Poincar´e Duality Section 3.3 239
The Duality Theorem
The form of Poincar´e duality we will prove asserts that for an R orientable closed k → n manifold, a certain naturally defined map H (M; R) Hn−k(M; R) is an isomor- phism. The definition of this map will be in terms of a more general construction called cap product, which has close connections with cup product.
Cap Product
Let us see how cup product leads naturally to cap product. For an arbitrary space X and coefficient ring R let us for simplicity write Ck(X; R) as Ck and its k = k ∈ k ∈ ` dual C (X; R) HomR(Ck,R) as C . For cochains ϕ C and ψ C we have their + cup product ϕ ` ψ ∈ Ck ` . When we regard ϕ ` ψ as a function of ψ for fixed ϕ, + + we get a map C`→Ck ` , ψ , ϕ ` ψ. One might ask whether this map C`→Ck ` is → the dual of a map Ck+` C` . The answer turns out to be yes, and this map on chains will be the cap product map α , α a ϕ. In order to define α a ϕ it suffices by linearity to take α to be a singular simplex + σ : ∆k `→X , and then the formula for σ a ϕ is rather like the formula defining cup product: a = | ··· | ··· σ ϕ ϕ σ [v0, ,vk] σ [vk, ,vk+`]
To say that for fixed ϕ the map α , α a ϕ has as its dual the map ψ , ϕ ` ψ is ------a→ϕ -----→ψ ` to say that the composition Ck+` C ` R is the map α , (ϕ ψ)(α),orin other words,
(∗)ψ(αaϕ) = (ϕ ` ψ)(α)
+ This holds since for σ : ∆k `→X we have | | ψ(σ a ϕ) = ψ ϕ σ|[v , ···,v ] σ|[v , ···,v + ] 0 k k k ` = | ··· | ··· = ` ϕ σ [v0, ,vk] ψ σ [vk, ,vk+`] (ϕ ψ)(σ )
Another way to write the formula (∗) that may be more suggestive is in the form
hα a ϕ, ψi=hα, ϕ ` ψi
h− −i × i→ where , is the map Ci C R evaluating a cochain on a chain. × k→ a In order to show that the cap product Ck+` C C` , (α, ϕ) , α ϕ, induces a × k → corresponding cap product Hk+`(X; R) H (X; R) H`(X; R) we need a formula for ∂(α a ϕ). This could be derived by a direct calculation similar to the one for cup 240 Chapter 3 Cohomology products, but it is easier to use the duality relation hα a ϕ, ψi=hα, ϕ ` ψi to reduce to the cup product formula. We have h∂(α a ϕ), ψi=hαaϕ, δψi=hα, ϕ ` δψi = (−1)k hα, δ(ϕ ` ψ)i−hα, δϕ ` ψi = (−1)k h∂α,ϕ ` ψi−hα, δϕ ` ψi = (−1)k h∂α a ϕ, ψi−hαaδϕ, ψi ∈ ` Since this holds for all ψ C and C` is a free R module, we must have ∂(α a ϕ) = (−1)k(∂α a ϕ − α a δϕ)
From this it follows that the cap product of a cycle α and a cocycle ϕ is a cycle. Further, if ∂α = 0 then ∂(α a ϕ) =(α a δϕ), so the cap product of a cycle and a coboundary is a boundary. And if δϕ = 0 then ∂(α a ϕ) =(∂α a ϕ), so the cap product of a boundary and a cocycle is a boundary. These facts imply that there is an induced cap product a × k ------→ Hk+`(X; R) H (X; R) H ` (X; R) This is R linear in each variable. ` `→ k+` a → We have seen that the map ϕ : C C is dual to ϕ : Ck+` C` , but when we pass to homology and cohomology this may no longer be true since cohomology is not always just the dual of homology. What we have instead is a slightly weaker relation h between cap and cup product in the form H`(XR) → Hom ( H(XR)R)