Normal Subgroups of SL2(K[T ]) with Or Without Free Quotients
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On Abelian Subgroups of Finitely Generated Metabelian
J. Group Theory 16 (2013), 695–705 DOI 10.1515/jgt-2013-0011 © de Gruyter 2013 On abelian subgroups of finitely generated metabelian groups Vahagn H. Mikaelian and Alexander Y. Olshanskii Communicated by John S. Wilson To Professor Gilbert Baumslag to his 80th birthday Abstract. In this note we introduce the class of H-groups (or Hall groups) related to the class of B-groups defined by P. Hall in the 1950s. Establishing some basic properties of Hall groups we use them to obtain results concerning embeddings of abelian groups. In particular, we give an explicit classification of all abelian groups that can occur as subgroups in finitely generated metabelian groups. Hall groups allow us to give a negative answer to G. Baumslag’s conjecture of 1990 on the cardinality of the set of isomorphism classes for abelian subgroups in finitely generated metabelian groups. 1 Introduction The subject of our note goes back to the paper of P. Hall [7], which established the properties of abelian normal subgroups in finitely generated metabelian and abelian-by-polycyclic groups. Let B be the class of all abelian groups B, where B is an abelian normal subgroup of some finitely generated group G with polycyclic quotient G=B. It is proved in [7, Lemmas 8 and 5.2] that B H, where the class H of countable abelian groups can be defined as follows (in the present paper, we will call the groups from H Hall groups). By definition, H H if 2 (1) H is a (finite or) countable abelian group, (2) H T K; where T is a bounded torsion group (i.e., the orders of all ele- D ˚ ments in T are bounded), K is torsion-free, (3) K has a free abelian subgroup F such that K=F is a torsion group with trivial p-subgroups for all primes except for the members of a finite set .K/. -
On Finite Groups Whose Every Proper Normal Subgroup Is a Union
Proc. Indian Acad. Sci. (Math. Sci.) Vol. 114, No. 3, August 2004, pp. 217–224. © Printed in India On finite groups whose every proper normal subgroup is a union of a given number of conjugacy classes ALI REZA ASHRAFI and GEETHA VENKATARAMAN∗ Department of Mathematics, University of Kashan, Kashan, Iran ∗Department of Mathematics and Mathematical Sciences Foundation, St. Stephen’s College, Delhi 110 007, India E-mail: ashrafi@kashanu.ac.ir; geetha [email protected] MS received 19 June 2002; revised 26 March 2004 Abstract. Let G be a finite group and A be a normal subgroup of G. We denote by ncc.A/ the number of G-conjugacy classes of A and A is called n-decomposable, if ncc.A/ = n. Set KG ={ncc.A/|A CG}. Let X be a non-empty subset of positive integers. A group G is called X-decomposable, if KG = X. Ashrafi and his co-authors [1–5] have characterized the X-decomposable non-perfect finite groups for X ={1;n} and n ≤ 10. In this paper, we continue this problem and investigate the structure of X-decomposable non-perfect finite groups, for X = {1; 2; 3}. We prove that such a group is isomorphic to Z6;D8;Q8;S4, SmallGroup(20, 3), SmallGroup(24, 3), where SmallGroup.m; n/ denotes the mth group of order n in the small group library of GAP [11]. Keywords. Finite group; n-decomposable subgroup; conjugacy class; X-decompo- sable group. 1. Introduction and preliminaries Let G be a finite group and let NG be the set of proper normal subgroups of G. -
Mathematics 310 Examination 1 Answers 1. (10 Points) Let G Be A
Mathematics 310 Examination 1 Answers 1. (10 points) Let G be a group, and let x be an element of G. Finish the following definition: The order of x is ... Answer: . the smallest positive integer n so that xn = e. 2. (10 points) State Lagrange’s Theorem. Answer: If G is a finite group, and H is a subgroup of G, then o(H)|o(G). 3. (10 points) Let ( a 0! ) H = : a, b ∈ Z, ab 6= 0 . 0 b Is H a group with the binary operation of matrix multiplication? Be sure to explain your answer fully. 2 0! 1/2 0 ! Answer: This is not a group. The inverse of the matrix is , which is not 0 2 0 1/2 in H. 4. (20 points) Suppose that G1 and G2 are groups, and φ : G1 → G2 is a homomorphism. (a) Recall that we defined φ(G1) = {φ(g1): g1 ∈ G1}. Show that φ(G1) is a subgroup of G2. −1 (b) Suppose that H2 is a subgroup of G2. Recall that we defined φ (H2) = {g1 ∈ G1 : −1 φ(g1) ∈ H2}. Prove that φ (H2) is a subgroup of G1. Answer:(a) Pick x, y ∈ φ(G1). Then we can write x = φ(a) and y = φ(b), with a, b ∈ G1. Because G1 is closed under the group operation, we know that ab ∈ G1. Because φ is a homomorphism, we know that xy = φ(a)φ(b) = φ(ab), and therefore xy ∈ φ(G1). That shows that φ(G1) is closed under the group operation. -
Group Theory
Appendix A Group Theory This appendix is a survey of only those topics in group theory that are needed to understand the composition of symmetry transformations and its consequences for fundamental physics. It is intended to be self-contained and covers those topics that are needed to follow the main text. Although in the end this appendix became quite long, a thorough understanding of group theory is possible only by consulting the appropriate literature in addition to this appendix. In order that this book not become too lengthy, proofs of theorems were largely omitted; again I refer to other monographs. From its very title, the book by H. Georgi [211] is the most appropriate if particle physics is the primary focus of interest. The book by G. Costa and G. Fogli [102] is written in the same spirit. Both books also cover the necessary group theory for grand unification ideas. A very comprehensive but also rather dense treatment is given by [428]. Still a classic is [254]; it contains more about the treatment of dynamical symmetries in quantum mechanics. A.1 Basics A.1.1 Definitions: Algebraic Structures From the structureless notion of a set, one can successively generate more and more algebraic structures. Those that play a prominent role in physics are defined in the following. Group A group G is a set with elements gi and an operation ◦ (called group multiplication) with the properties that (i) the operation is closed: gi ◦ g j ∈ G, (ii) a neutral element g0 ∈ G exists such that gi ◦ g0 = g0 ◦ gi = gi , (iii) for every gi exists an −1 ∈ ◦ −1 = = −1 ◦ inverse element gi G such that gi gi g0 gi gi , (iv) the operation is associative: gi ◦ (g j ◦ gk) = (gi ◦ g j ) ◦ gk. -
The Frattini Module and P -Automorphisms of Free Pro-P Groups
Publ. RIMS, Kyoto Univ. (), The Frattini module and p!-automorphisms of free pro-p groups. By Darren Semmen ∗ Abstract If a non-trivial subgroup A of the group of continuous automorphisms of a non- cyclic free pro-p group F has finite order, not divisible by p, then the group of fixed points FixF (A) has infinite rank. The semi-direct product F >!A is the universal p-Frattini cover of a finite group G, and so is the projective limit of a sequence of finite groups starting with G, each a canonical group extension of its predecessor by the Frattini module. Examining appearances of the trivial simple module 1 in the Frattini module’s Jordan-H¨older series arose in investigations ([FK97], [BaFr02] and [Sem02]) of modular towers. The number of these appearances prevents FixF (A) from having finite rank. For any group A of automorphisms of a group Γ, the set of fixed points FixΓ(A) := {g ∈ Γ | α(g) = g, ∀α ∈ A} of Γ under the action of A is a subgroup of Γ. Nielsen [N21] and, for the infinite rank case, Schreier [Schr27] showed that any subgroup of a free discrete group will be free. Tate (cf. [Ser02, I.§4.2, Cor. 3a]) extended this to free pro-p groups. In light of this, it is natural to ask for a free group F , what is the rank of FixF (A)? When F is a free discrete group and A is finite, Dyer and Scott [DS75] demonstrated that FixF (A) is a free factor of F , i.e. -
Math 412. Simple Groups
Math 412. Simple Groups DEFINITION: A group G is simple if its only normal subgroups are feg and G. Simple groups are rare among all groups in the same way that prime numbers are rare among all integers. The smallest non-abelian group is A5, which has order 60. THEOREM 8.25: A abelian group is simple if and only if it is finite of prime order. THEOREM: The Alternating Groups An where n ≥ 5 are simple. The simple groups are the building blocks of all groups, in a sense similar to how all integers are built from the prime numbers. One of the greatest mathematical achievements of the Twentieth Century was a classification of all the finite simple groups. These are recorded in the Atlas of Simple Groups. The mathematician who discovered the last-to-be-discovered finite simple group is right here in our own department: Professor Bob Greiss. This simple group is called the monster group because its order is so big—approximately 8 × 1053. Because we have classified all the finite simple groups, and we know how to put them together to form arbitrary groups, we essentially understand the structure of every finite group. It is difficult, in general, to tell whether a given group G is simple or not. Just like determining whether a given (large) integer is prime, there is an algorithm to check but it may take an unreasonable amount of time to run. A. WARM UP. Find proper non-trivial normal subgroups of the following groups: Z, Z35, GL5(Q), S17, D100. -
Normal Subgroups of the General Linear Groups Over Von Neumann Regular Rings L
PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 96, Number 2, February 1986 NORMAL SUBGROUPS OF THE GENERAL LINEAR GROUPS OVER VON NEUMANN REGULAR RINGS L. N. VASERSTEIN1 ABSTRACT. Let A be a von Neumann regular ring or, more generally, let A be an associative ring with 1 whose reduction modulo its Jacobson radical is von Neumann regular. We obtain a complete description of all subgroups of GLn A, n > 3, which are normalized by elementary matrices. 1. Introduction. For any associative ring A with 1 and any natural number n, let GLn A be the group of invertible n by n matrices over A and EnA the subgroup generated by all elementary matrices x1'3, where 1 < i / j < n and x E A. In this paper we describe all subgroups of GLn A normalized by EnA for any von Neumann regular A, provided n > 3. Our description is standard (see Bass [1] and Vaserstein [14, 16]): a subgroup H of GL„ A is normalized by EnA if and only if H is of level B for an ideal B of A, i.e. E„(A, B) C H C Gn(A, B). Here Gn(A, B) is the inverse image of the center of GL„(,4/S) (when n > 2, this center consists of scalar invertible matrices over the center of the ring A/B) under the canonical homomorphism GL„ A —►GLn(A/B) and En(A, B) is the normal subgroup of EnA generated by all elementary matrices in Gn(A, B) (when n > 3, the group En(A, B) is generated by matrices of the form (—y)J'lx1'Jy:i''1 with x € B,y £ A,l < i ^ j < n, see [14]). -
Solutions to Exercises for Mathematics 205A
SOLUTIONS TO EXERCISES FOR MATHEMATICS 205A | Part 6 Fall 2008 APPENDICES Appendix A : Topological groups (Munkres, Supplementary exercises following $ 22; see also course notes, Appendix D) Problems from Munkres, x 30, pp. 194 − 195 Munkres, x 26, pp. 170{172: 12, 13 Munkres, x 30, pp. 194{195: 18 Munkres, x 31, pp. 199{200: 8 Munkres, x 33, pp. 212{214: 10 Solutions for these problems will not be given. Additional exercises Notation. Let F be the real or complex numbers. Within the matrix group GL(n; F) there are certain subgroups of particular importance. One such subgroup is the special linear group SL(n; F) of all matrices of determinant 1. 0. Prove that the group SL(2; C) has no nontrivial proper normal subgroups except for the subgroup { Ig. [Hint: If N is a normal subgroup, show first that if A 2 N then N contains all matrices that are similar to A. Therefore the proof reduces to considering normal subgroups containing a Jordan form matrix of one of the following two types: α 0 " 1 ; 0 α−1 0 " Here α is a complex number not equal to 0 or 1 and " = 1. The idea is to show that if N contains one of these Jordan forms then it contains all such forms, and this is done by computing sufficiently many matrix products. Trial and error is a good way to approach this aspect of the problem.] SOLUTION. We shall follow the steps indicated in the hint. If N is a normal subgroup of SL(2; C) and A 2 N then N contains all matrices that are similar to A. -
Normal Subgroups of Invertibles and of Unitaries In
Normal subgroups of invertibles and of unitaries in a C∗-algebra Leonel Robert We investigate the normal subgroups of the groups of invertibles and unitaries in the connected component of the identity. By relating normal subgroups to closed two-sided ideals we obtain a “sandwich condition” describing all the closed normal subgroups both in the invertible and in the the unitary case. We use this to prove a conjecture by Elliott and Rørdam: in a simple C∗-algebra, the group of approximately inner automorphisms induced by unitaries in the connected com- ponent of the identity is topologically simple. Turning to non-closed subgroups, we show, among other things, that in simple unital C∗-algebra the commutator subgroup of the group of invertibles in the connected component of the identity is a simple group modulo its center. A similar result holds for unitaries under a mild extra assumption. 1 Introduction We investigate below the normal subgroups of the group of invertibles and of the group of unitaries of a C∗-algebra. We confine ourselves to the connected component of the identity. Let GA denote the group of invertibles connected to the identity and UA the unitaries connected to the identity, A being the ambient C∗-algebra. The problem of calculating the normal subgroups of GA and UA goes to back to Kadison’s papers [Kad52, Kad55, Kad54], where the (norm) closed normal subgroups of GA and UA, for A a von Neumann algebra factor, were fully described. Over the years various authors have returned to this problem, arXiv:1603.01884v1 [math.OA] 6 Mar 2016 focusing on the case that A is a simple C∗-algebra, and assuming further structural properties on A. -
A Splitting Theorem for Linear Polycyclic Groups
New York Journal of Mathematics New York J. Math. 15 (2009) 211–217. A splitting theorem for linear polycyclic groups Herbert Abels and Roger C. Alperin Abstract. We prove that an arbitrary polycyclic by finite subgroup of GL(n, Q) is up to conjugation virtually contained in a direct product of a triangular arithmetic group and a finitely generated diagonal group. Contents 1. Introduction 211 2. Restatement and proof 212 References 216 1. Introduction A linear algebraic group defined over a number field K is a subgroup G of GL(n, C),n ∈ N, which is also an affine algebraic set defined by polyno- mials with coefficients in K in the natural coordinates of GL(n, C). For a subring R of C put G(R)=GL(n, R) ∩ G.LetB(n, C)andT (n, C)bethe (Q-defined linear algebraic) subgroups of GL(n, C) of upper triangular or diagonal matrices in GL(n, C) respectively. Recall that a group Γ is called polycyclic if it has a composition series with cyclic factors. Let Q be the field of algebraic numbers in C.Every discrete solvable subgroup of GL(n, C) is polycyclic (see, e.g., [R]). 1.1. Let o denote the ring of integers in the number field K.IfH is a solvable K-defined algebraic group then H(o) is polycyclic (see [S]). Hence every subgroup of a group H(o)×Δ is polycyclic, if Δ is a finitely generated abelian group. Received November 15, 2007. Mathematics Subject Classification. 20H20, 20G20. Key words and phrases. Polycyclic group, arithmetic group, linear group. -
The Tits Alternative
The Tits Alternative Matthew Tointon April 2009 0 Introduction In 1972 Jacques Tits published his paper Free Subgroups in Linear Groups [Tits] in the Journal of Algebra. Its key achievement was to prove a conjecture of H. Bass and J.-P. Serre, now known as the Tits Alternative for linear groups, namely that a finitely-generated linear group over an arbitrary field possesses either a solvable subgroup of finite index or a non-abelian free subgroup. The aim of this essay is to present this result in such a way that it will be clear to a general mathematical audience. The greatest challenge in reading Tits's original paper is perhaps that the range of mathematics required to understand the theorem's proof is far greater than that required to understand its statement. Whilst this essay is not intended as a platform in which to regurgitate theory it is very much intended to overcome this challenge by presenting sufficient background detail to allow the reader, without too much effort, to enjoy a proof that is pleasing in both its variety and its ingenuity. Large parts of the prime-characteristic proof follow basically the same lines as the characteristic-zero proof; however, certain elements of the proof, particularly where it is necessary to introduce field theory or number theory, can be made more concrete or intuitive by restricting to characteristic zero. Therefore, for the sake of clarity this exposition will present the proof over the complex numbers, although where clarity and brevity are not impaired by considering a step in the general case we will do so. -
18.704 Supplementary Notes March 23, 2005 the Subgroup Ω For
18.704 Supplementary Notes March 23, 2005 The subgroup Ω for orthogonal groups In the case of the linear group, it is shown in the text that P SL(n; F ) (that is, the group SL(n) of determinant one matrices, divided by its center) is usually a simple group. In the case of symplectic group, P Sp(2n; F ) (the group of symplectic matrices divided by its center) is usually a simple group. In the case of the orthog- onal group (as Yelena will explain on March 28), what turns out to be simple is not P SO(V ) (the orthogonal group of V divided by its center). Instead there is a mysterious subgroup Ω(V ) of SO(V ), and what is usually simple is P Ω(V ). The purpose of these notes is first to explain why this complication arises, and then to give the general definition of Ω(V ) (along with some of its basic properties). So why should the complication arise? There are some hints of it already in the case of the linear group. We made a lot of use of GL(n; F ), the group of all invertible n × n matrices with entries in F . The most obvious normal subgroup of GL(n; F ) is its center, the group F × of (non-zero) scalar matrices. Dividing by the center gives (1) P GL(n; F ) = GL(n; F )=F ×; the projective general linear group. We saw that this group acts faithfully on the projective space Pn−1(F ), and generally it's a great group to work with.