<<

- QMII 2017/18

Daniel Aloni

0 References

1. Lecture notes - Gilad Perez

2. Lie in particle - H. Georgi

3. Google...

1Motivation

As a warm up let us motivate the need for in physics. It comes out that Group theory and share very similar properties. This motivates us to learn more sophisticated tools of Group theory and how to implement them in modern physics. We will take as an example but the following holds for any :

1. Arotationofarotationisalsoarotation-R = R R . 3 2 · 1 2. Multiplication of rotations is associative - R (R R )=(R R ) R . 3 · 2 · 1 3 · 2 · 1 3. The identity 1 is a unique which leaves the system unchanged and commutes with all other rotations.

4. For each rotation we can rotate the system backwards. This inverse 1 1 rotation is unique and satisfies - R R = R R = 1. · ·

1 This list is exactly the list of that defines a group.

A Group is a pair (G, )ofasetG and a product s.t. · · 1. - g ,g G , g g G. 8 1 2 2 2 · 1 2 2. Associativity - g ,g ,g G,(g g ) g = g (g g ). 8 1 2 3 2 3 · 2 · 1 3 · 2 · 1 3. There is an identity e G,s.t. g G, e g = g e = g. 2 8 2 · · 1 1 4. Every element g G has an inverse element g G,s.t. g g = 2 2 · 1 g g = e. ·

What we would like to learn? Here are few examples, considering the rotations again. A rotation of a three-vector v,isgivenbya3 3matrixR. ⇥ • How it acts on other vector spaces, for instance the Hilbert space in ?

• What are the conserved quantities?

• How to make it infinitesimal? (and what is it good for...)

• How a rotation of one space is induced to another space?

As we will see, Group theory and in particular Lie groups and will teach us how to answer these questions in a systematic way, and how to do that for any symmetry.

2 Classification

Adictionaryformostimportantgroups(inphysics...).

2.1 Discrete:

Adiscretegroupmightcontainafiniteorinfinitenumberofelements.If the of elements is finite,thenthenumber of elements is called the of the group.

2 • Zn -ThesetofintegernumbersG =(0, 1, 2,..n 1) with addition mod n.Itisequivalenttocyclicpermutationsofn objects.

Sn - All possible of n objects.

3 Example - Z3,S3 and the

Z3 is also the rotation group of the triangle. The elements of the rotation group are:

e =donothing ,a1 =(1, 2, 3) ,a2 =(3, 2, 1)

where a1 (a2)areunderstoodascyclic(anti-cyclic)interchangingofcorners in positions (1,2,3). Graphically

We can write the multiplication table for Z3,andcomparetorotationsof triangle:

modn 0 1 2 e a1 a2

0 0 1 2 e e a1 a2

1 1 2 0 , a1 a1 a2 e

2 2 0 1 a2 a2 e a1 The symmetric group includes three additional elements - mirroring around the altitudes. The elements of S3 are:

a3 =(2, 3) ,a4 =(3, 1) ,a5 =(1, 2)

where a3 for instance is understood as interchanging the corners in positions (2,3). Graphically

Exercise - write the multiplication table for S3.

4 • of - The elements are all the num- bers n Z.Theproductofthegroupisadditionofnumbers.Thisis 2 the most trivial example of infinite .

2.2 Lie groups:

By Lie groups we will always mean Lie Groups. A have an infinite number of elements which can be parametrized by a smooth function of a finite number of parameters f(x ,x ..., x ) G, x A.Forus 1 2 n 2 i 2 A = R, C. The group multiplication law is just .

• General GL(n, V )= A Mn(V ) det(A) =0 .The { 2 | 6 } set of all invertible n n matrices on a field V ,withmatrixmultipli- ⇥ cation.

O(n)= A GL(n, R) AT A =1 .Equivalently, { 2 | } the column vectors of A are an orthonormal set. Also equivalently, A preserve the canonical inner product in Rn. Note that det A = 1. ± • Special Orthogonal Group. SO(n)= A O(n) det A =1. { 2 | } SO(n)isthegroupofrotationsindimensionn. O(n)containsrotations and reflections. Question: does taking det A = 1 give a group?

. U(n)= A GL(n, C) A†A =1.Equivalently, { 2 | } the column vectors are an orthonormal set in Cn. Also equivalently, A preserves the canonical inner product. Note that det A =1. | | • . SU(n)= A U(n) det A =1 . { 2 | } • Generalized Orthogonal Group. O(n, k)= A GL(n+k, R) AT gA = n times k times { 2 | g ,whereg =diag(1,...,1, 1,..., 1). } Lets check that thisz is a}| group.{ z If}|A, B{ O(n, k)then(A B)T ⌘A B = ⌘ 2 · · BT AT ⌘AB = BT ⌘B = ⌘ A B O(n, k). ) · 2 Thez Lorentz}| { group is O(1, 3).

5 3

For a given group G,ifasubsetofelementsH G,formagroupwiththe ⇢ same product of G,wesaythatH is a of G. Examples:

• We already saw that Z3 is a subgroup of S3.

• Consider the two dimensional unitary group U(2). This is a set of unitary matrices which acts on two dimensional complex vectors.

1. The group U(1) which changes the overall phase of those vectors is a subgroup of U(2). 2. The group SU(2) is also a subgroup of U(2) since for all matrices A B = A B . | · | | |·| | Note that the two subgroups commutes. We will make use of these fact to show that U(2) can be decomposed completely to this two subgroups, denoted by U(2) = SU(2) U(1). ⇥ • SO(3) is a subgroup of SO(4). For instance we can choose a subset of matrices of the following form

1 000 00 1 O = B0 SO(3)C B C B0 C B C @ A Note that unlike the previous case, in this case the remaining is not a group, namely there is no group G, s.t. SO(4) = SO(3) G. ⇥

4 Representation

For physicists, the theory of representation is the link between group theory and applications in physics. It tells us how an element g in an abstract group G,actsonaphysicalsystem.Moreformally,

6 A Representation ( ) is a mapping, D of elements of G ⇠ onto a set of linear operators

D : G GL(V )s.t.D(g )D(g )=D(g g ) ! 1 2 1 2

We use rep as a short hand notation 1.

4.1 Discrete

• The action of Z3 on complex D : Z3 C: !

2⇡i/3 4⇡i/3 D(e)=1,D(a1)=e ,D(a2)=e .

This representation is 1 1andonto.Suchrepresentationsarecalled .

of a discrete group of order n, is constructed as follows:

1. For each element g G associate a vector g s.t. they form an i 2 | ii orthonormal basis, namely g g = . h i| ji ij 2. Define the regular representation on this as

D(g ) g = g g i | ji | i · ji

This is indeed a representation since D(gi)D(gj)=D(gigj). 3. The components of the matrices are given by [D(g)] = g D(g) g ij h i| | ji 1A homomorphism is a mapping from a group G to a group H which is compatible with the group product, namely : G H satisfies g1, G,(g1 g2)=(g1) (g2). ! 8 2 G· H· A representation is a homomorphism to the set of linear operators.

7 Let us find it explicitly for Z3:

1 0 0 e = 0 , a = 1 , a = 0 | i 0 1 | 1i 0 1 | 2i 0 1 0 0 1 B C B C B C @ A @ A @ A Clearly D(e) gi = egi = gi D(e)=1.Byusingthemultiplica- | i | i | i) tion table we find

D(a ) e = a ,D(a ) e = a 001 010 1 | i | 1i 2 | i | 2i D(a ) a = a ,D(a ) a = e D(a1)= 100 ,D(a2)= 001 1 | 1i | 2i 2 | 1i | i 9 0 1 0 1 D(a ) a = e ,D(a ) a = a => 010 100 1 | 2i | i 2 | 2i | 1i B C B C @ A @ A > as you already saw in ... ;

• ArepresentationofS3 on a two dimensional vector space is given by:

1 p3 1 p3 10 2 2 2 2 D(e)= ,D(a1)= p3 1 ,D(a2)= p3 1 01! ! ! 2 2 2 2 1 p3 1 p3 10 2 2 2 2 D(a3)= ,D(a4)= p3 1 ,D(a5)= p3 1 01! ! ! 2 2 2 2 Exercises:

– Check that this is indeed a representation.

– Find the regular representation of S3.

4.2 Lie groups

• The trivial representation - D(g)=1 , g G. 8 2 • Fundamental representation -ForaLiegroup,whichisdefinedas asetoflinearoperatorsthatactsonavectorspace,thefundamental representation is the representation of the group on its vector space: D(A)=A, A G. 8 2

8 Example - Consider a group element U SU(N) and an N-dimensional 2 complex vector v V .Thentheactionofthefundamentalrepresen- 2 tation on the vector space V is

D (U)v = Uv U i vj fund. , j

• Anti-fundamental Danti. is the complex conjugation (not )ofthe † fundamental representation D,namelyD (A)=D(A)⇤ = A⇤ , A anti. 8 2 G. Example - Consider again a group element U SU(N) and an N- 2 dimensional complex vector w V .Thentheactionoftheanti- 2 fundamental representation on the vector space V is

i j j i T D (U)w = U ⇤w U ⇤w = w (U †) w U † anti. , j j ,

Then if v transforms under the fundamental v⇤ transforms under the anti fundamental denoted by

v Uv v† v†U † ! ) !

comment: Note that physicists always make an in

this context. Although Dfund and Danti. tells us how to act with an element g GL(V )onthevectorspaceV ,itisalsosaidthatthevector 2 v lives in the fundamental and v⇤ lives in the anti fundamental. This convention will be convenient once we will start to learn field .

• Tensor representation -Byusingpreviousdefinitionswecancon- struct representations which act on tensors with any number of funda- mental and anti-fundamental indices. Example - Consider a group element U U(N)andatensorT ijk with 2 three fundamental indices. Then the tensor representation is

ijk i0 j0 k0 ijk Dtens.(U)T = U iU jU jT

9 4.2.1 Building invariants

We will deal with physical systems which are defined by their action S[]. The whole purpose of learning group theory is to learn how to deal with symmetries of this action. In the language of representations if S[]livesin the trivial representation of some G we are saying that G is asymmetryofthesystem.InotherwordsS[]isinvariant(orscalar)under the action of G. How do we build terms from general representations such that the whole object is ? There is a simple rule of thumb that all indices should be contracted by using Kronecker’s delta. This is not a general statement but will work with most of the groups that we will deal with. Examples: Consider a vector v which transforms uncder the fundamental of SU(3) and a tensor T with three anti-fundamental indices. Then the most trivial invariant that we can think of is

i i k i m i m i v⇤v v0⇤v0 = v⇤(U †) U v = v⇤ v = v⇤v , i ! i k i m i m i and a more complicated one will be

i j k i0 i j0 j k0 k l m m i0 j0 k0 i j k i j k v v v Tijk U v U v U v U ⇤U ⇤U ⇤Tlmn = v v v Tlmn = v v v Tijk . ! i j k i0 j0 k0 l m n

For SU(N) there is an additional way to contract indices by using the N- dimensional anti symmetric tensor. Consider three vectors v, w, z in the fundamental of SU(3). Then

✏ viwjzk ✏ U i0 U j0 U k0 viwjzk ijk ! i0j0k0 i j k

i0 j0 k0 where ✏123 =1.Weseethatif✏ijk = ✏i0j0k0 Ui Uj Uk then this object is i0 j0 k0 invariant. Let us choose ijk = 123. Then we observe that ✏i0j0k0 U1 U2 U3 = Det(U)=1, and for each anti-cyclic permutations of ijk we get a minus SU(N)

i0 j0 k0 sign. Therefore indeed ✏ijk = ✏i0j0k0 Ui Uj Uk and this construction is an SU(N)invariant. Exercise - Show that if i = j the right hand side also vanishes.

10