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Geometrical Optics Lenses Principal Rays Gaussian Lens Formula: 1 1 1   So Si F F I Optical Image Object Axis Fo

Geometrical Optics Lenses Principal Rays Gaussian Lens Formula: 1 1 1   So Si F F I Optical Image Object Axis Fo

Phys 322 Lecture 13 Chapter 5

Geometrical Principal rays Gaussian formula: 1 1 1   so si f F i Optical Object axis Fo

Principal rays:

1) Rays parallel to principal axis pass through focal point Fi. 2) Rays through center of lens are not refracted.

3) Rays through Fo emerge parallel to principal axis. In this case image is real, inverted and enlarged Assumptions: Since n is function of , in reality each has different focal point: • monochromatic . Contrast to • . : angle of incidence/reflection • rays are all “near” the principal axis not a function of  (paraxial). Converging lens: examples

This could be used in a . Big object on small film

so > 2F

This could be used as a . Small slide(object) on big F < so < 2F screen (image)

This is a 0 < si < F Lens magnification

so y Fi Image o optical axis Object f Fo yi 1 1 1 si   so si f

Green and blue triangles are similar: equation:

yi si MT    yo so

Example: f=10 cm, so=15 cm T = transverse 1 1 1   30cm si = 30 cm MT    2 15cm si 10cm 15cm Thin lens equations s 1 1 1 M   i   T s s s f o o i f= 100 mm

Real image formed formed by single lens is always inverted Longitudinal magnification 1 1 1   so si f

The 3D image of the horse is distorted: • transverse magnification changes along optical axis • longitudinal magnification is not linear Longitudinal magnification: 2 : a horse looking dxi f 2 M L     M towards the lens forms an image dx x2 T o o that looks away from the lens

dx d x x f 2 2 i 2 2 2 o i  xi  f / xo  f / xo  f / xo  dxo dxo Thin lens combinations In most of applications several lenses are used Example: multiple lenses

Image from lens 1 becomes object for lens 2

1 2

Fi1 Fi2

Lens 1 creates a real, inverted and enlarged image of the object. Lens 2 creates a real, inverted and reduced image of the image from lens 1. The combination gives a real, upright, enlarged image of the object. Example: multiple lenses

so1 = 15 cm 1 2

Fi1 Fi2 f1 = 10 cm f2 = 5 cm si1 = 30 cm First find image from lens 1.

1 1 1   si1 = 30 cm 15cm si1 10cm Example: multiple lenses

so1 = 15 cm 1 2 d = 42 cm si2 = 8.6 cm

Fi1 Fi2 f1 = 10 cm f2 = 5 cm s = 30 cm i1 so2 =12 cm Now find image from lens 2.

1 1 1   si2 = 8.6 cm 12cm si2 5cm Example: multiple lenses, magnification

so1 = 15 cm 1 2 d = 42 cm si2 = 8.6 cm

Fi1 Fi2 f1 = 10 cm s f2 = 5 cm M   i s = 30 cm T i1 so2=12 cm so 30cm Lens 1: M    2 Total magnification: T1 15cm M  M M  1.44 8.6cm T T1 T 2 Lens 2: MT 2    .72 12cm +: image is not inverted Two lens equation

so1 1 d 2 si2

Fi1 Fi2 f1 f2 s i1 so2 f d  f s f /s  f  For combination of two thin lenses: s  2 2 o1 1 o1 1 i2  d  f2  so1 f1 / so1  f1

f2 d  f1 distance from the last Back (so1=): b.f.l.  surface to the second d  f1  f2 focal plane f d  f Front focal length (s =): f.f.l.  1 2 distance from the first i2 d  f  f surface to the first 1 2 focal plane Multiple lenses: effective focal length

f2 d  f1  f1d  f2  b.f.l.  f.f.l.   d  f1  f2 d  f1  f2

If d  0 (lenses pushed close together), the effective focal length is: 1 1 1 1     ... If d  0 f f1 f2 f3 Stops and

Field stop - an element limiting the size, or angular breadth of the image (for example film edge in camera)

Aperture stop - an element that determines the amount of light reaching the image

Field stop determines the Apperture determines amount of light only Entrance and exit

Entrance : the image of the stop as seen from an axial point on the object through the elements preceding the stop : the image of the aperture stop as seen from an axial point on the image plane through the elements preceding the image no lenses between image and A.S. - exit pupil coincides with it. Chief and marginal rays

Marginal : the ray that comes from point on object and marginally passes the aperture stop

Chief ray: any ray from an object point that passes through the middle of the aperture stop It is effectively the central ray of the bundle emerging from a point on an object that can get through the aperture. Importance: aberations in optical systems

The cone of rays that reaches image plane frome the top of the object is smaller than that from the middle. There will be less light on the periphery of the image - a process called vignetting Example: of the can be as big as 8 mm. are designed to have exit pupil of 8 mm for maximum brightness of the image Collection Efficiency

Which lens collects more light?

f = 10 mm

f = 10 mm Relative aperture

Entrance pupil area determines the amount of light energy that reaches the image plane. Typically pupil is circular: the area varies as square of its diamater D. The image area varies as square of dimensions and is ~f2.

Flux density varies as (D/f)2. (D/f)  relative apperture f-number Example: f=50 mm, D = 25 mm: f/# = 2 f f /#  denoted as f/2 D F-number

The F-number, “f / #”, of a lens is the ratio of its focal length and its diameter. f / # = f / d f f

d1 f f d2

f / 1 f / 2 The F/#

f f /#  D

•referred to as the “f-number” or speed • time is proportional to the square of the f-number •measure of the collection efficiency of a system •smaller f/# implies higher collected flux: • f or D decreases the flux area • f or  D increases the flux area f-number of a

Change in neighbouring numbers is 2 Intensity is ~1/(f/#)2: changing diafragm from one label to another changes light intensity on film 2 times

Another measure of a lens size is the numerical aperture. It’s the product of the medium and the marginal ray angle.

NA = n sin() Why this definition? Because the  magnification can be shown to f be the ratio of the NA on the two sides of the lens.

High-numerical-aperture lenses are bigger. Numerical Aperture 

NA  nsin

•describes light gathering capability for: lenses  objectives (where n may not be 1) optical fibers …

 NA   photons gathered

Only one plane is imaged (i.e., is in ) at a time. But we’d like objects near this plane to at least be almost in focus. The range of distances in acceptable focus is called the depth of field.

It depends on how much of the lens is used, that is, the aperture.

Object Out-of-focus Size of blur in plane out-of-focus Image f plane

Focal Aperture plane

The smaller the aperture, the more the depth of field. Depth of field example A large depth of field isn’t always desirable.

f/32 (very small aperture; large depth of field)

f/5 (relatively large aperture; small depth of field)

A small depth of field is also desirable for portraits. Phys 322 Mirrors Lecture 13

Ancient bronze

Liquid mercury mirror

Hubble mirror Planar mirror also called plane, or flat mirrors

s = -s i r i o

Sign convention: s on the object side is positive, and negative on the opposite side Planar mirror

For a plane mirror, a point source and its image are at the same distance from the mirror on opposite sides; both lie on the same normal line.

Image is virtual, up-right, and life-size (MT = +1)

yi si The equation for lens works: MT    yo so