Some Problems of Erdős on the Sum-Of-Divisors Function
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Bi-Unitary Multiperfect Numbers, I
Notes on Number Theory and Discrete Mathematics Print ISSN 1310–5132, Online ISSN 2367–8275 Vol. 26, 2020, No. 1, 93–171 DOI: 10.7546/nntdm.2020.26.1.93-171 Bi-unitary multiperfect numbers, I Pentti Haukkanen1 and Varanasi Sitaramaiah2 1 Faculty of Information Technology and Communication Sciences, FI-33014 Tampere University, Finland e-mail: [email protected] 2 1/194e, Poola Subbaiah Street, Taluk Office Road, Markapur Prakasam District, Andhra Pradesh, 523316 India e-mail: [email protected] Dedicated to the memory of Prof. D. Suryanarayana Received: 19 December 2019 Revised: 21 January 2020 Accepted: 5 March 2020 Abstract: A divisor d of a positive integer n is called a unitary divisor if gcd(d; n=d) = 1; and d is called a bi-unitary divisor of n if the greatest common unitary divisor of d and n=d is unity. The concept of a bi-unitary divisor is due to D. Surynarayana [12]. Let σ∗∗(n) denote the sum of the bi-unitary divisors of n: A positive integer n is called a bi-unitary perfect number if σ∗∗(n) = 2n. This concept was introduced by C. R. Wall in 1972 [15], and he proved that there are only three bi-unitary perfect numbers, namely 6, 60 and 90. In 1987, Peter Hagis [6] introduced the notion of bi-unitary multi k-perfect numbers as solu- tions n of the equation σ∗∗(n) = kn. A bi-unitary multi 3-perfect number is called a bi-unitary triperfect number. A bi-unitary multiperfect number means a bi-unitary multi k-perfect number with k ≥ 3: Hagis [6] proved that there are no odd bi-unitary multiperfect numbers. -
Prime Divisors in the Rationality Condition for Odd Perfect Numbers
Aid#59330/Preprints/2019-09-10/www.mathjobs.org RFSC 04-01 Revised The Prime Divisors in the Rationality Condition for Odd Perfect Numbers Simon Davis Research Foundation of Southern California 8861 Villa La Jolla Drive #13595 La Jolla, CA 92037 Abstract. It is sufficient to prove that there is an excess of prime factors in the product of repunits with odd prime bases defined by the sum of divisors of the integer N = (4k + 4m+1 ℓ 2αi 1) i=1 qi to establish that there do not exist any odd integers with equality (4k+1)4m+2−1 between σ(N) and 2N. The existence of distinct prime divisors in the repunits 4k , 2α +1 Q q i −1 i , i = 1,...,ℓ, in σ(N) follows from a theorem on the primitive divisors of the Lucas qi−1 sequences and the square root of the product of 2(4k + 1), and the sequence of repunits will not be rational unless the primes are matched. Minimization of the number of prime divisors in σ(N) yields an infinite set of repunits of increasing magnitude or prime equations with no integer solutions. MSC: 11D61, 11K65 Keywords: prime divisors, rationality condition 1. Introduction While even perfect numbers were known to be given by 2p−1(2p − 1), for 2p − 1 prime, the universality of this result led to the the problem of characterizing any other possible types of perfect numbers. It was suggested initially by Descartes that it was not likely that odd integers could be perfect numbers [13]. After the work of de Bessy [3], Euler proved σ(N) that the condition = 2, where σ(N) = d|N d is the sum-of-divisors function, N d integer 4m+1 2α1 2αℓ restricted odd integers to have the form (4kP+ 1) q1 ...qℓ , with 4k + 1, q1,...,qℓ prime [18], and further, that there might exist no set of prime bases such that the perfect number condition was satisfied. -
Paul Erdős and the Rise of Statistical Thinking in Elementary Number Theory
Paul Erd®s and the rise of statistical thinking in elementary number theory Carl Pomerance, Dartmouth College based on the joint survey with Paul Pollack, University of Georgia 1 Let us begin at the beginning: 2 Pythagoras 3 Sum of proper divisors Let s(n) be the sum of the proper divisors of n: For example: s(10) = 1 + 2 + 5 = 8; s(11) = 1; s(12) = 1 + 2 + 3 + 4 + 6 = 16: 4 In modern notation: s(n) = σ(n) − n, where σ(n) is the sum of all of n's natural divisors. The function s(n) was considered by Pythagoras, about 2500 years ago. 5 Pythagoras: noticed that s(6) = 1 + 2 + 3 = 6 (If s(n) = n, we say n is perfect.) And he noticed that s(220) = 284; s(284) = 220: 6 If s(n) = m, s(m) = n, and m 6= n, we say n; m are an amicable pair and that they are amicable numbers. So 220 and 284 are amicable numbers. 7 In 1976, Enrico Bombieri wrote: 8 There are very many old problems in arithmetic whose interest is practically nil, e.g., the existence of odd perfect numbers, problems about the iteration of numerical functions, the existence of innitely many Fermat primes 22n + 1, etc. 9 Sir Fred Hoyle wrote in 1962 that there were two dicult astronomical problems faced by the ancients. One was a good problem, the other was not so good. 10 The good problem: Why do the planets wander through the constellations in the night sky? The not-so-good problem: Why is it that the sun and the moon are the same apparent size? 11 Perfect numbers, amicable numbers, and similar topics were important to the development of elementary number theory. -
MORE-ON-SEMIPRIMES.Pdf
MORE ON FACTORING SEMI-PRIMES In the last few years I have spent some time examining prime numbers and their properties. Among some of my new results are the a Prime Number Function F(N) and the concept of Number Fraction f(N). We can define these quantities as – (N ) N 1 f (N 2 ) 1 f (N ) and F(N ) N Nf (N 3 ) Here (N) is the divisor function of number theory. The interesting property of these functions is that when N is a prime then f(N)=0 and F(N)=1. For composite numbers f(N) is a positive fraction and F(N) will be less than one. One of the problems of major practical interest in number theory is how to rapidly factor large semi-primes N=pq, where p and q are prime numbers. This interest stems from the fact that encoded messages using public keys are vulnerable to decoding by adversaries if they can factor large semi-primes when they have a digit length of the order of 100. We want here to show how one might attempt to factor such large primes by a brute force approach using the above f(N) function. Our starting point is to consider a large semi-prime given by- N=pq with p<sqrt(N)<q By the basic definition of f(N) we get- p q p2 N f (N ) f ( pq) N pN This may be written as a quadratic in p which reads- p2 pNf (N ) N 0 It has the solution- p K K 2 N , with p N Here K=Nf(N)/2={(N)-N-1}/2. -
ON PERFECT and NEAR-PERFECT NUMBERS 1. Introduction a Perfect
ON PERFECT AND NEAR-PERFECT NUMBERS PAUL POLLACK AND VLADIMIR SHEVELEV Abstract. We call n a near-perfect number if n is the sum of all of its proper divisors, except for one of them, which we term the redundant divisor. For example, the representation 12 = 1 + 2 + 3 + 6 shows that 12 is near-perfect with redundant divisor 4. Near-perfect numbers are thus a very special class of pseudoperfect numbers, as defined by Sierpi´nski. We discuss some rules for generating near-perfect numbers similar to Euclid's rule for constructing even perfect numbers, and we obtain an upper bound of x5=6+o(1) for the number of near-perfect numbers in [1; x], as x ! 1. 1. Introduction A perfect number is a positive integer equal to the sum of its proper positive divisors. Let σ(n) denote the sum of all of the positive divisors of n. Then n is a perfect number if and only if σ(n) − n = n, that is, σ(n) = 2n. The first four perfect numbers { 6, 28, 496, and 8128 { were known to Euclid, who also succeeded in establishing the following general rule: Theorem A (Euclid). If p is a prime number for which 2p − 1 is also prime, then n = 2p−1(2p − 1) is a perfect number. It is interesting that 2000 years passed before the next important result in the theory of perfect numbers. In 1747, Euler showed that every even perfect number arises from an application of Euclid's rule: Theorem B (Euler). All even perfect numbers have the form 2p−1(2p − 1), where p and 2p − 1 are primes. -
Parity Alternating Permutations Starting with an Odd Integer
Parity alternating permutations starting with an odd integer Frether Getachew Kebede1a, Fanja Rakotondrajaob aDepartment of Mathematics, College of Natural and Computational Sciences, Addis Ababa University, P.O.Box 1176, Addis Ababa, Ethiopia; e-mail: [email protected] bD´epartement de Math´ematiques et Informatique, BP 907 Universit´ed’Antananarivo, 101 Antananarivo, Madagascar; e-mail: [email protected] Abstract A Parity Alternating Permutation of the set [n] = 1, 2,...,n is a permutation with { } even and odd entries alternatively. We deal with parity alternating permutations having an odd entry in the first position, PAPs. We study the numbers that count the PAPs with even as well as odd parity. We also study a subclass of PAPs being derangements as well, Parity Alternating Derangements (PADs). Moreover, by considering the parity of these PADs we look into their statistical property of excedance. Keywords: parity, parity alternating permutation, parity alternating derangement, excedance 2020 MSC: 05A05, 05A15, 05A19 arXiv:2101.09125v1 [math.CO] 22 Jan 2021 1. Introduction and preliminaries A permutation π is a bijection from the set [n]= 1, 2,...,n to itself and we will write it { } in standard representation as π = π(1) π(2) π(n), or as the product of disjoint cycles. ··· The parity of a permutation π is defined as the parity of the number of transpositions (cycles of length two) in any representation of π as a product of transpositions. One 1Corresponding author. n c way of determining the parity of π is by obtaining the sign of ( 1) − , where c is the − number of cycles in the cycle representation of π. -
PRIME-PERFECT NUMBERS Paul Pollack [email protected] Carl
PRIME-PERFECT NUMBERS Paul Pollack Department of Mathematics, University of Illinois, Urbana, Illinois 61801, USA [email protected] Carl Pomerance Department of Mathematics, Dartmouth College, Hanover, New Hampshire 03755, USA [email protected] In memory of John Lewis Selfridge Abstract We discuss a relative of the perfect numbers for which it is possible to prove that there are infinitely many examples. Call a natural number n prime-perfect if n and σ(n) share the same set of distinct prime divisors. For example, all even perfect numbers are prime-perfect. We show that the count Nσ(x) of prime-perfect numbers in [1; x] satisfies estimates of the form c= log log log x 1 +o(1) exp((log x) ) ≤ Nσ(x) ≤ x 3 ; as x ! 1. We also discuss the analogous problem for the Euler function. Letting N'(x) denote the number of n ≤ x for which n and '(n) share the same set of prime factors, we show that as x ! 1, x1=2 x7=20 ≤ N (x) ≤ ; where L(x) = xlog log log x= log log x: ' L(x)1=4+o(1) We conclude by discussing some related problems posed by Harborth and Cohen. 1. Introduction P Let σ(n) := djn d be the sum of the proper divisors of n. A natural number n is called perfect if σ(n) = 2n and, more generally, multiply perfect if n j σ(n). The study of such numbers has an ancient pedigree (surveyed, e.g., in [5, Chapter 1] and [28, Chapter 1]), but many of the most interesting problems remain unsolved. -
On Arithmetic Functions of Balancing and Lucas-Balancing Numbers 1
MATHEMATICAL COMMUNICATIONS 77 Math. Commun. 24(2019), 77–81 On arithmetic functions of balancing and Lucas-balancing numbers Utkal Keshari Dutta and Prasanta Kumar Ray∗ Department of Mathematics, Sambalpur University, Jyoti Vihar, Burla 768 019, Sambalpur, Odisha, India Received January 12, 2018; accepted June 21, 2018 Abstract. For any integers n ≥ 1 and k ≥ 0, let φ(n) and σk(n) denote the Euler phi function and the sum of the k-th powers of the divisors of n, respectively. In this article, the solutions to some Diophantine equations about these functions of balancing and Lucas- balancing numbers are discussed. AMS subject classifications: 11B37, 11B39, 11B83 Key words: Euler phi function, divisor function, balancing numbers, Lucas-balancing numbers 1. Introduction A balancing number n and a balancer r are the solutions to a simple Diophantine equation 1+2+ + (n 1)=(n +1)+(n +2)+ + (n + r) [1]. The sequence ··· − ··· of balancing numbers Bn satisfies the recurrence relation Bn = 6Bn Bn− , { } +1 − 1 n 1 with initials (B ,B ) = (0, 1). The companion of Bn is the sequence of ≥ 0 1 { } Lucas-balancing numbers Cn that satisfies the same recurrence relation as that { } of balancing numbers but with different initials (C0, C1) = (1, 3) [4]. Further, the closed forms known as Binet formulas for both of these sequences are given by n n n n λ1 λ2 λ1 + λ2 Bn = − , Cn = , λ λ 2 1 − 2 2 where λ1 =3+2√2 and λ2 =3 2√2 are the roots of the equation x 6x +1=0. Some more recent developments− of balancing and Lucas-balancing numbers− can be seen in [2, 3, 6, 8]. -
Cullen Numbers with the Lehmer Property
PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 00, Number 0, Pages 000–000 S 0002-9939(XX)0000-0 CULLEN NUMBERS WITH THE LEHMER PROPERTY JOSE´ MAR´IA GRAU RIBAS AND FLORIAN LUCA Abstract. Here, we show that there is no positive integer n such that n the nth Cullen number Cn = n2 + 1 has the property that it is com- posite but φ(Cn) | Cn − 1. 1. Introduction n A Cullen number is a number of the form Cn = n2 + 1 for some n ≥ 1. They attracted attention of researchers since it seems that it is hard to find primes of this form. Indeed, Hooley [8] showed that for most n the number Cn is composite. For more about testing Cn for primality, see [3] and [6]. For an integer a > 1, a pseudoprime to base a is a compositive positive integer m such that am ≡ a (mod m). Pseudoprime Cullen numbers have also been studied. For example, in [12] it is shown that for most n, Cn is not a base a-pseudoprime. Some computer searchers up to several millions did not turn up any pseudo-prime Cn to any base. Thus, it would seem that Cullen numbers which are pseudoprimes are very scarce. A Carmichael number is a positive integer m which is a base a pseudoprime for any a. A composite integer m is called a Lehmer number if φ(m) | m − 1, where φ(m) is the Euler function of m. Lehmer numbers are Carmichael numbers; hence, pseudoprimes in every base. No Lehmer number is known, although it is known that there are no Lehmer numbers in certain sequences, such as the Fibonacci sequence (see [9]), or the sequence of repunits in base g for any g ∈ [2, 1000] (see [4]). -
Types of Integer Harmonic Numbers (Ii)
Bulletin of the Transilvania University of Bra¸sov • Vol 9(58), No. 1 - 2016 Series III: Mathematics, Informatics, Physics, 67-82 TYPES OF INTEGER HARMONIC NUMBERS (II) Adelina MANEA1 and Nicu¸sorMINCULETE2 Abstract In the first part of this paper we obtained several bi-unitary harmonic numbers which are higher than 109, using the Mersenne prime numbers. In this paper we investigate bi-unitary harmonic numbers of some particular forms: 2k · n, pqt2, p2q2t, with different primes p, q, t and a squarefree inte- ger n. 2010 Mathematics Subject Classification: 11A25. Key words: harmonic numbers, bi-unitary harmonic numbers. 1 Introduction The harmonic numbers introduced by O. Ore in [8] were named in this way by C. Pomerance in [11]. They are defined as positive integers for which the harmonic mean of their divisors is an integer. O. Ore linked the perfect numbers with the harmonic numbers, showing that every perfect number is harmonic. A list of the harmonic numbers less than 2 · 109 is given by G. L. Cohen in [1], finding a total of 130 of harmonic numbers, and G. L. Cohen and R. M. Sorli in [2] have continued to this list up to 1010. The notion of harmonic numbers is extended to unitary harmonic numbers by K. Nageswara Rao in [7] and then to bi-unitary harmonic numbers by J. S´andor in [12]. Our paper is inspired by [12], where J. S´andorpresented a table containing all the 211 bi-unitary harmonic numbers up to 109. We extend the J. S´andors's study, looking for other bi-unitary harmonic numbers, greater than 109. -
The Aliquot Constant We first Show the Following Result on the Geometric Mean for the Ordi- Nary Sum of Divisors Function
THE ALIQUOT CONSTANT WIEB BOSMA AND BEN KANE Abstract. The average value of log s(n)/n taken over the first N even integers is shown to converge to a constant λ when N tends to infinity; moreover, the value of this constant is approximated and proven to be less than 0. Here s(n) sums the divisors of n less than n. Thus the geometric mean of s(n)/n, the growth factor of the function s, in the long run tends to be less than 1. This could be interpreted as probabilistic evidence that aliquot sequences tend to remain bounded. 1. Introduction This paper is concerned with the average growth of aliquot sequences. An aliquot sequence is a sequence a0, a1, a2,... of positive integers ob- tained by iteration of the sum-of-aliquot-divisors function s, which is defined for n> 1 by s(n)= d. d|n Xd<n The aliquot sequence with starting value a0 is then equal to 2 a0, a1 = s(a0), a2 = s(a1)= s (a0),... ; k we will say that the sequence terminates (at 1) if ak = s (a0)=1 for some k ≥ 0. The sequence cycles (or is said to end in a cycle) k l 0 if s (a0) = s (a0) for some k,l with 0 ≤ l<k, where s (n) = n by arXiv:0912.3660v1 [math.NT] 18 Dec 2009 definition. Note that s is related to the ordinary sum-of-divisors function σ, with σ(n)= d|n d, by s(n)= σ(n) − n for integers n> 1. -
On the Parity of the Number of Multiplicative Partitions and Related Problems
PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 140, Number 11, November 2012, Pages 3793–3803 S 0002-9939(2012)11254-7 Article electronically published on March 15, 2012 ON THE PARITY OF THE NUMBER OF MULTIPLICATIVE PARTITIONS AND RELATED PROBLEMS PAUL POLLACK (Communicated by Ken Ono) Abstract. Let f(N) be the number of unordered factorizations of N,where a factorization is a way of writing N as a product of integers all larger than 1. For example, the factorizations of 30 are 2 · 3 · 5, 5 · 6, 3 · 10, 2 · 15, 30, so that f(30) = 5. The function f(N), as a multiplicative analogue of the (additive) partition function p(N), was first proposed by MacMahon, and its study was pursued by Oppenheim, Szekeres and Tur´an, and others. Recently, Zaharescu and Zaki showed that f(N) is even a positive propor- tion of the time and odd a positive proportion of the time. Here we show that for any arithmetic progression a mod m,thesetofN for which f(N) ≡ a(mod m) possesses an asymptotic density. Moreover, the density is positive as long as there is at least one such N. For the case investigated by Zaharescu and Zaki, we show that f is odd more than 50 percent of the time (in fact, about 57 percent). 1. Introduction Let f(N) be the number of unordered factorizations of N,whereafactorization of N is a way of writing N as a product of integers larger than 1. For example, f(12) = 4, corresponding to 2 · 6, 2 · 2 · 3, 3 · 4, 12.