Circle Inversions Fun with a Serious Undertone
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Angle Bisection with Straightedge and Compass
ANGLE BISECTION WITH STRAIGHTEDGE AND COMPASS The discussion below is largely based upon material and drawings from the following site : http://strader.cehd.tamu.edu/geometry/bisectangle1.0/bisectangle.html Angle Bisection Problem: To construct the angle bisector of an angle using an unmarked straightedge and collapsible compass . Given an angle to bisect ; for example , take ∠∠∠ ABC. To construct a point X in the interior of the angle such that the ray [BX bisects the angle . In other words , |∠∠∠ ABX| = |∠∠∠ XBC|. Step 1. Draw a circle that is centered at the vertex B of the angle . This circle can have a radius of any length, and it must intersect both sides of the angle . We shall call these intersection points P and Q. This provides a point on each line that is an equal distance from the vertex of the angle . Step 2. Draw two more circles . The first will be centered at P and will pass through Q, while the other will be centered at Q and pass through P. A basic continuity result in geometry implies that the two circles meet in a pair of points , one on each side of the line PQ (see the footnote at the end of this document). Take X to be the intersection point which is not on the same side of PQ as B. Equivalently , choose X so that X and B lie on opposite sides of PQ. Step 3. Draw a line through the vertex B and the constructed point X. We claim that the ray [BX will be the angle bisector . -
Construction Surveying Curves
Construction Surveying Curves Three(3) Continuing Education Hours Course #LS1003 Approved Continuing Education for Licensed Professional Engineers EZ-pdh.com Ezekiel Enterprises, LLC 301 Mission Dr. Unit 571 New Smyrna Beach, FL 32170 800-433-1487 [email protected] Construction Surveying Curves Ezekiel Enterprises, LLC Course Description: The Construction Surveying Curves course satisfies three (3) hours of professional development. The course is designed as a distance learning course focused on the process required for a surveyor to establish curves. Objectives: The primary objective of this course is enable the student to understand practical methods to locate points along curves using variety of methods. Grading: Students must achieve a minimum score of 70% on the online quiz to pass this course. The quiz may be taken as many times as necessary to successful pass and complete the course. Ezekiel Enterprises, LLC Section I. Simple Horizontal Curves CURVE POINTS Simple The simple curve is an arc of a circle. It is the most By studying this course the surveyor learns to locate commonly used. The radius of the circle determines points using angles and distances. In construction the “sharpness” or “flatness” of the curve. The larger surveying, the surveyor must often establish the line of the radius, the “flatter” the curve. a curve for road layout or some other construction. The surveyor can establish curves of short radius, Compound usually less than one tape length, by holding one end Surveyors often have to use a compound curve because of the tape at the center of the circle and swinging the of the terrain. -
And Are Congruent Chords, So the Corresponding Arcs RS and ST Are Congruent
9-3 Arcs and Chords ALGEBRA Find the value of x. 3. SOLUTION: 1. In the same circle or in congruent circles, two minor SOLUTION: arcs are congruent if and only if their corresponding Arc ST is a minor arc, so m(arc ST) is equal to the chords are congruent. Since m(arc AB) = m(arc CD) measure of its related central angle or 93. = 127, arc AB arc CD and . and are congruent chords, so the corresponding arcs RS and ST are congruent. m(arc RS) = m(arc ST) and by substitution, x = 93. ANSWER: 93 ANSWER: 3 In , JK = 10 and . Find each measure. Round to the nearest hundredth. 2. SOLUTION: Since HG = 4 and FG = 4, and are 4. congruent chords and the corresponding arcs HG and FG are congruent. SOLUTION: m(arc HG) = m(arc FG) = x Radius is perpendicular to chord . So, by Arc HG, arc GF, and arc FH are adjacent arcs that Theorem 10.3, bisects arc JKL. Therefore, m(arc form the circle, so the sum of their measures is 360. JL) = m(arc LK). By substitution, m(arc JL) = or 67. ANSWER: 67 ANSWER: 70 eSolutions Manual - Powered by Cognero Page 1 9-3 Arcs and Chords 5. PQ ALGEBRA Find the value of x. SOLUTION: Draw radius and create right triangle PJQ. PM = 6 and since all radii of a circle are congruent, PJ = 6. Since the radius is perpendicular to , bisects by Theorem 10.3. So, JQ = (10) or 5. 7. Use the Pythagorean Theorem to find PQ. -
20. Geometry of the Circle (SC)
20. GEOMETRY OF THE CIRCLE PARTS OF THE CIRCLE Segments When we speak of a circle we may be referring to the plane figure itself or the boundary of the shape, called the circumference. In solving problems involving the circle, we must be familiar with several theorems. In order to understand these theorems, we review the names given to parts of a circle. Diameter and chord The region that is encompassed between an arc and a chord is called a segment. The region between the chord and the minor arc is called the minor segment. The region between the chord and the major arc is called the major segment. If the chord is a diameter, then both segments are equal and are called semi-circles. The straight line joining any two points on the circle is called a chord. Sectors A diameter is a chord that passes through the center of the circle. It is, therefore, the longest possible chord of a circle. In the diagram, O is the center of the circle, AB is a diameter and PQ is also a chord. Arcs The region that is enclosed by any two radii and an arc is called a sector. If the region is bounded by the two radii and a minor arc, then it is called the minor sector. www.faspassmaths.comIf the region is bounded by two radii and the major arc, it is called the major sector. An arc of a circle is the part of the circumference of the circle that is cut off by a chord. -
On the Standard Lengths of Angle Bisectors and the Angle Bisector Theorem
Global Journal of Advanced Research on Classical and Modern Geometries ISSN: 2284-5569, pp.15-27 ON THE STANDARD LENGTHS OF ANGLE BISECTORS AND THE ANGLE BISECTOR THEOREM G.W INDIKA SHAMEERA AMARASINGHE ABSTRACT. In this paper the author unveils several alternative proofs for the standard lengths of Angle Bisectors and Angle Bisector Theorem in any triangle, along with some new useful derivatives of them. 2010 Mathematical Subject Classification: 97G40 Keywords and phrases: Angle Bisector theorem, Parallel lines, Pythagoras Theorem, Similar triangles. 1. INTRODUCTION In this paper the author introduces alternative proofs for the standard length of An- gle Bisectors and the Angle Bisector Theorem in classical Euclidean Plane Geometry, on a concise elementary format while promoting the significance of them by acquainting some prominent generalized side length ratios within any two distinct triangles existed with some certain correlations of their corresponding angles, as new lemmas. Within this paper 8 new alternative proofs are exposed by the author on the angle bisection, 3 new proofs each for the lengths of the Angle Bisectors by various perspectives with also 5 new proofs for the Angle Bisector Theorem. 1.1. The Standard Length of the Angle Bisector Date: 1 February 2012 . 15 G.W Indika Shameera Amarasinghe The length of the angle bisector of a standard triangle such as AD in figure 1.1 is AD2 = AB · AC − BD · DC, or AD2 = bc 1 − (a2/(b + c)2) according to the standard notation of a triangle as it was initially proved by an extension of the angle bisector up to the circumcircle of the triangle. -
Claudius Ptolemy English Version
CLAUDIUS PTOLEMY (about 100 AD – about 170 AD) by HEINZ KLAUS STRICK, Germany The illustrated stamp block from Burundi, issued in 1973 – on the occasion of the 500th anniversary of the birth of NICOLAUS COPERNICUS, shows the portrait of the astronomer, who came from Thorn (Toruń), and a (fanciful) portrait of the scholar CLAUDIUS PTOLEMY, who worked in Alexandria, with representations of the world views associated with the names of the two scientists. The stamp on the left shows the geocentric celestial spheres on which the Moon, Mercury, Venus, Sun, Mars, Jupiter and Saturn move, as well as the sectors of the fixed starry sky assigned to the 12 signs of the zodiac; the illustration on the right shows the heliocentric arrangement of the planets with the Earth in different seasons. There is little certain information about the life of CLAUDIUS PTOLEMY. The first name indicates that he was a Roman citizen; the surname points to Greek and Egyptian roots. The dates of his life are uncertain and there is only certainty in some astronomical observations which he must have made in the period between 127 and 141 AD. Possibly he was taught by THEON OF SMYRNA whose work, most of which has survived, is entitled What is useful in terms of mathematical knowledge for reading PLATO? The most famous work of PTOLEMY is the Almagest, whose dominating influence on astronomical teaching was lost only in the 17th century, although the heliocentric model of COPERNICUS in his book De revolutionibus orbium coelestium was already available in print from 1543. The name of the work, consisting of 13 chapters (books), results from the Arabic translation of the original Greek title: μαθηματική σύνταξις (which translates as: Mathematical Compilation) and later became "Greatest Compilation", in the literal Arabic translation al-majisti. -
From the Theorem of the Broken Chord to the Beginning of the Trigonometry
From the Theorem of the Broken Chord to the Beginning of the Trigonometry MARIA DRAKAKI Advisor Professor:Michael Lambrou Department of Mathematics and Applied Mathematics University of Crete May 2020 1/18 MARIA DRAKAKI From the Theorem of the Broken Chord to the Beginning of the TrigonometryMay 2020 1 / 18 Introduction. Τhe Theorem Some proofs of it Archimedes and Trigonometry The trigonometric significance of the Theorem of the Broken Chord The sine of half of the angle Is Archimedes the founder of Trigonometry? ”Who is the founder of Trigonometry?” an open question Conclusion Contents The Broken Chord Theorem 2/18 MARIA DRAKAKI From the Theorem of the Broken Chord to the Beginning of the TrigonometryMay 2020 2 / 18 Archimedes and Trigonometry The trigonometric significance of the Theorem of the Broken Chord The sine of half of the angle Is Archimedes the founder of Trigonometry? ”Who is the founder of Trigonometry?” an open question Conclusion Contents The Broken Chord Theorem Introduction. Τhe Theorem Some proofs of it 2/18 MARIA DRAKAKI From the Theorem of the Broken Chord to the Beginning of the TrigonometryMay 2020 2 / 18 The trigonometric significance of the Theorem of the Broken Chord The sine of half of the angle Is Archimedes the founder of Trigonometry? ”Who is the founder of Trigonometry?” an open question Conclusion Contents The Broken Chord Theorem Introduction. Τhe Theorem Some proofs of it Archimedes and Trigonometry 2/18 MARIA DRAKAKI From the Theorem of the Broken Chord to the Beginning of the TrigonometryMay 2020 2 / 18 Is Archimedes the founder of Trigonometry? ”Who is the founder of Trigonometry?” an open question Conclusion Contents The Broken Chord Theorem Introduction. -
THE MULTIVARIATE BISECTION ALGORITHM 1. Introduction The
REVISTA DE LA UNION´ MATEMATICA´ ARGENTINA Vol. 60, No. 1, 2019, Pages 79–98 Published online: March 20, 2019 https://doi.org/10.33044/revuma.v60n1a06 THE MULTIVARIATE BISECTION ALGORITHM MANUEL LOPEZ´ GALVAN´ n Abstract. The aim of this paper is to study the bisection method in R . We propose a multivariate bisection method supported by the Poincar´e–Miranda theorem in order to solve non-linear systems of equations. Given an initial cube satisfying the hypothesis of the Poincar´e–Mirandatheorem, the algo- rithm performs congruent refinements through its center by generating a root approximation. Through preconditioning we will prove the local convergence of this new root finder methodology and moreover we will perform a numerical implementation for the two dimensional case. 1. Introduction The problem of finding numerical approximations to the roots of a non-linear system of equations was the subject of various studies, and different methodologies have been proposed between optimization and Newton’s procedures. In [4] D. H. Lehmer proposed a method for solving polynomial equations in the complex plane testing increasingly smaller disks for the presence or absence of roots. In other work, Herbert S. Wilf developed a global root finder of polynomials of one complex variable inside any rectangular region using Sturm sequences [12]. The classical Bolzano’s theorem or Intermediate Value theorem ensures that a continuous function that changes sign in an interval has a root, that is, if f :[a, b] → R is continuous and f(a)f(b) < 0 then there exists c ∈ (a, b) such that f(c) = 0. -
Quadrilateral Types & Their Properties
Quadrilateral Types & Their Properties Quadrilateral Type Shape Properties Square 1. All the sides of the square are of equal measure. 2. The opposite sides are parallel to each other. 3. All the interior angles of a square are at 90 degrees (i.e., right angle). 4. The diagonals of a square are equal and perpendicular to each other. 5. The diagonals bisect each other. 6. The ratio of the area of incircle and circumcircle of a square is 1:2. Rectangle 1. The opposite sides of a rectangle are of equal length. 2. The opposite sides are parallel to each other. 3. All the interior angles of a rectangle are at 90 degrees. 4. The diagonals of a rectangle are equal and bisect each other. 5. The diameter of the circumcircle of a rectangle is equal to the length of its diagonal. Rhombus 1. All the four sides of a rhombus are of the same measure. 2. The opposite sides of the rhombus are parallel to each other. 3. The opposite angles are of the same measure. 4. The sum of any two adjacent angles of a rhombus is equal to 180 degrees. 5. The diagonals perpendicularly bisect each other. 6. The diagonals bisect the internal angles of a rhombus. Parallelogram 1. The opposite sides of a parallelogram are of the same length. 2. The opposite sides are parallel to each other. 3. The diagonals of a parallelogram bisect each other. 4. The opposite angles are of equal measure. 5. The sum of two adjacent angles of a parallelogram is equal to 180 degrees. -
History of Mathematics Log of a Course
History of mathematics Log of a course David Pierce / This work is licensed under the Creative Commons Attribution–Noncommercial–Share-Alike License. To view a copy of this license, visit http://creativecommons.org/licenses/by-nc-sa/3.0/ CC BY: David Pierce $\ C Mathematics Department Middle East Technical University Ankara Turkey http://metu.edu.tr/~dpierce/ [email protected] Contents Prolegomena Whatishere .................................. Apology..................................... Possibilitiesforthefuture . I. Fall semester . Euclid .. Sunday,October ............................ .. Thursday,October ........................... .. Friday,October ............................. .. Saturday,October . .. Tuesday,October ........................... .. Friday,October ............................ .. Thursday,October. .. Saturday,October . .. Wednesday,October. ..Friday,November . ..Friday,November . ..Wednesday,November. ..Friday,November . ..Friday,November . ..Saturday,November. ..Friday,December . ..Tuesday,December . . Apollonius and Archimedes .. Tuesday,December . .. Saturday,December . .. Friday,January ............................. .. Friday,January ............................. Contents II. Spring semester Aboutthecourse ................................ . Al-Khw¯arizm¯ı, Th¯abitibnQurra,OmarKhayyám .. Thursday,February . .. Tuesday,February. .. Thursday,February . .. Tuesday,March ............................. . Cardano .. Thursday,March ............................ .. Excursus................................. -
From Stars to Waves Mathematics
underground From stars to waves mathematics The trigonometric functions sine and cosine seem to have split personalities. We know them as prime examples of periodic functions, since sin(푥) = sin(푥 + 360∘) and cos(푥) = cos(푥 + 360∘) for all 푥. With their beautifully undulating shapes they also give us the most perfect mathematical description of waves. The periodic behaviour is illustrated in these images. 푦 = sin 푥 푦 = cos 푥 When we first learn about sine and cosine though, it’s in the context of right-angled triangles. Page 1 of 7 Copyright © University of Cambridge. All rights reserved. Last updated 12-Dec-16 https://undergroundmathematics.org/trigonometry-triangles-to-functions/from-stars-to-waves How do the two representations of these two functions fit together? Imagine looking up at the night sky and try to visualise the stars and planets all lying on a sphere that curves around us, with the Earth at its centre. This is called a celestial sphere. Around 2000 years ago, when early astronomers were trying to chart the night sky, doing astronomy meant doing geometry involving spheres—and that meant being able to do geometry involving circles. Looking at two stars on the celestial sphere, we can ask how far apart they are. We can formulate this as a problem about points on a circle. Given two points 퐴 and 퐵 on a cirle, what is the shortest distance between them, measured along the straight line that lies inside the circle? Such a straight line is called a chord of the circle. Page 2 of 7 Copyright © University of Cambridge. -
Lesson 2: Circles, Chords, Diameters, and Their Relationships
NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 2 M5 GEOMETRY Lesson 2: Circles, Chords, Diameters, and Their Relationships Student Outcomes . Identify the relationships between the diameters of a circle and other chords of the circle. Lesson Notes Students are asked to construct the perpendicular bisector of a line segment and draw conclusions about points on that bisector and the endpoints of the segment. They relate the construction to the theorem stating that any perpendicular bisector of a chord must pass through the center of the circle. Classwork Opening Exercise (4 minutes) Scaffolding: Post a diagram and display the steps to create a Opening Exercise perpendicular bisector used in Construct the perpendicular bisector of line segment below (as you did in Module 1). Lesson 4 of Module 1. ���� Label the endpoints of the segment and . Draw circle with center and radius . Draw another line that bisects but is not perpendicular to it. Draw circle with center ���� and radius . List one similarity and one difference���� between the two bisectors. . Label the points of Answers will vary. All points on the perpendicular bisector are equidistant from points and 46T . ���� Points on the other bisector are not equidistant from points A and B. The perpendicular bisector intersection as and . meets at right angles. The other bisector meets at angles that are not congruent. Draw . ���� ⃖����⃗ You may wish to recall for students the definition of equidistant: EQUIDISTANT:. A point is said to be equidistant from two different points and if = . Points and can be replaced in the definition above with other figures (lines, etc.) as long as the distance to those figures is given meaning first.