View metadata, citation and similar papers at core.ac.uk brought to you by CORE
provided by Elsevier - Publisher Connector
Linear Algebra and its Applications 433 (2010) 164–171
Contents lists available at ScienceDirect
Linear Algebra and its Applications
journal homepage: www.elsevier.com/locate/laa
Positive semidefinite quadratic forms on unitary matrices Stanislav Popovych
Faculty of Mechanics and Mathematics, Kyiv Taras Schevchenko University, Ukraine
ARTICLE INFO ABSTRACT
Article history: Let Received 3 November 2009 n Accepted 28 January 2010 f (x , ...,x ) = α x x ,a= a ∈ R Available online 6 March 2010 1 n ij i j ij ji i,j=1 Submitted by V. Sergeichuk be a real quadratic form such that the trace of the Hermitian matrix n AMS classification: ( ... ) := α ∗ 15A63 f V1, ,Vn ijVi Vj = 15B48 i,j 1 15B10 is nonnegative for all unitary 2n × 2n matrices V , ...,V .We 90C22 1 n prove that f (U1, ...,Un) is positive semidefinite for all unitary matrices U , ...,U of arbitrary size m × m. Keywords: 1 n Unitary matrix © 2010 Elsevier Inc. All rights reserved. Positive semidefinite matrix Quadratic form Trace
1. Introduction and preliminary
For each real quadratic form n f (x1, ...,xn) = αijxixj, αij = αji ∈ R, i,j=1
and for unitary matrices U1, ...,Un ∈ Mm(C), we define the Hermitian matrix n ( ... ) := α ∗ . f U1, ,Un ijUi Uj i,j=1
E-mail address: [email protected]
0024-3795/$ - see front matter © 2010 Elsevier Inc. All rights reserved. doi:10.1016/j.laa.2010.01.041 S. Popovych / Linear Algebra and its Applications 433 (2010) 164–171 165
We say that f is unitary trace nonnegative if Tr f (U1, ...,Un) 0 for all unitary matrices U1, ...,Un.We say that f is unitary positive semidefinite if f (U1, ...,Un) 0 for all unitary matrices U1, ...,Un. The notation A 0 means that A is positive semidefinite. We prove that f is unitary trace nonnegative if and only if f is unitary positive semidefinite. We also show in Corollary 6 that the unitary trace nonnegative quadratic forms correspond to the dual cone of the cone of real correlation matrices. The following lemma gives a sufficient condition for a quadratic form to be unitary positive semidef- inite. It will follow from our main result that this condition is also necessary (see Corollary 6).
Lemma 1. Let n f (x1, ...,xn) = αijxixj, αij = αji ∈ R i,j=1 =[ ]n be a real quadratic form. Assume that there exists a positive semidefinite matrix C cij i,j= 1 such that α = =/ n α n . ( ... ) = n β ij cij for all i j and t=1 tt t=1 ctt Then there are linear forms gk x1, ,xn t=1 kt xt with βkt ∈ R,k= 1, ..., n and α ∈ R such that for any unitary matrices U1, ...,Un of arbitrary size m × mwehave n 2 ∗ f (U1, ...,Un) = α I + gk(U1, ...,Un) gk(U1, ...,Un). k=1
Proof. Since the matrix C =[cij]ij is positive semidefinite and real, there is a matrix V ∈ Mn(R) such T n that C = V V.Letv1, ...,vn ∈ R be the columns of V, then cij =vi,vj for all i, j = 1, ...,n. Take gk(x1, ...,xn) = vk1x1 + ...+ vknxn. Then it is easy to check that n n n ( ... )∗ ( ... ) = 2 + −1 . gk U1, ,Un gk U1, ,Un vk cijUi Uj k=1 k=1 i,j=1 i=/ j Hence, ⎛ ⎞ n n n ⎝ 2⎠ ∗ f (U1, ...,Un) = αtt − vk I + gk(U1, ...,Un) gk(U1, ...,Un) t=1 k=1 k=1 and the coefficient n n n n 2 αtt − vk = αtt − ctt t=1 k=1 t=1 t=1 is nonnegative. Take α equalling its square root.
n(n−1) T n Let a =[aij]1i T n where c =[c1, ...,cn] ∈ R and F(x) = F0 + x1F1 +···+xnFn with real symmetric matrices Fj.A problem of the form (1) is called primal. The primal problem (1) is called strictly feasible if there exists x such that F(x) is positive definite. The dual problem associated with (1) is the following: maximize − Tr(F0Z) subject to Z 0, Tr(FiZ) = ci,i= 1, ...,n. (2) Here and in sequel, Z is real and symmetric. Z 0 is called dual feasible if Tr(FiZ) = ci for i = 1, ...,n and dual strictly feasible if, in addition, Z is positive definite. If such Z exists, the dual problem (2)is called feasible and, respectively, strictly feasible. ∗ Let p be the optimal value of problem (1), i.e. ∗ p := inf{cT x|F(x) 0}, ∗ and let d be the optimal value of dual problem (2): ∗ d := sup{−Tr(F0Z)|Z 0, Tr(FiZ) = ci,i = 1, ...,m}. ∗ The sets {x|cT x = p ,F(x) 0} and ∗ {Z|−Tr(F0Z) = d ,Z 0, Tr(FiZ) = ci,i = 1, ...,m} are called optimal sets. We need the following theorem; for its proof we refer the readers to [12]or[18]. ∗ ∗ Theorem 2. We have p = d if either of the following conditions holds: • The primal problem (1) is strictly feasible. • The dual problem (2) is strictly feasible. If both conditions hold, the optimal sets are nonempty. The following optimization result is crucial for the proof of Theorem 5. n(n−1)/2 Theorem 3. Let a =[aij]i