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Psw Primality Test? ARE THERE COUNTER-EXAMPLES TO THE BAILLIE { PSW PRIMALITY TEST? Carl Pomerance 1984 to Arjen K. Lenstra on the defense of his doctoral thesis In [2] the following procedure is suggested for deciding whether a positive integer n is prime or composite: (1) Perform a base 2 strong pseudoprime test on n. If this test fails, declare n composite and halt. If this test succeeds, n is probably prime. Go on to step (2). (2) In the sequence 5; −7; 9; −11; 13; : : : find the first number D for which (D=n) = −1. Then perform a Lucas pseudoprime test with discriminant D on n (a specific one of these tests as described in [2]). If this test fails, declare n composite. If this test succeeds, n is \very probably" prime. Although it first appeared in [2], the idea of trying such a combined test origi- nated with Baillie. In an exhaustive search up to 25 · 109 in [2], no composite number was found that passed both (1) and (2). In fact, if (1) is weakened to just an ordinary base 2 pseudoprime test, every composite n ≤ 25 · 109 fails either (1) or (2). The authors of [2] have offered a prize of $30 (U.S.) for a composite number n (with its prime factorization) that passes (1) and (2) or a proof that no such n exists. Since the publication of [2], the second author has increased his $10 share of the prize money ten-fold, so now the award stands at $120. (The cheap first and third authors have not increased their shares as yet, although the third author has contemplated offering a \bit" more.) In the interests of helping Arjen start his post-doctoral career on a sound financial footing, I will give here some hint on how a counter-example to this Baillie-PSW \primality test" may be constructed. In fact, I will give a heuristic argument that will show that the number of counter-examples up to x is x1− for any > 0. This argument is based on one by Erdos [1] that suggested there are many Carmichael numbers. Let k > 4 be arbitrary but fixed and let T be large. Let Pk(T ) denote the set of primes p in the interval [T; T k] such that (a) p ≡ 3 mod 8, (5=p) = −1, (b) (p − 1)=2 is square free and composed solely of primes q < T with q ≡ 1 mod 4, (c) (p + 1)=4 is square free and composed solely of primes q < T with q ≡ 3 mod 4. Of course, 1=8 of all primes (asymptotically) in [T; T k] satisfy condition (a), and it can be shown that the conditions that (p − 1)=2 and (p + 1)=4 also be square free Typeset by AMS-TEX 1 2 CARL POMERANCE still leaves a positive fraction of all primes in [T; T k]. Heuristically, the conditions that p − 1 and p + 1 are composed solely of primes below T , allow us to keep still a positive proportion of all primes in [T; T k] (using k fixed). Finally, the event that every prime in (p − 1)=2 is 1 mod 4 should occur with probability c(log T )−1=2 and similarly for the event that every prime in (p+1)=4 is 3 mod 4. Thus the cardinality of Pk(T ) should be asymptotically as T ! 1 cT k log2 T where c is positive constant that depends on the choice of k. We now form square free numbers n composed of ` primes of Pk(T ), where ` is odd and just below T 2= log(T k). The number of choices for n is thus about k 2 [cT = log T ] 2 − > eT (1 3=k) ` 2 for large T (and k fixed). Also, each such n is less than eT . Let Q1 denote the product of the primes q < T with q ≡ 1 mod 4 and let Q3 denote the product of the primes q < T with q ≡ 3 mod 4. Then (Q1; Q3) = 1 and T Q1Q3 ≈ e . Thus the number of choices for n formed that in addition satisfy n ≡ 1 mod Q1; n ≡ −1 mod Q3 should, heuristically, be at least 2 − 2 − eT (1 3=k)=e2T > eT (1 4=k) for large T . But any such n is a counter-example to the Baillie-PSW primality test. Indeed, n will be a Carmichael number so it will automatically be a base 2 pseudoprime. Since n ≡ 3 mod 8 and each pjn is also ≡ 3 mod 8, it is easy to see that n will also be a strong base 2 pseudoprime. Since (5=n) = −1, since every prime pjn satisfies (5=p) = −1, and since p + 1jn + 1 for every prime pjn, it follows that n is a Lucas pseudoprime for any Lucas test with discriminant 5. 2 We thus see that for any fixed k and all large T , there should be at least eT (1−4=k) 2 2 counter-examples to Baillie-PSW below eT . That is, if we let x = eT , then there are at least x1−4=k counter-examples below x, so long as x is large. Since k is arbitrary, our argument implies that the number of counter-examples below x is x1− for any > 0. Remark. Both in the APR primality test and in the Cohen-Lenstra variation there is a part where many kinds of pseudo-primality tests are performed followed by a step where a limited amount of trial division is performed. No one has ever encountered an example of a number where the trial division was really needed { that is, every number that has made it through the pseudo-primality tests actually was prime. Perhaps an argument similar to the one here can show that in fact there are composite numbers that pass all the pseudo-primality tests and for which the trial division step is really needed to distinguish them from the primes. ARE THERE COUNTER-EXAMPLES TO THE BAILLIE { PSW PRIMALITY TEST? 3 References 1. P. Erdos, On pseudoprimes and Carmichael numbers, Publ. Math. Debrecen 4 (1956), 201{ 206. 2. C. Pomerance, J.L. Selfridge, and S.S. Wagstaff, Jr., The pseudoprimes to 25 · 109, Math. Comp. 35 (1980), 1003{1026. Department of Mathematics, University of Georgia, Athens, GA 30602 U.S.A..
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