Topology from order Order from topology Interval topology Applications
Order and Topology
Andrew Craig
BOATS Meeting Birmingham 20 April 2010
Andrew Craig Order and Topology Topology from order Order from topology Interval topology Applications
Ordered sets
A partially ordered set (X , 6) is a set X with a relation 6 satisfying (P1) x 6 x (reexivity) (P2) x 6 y, y 6 z =⇒ x 6 z (transitivity) (P3) x 6 y, y 6 x =⇒ x = y (anti-symmetry) Also called ordered sets or posets. Pre-orders require only (P1) and (P2). Examples (℘(X ), ⊆)
(R, 6) (a linear order, or chain) n R with product order: (x1,..., xn) 6 (y1,..., yn) ⇐⇒ ∀i, xi 6 yi X R with point-wise order: f 6 g ⇐⇒ ∀x ∈ X , f (x) 6 g(x)
Andrew Craig Order and Topology Topology from order Order from topology Interval topology Applications
Morphisms
A map f :(X , 6X ) −→ (Y , 6Y ) is order-preserving if whenever a 6 b in X , then f (a) 6 f (b) in Y . Up-sets and down-sets For A ⊆ X ,
↑A = { x ∈ X : ∃y ∈ A, y 6 x } ↓A = { x ∈ X : ∃y ∈ A, x 6 y } A is an up-set if A = ↑A, a down-set if A = ↓A.
Complements of up-sets are down-sets and vice-versa.
We have the principal up-sets ↑x = { y : x 6 y } and principal down-sets ↓x = { y : y 6 x } for x ∈ X .
Andrew Craig Order and Topology Topology from order Order from topology Interval topology Applications
Order topologies
Alexandrov topology - A = { U : U = ↑U } Upper topology - υ subbasic opens of the form X \↓x Lower topology - ω subbasic opens of the form X \↑x Interval topology - ι = υ ∨ ω Also Scott topology - σ U ∈ σ ⇐⇒ U an up-set, for every D ⊆ X directed, if W D ∈ U, then U ∩ D 6= ∅ Lawson topology - λ = σ ∨ ω Scott topology important on dcpo's and in domain theory.
Andrew Craig Order and Topology Topology from order Order from topology Interval topology Applications
Specialization order
Let (X , τ ) be a topological space. Dene 6τ by:
x 6τ y ⇐⇒ x ∈ {y}
⇐⇒ Nx ⊆ Ny
Then (X , 6τ ) is a pre-order. If (X , τ ) is T0 =⇒ 6τ a partial order. If (X , τ ) is T1 =⇒ 6τ the discrete order. Question: For which order topologies will the specialization order agree with the original order?
Andrew Craig Order and Topology Topology from order Order from topology Interval topology Applications
Answer:
For any ordered set (X , 6), we have: υ ⊆ σ ⊆ A.
Further, and 6υ = 6 6A = 6 . In fact, 6τ = 6 ⇐⇒ υ ⊆ τ ⊆ A.
If X is nite, then υ = σ = A.
Andrew Craig Order and Topology Topology from order Order from topology Interval topology Applications
A topological space (X , τ ) is an Alexandrov space if the intersection of any collection of open sets is open. Also called nitely-generated spaces. Taking the specialization order, we get that V ⊆ X is open i it is an upper set wrt 6τ . We have two functors:
S : TOP −→ PRE, (X , τ ) 7−→ (X , 6τ )
A : PRE −→ TOP, (X , 6) 7−→ (X , A) If we restrict TOP to Alexandrov spaces then we have an isomorphism between the categories. f :(X , τ ) −→ (Y , δ) is continuous i it is order-preserving from X Y . ( , 6τ ) −→ ( , 6δ)
Andrew Craig Order and Topology Topology from order Order from topology Interval topology Applications
Interval topology Consider the interval topology on a linearly ordered set. This is a LOTS. Every LOTS is T0, T1,... T5. Question: Is the same true for partially ordered sets? Answer: No.
Lemma (Erné) (X , 6) is T2 i for x 6= y there exist nite sets F , G such that F ∩ {x, y}u 6= ∅ and G ∩ {x, y}l 6= ∅ and X = ↓F ∪ ↑G.
Andrew Craig Order and Topology Topology from order Order from topology Interval topology Applications
Theorem (Erné) If (X , 6) contains an innite anti-chain then it is not T2. There exists an ordered set which is Hausdor but not regular.
Theorem (Wolk) A lattice is complete i it is compact in its interval topology.
Therefore, for a complete lattice, T2 ⇐⇒ regular ⇐⇒ normal.
Andrew Craig Order and Topology Topology from order Order from topology Interval topology Applications
Interval topology on products
For a family of ordered sets Xj , j ∈ J we have: