Algebraic Geometry by J.S
CHAPTER 13
Coherent Sheaves; Invertible Sheaves
In this chapter, k is an arbitrary field. a Coherent sheaves
Let V SpmA be an affine variety over k, and let M be a finitely generated A-module. D There is a unique sheaf of OV -modules M on V such that, for all f A, 2 .D.f /;M/ M . A A M /: D f D f ˝ Such an OV -module M is said to be coherent. A homomorphism M N of A-modules ! defines a homomorphism M N of OV -modules, and M M is a fully faithful functor ! 7! from the category of finitely generated A-modules to the category of coherent OV -modules, with quasi-inverse M .V;M/. 7! Now consider a variety V . An OV -module M is said to be coherent if, for every open affine subset U of V , M U is coherent. It suffices to check this condition for the sets in an j open affine covering of V . n For example, OV is a coherent OV -module. An OV -module M is said to be locally n free of rank n if it is locally isomorphic to OV , i.e., if every point P V has an open n 2 neighbourhood such that M U O . A locally free OV -module of rank n is coherent. j V Let v V , and let M be a coherent OV -module. We define a .v/-module M.v/ as 2 follows: after replacing V with an open neighbourhood of v, we can assume that it is affine; hence we may suppose that V Spm.A/, that v corresponds to a maximal ideal m in A (so D that .v/ A=m/, and M corresponds to the A-module M ; we then define D M.v/ M A .v/ M=mM: D ˝ D It is a finitely generated vector space over .v/. Don’t confuse M.v/ with the stalk Mv of M which, with the above notations, is Mm M A Am. Thus D ˝ M.v/ Mv=mMv .v/ A Mm: D D ˝ m This is Chapter 13 of Algebraic Geometry by J.S. Milne. July 8, 2015 Copyright c 2015 J.S. Milne. Single paper copies for noncommercial personal use may be made without explicit permission from the copyright holder.
1 2 13. COHERENT SHEAVES;INVERTIBLE SHEAVES
Nakayama’s lemma (AG 1.3) shows that
M.v/ 0 Mv 0: D ) D The support of a coherent sheaf M is
Supp.M/ v V M.v/ 0 v V Mv 0 : D f 2 j ¤ g D f 2 j ¤ g Suppose V is affine, and that M corresponds to the A-module M . Let a be the annihilator of M : a f A f M 0 : D f 2 j D g Then M=mM 0 m a (for otherwise A=mA contains a nonzero element annihilating ¤ ” M=mM ), and so Supp.M/ V.a/: D Thus the support of a coherent module is a closed subset of V . Note that if M is locally free of rank n, then M.v/ is a vector space of dimension n for all v. There is a converse of this.
PROPOSITION 13.1. If M is a coherent OV -module such that M.v/ has constant dimen- sion n for all v V , then M is a locally free of rank n. 2
PROOF. We may assume that V is affine, and that M corresponds to the finitely generated A-module M . Fix a maximal ideal m of A, and let x1;:::;xn be elements of M whose images in M=mM form a basis for it over .v/. Consider the map
n X A M; .a1;:::;an/ ai xi : W ! 7! Its cokernel is a finitely generated A-module whose support does not contain v. Therefore there is an element f A, f m, such that defines a surjection An M . After 2 … f ! f replacing A with Af we may assume that itself is surjective. For every maximal ideal n of A, the map .A=n/n M=nM is surjective, and hence (because of the condition on ! the dimension of M.v/) bijective. Therefore, the kernel of is contained in nn (meaning n n) for all maximal ideals n in A, and the next lemma shows that this implies that the kernel is zero. 2
LEMMA 13.2. Let A be an affine k-algebra. Then \ m 0 (intersection of all maximal ideals in A). D
PROOF. When k is algebraically closed, we showed (AG, 2.18) that this follows from the strong Nullstellensatz. In the general case, consider a maximal ideal m of A kal. Then ˝k A=.m A/ , .A kal/=m kal; \ ! ˝k D and so A=m A is an integral domain. Since it is finite-dimensional over k, it is a field, and \ so m A is a maximal ideal in A. Thus if f A is in all maximal ideals of A, then its image \ al 2 in A k is in all maximal ideals of A, and so is zero. 2 ˝ b. Invertible sheaves. 3
For two coherent OV -modules M and N , there is a unique coherent OV -module M O N such that ˝ V