<<

Chapter 21 Worksheet #3 Name ______

The of a stable nucleus is less than the sum of the of the and that make up that nucleus. The difference in mass is called the mass defect (Δm):

Δm = [Zmproton + (A-Z)mneutron] - (matom - Zmelectron) = [Zmproton + (A-Z)mneutron] - mnucleus

Δm = [Z(mH-) + (A-Z)mn] - matom

Einstein relation: E = mc2 (mass/ equivalency); c is the (3.00x108 m/s)

The energy equivalence of the mass defect is called the nuclear .

BE = Δmc2 (usually in MeV; 1 MeV = 1.60x10-13 ) (931.5 MeV = 1 amu; 1 amu = 1.50x10-10 joules)

The binding energy represents the amount of energy that must be supplied to break the nucleus into its individual protons and neutrons.

A more useful quantity for comparing the stability of is the binding energy per .

BE BE  nucleon # protons#neutrons

The greater the BE/nucleon, the more stable the nucleus.

Example: Determine the BE and BE/nucleon for Osmium-190. m(190Os) = 189.95863 amu; m(1n) = 1.00867 amu; m(1H) = 1.00783 amu

The binding energy per nucleon generally falls around 8 MeV. A plot of BE/nucleon vs Z shows that the most stable nuclei occur around Z = 26 (see text, Fig. 21.8, page 983). Fe-56 is the most stable nucleus in the universe. The existence of a maximum in this curve indicates that energy is released in either a fission or fusion process in which more stable nuclei are produced. Fission - the splitting of a heavy nucleus into two nuclei with smaller mass numbers (with the concomitant release of one or more neutrons). For example:

239 1 144 94 1 94 Pu0n 58Ce36Kr 20 n (this is only one of many possible fission outcomes)

Fusion - the combining of two light nuclei to form a heavier, more stable nucleus. For example:

2 3 4 1 1 H1H2 He0n

Because of the large binding involved in a nucleus, both fission and fusion involve energy changes of more than a million times larger than those energy changes associated with chemical reactions.

Calculate the amount of energy released (in kJ) when 1 mole (235 g) of 235U fissions to form 137Te + 96Zr. m(235U) = 235.043915 amu m(1n) = 1.0086654 amu m(137Te) = 136.925449 amu m(96Zr) = 95.908286 amu

Calculate the mass (in g) of methane (CH4) required to yield the same amount of energy as the fissioning 235 of one mole of U when methane is combusted to produce CO2(g) and H2O(l).