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Differentiability of the .

Pablo Jimenez´ Rodr´ıguez

Universidad de Valladolid

March, 8th, 2019

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Definition

Let L1[−1, 1] be the set of the 2-periodic functions f so that R 1 −1 |f (t)| dt < ∞. Given f , g ∈ L1[−1, 1], the convolution of f and g is the

Z 1 f ∗ g(x) = f (t)g(x − t) dt −1

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Definition

Let L1[−1, 1] be the set of the 2-periodic functions f so that R 1 −1 |f (t)| dt < ∞. Given f , g ∈ L1[−1, 1], the convolution of f and g is the function

Z 1 f ∗ g(x) = f (t)g(x − t) dt −1

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Definition

Let L1[−1, 1] be the set of the 2-periodic functions f so that R 1 −1 |f (t)| dt < ∞. Given f , g ∈ L1[−1, 1], the convolution of f and g is the function

Z 1 f ∗ g(x) = f (t)g(x − t) dt −1

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Definition

Let L1[−1, 1] be the set of the 2-periodic functions f so that R 1 −1 |f (t)| dt < ∞. Given f , g ∈ L1[−1, 1], the convolution of f and g is the function

Z 1 f ∗ g(x) = f (t)g(x − t) dt −1

Pablo Jim´enezRodr´ıguez Differentiability of the convolution If f is Lipschitz, then f ∗ g is Lipschitz.

If f , g ∈ L2[−1, 1], then f ∗ g is continuous. There exist nowhere differentiable functions f , g so that f ∗ g is differentiable.

The previous examples, and some others in the same way, gives the idea that the convolution takes “the best” properties from its parent functions Results in this line have given the convolution operator the label of smoothening.

Lemma

Let f , g ∈ L1[−1, 1]. dk f If f is k times differentiable (k ≥ 0), with dxk continuous, then f ∗ g is k times differentiable, with dk dk f dxk (f ∗ g)(x) = ( dxk ∗ g)(x).

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Pablo Jim´enezRodr´ıguez Differentiability of the convolution If f , g ∈ L2[−1, 1], then f ∗ g is continuous. There exist nowhere differentiable functions f , g so that f ∗ g is differentiable.

The previous examples, and some others in the same way, gives the idea that the convolution takes “the best” properties from its parent functions Results in this line have given the convolution operator the label of smoothening.

Lemma

Let f , g ∈ L1[−1, 1]. dk f If f is k times differentiable (k ≥ 0), with dxk continuous, then f ∗ g is k times differentiable, with dk dk f dxk (f ∗ g)(x) = ( dxk ∗ g)(x). If f is Lipschitz, then f ∗ g is Lipschitz.

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Pablo Jim´enezRodr´ıguez Differentiability of the convolution If f , g ∈ L2[−1, 1], then f ∗ g is continuous. There exist nowhere differentiable functions f , g so that f ∗ g is differentiable.

Results in this line have given the convolution operator the label of smoothening.

Lemma

Let f , g ∈ L1[−1, 1]. dk f If f is k times differentiable (k ≥ 0), with dxk continuous, then f ∗ g is k times differentiable, with dk dk f dxk (f ∗ g)(x) = ( dxk ∗ g)(x). If f is Lipschitz, then f ∗ g is Lipschitz.

The previous examples, and some others in the same way, gives the idea that the convolution takes “the best” properties from its parent functions.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution There exist nowhere differentiable functions f , g so that f ∗ g is differentiable.

Results in this line have given the convolution operator the label of smoothening.

Lemma

Let f , g ∈ L1[−1, 1]. dk f If f is k times differentiable (k ≥ 0), with dxk continuous, then f ∗ g is k times differentiable, with dk dk f dxk (f ∗ g)(x) = ( dxk ∗ g)(x). If f is Lipschitz, then f ∗ g is Lipschitz.

If f , g ∈ L2[−1, 1], then f ∗ g is continuous.

The previous examples, and some others in the same way, gives the idea that the convolution takes “the best” properties from its parent functions.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Results in this line have given the convolution operator the label of smoothening.

Lemma

Let f , g ∈ L1[−1, 1]. dk f If f is k times differentiable (k ≥ 0), with dxk continuous, then f ∗ g is k times differentiable, with dk dk f dxk (f ∗ g)(x) = ( dxk ∗ g)(x). If f is Lipschitz, then f ∗ g is Lipschitz.

If f , g ∈ L2[−1, 1], then f ∗ g is continuous. There exist nowhere differentiable functions f , g so that f ∗ g is differentiable.

The previous examples, and some others in the same way, gives the idea that the convolution takes “the best” properties from its parent functions.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Lemma

Let f , g ∈ L1[−1, 1]. dk f If f is k times differentiable (k ≥ 0), with dxk continuous, then f ∗ g is k times differentiable, with dk dk f dxk (f ∗ g)(x) = ( dxk ∗ g)(x). If f is Lipschitz, then f ∗ g is Lipschitz.

If f , g ∈ L2[−1, 1], then f ∗ g is continuous. There exist nowhere differentiable functions f , g so that f ∗ g is differentiable.

The previous examples, and some others in the same way, gives the idea that the convolution takes “the best” properties from its parent functions. Results in this line have given the convolution operator the label of smoothening.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Lemma

Let f , g ∈ L1[−1, 1]. dk f If f is k times differentiable (k ≥ 0), with dxk continuous, then f ∗ g is k times differentiable, with dk dk f dxk (f ∗ g)(x) = ( dxk ∗ g)(x). If f is Lipschitz, then f ∗ g is Lipschitz.a

If f , g ∈ L2[−1, 1], then f ∗ g is continuous. There exist nowhere differentiable functions f , g so that f ∗ g is differentiable. aLipschitz property is sometimes regarded as a ”middle way“ between continuity and differentiability.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Lemma

Let f , g ∈ L1[−1, 1]. dk f If f is k times differentiable (k ≥ 0), with dxk continuous, then f ∗ g is k times differentiable, with dk dk f dxk (f ∗ g)(x) = ( dxk ∗ g)(x). If f is Lipschitz, then f ∗ g is Lipschitz.a

If f , g ∈ L2[−1, 1], then f ∗ g is continuous. There exist nowhere differentiable functions f , g so that f ∗ g is differentiable. aLipschitz property is sometimes regarded as a ”middle way“ between continuity and differentiability.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Lemma

Let f , g ∈ L1[−1, 1]. dk f If f is k times differentiable (k ≥ 0), with dxk continuous, then f ∗ g is k times differentiable, with dk dk f dxk (f ∗ g)(x) = ( dxk ∗ g)(x). If f is Lipschitz, then f ∗ g is Lipschitz.a

If f , g ∈ L2[−1, 1], then f ∗ g is continuous. There exist nowhere differentiable functions f , g so that f ∗ g is differentiable. aLipschitz property is sometimes regarded as a ”middle way“ between continuity and differentiability.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution (from Wikipedia)

Theorem

Let f , g ∈ L1[−1, 1]. If f is differentiable with bounded , then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

Theorem

Let f , g ∈ L1[−1, 1]. If f is differentiable with integrable derivative, then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

What if we just ask differentiability?

With some more requirements over f 0 the property of differentiability can be extended to the convolution.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution (from Wikipedia)

Theorem

Let f , g ∈ L1[−1, 1]. If f is differentiable with integrable derivative, then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

What if we just ask differentiability?

With some more requirements over f 0 the property of differentiability can be extended to the convolution. Theorem

Let f , g ∈ L1[−1, 1]. If f is differentiable with bounded derivative, then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

Pablo Jim´enezRodr´ıguez Differentiability of the convolution (from Wikipedia)

What if we just ask differentiability?

With some more requirements over f 0 the property of differentiability can be extended to the convolution. Theorem

Let f , g ∈ L1[−1, 1]. If f is differentiable with bounded derivative, then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

Theorem

Let f , g ∈ L1[−1, 1]. If f is differentiable with integrable derivative, then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

Pablo Jim´enezRodr´ıguez Differentiability of the convolution What if we just ask differentiability?

With some more requirements over f 0 the property of differentiability can be extended to the convolution. Theorem

Let f , g ∈ L1[−1, 1]. If f is differentiable with bounded derivative, then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

Theorem (from Wikipedia)

Let f , g ∈ L1[−1, 1]. If f is differentiable with integrable derivative, then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

Pablo Jim´enezRodr´ıguez Differentiability of the convolution With some more requirements over f 0 the property of differentiability can be extended to the convolution. Theorem

Let f , g ∈ L1[−1, 1]. If f is differentiable with bounded derivative, then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

Theorem (from Wikipedia)

Let f , g ∈ L1[−1, 1]. If f is differentiable with integrable derivative, then f ∗ g is differentiable, with (f ∗ g)0(x) = (f 0 ∗ g)(x).

What if we just ask differentiability?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution  1  f (x) = x2 sin x3  1  g(x) = sin x3 f ∗ g not differentiable?

First idea Take a function with unbounded derivative.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution  1  g(x) = sin x3 f ∗ g not differentiable?

First idea Take a function with unbounded derivative.  1  f (x) = x2 sin x3

Pablo Jim´enezRodr´ıguez Differentiability of the convolution  1  g(x) = sin x3 f ∗ g not differentiable?

First idea Take a function with unbounded derivative.  1  f (x) = x2 sin x3

Pablo Jim´enezRodr´ıguez Differentiability of the convolution f ∗ g not differentiable?

First idea Take a function with unbounded derivative.  1  f (x) = x2 sin x3  1  g(x) = sin x3

Pablo Jim´enezRodr´ıguez Differentiability of the convolution First idea Take a function with unbounded derivative.  1  f (x) = x2 sin x3  1  g(x) = sin x3 f ∗ g not differentiable?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution First idea Take a function with unbounded derivative.  1  f (x) = x2 sin x3  1  g(x) = sin x3 f ∗ g not differentiable?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Z 1 Z 1 2  1   1  2 2  1  f ∗ g(0) = t sin 3 sin 3 dt = t sin 3 dt −1 t (−t) −1 t

First idea Take a function with unbounded derivative.  1  f (x) = x2 sin x3  1  g(x) = sin x3 f ∗ g not differentiable?

Z 1 2  1   1  f ∗ g(x) = t sin 3 sin 3 dt −1 t (x − t)

Pablo Jim´enezRodr´ıguez Differentiability of the convolution First idea Take a function with unbounded derivative.  1  f (x) = x2 sin x3  1  g(x) = sin x3 f ∗ g not differentiable?

Z 1 2  1   1  f ∗ g(x) = t sin 3 sin 3 dt −1 t (x − t) Z 1 Z 1 2  1   1  2 2  1  f ∗ g(0) = t sin 3 sin 3 dt = t sin 3 dt −1 t (−t) −1 t

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Pablo Jim´enezRodr´ıguez Differentiability of the convolution  1 1  7i For each i ≥ 1, divide the interval 2i , 2i−1 into 2 sub-intervals 7i−1 of the same length For each k = 0, 1,..., 2 − 1, consider φi,k ∞ and ψi,k two C −hat functions so that

 1 2k + 1 1 2k + 2 supp φ ⊆ + , + , i,k 2i 28i 2i 28i  1 2k 1 2k + 1 supp ψ ⊆ + , + , i,k 2i 28i 2i 28i 1 8k + 5 1 8k + 7 φ (x) = 1 for + ≤ x ≤ + and i,k 2i 28i+2 2i 28i+2 1 8k + 1 1 8k + 3 ψ (x) = 1 for + ≤ x ≤ + . i,k 2i 28i+2 2i 28i+2

Second idea Let’s see if there is anything we can do to simplify calculations...

Definition

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Pablo Jim´enezRodr´ıguez Differentiability of the convolution 7i−1 For each k = 0, 1,..., 2 − 1, consider φi,k ∞ and ψi,k two C −hat functions so that

 1 2k + 1 1 2k + 2 supp φ ⊆ + , + , i,k 2i 28i 2i 28i  1 2k 1 2k + 1 supp ψ ⊆ + , + , i,k 2i 28i 2i 28i 1 8k + 5 1 8k + 7 φ (x) = 1 for + ≤ x ≤ + and i,k 2i 28i+2 2i 28i+2 1 8k + 1 1 8k + 3 ψ (x) = 1 for + ≤ x ≤ + . i,k 2i 28i+2 2i 28i+2

Second idea Let’s see if there is anything we can do to simplify calculations...

Definition  1 1  7i For each i ≥ 1, divide the interval 2i , 2i−1 into 2 sub-intervals of the same length.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Definition  1 1  7i For each i ≥ 1, divide the interval 2i , 2i−1 into 2 sub-intervals 7i−1 of the same length. For each k = 0, 1,..., 2 − 1, consider φi,k ∞ and ψi,k two C −hat functions so that

 1 2k + 1 1 2k + 2 supp φ ⊆ + , + , i,k 2i 28i 2i 28i  1 2k 1 2k + 1 supp ψ ⊆ + , + , i,k 2i 28i 2i 28i 1 8k + 5 1 8k + 7 φ (x) = 1 for + ≤ x ≤ + and i,k 2i 28i+2 2i 28i+2 1 8k + 1 1 8k + 3 ψ (x) = 1 for + ≤ x ≤ + . i,k 2i 28i+2 2i 28i+2

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Theorem The functions f and g defined above are differentiable functions for which f ∗ g is not differentiable at 0.

Second idea Let’s see if there is anything we can do to simplify calculations...

Definition Define ∞ 27i−1−1 2 X X f (x) = x φi,k (x), i=1 k=0 ∞ 27j−1−1 2 X X g(x) = x ψj,l (x) j=1 l=0

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Second idea Let’s see if there is anything we can do to simplify calculations...

Definition Define ∞ 27i−1−1 2 X X f (x) = x φi,k (x), i=1 k=0 ∞ 27j−1−1 2 X X g(x) = x ψj,l (x) j=1 l=0

Theorem The functions f and g defined above are differentiable functions for which f ∗ g is not differentiable at 0.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution In fact, for the differentiable functions f and g in the previous theorem, one can prove that f 0 ∗ g(x) is well-defined for every −1 < x < 1.

Remark 1

Theorem There exist differentiable functions f and g so that f ∗ g(x) is not differentiable at x = 0.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution In fact, for the differentiable functions f and g in the previous theorem, one can prove that f 0 ∗ g(x) is well-defined for every −1 < x < 1.

Theorem There exist differentiable functions f and g so that f ∗ g(x) is not differentiable at x = 0.

Remark 1

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Theorem There exist differentiable functions f and g so that f ∗ g(x) is not differentiable at x = 0.

Remark 1 In fact, for the differentiable functions f and g in the previous theorem, one can prove that f 0 ∗ g(x) is well-defined for every −1 < x < 1.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Theorem There exist differentiable functions f and g so that f ∗ g(x) is not differentiable at x = 0.

Remark 1 In fact, for the differentiable functions f and g in the previous theorem, one can prove that f 0 ∗ g(x) is well-defined for every −1 < x < 1.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution (f + g) ∗ (f + g) = f ∗ f + f ∗ g + g ∗ f + g ∗ g = f ∗ f + 2f ∗ g + g ∗ g 1 f ∗ g = [(f + g) ∗ (f + g) − (f ∗ f + g ∗ g)] 2 In particular, there exists a differentiable function h so that h ∗ h is not differentiable at 0.

Theorem There exist differentiable functions f and g so that f ∗ g(x) is not differentiable at x = 0.

Remark 2 Can we make f = g for the previous theorem?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution 1 f ∗ g = [(f + g) ∗ (f + g) − (f ∗ f + g ∗ g)] 2 In particular, there exists a differentiable function h so that h ∗ h is not differentiable at 0.

Theorem There exist differentiable functions f and g so that f ∗ g(x) is not differentiable at x = 0.

Remark 2 Can we make f = g for the previous theorem?

(f + g) ∗ (f + g) = f ∗ f + f ∗ g + g ∗ f + g ∗ g = f ∗ f + 2f ∗ g + g ∗ g

Pablo Jim´enezRodr´ıguez Differentiability of the convolution In particular, there exists a differentiable function h so that h ∗ h is not differentiable at 0.

Theorem There exist differentiable functions f and g so that f ∗ g(x) is not differentiable at x = 0.

Remark 2 Can we make f = g for the previous theorem?

(f + g) ∗ (f + g) = f ∗ f + f ∗ g + g ∗ f + g ∗ g = f ∗ f + 2f ∗ g + g ∗ g 1 f ∗ g = [(f + g) ∗ (f + g) − (f ∗ f + g ∗ g)] 2

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Theorem There exist differentiable functions f and g so that f ∗ g(x) is not differentiable at x = 0.

Remark 2 Can we make f = g for the previous theorem?

(f + g) ∗ (f + g) = f ∗ f + f ∗ g + g ∗ f + g ∗ g = f ∗ f + 2f ∗ g + g ∗ g 1 f ∗ g = [(f + g) ∗ (f + g) − (f ∗ f + g ∗ g)] 2 In particular, there exists a differentiable function h so that h ∗ h is not differentiable at 0.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution What algebraic structure does this problem admit?

How many of such functions can we find?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution How many of such functions can we find? What algebraic structure does this problem admit?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Theorem There exist two closed cones V and W generated by two respective non-numerable sets of differentiable functions so that, if f ∈ V \{0} and g ∈ W \{0}, then f ∗ g is not differentiable at 0.

Theorem There exist two algebras A and B generated by two respective non-numerable sets of differentiable functions so that, if f ∈ A \{0} and g ∈ B \{0}, then f ∗ g is not differentiable at 0.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Theorem There exist two algebras A and B generated by two respective non-numerable sets of differentiable functions so that, if f ∈ A \{0} and g ∈ B \{0}, then f ∗ g is not differentiable at 0.

Theorem There exist two closed cones V and W generated by two respective non-numerable sets of differentiable functions so that, if f ∈ V \{0} and g ∈ W \{0}, then f ∗ g is not differentiable at 0.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution For the algebras, consider

2 ∞ 2i −i−1−1 λ X X λ fλ(x) = |x| φi,k (|x|) and i=1 k=0 2 ∞ 2i −i−1−1 λ X X λ gλ(x) = |x| ψi,k (|x|), i=1 k=0

Theorem There exist two closed cones V and W generated by two respective non-numerable sets of differentiable functions so that, if f ∈ V \{0} and g ∈ W \{0}, then f ∗ g is not differentiable at 0.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution For the algebras, consider

2 ∞ 2i −i−1−1 λ X X λ fλ(x) = |x| φi,k (|x|) and i=1 k=0 2 ∞ 2i −i−1−1 λ X X λ gλ(x) = |x| ψi,k (|x|), i=1 k=0 For the closed cones, consider

Pablo Jim´enezRodr´ıguez Differentiability of the convolution For the algebras, consider

2 ∞ 2i −i−1−1 λ X X λ fλ(x) = |x| φi,k (|x|) and i=1 k=0 2 ∞ 2i −i−1−1 λ X X λ gλ(x) = |x| ψi,k (|x|), i=1 k=0 For the closed cones, consider

Pablo Jim´enezRodr´ıguez Differentiability of the convolution For the algebras, consider

2 ∞ 2i −i−1−1 λ X X λ fλ(x) = |x| φi,k (|x|) and i=1 k=0 2 ∞ 2i −i−1−1 λ X X λ gλ(x) = |x| ψi,k (|x|), i=1 k=0 For the closed cones, consider

Pablo Jim´enezRodr´ıguez Differentiability of the convolution For the algebras, consider

2 ∞ 2i −i−1−1 λ X X λ fλ(x) = |x| φi,k (|x|) and i=1 k=0 2 ∞ 2i −i−1−1 λ X X λ gλ(x) = |x| ψi,k (|x|), i=1 k=0

Theorem (V.I. Gurariy) If V ⊆ D[−1, 1] is a closed , then V is of finite dimension.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution What about more points?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Pablo Jim´enezRodr´ıguez Differentiability of the convolution Pablo Jim´enezRodr´ıguez Differentiability of the convolution (of zero measure)

There exist differentiable functions f and g so that f ∗ g is not differentiable on a Perfect set

Pablo Jim´enezRodr´ıguez Differentiability of the convolution (of zero measure)

There exist differentiable functions f and g so that f ∗ g is not differentiable on a Perfect set

Pablo Jim´enezRodr´ıguez Differentiability of the convolution There exist differentiable functions f and g so that f ∗ g is not differentiable on a Perfect set (of zero measure)

Pablo Jim´enezRodr´ıguez Differentiability of the convolution If f and g are differentiable functions and x ∈/ ∆f + ∆g , then f ∗ g is differentiable at x and (f ∗ g)0(x) = (f 0 ∗ g)(x).

Theorem Let f be a differentiable function, 0 ∆f = {x ∈ [−1, 1] : f is locally unbounded}.

Any positive result?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution If f and g are differentiable functions and x ∈/ ∆f + ∆g , then f ∗ g is differentiable at x and (f ∗ g)0(x) = (f 0 ∗ g)(x).

Any positive result?

Theorem Let f be a differentiable function, 0 ∆f = {x ∈ [−1, 1] : f is locally unbounded}.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution then f ∗ g is differentiable at x and (f ∗ g)0(x) = (f 0 ∗ g)(x).

Any positive result?

Theorem Let f be a differentiable function, 0 ∆f = {x ∈ [−1, 1] : f is locally unbounded}. If f and g are differentiable functions and x ∈/ ∆f + ∆g ,

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Any positive result?

Theorem Let f be a differentiable function, 0 ∆f = {x ∈ [−1, 1] : f is locally unbounded}. If f and g are differentiable functions and x ∈/ ∆f + ∆g , then f ∗ g is differentiable at x and (f ∗ g)0(x) = (f 0 ∗ g)(x).

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Any positive result?

Theorem Let f be a differentiable function, 0 ∆f = {x ∈ [−1, 1] : f is locally unbounded}. If f and g are differentiable functions and x ∈/ ∆f + ∆g , then f ∗ g is differentiable at x and (f ∗ g)0(x) = (f 0 ∗ g)(x).

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Any positive result?

Theorem Let f be a differentiable function, 0 ∆f = {x ∈ [−1, 1] : f is locally unbounded}. If f and g are differentiable functions and x ∈/ ∆f + ∆g , then f ∗ g is differentiable at x and (f ∗ g)0(x) = (f 0 ∗ g)(x).

Pablo Jim´enezRodr´ıguez Differentiability of the convolution A dense set? Of positive measure? The whole [−1, 1]?

1 Let f and g be differentiable functions. How big can the set where f ∗ g is not differentiable be?

0 2 What are the weakest conditions over f to ensure that f ∗ g is differentiable? 3 If f and g are such that f ∗ g is differentiable at x and f 0 ∗ g(x) is well-defined, is it (f ∗ g)0(x) = f 0 ∗ g(x)?

Some open questions.

Pablo Jim´enezRodr´ıguez Differentiability of the convolution A dense set? Of positive measure? The whole [−1, 1]? 0 2 What are the weakest conditions over f to ensure that f ∗ g is differentiable? 3 If f and g are such that f ∗ g is differentiable at x and f 0 ∗ g(x) is well-defined, is it (f ∗ g)0(x) = f 0 ∗ g(x)?

Some open questions.

1 Let f and g be differentiable functions. How big can the set where f ∗ g is not differentiable be?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Of positive measure? The whole [−1, 1]? 0 2 What are the weakest conditions over f to ensure that f ∗ g is differentiable? 3 If f and g are such that f ∗ g is differentiable at x and f 0 ∗ g(x) is well-defined, is it (f ∗ g)0(x) = f 0 ∗ g(x)?

Some open questions.

1 Let f and g be differentiable functions. How big can the set where f ∗ g is not differentiable be? A dense set?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution The whole [−1, 1]? 0 2 What are the weakest conditions over f to ensure that f ∗ g is differentiable? 3 If f and g are such that f ∗ g is differentiable at x and f 0 ∗ g(x) is well-defined, is it (f ∗ g)0(x) = f 0 ∗ g(x)?

Some open questions.

1 Let f and g be differentiable functions. How big can the set where f ∗ g is not differentiable be? A dense set? Of positive measure?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution 0 2 What are the weakest conditions over f to ensure that f ∗ g is differentiable? 3 If f and g are such that f ∗ g is differentiable at x and f 0 ∗ g(x) is well-defined, is it (f ∗ g)0(x) = f 0 ∗ g(x)?

Some open questions.

1 Let f and g be differentiable functions. How big can the set where f ∗ g is not differentiable be? A dense set? Of positive measure? The whole [−1, 1]?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution 3 If f and g are such that f ∗ g is differentiable at x and f 0 ∗ g(x) is well-defined, is it (f ∗ g)0(x) = f 0 ∗ g(x)?

Some open questions.

1 Let f and g be differentiable functions. How big can the set where f ∗ g is not differentiable be? A dense set? Of positive measure? The whole [−1, 1]? 0 2 What are the weakest conditions over f to ensure that f ∗ g is differentiable?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Some open questions.

1 Let f and g be differentiable functions. How big can the set where f ∗ g is not differentiable be? A dense set? Of positive measure? The whole [−1, 1]? 0 2 What are the weakest conditions over f to ensure that f ∗ g is differentiable? 3 If f and g are such that f ∗ g is differentiable at x and f 0 ∗ g(x) is well-defined, is it (f ∗ g)0(x) = f 0 ∗ g(x)?

Pablo Jim´enezRodr´ıguez Differentiability of the convolution PUBLICATIONS

.J.R., G.A. Mu˜noz-Fern´andez,E. S´aezMaestro, J.B. Seoane-Sep´ulveda, The convolution of two differentiable functions on the circle need not be differentiable, Rev. Mat. Compl., ??, (2018) ??–??. .J.R., G.A. Mu˜noz-Fern´andez,E. S´aezMaestro, J.B. Seoane-Sep´ulveda, Algebraic structures and the differentiability of the convolution., J. Approx. Theory, ??, (2019) ??–??. .C. Ciesielski, P.J.R., G.A. Mu˜noz-Fern´andezand J.B. Seoane-Sep´ulveda, Nondifferentiability of the convolution of differentiable real functions., preprint..

Pablo Jim´enezRodr´ıguez Differentiability of the convolution Thank you for your attention!!

Pablo Jim´enezRodr´ıguez Differentiability of the convolution