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Power Operations &

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1. Power Operations

Powers are also called exponents or indices; we can work with the indices to simplify expressions and to solve problems.

Some key ideas:

a) Any base number raised to the power of 1 is the base itself: for example, 5 = 5 b) Any base number raised to the power of 0 equals 1, so: 4 = 1 1 c) Powers can be simplified if they are multiplied or divided0 and have the same base. d) Powers of powers are multiplied. Hence, (2 ) = 2 × 2 = 2 e) A negative power indicates a reciprocal: 3 3 =2 3 3 6 −2 1 2 3 Certain rules apply and are often referred to as: Index Laws. Below is a summary of the index rules:

Index Law Substitute variables for values × = 2 × 2 = 2 = 2 = 32 𝒎𝒎 𝒏𝒏 𝒎𝒎+𝒏𝒏 3 2 3+2 5 𝒂𝒂 ÷ 𝒂𝒂 = 𝒂𝒂 3 ÷ 3 = 3 = 3 = 27 𝒎𝒎 𝒏𝒏 𝒎𝒎−𝒏𝒏 6 3 × 6−3 3 𝒂𝒂 ( 𝒂𝒂) = 𝒂𝒂 (4 ) = 4 = 4 = 1048 576 𝒎𝒎 𝒏𝒏 𝒎𝒎𝒎𝒎 2 5 2 5 10 ( 𝒂𝒂 ) = 𝒂𝒂 (2 × 5) = 2 × 5 = 4 × 25 = 100 𝒎𝒎 𝒎𝒎 𝒎𝒎 2 2 2 ( 𝒂𝒂𝒂𝒂) = 𝒂𝒂 ÷𝒃𝒃 (10 ÷ 5) = 2 = 8; (10 ÷ 5 ) = 1000 ÷ 125 = 8 𝒎𝒎 𝒎𝒎 𝒎𝒎 3 3 3 3 𝒂𝒂 𝒂𝒂 𝒃𝒃 1 1 �𝒃𝒃 = 4 = = 4 16 −𝒎𝒎 𝟏𝟏 −2 𝒂𝒂 𝒎𝒎 2 = 𝒂𝒂 8 = 8 = 2 𝟏𝟏 3 𝒎𝒎 1� 𝒎𝒎 = 6 ÷ 6 = 6 3 = 6 = 1; (6 ÷ 6 = 1) 𝒂𝒂 √𝒂𝒂 √ 𝟎𝟎 3 3 3−3 0 𝒂𝒂 𝟏𝟏 EXAMPLE PROBLEMS:

a) Simplify 6 × 6 ÷ 6 × 7 + 6 = 5 3 2 2 4 = 6 × 7 + 6 5+3−2 2 4 = 6 × 7 + 6 6 2 4 b) Simplify × × = 5 4 − 1 = × × 𝑔𝑔 ℎ 𝑔𝑔 5 −1 4 = 𝑔𝑔 × 𝑔𝑔 ℎ 4 4 𝑔𝑔 ℎ Watch this short Khan Academy video for further explanation: “Simplifying expressions with exponents” https://www.khanacademy.org/math/algebra/exponent-equations/exponent-properties- algebra/v/simplifying-expressions-with-exponents

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Question 1:

a) Apply the index laws/rules:

i. Simplify 5 × 5 + 5 = 2 4 2

ii. Simplify × = 2 5 𝑥𝑥 𝑥𝑥 iii. Simplify 4 × t ÷ 4 = 2 3 2 iv. Simplify (5 ) = 4 3

= v. Simplify 4 6 2 3 4 3 vi. Simplify 3 × 3 = 2 −5

( ) = vii. Simplify 2 3 9 𝑥𝑥 2 3𝑥𝑥𝑥𝑥 viii. Simplify = −1 𝑎𝑎 √𝑎𝑎

b) What is the value of for the following?

𝑥𝑥 i. 49 = 7 𝑥𝑥

ii. = 2 1 𝑥𝑥 4 iii. 88 = 11 × 2 1 𝑥𝑥 iv. 480 = 2 × 3 × 5 𝑥𝑥 1 1

÷ = 6 v. Show that 2 3 2 16𝑎𝑎 𝑏𝑏 8𝑏𝑏 𝑎𝑎 5 3 3 5 3𝑎𝑎 𝑏𝑏 9𝑎𝑎 𝑏𝑏 𝑎𝑎𝑏𝑏

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2. Scientific Notation

Numbers as multiples or Number Number as a power of ten fractions of ten 10 x 10 x 10 1000 103 10 x 10 100 102 10 10 101 10 x 1/10 1 100 1/10 0.1 10−1 1/100 0.01 10−2 1/1000 0.001 10−3

Scientific notation is a convenient method of representing and working with very large and very small numbers. Transcribing a number such as 0.000000000000082 or 5480000000000 can be frustrating since there will be a constant need to count the number of zeroes each time the number is used. Scientific notation provides a way of writing such numbers easily and accurately. Scientific notation requires that a number is presented as a non-zero digit followed by a decimal point and then a power (exponential) of base 10. The exponential is determined by counting the number places the decimal point is moved. The number 65400000000 in scientific notation becomes 6.54 x 1010. The number 0.00000086 in scientific notation becomes 8.6 x 10-7. (Note: 10-6 = .) 1 6 10

(Coefficient)

(base 10)

If n is positive, shift the decimal point that many places to the right. If n is negative, shift the decimal point that many places to the left. Question 2:

Write the following in scientific notation: Write the following numbers out in full: a. 450 e. 3.75 × 10 2 b. 90000000 f. 3.97 × 10 1 c. 3.5 g. 1.875 × 10 −1 d. 0.0975 h. 8.75 × 10 −3 −

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3. Calculations with Scientific Notation

Multiplication and calculations of quantities expressed in scientific notation follow the index laws since they all they all have the common base, i.e. base 10.

Here are the steps:

Multiplication Division A. Multiply the coefficients 1. Divide the coefficients B. Add their exponents 2. Subtract their exponents C. Convert the answer to scientific 3. Convert the answer to scientific Notation Notation Example: Example: . × × ( . × ) (9 × 10 ) ÷ (3 × 10 ) . × . −𝟒𝟒= . (multiply− 𝟓𝟓coefficients) 9 ÷ 3 =203 (divide coefficients)11 � � ( ) ( ) 𝟕𝟕 𝟏𝟏 ×𝟏𝟏𝟏𝟏 = 𝟖𝟖 𝟓𝟓 𝟏𝟏𝟏𝟏 (add exponents) 10 ÷ 10 = 10 (subtract exponents) = 𝟕𝟕 𝟏𝟏−. 𝟒𝟒 𝟖𝟖×𝟓𝟓 −𝟓𝟓𝟔𝟔𝟔𝟔 – 𝟑𝟑check𝟑𝟑− 𝟒𝟒it’s+ −in𝟓𝟓 scientific=−𝟗𝟗 notation  = 3 ×2010 – 11check it’s in 20scientific−11 = notation9  = 𝟏𝟏𝟏𝟏. ×𝟏𝟏𝟏𝟏 −𝟗𝟗 –𝟏𝟏 convert𝟏𝟏 to scientific notation  9 𝟔𝟔𝟔𝟔 𝟑𝟑𝟑𝟑 𝟏𝟏𝟏𝟏−𝟖𝟖 Recall𝟔𝟔 𝟎𝟎that𝟎𝟎𝟎𝟎 𝟏𝟏𝟏𝟏 and of numbers with exponents (or indices) requires that the base and the exponent are the same. Since all numbers in scientific notation have the same base 10, for addition and subtraction calculations, we have to adjust the terms so the exponents are the same for both. This will ensure that the digits in the coefficients have the correct place value so they can be simply added or subtracted.

Here are the steps:

Addition Subtraction 1. Determine how much the smaller 1. Determine how much the smaller exponent must be increased by so it is exponent must be increased by so it is equal to the larger exponent equal to the larger exponent 2. Increase the smaller exponent by this 2. Increase the smaller exponent by this number and move the decimal point of number and move the decimal point of the coefficient to the left the same the coefficient to the left the same number of places number of places 3. Add the new coefficients 3. Subtract the new coefficients 4. Convert the answer to scientific 4. Convert the answer to scientific notation notation Example: Example: × + ( × ) (5.3 × 10 ) (4.224 × 10 ) =𝟐𝟐 increase the 𝟒𝟒small exponent by 2 to equal the 15 12 =12 3 increase the small15 exponent by 3 to equal �𝟑𝟑 𝟏𝟏𝟏𝟏 �larger𝟐𝟐 exponent𝟏𝟏𝟏𝟏 4 −the larger exponent 15 𝟒𝟒.− 𝟐𝟐× 𝟐𝟐 the coefficient of the first term is adjusted 0. 0053− × 10 the coefficient of the firs t term is adjusted so its exponent matches that of so 𝟒𝟒its exponent matches that of the second term 15 the second term =𝟎𝟎 𝟎𝟎.𝟎𝟎 ×𝟏𝟏𝟏𝟏 + × the two terms now = (0.0053 × 10 ) (4.224 × 10 ) the two have the𝟒𝟒 same base and exponent𝟒𝟒 and the �𝟎𝟎 𝟎𝟎𝟎𝟎 coefficients𝟏𝟏𝟏𝟏 � can�𝟐𝟐 be added𝟏𝟏𝟎𝟎 � 15terms now have the same15 base and exponent− and the coefficients can be = . × check it’s in scientific notation  subtracted. 𝟒𝟒 15 = 4.2187 × 10 check it’s in scientific notation  𝟐𝟐 𝟎𝟎𝟎𝟎 𝟏𝟏𝟏𝟏 −

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Questions 3:

a) (4.5 × 10 ) ÷ (3 × 10 ) −3 2

b) (2.25 × 10 ) × (1.5 × 10 ) 6 3

c) (6.078 × 10 ) (8.220 × 10 ) (give answer to 4 significant figures). 11 14 −

d) (3.67 × 10 ) × (23.6 × 10 ) 5 4

e) (7.6 × 10 ) + ( 9.0 × 10 ) −3 −2 √

f) Two particles weigh 2.43 X 10-2 grams and 3.04 X 10-3 grams. What is the difference in their weight in scientific notation?

g) How long does it take light to travel to the Earth from the Sun in seconds, given that the Earth is 1.5 X 108 km from the Sun and the speed of light is 3 X 105 km/s?

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4 Answers

Q1. Power Operations a) i. 5 × 5 + 5 = 5 + 5 ii. x2 × x 4 = x2 6 2 2 5 7 iii. 4 × t ÷ 4 = t 2 3 2 3 iv. (5 ) = 5 4 3 12 = 2 3 = 16 × 9 = 144 v. 4 6 2 3 4 2 4 vi. 33 × 3 = 3 = 2 −5 −3 1 ( ) = = 27 vii. 2 3 6 5 9 𝑥𝑥 9𝑥𝑥 3𝑥𝑥 2 2 2 3𝑥𝑥𝑥𝑥 =3𝑥𝑥𝑦𝑦 × 𝑦𝑦 = viii. 1 1 = − 1 1 −1 −1 2 2 1 𝑎𝑎 2 b) 𝑎𝑎 √𝑎𝑎 𝑎𝑎 𝑎𝑎 𝑎𝑎 √ 𝑜𝑜𝑜𝑜 𝑎𝑎 i. = 2 ii. = 2 iii. 𝑥𝑥 = 3 iv. 𝑥𝑥 = 5− 𝑥𝑥 v. Show that ÷ = 6 × 𝑥𝑥 2 3 2 2 3 3 5 16𝑎𝑎 𝑏𝑏 8𝑏𝑏 𝑎𝑎 5 16𝑎𝑎 𝑏𝑏 9𝑎𝑎 𝑏𝑏 3 3 5 3 2 3𝑎𝑎 𝑏𝑏 9𝑎𝑎 𝑏𝑏 𝑎𝑎𝑏𝑏 3𝑎𝑎 𝑏𝑏 8𝑏𝑏 𝑎𝑎 × × = = 6 5 8 = 1 5 2𝑎𝑎 𝑏𝑏 3 2𝑎𝑎 𝑏𝑏 3 5 3 4 Q2. Scientific Notation 𝑏𝑏 𝑎𝑎 1 𝑎𝑎𝑏𝑏 a) 4.5 x 102 e) 375 b) 9.0 x 107 f) 39.7 c) 3.5 x 100 g) 0.1875 d) 9.75 x 10-2 h) 0.00875

Q3. Calculations with scientific notation

a) 1.5 × 10 e) 3.076 × 10 b) 3.375 × 10−5 f) 2.126 × 10−2 c) 8.214 × 109 g) 500 s −2 d) 8.8612 × 10 14 − 10

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