Transformation of Some Lambert Series and Cotangent Sums
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mathematics Article Transformation of Some Lambert Series and Cotangent Sums Namhoon Kim Department of Mathematics Education, Hongik University, 94 Wausan-ro, Mapo-gu, Seoul 04066, Korea; [email protected] Received: 29 July 2019; Accepted: 8 September 2019; Published: 11 September 2019 Abstract: By considering a contour integral of a cotangent sum, we give a simple derivation of a ¥ 2pint transformation formula of the series A(t, s) = ∑n=1 ss−1(n)e for complex s under the action of the modular group on t in the upper half plane. Some special cases directly give expressions of generalized Dedekind sums as cotangent sums. Keywords: Lambert series; cotangent sum; modular transformation; Dedekind sum MSC: 11F99; 11F20 1. Introduction s For s 2 C, let ss(n) = ∑djn d be the sum of positive divisors function. For t in the upper half plane H, consider ¥ ¥ e2pint A( s) = (n)e2pint = ns−1 t, ∑ ss−1 ∑ 2pint . (1) n=1 n=1 1 − e A(t, s) is an entire function of s for every t 2 H and a Lambert series in q = e2pit for every s 2 C. The study of transformation of A(t, s) under the action of the modular group at + b t 7! a b 2 SL(2, Z) (2) ct + d c d has been a classical subject. Since A(t, s) is manifestly invariant under translation t 7! t + b for b 2 Z, one only needs to consider transformations (2) with c > 0. The main result of this article is the H a b following transformation formula of A(t, s). For t 2 , s 2 C and c d 2 SL(2, Z) with c > 0, at + b 1 (ct + d)−s A , s = A(t, s) + 1 − (ct + d)−s z(1 − s) ct + d 2 ! (3) cs−1 sec ps Z c−1 p jd iz j + 2 (−z)s−1 c + p i ct + d z − p p − z s/2 ∑ cot cot d 8(ct + d) C j=0 c ct + d c where C is the Hankel contour that encloses the nonnegative real axis in the clockwise direction but not any other poles of the integrand (see Definition1 and Theorem1). Many previously known transformation formulas can be derived as special cases of (3) by considering some particular values of s (see Corollary1). When s is an even positive integer, A(t, s) appears in the Fourier series of the holomorphic Eisenstein series of weight s and satisfies a simple transformation law [1,2] (Corollary1 (i) and (ii)). The case s = 0 is closely related to the Dedekind eta-function ¥ h(t) = epit/12 ∏ 1 − e2pint (t 2 H) n=1 Mathematics 2019, 7, 840; doi:10.3390/math7090840 www.mdpi.com/journal/mathematics Mathematics 2019, 7, 840 2 of 10 as a branch of log h on H is given by pit log h(t) = − A(t, 0). (4) 12 We can thus derive the transformation law of log h(t) by setting s = 0 in (3) (Corollary1 (iii)). Among many other proofs of the eta-transformation formula, we mention the work of Siegel [3], who gave a 1 simple proof of it under t 7! − t by considering a certain contour integral of a product of cotangent functions. This method was generalized by Rademacher to the full modular group in [4]. The transformation property of A(t, 0) also has many applications; for example, it is used in Rademacher’s derivation of an analytic formula of the partition function [5], which improved the result of Hardy and Ramanujan [6]. The formula also brings out the notion of the Dedekind sum, which has interesting arithmetic properties [7]. In Corollary1 (iii), we obtain the cotangent sum representation of the Dedekind sum directly from (3). The transformation formula of A(t, s) when s is an even negative integer, which led to the idea of generalized Dedekind sums, was found by Apostol [8]. A computational error in [8] was corrected by Mikolás [9] and Iseki [10]. We obtain this formula in Corollary1 (iv), also with cotangent sum expressions for the generalized Dedekind sums. The general transformation property of A(t, s) for complex s was first studied by Lewittes [11] in connection with certain generalized Eisenstein series. Berndt derived a transformation formula involving an integral expression in [12], which is further generalized in [13]. We note that the formula (3) involves an integral expression different from the formula in [12]. Studying the behavior of an integral of a more general cotangent sum may be an interesting topic for further investigation. Throughout this work, logarithms and powers are taken with the principal argument. 2. Transformation Formula p Definition 1. Let c, d 2 Z with (c, d) = 1 and c > 0. For t 2 H and s 2 C, we denote r = ct + d and define ! cs−1 Z c−1 jd iz j ( ) = (− )s−1 + − − Ic,d t, s s z c ∑ cot p irz cot p dz (5) 8r C j=0 c r c where C is the Hankel contour that encloses the nonnegative real axis [0, ¥) in the clockwise direction excluding any other poles of the integrand. Consider the integrand in (5). Since e2piz cot pz = −i 1 + 2 , (6) 1 − e2piz cot pz ! −i exponentially as Im z ! ¥. Since both ir and i/r are in the upper half plane, the integrand in (5) decays exponentially as Re z ! ¥ and thus (5) is an entire function in s. We also note that for s 2 Z, the integral (5) along C reduces to the integral around the origin, and Ic,d(t, s) = 0 whenever s is an odd integer as the integrand becomes even. We write the following standard argument as a lemma. Lemma 1. For Re s < 0, ! pics−1 c−1 jd iz j I (t, s) = Res (−z)s−1 cot p irz − cot p − (7) c,d 4rs ∑ ∑ c r c z2Cn[0,¥) j=0 where the sum denotes the sum of all residues in Cn[0, ¥). Mathematics 2019, 7, 840 3 of 10 Proof. Let KN = CN + SN be the keyhole contour in Cn[0, ¥), where CN is the part of C in Definition1 in the region jzj ≤ N, and SN traverses along the circle jzj = N. We can choose a sequence N ! ¥ such that each KN stays well away from the poles of the integrand of (5). The integral over CN is 2pi times the sum of the residues inside KN minus the integral along SN. The lemma follows since the integral along SN vanishes as N ! ¥ for Re s < 0. Under this − assumption, the sum of the residues in Cn[0, ¥) is absolutely convergent, and the term (−z)s 1c of the integrand can be ignored as it is holomorphic in the slit plane. We now restate and prove (3) using the notation introduced above. H a b Theorem 1. For t 2 and s 2 C, let A(t, s) be the series given by (1). For g = c d 2 SL(2, Z) with c > 0, we have 1 ps (ct + d)−s A (gt, s) = A(t, s) + 1 − (ct + d)−s z(1 − s) + sec I (t, s) (8) 2 2 c,d at+b where gt = ct+d , Ic,d(t, s) is given by (5) and z(s) is the Riemann zeta-function. Proof. Since both sides of (8) are entire in s, it suffices to prove the equality for Re s < 0. We use Lemma1 to compute Ic,d(t, s). For each 0 ≤ j < c, the factor cot p(irz − jd/c) of (7) has poles at z = (k + jd/c)/(ir) for k 2 Z with residue 1/(pir). Hence the contribution to Ic,d(t, s) from the residues of (7) at these poles, excluding z = 0, is given by s−1 s−1 ic 0 1 jd 1 jd 1 j − k + cot p k + − (9) 4rs ∑ ir c ir c r2 c k2Z, 0≤j<c where the prime in the sum indicates that the term with (k, j) = (0, 0) is omitted. Since (c, d) = 1, every integer can be uniquely written in the form kc + jd for k 2 Z and 0 ≤ j < c. Let −n = kc + jd. Since ad ≡ 1 mod c, we have na ≡ −j mod c, and (9) equals − ics−1 1 n s 1 n na − + s ∑ cot p 2 . (10) 4r n6=0 ir irc r c c We now use the fact that cot z is odd. For n positive, s−1 s−1 s−1 s−1 1 n 1 n n − pis pis −s ps n −s − − = e 2 + e 2 r = 2 cos r , ir irc ir irc c 2 c and by (6), (10) becomes 0 1 2pi − n + na 1 ps e r2c c B ( − ) + s−1 C 2s cos Bz 1 s 2 ∑ n C . (11) 2r 2 @ n>0 2pi − n + na A 1 − e r2c c Furthermore, since n na n(at + ad−1 ) at + b − + = c = n , r2c c ct + d ct + d the sum in (11) is in fact 2pin at+b e ct+d at + b ns−1 = A , s . ∑ 2pin at+b + n>0 1 − e ct+d ct d Mathematics 2019, 7, 840 4 of 10 We now treat the other poles in a similar fashion. For 0 ≤ j < c, the factor cot p(iz/r − j/c) of (7) has poles at z = (k + j/c)(r/i) for k 2 Z with residue r/(pi).