super matrices) is carried out (n > 2) when n = 2 this structure will be known as bisupermatrices or superbimatrices. When n = 3 we call it as trisupermatrix or supertrimatrix. This can be made into a neutrosophic superbimatrix by taking the entries from Z I or Q I or R I or C I or Zn I.
3.1 Super bimatrices and their properties
In this section we introduce the new notion of super bimatrices (bisuper matrices) and enumerate a few of its algebraic properties and operations on them. 88 Neutrosophic Super Matrices and Quasi Super Matrices
DEFINITION 3.1.1 : Let A = A1 A2 where A1 and A2 are super row vectors of type A, A1 = (a1, a2, …, ar | ar+1… | … | am … an) and A2 = (b1, …, bs | bs+1… | … | bt … br). Then we call A = A1 A2 to be a super birow vectors (bisuper row vectors or super row bivectors) of type A if and only if A1 and A2 are distinct in atleast one of the partitions.
We illustrate this situation by some examples.
Example 3.1.1: Let A = A1 A2 = (3 0 1 | 1 1 0 4 | –5 | 7 8 3 1 2) (1 0 | 3 1 2 | 1 1 0 4| 6 1 0). A is a super row bivector (bisuper row vector) of type A.
Example 3.1.2: Let A = A1 A2 = ( 0 0 | 0 0 0 | … | 0 0 0) (0 0 0 0 0 | 0 0 0 0 0| 0 0), A is a super row bivector of type A also known as the super row zero bivector of type A.
Example 3.1.3: Let A = A1 A2 = (1 1 1 1 | 1 1 1 1 1 1| 1 1) (1 1 | 1 1 1 1 | 1 1 1 1 1 1 1) ; A is a super row bivector of type A. Infact A is also know as the super row unit bivector of type A or bisuper row unit vector of type A.
Example 3.1.4 : Let A = A1 A2 = ( 3 1 0 | 4 5 | 1 1 1 2 5) (3 0 1 | 4 5 | 1 1 1 2 5); A is not a super row bivector for A1 and A2 are not distinct. If A = A1 A2 = (3 | 1 0 4 5 | 1 1 1 2 5) (3 0 | 1 4 5 1 | 1 1 1 2 5) then A is a super row bivector of type A.
Now we proceed on to define the new notion of bilength of the super row bivector of type A.
DEFINITION 3.1.2: Let A = A1 A2 = (a1 … | …. | …| ar … an) (b1 … | …. | …| bs … bn) be a super row bivector of type A where both A1 and A2 are of length n but they are distinct in the partitions. We say A is of bilength n and denote the bilength by (n, n). Super Bimatrices and their Generalization 89
If A = A1 A2 = (a1 … | …. | …| ar … an) (b1 … | …. | …| bs … bn) be a super row bivector of type A (m n) then we say A is of bilength (m, n).
We illustrate this by some examples.
Example 3.1.5: Let A = A1 A2 = (1 0 2 3 | 5 6 7 8 9 | 2 1) (0 1 2 0 | 1 0 9 2 7 | 5 3) be a super birow vector of type A. We say A is of bilength (11, 11), i.e., this super birow vector has same bilength.
Example 3.1.6: Let
A = A1 A2 = (0 1 0 | 2 5 3 | 1 1 0) (3 1 2 0 | 2 1 | 5) be a super birow vector of type A. A is of bilength (9,7). We see this super row bivector has different bilength for its component super row vectors A1 and A2.
We can define the notion of super row bivector equivalently in this form.
DEFINITION 3.1.3: Let A = A1 A2, if A1 and A2 are two distinct super row vectors of type A, then we call A to be a super row bivector of type A.
Now we proceed onto define the notion of super column bivector of type A (super bicolumn vector or bisuper column vector of type A).
DEFINITION 3.1.4: Let A = A1 A2 where A1 and A2 are super column vectors of type A which are distinct. Then we say A is a super column bivector of type A or bisuper column vector of type A or super bicolumn vector of type A.
We illustrate this situation by the following examples.
90 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.1.7: Let
5 3 7 1 7 0 2 1 A = A1 A2 = 4 1 0 1 3 0 1 7 2
be a super bicolumn vector of type A. Clearly A1 and A2 are distinct.
Example 3.1.8: Let
0 0 0 0 0 0 0 0 0 0 0 A = A1 A2 = 0 0 0 0 0 0 0 0 0 0 0 0
be a super column bivector of type A. We say A is the zero super column bivector of type A or super column zero vector of type A. Super Bimatrices and their Generalization 91
Example 3.1.9: Let 1 1 1 1 1 1 1 1 1 1 A = 1 = A1 A2. 1 1 1 1 1 1 1 1 1 1
A is a super column bivector of type A known as the super column unit bivector of type A.
DEFINITION 3.1.5: Let
ab11 A = A1 A2 = abmn
be a super column bivector of type A. If (m n) then we say A is of super bilength (m, n).
If in A = A1 A2 where A1 and A2 are distinct super column vectors, if the length of A1 is the same as that of A2 then we say A is a super column bivector of length n and denote the bilength by (n, n). 92 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.1.10: Let
32 01 20 56 15 A = A1 A2 = 37 08 19 11 04 40
be a super column bivector of type A. A is of bilength (11,11), i.e., both A1 and A2 are of length 11. Clearly A1 and A2 are distinct super column vectors.
Example 3.1.11: Let 3 3 1 4 0 0 1 2 3 7 A = A1 A2 = 1 5 2 8 1 9 1 1 5 10 7
Super Bimatrices and their Generalization 93
be a super column bivector of type A. We say A is of bilength (11,10). Clearly A1 and A2 are of different lengths.
These new type of super birow vectors and super bicolumn vectors will be useful in computer networking, in coding / cryptography and in fuzzy models.
Now we proceed on to define the transpose of a super row bivector and super column bivector of type A.
DEFINITION 3.1.6: Let A = A1 A2 be a super row bivector of type A. We define the transpose of A as the transpose of each of the super row vectors A1 and A2, i.e.,
t t tt A = (A1 A2) = AA 21 . Clearly the transpose of a super row bivector is a super column bivector of type A.
Likewise if A = A1 A2 is a super column bivector of type A then the transpose of A is a super row bivector of type A, i.e., t A is the union of the transpose of the column vectors A1 and A2 t t tt respectively. We denote A = (A1 A2) = AA 21 .
We shall illustrate this by the following example.
Example 3.1.12: Let A = A1 A2
= (0 1 2 3 | 4 3 1 | 7 0 3 5 6 8) (3 0 | 2 5 4 1 | 0 0 7 2 5) be a super row bivector of type A. 94 Neutrosophic Super Matrices and Quasi Super Matrices
0 13 20 32 45 34 The transpose of A denoted by At = 11 = AAtt . 12 70 00 37 52 65 8
It is clear that At is a super column bivector or super bicolumn vector of type A.
Example 3.1.13: Let A = 31 03 10 25 56 67 A A = 18 1 2 09 33 71 42 55 94 Super Bimatrices and their Generalization 95
be a super column bivector of type A. The transpose of A t tt denoted by A = AA12 = [3 0 1 2 5 6 | 1 0 3 | 7 4 5 9] [1 3 0 | 5 6 7 8 9 | 3 – 1 2 5 4].
It is easily verified that At is a super row bivector.
Now having seen the transpose when is the addition and multiplication of these super bivectors of type A is possible.
DEFINITION 3.1.7: Let A = A1 A2 and B = B1 B2 be two super row (column) bivectors of type A. We say A and B are similar or “identical in structure” (identical in structure does not mean they are identical) if the following conditions are satisfied.
1. The bilength of A and the bilength of B are the same i.e., if bilength of A = A1 A2 is (m,n) then the bilength of B = B1 B2 is also (m,n).
2. The partition of the row (column) vector Ai is identical with that of the row (column) vector Bi, true for i=1,2.
We illustrate this by the following examples.
Example 3.1.14: Let A = A1 A2
= [3 1 5 6 | 0 2 3 | 1 5 – 2 3 1 5] [8 0 | 1 2 3 | 7 | 5 6 7 8]
be a super row bivector.
B = [0 4 0 1 | 6 – 12 | 3 0 1 1 0 7] [3 5 | 0 1 0 | 8 | 3 0 1 5]
be another super row bivector. We can say A and B are identical in structure.
We see bilength of A is (13,10) and that of B is (13,10), they are equal.
96 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.1.15: Let A =
8 0 3 1 1 2 0 1 3 1 1 1 4 2 5 0 5 3 A1 A2 = 7 and B = 1 = B1 B2 . 7 4 8 2 1 5 1 3 2 9 8 4 0 8 0 5 3 7
Clearly the super column bivectors A and B are identical in structure and we see the bilength of A is (9,10) and that of B is (9,10) i.e., the bilength of A and B are the same.
Thus we see if two super bivectors of type A are identical in structure they also enjoy the property that they have same bilength. Only to make things clear we mention it as a separate property though the concept identical in structure covers the equal bilength.
However it is pertinent to mention here that equal bilength will not in general imply they are identical in structure. But identical in structure will always imply they have same bilength.
Now we proceed onto define the notion of addition of super bivectors of type A. When we say super bivectors of type A it implies the super bivector can be a sub birow vector of type A or super bicolumn vector of type A; i.e., the term super bivector of type A includes both row bivector as well as column bivector.
Super Bimatrices and their Generalization 97
DEFINITION 3.1.8: Let A = A1 A2 and B = B1 B2 be any two super row bivectors which are identical in structure. Then addition or subtraction of A with B denoted by
A + B = (A1 A2) (B1 B2) is well defined and Ai Bi is carried out component wise and A B is again a super birow vector which are identical in structure with A and B.
On similar lines we can define the addition or subtraction of A with B in case of super column bivectors A and B which are identical in structure.
We illustrate this by the following examples.
Example 3.1.16: Let
3 4 2 0 0 1 1 1 1 1 0 2 2 2 3 3 A = 5 = A1 A2 and B = 3 = B1 B2 4 1 7 0 7 0 3 1 2 2 4 4 0 5 5 1
be two super column bivectors which are identical in structure. We find A+B the sum of A with B to be (A1 + B1) (A2 + B2) 98 Neutrosophic Super Matrices and Quasi Super Matrices
7 2 1 0 0 2 4 6 = 8 = A+B. 3 7 7 4 4 8 5 4
Clearly A+B is again a super column bivector which are identical in structure with A and B.
Now A – B = A1 – B1 A2 – B2
1 2 1 2 2 2 0 0 = 2 . 5 7 7 2 0 0 5 6
We see A – B is again super row bivector of type A identical in structure with A and B. Thus we see the property of identical in structure is preserved under both addition and subtraction.
In view of this we have the following interesting result.
Super Bimatrices and their Generalization 99
THEOREM 3.1.1: Let S = {A = A1 A2 / the collection of all super row bivectors of type A which are identical in structures with A having its entries from Q or R or C or Zn or C(Zn) or 2 2 Z(g), Z(g1) or Z(g2) (g = 0 is a new element g1 = g1 is a new 2 element and g2 = –g2 a new element n is such that, 2 n }. Then S is a group under the operation of addition.
The proof is left as an exercise for the reader.
THEOREM 3.1.2: Let B = {B = B1 B2 / the collection of all super column bivectors of type A which are identical in structure of type A with B having its entries from Q or R or C or 2 Zn or C(Zn) or Z(g) or Z(g1) or Z(g2) (g = 0 is a new element 2 2 g1 = g1 is a new element and g2 = –g2 a new element; n is such that, 2 n }. Then B is a group under the operation of addition of the super column bivectors.
This proof is also simple left as an exercise for the reader.
Now we define the product of a super row bivector of type A with a super column bivector of type A where the multiplication is compatible.
We first show how the minor product of two super vectors are defined whenever the multiplication happens to be compatible.
This is illustrated by some examples.
Example 3.1.17:
Let x = [ 3 0 1 | 2 3 4 5] and y = [1 0 0 | 2 3 1 6]t.
The minor product of the super vectors x with y is given by
100 Neutrosophic Super Matrices and Quasi Super Matrices
1 0 0 xy = [3 0 1 | 2 3 4 5] 2 3 1 6
2 1 3 = [3 0 1] 0 + [2 3 4 5] 1 0 6
= 3 + {4 + 9 + 4 + 30} = 3+47 = 50.
Example 3.1.18: Let 6 1 2 3 4 5 7 x = [0 1 2 3 | 4 5 | 7 8 9 0 1 2 3 | 8] and y = 8 9 6 1 2 3 8 Super Bimatrices and their Generalization 101
be two super vectors 6 1 2 3 4 5 7 xy = [0 1 2 3 | 4 5 | 7 8 9 0 1 2 3 | 8] 8 9 6 1 2 3 8
7 8 6 9 1 4 = [0 1 2 3] + [4 5] + [7 8 9 0 1 2 3] 6 + [8] [–8] 2 5 1 3 2 3
= {0–1 + 4+9} + {–16+25} + {49 – 64 + 81+0–1+4–9} + {–64}
= 12 + 9 + 60 – 64 = 17.
102 Neutrosophic Super Matrices and Quasi Super Matrices
DEFINITION 3.1.9: Let
W1 W x = [V V … V ] and y = 2 1 2 n W n
be two super vectors of type A.
W1 W xy = [V V … V ] 2 1 2 n Wn
= V1 W1 + V2 W2 + … + Vn Wn.
Note:
The compatability of each Vi with Wi is well defined for i = 1, 2, …, n, this is illustrated by the following examples.
Example 3.1.19: Let
x = [1 2 0 1 5 | 3 2 0 | 7 0 – 1 2 3 4 8 | 8 0 1 4]
be a super row vector. Super Bimatrices and their Generalization 103
1 2 0 1 5 3 2 0 7 x t 0 1 2 3 4 8 8 0 1 4
1 2 3 xxt = [1 2 0 1 5] 0 + [ 3 2 0] 2 + 1 0 5 104 Neutrosophic Super Matrices and Quasi Super Matrices
7 0 8 1 0 [7 0 –1 2 3 4 8] 2 + [8 0 1 4] 1 3 4 4 8
= {1 + 4 + 0 + 1 + 25} + {9 + 4 + 0} + {49 + 0 + 1 + 4 + 9 + 16 + 64} + {64 + 0 + 1 + 16}
= {31 + 13 + 143 + 81}
= 268.
Thus we can define the product in case of super row vector x with xt which is as follows:
Vt 1 Vt If x = [V V … V ] then xt = 2 . 1 2 n t Vn
Vt 1 Vt Now xxt = [V V … V ] 2 . 1 2 n t Vn
tt t V11 V V 2 V 2 ... V n V n.
Super Bimatrices and their Generalization 105
We illustrate this by an example.
Example 3.1.20: Let
x = [0 1 | 3 4 0 1 | –3 2 1 6 7 8 9 | 3 2 1 4 5] then
0 1 3 4 0 1 3 2 1 x t 6 7 8 9 3 2 1 4 5
where xt is a transpose of x and x is a super row vector.
106 Neutrosophic Super Matrices and Quasi Super Matrices
0 1 3 4 0 1 3 2 1 xxt [01|3401| 3216789|32|145] 6 7 8 9 3 2 1 4 5
3 2 3 1 0 4 = [0 1] + [3 4 0 1] + [–3 2 1 6 7 8 9] 6 1 0 7 1 8 9
Super Bimatrices and their Generalization 107
3 2 + [3 2 1 4 5] 1 4 5
= {0 + 1} + {9 + 16 + 0 + 1} + {9 + 4 + 1 + 36 + 49 + 64 + 81} + {9 + 4 + 1 + 16 + 25}
= 1 + 26 + 244 + 55
= 326.
Now we proceed onto define the notion of major product of two super vectors.
We shall only illustrate this by simple examples.
Example 3.1.21: Let
0 1 2 4 x = 5 and y = [1 2 | 0 3 4 5 | 8 9 2 1 0] 7 8 1 4 be two super vectors of type A.
The major product of x with y denoted by 108 Neutrosophic Super Matrices and Quasi Super Matrices
0 1 2 4 xy = 5 [1 2 | 0 3 4 5 | 8 9 2 1 0] 7 8 1 4
00 0 112 10345 189210 22 2 44 4 55 5 = 12 0345 89210 77 7 88 8 11 1 12 0345 89210 44 4
0000 0 0 0 0 000 12034589210 2 4 0 6 8 1016184 20 4801216203236840 5 10 0 15 20 25 40 45 10 5 0 7 14 0 21 28 35 56 63 14 7 0 8 16 0 24 32 40 72 81 18 9 0 12034589210 4801216203236840 Super Bimatrices and their Generalization 109
Example 3.1.22: Let
1 4 3 7 0 2 5 1 x and y [340|21013|1214|1] 0 1 1 2 3 4 7 0
be two super vector.
The major product of x with y denoted xy =
110 Neutrosophic Super Matrices and Quasi Super Matrices
1 4 3 7 0 2 5 1 340|21013|1214|1 0 1 1 2 3 4 7 0
We see for major product to be defined we need not have
(1) The natural order of the super column vector to be equal to the transpose of the super row vector.
(2) The number of partitions of x need not be equal to the number of partitions of y.
Super Bimatrices and their Generalization 111
11 1 1 340 21013 1214 1 44 4 4 33 3 3 77 7 7 00 0 0 340 21013 1214 1 22 2 2 55 5 5 11 1 1 0 000 1 111 1 111 2 222 3402101312141 3 333 4 444 7 777 0 000
3402101312141 12 16 0 8 4 0 4 12 4 8 4 16 4 912063039363123 21 25 0 14 7 0 7 21 7 14 7 28 7 0000000000000 6 804 202 6 2 4 2 8 2 15 20 0 10 5 0 5 15 5 10 5 20 5 3402101312141 0000000000000 3402101312141 3402101312141 6 804 202 6 2 4 2 8 2 912063039363123 12 16 0 8 4 0 4 12 4 8 4 16 4 21 28 0 14 7 0 7 21 7 14 7 28 7 0000000000000
112 Neutrosophic Super Matrices and Quasi Super Matrices
Clearly the major product of two super vectors is a super matrix.
Now we show by examples the structure of a major product of a super column vector with its transpose.
Example 3.1.23: Let
3 0 1 5 1 2 3 A = 7 0 2 1 5 0 1
be a super column vector. To find the major product of A with At.
Here At = [3 0 1 5 | –1 2 3 7 0 2 1 | 5 0 1] Super Bimatrices and their Generalization 113
3 0 1 5 1 2 3 Now AAt = [3 0 1 5 | –1 2 3 7 0 2 1 | 5 0 1] 7 0 2 1 5 0 1
33 3 00 0 3015 1237021 501 11 1 55 5 11 1 22 2 33 3 773015 1237021 7 501 00 0 22 2 11 1 55 5 0 3015 01237021 0 501 11 1 114 Neutrosophic Super Matrices and Quasi Super Matrices
9031536 92106 31503 00000000000000 301 5 12 3 702 1 501 15 0 5 25 5 10 15 35 0 10 5 25 0 5 30 1 5 1 2 3 70 2 1 50 1 6021024 61404 21002 9031536 92106 31503 21 0 7 35 7 14 21 49 0 14 7 35 0 0 00000000000000 6021024 61404 21002 301 5 12 3 702 1 501 15 0 5 25 5 10 15 35 0 10 5 25 0 5 00000000000000 301 5 12 3 702 1 501
We see the major product of A with its transpose is a symmetric super matrix.
The symmetry in them occurs in a very special way the main diagonal component is a symmetric matrix where as the other components are transpose of each other; this can be observed from the above super matrix.
Super Bimatrices and their Generalization 115
Example 3.1.24: Let
3 1 2 0 1 4 A = 1 0 2 3 4 5 6
be the super column vector.
To find the major product of A with its transpose.
At = [3 | 1 2 | 0 1 4 | 10 2 3 4 5 6].
We see the major product of A and At results in a special symmetric super matrix whose natural order as well as the matrix order is a square matrix.
116 Neutrosophic Super Matrices and Quasi Super Matrices
3 1 2 0 1 4 We find AAt. AAt = 1 [3 | 1 2 | 0 1 4 | 10 2 3 4 5 6]. 0 2 3 4 5 6
33 312 3014 31023456 11 1 1 3 12 014 1023456 22 2 2 00 0 0 13 1 12 1 014 1 1023456 44 4 4 = 11 11 00 00 22 2 2 33312 3014 3 1023456 44 4 4 55 5 5 66 66 Super Bimatrices and their Generalization 117
93603123069121518 312014102 3 4 5 6 624028204 6 81012 000000000 0 0 0 0 312014102 3 4 5 6 12 4 8 0 4 16 4 0 8 12 16 20 24 = 312014102 3 4 5 6 000000000 0 0 0 0 624028204 6 81012 93603123069121518 12 4 8 0 4 16 4 0 8 12 16 20 24 15 5 10 0 5 20 5 0 10 15 20 25 30 186120624601218243036
It is easily observed that AAt is a super symmetric matrix.
This type of minor and major products in case of super vectors are extended to super bivectors which will be exhibited by one or two examples.
Example 3.1.25: Let
A = [0 1 2 1 | 3 4 | 0 2 1] [1 0 0 0 1 1 | 0 1 2 | 4 1] and
118 Neutrosophic Super Matrices and Quasi Super Matrices
0 11 21 31 40 B = 00 11 12 03 10 1
be two super bivectors. The minor product of A = A1 A2 with B = B1 B2 is given by
AB = (A1 A2) (B1 B2)
= A1 B1 A2 B2
0 1 1 2 1 3 1 4 0 = [0 1 2 1 | 3 4 | 0 2 1] 0 [1 0 0 0 1 1 | 0 1 2 | 4 1] 0 1 1 1 2 0 3 1 0 1 Super Bimatrices and their Generalization 119
1 1 20 = 0121 34 021 0 31 1 4
0 1 1 10 100011 012 2 41 11 3 0 0
= {12 + 4 + 1} {0 + 8 + 1}
= {17} {9}.
We give yet another example.
Example 3.1.26: Let
A = [0 1 2 3 4 | 5 6 | 7 | 8 9 0 1 2 3 4] [ 0 1 2 | 0 1 | 3 0 1 5] and 120 Neutrosophic Super Matrices and Quasi Super Matrices
0 1 0 11 50 10 05 B = 20 12 01 10 02 2 1 0
be two super bivectors.
To find the minor product of A with B.
(In case of minor product we see each of the component submatrix of the row super matrix is multiplied by the corresponding component submatrix of the column super matrix we get the resultant to be a singleton bimatrix, which is clearly not a super matrix).
Super Bimatrices and their Generalization 121
0 1 0 1 5 1 0 AB = [0 1 2 3 4 | 5 6 | 7 | 8 9 0 1 2 3 4] 2 1 0 1 0 2 1 0
1 0 0 5 [0 1 2 | 0 1 | 3 0 1 5] 0 2 1 0 2
122 Neutrosophic Super Matrices and Quasi Super Matrices
1 00 11 = 1 0123400 56 7 2 8901234 0 12 51 0 2 1 51 012 0 01 3015 00 0 2 = {24 + 5 + 14 + 9} {0 + 0 + 16} = {52} {16}.
Now we proceed onto illustrate the major product of two super bivectors in an analogous way as we have done for super vector by some examples.
1 0 0 1 1 2 2 3 3 4 1 0 Example 3.1.27: Let A = 4 1 5 5 6 0 7 1 0 0 1 1 0 Super Bimatrices and their Generalization 123
and B = [ 1 0 | 2 4 3 1 | 0 1 2 3 0 1 0] [3 1 2 0 | 1 1 2 0 0 | 3 0 | 2 5 1 0 1 1] be two super bivectors. To find the major product of these two super bivectors. AB = (A1 A2) (B1 B2) = A1 B1 A2 B2
0 1 2 3 1 = 4 [ 1 0 | 2 4 3 1 | 0 1 2 3 0 1 0] 5 6 7 0 1 1 0 1 2 3 4 0 [3 1 2 0 | 1 1 2 0 0 | 3 0 | 2 5 1 0 1 1] 1 5 0 1 0 1 0 124 Neutrosophic Super Matrices and Quasi Super Matrices
00 0 101 12431 10123010 22 2 33 3 01 2431 0123010 11 1 44 4 55 5 66 6 01 2431 0123010 77 7 00 0 11 1
11 11 312 0 112 0 0 30 2 51011 00 00 11 11 22 22 3120 11200 30 251011 33 33 44 44 00 00 13120 111200 130 1251011 55 55 0 000 11 11 312 0 112 0 0 30 2 51011 00 00 11 11
Super Bimatrices and their Generalization 125
00 0 0 0 000 0 0 000 01 2 4 3 101 2 3 010 02 4 8 6 202 4 6 020 03 6 129 303 6 9 030 01 2 4 3 101 2 3 010 = 04 8 1612404 812040 0 5 10 20 15 5 0 5 10 15 0 5 0 0 6 12 24 18 6 0 6 12 18 0 6 0 0 7 14 28 21 7 0 7 14 21 0 7 0 00 0 0 0 000 0 0 000 01 2 4 3 101 2 3 010
312011200302 51011 000000000000 00000 312011200302 51011 624022400604102022 936033600906153033 12480448001208204044 000000000000 00000 312011200302 51011 15510055100015010255055 000000000000 00000 312011200302 51011 000000000000 00000 312011200302 51011
Thus the major product of two super bivectors is a super bimatrix.
Now we give one more numerical illustration of the major product of two superbivectors 126 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.1.28: Let
3 1 1 0 2 1 3 1 0 1 1 2 0 0 A = 1 0 0 0 2 6 3 1 2 0 1 0 5 2 1
= A1 A2 and B = B1 B2 = [3 1 0 0 | 1 2 0 5 6 7 | 2 1 0] [1 0 1 | 2 3 4 0 5 | 1 1 0 0 0 2 1 0 3] be two super bivectors to find the major product of A with B.
In case of the major product of a column superbimatrix with a row row super bimatrix we get the resultant to be a super bimatrix rectangular square.
AB = (A1 A2) (B1 B2) = A1 B1 A2 B2 Super Bimatrices and their Generalization 127
3 1 1 0 2 1 3 1 0 1 1 2 0 0 [3 1 0 0 | 1 2 0 5 6 7 | 2 1 0] 1 [1 0 1 | 2 3 4 0 5 | 1 1 0 0 0 2 1 0 3] 0 0 0 2 6 3 1 2 0 1 0 5 2 1
33 3 13100 1120567 1210 00 0 11 1 113100 120567 1 210 11 1 22 2 00 0 00 0 00 0 66310 0 12 0567 6 210 11 1 00 0 00 0 223100 1205672 210 111 128 Neutrosophic Super Matrices and Quasi Super Matrices
11 1 22 2 33 3 00101 23405 0 110002103 11 1 00 0 11 1 00 0 2101 223405 2110002103 33 3 22 2 101 23405 110002103 11 1 5101 523405 5110002103
9 3003 6 01518216 30 3 1001 2 0 5 6 7 2 10 00000000 0 0 000 3 1001 2 0 5 6 7 2 10 3 1001 2 0 5 6 7 2 10 3 1001 2 0 5 6 7 2 10 6 2002 4 01012144 20 00000000 0 0 000 00000000 0 0 000 00000000 0 0 000 1860061203036421260 3 1001 2 0 5 6 7 2 10 00000000 0 0 000 00000000 0 0 000 6 2002 4 0 10 12 14 4 2 0 3 1001 2 0 5 6 7 2 10 Super Bimatrices and their Generalization 129
101 2 3 4 0 5 11000 2 10 3 202 4 6 8 01022000 4 20 6 303 6 9 1201533000 6 30 9 000 0 0 0 0 0 00000 0 00 0 101 2 3 4 0 5 11000 2 10 3 000 0 0 0 0 0 00000 0 00 0 101 2 3 4 0 5 11000 2 10 3 000 0 0 0 0 0 00000 0 00 0 202 4 6 8 01022000 6 20 6 303 6 9 1201533000 6 30 9 202 4 6 8 01022000 4 20 6 101 2 3 4 0 5 11000 2 10 3 50510152002555000105015
We see AB the minor product of the two super bivectors is a super bimatrix.
Now we proceed on to illustrate the major product of a super column vector with its transpose, by some numerical examples.
We see the major product of a column super vector with its transpose which is a row super vector get the resultant to be a square symmetric super matrix.
130 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.1.29: Let 2 1 0 1 3 5 0 A = 1 0 3 2 1 7
be a super column vector. To find the major product of A with its transpose At = [2 1 0 1 | 3 5 0 1 0 | 3 2 1 | 7].
2 1 0 1 3 5 t 0 AA = [2 1 0 1 | 3 5 0 1 0 | 3 2 1 | 7] 1 0 3 2 1 7 Super Bimatrices and their Generalization 131
22 22 11 11 2101 35010 321 7 00 00 11 11 33 33 55 55 002101 35010 00 321 7 11 11 00 00 3333 22101 235010 2321 27 11 11 72 1 0 1 73 5 0 1 0 73 2 1 [7][7]
420261002064214 21013 50103 217 0 000 0 0 000 0 0 0 0 21013 50103 217 63039150309 6321 1050515250501510535 0 000 0 0 000 0 0 0 0 = . 21013 50103 217 0 000 0 0 000 0 0 0 0 63039150309 6321 420261002064214 21013 50103 210 1470721350702114749
It is easily verified the major product of a super column vector with its transpose is a super matrix. 132 Neutrosophic Super Matrices and Quasi Super Matrices
Having just seen the major product of a super column vector with its transpose now we proceed on to illustrate the major product of a super column bivector with its transpose by a numerical example in an analogous way.
Example 3.1.30: Let
2 1 1 0 2 1 3 3 0 1 1 A = A A = 0 4 1 2 5 0 7 5 1 1 2 7 0 3 1
be a super column bivector.
t tt A = AA12 = [2 1 0 1 | 3 1 0 | 5 7 1 2 0 1] [1 2 | 3 0 1 4 | 0 5 1 | 7 3].
t tt The major biproduct of AA = (A1 A2) ( AA12 ) which will result in a symmetric square super bimatrix. Super Bimatrices and their Generalization 133
2 1 0 1 3 1 = AAtt AA = 0 [2 1 0 1 | 3 1 0 | 5 7 1 2 0 1] 11 2 2 5 7 1 2 0 1
1 2 3 0 1 4 [1 2 | 3 0 1 4 | 0 5 1| 7 3] 0 5 1 7 3
134 Neutrosophic Super Matrices and Quasi Super Matrices
222 111 2101 310 571201 000 111 333 12101 1310 1571201 000 555 777 111 2101 310 571201 222 000 111
11 1 1 12 3014 051 73 22 2 2 33 3 3 00 0 0 12 3014 051 73 11 1 1 44 4 4 00 0 0 512 53014 5051 573 11 1 1 77 77 12 3014 051 73 33 33 Super Bimatrices and their Generalization 135
420262010142402 21013105 71201 00000000 00000 21013105 71201 630393015213603 21013105 71201 00000000 00000 105051550253551005 147072170354971407 21013105 71201 420262010142402 00000000 00000 21013105 71201
12 30140517 3 24 60280102146 36 903120153219 00 00000000 0 12 30140517 3 4 812041602042812. 00 00000000 0 51015052002553515 12 30140517 3 71421072803574921 36 903120153219
We see the major product of a super column bivector with its transpose a super bimatrix which is symmetric.
136 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.1.31: Let 17 03 16 00 21 12 A = 31 00 10 33 73 51 11 = A A be a super column bivector. At = AAtt = [ 1 0 1 0 1 2 12 | 2 1 3 | 0 1 3 7 5 1] [7 3 6 0 –1 2 1 | 0 0 3 | 3 1 1]; we find t tt tt AA = (A1 A2) ( AA12 ) = AA11 AA 2 2 1 0 1 0 2 1 = 3 [ 1 0 1 0 | 2 1 3 | 0 1 3 7 5 1] 0 1 3 7 5 1 Super Bimatrices and their Generalization 137
7 3 6 0 1 2 1 [7 3 6 0 –1 2 1 | 0 0 3 | 3 1 1] 0 0 3 3 1 1
111 000 1010 213 013751 111 000 222 11010 1213 1013751 333 000 111 333 1010 213 013751 777 555 111 138 Neutrosophic Super Matrices and Quasi Super Matrices
77 7 33 3 66 6 007360 121 003 0 311 11 1 22 2 11 1 00 0 07360 121 0003 0311 33 3 33 3 17360 121 1003 1311 11 1
1010 2 1 3 01 3 7 5 1 0000 0 0 0 00 0 0 0 0 1010 2 1 3 01 3 7 5 1 0000 0 0 0 00 0 0 0 0 202042602614102 1010 2 1 3 01 3 7 5 1 = 3030 6 3 9 03 9 21153 0000 0 0 0 00 0 0 0 0 1010 2 1 3 01 3 7 5 1 3030 6 3 9 03 9 21153 707014721072149357 505010515051535255 1010 2 1 3 01 3 7 5 1 Super Bimatrices and their Generalization 139
49 21 42 0 7 14 7 0 0 21 21 7 7 21 9 18 0 3 6 3 0 0 9 9 3 3 42 18 24 0 6 12 6 0 0 18 18 6 6 0000000000000 73601 21003311 14 6 12 0 2 4 2 0 0 6 6 2 2 7360121003311 0000000000000 0000000000000 21 9 18 0 3 6 3 0 0 9 9 3 3 21 9 18 0 3 6 3 0 0 9 9 3 3 7360121003311 73601 21003311
It is easily seen AAt is a symmetric super bimatrix.
3.2 Operations on Super bivectors
In this section we define the notion of super row bivector of type B and super column bivector of type B. We define the basic operations of addition, subtraction, minor and major product whenever such operations are compatible. This concept is made easy to understand by numerous examples.
Now we proceed onto define the new notion of super row bivector of type B and super column bivector of type B.
DEFINITION 3.2.1: Let A = A1 A2 where A1 and A2 are distinct super row vectors of type B then we call A to be a super row bivector of type B (super birow vector of type B).
We first illustrate this by an example. 140 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.2.1: Let
3013112345 A = 1100101020 5202030405
1012331211 0101100223 = 0512011401 1000102010
A1 A2. A is a super row bivector of type B.
Example 3.2.2: Let
120010311234 A = 315501020123
1001000 2120111 3000001
= A1 A2; we see A is a super row bivector of type B.
Example 3.2.3: Let A = A1 A2 =
00000000 00000000 00000000 00000000
000000000 000000000; 000000000 Super Bimatrices and their Generalization 141
A is a super row bivector of type B. We see A is a zero super row bivector of type B.
Example 3.2.4: Let A = A1 A2 =
11111111111 11111111111 11111111111 11111111111 11111111111
111111111 111111111 111111111
be a super row bivector of type B.
We call this as a super unit row bivector of type B or super row unit bivector or bisuper unit vector of type B.
We now proceed onto define the notion of super column bivector of type B.
DEFINITION 3.2.2: Let A = A1 A2 where A1 and A2 are distinct super column vectors of type B. We call A to be a super column bivector of type B.
We illustrate this by the following examples.
142 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.2.5: Let 301 30145 458 21037 767 12345 841 54321 110 A = A1 A2 = 01010 202 ; 10101 010 12301 123 40512 456 37200 789 012
A is a super column bivector of type B.
We give yet another example before we proceed to give examples of the notion of super zero column bivector and super column unit bivector of type B.
Example 3.2.6: Let
31 1230 21 1110 12 0001 13 A = A A = 2345 30 ; 1 2 6789 10 3102 11 2011 01 51
A is a super column bivector of type B. Super Bimatrices and their Generalization 143
Example 3.2.7: Let
00 00 000 00 000 00 000 00 000 00 A = A A = 000 00 ; 1 2 000 00 000 00 000 00 000 00 00 00
A is defined to be a super zero column bivector of type B.
Example 3.2.8: Let
000 000 000 000 000 000 000 000 000 000 A = A1 A2 = ; 000 000 000 000 000 000 000 000 000 000
A is not a super zero column bivector of type B as A1 = A2. 144 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.2.9: Let A = A1 A2 =
0000 000000 0000 000000 0000 000000 0000 000000 0000 000000 ; 0000 000000 0000 000000 0000 000000 0000 000000 0000
A is a super zero column bivector of type B.
Example 3.2.10: 1111 111 1111 111 1111 111 1111 111 1111 Let A = ; 111 1111 111 1111 111 1111 111 1111 1111
A is a super unit column bivector of type B.
Now as in case of super row bivectors of type B we can define the transpose of a super row bivector of type B. It is easy to see that the transpose of a super row bivector of type B is a super column bivector of type B and vice versa. Super Bimatrices and their Generalization 145
We shall illustrate this situation by some simple examples.
Example 3.2.11: Let A = A1 A2 =
3120301013 1011410100 0120512345
3110345 1111234 0100567 1126011 be a super row bivector of type B.
Now transpose of A denotes
310 101 3101 212 1111 010 1102 t t tt345 by A = (A1 A2) = AA12 0106 011 . 3250 102 4361 013 5471 104 305
It is easily seen that At is a super column bivector of type B.
146 Neutrosophic Super Matrices and Quasi Super Matrices
Example 3.2.12: Let 21 35 013 67 111 01 021 12 456 34 701 56 A = 301 01 084 23 011 45 110 67 101 89 111 12 03
be a super column bivector of type B.
The transpose of A denoted by At =
01047300111 tt A A 11250081101 12 31161141011
23601350246810 . 15712461357923
Clearly At is a super row bivector of type B.
Now as in case of type A super row (column) bivectors we can define identical in structure super row (column) bivectors of type B.
Super Bimatrices and their Generalization 147
DEFINITION 3.2.3: Let A = A1 A2 where A1 and A2 are distinct i.e., A = A1 A2 is a super row bivector of type B. Let B = B1 B2 be a super row bivector of type B.
We say A and B similar or “identical in structure” if the length of Ai and Bi are the same and the number of rows in both Ai and Bi are equal and the partitions in Ai and Bi are identical for i=1,2.
By the term partitions are identical we mean if in Ai the first th partition is say between the r and (r+1) column then in Bi also the first partition will be only between the r and (r+1)th column and the number of partition carried out in Ai will be the same as that carried out in Bi, i=1,2.
We will illustrate this by some simple examples.
Example 3.1.13: Let
301237120132 A = A1 A2 = 110101234015 000511000178
23231254 31002310 and 15000000 01711237
110012003421 B = 010000560001 000170000810
148 Neutrosophic Super Matrices and Quasi Super Matrices
10111001 21001110 31110110 50001111
be two super row vectors of type B. We see A and B are “identical in structure”. For the bilength of A and B is (12, 8).
Also the partitions are identical in Bi and Ai, i=1,2. The number of rows in Ai equal to the number of rows in Bi, i=1,2.
Example 3.2.14: Let
200113378 A = A1 A2 = 116215123
57838800513 91241168157 and 03730074278
135678438 B = B1 B2 = 249012259
10279893155 34501203577 67862007119
be two super row bivectors of type B. We see A and B “identical in structure”. Super Bimatrices and their Generalization 149
Example 3.2.15: Let
31237817 11 57910158 2 2 A = (A1 A2) = 01271569 3 3 11012340 4 4
3417017084 0700011256 1008623708
1111013213 and B = B1 B2 = 2020826127 3021100136
213710438 487623675 be two super row bivectors of type B. We see A and B does not have identical structure.
We define now addition of two super row bivectors of type B of identical structure.
DEFINITION 3.2.4: Let A = A1 A2
111111 aaaaaa 11 1r 1r 1 1s 1t 1m = 111111 aaaaaan1 nr nr 1 ns nt nm
bbbbb11111 11 1u 1r 1s 1w 11111 bbbbbp1 pu pr ps pw 150 Neutrosophic Super Matrices and Quasi Super Matrices
and if B = B1 B2 =
222222 aaaaaa 11 1r 1r 1 1s 1t 1m 222222 aaaaaan1 nr nr 1 ns nt nm
bbbbb22222 11 1u 1r 1s 1w 22222 bbbbbp1 pu pr ps pw
are two super row bivectors of type B. We see A and B are identical in structure. The sum of A and B denoted by A+B = (A1 A2) + (B1 B2) = A1 + B1 A2 + B2
12 121 2 12 12 12 aa aaa a aa aa aa 11 11 1r 1r 1r 1 1r 1 1s 1s 1t 1t 1t 1t 12 121 2 12 12 12 aan1 n1 aaa nr nr nr 1 a nr 1 aa ns ns aa nt nt aa nt nt 12 12 1 2 12 1 2 bb bb b b bb bb 11 11 1u 1u 1r 1 1r 1 1s 1s 1w 1w 12 12 1 2 12 12 bbp1 p1 bb pu pu bpr 1 b pr 1 bb ps ns bbpt pt
is defined to be the sum of the two super row bivectors A and B of type B. Clearly A+B is again a super row bivector of type B with identical structure with A and B.
Now in view of this we have the following interesting theorem.
THEOREM 3.2.1: Let X = {A = A1 A2 be the collection of all super row bivector of type B which are identical in structure with A with entries from the field Q or R or C or Zp (p a prime) or from the rings Z or Zn, n not a prime or C(Zp) or Z(g1) or Super Bimatrices and their Generalization 151
2 Z(g2) or Z(g3) (g1, g2 and g3 are new elements such that g1 = 0, 2 2 g2 = g2 and g3 = –g3 and Z can be replaced by Q or R or C or
C(Zn) or Zn}. Then X is a group under addition.
Example 3.2.16: Let X = X1 X2 =
3210 10013 4 0 1 1526 0 1231 0 0 1 0630 6 1000 10 0
31414130021011 and 632 120111020 11
3 1 0010110 40 1 Y = 0 12010201 0 0 1 0 1 3101010 1 1 1
30 1 0301012 1011 21 110201011101
= Y1 Y2 be two identical structure with the super row bivector of type B. To find the sum
X+Y = (X1 X2) + (Y1 Y2) = (X1 + Y1) (X2 + Y2)
031000123000 = 144611432000 076162010011
0 1517 1401400 2 2 . 8 4 102 2 121121 12
We see X+Y is again a super row bivector with identical structure as that of X and Y. The subtraction of X with Y 152 Neutrosophic Super Matrices and Quasi Super Matrices
X–Y = (X1 – Y1) (X2 – Y2)
611020103802 = 160 6 11 0 3 0 0 0 2 050 1 6 0 0 10 2 1 1
6 1311 120 10 20 00 . 423 22 2101 12 1 10
X–Y is again a super row bivector of type B.
Now in a similar way we can define the notion when are two super column bivectors of type B are “identical in structure”. Let A = A1 A2 and B = B1 B2 be two super column bivectors of type B. We say A and B are super column bivectors of type B are identical in structure if the number of natural rows in Ai is equal to Bi, i=1,2 and the number of columns in Ai equal to Bi and the partition of Ai and Bi are identical. We can as in case of identical structure super row bivectors of type B, we can in case of identical structure of super column bivectors of type B, we can define addition and subtraction of super column bivectors of type B.
Example 3.2.17: 310 0 328 001 1 060 402 1 110 320 0 101 10 12 641 123 4 001 Let A = and 670 2 702 023 1 080 10 1 1 103 425 6 462 012 0 675 018 3 320 Super Bimatrices and their Generalization 153
010 0 012 001 0 020 10 10 110 010 1 010 110 2 011 003 6 110 B = 112 4 102 001 3 063 10 0 0 1 0 1 201 1 215 800 1 0 10 011 4 025 be two super column bivector of type B. The sum of A+B = (A1 + B1) (A2 + B2)
32 0 0 3 310 00 2 1 0 8 0 50 1 1 2 2 0 33 0 1 1 1 1 11 1 4 6 5 2 12 6 10 1 1 1 78 2 6 8 0 4 02 4 4 0143 20 1 1 2 0 4 62 6 7 6 7 7 81 2 1 6 6 5 02 9 7 3 4 5 is again a super bicolumn bivector of type B.
In view of this we have the following interesting theorem. 154 Neutrosophic Super Matrices and Quasi Super Matrices
THEOREM 3.2.2: Let V = {X = X1 X2 / collection of all super column bivector of type B with entries from a field or ring which are identical in structure}. Then V is a group under addition.
However to define multiplication we have to define either minor product or major product.
We proceed onto give the minor product of two super bivectors of type B by numerical illustrations.
Example 3.2.18: Let
15325701 X = (X1 X2) = 06211011 27100101
12010112340 01102101001 01010500112 10103011001
1201 0115 310 0010 100 2100 001 1001 002 and Y = 0110 = Y1 Y2 101 1001 221 0101 453 1010 012 0201 0120 Super Bimatrices and their Generalization 155
be two super bivectors.
The minor product of X with Y is given by XY = (X1 X2) (Y1 Y2) = X1 Y1 X2 Y2.
310 100 001 15325701 002 = 06211011 101 27100101 221 453 012
1201 0115 0010 2100 12010112340 1001 01102101001 0110 01010500112 1001 10103011001 0101 1010 0201 0120
153310 2 = 062100 1002 271001 0
156 Neutrosophic Super Matrices and Quasi Super Matrices
101 12011201 5701 221 01100115 1011 453 01010010 0101 012 10102106
1001 01 12340 0101 211001 01001 1010 050110 00112 0201 30 11001 0120
8 1 3 0 0 4 19 15 14 = 602 002 5 6 6 13 2 1 0 0 0 2 3 3
0110 3521 41037 2112 0125 0 2 21 0550 2215 1 4 51 3003 1211 1 2 22
7166 8 27 16 21 24 58 = 11 6 10 . 311116 15 5 4 54 35
It is pertinent to mention that the entries of these super matrices can be replaced by neutrosophic rings, special dual like number neutrosophic rings, special quasi dual number neutrosophic rings and mixed special dual number neutrosophic rings.
Chapter Four
QUASI SUPER MATRICES
A square or a rectangular matrix is called as a quasi super matrix. It cannot be obtained by partition of a matrix. All super matrices are quasi super matrix but quasi matrix in general is not a super matrix. Thus the elements of a quasi matrix are submatrices following some order.
DEFINITION 4.1: Take a m × n matrix A with entries from real or complex numbers.
AA11 12 A1r 1 AA21 22 A2r A = 2 AA A s1tt s2 sr tm
where Aij are submatrices of A with 1 j r1 , r2, …, rm and 1 i s1, s2, …, st.
158 Neutrosophic Super Matrices and Quasi Super Matrices
Clearly we do not demand the size of Aji to be same but the only condition to be satisfied is that if A is a m × n matrix then the number of the rows in each column of the matrix adds up to m and the number of the columns in each of rows added up to n. We define A to be a quasi super matrix.
Further we do not demand r1 = r2 and ri = rj in general also. Also si sj in general.
We give examples of one or two quasi super matrix before the proceed on to define some of their basic properties.
Example 4.1: Let A be a 6 × 4 quasi super matrix given by
321 2 015 0
983 2 AA11 12 A = = 141 4 AA21 22 253 0 315 1
where
321 2 A11 = , A12 = , 015 0
98 32 14 14 A21 = and A22 = . 25 30 31 51
We see the sum of the rows of A11 and A21 adds up to 4 and sum of the rows of A12 and A22 adds up to 6 where as some of columns adds up to 4 i.e., the sum of the columns of A11 and A12 is 4 and that of A21 and A22 is also 4. Quasi Super Matrices 159
Next we give some more examples.
Example 4.2: Let A be 9 × 8 quasi super matrix given by
2031 12 30 0521 21 11 3120 1 310 1211 0 A = 031 3300 2 202 5111 1 303 012 2 0 110 110 1 4 101
AAA11 12 13 = AAA21 22 23 AAAA31 32 34 33
Clearly the number of columns added up in A11 A12 and A13 to 4 + 2 + 2 = 8.
The sum of the columns added up in A21 A22 and A23 to 4 + 3 + 1 = 8. The sum of the columns of A31 A32 A34 and A33 to 3 + 1 + 3 + 1 = 8.
We see basically A is a 8 × 8 matrix but by the division it is made into a quasi super matrix of the given form having 10 number of submatrices. A11, A12, A13, A21, A22, A23, A31, A32, A33 and A34.
Now any 8 × 8 matrix can form a division in the following form given in the example 4.3.
160 Neutrosophic Super Matrices and Quasi Super Matrices
Example 4.3: Let A be any 8 × 8 matrix.
52102 031 11021 152 00110 001 52001 11220 A = 19312 01010 120 10101 315 22025 115 31020
AA11 12 = . AA21 22
Here the sum of the rows of the sub matrices A11 and A21 is 3 + 5 = 8 and sum of the columns of the sub matrices A21 and A22 is 5 + 3 = 8. We make the following observation we see all the four sub matrices are square matrices based on these observations we make the following definition.
DEFINITION 4.2: Let A be the m × m square matrix. If all the sub matrices of A are also square matrices then we call A to a quasi super square matrix.
The matrix given in example 4.3 is a square quasi super matrix. We give yet another example before we define some more results.
Example 4.4: Let A be a 8×8 matrix with the following representation.
Quasi Super Matrices 161
031521 02 01 152110 001001 10 793121 01 A = 010101 20 101013 20 22 02 53 15 31 02 01 15
A12 AA = 11 22 A 23 AAAA21 31 24 25
Sum of the rows A11 and A21 = 8, Sum of the rows A11 and A23 = 8, Sum of the rows A11 and A24 = 8, Sum of the rows A12, A22, A23, A25 is 8, Sum of the columns of A11 and A12 is 8, Sum of the columns of A11 and A22 is 8, Sum of the columns of A11 and A23 is 8, Sum of the columns of A21, A31, A24 and A25 is 8.
Example 4.5: Let A be a 5 × 6 matrix which is given in the following.
301 561 110 325 A = 212 102 21 01 11 02 10 11
162 Neutrosophic Super Matrices and Quasi Super Matrices
AA11 12 = AAA21 22 23
where A11, A12, A21, A22 and A23 are submatrices.
Clearly sum of rows of A11 and A21 is 5, sum of rows of A12 and A22 is five and that of A12 and A23 is five.
Sum of the columns A11 and A12 is six. Sum of the columns of A21 A22 and A23 is six.
Example 4.6: Let A be a 6 × 6 quasi super matrix with
AA11 12 00 A = AA , AA21 22
where A11 is a 4 × 4 square matrix and A12 is a 2 × 2 square matrix. A21 is a 2 × 2 square matrix and A22 is a 4 × 4 square matrix.
Now
031 2 110 5 A11 = , 512 1 010 1
01 A12 = , 21
11 00 A21 = , A° = A° = and 02 00
Quasi Super Matrices 163
6012 1002 A22 = . 1100 0101
031201 110521 512 100 010100 A = . 006012 001002 111100 020101
We see all the six sub matrices are square matrices.
Example 4.7: A be a 4 × 5 matrix which is a quasi super matrix given by
010 20 100 10 A = 111 11 101 01
AA11 12 = . AA21 22
Similarly we proceed on to define the notion of quasi super matrix which is rectangular.
DEFINITION 4.3: Let A be a quasi super matrix.
164 Neutrosophic Super Matrices and Quasi Super Matrices
AA A 11 12 1r1 AA21 22 A1r A = 2 AA A s112 s 2 sr tm
Aij’s are rectangular matrices, with 1 < i < r1, r2, …, rm and 1 < j < s1, s2,…, st, we define A to be a quasi super rectangular matrix.
We give an example of a matrix of this type.
Example 4.8: Let A be a 6 × 8 matrix quasi super matrix. 2012 1100 1105 1011 110 50111 A = 101 11010 111 10001 201 22022
AA11 12 = . AA21 22
A is a rectangular quasi super matrix.
Example 4.9: Let A be a 6 × 4 matrix. 210 1 112 0 120 1 A = 1025 3102 1110 Quasi Super Matrices 165
AA11 12 = A21 which is a quasi super matrix. Sum of the columns of A11 and A12 is four.
Number of columns in A21 is four. Sum of rows of A11 and A21 is six. Sum of rows of A12 and A21 is six. The quasi super matrix described in example 4.9 is not a rectangular quasi super matrix for it contains a 3 × 3 square matrix in it.
We proceed on to define these type of matrices,.
DEFINITION 4.4: Let A be a m × n rectangular matrix. A be a quasi super matrix.
AA11 12 A1r 1 AA21 22 A1r A = 2 AA A s112 s 2 sr tm
If some of the Aij’s are square submatrices and some of them are rectangular submatrices, then we call A to be mixed quasi super matrix.
Thus we have seen 3 types of quasi super matrices.
We have to give some more examples for we can have a square m × m matrix A: yet A can be a mixed quasi super matrix or a rectangular quasi matrix. Likewise a square m × m matrix can be a mixed quasi super matrix.
Example 4.10: Consider a 6 × 6 quasi super matrix where
AA11 12 A = AA21 22 166 Neutrosophic Super Matrices and Quasi Super Matrices
where
4102 12 A11 = = A12 6025 21
312 101 101 010 A21 = and A22 = 010 111 210 022
201421 520612 312101 i.e., A = . 101010 010111 210022
A is a 6 × 6 matrix but A is not a rectangular quasi super matrix or a square quasi super matrix it is only a mixed quasi super matrix.
Thus this example clearly shows a quasi super matrix which is a 6 × 6 square matrix can be a quasi super mixed square matrix.
Next we proceed on to give an example of a square matrix which is only a rectangular quasi super matrix.
Example 4.11: Let A be a 5 × 5 quasi super square matrix.
Quasi Super Matrices 167
01234 12340 A = 23401 34012 40123
AA11 12 = AA21 22 A51 where
34 012 A11 = , A12 = 40 123 01
234 A21 = , A22 = [ 1 2 ] and 340
A31 = [ 4 0 1 2 3 ].
A is a quasi super rectangular matrix.
Example 4.12: Let A be a 6 × 4 quasi super rectangular matrix.
0123 1102
2010 AA11 12 A = = . 1671 A21 5208 3192
168 Neutrosophic Super Matrices and Quasi Super Matrices
Clearly A is a square quasi super matrix which is not a square matrix. We see all the three submatrices of A are square matrices.
Now having seen three types of quasi super matrices, we now proceed on to define some sort of operation on then. First given any n × m matrix which we are not in a position to give a partition as in case of super matrices.
So we define in case of n × m matrices a new type of relation called quasi division.
A quasi division on the rectangular array of numbers is a cell formation such that the cells are either square, rectangular or row or column or singletons. Clearly or is not used in the mutually exclusive sense.
We just illustrate this by a very simple example.
Example 4.13: Let A be a 7 × 6 quasi super matrix.
078941 101010 11 1101 A = 801210 . 011101 21 1400 100111
We see the matrix or this 7 × 6 array of numbers which have been divided in 10 cells. Each cell is of a varying size. For we see first cell is a 2 × 2 square matrix.
07 = I cell = A11 10 Quasi Super Matrices 169
The second cell is a rectangular 2 × 3 matrix.
894 is the II cell-A12 101
1 is the III cell - A13 is a 2 × 1 column vector or matrix. 0
1 The fourth cell is again a column vector given by 8 = A21 0
The fifth cell is [1], a singleton A22. The sixth cell is [–1 1 0 1] is a row vector A23.
2 The seventh cell is a column vector = A31. The eighth cell is 1 a 4 × 3 rectangular matrix.
012 111 = A32 114 001
The ninth cell is a 3 × 2 rectangular matrix.
10 01 = A33. 00
th The 10 cell find its place as A44 a row vector [11]. The arrangement of writing or notational order is written in this form 170 Neutrosophic Super Matrices and Quasi Super Matrices
AAA11 12 13 AAA A = 21 22 23 AAA 31 32 33 A44
We see the sum of the columns of A11, A12 and A13 is 6. Sum of the columns of A21, A22 and A23 is six.
Sum of the columns of A31, A32 and A33 is six. (1+3+2=6). Also sum of the columns of A31, A32 and A44 is six.
Now having seen as example we define the notion of cell partition.
DEFINITION 4.5: A cell partition of m × n rectangular array of numbers A is a division of the m × n array of numbers using cells. The cells can only be singletons or row vectors or column vectors or square matrix and (or) rectangular matrix. i.e., each cell can be called as a sub matrix of A.
For instance this process is like finding subsets of a set. In that case we have lots of choices and we know given N number of elements in the set; the number of subsets is 2N. But dividing the n × m array of numbers of the n × m matrix is not identical for the cell division is not arbitrary each cell should have a form and the division can be many for instance we will first illustrate in how many ways a 2 × 2 matrix can be divided using the method of cell division,
01 Example 4.14: Let A = 23
We enumerate the number of cell division leading the quasi super matrix.
01 A11 A1= = A12 , 23 A21 Quasi Super Matrices 171
01 AA11 12 A2 = = , 23 A22
01 A3 = 23
01 and A4 = 23
There are only 4 quasi super matrices constructed using a 2 × 2 matrix.
However we have several partitions leading to a super matrix.
01 B = is a partition, 23
B is a super matrix.
01 C = is a super matrix different from B. 23
01 D = is a super matrix different from both B and C. 23
Thus using 2 2 matrices we have only 3 super matrices. But using cell division leading to quasi super matrix we have 4 quasi super matrices. Thus we have altogether 7 quasi super matrices if we make the rule all super matrices are quasi super matrices. That is the class of super matrices is contained in the class of quasi super matrices.
172 Neutrosophic Super Matrices and Quasi Super Matrices
Example 4.15: Let
012 A = 101 111 be a 3 × 3 matrix.
The number of quasi supermatrices from A are
012 AA11 12 A1 = 101 = A22 111
012 AA11 12 A2 = 101 = A22 111
012 A12 A3 = 101 = AA11 22 111 A13
012 A13 A4 = 101 = AA11 12 A23 111
012 A13 A5 = 101 = AA11 12 A23 111
012 AAA11 12 13 A6 = 101 = A23 111 A33 Quasi Super Matrices 173
012 AAA11 12 13 A7 = 101 = A22 111
012 AAA11 12 13 A8 = 101 = A22 111
012 AAA11 12 13 A9 = 101 = A22 111 A32
012 AAA11 12 13 A10 = 101 = AA22 23 111
012 AAA11 12 13 A11 = 101 = AA22 23 111
012 AAA11 12 13 A12 = 101 = AA22 23 111 A33
012 AAA11 12 13 A13 = 101 = AA22 23 111
174 Neutrosophic Super Matrices and Quasi Super Matrices
012 AAA11 12 13 A14 = 101 = AA22 23 111
012 AAA11 12 13 A15 = 101 = AA22 23 111 A33
012 AAA11 12 13 A16 = 101 = AA22 23 111 A32
012 AAA11 12 13 A17 = 101 = AA22 23 111 A32
012 AAA11 12 13 A18 = 101 = AA22 23 111 A33
012 AAA11 12 13 A19 = 101 = AAA21 22 23 111 AA32 33 and so on.
Thus we see even in case of a 3 × 3 matrix the number of quasi super matrix is very large. If we make the inclusion of super matrix into it. It will still be larger.
Thus at this juncture we propose the following problem.
Problem: Suppose P is any m × m square matrix. i.e., a square array of m × m numbers. Quasi Super Matrices 175
1. Find the number of super matrix constructed using P. 2. Find the number of quasi super matrix constructed using P.
Now we just try to work with a 2 × 4 matrix.
3210 Example 4.16: Let M = be a 2 × 4 matrix. 0101
We just indicate some of the quasi super matrix constructed using M.
0123 A12 M1 = = A11 1010 A22
0123 A13 M2 = = AA11 12 1010 A23
0123 AAAA11 12 13 14 M3 = = 1010 A23
0123 AAA11 12 13 M4 = = 1010 AA23 24
0123 AAA11 12 13 M4 = = 1010 AA23 24
0123 AAAA11 12 13 14 M5 = = 1010 A23
0123 AA11 12 M6 = = 1010 A22 176 Neutrosophic Super Matrices and Quasi Super Matrices
0123 AAA11 12 13 M7 = = 1010 A22
0123 AA11 12 M8 = = 1010 AA22 23
0123 AAA11 12 13 M9 = = 1010 A21
and so on. Thus we see even in case of the simple 2 × 4 matrix, we can have several quasi super matrices. We have shown only nine of them.
Now we propose the following problem.
Problem
1. Find the number of quasi super matrices that can be constructed using m × n matrix.
2. Find the number of super matrices that can be constructed using just a m × n rectangular matrix.
Now having defined the notion of cells partition of a matrix which has lead to the definition of quasi super matrices we proceed on the study the further properties of quasi super matrices like matrix addition and multiplication and see how best those concepts can be defined on them.
Example 4.17: Let A be a 9 × 4 rectangular matrix.
Quasi Super Matrices 177
0125 1101 0111 1010 A = 0101 1100 1001 2135 1234
AA11 12 AA = 21 22 . A 32 AAA41 42 43
We see A has 8 cells. We can have for the same A we can just have only 4 cells.
0125 1101 0111 1010 AA11 12 A = 0101 = . AA21 22 1100 1001 2135 1234
Suppose we have two quasi super matrices how to add? We first proceed on to define addition of a super quasi matrix A with itself. 178 Neutrosophic Super Matrices and Quasi Super Matrices
Example 4.18: Let A be a 5 × 7 quasi matrix with a well defined cell partition defined on it.
0123456 1101101 A = 0110110 5782143 8170 2 5 8
AAA11 12 13 = A22 . AAA31 32 33
0 2 4681012 2202202 A + A = 2A = 0220220 10 14 16 4 2 8 6 16 2 14 0 4 10 16
2A11 2A 12 2A 13 = 2A22 = 2A. 2A31 2A 32 2A 33
It is left as an exercise for the reader to verify that for the quasi super matrix A we have A – A = [0]. In this case
0000000 0000000 A – A = 0000000 . 0000000 0000000 Quasi Super Matrices 179
Just a quasi super matrix A under the same cell division can be added any number of times and this will not change the nature of a quasi super matrix cell division.
Thus we can say if A is a quasi super matrix then A + … + A: n times is the same as nA.
If A has A11, A12, …, Art to be the collection of all its submatrices then nA will have nA11, nA12, …, nArt to be the collection of all its submatrices.
Note: We can always take any m × n zero matrix and make the cell partition or division in a desired form so that A + (0) = (0) + A = A. For this we first define a simple notion called cell division function.
Suppose we have two m × n matrices A and B. We know the cell division of A how to get the same cell division of B so that the cell divisions of both A and B are the same and both of them are quasi super matrices of same type or similar.
DEFINITION 4.6: Let A be a m × n quasi super matrix. B any m × n matrix. To make B also a quasi super matrix similar to A; define a cell function Fc from A to B as follows.
Fc(A11) = B11 formed from B by taking the same number of rows and columns from B. So that A11 and B11 have the same number of rows and columns, not only that the placing of B11 in B is identical with that of A11 in A.
The same procedure is carried out for every Aij in A.
Thus the cell function Fc converts a usual m × n matrix B into a desired quasi matrix A.
Before we proceed on to define the properties of Fc we show this by some illustrations.
180 Neutrosophic Super Matrices and Quasi Super Matrices
Example 4.19: Let A be a given 3 × 5 quasi super matrix. B be any matrix. To find a similar cell division on B identical with A. Given 03520 A = 14412 25304
AA11 12 = AAAA21 22 23 24
is a quasi super matrix with A11, A12, A21, A22, A23 and A24 as submatrices.
Given
0 0.3 4 0.1 2 B = 14020 35111
Define the cell function Fc from A to B as follows.
00.3 Fc(A11) = = B11, 14
Fc(A12) = [4 0.1 2] = B12,
Fc(A21) = [3 5 1] = B21,
Fc(A22) = [0] = B22,
2 Fc(A23) = = B23 1
Quasi Super Matrices 181
0 and Fc (A24) = = B24. 1
0 0.3 4 0.1 2 B = 14020 35111
BB11 12 = . BBBB21 22 23 24
We enumerate some of the properties of Fc. Let Fc be a cell division function from A to B where A is a quasi super matrix.
Fc(A) = A
i.e., A is equivalent to A under Fc; i.e., Fc is reflexive.
If Fc(A) = B, i.e.,
A is equivalent to B under Fc then B is equivalent to A under Fc.
i.e., if Fc(A) = B then Fc (B) = A.
(Fc (Fc(A)) = A for all A).
If A is any quasi super matrix and B and C any two m × n matrices. If Fc is the cell division function such that Fc(A) B so that B becomes a quasi super matrix. Suppose Fc(B) C so that C becomes a quasi super matrix, then we see A, B and C and quasi super matrices with
A~B and B~C implies A~C.
Thus Fc is an equivalence relation on the class of all m × n matrices under a special or a specified cell division function.
182 Neutrosophic Super Matrices and Quasi Super Matrices
If we take the collection of all cells partitions of a m × n matrix and denote it by C then C is divided into disjoint Fc Fc classes by this relation i.e., C= {F | F ; A B; A and B Fc c c m × n matrices, A is a quasi super matrix and B any m × n matrix}
We illustrate this by an example.
Example 4.20: Let
ab T = a, b, c, d Z2 = {0, 1}}. cd
To find the partition of T under the cell division function.
First we find the number of elements in C. Fc
0 ab Fc = cd
1 ab Fc = cd
2 ab Fc = cd
3 ab Fc = cd
4 ab Fc = cd
Quasi Super Matrices 183
5 ab Fc = cd
6 ab Fc = cd
7 ab Fc = cd
We see C = {F,0 F,1 F,2 F,3 F,4 F,5 F6 , and F,7 Fc c c c c c c c c i.e., | C| = 8. Fc Now we have to find the number of matrices in T.
T =
00 11 10 01 00 00 11 10 ,,,,,,,, 00 11 00 00 10 01 00 10
01 00 10 01 11 11 01 10 , , , ,,,, . 01 11 01 10 10 01 11 11
Thus each and every class in C will have all the 16 Fc elements of T with no over lap.
If C is the class then every class contains exactly the same Fc number of elements in the set of matrices on which the quasi super matrices notion is to be defined.
Now as partition yields to a super matrix we see cell division leads to the concept of quasi super matrix.
Now two m × n quasi super matrix can be added if and only if they have the same cell division defined an them, otherwise 184 Neutrosophic Super Matrices and Quasi Super Matrices
we say addition is not compatible for the cell division is not compatible.
Example 4.21: Let
301 2 5 710 1 1 600 1 0 A = 301 0 0 125 11 116 2 1
AA11 12 = AAA21 22 13 ; A31
where A11, A12, A21, A22, A13 and A31 are submatrices of A.
11002 50110 BB11 12 62102 B = = BB. 11011 21 22 B31 20101 30220
Clearly the addition of A and B is not compatiable for we see the submatrices B11, B12, B21, B22, and B31 are different from A11, A12, A21, A22, A13 and A31.
Thus we see addition of A with B is impossible though both A and B are of same order viz., 6 × 5.
Thus is a quasi super matrix addition is compatiable if and only if (1) A and B are quasi super matrix of same order and Quasi Super Matrices 185
(2) cell division on A and B are the same that is we have a cell division function Fc: A B such that Fc(A) = B true.
Now we illustrate this situation by a simple example.
Example 4.22: Let
01234 56789 06284 A = 51739 11012 02101
AA11 12 = AAA21 22 23 A31 where A11, A12, A22, A23 and A31 are sub matrix of A.
10101 01010 11111 B = 11001 10011 01001
BB11 12 = BB22 23 B31
We see the total number of columns in B11 and B12 is 5; in B22 and B23 is 5 in B31 and B23 is 5. 186 Neutrosophic Super Matrices and Quasi Super Matrices
Now the addition of A and B is compatible.
01234 10101 56789 01010 06284 11111 A + B = + 51739 11001 11012 10011 02101 01001
0110 2130 41 5061708190 0161 21 81 41 = 5111703091 11 10 0 0 11 21 0021100011
1133 5 5779 9 1739 5 = . 627310 2102 3 0310 2
It is important and interesting to note that in case of quasi super matrices even addition is not always compatible even if the matrices are of same order.
Now we proceed on to define multiplication in case of quasi super matrices.
What ever be the situation we need to have compatability of order while multiplying. Quasi Super Matrices 187
Example 4.23: Let
01221 51131 A = 10100 51011 54 and
1011 0102 B = 1010 . 2101 00115x4 be any two quasi super matrices.
1011 01221 0102 51131 AB = 1010 10100 2101 51011 0011
If the partitions or cell divisions are removed imaginarily and the multiplication takes place we get a 4 × 4 matrix.
4335 12 4 7 11 AB = 2021 7269
188 Neutrosophic Super Matrices and Quasi Super Matrices
The quasi super matrix product assumes an approximate cell division which is not unique for it may not be possible to get a cell division exactly as the very order of it is changed.
We call it as the resultant quasi super matrix. What is more important in this situation is that we can find one or more type of cell division on the product. This is not a problem for the very concept of quasi super matrix was found to apply in fuzzy models.
So to over come all these hurdles we make a mention of the following. As in case of super matrices we first apply the product of a quasi super matrix and its transpose we may recall in case of super matrix we had the product of a super matrix with its transpose gave a nice symmetric super matrix.
We observe that in the case of quasi super matrix A, the transpose AT of A is such that in general the product is not defined. Thus we can define the product only when it is defined.
This is not the case in case of super matrix, for in super matrix we can always define such products but in case of quasi super matrix the product may be defined or not. Only if defined it can be calculated.
This quasi super matrix when its entries are from the fuzzy interval [0,1] we define it to be a fuzzy quasi super matrix or quasi fuzzy super matrix.
All these matrices find their applications when the problem under investigation uses several i.e., one or more fuzzy models simultaneously.
We just illustrate by examples some fuzzy quasi super matrices.
Example 4.24: Let Fs denote the fuzzy quasi super matrix given as
Quasi Super Matrices 189
A1 Fs = A3 A2
0 0.1 0.4 0.5 0.3 0.7 10.11 00.80.5 0.7 0.2 0.5 0.6 1 0.2 = 0.8 0.5 0.6 0.5 0.7 1 , 0.1 0.8 0.6 1 0 0.8 0.8 0.5 0.1 0.9 1 0.2 0.3 0.7 0.5 0.3 0.5 1 where A1 is a 4 × 6 fuzzy rectangular matrix and A2 and A3 are 3 × 3 fuzzy square super matrices.
Example 4.25: Let Ps denote a quasi fuzzy super matrix given by
0.1 1 0.2 0.1 0.9 0.7 0.2 0 0.9 0.1 1 0 0.8 0.6 0.4 0.6 0.7 0.5 0.6 0.8 0.7 0.1 0.5 0.1 0 1 0 0.5 0.4 0.7 0.4 0.3 0.3 1 0.6 0.1 0.5 0 0 0 Ps = ; 0.7 0 0.2 0.4 0.6 0.7 0 0 0.8 1 1 0 1 0 1 1 0.9 0 0.7 0.8 0.9 0.6 0.3 0.2 0.5 0.2 0.6 0.4 0.5 0.1 0.3 0.1 0.6 0.3 0.4 0.3 0.2 0.7 0.1 0 where
AA12 Ps = A ; A 4 3 A5 190 Neutrosophic Super Matrices and Quasi Super Matrices
where A1 and A2 is a 4 × 4 fuzzy matrix. A3 is a 6 × 6 square fuzzy matrix and A4 and A5 are 3 × 2 rectangular fuzzy matrices.
Thus we can have any number of quasi fuzzy super matrices. In case of even quasi fuzzy super matrices we cannot always define the notion of addition or multiplication. Only when special type of compatibility exists we can proceed onto define sum or product or both.
Example 4.26: Let Fs and Ps be two quasi fuzzy super matrices given by
0.3 0.1 0.2 0.7 0.2 0 0.1 1 0.2 0.5 0 0 0.5 1 0 0.3 1 0.1 0.1 0.2 0.3 Fs = 0 0.3 0.8 0.4 1 0.1 0.7 1 0.7 0.3 1 0.1 0.7 1 0.5 0.8 0.9 0 0.3 0.2 0.5
AA12 = AAA345 and
0 0.7 1 0 0.6 1 0.7 0.3 0 0.8 1 0.5 0.3 1 0.1 0.9 0 0 1 0.2 0 Ps = 0.9 0 0.7 0.5 0.1 0.1 1 0.2 0.3 0.5 0.3 0.5 1 0.7 0.4 0.1 0.6 1 0 0 0.5
BB12 = BBB345 Quasi Super Matrices 191
We see both min {Ps, Fs}; Ps + Fs = min {Ps, Fs} where min function is well defined.
For if
12 aaij ij Fs = 345 aaaij ij ij
t where At = ( aij ); t = 1, 2, 3, 4, 5. and 12 bbij ij Ps = 345 bijbb ij ij
p where Bp = ( bij ); p = 1, 2, 3, 4, 5.
11 22 min{aij ,b ij } min{aij ,b ij } min {Fs + Ps} = 33 44 55 min{aij ,b ij } min{aij ,b ij } max{aij ,b ij }
00.10.200.200.1 0.3 0 0.5 0 0 0.3 1 00.30 00.10.20 = 0 0 0.7 0.4 0.1 0.1 0.7 0.2 0.3 0.3 0.3 0.1 0.7 0.7 0.4 0.1 0.6 0 0 0 0.5
Thus only when compatibility exists we may be in a position to define min function.
Now we proceed onto define max function on Fs and Ps. 192 Neutrosophic Super Matrices and Quasi Super Matrices
11 22 max{aij ,b ij } max{aij ,b ij } max {Fs + Ps} = 33 44 55 max{aij ,b ij } max{aij ,b ij } max{aij ,b ij }
0.30.710.70.610.7 1 0.2 0.8 1 0.5 0.5 1 0.1 0.9 1 0.1 1 0.2 0.3 =. 0.9 0.3 0.8 0.5 1 0.1 1 1 0.7 0.5 1 0.5 1 1 0.5 0.8 0.9 1 0.3 0.2 0.5
Now we proceed onto define max min of Fs, Ps.
i.e., max min {Fs, Ps}
max min{A11 ,B } max min{A2 ,B 2 } = max min{A33 ,B } max min{A44 ,B } max min{A55 ,B }
0.1 0.3 0.3 0.2 0.6 0.7 0.7 0.2 0.7 1 0.5 0.5 0.2 1 0.3 0.9 0.3 0.3 0.2 0.2 0.3 max min {Fs, Ps} = 0.4 0.3 0.6 1 0.5 0.4 1 0.9 0.3 0.7 0.3 0.5 0.7 0.7 0.5 0.3 0.6 0.3 0 0.2 0.5
At times we may have only ‘addition’ to be compatible. For instance consider the example.
Example 4.27: Let Fs and Ps be any two quasi fuzzy super matrices given by
Quasi Super Matrices 193
0.3 0.8 1 0.4 1 0 0.9 0 0.4 0.5 0.8 0 0.8 0.4 0.8 1 0 0.6 0.7 1 0.3 0.4 0.3 0.8 0.1 0.5 0.6 0.1 Fs = 0.5 0.8 0.6 1 0 0.8 0.1 0.5 1 0 0.5 0.6 1 0 1 0 0.8 1 0.4 0 0.2 0.4 0.5 1 0.3 1 0.4 0.7 and
0.7 0.3 0.5 0.3 0.5 0.1 0 1 0.8 0.4 0.8 0 0.4 0.9 0.7 0.6 0.3 0.1 0.8 0.1 0.3 0.3 0.8 0.5 0.7 0.9 0.7 0.2 Ps = . 0.1 0.5 0.1 0.3 0.4 0.5 0.3 0.30.20.40.70.50.10.8 0.1 0.8 0.3 0.3 0.7 0.2 0.1 0.8 0.7 0.1 0.1 0.6 0.3 0.5
Let us denote
12 Aa1ij2ij Aa Fs = 34 AaAa3ij4ij and 12 BbBb1ij2ij Ps = 34 BbBb3ij4ij max min {Fs, Ps} is not defined as max min {A1, B1} is not defined min or max is defined by
194 Neutrosophic Super Matrices and Quasi Super Matrices
11 22 max(aij ,b ij ) max(aij ,b ij ) max {Fs + Ps} = 33 44 max(aij ,b ij ) max(aij ,b ij )
0.7 0.8 1 0.4 1 0.1 0.9 1 0.8 0.5 0.8 0 0.8 0.9 0.8 1 0.3 0.6 0.8 1 0.3 0.4 0.8 0.8 0.7 0.9 0.7 0.2 = . 0.5 0.8 0.6 1 0.4 0.8 0.3 0.5 1 0.4 0.7 0.6 1 0.8 1 0.8 0.8 1 0.7 0.2 0.2 0.8 0.7 1 0.3 1 0.4 0.7
Thus we see at times max and min may be defined but max min may not be defined.
Here also entries of all these quasi super matrices can be replaced by the entries from neutrosophic ring, dual number ring, dual neutrosophic number rings and so on.
These new structures find applications in constructing the fuzzy neutrosophic quasi super models.
FURTHER READING
1. Birkhoff. G, On the structure of abstract algebras, Proc. Cambridge Philos. Soc, 31, 433-435, 1995.
2. Horst P., Matrix Algebra for Social Scientists, Holt, Rinehart and Winston Inc, 1963.
3. Smarandache. Florentin, An Introduction to Neutrosophy, http://gallup.unm.edu/~smarandache/ introduction.pdf.
4. Smarandache Florentin (editor) Proceedings of the First International Conference on Neutrosophy, Neutrosophic Probability and Statistics, Univ. of New Mexico, Gallup, 2001.
5. Vasantha Kandasamy, W.B. and Florentin Smarandache, Super Linear Algebra, Infolearnquest, Ann Arbor, 2008.
6. Vasantha Kandasamy, W.B. Florentin Smarandache and K. Ilanthenral, Introduction to Bimatrices, Hexis, 2005.
7. Vasantha Kandasamy and Florentin Smarandache, Neutrosophic rings, Hexis, Arizona, U.S.A., 2006.
196 Neutrosophic Super Matrices and Quasi Super Matrices
8. Vasantha Kandasamy, W.B. and Florentin Smarandache, Natural Product n on matrices, Zip Publishing, Ohio, 2012.
9. Vasantha Kandasamy, W.B., Smarandache Rings, American Research Press, Rehoboth, 2002.
10. Vasantha Kandasamy, W.B. and Florentin Smarandache, Finite Neutrosophic Complex Numbers, Zip Publishing, Ohio, 2011.
11. Vasantha Kandasamy, W.B. and Florentin Smarandache, Dual Numbers, Zip Publishing, Ohio, 2012.
12. Vasantha Kandasamy, W.B. and Florentin Smarandache, Special dual like numbers and lattices, Zip Publishing, Ohio, 2012.
13. Vasantha Kandasamy, W.B. and Florentin Smarandache, Special quasi dual numbers and groupoids, Zip Publishing, Ohio, 2012.
INDEX
A
All partitions of a super matrix, 170-2
B
Bilength of a super row bivector, 88-9 Bimatrices, 7-8 Bisuper matrices, 87-9
D
Dual number neutrosophic ring, 7-8
F
Fuzzy quasi super matrix, 188-9
I
Identical in structure, 95-9, 147 198 Neutrosophic Super Matrices and Quasi Super Matrices
M
Major product of super neutrosophic vectors of type A, 35-8 Matrix order of a neutrosophic super matrix, 16-8 Minor product of super neutrosophic vectors of type A, 32-4 Mixed quasi super matrix, 165
N
Natural order of a super neutrosophic matrix, 16-8 Neutrosophic ring, 7-9 Neutrosophic super square matrix, 12 Neutrosophic super vector of type A, 22-5 Neutrosophic super vector of type B, 24-6
Q
Quasi super matrix, 157-9 Quasi super rectangular matrix, 163-5 Quasi super square matrix, 160-2
R
Rectangular super neutrosophic matrix, 14
S
Similar quasi super matrix, 179-2 Simple neutrosophic matrix, 16-8 Special dual like neutrosophic ring, 7-8 Special mixed neutrosophic dual number rings, 7-8 Special quasi dual number neutrosophic ring, 7-8 Super bicolumn vector of type A, 89-91 Super bicolumn vector of type B, 141-3 Super bicolumn vectors, 129 Super bilength of a super column bivector, 91-3 Super bimatrices, 87-9 Super birow vector of type A, 89-91 Index 199
Super birow vectors, 88-9 Super bivectors, 129 Super column bivector of type A, 89-91 Super column neutrosophic matrix, 10 Super neutrosophic rectangular matrix, 14 Super neutrosophic square matrix, 12 Super row bivector of type B, 139-142 Super row bivectors, 88-9 Super matrices, 7-8 Super row neutrosophic matrix, 9-10 Symmetric neutrosophic super matrix, 53-5 Symmetric simple neutrosophic matrix, 45-8
T
Transpose of neutrosophic super vector of type B, 24-6
ABOUT THE AUTHORS
Dr.W.B.Vasantha Kandasamy is an Associate Professor in the Department of Mathematics, Indian Institute of Technology Madras, Chennai. In the past decade she has guided 13 Ph.D. scholars in the different fields of non-associative algebras, algebraic coding theory, transportation theory, fuzzy groups, and applications of fuzzy theory of the problems faced in chemical industries and cement industries. She has to her credit 646 research papers. She has guided over 68 M.Sc. and M.Tech. projects. She has worked in collaboration projects with the Indian Space Research Organization and with the Tamil Nadu State AIDS Control Society. She is presently working on a research project funded by the Board of Research in Nuclear Sciences, Government of India. This is her 74th book. On India's 60th Independence Day, Dr.Vasantha was conferred the Kalpana Chawla Award for Courage and Daring Enterprise by the State Government of Tamil Nadu in recognition of her sustained fight for social justice in the Indian Institute of Technology (IIT) Madras and for her contribution to mathematics. The award, instituted in the memory of Indian-American astronaut Kalpana Chawla who died aboard Space Shuttle Columbia, carried a cash prize of five lakh rupees (the highest prize-money for any Indian award) and a gold medal. She can be contacted at [email protected] Web Site: http://mat.iitm.ac.in/home/wbv/public_html/ or http://www.vasantha.in
Dr. Florentin Smarandache is a Professor of Mathematics at the University of New Mexico in USA. He published over 75 books and 200 articles and notes in mathematics, physics, philosophy, psychology, rebus, literature. In mathematics his research is in number theory, non-Euclidean geometry, synthetic geometry, algebraic structures, statistics, neutrosophic logic and set (generalizations of fuzzy logic and set respectively), neutrosophic probability (generalization of classical and imprecise probability). Also, small contributions to nuclear and particle physics, information fusion, neutrosophy (a generalization of dialectics), law of sensations and stimuli, etc. He got the 2010 Telesio-Galilei Academy of Science Gold Medal, Adjunct Professor (equivalent to Doctor Honoris Causa) of Beijing Jiaotong University in 2011, and 2011 Romanian Academy Award for Technical Science (the highest in the country). Dr. W. B. Vasantha Kandasamy and Dr. Florentin Smarandache got the 2011 New Mexico Book Award for Algebraic Structures. He can be contacted at [email protected]