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Changing Frequencies

Evolution

is defined as a change in the inherited characteristics of biological over successive generations. • Microevolution involves the change in allele frequencies that occur over time within a . ( is evolution on a scale of separated pools – larger evolutionary changes above the level of “”) • This change is due to four different processes: , selection (natural and artificial), , and . 2 Determining

• Examine the frog population presented here. • Their color is determined by a single gene, which has two and phenotypically exhibits incomplete . • CGCG is green, CG CR is blue, and CR CR is red • Calculate the allele frequency of the in the diagram.

3 Determining Allele Frequency • These frogs are diploid, thus have two copies of their for color. Allele: CG CR Green (11) 22 0 Blue (2) 2 2 Red (3) 0 6 Total: 24 8 Frequency: p = 24 ÷ 32 q = 8 ÷ 32 p = ¾ = 0.75 q = ¼ = 0.25 • If allelic frequencies change, then evolution is occurring. • Let’s suppose 4 green frogs enter the population (immigration). How do the frequencies change? 4 Immigration: Determining Allele Frequency

Recall that currently: CG = 0.75 & CR = 0.25

Allele: CG CR Green (15) 30 0 Blue (2) 2 2 Red (3) 0 6 Total: 32 8 Frequency: p = 32 ÷ 40 q = 8 ÷ 40 p = 8/10 = 0.80 q = 2/10 = 0.20

5 Determining Allele Frequency

How do the allelic frequencies change if 4 green frogs leave the population instead of enter the population? (emigration)

6 Emigration: Determining Allele Frequency

Recall that originally: CG = 0.75 & CR = 0.25

Allele: CG CR Green (7) 14 0 Blue (2) 2 2 Red (3) 0 6 Total: 16 8 Frequency: p = 16 ÷ 24 q = 8 ÷ 24 p = 2/3 = 0.67 q = 1/3 = 0.33

7 Impact On Small vs. Large Population

Before 4 frogs joined After 4 frogs joined

Compare the effect on the small population to 4 frogs joining a much larger population.

8 Impact Large Population

Before 4 frogs joined After 4 green frogs joined larger population larger population

Allele: G R C C Allele: CG CR Green (22) 44 0 Green (26) 52 0 Blue (4) 4 4 Blue (4) 4 4 Red (6) 0 12 Red (6) 0 12 Total: 48 16 Total: 56 16 Frequency: p = 48 ÷ 64 q = 16 ÷ 64 Frequency: p = 5 ÷ 72 q = 16 ÷ 72 p = 3/4 q = 1/4 p = 56/72 q = 16/72 = 0.75 = 0.25 = 0.78 = 0.22

9 Impact Small Population

Before 4 frogs joined After 4 green frogs joined

Allele: CG CR Allele: CG CR Green (11) 22 0 Green (15) 30 0 Blue (2) 2 2 Blue (2) 2 2 Red (3) 0 6 Red (3) 0 6 Total: 24 8 Total: 32 8 Frequency: p = 24 ÷ 32 q = 8 ÷ 32 Frequency: p = 32 ÷ 40 q = 8 ÷ 40 p = ¾ = 0.75 q = ¼ = 0.25 p = 8/10 = 0.80 q = 2/10 = 0.20

In both cases the allele frequency for CG increases but it has a bigger impact on the smaller population.

10 Hardy-Weinberg Equilibrium

So, when is there no change in the allele frequency? When the population is said to be in Hardy-Weinberg Equilibrium, thus no evolution is occurring. FIVE Conditions of Hardy-Weinberg Equilibrium: 1. Population must be large so chance is not a factor. (No genetic drift). 2. Population must be isolated to prevent gene flow. (No immigration or emigration) 3. No occur. 4. Mating is completely random with respect to time and space. 5. Every offspring has an equal chance of survival without regard to . (No )

11 Hardy-Weinberg Equilibrium

• Condition #1 can be met. It is important to have large populations in order that the loss or addition of genes is not a factor. By contrast, small populations experience genetic drift. Additionally, if a small population moves to another area or becomes isolated, the gene pool will be different from the original gene pool. And the founder effect comes into play. • Condition #2 can only be met if the population is isolated. If individuals immigrate or emigrate from the population, the allele frequencies change and evolution occurs. • Condition #3 cannot ever be met since mutations always occur. Thus mutational equilibrium can never be met. • Condition #4 can never be met. Mating is never random. from an apple tree in Ohio is more likely to pollinate a tree in Ohio than one in Washington state.

• Condition #5 can never be met. There will always be variation. Variation can help survive longer and/or reproduce more effectively.

• Since 3 out of the 5 H-W conditions can never be met, evolution DOES occur and allele frequencies do indeed change.

12 Applying the H-W Model

Here we go with our frogs again! Let’s suppose that in a population of 100 frogs, 36 were green (CGCG), 48 were blue (CGCR) and 16 were red (CRCR) and there was total random mating. Allele: CG CR

Green (36) 72 0

Blue (48) 48 48

Red (16) 0 32

Total: 120 80

Frequency: p = 120 ÷ 200 q = 80 ÷ 200 p = 3/5 = 0.60 q = 2/5 = 0.40 Thus, it can be assumed that 60% of all the gametes (eggs and sperm) should carry the CG allele and 40% of the gametes should carry the CR allele.

13 Applying the H-W Model

CG 0.60 CR 0.40 CG 0.60 CGCG CGCR 0.36 0.24 CR 0.40 CGCR CRCR 0.24 0.16 A population is shown above. It indicates that the next generation should have the following offspring distribution: 36% green (CGCG), 48% blue(CGCR), 16% red (CRCR). When the second generation gets ready to reproduce, the results will be the same as before. Allele: CG CR Green (36) 72 0 Blue (48) 48 48 Red (16) 0 32 Total: 120 80 Frequency: p = 120 ÷ 200 q = 80 ÷ 200 p = 3/5 = 0.60 q = 2/5 = 0.40

14 Applying the H-W Model

So, the allele frequency remains at 0.40 CG and 0.60 CR thus no evolution is taking place. Let’s suppose that there is an environmental change that makes red frogs more obvious to predators. How is the population affected and now the population consists of 36 green, 48 blue, and 6 red frogs? Allele: CG CR Green (36) 72 0 Blue (48) 48 48 Red (6) 0 12 Total: 120 60 Frequency: p = 120 ÷ 180 q = 60 ÷ 180 p = 2/3 = 0.66 q = 1/3 = 0.33 Now, allele frequencies are changing and there is an advantage to being green or blue but NOT red. Evolution is indeed occurring. 15 Deriving the H-W Model

CG 0.60 CR 0.40 CG 0.60 CGCG CGCR 0.36 0.24 CR 0.40 CGCR CRCR 0.24 0.16 Examine this Punnett square again. If p represents the allele frequency of CG (dominant) and q represents the allele frequency of CR (recessive) then two equations for a population in Hardy-Weinberg equilibrium can be derived where the following are represented by: CGCG = p2 CRCR = q2 CGCR = 2pq Mathematically then p + q = 0.60 + 0.40 = 1 (1st H-W equation) So, the Punnett square effectively crossed (p + q )  (p + q ) which gives p2 + 2pq + q2 = 1 (2nd H-W equation)

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